src/HOL/Divides.thy
author haftmann
Sun Oct 16 13:47:37 2016 +0200 (2016-10-16)
changeset 64250 0cde0b4d4cb5
parent 64246 15d1ee6e847b
child 64592 7759f1766189
permissions -rw-r--r--
clarified prover-specific rules
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(*  Title:      HOL/Divides.thy
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    Author:     Lawrence C Paulson, Cambridge University Computer Laboratory
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    Copyright   1999  University of Cambridge
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*)
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section \<open>The division operators div and mod\<close>
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theory Divides
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imports Parity
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begin
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subsection \<open>Abstract division in commutative semirings.\<close>
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class semiring_div = semidom + semiring_modulo +
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  assumes div_by_0: "a div 0 = 0"
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    and div_0: "0 div a = 0"
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    and div_mult_self1 [simp]: "b \<noteq> 0 \<Longrightarrow> (a + c * b) div b = c + a div b"
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    and div_mult_mult1 [simp]: "c \<noteq> 0 \<Longrightarrow> (c * a) div (c * b) = a div b"
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begin
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subclass algebraic_semidom
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proof
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  fix b a
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  assume "b \<noteq> 0"
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  then show "a * b div b = a"
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    using div_mult_self1 [of b 0 a] by (simp add: ac_simps div_0)
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qed (simp add: div_by_0)
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text \<open>@{const divide} and @{const modulo}\<close>
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lemma mod_by_0 [simp]: "a mod 0 = a"
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  using div_mult_mod_eq [of a zero] by simp
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lemma mod_0 [simp]: "0 mod a = 0"
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  using div_mult_mod_eq [of zero a] div_0 by simp
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lemma div_mult_self2 [simp]:
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  assumes "b \<noteq> 0"
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  shows "(a + b * c) div b = c + a div b"
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  using assms div_mult_self1 [of b a c] by (simp add: mult.commute)
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lemma div_mult_self3 [simp]:
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  assumes "b \<noteq> 0"
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  shows "(c * b + a) div b = c + a div b"
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  using assms by (simp add: add.commute)
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lemma div_mult_self4 [simp]:
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  assumes "b \<noteq> 0"
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  shows "(b * c + a) div b = c + a div b"
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  using assms by (simp add: add.commute)
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lemma mod_mult_self1 [simp]: "(a + c * b) mod b = a mod b"
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proof (cases "b = 0")
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  case True then show ?thesis by simp
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next
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  case False
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  have "a + c * b = (a + c * b) div b * b + (a + c * b) mod b"
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    by (simp add: div_mult_mod_eq)
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  also from False div_mult_self1 [of b a c] have
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    "\<dots> = (c + a div b) * b + (a + c * b) mod b"
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      by (simp add: algebra_simps)
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  finally have "a = a div b * b + (a + c * b) mod b"
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    by (simp add: add.commute [of a] add.assoc distrib_right)
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  then have "a div b * b + (a + c * b) mod b = a div b * b + a mod b"
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    by (simp add: div_mult_mod_eq)
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  then show ?thesis by simp
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qed
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lemma mod_mult_self2 [simp]:
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  "(a + b * c) mod b = a mod b"
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  by (simp add: mult.commute [of b])
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lemma mod_mult_self3 [simp]:
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  "(c * b + a) mod b = a mod b"
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  by (simp add: add.commute)
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lemma mod_mult_self4 [simp]:
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  "(b * c + a) mod b = a mod b"
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  by (simp add: add.commute)
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lemma mod_mult_self1_is_0 [simp]:
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  "b * a mod b = 0"
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  using mod_mult_self2 [of 0 b a] by simp
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lemma mod_mult_self2_is_0 [simp]:
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  "a * b mod b = 0"
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  using mod_mult_self1 [of 0 a b] by simp
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lemma mod_by_1 [simp]:
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  "a mod 1 = 0"
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proof -
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  from div_mult_mod_eq [of a one] div_by_1 have "a + a mod 1 = a" by simp
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  then have "a + a mod 1 = a + 0" by simp
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  then show ?thesis by (rule add_left_imp_eq)
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qed
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lemma mod_self [simp]:
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  "a mod a = 0"
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  using mod_mult_self2_is_0 [of 1] by simp
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lemma div_add_self1:
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  assumes "b \<noteq> 0"
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  shows "(b + a) div b = a div b + 1"
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  using assms div_mult_self1 [of b a 1] by (simp add: add.commute)
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lemma div_add_self2:
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  assumes "b \<noteq> 0"
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  shows "(a + b) div b = a div b + 1"
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  using assms div_add_self1 [of b a] by (simp add: add.commute)
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lemma mod_add_self1 [simp]:
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  "(b + a) mod b = a mod b"
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  using mod_mult_self1 [of a 1 b] by (simp add: add.commute)
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lemma mod_add_self2 [simp]:
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  "(a + b) mod b = a mod b"
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  using mod_mult_self1 [of a 1 b] by simp
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lemma dvd_imp_mod_0 [simp]:
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  assumes "a dvd b"
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  shows "b mod a = 0"
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proof -
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  from assms obtain c where "b = a * c" ..
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  then have "b mod a = a * c mod a" by simp
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  then show "b mod a = 0" by simp
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qed
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lemma mod_eq_0_iff_dvd:
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  "a mod b = 0 \<longleftrightarrow> b dvd a"
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proof
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  assume "b dvd a"
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  then show "a mod b = 0" by simp
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next
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  assume "a mod b = 0"
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  with div_mult_mod_eq [of a b] have "a div b * b = a" by simp
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  then have "a = b * (a div b)" by (simp add: ac_simps)
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  then show "b dvd a" ..
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qed
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lemma dvd_eq_mod_eq_0 [nitpick_unfold, code]:
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  "a dvd b \<longleftrightarrow> b mod a = 0"
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  by (simp add: mod_eq_0_iff_dvd)
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lemma mod_div_trivial [simp]:
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  "a mod b div b = 0"
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proof (cases "b = 0")
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  assume "b = 0"
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  thus ?thesis by simp
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next
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  assume "b \<noteq> 0"
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  hence "a div b + a mod b div b = (a mod b + a div b * b) div b"
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    by (rule div_mult_self1 [symmetric])
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  also have "\<dots> = a div b"
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    by (simp only: mod_div_mult_eq)
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  also have "\<dots> = a div b + 0"
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    by simp
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  finally show ?thesis
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    by (rule add_left_imp_eq)
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qed
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lemma mod_mod_trivial [simp]:
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  "a mod b mod b = a mod b"
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proof -
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  have "a mod b mod b = (a mod b + a div b * b) mod b"
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    by (simp only: mod_mult_self1)
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  also have "\<dots> = a mod b"
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    by (simp only: mod_div_mult_eq)
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  finally show ?thesis .
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qed
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lemma dvd_mod_imp_dvd:
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  assumes "k dvd m mod n" and "k dvd n"
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  shows "k dvd m"
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proof -
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  from assms have "k dvd (m div n) * n + m mod n"
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    by (simp only: dvd_add dvd_mult)
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  then show ?thesis by (simp add: div_mult_mod_eq)
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qed
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text \<open>Addition respects modular equivalence.\<close>
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lemma mod_add_left_eq: \<comment> \<open>FIXME reorient\<close>
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  "(a + b) mod c = (a mod c + b) mod c"
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proof -
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  have "(a + b) mod c = (a div c * c + a mod c + b) mod c"
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    by (simp only: div_mult_mod_eq)
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  also have "\<dots> = (a mod c + b + a div c * c) mod c"
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    by (simp only: ac_simps)
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  also have "\<dots> = (a mod c + b) mod c"
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    by (rule mod_mult_self1)
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  finally show ?thesis .
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qed
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lemma mod_add_right_eq: \<comment> \<open>FIXME reorient\<close>
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  "(a + b) mod c = (a + b mod c) mod c"
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proof -
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  have "(a + b) mod c = (a + (b div c * c + b mod c)) mod c"
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    by (simp only: div_mult_mod_eq)
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  also have "\<dots> = (a + b mod c + b div c * c) mod c"
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    by (simp only: ac_simps)
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  also have "\<dots> = (a + b mod c) mod c"
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    by (rule mod_mult_self1)
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  finally show ?thesis .
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qed
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lemma mod_add_eq: \<comment> \<open>FIXME reorient\<close>
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  "(a + b) mod c = (a mod c + b mod c) mod c"
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by (rule trans [OF mod_add_left_eq mod_add_right_eq])
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lemma mod_add_cong:
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  assumes "a mod c = a' mod c"
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  assumes "b mod c = b' mod c"
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  shows "(a + b) mod c = (a' + b') mod c"
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proof -
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  have "(a mod c + b mod c) mod c = (a' mod c + b' mod c) mod c"
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    unfolding assms ..
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  thus ?thesis
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    by (simp only: mod_add_eq [symmetric])
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qed
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text \<open>Multiplication respects modular equivalence.\<close>
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lemma mod_mult_left_eq: \<comment> \<open>FIXME reorient\<close>
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  "(a * b) mod c = ((a mod c) * b) mod c"
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proof -
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  have "(a * b) mod c = ((a div c * c + a mod c) * b) mod c"
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    by (simp only: div_mult_mod_eq)
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  also have "\<dots> = (a mod c * b + a div c * b * c) mod c"
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    by (simp only: algebra_simps)
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  also have "\<dots> = (a mod c * b) mod c"
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    by (rule mod_mult_self1)
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  finally show ?thesis .
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qed
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lemma mod_mult_right_eq: \<comment> \<open>FIXME reorient\<close>
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  "(a * b) mod c = (a * (b mod c)) mod c"
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proof -
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  have "(a * b) mod c = (a * (b div c * c + b mod c)) mod c"
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    by (simp only: div_mult_mod_eq)
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  also have "\<dots> = (a * (b mod c) + a * (b div c) * c) mod c"
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    by (simp only: algebra_simps)
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  also have "\<dots> = (a * (b mod c)) mod c"
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    by (rule mod_mult_self1)
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  finally show ?thesis .
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qed
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lemma mod_mult_eq: \<comment> \<open>FIXME reorient\<close>
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  "(a * b) mod c = ((a mod c) * (b mod c)) mod c"
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by (rule trans [OF mod_mult_left_eq mod_mult_right_eq])
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lemma mod_mult_cong:
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  assumes "a mod c = a' mod c"
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  assumes "b mod c = b' mod c"
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  shows "(a * b) mod c = (a' * b') mod c"
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proof -
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  have "(a mod c * (b mod c)) mod c = (a' mod c * (b' mod c)) mod c"
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    unfolding assms ..
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  thus ?thesis
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    by (simp only: mod_mult_eq [symmetric])
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qed
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text \<open>Exponentiation respects modular equivalence.\<close>
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lemma power_mod: "(a mod b) ^ n mod b = a ^ n mod b"
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apply (induct n, simp_all)
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apply (rule mod_mult_right_eq [THEN trans])
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apply (simp (no_asm_simp))
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apply (rule mod_mult_eq [symmetric])
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done
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lemma mod_mod_cancel:
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  assumes "c dvd b"
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  shows "a mod b mod c = a mod c"
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proof -
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  from \<open>c dvd b\<close> obtain k where "b = c * k"
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    by (rule dvdE)
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  have "a mod b mod c = a mod (c * k) mod c"
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    by (simp only: \<open>b = c * k\<close>)
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  also have "\<dots> = (a mod (c * k) + a div (c * k) * k * c) mod c"
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    by (simp only: mod_mult_self1)
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  also have "\<dots> = (a div (c * k) * (c * k) + a mod (c * k)) mod c"
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    by (simp only: ac_simps)
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  also have "\<dots> = a mod c"
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    by (simp only: div_mult_mod_eq)
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  finally show ?thesis .
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qed
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lemma div_mult_mult2 [simp]:
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  "c \<noteq> 0 \<Longrightarrow> (a * c) div (b * c) = a div b"
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  by (drule div_mult_mult1) (simp add: mult.commute)
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lemma div_mult_mult1_if [simp]:
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  "(c * a) div (c * b) = (if c = 0 then 0 else a div b)"
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  by simp_all
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lemma mod_mult_mult1:
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  "(c * a) mod (c * b) = c * (a mod b)"
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proof (cases "c = 0")
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  case True then show ?thesis by simp
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next
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  case False
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  from div_mult_mod_eq
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  have "((c * a) div (c * b)) * (c * b) + (c * a) mod (c * b) = c * a" .
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  with False have "c * ((a div b) * b + a mod b) + (c * a) mod (c * b)
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    = c * a + c * (a mod b)" by (simp add: algebra_simps)
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  with div_mult_mod_eq show ?thesis by simp
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qed
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lemma mod_mult_mult2:
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  "(a * c) mod (b * c) = (a mod b) * c"
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  using mod_mult_mult1 [of c a b] by (simp add: mult.commute)
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lemma mult_mod_left: "(a mod b) * c = (a * c) mod (b * c)"
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  by (fact mod_mult_mult2 [symmetric])
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lemma mult_mod_right: "c * (a mod b) = (c * a) mod (c * b)"
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  by (fact mod_mult_mult1 [symmetric])
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   319
lemma dvd_mod: "k dvd m \<Longrightarrow> k dvd n \<Longrightarrow> k dvd (m mod n)"
huffman@31662
   320
  unfolding dvd_def by (auto simp add: mod_mult_mult1)
huffman@31662
   321
huffman@31662
   322
lemma dvd_mod_iff: "k dvd n \<Longrightarrow> k dvd (m mod n) \<longleftrightarrow> k dvd m"
huffman@31662
   323
by (blast intro: dvd_mod_imp_dvd dvd_mod)
huffman@31662
   324
eberlm@63317
   325
lemma div_div_eq_right:
eberlm@63317
   326
  assumes "c dvd b" "b dvd a"
eberlm@63317
   327
  shows   "a div (b div c) = a div b * c"
eberlm@63317
   328
proof -
eberlm@63317
   329
  from assms have "a div b * c = (a * c) div b"
eberlm@63317
   330
    by (subst dvd_div_mult) simp_all
eberlm@63317
   331
  also from assms have "\<dots> = (a * c) div ((b div c) * c)" by simp
eberlm@63317
   332
  also have "a * c div (b div c * c) = a div (b div c)"
eberlm@63317
   333
    by (cases "c = 0") simp_all
eberlm@63317
   334
  finally show ?thesis ..
eberlm@63317
   335
qed
eberlm@63317
   336
eberlm@63317
   337
lemma div_div_div_same:
eberlm@63317
   338
  assumes "d dvd a" "d dvd b" "b dvd a"
eberlm@63317
   339
  shows   "(a div d) div (b div d) = a div b"
eberlm@63317
   340
  using assms by (subst dvd_div_mult2_eq [symmetric]) simp_all
eberlm@63317
   341
haftmann@64250
   342
lemma cancel_div_mod_rules:
haftmann@64250
   343
  "((a div b) * b + a mod b) + c = a + c"
haftmann@64250
   344
  "(b * (a div b) + a mod b) + c = a + c"
haftmann@64250
   345
  by (simp_all add: div_mult_mod_eq mult_div_mod_eq)
haftmann@64250
   346
huffman@31661
   347
end
huffman@31661
   348
haftmann@59833
   349
class ring_div = comm_ring_1 + semiring_div
huffman@29405
   350
begin
huffman@29405
   351
haftmann@60353
   352
subclass idom_divide ..
haftmann@36634
   353
wenzelm@60758
   354
text \<open>Negation respects modular equivalence.\<close>
huffman@29405
   355
huffman@29405
   356
lemma mod_minus_eq: "(- a) mod b = (- (a mod b)) mod b"
huffman@29405
   357
proof -
huffman@29405
   358
  have "(- a) mod b = (- (a div b * b + a mod b)) mod b"
haftmann@64242
   359
    by (simp only: div_mult_mod_eq)
huffman@29405
   360
  also have "\<dots> = (- (a mod b) + - (a div b) * b) mod b"
haftmann@57514
   361
    by (simp add: ac_simps)
huffman@29405
   362
  also have "\<dots> = (- (a mod b)) mod b"
huffman@29405
   363
    by (rule mod_mult_self1)
huffman@29405
   364
  finally show ?thesis .
huffman@29405
   365
qed
huffman@29405
   366
huffman@29405
   367
lemma mod_minus_cong:
huffman@29405
   368
  assumes "a mod b = a' mod b"
huffman@29405
   369
  shows "(- a) mod b = (- a') mod b"
huffman@29405
   370
proof -
huffman@29405
   371
  have "(- (a mod b)) mod b = (- (a' mod b)) mod b"
huffman@29405
   372
    unfolding assms ..
huffman@29405
   373
  thus ?thesis
huffman@29405
   374
    by (simp only: mod_minus_eq [symmetric])
huffman@29405
   375
qed
huffman@29405
   376
wenzelm@60758
   377
text \<open>Subtraction respects modular equivalence.\<close>
huffman@29405
   378
haftmann@54230
   379
lemma mod_diff_left_eq:
haftmann@54230
   380
  "(a - b) mod c = (a mod c - b) mod c"
haftmann@54230
   381
  using mod_add_cong [of a c "a mod c" "- b" "- b"] by simp
haftmann@54230
   382
haftmann@54230
   383
lemma mod_diff_right_eq:
haftmann@54230
   384
  "(a - b) mod c = (a - b mod c) mod c"
haftmann@54230
   385
  using mod_add_cong [of a c a "- b" "- (b mod c)"] mod_minus_cong [of "b mod c" c b] by simp
haftmann@54230
   386
haftmann@54230
   387
lemma mod_diff_eq:
haftmann@54230
   388
  "(a - b) mod c = (a mod c - b mod c) mod c"
haftmann@54230
   389
  using mod_add_cong [of a c "a mod c" "- b" "- (b mod c)"] mod_minus_cong [of "b mod c" c b] by simp
huffman@29405
   390
huffman@29405
   391
lemma mod_diff_cong:
huffman@29405
   392
  assumes "a mod c = a' mod c"
huffman@29405
   393
  assumes "b mod c = b' mod c"
huffman@29405
   394
  shows "(a - b) mod c = (a' - b') mod c"
haftmann@54230
   395
  using assms mod_add_cong [of a c a' "- b" "- b'"] mod_minus_cong [of b c "b'"] by simp
huffman@29405
   396
nipkow@30180
   397
lemma dvd_neg_div: "y dvd x \<Longrightarrow> -x div y = - (x div y)"
nipkow@30180
   398
apply (case_tac "y = 0") apply simp
nipkow@30180
   399
apply (auto simp add: dvd_def)
nipkow@30180
   400
apply (subgoal_tac "-(y * k) = y * - k")
thomas@57492
   401
 apply (simp only:)
haftmann@64240
   402
 apply (erule nonzero_mult_div_cancel_left)
nipkow@30180
   403
apply simp
nipkow@30180
   404
done
nipkow@30180
   405
nipkow@30180
   406
lemma dvd_div_neg: "y dvd x \<Longrightarrow> x div -y = - (x div y)"
nipkow@30180
   407
apply (case_tac "y = 0") apply simp
nipkow@30180
   408
apply (auto simp add: dvd_def)
nipkow@30180
   409
apply (subgoal_tac "y * k = -y * -k")
haftmann@64240
   410
 apply (erule ssubst, rule nonzero_mult_div_cancel_left)
nipkow@30180
   411
 apply simp
nipkow@30180
   412
apply simp
nipkow@30180
   413
done
nipkow@30180
   414
haftmann@60867
   415
lemma div_diff [simp]:
haftmann@60867
   416
  "z dvd x \<Longrightarrow> z dvd y \<Longrightarrow> (x - y) div z = x div z - y div z"
haftmann@60867
   417
  using div_add [of _ _ "- y"] by (simp add: dvd_neg_div)
nipkow@59380
   418
huffman@47159
   419
lemma div_minus_minus [simp]: "(-a) div (-b) = a div b"
huffman@47159
   420
  using div_mult_mult1 [of "- 1" a b]
huffman@47159
   421
  unfolding neg_equal_0_iff_equal by simp
huffman@47159
   422
huffman@47159
   423
lemma mod_minus_minus [simp]: "(-a) mod (-b) = - (a mod b)"
huffman@47159
   424
  using mod_mult_mult1 [of "- 1" a b] by simp
huffman@47159
   425
huffman@47159
   426
lemma div_minus_right: "a div (-b) = (-a) div b"
huffman@47159
   427
  using div_minus_minus [of "-a" b] by simp
huffman@47159
   428
huffman@47159
   429
lemma mod_minus_right: "a mod (-b) = - ((-a) mod b)"
huffman@47159
   430
  using mod_minus_minus [of "-a" b] by simp
huffman@47159
   431
huffman@47160
   432
lemma div_minus1_right [simp]: "a div (-1) = -a"
huffman@47160
   433
  using div_minus_right [of a 1] by simp
huffman@47160
   434
huffman@47160
   435
lemma mod_minus1_right [simp]: "a mod (-1) = 0"
huffman@47160
   436
  using mod_minus_right [of a 1] by simp
huffman@47160
   437
lp15@60562
   438
lemma minus_mod_self2 [simp]:
haftmann@54221
   439
  "(a - b) mod b = a mod b"
haftmann@54221
   440
  by (simp add: mod_diff_right_eq)
haftmann@54221
   441
lp15@60562
   442
lemma minus_mod_self1 [simp]:
haftmann@54221
   443
  "(b - a) mod b = - a mod b"
haftmann@54230
   444
  using mod_add_self2 [of "- a" b] by simp
haftmann@54221
   445
huffman@29405
   446
end
huffman@29405
   447
haftmann@58778
   448
wenzelm@60758
   449
subsubsection \<open>Parity and division\<close>
haftmann@58778
   450
lp15@60562
   451
class semiring_div_parity = semiring_div + comm_semiring_1_cancel + numeral +
haftmann@54226
   452
  assumes parity: "a mod 2 = 0 \<or> a mod 2 = 1"
haftmann@58786
   453
  assumes one_mod_two_eq_one [simp]: "1 mod 2 = 1"
haftmann@58710
   454
  assumes zero_not_eq_two: "0 \<noteq> 2"
haftmann@54226
   455
begin
haftmann@54226
   456
haftmann@54226
   457
lemma parity_cases [case_names even odd]:
haftmann@54226
   458
  assumes "a mod 2 = 0 \<Longrightarrow> P"
haftmann@54226
   459
  assumes "a mod 2 = 1 \<Longrightarrow> P"
haftmann@54226
   460
  shows P
haftmann@54226
   461
  using assms parity by blast
haftmann@54226
   462
haftmann@58786
   463
lemma one_div_two_eq_zero [simp]:
haftmann@58778
   464
  "1 div 2 = 0"
haftmann@58778
   465
proof (cases "2 = 0")
haftmann@58778
   466
  case True then show ?thesis by simp
haftmann@58778
   467
next
haftmann@58778
   468
  case False
haftmann@64242
   469
  from div_mult_mod_eq have "1 div 2 * 2 + 1 mod 2 = 1" .
haftmann@58778
   470
  with one_mod_two_eq_one have "1 div 2 * 2 + 1 = 1" by simp
haftmann@58953
   471
  then have "1 div 2 * 2 = 0" by (simp add: ac_simps add_left_imp_eq del: mult_eq_0_iff)
haftmann@58953
   472
  then have "1 div 2 = 0 \<or> 2 = 0" by simp
haftmann@58778
   473
  with False show ?thesis by auto
haftmann@58778
   474
qed
haftmann@58778
   475
haftmann@58786
   476
lemma not_mod_2_eq_0_eq_1 [simp]:
haftmann@58786
   477
  "a mod 2 \<noteq> 0 \<longleftrightarrow> a mod 2 = 1"
haftmann@58786
   478
  by (cases a rule: parity_cases) simp_all
haftmann@58786
   479
haftmann@58786
   480
lemma not_mod_2_eq_1_eq_0 [simp]:
haftmann@58786
   481
  "a mod 2 \<noteq> 1 \<longleftrightarrow> a mod 2 = 0"
haftmann@58786
   482
  by (cases a rule: parity_cases) simp_all
haftmann@58786
   483
haftmann@58778
   484
subclass semiring_parity
haftmann@58778
   485
proof (unfold_locales, unfold dvd_eq_mod_eq_0 not_mod_2_eq_0_eq_1)
haftmann@58778
   486
  show "1 mod 2 = 1"
haftmann@58778
   487
    by (fact one_mod_two_eq_one)
haftmann@58778
   488
next
haftmann@58778
   489
  fix a b
haftmann@58778
   490
  assume "a mod 2 = 1"
haftmann@58778
   491
  moreover assume "b mod 2 = 1"
haftmann@58778
   492
  ultimately show "(a + b) mod 2 = 0"
haftmann@58778
   493
    using mod_add_eq [of a b 2] by simp
haftmann@58778
   494
next
haftmann@58778
   495
  fix a b
haftmann@58778
   496
  assume "(a * b) mod 2 = 0"
haftmann@58778
   497
  then have "(a mod 2) * (b mod 2) = 0"
haftmann@58778
   498
    by (cases "a mod 2 = 0") (simp_all add: mod_mult_eq [of a b 2])
haftmann@58778
   499
  then show "a mod 2 = 0 \<or> b mod 2 = 0"
haftmann@58778
   500
    by (rule divisors_zero)
haftmann@58778
   501
next
haftmann@58778
   502
  fix a
haftmann@58778
   503
  assume "a mod 2 = 1"
haftmann@64242
   504
  then have "a = a div 2 * 2 + 1" using div_mult_mod_eq [of a 2] by simp
haftmann@58778
   505
  then show "\<exists>b. a = b + 1" ..
haftmann@58778
   506
qed
haftmann@58778
   507
haftmann@58778
   508
lemma even_iff_mod_2_eq_zero:
haftmann@58778
   509
  "even a \<longleftrightarrow> a mod 2 = 0"
haftmann@58778
   510
  by (fact dvd_eq_mod_eq_0)
haftmann@58778
   511
haftmann@64014
   512
lemma odd_iff_mod_2_eq_one:
haftmann@64014
   513
  "odd a \<longleftrightarrow> a mod 2 = 1"
haftmann@64014
   514
  by (auto simp add: even_iff_mod_2_eq_zero)
haftmann@64014
   515
haftmann@58778
   516
lemma even_succ_div_two [simp]:
haftmann@58778
   517
  "even a \<Longrightarrow> (a + 1) div 2 = a div 2"
haftmann@58778
   518
  by (cases "a = 0") (auto elim!: evenE dest: mult_not_zero)
haftmann@58778
   519
haftmann@58778
   520
lemma odd_succ_div_two [simp]:
haftmann@58778
   521
  "odd a \<Longrightarrow> (a + 1) div 2 = a div 2 + 1"
haftmann@58778
   522
  by (auto elim!: oddE simp add: zero_not_eq_two [symmetric] add.assoc)
haftmann@58778
   523
haftmann@58778
   524
lemma even_two_times_div_two:
haftmann@58778
   525
  "even a \<Longrightarrow> 2 * (a div 2) = a"
haftmann@58778
   526
  by (fact dvd_mult_div_cancel)
haftmann@58778
   527
haftmann@58834
   528
lemma odd_two_times_div_two_succ [simp]:
haftmann@58778
   529
  "odd a \<Longrightarrow> 2 * (a div 2) + 1 = a"
haftmann@64242
   530
  using mult_div_mod_eq [of 2 a] by (simp add: even_iff_mod_2_eq_zero)
haftmann@60868
   531
 
haftmann@54226
   532
end
haftmann@54226
   533
haftmann@25942
   534
wenzelm@60758
   535
subsection \<open>Generic numeral division with a pragmatic type class\<close>
wenzelm@60758
   536
wenzelm@60758
   537
text \<open>
haftmann@53067
   538
  The following type class contains everything necessary to formulate
haftmann@53067
   539
  a division algorithm in ring structures with numerals, restricted
haftmann@53067
   540
  to its positive segments.  This is its primary motiviation, and it
haftmann@53067
   541
  could surely be formulated using a more fine-grained, more algebraic
haftmann@53067
   542
  and less technical class hierarchy.
wenzelm@60758
   543
\<close>
haftmann@53067
   544
lp15@60562
   545
class semiring_numeral_div = semiring_div + comm_semiring_1_cancel + linordered_semidom +
haftmann@59816
   546
  assumes div_less: "0 \<le> a \<Longrightarrow> a < b \<Longrightarrow> a div b = 0"
haftmann@53067
   547
    and mod_less: " 0 \<le> a \<Longrightarrow> a < b \<Longrightarrow> a mod b = a"
haftmann@53067
   548
    and div_positive: "0 < b \<Longrightarrow> b \<le> a \<Longrightarrow> a div b > 0"
haftmann@53067
   549
    and mod_less_eq_dividend: "0 \<le> a \<Longrightarrow> a mod b \<le> a"
haftmann@53067
   550
    and pos_mod_bound: "0 < b \<Longrightarrow> a mod b < b"
haftmann@53067
   551
    and pos_mod_sign: "0 < b \<Longrightarrow> 0 \<le> a mod b"
haftmann@53067
   552
    and mod_mult2_eq: "0 \<le> c \<Longrightarrow> a mod (b * c) = b * (a div b mod c) + a mod b"
haftmann@53067
   553
    and div_mult2_eq: "0 \<le> c \<Longrightarrow> a div (b * c) = a div b div c"
haftmann@53067
   554
  assumes discrete: "a < b \<longleftrightarrow> a + 1 \<le> b"
haftmann@61275
   555
  fixes divmod :: "num \<Rightarrow> num \<Rightarrow> 'a \<times> 'a"
haftmann@61275
   556
    and divmod_step :: "num \<Rightarrow> 'a \<times> 'a \<Rightarrow> 'a \<times> 'a"
haftmann@61275
   557
  assumes divmod_def: "divmod m n = (numeral m div numeral n, numeral m mod numeral n)"
haftmann@61275
   558
    and divmod_step_def: "divmod_step l qr = (let (q, r) = qr
haftmann@61275
   559
    in if r \<ge> numeral l then (2 * q + 1, r - numeral l)
haftmann@61275
   560
    else (2 * q, r))"
wenzelm@61799
   561
    \<comment> \<open>These are conceptually definitions but force generated code
haftmann@61275
   562
    to be monomorphic wrt. particular instances of this class which
haftmann@61275
   563
    yields a significant speedup.\<close>
haftmann@61275
   564
haftmann@53067
   565
begin
haftmann@53067
   566
haftmann@54226
   567
subclass semiring_div_parity
haftmann@54226
   568
proof
haftmann@54226
   569
  fix a
haftmann@54226
   570
  show "a mod 2 = 0 \<or> a mod 2 = 1"
haftmann@54226
   571
  proof (rule ccontr)
haftmann@54226
   572
    assume "\<not> (a mod 2 = 0 \<or> a mod 2 = 1)"
haftmann@54226
   573
    then have "a mod 2 \<noteq> 0" and "a mod 2 \<noteq> 1" by simp_all
haftmann@54226
   574
    have "0 < 2" by simp
haftmann@54226
   575
    with pos_mod_bound pos_mod_sign have "0 \<le> a mod 2" "a mod 2 < 2" by simp_all
wenzelm@60758
   576
    with \<open>a mod 2 \<noteq> 0\<close> have "0 < a mod 2" by simp
haftmann@54226
   577
    with discrete have "1 \<le> a mod 2" by simp
wenzelm@60758
   578
    with \<open>a mod 2 \<noteq> 1\<close> have "1 < a mod 2" by simp
haftmann@54226
   579
    with discrete have "2 \<le> a mod 2" by simp
wenzelm@60758
   580
    with \<open>a mod 2 < 2\<close> show False by simp
haftmann@54226
   581
  qed
haftmann@58646
   582
next
haftmann@58646
   583
  show "1 mod 2 = 1"
haftmann@58646
   584
    by (rule mod_less) simp_all
haftmann@58710
   585
next
haftmann@58710
   586
  show "0 \<noteq> 2"
haftmann@58710
   587
    by simp
haftmann@53067
   588
qed
haftmann@53067
   589
haftmann@53067
   590
lemma divmod_digit_1:
haftmann@53067
   591
  assumes "0 \<le> a" "0 < b" and "b \<le> a mod (2 * b)"
haftmann@53067
   592
  shows "2 * (a div (2 * b)) + 1 = a div b" (is "?P")
haftmann@53067
   593
    and "a mod (2 * b) - b = a mod b" (is "?Q")
haftmann@53067
   594
proof -
haftmann@53067
   595
  from assms mod_less_eq_dividend [of a "2 * b"] have "b \<le> a"
haftmann@53067
   596
    by (auto intro: trans)
wenzelm@60758
   597
  with \<open>0 < b\<close> have "0 < a div b" by (auto intro: div_positive)
haftmann@53067
   598
  then have [simp]: "1 \<le> a div b" by (simp add: discrete)
wenzelm@60758
   599
  with \<open>0 < b\<close> have mod_less: "a mod b < b" by (simp add: pos_mod_bound)
wenzelm@63040
   600
  define w where "w = a div b mod 2"
wenzelm@63040
   601
  with parity have w_exhaust: "w = 0 \<or> w = 1" by auto
haftmann@53067
   602
  have mod_w: "a mod (2 * b) = a mod b + b * w"
haftmann@53067
   603
    by (simp add: w_def mod_mult2_eq ac_simps)
haftmann@53067
   604
  from assms w_exhaust have "w = 1"
haftmann@53067
   605
    by (auto simp add: mod_w) (insert mod_less, auto)
haftmann@53067
   606
  with mod_w have mod: "a mod (2 * b) = a mod b + b" by simp
haftmann@53067
   607
  have "2 * (a div (2 * b)) = a div b - w"
haftmann@64246
   608
    by (simp add: w_def div_mult2_eq minus_mod_eq_mult_div ac_simps)
wenzelm@60758
   609
  with \<open>w = 1\<close> have div: "2 * (a div (2 * b)) = a div b - 1" by simp
haftmann@53067
   610
  then show ?P and ?Q
haftmann@60867
   611
    by (simp_all add: div mod add_implies_diff [symmetric])
haftmann@53067
   612
qed
haftmann@53067
   613
haftmann@53067
   614
lemma divmod_digit_0:
haftmann@53067
   615
  assumes "0 < b" and "a mod (2 * b) < b"
haftmann@53067
   616
  shows "2 * (a div (2 * b)) = a div b" (is "?P")
haftmann@53067
   617
    and "a mod (2 * b) = a mod b" (is "?Q")
haftmann@53067
   618
proof -
wenzelm@63040
   619
  define w where "w = a div b mod 2"
wenzelm@63040
   620
  with parity have w_exhaust: "w = 0 \<or> w = 1" by auto
haftmann@53067
   621
  have mod_w: "a mod (2 * b) = a mod b + b * w"
haftmann@53067
   622
    by (simp add: w_def mod_mult2_eq ac_simps)
haftmann@53067
   623
  moreover have "b \<le> a mod b + b"
haftmann@53067
   624
  proof -
wenzelm@60758
   625
    from \<open>0 < b\<close> pos_mod_sign have "0 \<le> a mod b" by blast
haftmann@53067
   626
    then have "0 + b \<le> a mod b + b" by (rule add_right_mono)
haftmann@53067
   627
    then show ?thesis by simp
haftmann@53067
   628
  qed
haftmann@53067
   629
  moreover note assms w_exhaust
haftmann@53067
   630
  ultimately have "w = 0" by auto
haftmann@53067
   631
  with mod_w have mod: "a mod (2 * b) = a mod b" by simp
haftmann@53067
   632
  have "2 * (a div (2 * b)) = a div b - w"
haftmann@64246
   633
    by (simp add: w_def div_mult2_eq minus_mod_eq_mult_div ac_simps)
wenzelm@60758
   634
  with \<open>w = 0\<close> have div: "2 * (a div (2 * b)) = a div b" by simp
haftmann@53067
   635
  then show ?P and ?Q
haftmann@53067
   636
    by (simp_all add: div mod)
haftmann@53067
   637
qed
haftmann@53067
   638
haftmann@60867
   639
lemma fst_divmod:
haftmann@53067
   640
  "fst (divmod m n) = numeral m div numeral n"
haftmann@53067
   641
  by (simp add: divmod_def)
haftmann@53067
   642
haftmann@60867
   643
lemma snd_divmod:
haftmann@53067
   644
  "snd (divmod m n) = numeral m mod numeral n"
haftmann@53067
   645
  by (simp add: divmod_def)
haftmann@53067
   646
wenzelm@60758
   647
text \<open>
haftmann@53067
   648
  This is a formulation of one step (referring to one digit position)
haftmann@53067
   649
  in school-method division: compare the dividend at the current
haftmann@53070
   650
  digit position with the remainder from previous division steps
haftmann@53067
   651
  and evaluate accordingly.
wenzelm@60758
   652
\<close>
haftmann@53067
   653
haftmann@61275
   654
lemma divmod_step_eq [simp]:
haftmann@53067
   655
  "divmod_step l (q, r) = (if numeral l \<le> r
haftmann@53067
   656
    then (2 * q + 1, r - numeral l) else (2 * q, r))"
haftmann@53067
   657
  by (simp add: divmod_step_def)
haftmann@53067
   658
wenzelm@60758
   659
text \<open>
haftmann@53067
   660
  This is a formulation of school-method division.
haftmann@53067
   661
  If the divisor is smaller than the dividend, terminate.
haftmann@53067
   662
  If not, shift the dividend to the right until termination
haftmann@53067
   663
  occurs and then reiterate single division steps in the
haftmann@53067
   664
  opposite direction.
wenzelm@60758
   665
\<close>
haftmann@53067
   666
haftmann@60867
   667
lemma divmod_divmod_step:
haftmann@53067
   668
  "divmod m n = (if m < n then (0, numeral m)
haftmann@53067
   669
    else divmod_step n (divmod m (Num.Bit0 n)))"
haftmann@53067
   670
proof (cases "m < n")
haftmann@53067
   671
  case True then have "numeral m < numeral n" by simp
haftmann@53067
   672
  then show ?thesis
haftmann@60867
   673
    by (simp add: prod_eq_iff div_less mod_less fst_divmod snd_divmod)
haftmann@53067
   674
next
haftmann@53067
   675
  case False
haftmann@53067
   676
  have "divmod m n =
haftmann@53067
   677
    divmod_step n (numeral m div (2 * numeral n),
haftmann@53067
   678
      numeral m mod (2 * numeral n))"
haftmann@53067
   679
  proof (cases "numeral n \<le> numeral m mod (2 * numeral n)")
haftmann@53067
   680
    case True
haftmann@60867
   681
    with divmod_step_eq
haftmann@53067
   682
      have "divmod_step n (numeral m div (2 * numeral n), numeral m mod (2 * numeral n)) =
haftmann@53067
   683
        (2 * (numeral m div (2 * numeral n)) + 1, numeral m mod (2 * numeral n) - numeral n)"
haftmann@60867
   684
        by simp
haftmann@53067
   685
    moreover from True divmod_digit_1 [of "numeral m" "numeral n"]
haftmann@53067
   686
      have "2 * (numeral m div (2 * numeral n)) + 1 = numeral m div numeral n"
haftmann@53067
   687
      and "numeral m mod (2 * numeral n) - numeral n = numeral m mod numeral n"
haftmann@53067
   688
      by simp_all
haftmann@53067
   689
    ultimately show ?thesis by (simp only: divmod_def)
haftmann@53067
   690
  next
haftmann@53067
   691
    case False then have *: "numeral m mod (2 * numeral n) < numeral n"
haftmann@53067
   692
      by (simp add: not_le)
haftmann@60867
   693
    with divmod_step_eq
haftmann@53067
   694
      have "divmod_step n (numeral m div (2 * numeral n), numeral m mod (2 * numeral n)) =
haftmann@53067
   695
        (2 * (numeral m div (2 * numeral n)), numeral m mod (2 * numeral n))"
haftmann@60867
   696
        by auto
haftmann@53067
   697
    moreover from * divmod_digit_0 [of "numeral n" "numeral m"]
haftmann@53067
   698
      have "2 * (numeral m div (2 * numeral n)) = numeral m div numeral n"
haftmann@53067
   699
      and "numeral m mod (2 * numeral n) = numeral m mod numeral n"
haftmann@53067
   700
      by (simp_all only: zero_less_numeral)
haftmann@53067
   701
    ultimately show ?thesis by (simp only: divmod_def)
haftmann@53067
   702
  qed
haftmann@53067
   703
  then have "divmod m n =
haftmann@53067
   704
    divmod_step n (numeral m div numeral (Num.Bit0 n),
haftmann@53067
   705
      numeral m mod numeral (Num.Bit0 n))"
lp15@60562
   706
    by (simp only: numeral.simps distrib mult_1)
haftmann@53067
   707
  then have "divmod m n = divmod_step n (divmod m (Num.Bit0 n))"
haftmann@53067
   708
    by (simp add: divmod_def)
haftmann@53067
   709
  with False show ?thesis by simp
haftmann@53067
   710
qed
haftmann@53067
   711
wenzelm@61799
   712
text \<open>The division rewrite proper -- first, trivial results involving \<open>1\<close>\<close>
haftmann@60867
   713
haftmann@61275
   714
lemma divmod_trivial [simp]:
haftmann@60867
   715
  "divmod Num.One Num.One = (numeral Num.One, 0)"
haftmann@60867
   716
  "divmod (Num.Bit0 m) Num.One = (numeral (Num.Bit0 m), 0)"
haftmann@60867
   717
  "divmod (Num.Bit1 m) Num.One = (numeral (Num.Bit1 m), 0)"
haftmann@60867
   718
  "divmod num.One (num.Bit0 n) = (0, Numeral1)"
haftmann@60867
   719
  "divmod num.One (num.Bit1 n) = (0, Numeral1)"
haftmann@60867
   720
  using divmod_divmod_step [of "Num.One"] by (simp_all add: divmod_def)
haftmann@60867
   721
haftmann@60867
   722
text \<open>Division by an even number is a right-shift\<close>
haftmann@58953
   723
haftmann@61275
   724
lemma divmod_cancel [simp]:
haftmann@53069
   725
  "divmod (Num.Bit0 m) (Num.Bit0 n) = (case divmod m n of (q, r) \<Rightarrow> (q, 2 * r))" (is ?P)
haftmann@53069
   726
  "divmod (Num.Bit1 m) (Num.Bit0 n) = (case divmod m n of (q, r) \<Rightarrow> (q, 2 * r + 1))" (is ?Q)
haftmann@53069
   727
proof -
haftmann@53069
   728
  have *: "\<And>q. numeral (Num.Bit0 q) = 2 * numeral q"
haftmann@53069
   729
    "\<And>q. numeral (Num.Bit1 q) = 2 * numeral q + 1"
haftmann@53069
   730
    by (simp_all only: numeral_mult numeral.simps distrib) simp_all
haftmann@53069
   731
  have "1 div 2 = 0" "1 mod 2 = 1" by (auto intro: div_less mod_less)
haftmann@53069
   732
  then show ?P and ?Q
haftmann@60867
   733
    by (simp_all add: fst_divmod snd_divmod prod_eq_iff split_def * [of m] * [of n] mod_mult_mult1
haftmann@60867
   734
      div_mult2_eq [of _ _ 2] mod_mult2_eq [of _ _ 2]
haftmann@60867
   735
      add.commute del: numeral_times_numeral)
haftmann@58953
   736
qed
haftmann@58953
   737
haftmann@60867
   738
text \<open>The really hard work\<close>
haftmann@60867
   739
haftmann@61275
   740
lemma divmod_steps [simp]:
haftmann@60867
   741
  "divmod (num.Bit0 m) (num.Bit1 n) =
haftmann@60867
   742
      (if m \<le> n then (0, numeral (num.Bit0 m))
haftmann@60867
   743
       else divmod_step (num.Bit1 n)
haftmann@60867
   744
             (divmod (num.Bit0 m)
haftmann@60867
   745
               (num.Bit0 (num.Bit1 n))))"
haftmann@60867
   746
  "divmod (num.Bit1 m) (num.Bit1 n) =
haftmann@60867
   747
      (if m < n then (0, numeral (num.Bit1 m))
haftmann@60867
   748
       else divmod_step (num.Bit1 n)
haftmann@60867
   749
             (divmod (num.Bit1 m)
haftmann@60867
   750
               (num.Bit0 (num.Bit1 n))))"
haftmann@60867
   751
  by (simp_all add: divmod_divmod_step)
haftmann@60867
   752
haftmann@61275
   753
lemmas divmod_algorithm_code = divmod_step_eq divmod_trivial divmod_cancel divmod_steps  
haftmann@61275
   754
wenzelm@60758
   755
text \<open>Special case: divisibility\<close>
haftmann@58953
   756
haftmann@58953
   757
definition divides_aux :: "'a \<times> 'a \<Rightarrow> bool"
haftmann@58953
   758
where
haftmann@58953
   759
  "divides_aux qr \<longleftrightarrow> snd qr = 0"
haftmann@58953
   760
haftmann@58953
   761
lemma divides_aux_eq [simp]:
haftmann@58953
   762
  "divides_aux (q, r) \<longleftrightarrow> r = 0"
haftmann@58953
   763
  by (simp add: divides_aux_def)
haftmann@58953
   764
haftmann@58953
   765
lemma dvd_numeral_simp [simp]:
haftmann@58953
   766
  "numeral m dvd numeral n \<longleftrightarrow> divides_aux (divmod n m)"
haftmann@58953
   767
  by (simp add: divmod_def mod_eq_0_iff_dvd)
haftmann@53069
   768
haftmann@60867
   769
text \<open>Generic computation of quotient and remainder\<close>  
haftmann@60867
   770
haftmann@60867
   771
lemma numeral_div_numeral [simp]: 
haftmann@60867
   772
  "numeral k div numeral l = fst (divmod k l)"
haftmann@60867
   773
  by (simp add: fst_divmod)
haftmann@60867
   774
haftmann@60867
   775
lemma numeral_mod_numeral [simp]: 
haftmann@60867
   776
  "numeral k mod numeral l = snd (divmod k l)"
haftmann@60867
   777
  by (simp add: snd_divmod)
haftmann@60867
   778
haftmann@60867
   779
lemma one_div_numeral [simp]:
haftmann@60867
   780
  "1 div numeral n = fst (divmod num.One n)"
haftmann@60867
   781
  by (simp add: fst_divmod)
haftmann@60867
   782
haftmann@60867
   783
lemma one_mod_numeral [simp]:
haftmann@60867
   784
  "1 mod numeral n = snd (divmod num.One n)"
haftmann@60867
   785
  by (simp add: snd_divmod)
haftmann@60867
   786
  
haftmann@53067
   787
end
haftmann@53067
   788
lp15@60562
   789
wenzelm@60758
   790
subsection \<open>Division on @{typ nat}\<close>
wenzelm@60758
   791
haftmann@61433
   792
context
haftmann@61433
   793
begin
haftmann@61433
   794
wenzelm@60758
   795
text \<open>
haftmann@63950
   796
  We define @{const divide} and @{const modulo} on @{typ nat} by means
haftmann@26100
   797
  of a characteristic relation with two input arguments
wenzelm@61076
   798
  @{term "m::nat"}, @{term "n::nat"} and two output arguments
wenzelm@61076
   799
  @{term "q::nat"}(uotient) and @{term "r::nat"}(emainder).
wenzelm@60758
   800
\<close>
haftmann@26100
   801
haftmann@33340
   802
definition divmod_nat_rel :: "nat \<Rightarrow> nat \<Rightarrow> nat \<times> nat \<Rightarrow> bool" where
haftmann@33340
   803
  "divmod_nat_rel m n qr \<longleftrightarrow>
haftmann@30923
   804
    m = fst qr * n + snd qr \<and>
haftmann@30923
   805
      (if n = 0 then fst qr = 0 else if n > 0 then 0 \<le> snd qr \<and> snd qr < n else n < snd qr \<and> snd qr \<le> 0)"
haftmann@26100
   806
wenzelm@60758
   807
text \<open>@{const divmod_nat_rel} is total:\<close>
haftmann@26100
   808
haftmann@61433
   809
qualified lemma divmod_nat_rel_ex:
haftmann@33340
   810
  obtains q r where "divmod_nat_rel m n (q, r)"
haftmann@26100
   811
proof (cases "n = 0")
haftmann@30923
   812
  case True  with that show thesis
haftmann@33340
   813
    by (auto simp add: divmod_nat_rel_def)
haftmann@26100
   814
next
haftmann@26100
   815
  case False
haftmann@26100
   816
  have "\<exists>q r. m = q * n + r \<and> r < n"
haftmann@26100
   817
  proof (induct m)
wenzelm@60758
   818
    case 0 with \<open>n \<noteq> 0\<close>
wenzelm@61076
   819
    have "(0::nat) = 0 * n + 0 \<and> 0 < n" by simp
haftmann@26100
   820
    then show ?case by blast
haftmann@26100
   821
  next
haftmann@26100
   822
    case (Suc m) then obtain q' r'
haftmann@26100
   823
      where m: "m = q' * n + r'" and n: "r' < n" by auto
haftmann@26100
   824
    then show ?case proof (cases "Suc r' < n")
haftmann@26100
   825
      case True
haftmann@26100
   826
      from m n have "Suc m = q' * n + Suc r'" by simp
haftmann@26100
   827
      with True show ?thesis by blast
haftmann@26100
   828
    next
haftmann@26100
   829
      case False then have "n \<le> Suc r'" by auto
haftmann@26100
   830
      moreover from n have "Suc r' \<le> n" by auto
haftmann@26100
   831
      ultimately have "n = Suc r'" by auto
haftmann@26100
   832
      with m have "Suc m = Suc q' * n + 0" by simp
wenzelm@60758
   833
      with \<open>n \<noteq> 0\<close> show ?thesis by blast
haftmann@26100
   834
    qed
haftmann@26100
   835
  qed
haftmann@26100
   836
  with that show thesis
wenzelm@60758
   837
    using \<open>n \<noteq> 0\<close> by (auto simp add: divmod_nat_rel_def)
haftmann@26100
   838
qed
haftmann@26100
   839
wenzelm@60758
   840
text \<open>@{const divmod_nat_rel} is injective:\<close>
haftmann@26100
   841
haftmann@61433
   842
qualified lemma divmod_nat_rel_unique:
haftmann@33340
   843
  assumes "divmod_nat_rel m n qr"
haftmann@33340
   844
    and "divmod_nat_rel m n qr'"
haftmann@30923
   845
  shows "qr = qr'"
haftmann@26100
   846
proof (cases "n = 0")
haftmann@26100
   847
  case True with assms show ?thesis
haftmann@30923
   848
    by (cases qr, cases qr')
haftmann@33340
   849
      (simp add: divmod_nat_rel_def)
haftmann@26100
   850
next
haftmann@26100
   851
  case False
wenzelm@61076
   852
  have aux: "\<And>q r q' r'. q' * n + r' = q * n + r \<Longrightarrow> r < n \<Longrightarrow> q' \<le> (q::nat)"
haftmann@26100
   853
  apply (rule leI)
haftmann@26100
   854
  apply (subst less_iff_Suc_add)
haftmann@26100
   855
  apply (auto simp add: add_mult_distrib)
haftmann@26100
   856
  done
wenzelm@60758
   857
  from \<open>n \<noteq> 0\<close> assms have *: "fst qr = fst qr'"
haftmann@33340
   858
    by (auto simp add: divmod_nat_rel_def intro: order_antisym dest: aux sym)
wenzelm@53374
   859
  with assms have "snd qr = snd qr'"
haftmann@33340
   860
    by (simp add: divmod_nat_rel_def)
wenzelm@53374
   861
  with * show ?thesis by (cases qr, cases qr') simp
haftmann@26100
   862
qed
haftmann@26100
   863
wenzelm@60758
   864
text \<open>
haftmann@26100
   865
  We instantiate divisibility on the natural numbers by
haftmann@33340
   866
  means of @{const divmod_nat_rel}:
wenzelm@60758
   867
\<close>
haftmann@25942
   868
haftmann@61433
   869
qualified definition divmod_nat :: "nat \<Rightarrow> nat \<Rightarrow> nat \<times> nat" where
haftmann@37767
   870
  "divmod_nat m n = (THE qr. divmod_nat_rel m n qr)"
haftmann@30923
   871
haftmann@61433
   872
qualified lemma divmod_nat_rel_divmod_nat:
haftmann@33340
   873
  "divmod_nat_rel m n (divmod_nat m n)"
haftmann@30923
   874
proof -
haftmann@33340
   875
  from divmod_nat_rel_ex
haftmann@33340
   876
    obtain qr where rel: "divmod_nat_rel m n qr" .
haftmann@30923
   877
  then show ?thesis
haftmann@33340
   878
  by (auto simp add: divmod_nat_def intro: theI elim: divmod_nat_rel_unique)
haftmann@30923
   879
qed
haftmann@30923
   880
haftmann@61433
   881
qualified lemma divmod_nat_unique:
lp15@60562
   882
  assumes "divmod_nat_rel m n qr"
haftmann@33340
   883
  shows "divmod_nat m n = qr"
haftmann@33340
   884
  using assms by (auto intro: divmod_nat_rel_unique divmod_nat_rel_divmod_nat)
haftmann@26100
   885
haftmann@61433
   886
qualified lemma divmod_nat_zero: "divmod_nat m 0 = (0, m)"
haftmann@61433
   887
  by (simp add: Divides.divmod_nat_unique divmod_nat_rel_def)
haftmann@61433
   888
haftmann@61433
   889
qualified lemma divmod_nat_zero_left: "divmod_nat 0 n = (0, 0)"
haftmann@61433
   890
  by (simp add: Divides.divmod_nat_unique divmod_nat_rel_def)
haftmann@61433
   891
haftmann@61433
   892
qualified lemma divmod_nat_base: "m < n \<Longrightarrow> divmod_nat m n = (0, m)"
haftmann@61433
   893
  by (simp add: divmod_nat_unique divmod_nat_rel_def)
haftmann@61433
   894
haftmann@61433
   895
qualified lemma divmod_nat_step:
haftmann@61433
   896
  assumes "0 < n" and "n \<le> m"
haftmann@61433
   897
  shows "divmod_nat m n = apfst Suc (divmod_nat (m - n) n)"
haftmann@61433
   898
proof (rule divmod_nat_unique)
haftmann@61433
   899
  have "divmod_nat_rel (m - n) n (divmod_nat (m - n) n)"
haftmann@61433
   900
    by (fact divmod_nat_rel_divmod_nat)
haftmann@61433
   901
  then show "divmod_nat_rel m n (apfst Suc (divmod_nat (m - n) n))"
haftmann@61433
   902
    unfolding divmod_nat_rel_def using assms by auto
haftmann@61433
   903
qed
haftmann@61433
   904
haftmann@61433
   905
end
haftmann@61433
   906
  
haftmann@60429
   907
instantiation nat :: semiring_div
haftmann@60352
   908
begin
haftmann@60352
   909
haftmann@60352
   910
definition divide_nat where
haftmann@61433
   911
  div_nat_def: "m div n = fst (Divides.divmod_nat m n)"
haftmann@60352
   912
haftmann@63950
   913
definition modulo_nat where
haftmann@63950
   914
  mod_nat_def: "m mod n = snd (Divides.divmod_nat m n)"
huffman@46551
   915
huffman@46551
   916
lemma fst_divmod_nat [simp]:
haftmann@61433
   917
  "fst (Divides.divmod_nat m n) = m div n"
huffman@46551
   918
  by (simp add: div_nat_def)
huffman@46551
   919
huffman@46551
   920
lemma snd_divmod_nat [simp]:
haftmann@61433
   921
  "snd (Divides.divmod_nat m n) = m mod n"
huffman@46551
   922
  by (simp add: mod_nat_def)
huffman@46551
   923
haftmann@33340
   924
lemma divmod_nat_div_mod:
haftmann@61433
   925
  "Divides.divmod_nat m n = (m div n, m mod n)"
huffman@46551
   926
  by (simp add: prod_eq_iff)
haftmann@26100
   927
huffman@47135
   928
lemma div_nat_unique:
lp15@60562
   929
  assumes "divmod_nat_rel m n (q, r)"
haftmann@26100
   930
  shows "m div n = q"
haftmann@61433
   931
  using assms by (auto dest!: Divides.divmod_nat_unique simp add: prod_eq_iff)
huffman@47135
   932
huffman@47135
   933
lemma mod_nat_unique:
lp15@60562
   934
  assumes "divmod_nat_rel m n (q, r)"
haftmann@26100
   935
  shows "m mod n = r"
haftmann@61433
   936
  using assms by (auto dest!: Divides.divmod_nat_unique simp add: prod_eq_iff)
haftmann@25571
   937
haftmann@33340
   938
lemma divmod_nat_rel: "divmod_nat_rel m n (m div n, m mod n)"
haftmann@61433
   939
  using Divides.divmod_nat_rel_divmod_nat by (simp add: divmod_nat_div_mod)
haftmann@25942
   940
haftmann@63950
   941
text \<open>The ''recursion'' equations for @{const divide} and @{const modulo}\<close>
haftmann@26100
   942
haftmann@26100
   943
lemma div_less [simp]:
haftmann@26100
   944
  fixes m n :: nat
haftmann@26100
   945
  assumes "m < n"
haftmann@26100
   946
  shows "m div n = 0"
haftmann@61433
   947
  using assms Divides.divmod_nat_base by (simp add: prod_eq_iff)
haftmann@25942
   948
haftmann@26100
   949
lemma le_div_geq:
haftmann@26100
   950
  fixes m n :: nat
haftmann@26100
   951
  assumes "0 < n" and "n \<le> m"
haftmann@26100
   952
  shows "m div n = Suc ((m - n) div n)"
haftmann@61433
   953
  using assms Divides.divmod_nat_step by (simp add: prod_eq_iff)
paulson@14267
   954
haftmann@26100
   955
lemma mod_less [simp]:
haftmann@26100
   956
  fixes m n :: nat
haftmann@26100
   957
  assumes "m < n"
haftmann@26100
   958
  shows "m mod n = m"
haftmann@61433
   959
  using assms Divides.divmod_nat_base by (simp add: prod_eq_iff)
haftmann@26100
   960
haftmann@26100
   961
lemma le_mod_geq:
haftmann@26100
   962
  fixes m n :: nat
haftmann@26100
   963
  assumes "n \<le> m"
haftmann@26100
   964
  shows "m mod n = (m - n) mod n"
haftmann@61433
   965
  using assms Divides.divmod_nat_step by (cases "n = 0") (simp_all add: prod_eq_iff)
paulson@14267
   966
huffman@47136
   967
instance proof
huffman@47136
   968
  fix m n :: nat
huffman@47136
   969
  show "m div n * n + m mod n = m"
huffman@47136
   970
    using divmod_nat_rel [of m n] by (simp add: divmod_nat_rel_def)
huffman@47136
   971
next
huffman@47136
   972
  fix m n q :: nat
huffman@47136
   973
  assume "n \<noteq> 0"
huffman@47136
   974
  then show "(q + m * n) div n = m + q div n"
huffman@47136
   975
    by (induct m) (simp_all add: le_div_geq)
huffman@47136
   976
next
huffman@47136
   977
  fix m n q :: nat
huffman@47136
   978
  assume "m \<noteq> 0"
huffman@47136
   979
  hence "\<And>a b. divmod_nat_rel n q (a, b) \<Longrightarrow> divmod_nat_rel (m * n) (m * q) (a, m * b)"
huffman@47136
   980
    unfolding divmod_nat_rel_def
nipkow@62390
   981
    by (auto split: if_split_asm, simp_all add: algebra_simps)
huffman@47136
   982
  moreover from divmod_nat_rel have "divmod_nat_rel n q (n div q, n mod q)" .
huffman@47136
   983
  ultimately have "divmod_nat_rel (m * n) (m * q) (n div q, m * (n mod q))" .
huffman@47136
   984
  thus "(m * n) div (m * q) = n div q" by (rule div_nat_unique)
huffman@47136
   985
next
huffman@47136
   986
  fix n :: nat show "n div 0 = 0"
haftmann@61433
   987
    by (simp add: div_nat_def Divides.divmod_nat_zero)
huffman@47136
   988
next
huffman@47136
   989
  fix n :: nat show "0 div n = 0"
haftmann@61433
   990
    by (simp add: div_nat_def Divides.divmod_nat_zero_left)
haftmann@25942
   991
qed
haftmann@26100
   992
haftmann@25942
   993
end
paulson@14267
   994
haftmann@60685
   995
instantiation nat :: normalization_semidom
haftmann@60685
   996
begin
haftmann@60685
   997
haftmann@60685
   998
definition normalize_nat
haftmann@60685
   999
  where [simp]: "normalize = (id :: nat \<Rightarrow> nat)"
haftmann@60685
  1000
haftmann@60685
  1001
definition unit_factor_nat
haftmann@60685
  1002
  where "unit_factor n = (if n = 0 then 0 else 1 :: nat)"
haftmann@60685
  1003
haftmann@60685
  1004
lemma unit_factor_simps [simp]:
haftmann@60685
  1005
  "unit_factor 0 = (0::nat)"
haftmann@60685
  1006
  "unit_factor (Suc n) = 1"
haftmann@60685
  1007
  by (simp_all add: unit_factor_nat_def)
haftmann@60685
  1008
haftmann@60685
  1009
instance
haftmann@60685
  1010
  by standard (simp_all add: unit_factor_nat_def)
haftmann@60685
  1011
  
haftmann@60685
  1012
end
haftmann@60685
  1013
haftmann@61433
  1014
lemma divmod_nat_if [code]:
haftmann@61433
  1015
  "Divides.divmod_nat m n = (if n = 0 \<or> m < n then (0, m) else
haftmann@61433
  1016
    let (q, r) = Divides.divmod_nat (m - n) n in (Suc q, r))"
blanchet@55414
  1017
  by (simp add: prod_eq_iff case_prod_beta not_less le_div_geq le_mod_geq)
haftmann@33361
  1018
haftmann@63950
  1019
text \<open>Simproc for cancelling @{const divide} and @{const modulo}\<close>
haftmann@25942
  1020
wenzelm@51299
  1021
ML_file "~~/src/Provers/Arith/cancel_div_mod.ML"
wenzelm@51299
  1022
wenzelm@60758
  1023
ML \<open>
wenzelm@43594
  1024
structure Cancel_Div_Mod_Nat = Cancel_Div_Mod
wenzelm@41550
  1025
(
haftmann@60352
  1026
  val div_name = @{const_name divide};
haftmann@63950
  1027
  val mod_name = @{const_name modulo};
haftmann@30934
  1028
  val mk_binop = HOLogic.mk_binop;
huffman@48561
  1029
  val mk_plus = HOLogic.mk_binop @{const_name Groups.plus};
huffman@48561
  1030
  val dest_plus = HOLogic.dest_bin @{const_name Groups.plus} HOLogic.natT;
huffman@48561
  1031
  fun mk_sum [] = HOLogic.zero
huffman@48561
  1032
    | mk_sum [t] = t
huffman@48561
  1033
    | mk_sum (t :: ts) = mk_plus (t, mk_sum ts);
huffman@48561
  1034
  fun dest_sum tm =
huffman@48561
  1035
    if HOLogic.is_zero tm then []
huffman@48561
  1036
    else
huffman@48561
  1037
      (case try HOLogic.dest_Suc tm of
huffman@48561
  1038
        SOME t => HOLogic.Suc_zero :: dest_sum t
huffman@48561
  1039
      | NONE =>
huffman@48561
  1040
          (case try dest_plus tm of
huffman@48561
  1041
            SOME (t, u) => dest_sum t @ dest_sum u
huffman@48561
  1042
          | NONE => [tm]));
haftmann@25942
  1043
haftmann@64250
  1044
  val div_mod_eqs = map mk_meta_eq @{thms cancel_div_mod_rules};
haftmann@64250
  1045
haftmann@64250
  1046
  val prove_eq_sums = Arith_Data.prove_conv2 all_tac
haftmann@64250
  1047
    (Arith_Data.simp_all_tac @{thms add_0_left add_0_right ac_simps})
wenzelm@41550
  1048
)
wenzelm@60758
  1049
\<close>
wenzelm@60758
  1050
wenzelm@60758
  1051
simproc_setup cancel_div_mod_nat ("(m::nat) + n") = \<open>K Cancel_Div_Mod_Nat.proc\<close>
wenzelm@60758
  1052
wenzelm@60758
  1053
wenzelm@60758
  1054
subsubsection \<open>Quotient\<close>
haftmann@26100
  1055
haftmann@26100
  1056
lemma div_geq: "0 < n \<Longrightarrow>  \<not> m < n \<Longrightarrow> m div n = Suc ((m - n) div n)"
nipkow@29667
  1057
by (simp add: le_div_geq linorder_not_less)
haftmann@26100
  1058
haftmann@26100
  1059
lemma div_if: "0 < n \<Longrightarrow> m div n = (if m < n then 0 else Suc ((m - n) div n))"
nipkow@29667
  1060
by (simp add: div_geq)
haftmann@26100
  1061
haftmann@26100
  1062
lemma div_mult_self_is_m [simp]: "0<n ==> (m*n) div n = (m::nat)"
nipkow@29667
  1063
by simp
haftmann@26100
  1064
haftmann@26100
  1065
lemma div_mult_self1_is_m [simp]: "0<n ==> (n*m) div n = (m::nat)"
nipkow@29667
  1066
by simp
haftmann@26100
  1067
haftmann@53066
  1068
lemma div_positive:
haftmann@53066
  1069
  fixes m n :: nat
haftmann@53066
  1070
  assumes "n > 0"
haftmann@53066
  1071
  assumes "m \<ge> n"
haftmann@53066
  1072
  shows "m div n > 0"
haftmann@53066
  1073
proof -
wenzelm@60758
  1074
  from \<open>m \<ge> n\<close> obtain q where "m = n + q"
haftmann@53066
  1075
    by (auto simp add: le_iff_add)
eberlm@63499
  1076
  with \<open>n > 0\<close> show ?thesis by (simp add: div_add_self1)
haftmann@53066
  1077
qed
haftmann@53066
  1078
hoelzl@59000
  1079
lemma div_eq_0_iff: "(a div b::nat) = 0 \<longleftrightarrow> a < b \<or> b = 0"
hoelzl@59000
  1080
  by (metis div_less div_positive div_by_0 gr0I less_numeral_extra(3) not_less)
haftmann@25942
  1081
wenzelm@60758
  1082
subsubsection \<open>Remainder\<close>
haftmann@25942
  1083
haftmann@26100
  1084
lemma mod_less_divisor [simp]:
haftmann@26100
  1085
  fixes m n :: nat
haftmann@26100
  1086
  assumes "n > 0"
haftmann@26100
  1087
  shows "m mod n < (n::nat)"
haftmann@33340
  1088
  using assms divmod_nat_rel [of m n] unfolding divmod_nat_rel_def by auto
paulson@14267
  1089
haftmann@51173
  1090
lemma mod_Suc_le_divisor [simp]:
haftmann@51173
  1091
  "m mod Suc n \<le> n"
haftmann@51173
  1092
  using mod_less_divisor [of "Suc n" m] by arith
haftmann@51173
  1093
haftmann@26100
  1094
lemma mod_less_eq_dividend [simp]:
haftmann@26100
  1095
  fixes m n :: nat
haftmann@26100
  1096
  shows "m mod n \<le> m"
haftmann@26100
  1097
proof (rule add_leD2)
haftmann@64242
  1098
  from div_mult_mod_eq have "m div n * n + m mod n = m" .
haftmann@26100
  1099
  then show "m div n * n + m mod n \<le> m" by auto
haftmann@26100
  1100
qed
haftmann@26100
  1101
wenzelm@61076
  1102
lemma mod_geq: "\<not> m < (n::nat) \<Longrightarrow> m mod n = (m - n) mod n"
nipkow@29667
  1103
by (simp add: le_mod_geq linorder_not_less)
paulson@14267
  1104
wenzelm@61076
  1105
lemma mod_if: "m mod (n::nat) = (if m < n then m else (m - n) mod n)"
nipkow@29667
  1106
by (simp add: le_mod_geq)
haftmann@26100
  1107
haftmann@64244
  1108
lemma mod_by_Suc_0 [simp]: "m mod Suc 0 = 0"
nipkow@29667
  1109
by (induct m) (simp_all add: mod_geq)
paulson@14267
  1110
nipkow@15439
  1111
lemma mod_le_divisor[simp]: "0 < n \<Longrightarrow> m mod n \<le> (n::nat)"
wenzelm@22718
  1112
  apply (drule mod_less_divisor [where m = m])
wenzelm@22718
  1113
  apply simp
wenzelm@22718
  1114
  done
paulson@14267
  1115
wenzelm@60758
  1116
subsubsection \<open>Quotient and Remainder\<close>
paulson@14267
  1117
haftmann@33340
  1118
lemma divmod_nat_rel_mult1_eq:
bulwahn@46552
  1119
  "divmod_nat_rel b c (q, r)
haftmann@33340
  1120
   \<Longrightarrow> divmod_nat_rel (a * b) c (a * q + a * r div c, a * r mod c)"
haftmann@33340
  1121
by (auto simp add: split_ifs divmod_nat_rel_def algebra_simps)
paulson@14267
  1122
haftmann@30923
  1123
lemma div_mult1_eq:
haftmann@30923
  1124
  "(a * b) div c = a * (b div c) + a * (b mod c) div (c::nat)"
huffman@47135
  1125
by (blast intro: divmod_nat_rel_mult1_eq [THEN div_nat_unique] divmod_nat_rel)
paulson@14267
  1126
haftmann@33340
  1127
lemma divmod_nat_rel_add1_eq:
bulwahn@46552
  1128
  "divmod_nat_rel a c (aq, ar) \<Longrightarrow> divmod_nat_rel b c (bq, br)
haftmann@33340
  1129
   \<Longrightarrow> divmod_nat_rel (a + b) c (aq + bq + (ar + br) div c, (ar + br) mod c)"
haftmann@33340
  1130
by (auto simp add: split_ifs divmod_nat_rel_def algebra_simps)
paulson@14267
  1131
paulson@14267
  1132
(*NOT suitable for rewriting: the RHS has an instance of the LHS*)
paulson@14267
  1133
lemma div_add1_eq:
nipkow@25134
  1134
  "(a+b) div (c::nat) = a div c + b div c + ((a mod c + b mod c) div c)"
huffman@47135
  1135
by (blast intro: divmod_nat_rel_add1_eq [THEN div_nat_unique] divmod_nat_rel)
paulson@14267
  1136
haftmann@33340
  1137
lemma divmod_nat_rel_mult2_eq:
haftmann@60352
  1138
  assumes "divmod_nat_rel a b (q, r)"
haftmann@60352
  1139
  shows "divmod_nat_rel a (b * c) (q div c, b *(q mod c) + r)"
haftmann@60352
  1140
proof -
lp15@60562
  1141
  { assume "r < b" and "0 < c"
haftmann@60352
  1142
    then have "b * (q mod c) + r < b * c"
haftmann@60352
  1143
      apply (cut_tac m = q and n = c in mod_less_divisor)
haftmann@60352
  1144
      apply (drule_tac [2] m = "q mod c" in less_imp_Suc_add, auto)
haftmann@60352
  1145
      apply (erule_tac P = "%x. lhs < rhs x" for lhs rhs in ssubst)
haftmann@60352
  1146
      apply (simp add: add_mult_distrib2)
haftmann@60352
  1147
      done
haftmann@60352
  1148
    then have "r + b * (q mod c) < b * c"
haftmann@60352
  1149
      by (simp add: ac_simps)
haftmann@60352
  1150
  } with assms show ?thesis
haftmann@60352
  1151
    by (auto simp add: divmod_nat_rel_def algebra_simps add_mult_distrib2 [symmetric])
haftmann@60352
  1152
qed
lp15@60562
  1153
blanchet@55085
  1154
lemma div_mult2_eq: "a div (b * c) = (a div b) div (c::nat)"
huffman@47135
  1155
by (force simp add: divmod_nat_rel [THEN divmod_nat_rel_mult2_eq, THEN div_nat_unique])
paulson@14267
  1156
blanchet@55085
  1157
lemma mod_mult2_eq: "a mod (b * c) = b * (a div b mod c) + a mod (b::nat)"
haftmann@57512
  1158
by (auto simp add: mult.commute divmod_nat_rel [THEN divmod_nat_rel_mult2_eq, THEN mod_nat_unique])
paulson@14267
  1159
haftmann@61275
  1160
instantiation nat :: semiring_numeral_div
haftmann@61275
  1161
begin
haftmann@61275
  1162
haftmann@61275
  1163
definition divmod_nat :: "num \<Rightarrow> num \<Rightarrow> nat \<times> nat"
haftmann@61275
  1164
where
haftmann@61275
  1165
  divmod'_nat_def: "divmod_nat m n = (numeral m div numeral n, numeral m mod numeral n)"
haftmann@61275
  1166
haftmann@61275
  1167
definition divmod_step_nat :: "num \<Rightarrow> nat \<times> nat \<Rightarrow> nat \<times> nat"
haftmann@61275
  1168
where
haftmann@61275
  1169
  "divmod_step_nat l qr = (let (q, r) = qr
haftmann@61275
  1170
    in if r \<ge> numeral l then (2 * q + 1, r - numeral l)
haftmann@61275
  1171
    else (2 * q, r))"
haftmann@61275
  1172
haftmann@61275
  1173
instance
haftmann@61275
  1174
  by standard (auto intro: div_positive simp add: divmod'_nat_def divmod_step_nat_def mod_mult2_eq div_mult2_eq)
haftmann@61275
  1175
haftmann@61275
  1176
end
haftmann@61275
  1177
haftmann@61275
  1178
declare divmod_algorithm_code [where ?'a = nat, code]
haftmann@61275
  1179
  
paulson@14267
  1180
wenzelm@60758
  1181
subsubsection \<open>Further Facts about Quotient and Remainder\<close>
paulson@14267
  1182
haftmann@64244
  1183
lemma div_by_Suc_0 [simp]:
haftmann@58786
  1184
  "m div Suc 0 = m"
haftmann@58786
  1185
  using div_by_1 [of m] by simp
paulson@14267
  1186
paulson@14267
  1187
(* Monotonicity of div in first argument *)
haftmann@30923
  1188
lemma div_le_mono [rule_format (no_asm)]:
wenzelm@22718
  1189
    "\<forall>m::nat. m \<le> n --> (m div k) \<le> (n div k)"
paulson@14267
  1190
apply (case_tac "k=0", simp)
paulson@15251
  1191
apply (induct "n" rule: nat_less_induct, clarify)
paulson@14267
  1192
apply (case_tac "n<k")
paulson@14267
  1193
(* 1  case n<k *)
paulson@14267
  1194
apply simp
paulson@14267
  1195
(* 2  case n >= k *)
paulson@14267
  1196
apply (case_tac "m<k")
paulson@14267
  1197
(* 2.1  case m<k *)
paulson@14267
  1198
apply simp
paulson@14267
  1199
(* 2.2  case m>=k *)
nipkow@15439
  1200
apply (simp add: div_geq diff_le_mono)
paulson@14267
  1201
done
paulson@14267
  1202
paulson@14267
  1203
(* Antimonotonicity of div in second argument *)
paulson@14267
  1204
lemma div_le_mono2: "!!m::nat. [| 0<m; m\<le>n |] ==> (k div n) \<le> (k div m)"
paulson@14267
  1205
apply (subgoal_tac "0<n")
wenzelm@22718
  1206
 prefer 2 apply simp
paulson@15251
  1207
apply (induct_tac k rule: nat_less_induct)
paulson@14267
  1208
apply (rename_tac "k")
paulson@14267
  1209
apply (case_tac "k<n", simp)
paulson@14267
  1210
apply (subgoal_tac "~ (k<m) ")
wenzelm@22718
  1211
 prefer 2 apply simp
paulson@14267
  1212
apply (simp add: div_geq)
paulson@15251
  1213
apply (subgoal_tac "(k-n) div n \<le> (k-m) div n")
paulson@14267
  1214
 prefer 2
paulson@14267
  1215
 apply (blast intro: div_le_mono diff_le_mono2)
paulson@14267
  1216
apply (rule le_trans, simp)
nipkow@15439
  1217
apply (simp)
paulson@14267
  1218
done
paulson@14267
  1219
paulson@14267
  1220
lemma div_le_dividend [simp]: "m div n \<le> (m::nat)"
paulson@14267
  1221
apply (case_tac "n=0", simp)
paulson@14267
  1222
apply (subgoal_tac "m div n \<le> m div 1", simp)
paulson@14267
  1223
apply (rule div_le_mono2)
paulson@14267
  1224
apply (simp_all (no_asm_simp))
paulson@14267
  1225
done
paulson@14267
  1226
wenzelm@22718
  1227
(* Similar for "less than" *)
huffman@47138
  1228
lemma div_less_dividend [simp]:
huffman@47138
  1229
  "\<lbrakk>(1::nat) < n; 0 < m\<rbrakk> \<Longrightarrow> m div n < m"
huffman@47138
  1230
apply (induct m rule: nat_less_induct)
paulson@14267
  1231
apply (rename_tac "m")
paulson@14267
  1232
apply (case_tac "m<n", simp)
paulson@14267
  1233
apply (subgoal_tac "0<n")
wenzelm@22718
  1234
 prefer 2 apply simp
paulson@14267
  1235
apply (simp add: div_geq)
paulson@14267
  1236
apply (case_tac "n<m")
paulson@15251
  1237
 apply (subgoal_tac "(m-n) div n < (m-n) ")
paulson@14267
  1238
  apply (rule impI less_trans_Suc)+
paulson@14267
  1239
apply assumption
nipkow@15439
  1240
  apply (simp_all)
paulson@14267
  1241
done
paulson@14267
  1242
wenzelm@60758
  1243
text\<open>A fact for the mutilated chess board\<close>
paulson@14267
  1244
lemma mod_Suc: "Suc(m) mod n = (if Suc(m mod n) = n then 0 else Suc(m mod n))"
paulson@14267
  1245
apply (case_tac "n=0", simp)
paulson@15251
  1246
apply (induct "m" rule: nat_less_induct)
paulson@14267
  1247
apply (case_tac "Suc (na) <n")
paulson@14267
  1248
(* case Suc(na) < n *)
paulson@14267
  1249
apply (frule lessI [THEN less_trans], simp add: less_not_refl3)
paulson@14267
  1250
(* case n \<le> Suc(na) *)
paulson@16796
  1251
apply (simp add: linorder_not_less le_Suc_eq mod_geq)
nipkow@15439
  1252
apply (auto simp add: Suc_diff_le le_mod_geq)
paulson@14267
  1253
done
paulson@14267
  1254
paulson@14267
  1255
lemma mod_eq_0_iff: "(m mod d = 0) = (\<exists>q::nat. m = d*q)"
nipkow@29667
  1256
by (auto simp add: dvd_eq_mod_eq_0 [symmetric] dvd_def)
paulson@17084
  1257
wenzelm@22718
  1258
lemmas mod_eq_0D [dest!] = mod_eq_0_iff [THEN iffD1]
paulson@14267
  1259
paulson@14267
  1260
(*Loses information, namely we also have r<d provided d is nonzero*)
haftmann@57514
  1261
lemma mod_eqD:
haftmann@57514
  1262
  fixes m d r q :: nat
haftmann@57514
  1263
  assumes "m mod d = r"
haftmann@57514
  1264
  shows "\<exists>q. m = r + q * d"
haftmann@57514
  1265
proof -
haftmann@64242
  1266
  from div_mult_mod_eq obtain q where "q * d + m mod d = m" by blast
haftmann@57514
  1267
  with assms have "m = r + q * d" by simp
haftmann@57514
  1268
  then show ?thesis ..
haftmann@57514
  1269
qed
paulson@14267
  1270
nipkow@13152
  1271
lemma split_div:
nipkow@13189
  1272
 "P(n div k :: nat) =
nipkow@13189
  1273
 ((k = 0 \<longrightarrow> P 0) \<and> (k \<noteq> 0 \<longrightarrow> (!i. !j<k. n = k*i + j \<longrightarrow> P i)))"
nipkow@13189
  1274
 (is "?P = ?Q" is "_ = (_ \<and> (_ \<longrightarrow> ?R))")
nipkow@13189
  1275
proof
nipkow@13189
  1276
  assume P: ?P
nipkow@13189
  1277
  show ?Q
nipkow@13189
  1278
  proof (cases)
nipkow@13189
  1279
    assume "k = 0"
haftmann@27651
  1280
    with P show ?Q by simp
nipkow@13189
  1281
  next
nipkow@13189
  1282
    assume not0: "k \<noteq> 0"
nipkow@13189
  1283
    thus ?Q
nipkow@13189
  1284
    proof (simp, intro allI impI)
nipkow@13189
  1285
      fix i j
nipkow@13189
  1286
      assume n: "n = k*i + j" and j: "j < k"
nipkow@13189
  1287
      show "P i"
nipkow@13189
  1288
      proof (cases)
wenzelm@22718
  1289
        assume "i = 0"
wenzelm@22718
  1290
        with n j P show "P i" by simp
nipkow@13189
  1291
      next
wenzelm@22718
  1292
        assume "i \<noteq> 0"
haftmann@57514
  1293
        with not0 n j P show "P i" by(simp add:ac_simps)
nipkow@13189
  1294
      qed
nipkow@13189
  1295
    qed
nipkow@13189
  1296
  qed
nipkow@13189
  1297
next
nipkow@13189
  1298
  assume Q: ?Q
nipkow@13189
  1299
  show ?P
nipkow@13189
  1300
  proof (cases)
nipkow@13189
  1301
    assume "k = 0"
haftmann@27651
  1302
    with Q show ?P by simp
nipkow@13189
  1303
  next
nipkow@13189
  1304
    assume not0: "k \<noteq> 0"
nipkow@13189
  1305
    with Q have R: ?R by simp
nipkow@13189
  1306
    from not0 R[THEN spec,of "n div k",THEN spec, of "n mod k"]
nipkow@13517
  1307
    show ?P by simp
nipkow@13189
  1308
  qed
nipkow@13189
  1309
qed
nipkow@13189
  1310
berghofe@13882
  1311
lemma split_div_lemma:
haftmann@26100
  1312
  assumes "0 < n"
wenzelm@61076
  1313
  shows "n * q \<le> m \<and> m < n * Suc q \<longleftrightarrow> q = ((m::nat) div n)" (is "?lhs \<longleftrightarrow> ?rhs")
haftmann@26100
  1314
proof
haftmann@26100
  1315
  assume ?rhs
haftmann@64246
  1316
  with minus_mod_eq_mult_div [symmetric] have nq: "n * q = m - (m mod n)" by simp
haftmann@26100
  1317
  then have A: "n * q \<le> m" by simp
haftmann@26100
  1318
  have "n - (m mod n) > 0" using mod_less_divisor assms by auto
haftmann@26100
  1319
  then have "m < m + (n - (m mod n))" by simp
haftmann@26100
  1320
  then have "m < n + (m - (m mod n))" by simp
haftmann@26100
  1321
  with nq have "m < n + n * q" by simp
haftmann@26100
  1322
  then have B: "m < n * Suc q" by simp
haftmann@26100
  1323
  from A B show ?lhs ..
haftmann@26100
  1324
next
haftmann@26100
  1325
  assume P: ?lhs
haftmann@33340
  1326
  then have "divmod_nat_rel m n (q, m - n * q)"
haftmann@57514
  1327
    unfolding divmod_nat_rel_def by (auto simp add: ac_simps)
haftmann@61433
  1328
  then have "m div n = q"
haftmann@61433
  1329
    by (rule div_nat_unique)
haftmann@30923
  1330
  then show ?rhs by simp
haftmann@26100
  1331
qed
berghofe@13882
  1332
berghofe@13882
  1333
theorem split_div':
berghofe@13882
  1334
  "P ((m::nat) div n) = ((n = 0 \<and> P 0) \<or>
paulson@14267
  1335
   (\<exists>q. (n * q \<le> m \<and> m < n * (Suc q)) \<and> P q))"
haftmann@61433
  1336
  apply (cases "0 < n")
berghofe@13882
  1337
  apply (simp only: add: split_div_lemma)
haftmann@27651
  1338
  apply simp_all
berghofe@13882
  1339
  done
berghofe@13882
  1340
nipkow@13189
  1341
lemma split_mod:
nipkow@13189
  1342
 "P(n mod k :: nat) =
nipkow@13189
  1343
 ((k = 0 \<longrightarrow> P n) \<and> (k \<noteq> 0 \<longrightarrow> (!i. !j<k. n = k*i + j \<longrightarrow> P j)))"
nipkow@13189
  1344
 (is "?P = ?Q" is "_ = (_ \<and> (_ \<longrightarrow> ?R))")
nipkow@13189
  1345
proof
nipkow@13189
  1346
  assume P: ?P
nipkow@13189
  1347
  show ?Q
nipkow@13189
  1348
  proof (cases)
nipkow@13189
  1349
    assume "k = 0"
haftmann@27651
  1350
    with P show ?Q by simp
nipkow@13189
  1351
  next
nipkow@13189
  1352
    assume not0: "k \<noteq> 0"
nipkow@13189
  1353
    thus ?Q
nipkow@13189
  1354
    proof (simp, intro allI impI)
nipkow@13189
  1355
      fix i j
nipkow@13189
  1356
      assume "n = k*i + j" "j < k"
haftmann@58786
  1357
      thus "P j" using not0 P by (simp add: ac_simps)
nipkow@13189
  1358
    qed
nipkow@13189
  1359
  qed
nipkow@13189
  1360
next
nipkow@13189
  1361
  assume Q: ?Q
nipkow@13189
  1362
  show ?P
nipkow@13189
  1363
  proof (cases)
nipkow@13189
  1364
    assume "k = 0"
haftmann@27651
  1365
    with Q show ?P by simp
nipkow@13189
  1366
  next
nipkow@13189
  1367
    assume not0: "k \<noteq> 0"
nipkow@13189
  1368
    with Q have R: ?R by simp
nipkow@13189
  1369
    from not0 R[THEN spec,of "n div k",THEN spec, of "n mod k"]
nipkow@13517
  1370
    show ?P by simp
nipkow@13189
  1371
  qed
nipkow@13189
  1372
qed
nipkow@13189
  1373
noschinl@52398
  1374
lemma div_eq_dividend_iff: "a \<noteq> 0 \<Longrightarrow> (a :: nat) div b = a \<longleftrightarrow> b = 1"
noschinl@52398
  1375
  apply rule
noschinl@52398
  1376
  apply (cases "b = 0")
noschinl@52398
  1377
  apply simp_all
noschinl@52398
  1378
  apply (metis (full_types) One_nat_def Suc_lessI div_less_dividend less_not_refl3)
noschinl@52398
  1379
  done
noschinl@52398
  1380
haftmann@63417
  1381
lemma (in field_char_0) of_nat_div:
haftmann@63417
  1382
  "of_nat (m div n) = ((of_nat m - of_nat (m mod n)) / of_nat n)"
haftmann@63417
  1383
proof -
haftmann@63417
  1384
  have "of_nat (m div n) = ((of_nat (m div n * n + m mod n) - of_nat (m mod n)) / of_nat n :: 'a)"
haftmann@63417
  1385
    unfolding of_nat_add by (cases "n = 0") simp_all
haftmann@63417
  1386
  then show ?thesis
haftmann@63417
  1387
    by simp
haftmann@63417
  1388
qed
haftmann@63417
  1389
haftmann@22800
  1390
wenzelm@60758
  1391
subsubsection \<open>An ``induction'' law for modulus arithmetic.\<close>
paulson@14640
  1392
paulson@14640
  1393
lemma mod_induct_0:
paulson@14640
  1394
  assumes step: "\<forall>i<p. P i \<longrightarrow> P ((Suc i) mod p)"
paulson@14640
  1395
  and base: "P i" and i: "i<p"
paulson@14640
  1396
  shows "P 0"
paulson@14640
  1397
proof (rule ccontr)
paulson@14640
  1398
  assume contra: "\<not>(P 0)"
paulson@14640
  1399
  from i have p: "0<p" by simp
paulson@14640
  1400
  have "\<forall>k. 0<k \<longrightarrow> \<not> P (p-k)" (is "\<forall>k. ?A k")
paulson@14640
  1401
  proof
paulson@14640
  1402
    fix k
paulson@14640
  1403
    show "?A k"
paulson@14640
  1404
    proof (induct k)
wenzelm@61799
  1405
      show "?A 0" by simp  \<comment> "by contradiction"
paulson@14640
  1406
    next
paulson@14640
  1407
      fix n
paulson@14640
  1408
      assume ih: "?A n"
paulson@14640
  1409
      show "?A (Suc n)"
paulson@14640
  1410
      proof (clarsimp)
wenzelm@22718
  1411
        assume y: "P (p - Suc n)"
wenzelm@22718
  1412
        have n: "Suc n < p"
wenzelm@22718
  1413
        proof (rule ccontr)
wenzelm@22718
  1414
          assume "\<not>(Suc n < p)"
wenzelm@22718
  1415
          hence "p - Suc n = 0"
wenzelm@22718
  1416
            by simp
wenzelm@22718
  1417
          with y contra show "False"
wenzelm@22718
  1418
            by simp
wenzelm@22718
  1419
        qed
wenzelm@22718
  1420
        hence n2: "Suc (p - Suc n) = p-n" by arith
wenzelm@22718
  1421
        from p have "p - Suc n < p" by arith
wenzelm@22718
  1422
        with y step have z: "P ((Suc (p - Suc n)) mod p)"
wenzelm@22718
  1423
          by blast
wenzelm@22718
  1424
        show "False"
wenzelm@22718
  1425
        proof (cases "n=0")
wenzelm@22718
  1426
          case True
wenzelm@22718
  1427
          with z n2 contra show ?thesis by simp
wenzelm@22718
  1428
        next
wenzelm@22718
  1429
          case False
wenzelm@22718
  1430
          with p have "p-n < p" by arith
wenzelm@22718
  1431
          with z n2 False ih show ?thesis by simp
wenzelm@22718
  1432
        qed
paulson@14640
  1433
      qed
paulson@14640
  1434
    qed
paulson@14640
  1435
  qed
paulson@14640
  1436
  moreover
paulson@14640
  1437
  from i obtain k where "0<k \<and> i+k=p"
paulson@14640
  1438
    by (blast dest: less_imp_add_positive)
paulson@14640
  1439
  hence "0<k \<and> i=p-k" by auto
paulson@14640
  1440
  moreover
paulson@14640
  1441
  note base
paulson@14640
  1442
  ultimately
paulson@14640
  1443
  show "False" by blast
paulson@14640
  1444
qed
paulson@14640
  1445
paulson@14640
  1446
lemma mod_induct:
paulson@14640
  1447
  assumes step: "\<forall>i<p. P i \<longrightarrow> P ((Suc i) mod p)"
paulson@14640
  1448
  and base: "P i" and i: "i<p" and j: "j<p"
paulson@14640
  1449
  shows "P j"
paulson@14640
  1450
proof -
paulson@14640
  1451
  have "\<forall>j<p. P j"
paulson@14640
  1452
  proof
paulson@14640
  1453
    fix j
paulson@14640
  1454
    show "j<p \<longrightarrow> P j" (is "?A j")
paulson@14640
  1455
    proof (induct j)
paulson@14640
  1456
      from step base i show "?A 0"
wenzelm@22718
  1457
        by (auto elim: mod_induct_0)
paulson@14640
  1458
    next
paulson@14640
  1459
      fix k
paulson@14640
  1460
      assume ih: "?A k"
paulson@14640
  1461
      show "?A (Suc k)"
paulson@14640
  1462
      proof
wenzelm@22718
  1463
        assume suc: "Suc k < p"
wenzelm@22718
  1464
        hence k: "k<p" by simp
wenzelm@22718
  1465
        with ih have "P k" ..
wenzelm@22718
  1466
        with step k have "P (Suc k mod p)"
wenzelm@22718
  1467
          by blast
wenzelm@22718
  1468
        moreover
wenzelm@22718
  1469
        from suc have "Suc k mod p = Suc k"
wenzelm@22718
  1470
          by simp
wenzelm@22718
  1471
        ultimately
wenzelm@22718
  1472
        show "P (Suc k)" by simp
paulson@14640
  1473
      qed
paulson@14640
  1474
    qed
paulson@14640
  1475
  qed
paulson@14640
  1476
  with j show ?thesis by blast
paulson@14640
  1477
qed
paulson@14640
  1478
haftmann@33296
  1479
lemma div2_Suc_Suc [simp]: "Suc (Suc m) div 2 = Suc (m div 2)"
huffman@47138
  1480
  by (simp add: numeral_2_eq_2 le_div_geq)
huffman@47138
  1481
huffman@47138
  1482
lemma mod2_Suc_Suc [simp]: "Suc (Suc m) mod 2 = m mod 2"
huffman@47138
  1483
  by (simp add: numeral_2_eq_2 le_mod_geq)
haftmann@33296
  1484
haftmann@33296
  1485
lemma add_self_div_2 [simp]: "(m + m) div 2 = (m::nat)"
huffman@47217
  1486
by (simp add: mult_2 [symmetric])
haftmann@33296
  1487
wenzelm@61076
  1488
lemma mod2_gr_0 [simp]: "0 < (m::nat) mod 2 \<longleftrightarrow> m mod 2 = 1"
haftmann@33296
  1489
proof -
boehmes@35815
  1490
  { fix n :: nat have  "(n::nat) < 2 \<Longrightarrow> n = 0 \<or> n = 1" by (cases n) simp_all }
haftmann@33296
  1491
  moreover have "m mod 2 < 2" by simp
haftmann@33296
  1492
  ultimately have "m mod 2 = 0 \<or> m mod 2 = 1" .
haftmann@33296
  1493
  then show ?thesis by auto
haftmann@33296
  1494
qed
haftmann@33296
  1495
wenzelm@60758
  1496
text\<open>These lemmas collapse some needless occurrences of Suc:
haftmann@33296
  1497
    at least three Sucs, since two and fewer are rewritten back to Suc again!
wenzelm@60758
  1498
    We already have some rules to simplify operands smaller than 3.\<close>
haftmann@33296
  1499
haftmann@33296
  1500
lemma div_Suc_eq_div_add3 [simp]: "m div (Suc (Suc (Suc n))) = m div (3+n)"
haftmann@33296
  1501
by (simp add: Suc3_eq_add_3)
haftmann@33296
  1502
haftmann@33296
  1503
lemma mod_Suc_eq_mod_add3 [simp]: "m mod (Suc (Suc (Suc n))) = m mod (3+n)"
haftmann@33296
  1504
by (simp add: Suc3_eq_add_3)
haftmann@33296
  1505
haftmann@33296
  1506
lemma Suc_div_eq_add3_div: "(Suc (Suc (Suc m))) div n = (3+m) div n"
haftmann@33296
  1507
by (simp add: Suc3_eq_add_3)
haftmann@33296
  1508
haftmann@33296
  1509
lemma Suc_mod_eq_add3_mod: "(Suc (Suc (Suc m))) mod n = (3+m) mod n"
haftmann@33296
  1510
by (simp add: Suc3_eq_add_3)
haftmann@33296
  1511
huffman@47108
  1512
lemmas Suc_div_eq_add3_div_numeral [simp] = Suc_div_eq_add3_div [of _ "numeral v"] for v
huffman@47108
  1513
lemmas Suc_mod_eq_add3_mod_numeral [simp] = Suc_mod_eq_add3_mod [of _ "numeral v"] for v
haftmann@33296
  1514
lp15@60562
  1515
lemma Suc_times_mod_eq: "1<k ==> Suc (k * m) mod k = 1"
haftmann@33361
  1516
apply (induct "m")
haftmann@33361
  1517
apply (simp_all add: mod_Suc)
haftmann@33361
  1518
done
haftmann@33361
  1519
huffman@47108
  1520
declare Suc_times_mod_eq [of "numeral w", simp] for w
haftmann@33361
  1521
haftmann@60868
  1522
lemma mod_greater_zero_iff_not_dvd:
haftmann@60868
  1523
  fixes m n :: nat
haftmann@60868
  1524
  shows "m mod n > 0 \<longleftrightarrow> \<not> n dvd m"
haftmann@60868
  1525
  by (simp add: dvd_eq_mod_eq_0)
haftmann@60868
  1526
huffman@47138
  1527
lemma Suc_div_le_mono [simp]: "n div k \<le> (Suc n) div k"
huffman@47138
  1528
by (simp add: div_le_mono)
haftmann@33361
  1529
haftmann@33361
  1530
lemma Suc_n_div_2_gt_zero [simp]: "(0::nat) < n ==> 0 < (n + 1) div 2"
haftmann@33361
  1531
by (cases n) simp_all
haftmann@33361
  1532
boehmes@35815
  1533
lemma div_2_gt_zero [simp]: assumes A: "(1::nat) < n" shows "0 < n div 2"
boehmes@35815
  1534
proof -
boehmes@35815
  1535
  from A have B: "0 < n - 1" and C: "n - 1 + 1 = n" by simp_all
lp15@60562
  1536
  from Suc_n_div_2_gt_zero [OF B] C show ?thesis by simp
boehmes@35815
  1537
qed
haftmann@33361
  1538
haftmann@33361
  1539
lemma mod_mult_self4 [simp]: "Suc (k*n + m) mod n = Suc m mod n"
haftmann@33361
  1540
proof -
haftmann@33361
  1541
  have "Suc (k * n + m) mod n = (k * n + Suc m) mod n" by simp
lp15@60562
  1542
  also have "... = Suc m mod n" by (rule mod_mult_self3)
haftmann@33361
  1543
  finally show ?thesis .
haftmann@33361
  1544
qed
haftmann@33361
  1545
haftmann@33361
  1546
lemma mod_Suc_eq_Suc_mod: "Suc m mod n = Suc (m mod n) mod n"
lp15@60562
  1547
apply (subst mod_Suc [of m])
lp15@60562
  1548
apply (subst mod_Suc [of "m mod n"], simp)
haftmann@33361
  1549
done
haftmann@33361
  1550
huffman@47108
  1551
lemma mod_2_not_eq_zero_eq_one_nat:
huffman@47108
  1552
  fixes n :: nat
huffman@47108
  1553
  shows "n mod 2 \<noteq> 0 \<longleftrightarrow> n mod 2 = 1"
haftmann@58786
  1554
  by (fact not_mod_2_eq_0_eq_1)
lp15@60562
  1555
haftmann@58778
  1556
lemma even_Suc_div_two [simp]:
haftmann@58778
  1557
  "even n \<Longrightarrow> Suc n div 2 = n div 2"
haftmann@58778
  1558
  using even_succ_div_two [of n] by simp
lp15@60562
  1559
haftmann@58778
  1560
lemma odd_Suc_div_two [simp]:
haftmann@58778
  1561
  "odd n \<Longrightarrow> Suc n div 2 = Suc (n div 2)"
haftmann@58778
  1562
  using odd_succ_div_two [of n] by simp
haftmann@58778
  1563
haftmann@58834
  1564
lemma odd_two_times_div_two_nat [simp]:
haftmann@60352
  1565
  assumes "odd n"
haftmann@60352
  1566
  shows "2 * (n div 2) = n - (1 :: nat)"
haftmann@60352
  1567
proof -
haftmann@60352
  1568
  from assms have "2 * (n div 2) + 1 = n"
haftmann@60352
  1569
    by (rule odd_two_times_div_two_succ)
haftmann@60352
  1570
  then have "Suc (2 * (n div 2)) - 1 = n - 1"
haftmann@60352
  1571
    by simp
haftmann@60352
  1572
  then show ?thesis
haftmann@60352
  1573
    by simp
haftmann@60352
  1574
qed
haftmann@58778
  1575
haftmann@58778
  1576
lemma parity_induct [case_names zero even odd]:
haftmann@58778
  1577
  assumes zero: "P 0"
haftmann@58778
  1578
  assumes even: "\<And>n. P n \<Longrightarrow> P (2 * n)"
haftmann@58778
  1579
  assumes odd: "\<And>n. P n \<Longrightarrow> P (Suc (2 * n))"
haftmann@58778
  1580
  shows "P n"
haftmann@58778
  1581
proof (induct n rule: less_induct)
haftmann@58778
  1582
  case (less n)
haftmann@58778
  1583
  show "P n"
haftmann@58778
  1584
  proof (cases "n = 0")
haftmann@58778
  1585
    case True with zero show ?thesis by simp
haftmann@58778
  1586
  next
haftmann@58778
  1587
    case False
haftmann@58778
  1588
    with less have hyp: "P (n div 2)" by simp
haftmann@58778
  1589
    show ?thesis
haftmann@58778
  1590
    proof (cases "even n")
haftmann@58778
  1591
      case True
haftmann@58778
  1592
      with hyp even [of "n div 2"] show ?thesis
haftmann@58834
  1593
        by simp
haftmann@58778
  1594
    next
haftmann@58778
  1595
      case False
lp15@60562
  1596
      with hyp odd [of "n div 2"] show ?thesis
haftmann@58834
  1597
        by simp
haftmann@58778
  1598
    qed
haftmann@58778
  1599
  qed
haftmann@58778
  1600
qed
haftmann@58778
  1601
haftmann@60868
  1602
lemma Suc_0_div_numeral [simp]:
haftmann@60868
  1603
  fixes k l :: num
haftmann@60868
  1604
  shows "Suc 0 div numeral k = fst (divmod Num.One k)"
haftmann@60868
  1605
  by (simp_all add: fst_divmod)
haftmann@60868
  1606
haftmann@60868
  1607
lemma Suc_0_mod_numeral [simp]:
haftmann@60868
  1608
  fixes k l :: num
haftmann@60868
  1609
  shows "Suc 0 mod numeral k = snd (divmod Num.One k)"
haftmann@60868
  1610
  by (simp_all add: snd_divmod)
haftmann@60868
  1611
wenzelm@63145
  1612
lemma cut_eq_simps: \<comment> \<open>rewriting equivalence on \<open>n mod 2 ^ q\<close>\<close>
haftmann@62597
  1613
  fixes m n q :: num
haftmann@62597
  1614
  shows
haftmann@62597
  1615
    "numeral n mod numeral Num.One = (0::nat)
haftmann@62597
  1616
      \<longleftrightarrow> True"
haftmann@62597
  1617
    "numeral (Num.Bit0 n) mod numeral (Num.Bit0 q) = (0::nat)
haftmann@62597
  1618
      \<longleftrightarrow> numeral n mod numeral q = (0::nat)"
haftmann@62597
  1619
    "numeral (Num.Bit1 n) mod numeral (Num.Bit0 q) = (0::nat)
haftmann@62597
  1620
      \<longleftrightarrow> False"
haftmann@62597
  1621
    "numeral m mod numeral Num.One = (numeral n mod numeral Num.One :: nat)
haftmann@62597
  1622
      \<longleftrightarrow> True"
haftmann@62597
  1623
    "numeral Num.One mod numeral (Num.Bit0 q) = (numeral Num.One mod numeral (Num.Bit0 q) :: nat)
haftmann@62597
  1624
      \<longleftrightarrow> True"
haftmann@62597
  1625
    "numeral Num.One mod numeral (Num.Bit0 q) = (numeral (Num.Bit0 n) mod numeral (Num.Bit0 q) :: nat)
haftmann@62597
  1626
      \<longleftrightarrow> False"
haftmann@62597
  1627
    "numeral Num.One mod numeral (Num.Bit0 q) = (numeral (Num.Bit1 n) mod numeral (Num.Bit0 q) :: nat)
haftmann@62597
  1628
      \<longleftrightarrow> (numeral n mod numeral q :: nat) = 0"
haftmann@62597
  1629
    "numeral (Num.Bit0 m) mod numeral (Num.Bit0 q) = (numeral Num.One mod numeral (Num.Bit0 q) :: nat)
haftmann@62597
  1630
      \<longleftrightarrow> False"
haftmann@62597
  1631
    "numeral (Num.Bit0 m) mod numeral (Num.Bit0 q) = (numeral (Num.Bit0 n) mod numeral (Num.Bit0 q) :: nat)
haftmann@62597
  1632
      \<longleftrightarrow> numeral m mod numeral q = (numeral n mod numeral q :: nat)"
haftmann@62597
  1633
    "numeral (Num.Bit0 m) mod numeral (Num.Bit0 q) = (numeral (Num.Bit1 n) mod numeral (Num.Bit0 q) :: nat)
haftmann@62597
  1634
      \<longleftrightarrow> False"
haftmann@62597
  1635
    "numeral (Num.Bit1 m) mod numeral (Num.Bit0 q) = (numeral Num.One mod numeral (Num.Bit0 q) :: nat)
haftmann@62597
  1636
      \<longleftrightarrow> (numeral m mod numeral q :: nat) = 0"
haftmann@62597
  1637
    "numeral (Num.Bit1 m) mod numeral (Num.Bit0 q) = (numeral (Num.Bit0 n) mod numeral (Num.Bit0 q) :: nat)
haftmann@62597
  1638
      \<longleftrightarrow> False"
haftmann@62597
  1639
    "numeral (Num.Bit1 m) mod numeral (Num.Bit0 q) = (numeral (Num.Bit1 n) mod numeral (Num.Bit0 q) :: nat)
haftmann@62597
  1640
      \<longleftrightarrow> numeral m mod numeral q = (numeral n mod numeral q :: nat)"
haftmann@62597
  1641
  by (auto simp add: case_prod_beta Suc_double_not_eq_double double_not_eq_Suc_double)
haftmann@62597
  1642
haftmann@33361
  1643
wenzelm@60758
  1644
subsection \<open>Division on @{typ int}\<close>
haftmann@33361
  1645
wenzelm@61799
  1646
definition divmod_int_rel :: "int \<Rightarrow> int \<Rightarrow> int \<times> int \<Rightarrow> bool" \<comment> \<open>definition of quotient and remainder\<close>
haftmann@60868
  1647
  where "divmod_int_rel a b = (\<lambda>(q, r). a = b * q + r \<and>
huffman@47139
  1648
    (if 0 < b then 0 \<le> r \<and> r < b else if b < 0 then b < r \<and> r \<le> 0 else q = 0))"
haftmann@33361
  1649
haftmann@33361
  1650
lemma unique_quotient_lemma:
haftmann@60868
  1651
  "b * q' + r' \<le> b * q + r \<Longrightarrow> 0 \<le> r' \<Longrightarrow> r' < b \<Longrightarrow> r < b \<Longrightarrow> q' \<le> (q::int)"
haftmann@33361
  1652
apply (subgoal_tac "r' + b * (q'-q) \<le> r")
haftmann@33361
  1653
 prefer 2 apply (simp add: right_diff_distrib)
haftmann@33361
  1654
apply (subgoal_tac "0 < b * (1 + q - q') ")
haftmann@33361
  1655
apply (erule_tac [2] order_le_less_trans)
webertj@49962
  1656
 prefer 2 apply (simp add: right_diff_distrib distrib_left)
haftmann@33361
  1657
apply (subgoal_tac "b * q' < b * (1 + q) ")
webertj@49962
  1658
 prefer 2 apply (simp add: right_diff_distrib distrib_left)
haftmann@33361
  1659
apply (simp add: mult_less_cancel_left)
haftmann@33361
  1660
done
haftmann@33361
  1661
haftmann@33361
  1662
lemma unique_quotient_lemma_neg:
haftmann@60868
  1663
  "b * q' + r' \<le> b*q + r \<Longrightarrow> r \<le> 0 \<Longrightarrow> b < r \<Longrightarrow> b < r' \<Longrightarrow> q \<le> (q'::int)"
haftmann@60868
  1664
  by (rule_tac b = "-b" and r = "-r'" and r' = "-r" in unique_quotient_lemma) auto
haftmann@33361
  1665
haftmann@33361
  1666
lemma unique_quotient:
haftmann@60868
  1667
  "divmod_int_rel a b (q, r) \<Longrightarrow> divmod_int_rel a b (q', r') \<Longrightarrow> q = q'"
nipkow@62390
  1668
apply (simp add: divmod_int_rel_def linorder_neq_iff split: if_split_asm)
haftmann@33361
  1669
apply (blast intro: order_antisym
lp15@60562
  1670
             dest: order_eq_refl [THEN unique_quotient_lemma]
haftmann@33361
  1671
             order_eq_refl [THEN unique_quotient_lemma_neg] sym)+
haftmann@33361
  1672
done
haftmann@33361
  1673
haftmann@33361
  1674
lemma unique_remainder:
haftmann@60868
  1675
  "divmod_int_rel a b (q, r) \<Longrightarrow> divmod_int_rel a b (q', r') \<Longrightarrow> r = r'"
haftmann@33361
  1676
apply (subgoal_tac "q = q'")
haftmann@33361
  1677
 apply (simp add: divmod_int_rel_def)
haftmann@33361
  1678
apply (blast intro: unique_quotient)
haftmann@33361
  1679
done
haftmann@33361
  1680
haftmann@63950
  1681
instantiation int :: modulo
haftmann@60868
  1682
begin
haftmann@60868
  1683
haftmann@60868
  1684
definition divide_int
haftmann@60868
  1685
  where "k div l = (if l = 0 \<or> k = 0 then 0
haftmann@60868
  1686
    else if k > 0 \<and> l > 0 \<or> k < 0 \<and> l < 0
haftmann@60868
  1687
      then int (nat \<bar>k\<bar> div nat \<bar>l\<bar>)
haftmann@60868
  1688
      else
haftmann@60868
  1689
        if l dvd k then - int (nat \<bar>k\<bar> div nat \<bar>l\<bar>)
haftmann@60868
  1690
        else - int (Suc (nat \<bar>k\<bar> div nat \<bar>l\<bar>)))"
haftmann@60868
  1691
haftmann@63950
  1692
definition modulo_int
haftmann@60868
  1693
  where "k mod l = (if l = 0 then k else if l dvd k then 0
haftmann@60868
  1694
    else if k > 0 \<and> l > 0 \<or> k < 0 \<and> l < 0
haftmann@60868
  1695
      then sgn l * int (nat \<bar>k\<bar> mod nat \<bar>l\<bar>)
haftmann@60868
  1696
      else sgn l * (\<bar>l\<bar> - int (nat \<bar>k\<bar> mod nat \<bar>l\<bar>)))"
haftmann@60868
  1697
haftmann@60868
  1698
instance ..      
haftmann@60868
  1699
haftmann@60868
  1700
end
haftmann@60868
  1701
haftmann@60868
  1702
lemma divmod_int_rel:
haftmann@60868
  1703
  "divmod_int_rel k l (k div l, k mod l)"
haftmann@63950
  1704
  unfolding divmod_int_rel_def divide_int_def modulo_int_def
haftmann@60868
  1705
  apply (cases k rule: int_cases3)
lp15@61649
  1706
  apply (simp add: mod_greater_zero_iff_not_dvd not_le algebra_simps)
haftmann@60868
  1707
  apply (cases l rule: int_cases3)
lp15@61649
  1708
  apply (simp add: mod_greater_zero_iff_not_dvd not_le algebra_simps)
lp15@61649
  1709
  apply (simp_all del: of_nat_add of_nat_mult add: mod_greater_zero_iff_not_dvd not_le algebra_simps int_dvd_iff of_nat_add [symmetric] of_nat_mult [symmetric])
haftmann@60868
  1710
  apply (cases l rule: int_cases3)
lp15@61649
  1711
  apply (simp_all del: of_nat_add of_nat_mult add: not_le algebra_simps int_dvd_iff of_nat_add [symmetric] of_nat_mult [symmetric])
wenzelm@41550
  1712
  done
haftmann@33361
  1713
haftmann@60868
  1714
instantiation int :: ring_div
haftmann@60868
  1715
begin
haftmann@60868
  1716
haftmann@60868
  1717
subsubsection \<open>Uniqueness and Monotonicity of Quotients and Remainders\<close>
haftmann@33361
  1718
huffman@47141
  1719
lemma divmod_int_unique:
haftmann@60868
  1720
  assumes "divmod_int_rel k l (q, r)"
haftmann@60868
  1721
  shows div_int_unique: "k div l = q" and mod_int_unique: "k mod l = r"
haftmann@60868
  1722
  using assms divmod_int_rel [of k l]
haftmann@60868
  1723
  using unique_quotient [of k l] unique_remainder [of k l]
haftmann@60868
  1724
  by auto
haftmann@60868
  1725
  
haftmann@60429
  1726
instance
huffman@47141
  1727
proof
huffman@47141
  1728
  fix a b :: int
huffman@47141
  1729
  show "a div b * b + a mod b = a"
haftmann@60868
  1730
    using divmod_int_rel [of a b]
haftmann@57512
  1731
    unfolding divmod_int_rel_def by (simp add: mult.commute)
huffman@47141
  1732
next
huffman@47141
  1733
  fix a b c :: int
huffman@47141
  1734
  assume "b \<noteq> 0"
huffman@47141
  1735
  hence "divmod_int_rel (a + c * b) b (c + a div b, a mod b)"
haftmann@60868
  1736
    using divmod_int_rel [of a b]
huffman@47141
  1737
    unfolding divmod_int_rel_def by (auto simp: algebra_simps)
huffman@47141
  1738
  thus "(a + c * b) div b = c + a div b"
huffman@47141
  1739
    by (rule div_int_unique)
huffman@47141
  1740
next
huffman@47141
  1741
  fix a b c :: int
wenzelm@63834
  1742
  assume c: "c \<noteq> 0"
wenzelm@63834
  1743
  have "\<And>q r. divmod_int_rel a b (q, r)
huffman@47141
  1744
    \<Longrightarrow> divmod_int_rel (c * a) (c * b) (q, c * r)"
huffman@47141
  1745
    unfolding divmod_int_rel_def
wenzelm@63834
  1746
    by (rule linorder_cases [of 0 b])
wenzelm@63834
  1747
      (use c in \<open>auto simp: algebra_simps
huffman@47141
  1748
      mult_less_0_iff zero_less_mult_iff mult_strict_right_mono
wenzelm@63834
  1749
      mult_strict_right_mono_neg zero_le_mult_iff mult_le_0_iff\<close>)
huffman@47141
  1750
  hence "divmod_int_rel (c * a) (c * b) (a div b, c * (a mod b))"
haftmann@60868
  1751
    using divmod_int_rel [of a b] .
huffman@47141
  1752
  thus "(c * a) div (c * b) = a div b"
huffman@47141
  1753
    by (rule div_int_unique)
huffman@47141
  1754
next
huffman@47141
  1755
  fix a :: int show "a div 0 = 0"
huffman@47141
  1756
    by (rule div_int_unique, simp add: divmod_int_rel_def)
huffman@47141
  1757
next
huffman@47141
  1758
  fix a :: int show "0 div a = 0"
huffman@47141
  1759
    by (rule div_int_unique, auto simp add: divmod_int_rel_def)
huffman@47141
  1760
qed
huffman@47141
  1761
haftmann@60429
  1762
end
haftmann@60429
  1763
haftmann@60517
  1764
lemma is_unit_int:
haftmann@60517
  1765
  "is_unit (k::int) \<longleftrightarrow> k = 1 \<or> k = - 1"
haftmann@60517
  1766
  by auto
haftmann@60517
  1767
haftmann@60685
  1768
instantiation int :: normalization_semidom
haftmann@60685
  1769
begin
haftmann@60685
  1770
haftmann@60685
  1771
definition normalize_int
haftmann@60685
  1772
  where [simp]: "normalize = (abs :: int \<Rightarrow> int)"
haftmann@60685
  1773
haftmann@60685
  1774
definition unit_factor_int
haftmann@60685
  1775
  where [simp]: "unit_factor = (sgn :: int \<Rightarrow> int)"
haftmann@60685
  1776
haftmann@60685
  1777
instance
haftmann@60685
  1778
proof
haftmann@60685
  1779
  fix k :: int
haftmann@60685
  1780
  assume "k \<noteq> 0"
haftmann@60685
  1781
  then have "\<bar>sgn k\<bar> = 1"
haftmann@60685
  1782
    by (cases "0::int" k rule: linorder_cases) simp_all
haftmann@60685
  1783
  then show "is_unit (unit_factor k)"
haftmann@60685
  1784
    by simp
haftmann@64240
  1785
qed (simp_all add: sgn_mult mult_sgn_abs)
haftmann@60685
  1786
  
haftmann@60685
  1787
end
haftmann@60685
  1788
  
wenzelm@60758
  1789
text\<open>Basic laws about division and remainder\<close>
haftmann@33361
  1790
haftmann@60868
  1791
lemma zdiv_int: "int (a div b) = int a div int b"
haftmann@60868
  1792
  by (simp add: divide_int_def)
haftmann@60868
  1793
haftmann@60868
  1794
lemma zmod_int: "int (a mod b) = int a mod int b"
haftmann@63950
  1795
  by (simp add: modulo_int_def int_dvd_iff)
haftmann@60868
  1796
  
wenzelm@60758
  1797
text \<open>Tool setup\<close>
wenzelm@60758
  1798
wenzelm@60758
  1799
ML \<open>
wenzelm@43594
  1800
structure Cancel_Div_Mod_Int = Cancel_Div_Mod
wenzelm@41550
  1801
(
haftmann@63950
  1802
  val div_name = @{const_name divide};
haftmann@63950
  1803
  val mod_name = @{const_name modulo};
haftmann@33361
  1804
  val mk_binop = HOLogic.mk_binop;
haftmann@33361
  1805
  val mk_sum = Arith_Data.mk_sum HOLogic.intT;
haftmann@33361
  1806
  val dest_sum = Arith_Data.dest_sum;
haftmann@33361
  1807
haftmann@64250
  1808
  val div_mod_eqs = map mk_meta_eq @{thms cancel_div_mod_rules};
haftmann@64250
  1809
haftmann@64250
  1810
  val prove_eq_sums = Arith_Data.prove_conv2 all_tac
haftmann@64250
  1811
    (Arith_Data.simp_all_tac @{thms diff_conv_add_uminus add_0_left add_0_right ac_simps})
wenzelm@41550
  1812
)
wenzelm@60758
  1813
\<close>
wenzelm@60758
  1814
wenzelm@60758
  1815
simproc_setup cancel_div_mod_int ("(k::int) + l") = \<open>K Cancel_Div_Mod_Int.proc\<close>
wenzelm@43594
  1816
huffman@47141
  1817
lemma pos_mod_conj: "(0::int) < b \<Longrightarrow> 0 \<le> a mod b \<and> a mod b < b"
haftmann@60868
  1818
  using divmod_int_rel [of a b]
huffman@47141
  1819
  by (auto simp add: divmod_int_rel_def prod_eq_iff)
haftmann@33361
  1820
wenzelm@45607
  1821
lemmas pos_mod_sign [simp] = pos_mod_conj [THEN conjunct1]
wenzelm@45607
  1822
   and pos_mod_bound [simp] = pos_mod_conj [THEN conjunct2]
haftmann@33361
  1823
huffman@47141
  1824
lemma neg_mod_conj: "b < (0::int) \<Longrightarrow> a mod b \<le> 0 \<and> b < a mod b"
haftmann@60868
  1825
  using divmod_int_rel [of a b]
huffman@47141
  1826
  by (auto simp add: divmod_int_rel_def prod_eq_iff)
haftmann@33361
  1827
wenzelm@45607
  1828
lemmas neg_mod_sign [simp] = neg_mod_conj [THEN conjunct1]
wenzelm@45607
  1829
   and neg_mod_bound [simp] = neg_mod_conj [THEN conjunct2]
haftmann@33361
  1830
haftmann@33361
  1831
wenzelm@60758
  1832
subsubsection \<open>General Properties of div and mod\<close>
haftmann@33361
  1833
haftmann@33361
  1834
lemma div_pos_pos_trivial: "[| (0::int) \<le> a;  a < b |] ==> a div b = 0"
huffman@47140
  1835
apply (rule div_int_unique)
haftmann@33361
  1836
apply (auto simp add: divmod_int_rel_def)
haftmann@33361
  1837
done
haftmann@33361
  1838
haftmann@33361
  1839
lemma div_neg_neg_trivial: "[| a \<le> (0::int);  b < a |] ==> a div b = 0"
huffman@47140
  1840
apply (rule div_int_unique)
haftmann@33361
  1841
apply (auto simp add: divmod_int_rel_def)
haftmann@33361
  1842
done
haftmann@33361
  1843
haftmann@33361
  1844
lemma div_pos_neg_trivial: "[| (0::int) < a;  a+b \<le> 0 |] ==> a div b = -1"
huffman@47140
  1845
apply (rule div_int_unique)
haftmann@33361
  1846
apply (auto simp add: divmod_int_rel_def)
haftmann@33361
  1847
done
haftmann@33361
  1848
haftmann@33361
  1849
(*There is no div_neg_pos_trivial because  0 div b = 0 would supersede it*)
haftmann@33361
  1850
haftmann@33361
  1851
lemma mod_pos_pos_trivial: "[| (0::int) \<le> a;  a < b |] ==> a mod b = a"
huffman@47140
  1852
apply (rule_tac q = 0 in mod_int_unique)
haftmann@33361
  1853
apply (auto simp add: divmod_int_rel_def)
haftmann@33361
  1854
done
haftmann@33361
  1855
haftmann@33361
  1856
lemma mod_neg_neg_trivial: "[| a \<le> (0::int);  b < a |] ==> a mod b = a"
huffman@47140
  1857
apply (rule_tac q = 0 in mod_int_unique)
haftmann@33361
  1858
apply (auto simp add: divmod_int_rel_def)
haftmann@33361
  1859
done
haftmann@33361
  1860
haftmann@33361
  1861
lemma mod_pos_neg_trivial: "[| (0::int) < a;  a+b \<le> 0 |] ==> a mod b = a+b"
huffman@47140
  1862
apply (rule_tac q = "-1" in mod_int_unique)
haftmann@33361
  1863
apply (auto simp add: divmod_int_rel_def)
haftmann@33361
  1864
done
haftmann@33361
  1865
wenzelm@61799
  1866
text\<open>There is no \<open>mod_neg_pos_trivial\<close>.\<close>
wenzelm@60758
  1867
wenzelm@60758
  1868
wenzelm@60758
  1869
subsubsection \<open>Laws for div and mod with Unary Minus\<close>
haftmann@33361
  1870
haftmann@33361
  1871
lemma zminus1_lemma:
huffman@47139
  1872
     "divmod_int_rel a b (q, r) ==> b \<noteq> 0
lp15@60562
  1873
      ==> divmod_int_rel (-a) b (if r=0 then -q else -q - 1,
haftmann@33361
  1874
                          if r=0 then 0 else b-r)"
haftmann@33361
  1875
by (force simp add: split_ifs divmod_int_rel_def linorder_neq_iff right_diff_distrib)
haftmann@33361
  1876
haftmann@33361
  1877
haftmann@33361
  1878
lemma zdiv_zminus1_eq_if:
lp15@60562
  1879
     "b \<noteq> (0::int)
lp15@60562
  1880
      ==> (-a) div b =
haftmann@33361
  1881
          (if a mod b = 0 then - (a div b) else  - (a div b) - 1)"
haftmann@60868
  1882
by (blast intro: divmod_int_rel [THEN zminus1_lemma, THEN div_int_unique])
haftmann@33361
  1883
haftmann@33361
  1884
lemma zmod_zminus1_eq_if:
haftmann@33361
  1885
     "(-a::int) mod b = (if a mod b = 0 then 0 else  b - (a mod b))"
haftmann@33361
  1886
apply (case_tac "b = 0", simp)
haftmann@60868
  1887
apply (blast intro: divmod_int_rel [THEN zminus1_lemma, THEN mod_int_unique])
haftmann@33361
  1888
done
haftmann@33361
  1889
haftmann@33361
  1890
lemma zmod_zminus1_not_zero:
haftmann@33361
  1891
  fixes k l :: int
haftmann@33361
  1892
  shows "- k mod l \<noteq> 0 \<Longrightarrow> k mod l \<noteq> 0"
haftmann@33361
  1893
  unfolding zmod_zminus1_eq_if by auto
haftmann@33361
  1894
haftmann@33361
  1895
lemma zdiv_zminus2_eq_if:
lp15@60562
  1896
     "b \<noteq> (0::int)
lp15@60562
  1897
      ==> a div (-b) =
haftmann@33361
  1898
          (if a mod b = 0 then - (a div b) else  - (a div b) - 1)"
huffman@47159
  1899
by (simp add: zdiv_zminus1_eq_if div_minus_right)
haftmann@33361
  1900
haftmann@33361
  1901
lemma zmod_zminus2_eq_if:
haftmann@33361
  1902
     "a mod (-b::int) = (if a mod b = 0 then 0 else  (a mod b) - b)"
huffman@47159
  1903
by (simp add: zmod_zminus1_eq_if mod_minus_right)
haftmann@33361
  1904
haftmann@33361
  1905
lemma zmod_zminus2_not_zero:
haftmann@33361
  1906
  fixes k l :: int
haftmann@33361
  1907
  shows "k mod - l \<noteq> 0 \<Longrightarrow> k mod l \<noteq> 0"
lp15@60562
  1908
  unfolding zmod_zminus2_eq_if by auto
haftmann@33361
  1909
haftmann@33361
  1910
wenzelm@60758
  1911
subsubsection \<open>Monotonicity in the First Argument (Dividend)\<close>
haftmann@33361
  1912
haftmann@33361
  1913
lemma zdiv_mono1: "[| a \<le> a';  0 < (b::int) |] ==> a div b \<le> a' div b"
haftmann@64246
  1914
using mult_div_mod_eq [symmetric, of a b]
haftmann@64246
  1915
using mult_div_mod_eq [symmetric, of a' b]
haftmann@64246
  1916
apply -
haftmann@33361
  1917
apply (rule unique_quotient_lemma)
haftmann@33361
  1918
apply (erule subst)
haftmann@33361
  1919
apply (erule subst, simp_all)
haftmann@33361
  1920
done
haftmann@33361
  1921
haftmann@33361
  1922
lemma zdiv_mono1_neg: "[| a \<le> a';  (b::int) < 0 |] ==> a' div b \<le> a div b"
haftmann@64246
  1923
using mult_div_mod_eq [symmetric, of a b]
haftmann@64246
  1924
using mult_div_mod_eq [symmetric, of a' b]
haftmann@64246
  1925
apply -
haftmann@33361
  1926
apply (rule unique_quotient_lemma_neg)
haftmann@33361
  1927
apply (erule subst)
haftmann@33361
  1928
apply (erule subst, simp_all)
haftmann@33361
  1929
done
haftmann@33361
  1930
haftmann@33361
  1931
wenzelm@60758
  1932
subsubsection \<open>Monotonicity in the Second Argument (Divisor)\<close>
haftmann@33361
  1933
haftmann@33361
  1934
lemma q_pos_lemma:
haftmann@33361
  1935
     "[| 0 \<le> b'*q' + r'; r' < b';  0 < b' |] ==> 0 \<le> (q'::int)"
haftmann@33361
  1936
apply (subgoal_tac "0 < b'* (q' + 1) ")
haftmann@33361
  1937
 apply (simp add: zero_less_mult_iff)
webertj@49962
  1938
apply (simp add: distrib_left)
haftmann@33361
  1939
done
haftmann@33361
  1940
haftmann@33361
  1941
lemma zdiv_mono2_lemma:
lp15@60562
  1942
     "[| b*q + r = b'*q' + r';  0 \<le> b'*q' + r';
lp15@60562
  1943
         r' < b';  0 \<le> r;  0 < b';  b' \<le> b |]
haftmann@33361
  1944
      ==> q \<le> (q'::int)"
lp15@60562
  1945
apply (frule q_pos_lemma, assumption+)
haftmann@33361
  1946
apply (subgoal_tac "b*q < b* (q' + 1) ")
haftmann@33361
  1947
 apply (simp add: mult_less_cancel_left)
haftmann@33361
  1948
apply (subgoal_tac "b*q = r' - r + b'*q'")
haftmann@33361
  1949
 prefer 2 apply simp
webertj@49962
  1950
apply (simp (no_asm_simp) add: distrib_left)
haftmann@57512
  1951
apply (subst add.commute, rule add_less_le_mono, arith)
haftmann@33361
  1952
apply (rule mult_right_mono, auto)
haftmann@33361
  1953
done
haftmann@33361
  1954
haftmann@33361
  1955
lemma zdiv_mono2:
haftmann@33361
  1956
     "[| (0::int) \<le> a;  0 < b';  b' \<le> b |] ==> a div b \<le> a div b'"
haftmann@33361
  1957
apply (subgoal_tac "b \<noteq> 0")
haftmann@64246
  1958
  prefer 2 apply arith
haftmann@64246
  1959
using mult_div_mod_eq [symmetric, of a b]
haftmann@64246
  1960
using mult_div_mod_eq [symmetric, of a b']
haftmann@64246
  1961
apply -
haftmann@33361
  1962
apply (rule zdiv_mono2_lemma)
haftmann@33361
  1963
apply (erule subst)
haftmann@33361
  1964
apply (erule subst, simp_all)
haftmann@33361
  1965
done
haftmann@33361
  1966
haftmann@33361
  1967
lemma q_neg_lemma:
haftmann@33361
  1968
     "[| b'*q' + r' < 0;  0 \<le> r';  0 < b' |] ==> q' \<le> (0::int)"
haftmann@33361
  1969
apply (subgoal_tac "b'*q' < 0")
haftmann@33361
  1970
 apply (simp add: mult_less_0_iff, arith)
haftmann@33361
  1971
done
haftmann@33361
  1972
haftmann@33361
  1973
lemma zdiv_mono2_neg_lemma:
lp15@60562
  1974
     "[| b*q + r = b'*q' + r';  b'*q' + r' < 0;
lp15@60562
  1975
         r < b;  0 \<le> r';  0 < b';  b' \<le> b |]
haftmann@33361
  1976
      ==> q' \<le> (q::int)"
lp15@60562
  1977
apply (frule q_neg_lemma, assumption+)
haftmann@33361
  1978
apply (subgoal_tac "b*q' < b* (q + 1) ")
haftmann@33361
  1979
 apply (simp add: mult_less_cancel_left)
webertj@49962
  1980
apply (simp add: distrib_left)
haftmann@33361
  1981
apply (subgoal_tac "b*q' \<le> b'*q'")
haftmann@33361
  1982
 prefer 2 apply (simp add: mult_right_mono_neg, arith)
haftmann@33361
  1983
done
haftmann@33361
  1984
haftmann@33361
  1985
lemma zdiv_mono2_neg:
haftmann@33361
  1986
     "[| a < (0::int);  0 < b';  b' \<le> b |] ==> a div b' \<le> a div b"
haftmann@64246
  1987
using mult_div_mod_eq [symmetric, of a b]
haftmann@64246
  1988
using mult_div_mod_eq [symmetric, of a b']
haftmann@64246
  1989
apply -
haftmann@33361
  1990
apply (rule zdiv_mono2_neg_lemma)
haftmann@33361
  1991
apply (erule subst)
haftmann@33361
  1992
apply (erule subst, simp_all)
haftmann@33361
  1993
done
haftmann@33361
  1994
haftmann@33361
  1995
wenzelm@60758
  1996
subsubsection \<open>More Algebraic Laws for div and mod\<close>
wenzelm@60758
  1997
wenzelm@60758
  1998
text\<open>proving (a*b) div c = a * (b div c) + a * (b mod c)\<close>
haftmann@33361
  1999
haftmann@33361
  2000
lemma zmult1_lemma:
lp15@60562
  2001
     "[| divmod_int_rel b c (q, r) |]
haftmann@33361
  2002
      ==> divmod_int_rel (a * b) c (a*q + a*r div c, a*r mod c)"
haftmann@57514
  2003
by (auto simp add: split_ifs divmod_int_rel_def linorder_neq_iff distrib_left ac_simps)
haftmann@33361
  2004
haftmann@33361
  2005
lemma zdiv_zmult1_eq: "(a*b) div c = a*(b div c) + a*(b mod c) div (c::int)"
haftmann@33361
  2006
apply (case_tac "c = 0", simp)
haftmann@60868
  2007
apply (blast intro: divmod_int_rel [THEN zmult1_lemma, THEN div_int_unique])
haftmann@33361
  2008
done
haftmann@33361
  2009
wenzelm@60758
  2010
text\<open>proving (a+b) div c = a div c + b div c + ((a mod c + b mod c) div c)\<close>
haftmann@33361
  2011
haftmann@33361
  2012
lemma zadd1_lemma:
lp15@60562
  2013
     "[| divmod_int_rel a c (aq, ar);  divmod_int_rel b c (bq, br) |]
haftmann@33361
  2014
      ==> divmod_int_rel (a+b) c (aq + bq + (ar+br) div c, (ar+br) mod c)"
webertj@49962
  2015
by (force simp add: split_ifs divmod_int_rel_def linorder_neq_iff distrib_left)
haftmann@33361
  2016
haftmann@33361
  2017
(*NOT suitable for rewriting: the RHS has an instance of the LHS*)
haftmann@33361
  2018
lemma zdiv_zadd1_eq:
haftmann@33361
  2019
     "(a+b) div (c::int) = a div c + b div c + ((a mod c + b mod c) div c)"
haftmann@33361
  2020
apply (case_tac "c = 0", simp)
haftmann@60868
  2021
apply (blast intro: zadd1_lemma [OF divmod_int_rel divmod_int_rel] div_int_unique)
haftmann@33361
  2022
done
haftmann@33361
  2023
haftmann@33361
  2024
lemma zmod_eq_0_iff: "(m mod d = 0) = (EX q::int. m = d*q)"
haftmann@33361
  2025
by (simp add: dvd_eq_mod_eq_0 [symmetric] dvd_def)
haftmann@33361
  2026
haftmann@33361
  2027
(* REVISIT: should this be generalized to all semiring_div types? *)
haftmann@33361
  2028
lemmas zmod_eq_0D [dest!] = zmod_eq_0_iff [THEN iffD1]
haftmann@33361
  2029
haftmann@33361
  2030
wenzelm@60758
  2031
subsubsection \<open>Proving  @{term "a div (b * c) = (a div b) div c"}\<close>
haftmann@33361
  2032
haftmann@33361
  2033
(*The condition c>0 seems necessary.  Consider that 7 div ~6 = ~2 but
haftmann@33361
  2034
  7 div 2 div ~3 = 3 div ~3 = ~1.  The subcase (a div b) mod c = 0 seems
haftmann@33361
  2035
  to cause particular problems.*)
haftmann@33361
  2036
wenzelm@60758
  2037
text\<open>first, four lemmas to bound the remainder for the cases b<0 and b>0\<close>
haftmann@33361
  2038
blanchet@55085
  2039
lemma zmult2_lemma_aux1: "[| (0::int) < c;  b < r;  r \<le> 0 |] ==> b * c < b * (q mod c) + r"
haftmann@33361
  2040
apply (subgoal_tac "b * (c - q mod c) < r * 1")
haftmann@33361
  2041
 apply (simp add: algebra_simps)
haftmann@33361
  2042
apply (rule order_le_less_trans)
haftmann@33361
  2043
 apply (erule_tac [2] mult_strict_right_mono)
haftmann@33361
  2044
 apply (rule mult_left_mono_neg)
huffman@35216
  2045
  using add1_zle_eq[of "q mod c"]apply(simp add: algebra_simps)
haftmann@33361
  2046
 apply (simp)
haftmann@33361
  2047
apply (simp)
haftmann@33361
  2048
done
haftmann@33361
  2049
haftmann@33361
  2050
lemma zmult2_lemma_aux2:
haftmann@33361
  2051
     "[| (0::int) < c;   b < r;  r \<le> 0 |] ==> b * (q mod c) + r \<le> 0"
haftmann@33361
  2052
apply (subgoal_tac "b * (q mod c) \<le> 0")
haftmann@33361
  2053
 apply arith
haftmann@33361
  2054
apply (simp add: mult_le_0_iff)
haftmann@33361
  2055
done
haftmann@33361
  2056
haftmann@33361
  2057
lemma zmult2_lemma_aux3: "[| (0::int) < c;  0 \<le> r;  r < b |] ==> 0 \<le> b * (q mod c) + r"
haftmann@33361
  2058
apply (subgoal_tac "0 \<le> b * (q mod c) ")
haftmann@33361
  2059
apply arith
haftmann@33361
  2060
apply (simp add: zero_le_mult_iff)
haftmann@33361
  2061
done
haftmann@33361
  2062
haftmann@33361
  2063
lemma zmult2_lemma_aux4: "[| (0::int) < c; 0 \<le> r; r < b |] ==> b * (q mod c) + r < b * c"
haftmann@33361
  2064
apply (subgoal_tac "r * 1 < b * (c - q mod c) ")
haftmann@33361
  2065
 apply (simp add: right_diff_distrib)
haftmann@33361
  2066
apply (rule order_less_le_trans)
haftmann@33361
  2067
 apply (erule mult_strict_right_mono)
haftmann@33361
  2068
 apply (rule_tac [2] mult_left_mono)
haftmann@33361
  2069
  apply simp
huffman@35216
  2070
 using add1_zle_eq[of "q mod c"] apply (simp add: algebra_simps)
haftmann@33361
  2071
apply simp
haftmann@33361
  2072
done
haftmann@33361
  2073
lp15@60562
  2074
lemma zmult2_lemma: "[| divmod_int_rel a b (q, r); 0 < c |]
haftmann@33361
  2075
      ==> divmod_int_rel a (b * c) (q div c, b*(q mod c) + r)"
haftmann@57514
  2076
by (auto simp add: mult.assoc divmod_int_rel_def linorder_neq_iff
lp15@60562
  2077
                   zero_less_mult_iff distrib_left [symmetric]
nipkow@62390
  2078
                   zmult2_lemma_aux1 zmult2_lemma_aux2 zmult2_lemma_aux3 zmult2_lemma_aux4 mult_less_0_iff split: if_split_asm)
haftmann@33361
  2079
haftmann@53068
  2080
lemma zdiv_zmult2_eq:
haftmann@53068
  2081
  fixes a b c :: int
haftmann@53068
  2082
  shows "0 \<le> c \<Longrightarrow> a div (b * c) = (a div b) div c"
haftmann@33361
  2083
apply (case_tac "b = 0", simp)
haftmann@60868
  2084
apply (force simp add: le_less divmod_int_rel [THEN zmult2_lemma, THEN div_int_unique])
haftmann@33361
  2085
done
haftmann@33361
  2086
haftmann@33361
  2087
lemma zmod_zmult2_eq:
haftmann@53068
  2088
  fixes a b c :: int
haftmann@53068
  2089
  shows "0 \<le> c \<Longrightarrow> a mod (b * c) = b * (a div b mod c) + a mod b"
haftmann@33361
  2090
apply (case_tac "b = 0", simp)
haftmann@60868
  2091
apply (force simp add: le_less divmod_int_rel [THEN zmult2_lemma, THEN mod_int_unique])
haftmann@33361
  2092
done
haftmann@33361
  2093
huffman@47108
  2094
lemma div_pos_geq:
huffman@47108
  2095
  fixes k l :: int
huffman@47108
  2096
  assumes "0 < l" and "l \<le> k"
huffman@47108
  2097
  shows "k div l = (k - l) div l + 1"
huffman@47108
  2098
proof -
huffman@47108
  2099
  have "k = (k - l) + l" by simp
huffman@47108
  2100
  then obtain j where k: "k = j + l" ..
eberlm@63499
  2101
  with assms show ?thesis by (simp add: div_add_self2)
huffman@47108
  2102
qed
huffman@47108
  2103
huffman@47108
  2104
lemma mod_pos_geq:
huffman@47108
  2105
  fixes k l :: int
huffman@47108
  2106
  assumes "0 < l" and "l \<le> k"
huffman@47108
  2107
  shows "k mod l = (k - l) mod l"
huffman@47108
  2108
proof -
huffman@47108
  2109
  have "k = (k - l) + l" by simp
huffman@47108
  2110
  then obtain j where k: "k = j + l" ..
huffman@47108
  2111
  with assms show ?thesis by simp
huffman@47108
  2112
qed
huffman@47108
  2113
haftmann@33361
  2114
wenzelm@60758
  2115
subsubsection \<open>Splitting Rules for div and mod\<close>
wenzelm@60758
  2116
wenzelm@60758
  2117
text\<open>The proofs of the two lemmas below are essentially identical\<close>
haftmann@33361
  2118
haftmann@33361
  2119
lemma split_pos_lemma:
lp15@60562
  2120
 "0<k ==>
haftmann@33361
  2121
    P(n div k :: int)(n mod k) = (\<forall>i j. 0\<le>j & j<k & n = k*i + j --> P i j)"
haftmann@33361
  2122
apply (rule iffI, clarify)
lp15@60562
  2123
 apply (erule_tac P="P x y" for x y in rev_mp)
lp15@60562
  2124
 apply (subst mod_add_eq)
lp15@60562
  2125
 apply (subst zdiv_zadd1_eq)
lp15@60562
  2126
 apply (simp add: div_pos_pos_trivial mod_pos_pos_trivial)
wenzelm@60758
  2127
txt\<open>converse direction\<close>
lp15@60562
  2128
apply (drule_tac x = "n div k" in spec)
haftmann@33361
  2129
apply (drule_tac x = "n mod k" in spec, simp)
haftmann@33361
  2130
done
haftmann@33361
  2131
haftmann@33361
  2132
lemma split_neg_lemma:
haftmann@33361
  2133
 "k<0 ==>
haftmann@33361
  2134
    P(n div k :: int)(n mod k) = (\<forall>i j. k<j & j\<le>0 & n = k*i + j --> P i j)"
haftmann@33361
  2135
apply (rule iffI, clarify)
lp15@60562
  2136
 apply (erule_tac P="P x y" for x y in rev_mp)
lp15@60562
  2137
 apply (subst mod_add_eq)
lp15@60562
  2138
 apply (subst zdiv_zadd1_eq)
lp15@60562
  2139
 apply (simp add: div_neg_neg_trivial mod_neg_neg_trivial)
wenzelm@60758
  2140
txt\<open>converse direction\<close>
lp15@60562
  2141
apply (drule_tac x = "n div k" in spec)
haftmann@33361
  2142
apply (drule_tac x = "n mod k" in spec, simp)
haftmann@33361
  2143
done
haftmann@33361
  2144
haftmann@33361
  2145
lemma split_zdiv:
haftmann@33361
  2146
 "P(n div k :: int) =
lp15@60562
  2147
  ((k = 0 --> P 0) &
lp15@60562
  2148
   (0<k --> (\<forall>i j. 0\<le>j & j<k & n = k*i + j --> P i)) &
haftmann@33361
  2149
   (k<0 --> (\<forall>i j. k<j & j\<le>0 & n = k*i + j --> P i)))"
haftmann@33361
  2150
apply (case_tac "k=0", simp)
haftmann@33361
  2151
apply (simp only: linorder_neq_iff)
lp15@60562
  2152
apply (erule disjE)
lp15@60562
  2153
 apply (simp_all add: split_pos_lemma [of concl: "%x y. P x"]
haftmann@33361
  2154
                      split_neg_lemma [of concl: "%x y. P x"])
haftmann@33361
  2155
done
haftmann@33361
  2156
haftmann@33361
  2157
lemma split_zmod:
haftmann@33361
  2158
 "P(n mod k :: int) =
lp15@60562
  2159
  ((k = 0 --> P n) &
lp15@60562
  2160
   (0<k --> (\<forall>i j. 0\<le>j & j<k & n = k*i + j --> P j)) &
haftmann@33361
  2161
   (k<0 --> (\<forall>i j. k<j & j\<le>0 & n = k*i + j --> P j)))"
haftmann@33361
  2162
apply (case_tac "k=0", simp)
haftmann@33361
  2163
apply (simp only: linorder_neq_iff)
lp15@60562
  2164
apply (erule disjE)
lp15@60562
  2165
 apply (simp_all add: split_pos_lemma [of concl: "%x y. P y"]
haftmann@33361
  2166
                      split_neg_lemma [of concl: "%x y. P y"])
haftmann@33361
  2167
done
haftmann@33361
  2168
haftmann@63950
  2169
text \<open>Enable (lin)arith to deal with @{const divide} and @{const modulo}
webertj@33730
  2170
  when these are applied to some constant that is of the form
wenzelm@60758
  2171
  @{term "numeral k"}:\<close>
huffman@47108
  2172
declare split_zdiv [of _ _ "numeral k", arith_split] for k
huffman@47108
  2173
declare split_zmod [of _ _ "numeral k", arith_split] for k
haftmann@33361
  2174
haftmann@33361
  2175
wenzelm@61799
  2176
subsubsection \<open>Computing \<open>div\<close> and \<open>mod\<close> with shifting\<close>
huffman@47166
  2177
huffman@47166
  2178
lemma pos_divmod_int_rel_mult_2:
huffman@47166
  2179
  assumes "0 \<le> b"
huffman@47166
  2180
  assumes "divmod_int_rel a b (q, r)"
huffman@47166
  2181
  shows "divmod_int_rel (1 + 2*a) (2*b) (q, 1 + 2*r)"
huffman@47166
  2182
  using assms unfolding divmod_int_rel_def by auto
huffman@47166
  2183
huffman@47166
  2184
lemma neg_divmod_int_rel_mult_2:
huffman@47166
  2185
  assumes "b \<le> 0"
huffman@47166
  2186
  assumes "divmod_int_rel (a + 1) b (q, r)"
huffman@47166
  2187
  shows "divmod_int_rel (1 + 2*a) (2*b) (q, 2*r - 1)"
huffman@47166
  2188
  using assms unfolding divmod_int_rel_def by auto
haftmann@33361
  2189
wenzelm@60758
  2190
text\<open>computing div by shifting\<close>
haftmann@33361
  2191
haftmann@33361
  2192
lemma pos_zdiv_mult_2: "(0::int) \<le> a ==> (1 + 2*b) div (2*a) = b div a"
haftmann@60868
  2193
  using pos_divmod_int_rel_mult_2 [OF _ divmod_int_rel]
huffman@47166
  2194
  by (rule div_int_unique)
haftmann@33361
  2195
lp15@60562
  2196
lemma neg_zdiv_mult_2:
boehmes@35815
  2197
  assumes A: "a \<le> (0::int)" shows "(1 + 2*b) div (2*a) = (b+1) div a"
haftmann@60868
  2198
  using neg_divmod_int_rel_mult_2 [OF A divmod_int_rel]
huffman@47166
  2199
  by (rule div_int_unique)
haftmann@33361
  2200
huffman@47108
  2201
(* FIXME: add rules for negative numerals *)
huffman@47108
  2202
lemma zdiv_numeral_Bit0 [simp]:
huffman@47108
  2203
  "numeral (Num.Bit0 v) div numeral (Num.Bit0 w) =
huffman@47108
  2204
    numeral v div (numeral w :: int)"
huffman@47108
  2205
  unfolding numeral.simps unfolding mult_2 [symmetric]
huffman@47108
  2206
  by (rule div_mult_mult1, simp)
huffman@47108
  2207
huffman@47108
  2208
lemma zdiv_numeral_Bit1 [simp]:
lp15@60562
  2209
  "numeral (Num.Bit1 v) div numeral (Num.Bit0 w) =
huffman@47108
  2210
    (numeral v div (numeral w :: int))"
huffman@47108
  2211
  unfolding numeral.simps
haftmann@57512
  2212
  unfolding mult_2 [symmetric] add.commute [of _ 1]
huffman@47108
  2213
  by (rule pos_zdiv_mult_2, simp)
haftmann@33361
  2214
haftmann@33361
  2215
lemma pos_zmod_mult_2:
haftmann@33361
  2216
  fixes a b :: int
haftmann@33361
  2217
  assumes "0 \<le> a"
haftmann@33361
  2218
  shows "(1 + 2 * b) mod (2 * a) = 1 + 2 * (b mod a)"
haftmann@60868
  2219
  using pos_divmod_int_rel_mult_2 [OF assms divmod_int_rel]
huffman@47166
  2220
  by (rule mod_int_unique)
haftmann@33361
  2221
haftmann@33361
  2222
lemma neg_zmod_mult_2:
haftmann@33361
  2223
  fixes a b :: int
haftmann@33361
  2224
  assumes "a \<le> 0"
haftmann@33361
  2225
  shows "(1 + 2 * b) mod (2 * a) = 2 * ((b + 1) mod a) - 1"
haftmann@60868
  2226
  using neg_divmod_int_rel_mult_2 [OF assms divmod_int_rel]
huffman@47166
  2227
  by (rule mod_int_unique)
haftmann@33361
  2228
huffman@47108
  2229
(* FIXME: add rules for negative numerals *)
huffman@47108
  2230
lemma zmod_numeral_Bit0 [simp]:
lp15@60562
  2231
  "numeral (Num.Bit0 v) mod numeral (Num.Bit0 w) =
huffman@47108
  2232
    (2::int) * (numeral v mod numeral w)"
huffman@47108
  2233
  unfolding numeral_Bit0 [of v] numeral_Bit0 [of w]
huffman@47108
  2234
  unfolding mult_2 [symmetric] by (rule mod_mult_mult1)
huffman@47108
  2235
huffman@47108
  2236
lemma zmod_numeral_Bit1 [simp]:
huffman@47108
  2237
  "numeral (Num.Bit1 v) mod numeral (Num.Bit0 w) =
huffman@47108
  2238
    2 * (numeral v mod numeral w) + (1::int)"
huffman@47108
  2239
  unfolding numeral_Bit1 [of v] numeral_Bit0 [of w]
haftmann@57512
  2240
  unfolding mult_2 [symmetric] add.commute [of _ 1]
huffman@47108
  2241
  by (rule pos_zmod_mult_2, simp)
haftmann@33361
  2242
nipkow@39489
  2243
lemma zdiv_eq_0_iff:
nipkow@39489
  2244
 "(i::int) div k = 0 \<longleftrightarrow> k=0 \<or> 0\<le>i \<and> i<k \<or> i\<le>0 \<and> k<i" (is "?L = ?R")
nipkow@39489
  2245
proof
nipkow@39489
  2246
  assume ?L
nipkow@39489
  2247
  have "?L \<longrightarrow> ?R" by (rule split_zdiv[THEN iffD2]) simp
wenzelm@60758
  2248
  with \<open>?L\<close> show ?R by blast
nipkow@39489
  2249
next
nipkow@39489
  2250
  assume ?R thus ?L
nipkow@39489
  2251
    by(auto simp: div_pos_pos_trivial div_neg_neg_trivial)
nipkow@39489
  2252
qed
nipkow@39489
  2253
haftmann@63947
  2254
lemma zmod_trival_iff:
haftmann@63947
  2255
  fixes i k :: int
haftmann@63947
  2256
  shows "i mod k = i \<longleftrightarrow> k = 0 \<or> 0 \<le> i \<and> i < k \<or> i \<le> 0 \<and> k < i"
haftmann@63947
  2257
proof -
haftmann@63947
  2258
  have "i mod k = i \<longleftrightarrow> i div k = 0"
haftmann@64242
  2259
    by safe (insert div_mult_mod_eq [of i k], auto)
haftmann@63947
  2260
  with zdiv_eq_0_iff
haftmann@63947
  2261
  show ?thesis
haftmann@63947
  2262
    by simp
haftmann@63947
  2263
qed
nipkow@39489
  2264
wenzelm@60758
  2265
subsubsection \<open>Quotients of Signs\<close>
haftmann@33361
  2266
haftmann@60868
  2267
lemma div_eq_minus1: "(0::int) < b ==> -1 div b = -1"
haftmann@60868
  2268
by (simp add: divide_int_def)
haftmann@60868
  2269
haftmann@60868
  2270
lemma zmod_minus1: "(0::int) < b ==> -1 mod b = b - 1"
haftmann@63950
  2271
by (simp add: modulo_int_def)
haftmann@60868
  2272
haftmann@33361
  2273
lemma div_neg_pos_less0: "[| a < (0::int);  0 < b |] ==> a div b < 0"
haftmann@33361
  2274
apply (subgoal_tac "a div b \<le> -1", force)
haftmann@33361
  2275
apply (rule order_trans)
haftmann@33361
  2276
apply (rule_tac a' = "-1" in zdiv_mono1)
haftmann@33361
  2277
apply (auto simp add: div_eq_minus1)
haftmann@33361
  2278
done
haftmann@33361
  2279
haftmann@33361
  2280
lemma div_nonneg_neg_le0: "[| (0::int) \<le> a; b < 0 |] ==> a div b \<le> 0"
haftmann@33361
  2281
by (drule zdiv_mono1_neg, auto)
haftmann@33361
  2282
haftmann@33361
  2283
lemma div_nonpos_pos_le0: "[| (a::int) \<le> 0; b > 0 |] ==> a div b \<le> 0"
haftmann@33361
  2284
by (drule zdiv_mono1, auto)
haftmann@33361
  2285
wenzelm@61799
  2286
text\<open>Now for some equivalences of the form \<open>a div b >=< 0 \<longleftrightarrow> \<dots>\<close>
wenzelm@61799
  2287
conditional upon the sign of \<open>a\<close> or \<open>b\<close>. There are many more.
wenzelm@60758
  2288
They should all be simp rules unless that causes too much search.\<close>
nipkow@33804
  2289
haftmann@33361
  2290
lemma pos_imp_zdiv_nonneg_iff: "(0::int) < b ==> (0 \<le> a div b) = (0 \<le> a)"
haftmann@33361
  2291
apply auto
haftmann@33361
  2292
apply (drule_tac [2] zdiv_mono1)
haftmann@33361
  2293
apply (auto simp add: linorder_neq_iff)
haftmann@33361
  2294
apply (simp (no_asm_use) add: linorder_not_less [symmetric])
haftmann@33361
  2295
apply (blast intro: div_neg_pos_less0)
haftmann@33361
  2296
done
haftmann@33361
  2297
haftmann@60868
  2298
lemma pos_imp_zdiv_pos_iff:
haftmann@60868
  2299
  "0<k \<Longrightarrow> 0 < (i::int) div k \<longleftrightarrow> k \<le> i"
haftmann@60868
  2300
using pos_imp_zdiv_nonneg_iff[of k i] zdiv_eq_0_iff[of i k]
haftmann@60868
  2301
by arith
haftmann@60868
  2302
haftmann@33361
  2303
lemma neg_imp_zdiv_nonneg_iff:
nipkow@33804
  2304
  "b < (0::int) ==> (0 \<le> a div b) = (a \<le> (0::int))"
huffman@47159
  2305
apply (subst div_minus_minus [symmetric])
haftmann@33361
  2306
apply (subst pos_imp_zdiv_nonneg_iff, auto)
haftmann@33361
  2307
done
haftmann@33361
  2308
haftmann@33361
  2309
(*But not (a div b \<le> 0 iff a\<le>0); consider a=1, b=2 when a div b = 0.*)
haftmann@33361
  2310
lemma pos_imp_zdiv_neg_iff: "(0::int) < b ==> (a div b < 0) = (a < 0)"
haftmann@33361
  2311
by (simp add: linorder_not_le [symmetric] pos_imp_zdiv_nonneg_iff)
haftmann@33361
  2312
haftmann@33361
  2313
(*Again the law fails for \<le>: consider a = -1, b = -2 when a div b = 0*)
haftmann@33361
  2314
lemma neg_imp_zdiv_neg_iff: "b < (0::int) ==> (a div b < 0) = (0 < a)"
haftmann@33361
  2315
by (simp add: linorder_not_le [symmetric] neg_imp_zdiv_nonneg_iff)
haftmann@33361
  2316
nipkow@33804
  2317
lemma nonneg1_imp_zdiv_pos_iff:
nipkow@33804
  2318
  "(0::int) <= a \<Longrightarrow> (a div b > 0) = (a >= b & b>0)"
nipkow@33804
  2319
apply rule
nipkow@33804
  2320
 apply rule
nipkow@33804
  2321
  using div_pos_pos_trivial[of a b]apply arith
nipkow@33804
  2322
 apply(cases "b=0")apply simp
nipkow@33804
  2323
 using div_nonneg_neg_le0[of a b]apply arith
nipkow@33804
  2324
using int_one_le_iff_zero_less[of "a div b"] zdiv_mono1[of b a b]apply simp
nipkow@33804
  2325
done
nipkow@33804
  2326
nipkow@39489
  2327
lemma zmod_le_nonneg_dividend: "(m::int) \<ge> 0 ==> m mod k \<le> m"
nipkow@39489
  2328
apply (rule split_zmod[THEN iffD2])
nipkow@44890
  2329
apply(fastforce dest: q_pos_lemma intro: split_mult_pos_le)
nipkow@39489
  2330
done
nipkow@39489
  2331
haftmann@60868
  2332
haftmann@60868
  2333
subsubsection \<open>Computation of Division and Remainder\<close>
haftmann@60868
  2334
haftmann@61275
  2335
instantiation int :: semiring_numeral_div
haftmann@61275
  2336
begin
haftmann@61275
  2337
haftmann@61275
  2338
definition divmod_int :: "num \<Rightarrow> num \<Rightarrow> int \<times> int"
haftmann@61275
  2339
where
haftmann@61275
  2340
  "divmod_int m n = (numeral m div numeral n, numeral m mod numeral n)"
haftmann@61275
  2341
haftmann@61275
  2342
definition divmod_step_int :: "num \<Rightarrow> int \<times> int \<Rightarrow> int \<times> int"
haftmann@61275
  2343
where
haftmann@61275
  2344
  "divmod_step_int l qr = (let (q, r) = qr
haftmann@61275
  2345
    in if r \<ge> numeral l then (2 * q + 1, r - numeral l)
haftmann@61275
  2346
    else (2 * q, r))"
haftmann@61275
  2347
haftmann@61275
  2348
instance
haftmann@61275
  2349
  by standard (auto intro: zmod_le_nonneg_dividend simp add: divmod_int_def divmod_step_int_def
haftmann@61275
  2350
    pos_imp_zdiv_pos_iff div_pos_pos_trivial mod_pos_pos_trivial zmod_zmult2_eq zdiv_zmult2_eq)
haftmann@61275
  2351
haftmann@61275
  2352
end
haftmann@61275
  2353
haftmann@61275
  2354
declare divmod_algorithm_code [where ?'a = int, code]
lp15@60562
  2355
haftmann@60930
  2356
context
haftmann@60930
  2357
begin
haftmann@60930
  2358
  
haftmann@60930
  2359
qualified definition adjust_div :: "int \<times> int \<Rightarrow> int"
haftmann@60868
  2360
where
haftmann@60868
  2361
  "adjust_div qr = (let (q, r) = qr in q + of_bool (r \<noteq> 0))"
haftmann@60868
  2362
haftmann@60930
  2363
qualified lemma adjust_div_eq [simp, code]:
haftmann@60868
  2364
  "adjust_div (q, r) = q + of_bool (r \<noteq> 0)"
haftmann@60868
  2365
  by (simp add: adjust_div_def)
haftmann@60868
  2366
haftmann@60930
  2367
qualified definition adjust_mod :: "int \<Rightarrow> int \<Rightarrow> int"
haftmann@60868
  2368
where
haftmann@60868
  2369
  [simp]: "adjust_mod l r = (if r = 0 then 0 else l - r)"
haftmann@60868
  2370
haftmann@60868
  2371
lemma minus_numeral_div_numeral [simp]:
haftmann@60868
  2372
  "- numeral m div numeral n = - (adjust_div (divmod m n) :: int)"
haftmann@60868
  2373
proof -
haftmann@60868
  2374
  have "int (fst (divmod m n)) = fst (divmod m n)"
haftmann@60868
  2375
    by (simp only: fst_divmod divide_int_def) auto
haftmann@60868
  2376
  then show ?thesis
haftmann@60868
  2377
    by (auto simp add: split_def Let_def adjust_div_def divides_aux_def divide_int_def)
haftmann@60868
  2378
qed
haftmann@60868
  2379
haftmann@60868
  2380
lemma minus_numeral_mod_numeral [simp]:
haftmann@60868
  2381
  "- numeral m mod numeral n = adjust_mod (numeral n) (snd (divmod m n) :: int)"
haftmann@60868
  2382
proof -
haftmann@60868
  2383
  have "int (snd (divmod m n)) = snd (divmod m n)" if "snd (divmod m n) \<noteq> (0::int)"
haftmann@63950
  2384
    using that by (simp only: snd_divmod modulo_int_def) auto
haftmann@60868
  2385
  then show ?thesis
haftmann@63950
  2386
    by (auto simp add: split_def Let_def adjust_div_def divides_aux_def modulo_int_def)
haftmann@60868
  2387
qed
haftmann@60868
  2388
haftmann@60868
  2389
lemma numeral_div_minus_numeral [simp]:
haftmann@60868
  2390
  "numeral m div - numeral n = - (adjust_div (divmod m n) :: int)"
haftmann@60868
  2391
proof -
haftmann@60868
  2392
  have "int (fst (divmod m n)) = fst (divmod m n)"
haftmann@60868
  2393
    by (simp only: fst_divmod divide_int_def) auto
haftmann@60868
  2394
  then show ?thesis
haftmann@60868
  2395
    by (auto simp add: split_def Let_def adjust_div_def divides_aux_def divide_int_def)
haftmann@60868
  2396
qed
haftmann@60868
  2397
  
haftmann@60868
  2398
lemma numeral_mod_minus_numeral [simp]:
haftmann@60868
  2399
  "numeral m mod - numeral n = - adjust_mod (numeral n) (snd (divmod m n) :: int)"
haftmann@60868
  2400
proof -
haftmann@60868
  2401
  have "int (snd (divmod m n)) = snd (divmod m n)" if "snd (divmod m n) \<noteq> (0::int)"
haftmann@63950
  2402
    using that by (simp only: snd_divmod modulo_int_def) auto
haftmann@60868
  2403
  then show ?thesis
haftmann@63950
  2404
    by (auto simp add: split_def Let_def adjust_div_def divides_aux_def modulo_int_def)
haftmann@60868
  2405
qed
haftmann@60868
  2406
haftmann@60868
  2407
lemma minus_one_div_numeral [simp]:
haftmann@60868
  2408
  "- 1 div numeral n = - (adjust_div (divmod Num.One n) :: int)"
haftmann@60868
  2409
  using minus_numeral_div_numeral [of Num.One n] by simp  
haftmann@60868
  2410
haftmann@60868
  2411
lemma minus_one_mod_numeral [simp]:
haftmann@60868
  2412
  "- 1 mod numeral n = adjust_mod (numeral n) (snd (divmod Num.One n) :: int)"
haftmann@60868
  2413
  using minus_numeral_mod_numeral [of Num.One n] by simp
haftmann@60868
  2414
haftmann@60868
  2415
lemma one_div_minus_numeral [simp]:
haftmann@60868
  2416
  "1 div - numeral n = - (adjust_div (divmod Num.One n) :: int)"
haftmann@60868
  2417
  using numeral_div_minus_numeral [of Num.One n] by simp
haftmann@60868
  2418
  
haftmann@60868
  2419
lemma one_mod_minus_numeral [simp]:
haftmann@60868
  2420
  "1 mod - numeral n = - adjust_mod (numeral n) (snd (divmod Num.One n) :: int)"
haftmann@60868
  2421
  using numeral_mod_minus_numeral [of Num.One n] by simp
haftmann@60868
  2422
haftmann@60930
  2423
end
haftmann@60930
  2424
haftmann@60868
  2425
haftmann@60868
  2426
subsubsection \<open>Further properties\<close>
haftmann@60868
  2427
haftmann@60868
  2428
text \<open>Simplify expresions in which div and mod combine numerical constants\<close>
haftmann@60868
  2429
haftmann@60868
  2430
lemma int_div_pos_eq: "\<lbrakk>(a::int) = b * q + r; 0 \<le> r; r < b\<rbrakk> \<Longrightarrow> a div b = q"
haftmann@60868
  2431
  by (rule div_int_unique [of a b q r]) (simp add: divmod_int_rel_def)
haftmann@60868
  2432
haftmann@60868
  2433
lemma int_div_neg_eq: "\<lbrakk>(a::int) = b * q + r; r \<le> 0; b < r\<rbrakk> \<Longrightarrow> a div b = q"
haftmann@60868
  2434
  by (rule div_int_unique [of a b q r],
haftmann@60868
  2435
    simp add: divmod_int_rel_def)
haftmann@60868
  2436
haftmann@60868
  2437
lemma int_mod_pos_eq: "\<lbrakk>(a::int) = b * q + r; 0 \<le> r; r < b\<rbrakk> \<Longrightarrow> a mod b = r"
haftmann@60868
  2438
  by (rule mod_int_unique [of a b q r],
haftmann@60868
  2439
    simp add: divmod_int_rel_def)
haftmann@60868
  2440
haftmann@60868
  2441
lemma int_mod_neg_eq: "\<lbrakk>(a::int) = b * q + r; r \<le> 0; b < r\<rbrakk> \<Longrightarrow> a mod b = r"
haftmann@60868
  2442
  by (rule mod_int_unique [of a b q r],
haftmann@60868
  2443
    simp add: divmod_int_rel_def)
haftmann@33361
  2444
wenzelm@61944
  2445
lemma abs_div: "(y::int) dvd x \<Longrightarrow> \<bar>x div y\<bar> = \<bar>x\<bar> div \<bar>y\<bar>"
haftmann@33361
  2446
by (unfold dvd_def, cases "y=0", auto simp add: abs_mult)
haftmann@33361
  2447
wenzelm@60758
  2448
text\<open>Suggested by Matthias Daum\<close>
haftmann@33361
  2449
lemma int_power_div_base:
haftmann@33361
  2450
     "\<lbrakk>0 < m; 0 < k\<rbrakk> \<Longrightarrow> k ^ m div k = (k::int) ^ (m - Suc 0)"
haftmann@33361
  2451
apply (subgoal_tac "k ^ m = k ^ ((m - Suc 0) + Suc 0)")
haftmann@33361
  2452
 apply (erule ssubst)
haftmann@33361
  2453
 apply (simp only: power_add)
haftmann@33361
  2454
 apply simp_all
haftmann@33361
  2455
done
haftmann@33361
  2456
wenzelm@60758
  2457
text \<open>by Brian Huffman\<close>
haftmann@33361
  2458
lemma zminus_zmod: "- ((x::int) mod m) mod m = - x mod m"
haftmann@33361
  2459
by (rule mod_minus_eq [symmetric])
haftmann@33361
  2460
haftmann@33361
  2461
lemma zdiff_zmod_left: "(x mod m - y) mod m = (x - y) mod (m::int)"
haftmann@33361
  2462
by (rule mod_diff_left_eq [symmetric])
haftmann@33361
  2463
haftmann@33361
  2464
lemma zdiff_zmod_right: "(x - y mod m) mod m = (x - y) mod (m::int)"
haftmann@33361
  2465
by (rule mod_diff_right_eq [symmetric])
haftmann@33361
  2466
haftmann@33361
  2467
lemmas zmod_simps =
haftmann@33361
  2468
  mod_add_left_eq  [symmetric]
haftmann@33361
  2469
  mod_add_right_eq [symmetric]
huffman@47142
  2470
  mod_mult_right_eq[symmetric]
haftmann@33361
  2471
  mod_mult_left_eq [symmetric]
huffman@47164
  2472
  power_mod
haftmann@33361
  2473
  zminus_zmod zdiff_zmod_left zdiff_zmod_right
haftmann@33361
  2474
wenzelm@61799
  2475
text \<open>Distributive laws for function \<open>nat\<close>.\<close>
haftmann@33361
  2476
haftmann@33361
  2477
lemma nat_div_distrib: "0 \<le> x \<Longrightarrow> nat (x div y) = nat x div nat y"
haftmann@33361
  2478
apply (rule linorder_cases [of y 0])
haftmann@33361
  2479
apply (simp add: div_nonneg_neg_le0)
haftmann@33361
  2480
apply simp
haftmann@33361
  2481
apply (simp add: nat_eq_iff pos_imp_zdiv_nonneg_iff zdiv_int)
haftmann@33361
  2482
done
haftmann@33361
  2483
haftmann@33361
  2484
(*Fails if y<0: the LHS collapses to (nat z) but the RHS doesn't*)
haftmann@33361
  2485
lemma nat_mod_distrib:
haftmann@33361
  2486
  "\<lbrakk>0 \<le> x; 0 \<le> y\<rbrakk> \<Longrightarrow> nat (x mod y) = nat x mod nat y"
haftmann@33361
  2487
apply (case_tac "y = 0", simp)
haftmann@33361
  2488
apply (simp add: nat_eq_iff zmod_int)
haftmann@33361
  2489
done
haftmann@33361
  2490
wenzelm@60758
  2491
text  \<open>transfer setup\<close>
haftmann@33361
  2492
haftmann@33361
  2493
lemma transfer_nat_int_functions:
haftmann@33361
  2494
    "(x::int) >= 0 \<Longrightarrow> y >= 0 \<Longrightarrow> (nat x) div (nat y) = nat (x div y)"
haftmann@33361
  2495
    "(x::int) >= 0 \<Longrightarrow> y >= 0 \<Longrightarrow> (nat x) mod (nat y) = nat (x mod y)"
haftmann@33361
  2496
  by (auto simp add: nat_div_distrib nat_mod_distrib)
haftmann@33361
  2497
haftmann@33361
  2498
lemma transfer_nat_int_function_closures:
haftmann@33361
  2499
    "(x::int) >= 0 \<Longrightarrow> y >= 0 \<Longrightarrow> x div y >= 0"
haftmann@33361
  2500
    "(x::int) >= 0 \<Longrightarrow> y >= 0 \<Longrightarrow> x mod y >= 0"
haftmann@33361
  2501
  apply (cases "y = 0")
haftmann@33361
  2502
  apply (auto simp add: pos_imp_zdiv_nonneg_iff)
haftmann@33361
  2503
  apply (cases "y = 0")
haftmann@33361
  2504
  apply auto
haftmann@33361
  2505
done
haftmann@33361
  2506
haftmann@35644
  2507
declare transfer_morphism_nat_int [transfer add return:
haftmann@33361
  2508
  transfer_nat_int_functions
haftmann@33361
  2509
  transfer_nat_int_function_closures
haftmann@33361
  2510
]
haftmann@33361
  2511
haftmann@33361
  2512
lemma transfer_int_nat_functions:
haftmann@33361
  2513
    "(int x) div (int y) = int (x div y)"
haftmann@33361
  2514
    "(int x) mod (int y) = int (x mod y)"
haftmann@33361
  2515
  by (auto simp add: zdiv_int zmod_int)
haftmann@33361
  2516
haftmann@33361
  2517
lemma transfer_int_nat_function_closures:
haftmann@33361