src/HOL/Divides.thy
author bulwahn
Mon Feb 20 15:17:03 2012 +0100 (2012-02-20)
changeset 46552 5d33a3269029
parent 46551 866bce5442a3
child 46560 8e252a608765
permissions -rw-r--r--
removing some unnecessary premises from Divides
paulson@3366
     1
(*  Title:      HOL/Divides.thy
paulson@3366
     2
    Author:     Lawrence C Paulson, Cambridge University Computer Laboratory
paulson@6865
     3
    Copyright   1999  University of Cambridge
huffman@18154
     4
*)
paulson@3366
     5
haftmann@27651
     6
header {* The division operators div and mod *}
paulson@3366
     7
nipkow@15131
     8
theory Divides
haftmann@33318
     9
imports Nat_Numeral Nat_Transfer
haftmann@33340
    10
uses "~~/src/Provers/Arith/cancel_div_mod.ML"
nipkow@15131
    11
begin
paulson@3366
    12
haftmann@25942
    13
subsection {* Syntactic division operations *}
haftmann@25942
    14
haftmann@27651
    15
class div = dvd +
haftmann@27540
    16
  fixes div :: "'a \<Rightarrow> 'a \<Rightarrow> 'a" (infixl "div" 70)
haftmann@27651
    17
    and mod :: "'a \<Rightarrow> 'a \<Rightarrow> 'a" (infixl "mod" 70)
haftmann@27540
    18
haftmann@27540
    19
haftmann@27651
    20
subsection {* Abstract division in commutative semirings. *}
haftmann@25942
    21
haftmann@30930
    22
class semiring_div = comm_semiring_1_cancel + no_zero_divisors + div +
haftmann@25942
    23
  assumes mod_div_equality: "a div b * b + a mod b = a"
haftmann@27651
    24
    and div_by_0 [simp]: "a div 0 = 0"
haftmann@27651
    25
    and div_0 [simp]: "0 div a = 0"
haftmann@27651
    26
    and div_mult_self1 [simp]: "b \<noteq> 0 \<Longrightarrow> (a + c * b) div b = c + a div b"
haftmann@30930
    27
    and div_mult_mult1 [simp]: "c \<noteq> 0 \<Longrightarrow> (c * a) div (c * b) = a div b"
haftmann@25942
    28
begin
haftmann@25942
    29
haftmann@26100
    30
text {* @{const div} and @{const mod} *}
haftmann@26100
    31
haftmann@26062
    32
lemma mod_div_equality2: "b * (a div b) + a mod b = a"
haftmann@26062
    33
  unfolding mult_commute [of b]
haftmann@26062
    34
  by (rule mod_div_equality)
haftmann@26062
    35
huffman@29403
    36
lemma mod_div_equality': "a mod b + a div b * b = a"
huffman@29403
    37
  using mod_div_equality [of a b]
huffman@29403
    38
  by (simp only: add_ac)
huffman@29403
    39
haftmann@26062
    40
lemma div_mod_equality: "((a div b) * b + a mod b) + c = a + c"
haftmann@30934
    41
  by (simp add: mod_div_equality)
haftmann@26062
    42
haftmann@26062
    43
lemma div_mod_equality2: "(b * (a div b) + a mod b) + c = a + c"
haftmann@30934
    44
  by (simp add: mod_div_equality2)
haftmann@26062
    45
haftmann@27651
    46
lemma mod_by_0 [simp]: "a mod 0 = a"
haftmann@30934
    47
  using mod_div_equality [of a zero] by simp
haftmann@27651
    48
haftmann@27651
    49
lemma mod_0 [simp]: "0 mod a = 0"
haftmann@30934
    50
  using mod_div_equality [of zero a] div_0 by simp
haftmann@27651
    51
haftmann@27651
    52
lemma div_mult_self2 [simp]:
haftmann@27651
    53
  assumes "b \<noteq> 0"
haftmann@27651
    54
  shows "(a + b * c) div b = c + a div b"
haftmann@27651
    55
  using assms div_mult_self1 [of b a c] by (simp add: mult_commute)
haftmann@26100
    56
haftmann@27651
    57
lemma mod_mult_self1 [simp]: "(a + c * b) mod b = a mod b"
haftmann@27651
    58
proof (cases "b = 0")
haftmann@27651
    59
  case True then show ?thesis by simp
haftmann@27651
    60
next
haftmann@27651
    61
  case False
haftmann@27651
    62
  have "a + c * b = (a + c * b) div b * b + (a + c * b) mod b"
haftmann@27651
    63
    by (simp add: mod_div_equality)
haftmann@27651
    64
  also from False div_mult_self1 [of b a c] have
haftmann@27651
    65
    "\<dots> = (c + a div b) * b + (a + c * b) mod b"
nipkow@29667
    66
      by (simp add: algebra_simps)
haftmann@27651
    67
  finally have "a = a div b * b + (a + c * b) mod b"
haftmann@27651
    68
    by (simp add: add_commute [of a] add_assoc left_distrib)
haftmann@27651
    69
  then have "a div b * b + (a + c * b) mod b = a div b * b + a mod b"
haftmann@27651
    70
    by (simp add: mod_div_equality)
haftmann@27651
    71
  then show ?thesis by simp
haftmann@27651
    72
qed
haftmann@27651
    73
haftmann@27651
    74
lemma mod_mult_self2 [simp]: "(a + b * c) mod b = a mod b"
haftmann@30934
    75
  by (simp add: mult_commute [of b])
haftmann@27651
    76
haftmann@27651
    77
lemma div_mult_self1_is_id [simp]: "b \<noteq> 0 \<Longrightarrow> b * a div b = a"
haftmann@27651
    78
  using div_mult_self2 [of b 0 a] by simp
haftmann@27651
    79
haftmann@27651
    80
lemma div_mult_self2_is_id [simp]: "b \<noteq> 0 \<Longrightarrow> a * b div b = a"
haftmann@27651
    81
  using div_mult_self1 [of b 0 a] by simp
haftmann@27651
    82
haftmann@27651
    83
lemma mod_mult_self1_is_0 [simp]: "b * a mod b = 0"
haftmann@27651
    84
  using mod_mult_self2 [of 0 b a] by simp
haftmann@27651
    85
haftmann@27651
    86
lemma mod_mult_self2_is_0 [simp]: "a * b mod b = 0"
haftmann@27651
    87
  using mod_mult_self1 [of 0 a b] by simp
haftmann@26062
    88
haftmann@27651
    89
lemma div_by_1 [simp]: "a div 1 = a"
haftmann@27651
    90
  using div_mult_self2_is_id [of 1 a] zero_neq_one by simp
haftmann@27651
    91
haftmann@27651
    92
lemma mod_by_1 [simp]: "a mod 1 = 0"
haftmann@27651
    93
proof -
haftmann@27651
    94
  from mod_div_equality [of a one] div_by_1 have "a + a mod 1 = a" by simp
haftmann@27651
    95
  then have "a + a mod 1 = a + 0" by simp
haftmann@27651
    96
  then show ?thesis by (rule add_left_imp_eq)
haftmann@27651
    97
qed
haftmann@27651
    98
haftmann@27651
    99
lemma mod_self [simp]: "a mod a = 0"
haftmann@27651
   100
  using mod_mult_self2_is_0 [of 1] by simp
haftmann@27651
   101
haftmann@27651
   102
lemma div_self [simp]: "a \<noteq> 0 \<Longrightarrow> a div a = 1"
haftmann@27651
   103
  using div_mult_self2_is_id [of _ 1] by simp
haftmann@27651
   104
haftmann@27676
   105
lemma div_add_self1 [simp]:
haftmann@27651
   106
  assumes "b \<noteq> 0"
haftmann@27651
   107
  shows "(b + a) div b = a div b + 1"
haftmann@27651
   108
  using assms div_mult_self1 [of b a 1] by (simp add: add_commute)
haftmann@26062
   109
haftmann@27676
   110
lemma div_add_self2 [simp]:
haftmann@27651
   111
  assumes "b \<noteq> 0"
haftmann@27651
   112
  shows "(a + b) div b = a div b + 1"
haftmann@27651
   113
  using assms div_add_self1 [of b a] by (simp add: add_commute)
haftmann@27651
   114
haftmann@27676
   115
lemma mod_add_self1 [simp]:
haftmann@27651
   116
  "(b + a) mod b = a mod b"
haftmann@27651
   117
  using mod_mult_self1 [of a 1 b] by (simp add: add_commute)
haftmann@27651
   118
haftmann@27676
   119
lemma mod_add_self2 [simp]:
haftmann@27651
   120
  "(a + b) mod b = a mod b"
haftmann@27651
   121
  using mod_mult_self1 [of a 1 b] by simp
haftmann@27651
   122
haftmann@27651
   123
lemma mod_div_decomp:
haftmann@27651
   124
  fixes a b
haftmann@27651
   125
  obtains q r where "q = a div b" and "r = a mod b"
haftmann@27651
   126
    and "a = q * b + r"
haftmann@27651
   127
proof -
haftmann@27651
   128
  from mod_div_equality have "a = a div b * b + a mod b" by simp
haftmann@27651
   129
  moreover have "a div b = a div b" ..
haftmann@27651
   130
  moreover have "a mod b = a mod b" ..
haftmann@27651
   131
  note that ultimately show thesis by blast
haftmann@27651
   132
qed
haftmann@27651
   133
bulwahn@45231
   134
lemma dvd_eq_mod_eq_0 [code]: "a dvd b \<longleftrightarrow> b mod a = 0"
haftmann@25942
   135
proof
haftmann@25942
   136
  assume "b mod a = 0"
haftmann@25942
   137
  with mod_div_equality [of b a] have "b div a * a = b" by simp
haftmann@25942
   138
  then have "b = a * (b div a)" unfolding mult_commute ..
haftmann@25942
   139
  then have "\<exists>c. b = a * c" ..
haftmann@25942
   140
  then show "a dvd b" unfolding dvd_def .
haftmann@25942
   141
next
haftmann@25942
   142
  assume "a dvd b"
haftmann@25942
   143
  then have "\<exists>c. b = a * c" unfolding dvd_def .
haftmann@25942
   144
  then obtain c where "b = a * c" ..
haftmann@25942
   145
  then have "b mod a = a * c mod a" by simp
haftmann@25942
   146
  then have "b mod a = c * a mod a" by (simp add: mult_commute)
haftmann@27651
   147
  then show "b mod a = 0" by simp
haftmann@25942
   148
qed
haftmann@25942
   149
huffman@29403
   150
lemma mod_div_trivial [simp]: "a mod b div b = 0"
huffman@29403
   151
proof (cases "b = 0")
huffman@29403
   152
  assume "b = 0"
huffman@29403
   153
  thus ?thesis by simp
huffman@29403
   154
next
huffman@29403
   155
  assume "b \<noteq> 0"
huffman@29403
   156
  hence "a div b + a mod b div b = (a mod b + a div b * b) div b"
huffman@29403
   157
    by (rule div_mult_self1 [symmetric])
huffman@29403
   158
  also have "\<dots> = a div b"
huffman@29403
   159
    by (simp only: mod_div_equality')
huffman@29403
   160
  also have "\<dots> = a div b + 0"
huffman@29403
   161
    by simp
huffman@29403
   162
  finally show ?thesis
huffman@29403
   163
    by (rule add_left_imp_eq)
huffman@29403
   164
qed
huffman@29403
   165
huffman@29403
   166
lemma mod_mod_trivial [simp]: "a mod b mod b = a mod b"
huffman@29403
   167
proof -
huffman@29403
   168
  have "a mod b mod b = (a mod b + a div b * b) mod b"
huffman@29403
   169
    by (simp only: mod_mult_self1)
huffman@29403
   170
  also have "\<dots> = a mod b"
huffman@29403
   171
    by (simp only: mod_div_equality')
huffman@29403
   172
  finally show ?thesis .
huffman@29403
   173
qed
huffman@29403
   174
nipkow@29925
   175
lemma dvd_imp_mod_0: "a dvd b \<Longrightarrow> b mod a = 0"
nipkow@29948
   176
by (rule dvd_eq_mod_eq_0[THEN iffD1])
nipkow@29925
   177
nipkow@29925
   178
lemma dvd_div_mult_self: "a dvd b \<Longrightarrow> (b div a) * a = b"
nipkow@29925
   179
by (subst (2) mod_div_equality [of b a, symmetric]) (simp add:dvd_imp_mod_0)
nipkow@29925
   180
haftmann@33274
   181
lemma dvd_mult_div_cancel: "a dvd b \<Longrightarrow> a * (b div a) = b"
haftmann@33274
   182
by (drule dvd_div_mult_self) (simp add: mult_commute)
haftmann@33274
   183
nipkow@30052
   184
lemma dvd_div_mult: "a dvd b \<Longrightarrow> (b div a) * c = b * c div a"
nipkow@30052
   185
apply (cases "a = 0")
nipkow@30052
   186
 apply simp
nipkow@30052
   187
apply (auto simp: dvd_def mult_assoc)
nipkow@30052
   188
done
nipkow@30052
   189
nipkow@29925
   190
lemma div_dvd_div[simp]:
nipkow@29925
   191
  "a dvd b \<Longrightarrow> a dvd c \<Longrightarrow> (b div a dvd c div a) = (b dvd c)"
nipkow@29925
   192
apply (cases "a = 0")
nipkow@29925
   193
 apply simp
nipkow@29925
   194
apply (unfold dvd_def)
nipkow@29925
   195
apply auto
nipkow@29925
   196
 apply(blast intro:mult_assoc[symmetric])
nipkow@44890
   197
apply(fastforce simp add: mult_assoc)
nipkow@29925
   198
done
nipkow@29925
   199
huffman@30078
   200
lemma dvd_mod_imp_dvd: "[| k dvd m mod n;  k dvd n |] ==> k dvd m"
huffman@30078
   201
  apply (subgoal_tac "k dvd (m div n) *n + m mod n")
huffman@30078
   202
   apply (simp add: mod_div_equality)
huffman@30078
   203
  apply (simp only: dvd_add dvd_mult)
huffman@30078
   204
  done
huffman@30078
   205
huffman@29403
   206
text {* Addition respects modular equivalence. *}
huffman@29403
   207
huffman@29403
   208
lemma mod_add_left_eq: "(a + b) mod c = (a mod c + b) mod c"
huffman@29403
   209
proof -
huffman@29403
   210
  have "(a + b) mod c = (a div c * c + a mod c + b) mod c"
huffman@29403
   211
    by (simp only: mod_div_equality)
huffman@29403
   212
  also have "\<dots> = (a mod c + b + a div c * c) mod c"
huffman@29403
   213
    by (simp only: add_ac)
huffman@29403
   214
  also have "\<dots> = (a mod c + b) mod c"
huffman@29403
   215
    by (rule mod_mult_self1)
huffman@29403
   216
  finally show ?thesis .
huffman@29403
   217
qed
huffman@29403
   218
huffman@29403
   219
lemma mod_add_right_eq: "(a + b) mod c = (a + b mod c) mod c"
huffman@29403
   220
proof -
huffman@29403
   221
  have "(a + b) mod c = (a + (b div c * c + b mod c)) mod c"
huffman@29403
   222
    by (simp only: mod_div_equality)
huffman@29403
   223
  also have "\<dots> = (a + b mod c + b div c * c) mod c"
huffman@29403
   224
    by (simp only: add_ac)
huffman@29403
   225
  also have "\<dots> = (a + b mod c) mod c"
huffman@29403
   226
    by (rule mod_mult_self1)
huffman@29403
   227
  finally show ?thesis .
huffman@29403
   228
qed
huffman@29403
   229
huffman@29403
   230
lemma mod_add_eq: "(a + b) mod c = (a mod c + b mod c) mod c"
huffman@29403
   231
by (rule trans [OF mod_add_left_eq mod_add_right_eq])
huffman@29403
   232
huffman@29403
   233
lemma mod_add_cong:
huffman@29403
   234
  assumes "a mod c = a' mod c"
huffman@29403
   235
  assumes "b mod c = b' mod c"
huffman@29403
   236
  shows "(a + b) mod c = (a' + b') mod c"
huffman@29403
   237
proof -
huffman@29403
   238
  have "(a mod c + b mod c) mod c = (a' mod c + b' mod c) mod c"
huffman@29403
   239
    unfolding assms ..
huffman@29403
   240
  thus ?thesis
huffman@29403
   241
    by (simp only: mod_add_eq [symmetric])
huffman@29403
   242
qed
huffman@29403
   243
haftmann@30923
   244
lemma div_add [simp]: "z dvd x \<Longrightarrow> z dvd y
nipkow@30837
   245
  \<Longrightarrow> (x + y) div z = x div z + y div z"
haftmann@30923
   246
by (cases "z = 0", simp, unfold dvd_def, auto simp add: algebra_simps)
nipkow@30837
   247
huffman@29403
   248
text {* Multiplication respects modular equivalence. *}
huffman@29403
   249
huffman@29403
   250
lemma mod_mult_left_eq: "(a * b) mod c = ((a mod c) * b) mod c"
huffman@29403
   251
proof -
huffman@29403
   252
  have "(a * b) mod c = ((a div c * c + a mod c) * b) mod c"
huffman@29403
   253
    by (simp only: mod_div_equality)
huffman@29403
   254
  also have "\<dots> = (a mod c * b + a div c * b * c) mod c"
nipkow@29667
   255
    by (simp only: algebra_simps)
huffman@29403
   256
  also have "\<dots> = (a mod c * b) mod c"
huffman@29403
   257
    by (rule mod_mult_self1)
huffman@29403
   258
  finally show ?thesis .
huffman@29403
   259
qed
huffman@29403
   260
huffman@29403
   261
lemma mod_mult_right_eq: "(a * b) mod c = (a * (b mod c)) mod c"
huffman@29403
   262
proof -
huffman@29403
   263
  have "(a * b) mod c = (a * (b div c * c + b mod c)) mod c"
huffman@29403
   264
    by (simp only: mod_div_equality)
huffman@29403
   265
  also have "\<dots> = (a * (b mod c) + a * (b div c) * c) mod c"
nipkow@29667
   266
    by (simp only: algebra_simps)
huffman@29403
   267
  also have "\<dots> = (a * (b mod c)) mod c"
huffman@29403
   268
    by (rule mod_mult_self1)
huffman@29403
   269
  finally show ?thesis .
huffman@29403
   270
qed
huffman@29403
   271
huffman@29403
   272
lemma mod_mult_eq: "(a * b) mod c = ((a mod c) * (b mod c)) mod c"
huffman@29403
   273
by (rule trans [OF mod_mult_left_eq mod_mult_right_eq])
huffman@29403
   274
huffman@29403
   275
lemma mod_mult_cong:
huffman@29403
   276
  assumes "a mod c = a' mod c"
huffman@29403
   277
  assumes "b mod c = b' mod c"
huffman@29403
   278
  shows "(a * b) mod c = (a' * b') mod c"
huffman@29403
   279
proof -
huffman@29403
   280
  have "(a mod c * (b mod c)) mod c = (a' mod c * (b' mod c)) mod c"
huffman@29403
   281
    unfolding assms ..
huffman@29403
   282
  thus ?thesis
huffman@29403
   283
    by (simp only: mod_mult_eq [symmetric])
huffman@29403
   284
qed
huffman@29403
   285
huffman@29404
   286
lemma mod_mod_cancel:
huffman@29404
   287
  assumes "c dvd b"
huffman@29404
   288
  shows "a mod b mod c = a mod c"
huffman@29404
   289
proof -
huffman@29404
   290
  from `c dvd b` obtain k where "b = c * k"
huffman@29404
   291
    by (rule dvdE)
huffman@29404
   292
  have "a mod b mod c = a mod (c * k) mod c"
huffman@29404
   293
    by (simp only: `b = c * k`)
huffman@29404
   294
  also have "\<dots> = (a mod (c * k) + a div (c * k) * k * c) mod c"
huffman@29404
   295
    by (simp only: mod_mult_self1)
huffman@29404
   296
  also have "\<dots> = (a div (c * k) * (c * k) + a mod (c * k)) mod c"
huffman@29404
   297
    by (simp only: add_ac mult_ac)
huffman@29404
   298
  also have "\<dots> = a mod c"
huffman@29404
   299
    by (simp only: mod_div_equality)
huffman@29404
   300
  finally show ?thesis .
huffman@29404
   301
qed
huffman@29404
   302
haftmann@30930
   303
lemma div_mult_div_if_dvd:
haftmann@30930
   304
  "y dvd x \<Longrightarrow> z dvd w \<Longrightarrow> (x div y) * (w div z) = (x * w) div (y * z)"
haftmann@30930
   305
  apply (cases "y = 0", simp)
haftmann@30930
   306
  apply (cases "z = 0", simp)
haftmann@30930
   307
  apply (auto elim!: dvdE simp add: algebra_simps)
nipkow@30476
   308
  apply (subst mult_assoc [symmetric])
nipkow@30476
   309
  apply (simp add: no_zero_divisors)
haftmann@30930
   310
  done
haftmann@30930
   311
haftmann@35367
   312
lemma div_mult_swap:
haftmann@35367
   313
  assumes "c dvd b"
haftmann@35367
   314
  shows "a * (b div c) = (a * b) div c"
haftmann@35367
   315
proof -
haftmann@35367
   316
  from assms have "b div c * (a div 1) = b * a div (c * 1)"
haftmann@35367
   317
    by (simp only: div_mult_div_if_dvd one_dvd)
haftmann@35367
   318
  then show ?thesis by (simp add: mult_commute)
haftmann@35367
   319
qed
haftmann@35367
   320
   
haftmann@30930
   321
lemma div_mult_mult2 [simp]:
haftmann@30930
   322
  "c \<noteq> 0 \<Longrightarrow> (a * c) div (b * c) = a div b"
haftmann@30930
   323
  by (drule div_mult_mult1) (simp add: mult_commute)
haftmann@30930
   324
haftmann@30930
   325
lemma div_mult_mult1_if [simp]:
haftmann@30930
   326
  "(c * a) div (c * b) = (if c = 0 then 0 else a div b)"
haftmann@30930
   327
  by simp_all
nipkow@30476
   328
haftmann@30930
   329
lemma mod_mult_mult1:
haftmann@30930
   330
  "(c * a) mod (c * b) = c * (a mod b)"
haftmann@30930
   331
proof (cases "c = 0")
haftmann@30930
   332
  case True then show ?thesis by simp
haftmann@30930
   333
next
haftmann@30930
   334
  case False
haftmann@30930
   335
  from mod_div_equality
haftmann@30930
   336
  have "((c * a) div (c * b)) * (c * b) + (c * a) mod (c * b) = c * a" .
haftmann@30930
   337
  with False have "c * ((a div b) * b + a mod b) + (c * a) mod (c * b)
haftmann@30930
   338
    = c * a + c * (a mod b)" by (simp add: algebra_simps)
haftmann@30930
   339
  with mod_div_equality show ?thesis by simp 
haftmann@30930
   340
qed
haftmann@30930
   341
  
haftmann@30930
   342
lemma mod_mult_mult2:
haftmann@30930
   343
  "(a * c) mod (b * c) = (a mod b) * c"
haftmann@30930
   344
  using mod_mult_mult1 [of c a b] by (simp add: mult_commute)
haftmann@30930
   345
huffman@31662
   346
lemma dvd_mod: "k dvd m \<Longrightarrow> k dvd n \<Longrightarrow> k dvd (m mod n)"
huffman@31662
   347
  unfolding dvd_def by (auto simp add: mod_mult_mult1)
huffman@31662
   348
huffman@31662
   349
lemma dvd_mod_iff: "k dvd n \<Longrightarrow> k dvd (m mod n) \<longleftrightarrow> k dvd m"
huffman@31662
   350
by (blast intro: dvd_mod_imp_dvd dvd_mod)
huffman@31662
   351
haftmann@31009
   352
lemma div_power:
huffman@31661
   353
  "y dvd x \<Longrightarrow> (x div y) ^ n = x ^ n div y ^ n"
nipkow@30476
   354
apply (induct n)
nipkow@30476
   355
 apply simp
nipkow@30476
   356
apply(simp add: div_mult_div_if_dvd dvd_power_same)
nipkow@30476
   357
done
nipkow@30476
   358
haftmann@35367
   359
lemma dvd_div_eq_mult:
haftmann@35367
   360
  assumes "a \<noteq> 0" and "a dvd b"  
haftmann@35367
   361
  shows "b div a = c \<longleftrightarrow> b = c * a"
haftmann@35367
   362
proof
haftmann@35367
   363
  assume "b = c * a"
haftmann@35367
   364
  then show "b div a = c" by (simp add: assms)
haftmann@35367
   365
next
haftmann@35367
   366
  assume "b div a = c"
haftmann@35367
   367
  then have "b div a * a = c * a" by simp
haftmann@35367
   368
  moreover from `a dvd b` have "b div a * a = b" by (simp add: dvd_div_mult_self)
haftmann@35367
   369
  ultimately show "b = c * a" by simp
haftmann@35367
   370
qed
haftmann@35367
   371
   
haftmann@35367
   372
lemma dvd_div_div_eq_mult:
haftmann@35367
   373
  assumes "a \<noteq> 0" "c \<noteq> 0" and "a dvd b" "c dvd d"
haftmann@35367
   374
  shows "b div a = d div c \<longleftrightarrow> b * c = a * d"
haftmann@35367
   375
  using assms by (auto simp add: mult_commute [of _ a] dvd_div_mult_self dvd_div_eq_mult div_mult_swap intro: sym)
haftmann@35367
   376
huffman@31661
   377
end
huffman@31661
   378
haftmann@35673
   379
class ring_div = semiring_div + comm_ring_1
huffman@29405
   380
begin
huffman@29405
   381
haftmann@36634
   382
subclass ring_1_no_zero_divisors ..
haftmann@36634
   383
huffman@29405
   384
text {* Negation respects modular equivalence. *}
huffman@29405
   385
huffman@29405
   386
lemma mod_minus_eq: "(- a) mod b = (- (a mod b)) mod b"
huffman@29405
   387
proof -
huffman@29405
   388
  have "(- a) mod b = (- (a div b * b + a mod b)) mod b"
huffman@29405
   389
    by (simp only: mod_div_equality)
huffman@29405
   390
  also have "\<dots> = (- (a mod b) + - (a div b) * b) mod b"
huffman@29405
   391
    by (simp only: minus_add_distrib minus_mult_left add_ac)
huffman@29405
   392
  also have "\<dots> = (- (a mod b)) mod b"
huffman@29405
   393
    by (rule mod_mult_self1)
huffman@29405
   394
  finally show ?thesis .
huffman@29405
   395
qed
huffman@29405
   396
huffman@29405
   397
lemma mod_minus_cong:
huffman@29405
   398
  assumes "a mod b = a' mod b"
huffman@29405
   399
  shows "(- a) mod b = (- a') mod b"
huffman@29405
   400
proof -
huffman@29405
   401
  have "(- (a mod b)) mod b = (- (a' mod b)) mod b"
huffman@29405
   402
    unfolding assms ..
huffman@29405
   403
  thus ?thesis
huffman@29405
   404
    by (simp only: mod_minus_eq [symmetric])
huffman@29405
   405
qed
huffman@29405
   406
huffman@29405
   407
text {* Subtraction respects modular equivalence. *}
huffman@29405
   408
huffman@29405
   409
lemma mod_diff_left_eq: "(a - b) mod c = (a mod c - b) mod c"
huffman@29405
   410
  unfolding diff_minus
huffman@29405
   411
  by (intro mod_add_cong mod_minus_cong) simp_all
huffman@29405
   412
huffman@29405
   413
lemma mod_diff_right_eq: "(a - b) mod c = (a - b mod c) mod c"
huffman@29405
   414
  unfolding diff_minus
huffman@29405
   415
  by (intro mod_add_cong mod_minus_cong) simp_all
huffman@29405
   416
huffman@29405
   417
lemma mod_diff_eq: "(a - b) mod c = (a mod c - b mod c) mod c"
huffman@29405
   418
  unfolding diff_minus
huffman@29405
   419
  by (intro mod_add_cong mod_minus_cong) simp_all
huffman@29405
   420
huffman@29405
   421
lemma mod_diff_cong:
huffman@29405
   422
  assumes "a mod c = a' mod c"
huffman@29405
   423
  assumes "b mod c = b' mod c"
huffman@29405
   424
  shows "(a - b) mod c = (a' - b') mod c"
huffman@29405
   425
  unfolding diff_minus using assms
huffman@29405
   426
  by (intro mod_add_cong mod_minus_cong)
huffman@29405
   427
nipkow@30180
   428
lemma dvd_neg_div: "y dvd x \<Longrightarrow> -x div y = - (x div y)"
nipkow@30180
   429
apply (case_tac "y = 0") apply simp
nipkow@30180
   430
apply (auto simp add: dvd_def)
nipkow@30180
   431
apply (subgoal_tac "-(y * k) = y * - k")
nipkow@30180
   432
 apply (erule ssubst)
nipkow@30180
   433
 apply (erule div_mult_self1_is_id)
nipkow@30180
   434
apply simp
nipkow@30180
   435
done
nipkow@30180
   436
nipkow@30180
   437
lemma dvd_div_neg: "y dvd x \<Longrightarrow> x div -y = - (x div y)"
nipkow@30180
   438
apply (case_tac "y = 0") apply simp
nipkow@30180
   439
apply (auto simp add: dvd_def)
nipkow@30180
   440
apply (subgoal_tac "y * k = -y * -k")
nipkow@30180
   441
 apply (erule ssubst)
nipkow@30180
   442
 apply (rule div_mult_self1_is_id)
nipkow@30180
   443
 apply simp
nipkow@30180
   444
apply simp
nipkow@30180
   445
done
nipkow@30180
   446
huffman@29405
   447
end
huffman@29405
   448
haftmann@25942
   449
haftmann@26100
   450
subsection {* Division on @{typ nat} *}
haftmann@26100
   451
haftmann@26100
   452
text {*
haftmann@26100
   453
  We define @{const div} and @{const mod} on @{typ nat} by means
haftmann@26100
   454
  of a characteristic relation with two input arguments
haftmann@26100
   455
  @{term "m\<Colon>nat"}, @{term "n\<Colon>nat"} and two output arguments
haftmann@26100
   456
  @{term "q\<Colon>nat"}(uotient) and @{term "r\<Colon>nat"}(emainder).
haftmann@26100
   457
*}
haftmann@26100
   458
haftmann@33340
   459
definition divmod_nat_rel :: "nat \<Rightarrow> nat \<Rightarrow> nat \<times> nat \<Rightarrow> bool" where
haftmann@33340
   460
  "divmod_nat_rel m n qr \<longleftrightarrow>
haftmann@30923
   461
    m = fst qr * n + snd qr \<and>
haftmann@30923
   462
      (if n = 0 then fst qr = 0 else if n > 0 then 0 \<le> snd qr \<and> snd qr < n else n < snd qr \<and> snd qr \<le> 0)"
haftmann@26100
   463
haftmann@33340
   464
text {* @{const divmod_nat_rel} is total: *}
haftmann@26100
   465
haftmann@33340
   466
lemma divmod_nat_rel_ex:
haftmann@33340
   467
  obtains q r where "divmod_nat_rel m n (q, r)"
haftmann@26100
   468
proof (cases "n = 0")
haftmann@30923
   469
  case True  with that show thesis
haftmann@33340
   470
    by (auto simp add: divmod_nat_rel_def)
haftmann@26100
   471
next
haftmann@26100
   472
  case False
haftmann@26100
   473
  have "\<exists>q r. m = q * n + r \<and> r < n"
haftmann@26100
   474
  proof (induct m)
haftmann@26100
   475
    case 0 with `n \<noteq> 0`
haftmann@26100
   476
    have "(0\<Colon>nat) = 0 * n + 0 \<and> 0 < n" by simp
haftmann@26100
   477
    then show ?case by blast
haftmann@26100
   478
  next
haftmann@26100
   479
    case (Suc m) then obtain q' r'
haftmann@26100
   480
      where m: "m = q' * n + r'" and n: "r' < n" by auto
haftmann@26100
   481
    then show ?case proof (cases "Suc r' < n")
haftmann@26100
   482
      case True
haftmann@26100
   483
      from m n have "Suc m = q' * n + Suc r'" by simp
haftmann@26100
   484
      with True show ?thesis by blast
haftmann@26100
   485
    next
haftmann@26100
   486
      case False then have "n \<le> Suc r'" by auto
haftmann@26100
   487
      moreover from n have "Suc r' \<le> n" by auto
haftmann@26100
   488
      ultimately have "n = Suc r'" by auto
haftmann@26100
   489
      with m have "Suc m = Suc q' * n + 0" by simp
haftmann@26100
   490
      with `n \<noteq> 0` show ?thesis by blast
haftmann@26100
   491
    qed
haftmann@26100
   492
  qed
haftmann@26100
   493
  with that show thesis
haftmann@33340
   494
    using `n \<noteq> 0` by (auto simp add: divmod_nat_rel_def)
haftmann@26100
   495
qed
haftmann@26100
   496
haftmann@33340
   497
text {* @{const divmod_nat_rel} is injective: *}
haftmann@26100
   498
haftmann@33340
   499
lemma divmod_nat_rel_unique:
haftmann@33340
   500
  assumes "divmod_nat_rel m n qr"
haftmann@33340
   501
    and "divmod_nat_rel m n qr'"
haftmann@30923
   502
  shows "qr = qr'"
haftmann@26100
   503
proof (cases "n = 0")
haftmann@26100
   504
  case True with assms show ?thesis
haftmann@30923
   505
    by (cases qr, cases qr')
haftmann@33340
   506
      (simp add: divmod_nat_rel_def)
haftmann@26100
   507
next
haftmann@26100
   508
  case False
haftmann@26100
   509
  have aux: "\<And>q r q' r'. q' * n + r' = q * n + r \<Longrightarrow> r < n \<Longrightarrow> q' \<le> (q\<Colon>nat)"
haftmann@26100
   510
  apply (rule leI)
haftmann@26100
   511
  apply (subst less_iff_Suc_add)
haftmann@26100
   512
  apply (auto simp add: add_mult_distrib)
haftmann@26100
   513
  done
haftmann@30923
   514
  from `n \<noteq> 0` assms have "fst qr = fst qr'"
haftmann@33340
   515
    by (auto simp add: divmod_nat_rel_def intro: order_antisym dest: aux sym)
haftmann@30923
   516
  moreover from this assms have "snd qr = snd qr'"
haftmann@33340
   517
    by (simp add: divmod_nat_rel_def)
haftmann@30923
   518
  ultimately show ?thesis by (cases qr, cases qr') simp
haftmann@26100
   519
qed
haftmann@26100
   520
haftmann@26100
   521
text {*
haftmann@26100
   522
  We instantiate divisibility on the natural numbers by
haftmann@33340
   523
  means of @{const divmod_nat_rel}:
haftmann@26100
   524
*}
haftmann@25942
   525
haftmann@33340
   526
definition divmod_nat :: "nat \<Rightarrow> nat \<Rightarrow> nat \<times> nat" where
haftmann@37767
   527
  "divmod_nat m n = (THE qr. divmod_nat_rel m n qr)"
haftmann@30923
   528
haftmann@33340
   529
lemma divmod_nat_rel_divmod_nat:
haftmann@33340
   530
  "divmod_nat_rel m n (divmod_nat m n)"
haftmann@30923
   531
proof -
haftmann@33340
   532
  from divmod_nat_rel_ex
haftmann@33340
   533
    obtain qr where rel: "divmod_nat_rel m n qr" .
haftmann@30923
   534
  then show ?thesis
haftmann@33340
   535
  by (auto simp add: divmod_nat_def intro: theI elim: divmod_nat_rel_unique)
haftmann@30923
   536
qed
haftmann@30923
   537
haftmann@33340
   538
lemma divmod_nat_eq:
haftmann@33340
   539
  assumes "divmod_nat_rel m n qr" 
haftmann@33340
   540
  shows "divmod_nat m n = qr"
haftmann@33340
   541
  using assms by (auto intro: divmod_nat_rel_unique divmod_nat_rel_divmod_nat)
haftmann@26100
   542
huffman@46551
   543
instantiation nat :: semiring_div
huffman@46551
   544
begin
huffman@46551
   545
haftmann@26100
   546
definition div_nat where
haftmann@33340
   547
  "m div n = fst (divmod_nat m n)"
haftmann@26100
   548
huffman@46551
   549
lemma fst_divmod_nat [simp]:
huffman@46551
   550
  "fst (divmod_nat m n) = m div n"
huffman@46551
   551
  by (simp add: div_nat_def)
huffman@46551
   552
haftmann@26100
   553
definition mod_nat where
haftmann@33340
   554
  "m mod n = snd (divmod_nat m n)"
haftmann@25571
   555
huffman@46551
   556
lemma snd_divmod_nat [simp]:
huffman@46551
   557
  "snd (divmod_nat m n) = m mod n"
huffman@46551
   558
  by (simp add: mod_nat_def)
huffman@46551
   559
haftmann@33340
   560
lemma divmod_nat_div_mod:
haftmann@33340
   561
  "divmod_nat m n = (m div n, m mod n)"
huffman@46551
   562
  by (simp add: prod_eq_iff)
haftmann@26100
   563
haftmann@26100
   564
lemma div_eq:
haftmann@33340
   565
  assumes "divmod_nat_rel m n (q, r)" 
haftmann@26100
   566
  shows "m div n = q"
huffman@46551
   567
  using assms by (auto dest!: divmod_nat_eq simp add: prod_eq_iff)
haftmann@26100
   568
haftmann@26100
   569
lemma mod_eq:
haftmann@33340
   570
  assumes "divmod_nat_rel m n (q, r)" 
haftmann@26100
   571
  shows "m mod n = r"
huffman@46551
   572
  using assms by (auto dest!: divmod_nat_eq simp add: prod_eq_iff)
haftmann@25571
   573
haftmann@33340
   574
lemma divmod_nat_rel: "divmod_nat_rel m n (m div n, m mod n)"
huffman@46551
   575
  using divmod_nat_rel_divmod_nat by (simp add: divmod_nat_div_mod)
paulson@14267
   576
haftmann@33340
   577
lemma divmod_nat_zero:
haftmann@33340
   578
  "divmod_nat m 0 = (0, m)"
haftmann@26100
   579
proof -
haftmann@33340
   580
  from divmod_nat_rel [of m 0] show ?thesis
haftmann@33340
   581
    unfolding divmod_nat_div_mod divmod_nat_rel_def by simp
haftmann@26100
   582
qed
haftmann@25942
   583
haftmann@33340
   584
lemma divmod_nat_base:
haftmann@26100
   585
  assumes "m < n"
haftmann@33340
   586
  shows "divmod_nat m n = (0, m)"
haftmann@26100
   587
proof -
haftmann@33340
   588
  from divmod_nat_rel [of m n] show ?thesis
haftmann@33340
   589
    unfolding divmod_nat_div_mod divmod_nat_rel_def
haftmann@26100
   590
    using assms by (cases "m div n = 0")
haftmann@26100
   591
      (auto simp add: gr0_conv_Suc [of "m div n"])
haftmann@26100
   592
qed
haftmann@25942
   593
haftmann@33340
   594
lemma divmod_nat_step:
haftmann@26100
   595
  assumes "0 < n" and "n \<le> m"
haftmann@33340
   596
  shows "divmod_nat m n = (Suc ((m - n) div n), (m - n) mod n)"
haftmann@26100
   597
proof -
haftmann@33340
   598
  from divmod_nat_rel have divmod_nat_m_n: "divmod_nat_rel m n (m div n, m mod n)" .
haftmann@26100
   599
  with assms have m_div_n: "m div n \<ge> 1"
haftmann@33340
   600
    by (cases "m div n") (auto simp add: divmod_nat_rel_def)
boehmes@35815
   601
  have "divmod_nat_rel (m - n) n (m div n - Suc 0, m mod n)"
boehmes@35815
   602
  proof -
boehmes@35815
   603
    from assms have
boehmes@35815
   604
      "n \<noteq> 0"
boehmes@35815
   605
      "\<And>k. m = Suc k * n + m mod n ==> m - n = (Suc k - Suc 0) * n + m mod n"
boehmes@35815
   606
      by simp_all
boehmes@35815
   607
    then show ?thesis using assms divmod_nat_m_n 
boehmes@35815
   608
      by (cases "m div n")
boehmes@35815
   609
         (simp_all only: divmod_nat_rel_def fst_conv snd_conv, simp_all)
boehmes@35815
   610
  qed
haftmann@33340
   611
  with divmod_nat_eq have "divmod_nat (m - n) n = (m div n - Suc 0, m mod n)" by simp
haftmann@33340
   612
  moreover from divmod_nat_div_mod have "divmod_nat (m - n) n = ((m - n) div n, (m - n) mod n)" .
haftmann@26100
   613
  ultimately have "m div n = Suc ((m - n) div n)"
haftmann@26100
   614
    and "m mod n = (m - n) mod n" using m_div_n by simp_all
haftmann@33340
   615
  then show ?thesis using divmod_nat_div_mod by simp
haftmann@26100
   616
qed
haftmann@25942
   617
wenzelm@26300
   618
text {* The ''recursion'' equations for @{const div} and @{const mod} *}
haftmann@26100
   619
haftmann@26100
   620
lemma div_less [simp]:
haftmann@26100
   621
  fixes m n :: nat
haftmann@26100
   622
  assumes "m < n"
haftmann@26100
   623
  shows "m div n = 0"
huffman@46551
   624
  using assms divmod_nat_base by (simp add: prod_eq_iff)
haftmann@25942
   625
haftmann@26100
   626
lemma le_div_geq:
haftmann@26100
   627
  fixes m n :: nat
haftmann@26100
   628
  assumes "0 < n" and "n \<le> m"
haftmann@26100
   629
  shows "m div n = Suc ((m - n) div n)"
huffman@46551
   630
  using assms divmod_nat_step by (simp add: prod_eq_iff)
paulson@14267
   631
haftmann@26100
   632
lemma mod_less [simp]:
haftmann@26100
   633
  fixes m n :: nat
haftmann@26100
   634
  assumes "m < n"
haftmann@26100
   635
  shows "m mod n = m"
huffman@46551
   636
  using assms divmod_nat_base by (simp add: prod_eq_iff)
haftmann@26100
   637
haftmann@26100
   638
lemma le_mod_geq:
haftmann@26100
   639
  fixes m n :: nat
haftmann@26100
   640
  assumes "n \<le> m"
haftmann@26100
   641
  shows "m mod n = (m - n) mod n"
huffman@46551
   642
  using assms divmod_nat_step by (cases "n = 0") (simp_all add: prod_eq_iff)
paulson@14267
   643
haftmann@30930
   644
instance proof -
haftmann@30930
   645
  have [simp]: "\<And>n::nat. n div 0 = 0"
haftmann@33340
   646
    by (simp add: div_nat_def divmod_nat_zero)
haftmann@30930
   647
  have [simp]: "\<And>n::nat. 0 div n = 0"
haftmann@30930
   648
  proof -
haftmann@30930
   649
    fix n :: nat
haftmann@30930
   650
    show "0 div n = 0"
haftmann@30930
   651
      by (cases "n = 0") simp_all
haftmann@30930
   652
  qed
haftmann@30930
   653
  show "OFCLASS(nat, semiring_div_class)" proof
haftmann@30930
   654
    fix m n :: nat
haftmann@30930
   655
    show "m div n * n + m mod n = m"
haftmann@33340
   656
      using divmod_nat_rel [of m n] by (simp add: divmod_nat_rel_def)
haftmann@30930
   657
  next
haftmann@30930
   658
    fix m n q :: nat
haftmann@30930
   659
    assume "n \<noteq> 0"
haftmann@30930
   660
    then show "(q + m * n) div n = m + q div n"
haftmann@30930
   661
      by (induct m) (simp_all add: le_div_geq)
haftmann@30930
   662
  next
haftmann@30930
   663
    fix m n q :: nat
haftmann@30930
   664
    assume "m \<noteq> 0"
haftmann@30930
   665
    then show "(m * n) div (m * q) = n div q"
haftmann@30930
   666
    proof (cases "n \<noteq> 0 \<and> q \<noteq> 0")
haftmann@30930
   667
      case False then show ?thesis by auto
haftmann@30930
   668
    next
haftmann@30930
   669
      case True with `m \<noteq> 0`
haftmann@30930
   670
        have "m > 0" and "n > 0" and "q > 0" by auto
haftmann@33340
   671
      then have "\<And>a b. divmod_nat_rel n q (a, b) \<Longrightarrow> divmod_nat_rel (m * n) (m * q) (a, m * b)"
haftmann@33340
   672
        by (auto simp add: divmod_nat_rel_def) (simp_all add: algebra_simps)
haftmann@33340
   673
      moreover from divmod_nat_rel have "divmod_nat_rel n q (n div q, n mod q)" .
haftmann@33340
   674
      ultimately have "divmod_nat_rel (m * n) (m * q) (n div q, m * (n mod q))" .
haftmann@30930
   675
      then show ?thesis by (simp add: div_eq)
haftmann@30930
   676
    qed
haftmann@30930
   677
  qed simp_all
haftmann@25942
   678
qed
haftmann@26100
   679
haftmann@25942
   680
end
paulson@14267
   681
haftmann@33361
   682
lemma divmod_nat_if [code]: "divmod_nat m n = (if n = 0 \<or> m < n then (0, m) else
haftmann@33361
   683
  let (q, r) = divmod_nat (m - n) n in (Suc q, r))"
huffman@46551
   684
  by (simp add: prod_eq_iff prod_case_beta not_less le_div_geq le_mod_geq)
haftmann@33361
   685
haftmann@26100
   686
text {* Simproc for cancelling @{const div} and @{const mod} *}
haftmann@25942
   687
haftmann@30934
   688
ML {*
wenzelm@43594
   689
structure Cancel_Div_Mod_Nat = Cancel_Div_Mod
wenzelm@41550
   690
(
haftmann@30934
   691
  val div_name = @{const_name div};
haftmann@30934
   692
  val mod_name = @{const_name mod};
haftmann@30934
   693
  val mk_binop = HOLogic.mk_binop;
haftmann@30934
   694
  val mk_sum = Nat_Arith.mk_sum;
haftmann@30934
   695
  val dest_sum = Nat_Arith.dest_sum;
haftmann@25942
   696
haftmann@30934
   697
  val div_mod_eqs = map mk_meta_eq [@{thm div_mod_equality}, @{thm div_mod_equality2}];
paulson@14267
   698
haftmann@30934
   699
  val prove_eq_sums = Arith_Data.prove_conv2 all_tac (Arith_Data.simp_all_tac
haftmann@35050
   700
    (@{thm add_0_left} :: @{thm add_0_right} :: @{thms add_ac}))
wenzelm@41550
   701
)
haftmann@25942
   702
*}
haftmann@25942
   703
wenzelm@43594
   704
simproc_setup cancel_div_mod_nat ("(m::nat) + n") = {* K Cancel_Div_Mod_Nat.proc *}
wenzelm@43594
   705
haftmann@26100
   706
haftmann@26100
   707
subsubsection {* Quotient *}
haftmann@26100
   708
haftmann@26100
   709
lemma div_geq: "0 < n \<Longrightarrow>  \<not> m < n \<Longrightarrow> m div n = Suc ((m - n) div n)"
nipkow@29667
   710
by (simp add: le_div_geq linorder_not_less)
haftmann@26100
   711
haftmann@26100
   712
lemma div_if: "0 < n \<Longrightarrow> m div n = (if m < n then 0 else Suc ((m - n) div n))"
nipkow@29667
   713
by (simp add: div_geq)
haftmann@26100
   714
haftmann@26100
   715
lemma div_mult_self_is_m [simp]: "0<n ==> (m*n) div n = (m::nat)"
nipkow@29667
   716
by simp
haftmann@26100
   717
haftmann@26100
   718
lemma div_mult_self1_is_m [simp]: "0<n ==> (n*m) div n = (m::nat)"
nipkow@29667
   719
by simp
haftmann@26100
   720
haftmann@25942
   721
haftmann@25942
   722
subsubsection {* Remainder *}
haftmann@25942
   723
haftmann@26100
   724
lemma mod_less_divisor [simp]:
haftmann@26100
   725
  fixes m n :: nat
haftmann@26100
   726
  assumes "n > 0"
haftmann@26100
   727
  shows "m mod n < (n::nat)"
haftmann@33340
   728
  using assms divmod_nat_rel [of m n] unfolding divmod_nat_rel_def by auto
paulson@14267
   729
haftmann@26100
   730
lemma mod_less_eq_dividend [simp]:
haftmann@26100
   731
  fixes m n :: nat
haftmann@26100
   732
  shows "m mod n \<le> m"
haftmann@26100
   733
proof (rule add_leD2)
haftmann@26100
   734
  from mod_div_equality have "m div n * n + m mod n = m" .
haftmann@26100
   735
  then show "m div n * n + m mod n \<le> m" by auto
haftmann@26100
   736
qed
haftmann@26100
   737
haftmann@26100
   738
lemma mod_geq: "\<not> m < (n\<Colon>nat) \<Longrightarrow> m mod n = (m - n) mod n"
nipkow@29667
   739
by (simp add: le_mod_geq linorder_not_less)
paulson@14267
   740
haftmann@26100
   741
lemma mod_if: "m mod (n\<Colon>nat) = (if m < n then m else (m - n) mod n)"
nipkow@29667
   742
by (simp add: le_mod_geq)
haftmann@26100
   743
paulson@14267
   744
lemma mod_1 [simp]: "m mod Suc 0 = 0"
nipkow@29667
   745
by (induct m) (simp_all add: mod_geq)
paulson@14267
   746
haftmann@26100
   747
lemma mod_mult_distrib: "(m mod n) * (k\<Colon>nat) = (m * k) mod (n * k)"
wenzelm@22718
   748
  apply (cases "n = 0", simp)
wenzelm@22718
   749
  apply (cases "k = 0", simp)
wenzelm@22718
   750
  apply (induct m rule: nat_less_induct)
wenzelm@22718
   751
  apply (subst mod_if, simp)
wenzelm@22718
   752
  apply (simp add: mod_geq diff_mult_distrib)
wenzelm@22718
   753
  done
paulson@14267
   754
paulson@14267
   755
lemma mod_mult_distrib2: "(k::nat) * (m mod n) = (k*m) mod (k*n)"
nipkow@29667
   756
by (simp add: mult_commute [of k] mod_mult_distrib)
paulson@14267
   757
paulson@14267
   758
(* a simple rearrangement of mod_div_equality: *)
paulson@14267
   759
lemma mult_div_cancel: "(n::nat) * (m div n) = m - (m mod n)"
nipkow@29667
   760
by (cut_tac a = m and b = n in mod_div_equality2, arith)
paulson@14267
   761
nipkow@15439
   762
lemma mod_le_divisor[simp]: "0 < n \<Longrightarrow> m mod n \<le> (n::nat)"
wenzelm@22718
   763
  apply (drule mod_less_divisor [where m = m])
wenzelm@22718
   764
  apply simp
wenzelm@22718
   765
  done
paulson@14267
   766
haftmann@26100
   767
subsubsection {* Quotient and Remainder *}
paulson@14267
   768
haftmann@33340
   769
lemma divmod_nat_rel_mult1_eq:
bulwahn@46552
   770
  "divmod_nat_rel b c (q, r)
haftmann@33340
   771
   \<Longrightarrow> divmod_nat_rel (a * b) c (a * q + a * r div c, a * r mod c)"
haftmann@33340
   772
by (auto simp add: split_ifs divmod_nat_rel_def algebra_simps)
paulson@14267
   773
haftmann@30923
   774
lemma div_mult1_eq:
haftmann@30923
   775
  "(a * b) div c = a * (b div c) + a * (b mod c) div (c::nat)"
bulwahn@46552
   776
by (blast intro: divmod_nat_rel [THEN divmod_nat_rel_mult1_eq, THEN div_eq])
paulson@14267
   777
haftmann@33340
   778
lemma divmod_nat_rel_add1_eq:
bulwahn@46552
   779
  "divmod_nat_rel a c (aq, ar) \<Longrightarrow> divmod_nat_rel b c (bq, br)
haftmann@33340
   780
   \<Longrightarrow> divmod_nat_rel (a + b) c (aq + bq + (ar + br) div c, (ar + br) mod c)"
haftmann@33340
   781
by (auto simp add: split_ifs divmod_nat_rel_def algebra_simps)
paulson@14267
   782
paulson@14267
   783
(*NOT suitable for rewriting: the RHS has an instance of the LHS*)
paulson@14267
   784
lemma div_add1_eq:
nipkow@25134
   785
  "(a+b) div (c::nat) = a div c + b div c + ((a mod c + b mod c) div c)"
bulwahn@46552
   786
by (blast intro: divmod_nat_rel_add1_eq [THEN div_eq] divmod_nat_rel)
paulson@14267
   787
paulson@14267
   788
lemma mod_lemma: "[| (0::nat) < c; r < b |] ==> b * (q mod c) + r < b * c"
wenzelm@22718
   789
  apply (cut_tac m = q and n = c in mod_less_divisor)
wenzelm@22718
   790
  apply (drule_tac [2] m = "q mod c" in less_imp_Suc_add, auto)
wenzelm@22718
   791
  apply (erule_tac P = "%x. ?lhs < ?rhs x" in ssubst)
wenzelm@22718
   792
  apply (simp add: add_mult_distrib2)
wenzelm@22718
   793
  done
paulson@10559
   794
haftmann@33340
   795
lemma divmod_nat_rel_mult2_eq:
bulwahn@46552
   796
  "divmod_nat_rel a b (q, r)
haftmann@33340
   797
   \<Longrightarrow> divmod_nat_rel a (b * c) (q div c, b *(q mod c) + r)"
haftmann@33340
   798
by (auto simp add: mult_ac divmod_nat_rel_def add_mult_distrib2 [symmetric] mod_lemma)
paulson@14267
   799
paulson@14267
   800
lemma div_mult2_eq: "a div (b*c) = (a div b) div (c::nat)"
bulwahn@46552
   801
by (force simp add: divmod_nat_rel [THEN divmod_nat_rel_mult2_eq, THEN div_eq])
paulson@14267
   802
paulson@14267
   803
lemma mod_mult2_eq: "a mod (b*c) = b*(a div b mod c) + a mod (b::nat)"
bulwahn@46552
   804
by (auto simp add: mult_commute divmod_nat_rel [THEN divmod_nat_rel_mult2_eq, THEN mod_eq])
paulson@14267
   805
paulson@14267
   806
huffman@46551
   807
subsubsection {* Further Facts about Quotient and Remainder *}
paulson@14267
   808
paulson@14267
   809
lemma div_1 [simp]: "m div Suc 0 = m"
nipkow@29667
   810
by (induct m) (simp_all add: div_geq)
paulson@14267
   811
paulson@14267
   812
(* Monotonicity of div in first argument *)
haftmann@30923
   813
lemma div_le_mono [rule_format (no_asm)]:
wenzelm@22718
   814
    "\<forall>m::nat. m \<le> n --> (m div k) \<le> (n div k)"
paulson@14267
   815
apply (case_tac "k=0", simp)
paulson@15251
   816
apply (induct "n" rule: nat_less_induct, clarify)
paulson@14267
   817
apply (case_tac "n<k")
paulson@14267
   818
(* 1  case n<k *)
paulson@14267
   819
apply simp
paulson@14267
   820
(* 2  case n >= k *)
paulson@14267
   821
apply (case_tac "m<k")
paulson@14267
   822
(* 2.1  case m<k *)
paulson@14267
   823
apply simp
paulson@14267
   824
(* 2.2  case m>=k *)
nipkow@15439
   825
apply (simp add: div_geq diff_le_mono)
paulson@14267
   826
done
paulson@14267
   827
paulson@14267
   828
(* Antimonotonicity of div in second argument *)
paulson@14267
   829
lemma div_le_mono2: "!!m::nat. [| 0<m; m\<le>n |] ==> (k div n) \<le> (k div m)"
paulson@14267
   830
apply (subgoal_tac "0<n")
wenzelm@22718
   831
 prefer 2 apply simp
paulson@15251
   832
apply (induct_tac k rule: nat_less_induct)
paulson@14267
   833
apply (rename_tac "k")
paulson@14267
   834
apply (case_tac "k<n", simp)
paulson@14267
   835
apply (subgoal_tac "~ (k<m) ")
wenzelm@22718
   836
 prefer 2 apply simp
paulson@14267
   837
apply (simp add: div_geq)
paulson@15251
   838
apply (subgoal_tac "(k-n) div n \<le> (k-m) div n")
paulson@14267
   839
 prefer 2
paulson@14267
   840
 apply (blast intro: div_le_mono diff_le_mono2)
paulson@14267
   841
apply (rule le_trans, simp)
nipkow@15439
   842
apply (simp)
paulson@14267
   843
done
paulson@14267
   844
paulson@14267
   845
lemma div_le_dividend [simp]: "m div n \<le> (m::nat)"
paulson@14267
   846
apply (case_tac "n=0", simp)
paulson@14267
   847
apply (subgoal_tac "m div n \<le> m div 1", simp)
paulson@14267
   848
apply (rule div_le_mono2)
paulson@14267
   849
apply (simp_all (no_asm_simp))
paulson@14267
   850
done
paulson@14267
   851
wenzelm@22718
   852
(* Similar for "less than" *)
paulson@17085
   853
lemma div_less_dividend [rule_format]:
paulson@14267
   854
     "!!n::nat. 1<n ==> 0 < m --> m div n < m"
paulson@15251
   855
apply (induct_tac m rule: nat_less_induct)
paulson@14267
   856
apply (rename_tac "m")
paulson@14267
   857
apply (case_tac "m<n", simp)
paulson@14267
   858
apply (subgoal_tac "0<n")
wenzelm@22718
   859
 prefer 2 apply simp
paulson@14267
   860
apply (simp add: div_geq)
paulson@14267
   861
apply (case_tac "n<m")
paulson@15251
   862
 apply (subgoal_tac "(m-n) div n < (m-n) ")
paulson@14267
   863
  apply (rule impI less_trans_Suc)+
paulson@14267
   864
apply assumption
nipkow@15439
   865
  apply (simp_all)
paulson@14267
   866
done
paulson@14267
   867
paulson@17085
   868
declare div_less_dividend [simp]
paulson@17085
   869
paulson@14267
   870
text{*A fact for the mutilated chess board*}
paulson@14267
   871
lemma mod_Suc: "Suc(m) mod n = (if Suc(m mod n) = n then 0 else Suc(m mod n))"
paulson@14267
   872
apply (case_tac "n=0", simp)
paulson@15251
   873
apply (induct "m" rule: nat_less_induct)
paulson@14267
   874
apply (case_tac "Suc (na) <n")
paulson@14267
   875
(* case Suc(na) < n *)
paulson@14267
   876
apply (frule lessI [THEN less_trans], simp add: less_not_refl3)
paulson@14267
   877
(* case n \<le> Suc(na) *)
paulson@16796
   878
apply (simp add: linorder_not_less le_Suc_eq mod_geq)
nipkow@15439
   879
apply (auto simp add: Suc_diff_le le_mod_geq)
paulson@14267
   880
done
paulson@14267
   881
paulson@14267
   882
lemma mod_eq_0_iff: "(m mod d = 0) = (\<exists>q::nat. m = d*q)"
nipkow@29667
   883
by (auto simp add: dvd_eq_mod_eq_0 [symmetric] dvd_def)
paulson@17084
   884
wenzelm@22718
   885
lemmas mod_eq_0D [dest!] = mod_eq_0_iff [THEN iffD1]
paulson@14267
   886
paulson@14267
   887
(*Loses information, namely we also have r<d provided d is nonzero*)
paulson@14267
   888
lemma mod_eqD: "(m mod d = r) ==> \<exists>q::nat. m = r + q*d"
haftmann@27651
   889
  apply (cut_tac a = m in mod_div_equality)
wenzelm@22718
   890
  apply (simp only: add_ac)
wenzelm@22718
   891
  apply (blast intro: sym)
wenzelm@22718
   892
  done
paulson@14267
   893
nipkow@13152
   894
lemma split_div:
nipkow@13189
   895
 "P(n div k :: nat) =
nipkow@13189
   896
 ((k = 0 \<longrightarrow> P 0) \<and> (k \<noteq> 0 \<longrightarrow> (!i. !j<k. n = k*i + j \<longrightarrow> P i)))"
nipkow@13189
   897
 (is "?P = ?Q" is "_ = (_ \<and> (_ \<longrightarrow> ?R))")
nipkow@13189
   898
proof
nipkow@13189
   899
  assume P: ?P
nipkow@13189
   900
  show ?Q
nipkow@13189
   901
  proof (cases)
nipkow@13189
   902
    assume "k = 0"
haftmann@27651
   903
    with P show ?Q by simp
nipkow@13189
   904
  next
nipkow@13189
   905
    assume not0: "k \<noteq> 0"
nipkow@13189
   906
    thus ?Q
nipkow@13189
   907
    proof (simp, intro allI impI)
nipkow@13189
   908
      fix i j
nipkow@13189
   909
      assume n: "n = k*i + j" and j: "j < k"
nipkow@13189
   910
      show "P i"
nipkow@13189
   911
      proof (cases)
wenzelm@22718
   912
        assume "i = 0"
wenzelm@22718
   913
        with n j P show "P i" by simp
nipkow@13189
   914
      next
wenzelm@22718
   915
        assume "i \<noteq> 0"
wenzelm@22718
   916
        with not0 n j P show "P i" by(simp add:add_ac)
nipkow@13189
   917
      qed
nipkow@13189
   918
    qed
nipkow@13189
   919
  qed
nipkow@13189
   920
next
nipkow@13189
   921
  assume Q: ?Q
nipkow@13189
   922
  show ?P
nipkow@13189
   923
  proof (cases)
nipkow@13189
   924
    assume "k = 0"
haftmann@27651
   925
    with Q show ?P by simp
nipkow@13189
   926
  next
nipkow@13189
   927
    assume not0: "k \<noteq> 0"
nipkow@13189
   928
    with Q have R: ?R by simp
nipkow@13189
   929
    from not0 R[THEN spec,of "n div k",THEN spec, of "n mod k"]
nipkow@13517
   930
    show ?P by simp
nipkow@13189
   931
  qed
nipkow@13189
   932
qed
nipkow@13189
   933
berghofe@13882
   934
lemma split_div_lemma:
haftmann@26100
   935
  assumes "0 < n"
haftmann@26100
   936
  shows "n * q \<le> m \<and> m < n * Suc q \<longleftrightarrow> q = ((m\<Colon>nat) div n)" (is "?lhs \<longleftrightarrow> ?rhs")
haftmann@26100
   937
proof
haftmann@26100
   938
  assume ?rhs
haftmann@26100
   939
  with mult_div_cancel have nq: "n * q = m - (m mod n)" by simp
haftmann@26100
   940
  then have A: "n * q \<le> m" by simp
haftmann@26100
   941
  have "n - (m mod n) > 0" using mod_less_divisor assms by auto
haftmann@26100
   942
  then have "m < m + (n - (m mod n))" by simp
haftmann@26100
   943
  then have "m < n + (m - (m mod n))" by simp
haftmann@26100
   944
  with nq have "m < n + n * q" by simp
haftmann@26100
   945
  then have B: "m < n * Suc q" by simp
haftmann@26100
   946
  from A B show ?lhs ..
haftmann@26100
   947
next
haftmann@26100
   948
  assume P: ?lhs
haftmann@33340
   949
  then have "divmod_nat_rel m n (q, m - n * q)"
haftmann@33340
   950
    unfolding divmod_nat_rel_def by (auto simp add: mult_ac)
haftmann@33340
   951
  with divmod_nat_rel_unique divmod_nat_rel [of m n]
haftmann@30923
   952
  have "(q, m - n * q) = (m div n, m mod n)" by auto
haftmann@30923
   953
  then show ?rhs by simp
haftmann@26100
   954
qed
berghofe@13882
   955
berghofe@13882
   956
theorem split_div':
berghofe@13882
   957
  "P ((m::nat) div n) = ((n = 0 \<and> P 0) \<or>
paulson@14267
   958
   (\<exists>q. (n * q \<le> m \<and> m < n * (Suc q)) \<and> P q))"
berghofe@13882
   959
  apply (case_tac "0 < n")
berghofe@13882
   960
  apply (simp only: add: split_div_lemma)
haftmann@27651
   961
  apply simp_all
berghofe@13882
   962
  done
berghofe@13882
   963
nipkow@13189
   964
lemma split_mod:
nipkow@13189
   965
 "P(n mod k :: nat) =
nipkow@13189
   966
 ((k = 0 \<longrightarrow> P n) \<and> (k \<noteq> 0 \<longrightarrow> (!i. !j<k. n = k*i + j \<longrightarrow> P j)))"
nipkow@13189
   967
 (is "?P = ?Q" is "_ = (_ \<and> (_ \<longrightarrow> ?R))")
nipkow@13189
   968
proof
nipkow@13189
   969
  assume P: ?P
nipkow@13189
   970
  show ?Q
nipkow@13189
   971
  proof (cases)
nipkow@13189
   972
    assume "k = 0"
haftmann@27651
   973
    with P show ?Q by simp
nipkow@13189
   974
  next
nipkow@13189
   975
    assume not0: "k \<noteq> 0"
nipkow@13189
   976
    thus ?Q
nipkow@13189
   977
    proof (simp, intro allI impI)
nipkow@13189
   978
      fix i j
nipkow@13189
   979
      assume "n = k*i + j" "j < k"
nipkow@13189
   980
      thus "P j" using not0 P by(simp add:add_ac mult_ac)
nipkow@13189
   981
    qed
nipkow@13189
   982
  qed
nipkow@13189
   983
next
nipkow@13189
   984
  assume Q: ?Q
nipkow@13189
   985
  show ?P
nipkow@13189
   986
  proof (cases)
nipkow@13189
   987
    assume "k = 0"
haftmann@27651
   988
    with Q show ?P by simp
nipkow@13189
   989
  next
nipkow@13189
   990
    assume not0: "k \<noteq> 0"
nipkow@13189
   991
    with Q have R: ?R by simp
nipkow@13189
   992
    from not0 R[THEN spec,of "n div k",THEN spec, of "n mod k"]
nipkow@13517
   993
    show ?P by simp
nipkow@13189
   994
  qed
nipkow@13189
   995
qed
nipkow@13189
   996
berghofe@13882
   997
theorem mod_div_equality': "(m::nat) mod n = m - (m div n) * n"
berghofe@13882
   998
  apply (rule_tac P="%x. m mod n = x - (m div n) * n" in
berghofe@13882
   999
    subst [OF mod_div_equality [of _ n]])
berghofe@13882
  1000
  apply arith
berghofe@13882
  1001
  done
berghofe@13882
  1002
haftmann@22800
  1003
lemma div_mod_equality':
haftmann@22800
  1004
  fixes m n :: nat
haftmann@22800
  1005
  shows "m div n * n = m - m mod n"
haftmann@22800
  1006
proof -
haftmann@22800
  1007
  have "m mod n \<le> m mod n" ..
haftmann@22800
  1008
  from div_mod_equality have 
haftmann@22800
  1009
    "m div n * n + m mod n - m mod n = m - m mod n" by simp
haftmann@22800
  1010
  with diff_add_assoc [OF `m mod n \<le> m mod n`, of "m div n * n"] have
haftmann@22800
  1011
    "m div n * n + (m mod n - m mod n) = m - m mod n"
haftmann@22800
  1012
    by simp
haftmann@22800
  1013
  then show ?thesis by simp
haftmann@22800
  1014
qed
haftmann@22800
  1015
haftmann@22800
  1016
huffman@46551
  1017
subsubsection {* An ``induction'' law for modulus arithmetic. *}
paulson@14640
  1018
paulson@14640
  1019
lemma mod_induct_0:
paulson@14640
  1020
  assumes step: "\<forall>i<p. P i \<longrightarrow> P ((Suc i) mod p)"
paulson@14640
  1021
  and base: "P i" and i: "i<p"
paulson@14640
  1022
  shows "P 0"
paulson@14640
  1023
proof (rule ccontr)
paulson@14640
  1024
  assume contra: "\<not>(P 0)"
paulson@14640
  1025
  from i have p: "0<p" by simp
paulson@14640
  1026
  have "\<forall>k. 0<k \<longrightarrow> \<not> P (p-k)" (is "\<forall>k. ?A k")
paulson@14640
  1027
  proof
paulson@14640
  1028
    fix k
paulson@14640
  1029
    show "?A k"
paulson@14640
  1030
    proof (induct k)
paulson@14640
  1031
      show "?A 0" by simp  -- "by contradiction"
paulson@14640
  1032
    next
paulson@14640
  1033
      fix n
paulson@14640
  1034
      assume ih: "?A n"
paulson@14640
  1035
      show "?A (Suc n)"
paulson@14640
  1036
      proof (clarsimp)
wenzelm@22718
  1037
        assume y: "P (p - Suc n)"
wenzelm@22718
  1038
        have n: "Suc n < p"
wenzelm@22718
  1039
        proof (rule ccontr)
wenzelm@22718
  1040
          assume "\<not>(Suc n < p)"
wenzelm@22718
  1041
          hence "p - Suc n = 0"
wenzelm@22718
  1042
            by simp
wenzelm@22718
  1043
          with y contra show "False"
wenzelm@22718
  1044
            by simp
wenzelm@22718
  1045
        qed
wenzelm@22718
  1046
        hence n2: "Suc (p - Suc n) = p-n" by arith
wenzelm@22718
  1047
        from p have "p - Suc n < p" by arith
wenzelm@22718
  1048
        with y step have z: "P ((Suc (p - Suc n)) mod p)"
wenzelm@22718
  1049
          by blast
wenzelm@22718
  1050
        show "False"
wenzelm@22718
  1051
        proof (cases "n=0")
wenzelm@22718
  1052
          case True
wenzelm@22718
  1053
          with z n2 contra show ?thesis by simp
wenzelm@22718
  1054
        next
wenzelm@22718
  1055
          case False
wenzelm@22718
  1056
          with p have "p-n < p" by arith
wenzelm@22718
  1057
          with z n2 False ih show ?thesis by simp
wenzelm@22718
  1058
        qed
paulson@14640
  1059
      qed
paulson@14640
  1060
    qed
paulson@14640
  1061
  qed
paulson@14640
  1062
  moreover
paulson@14640
  1063
  from i obtain k where "0<k \<and> i+k=p"
paulson@14640
  1064
    by (blast dest: less_imp_add_positive)
paulson@14640
  1065
  hence "0<k \<and> i=p-k" by auto
paulson@14640
  1066
  moreover
paulson@14640
  1067
  note base
paulson@14640
  1068
  ultimately
paulson@14640
  1069
  show "False" by blast
paulson@14640
  1070
qed
paulson@14640
  1071
paulson@14640
  1072
lemma mod_induct:
paulson@14640
  1073
  assumes step: "\<forall>i<p. P i \<longrightarrow> P ((Suc i) mod p)"
paulson@14640
  1074
  and base: "P i" and i: "i<p" and j: "j<p"
paulson@14640
  1075
  shows "P j"
paulson@14640
  1076
proof -
paulson@14640
  1077
  have "\<forall>j<p. P j"
paulson@14640
  1078
  proof
paulson@14640
  1079
    fix j
paulson@14640
  1080
    show "j<p \<longrightarrow> P j" (is "?A j")
paulson@14640
  1081
    proof (induct j)
paulson@14640
  1082
      from step base i show "?A 0"
wenzelm@22718
  1083
        by (auto elim: mod_induct_0)
paulson@14640
  1084
    next
paulson@14640
  1085
      fix k
paulson@14640
  1086
      assume ih: "?A k"
paulson@14640
  1087
      show "?A (Suc k)"
paulson@14640
  1088
      proof
wenzelm@22718
  1089
        assume suc: "Suc k < p"
wenzelm@22718
  1090
        hence k: "k<p" by simp
wenzelm@22718
  1091
        with ih have "P k" ..
wenzelm@22718
  1092
        with step k have "P (Suc k mod p)"
wenzelm@22718
  1093
          by blast
wenzelm@22718
  1094
        moreover
wenzelm@22718
  1095
        from suc have "Suc k mod p = Suc k"
wenzelm@22718
  1096
          by simp
wenzelm@22718
  1097
        ultimately
wenzelm@22718
  1098
        show "P (Suc k)" by simp
paulson@14640
  1099
      qed
paulson@14640
  1100
    qed
paulson@14640
  1101
  qed
paulson@14640
  1102
  with j show ?thesis by blast
paulson@14640
  1103
qed
paulson@14640
  1104
haftmann@33296
  1105
lemma div2_Suc_Suc [simp]: "Suc (Suc m) div 2 = Suc (m div 2)"
haftmann@33296
  1106
by (auto simp add: numeral_2_eq_2 le_div_geq)
haftmann@33296
  1107
haftmann@33296
  1108
lemma add_self_div_2 [simp]: "(m + m) div 2 = (m::nat)"
haftmann@33296
  1109
by (simp add: nat_mult_2 [symmetric])
haftmann@33296
  1110
haftmann@33296
  1111
lemma mod2_Suc_Suc [simp]: "Suc(Suc(m)) mod 2 = m mod 2"
haftmann@33296
  1112
apply (subgoal_tac "m mod 2 < 2")
haftmann@33296
  1113
apply (erule less_2_cases [THEN disjE])
huffman@35216
  1114
apply (simp_all (no_asm_simp) add: Let_def mod_Suc)
haftmann@33296
  1115
done
haftmann@33296
  1116
haftmann@33296
  1117
lemma mod2_gr_0 [simp]: "0 < (m\<Colon>nat) mod 2 \<longleftrightarrow> m mod 2 = 1"
haftmann@33296
  1118
proof -
boehmes@35815
  1119
  { fix n :: nat have  "(n::nat) < 2 \<Longrightarrow> n = 0 \<or> n = 1" by (cases n) simp_all }
haftmann@33296
  1120
  moreover have "m mod 2 < 2" by simp
haftmann@33296
  1121
  ultimately have "m mod 2 = 0 \<or> m mod 2 = 1" .
haftmann@33296
  1122
  then show ?thesis by auto
haftmann@33296
  1123
qed
haftmann@33296
  1124
haftmann@33296
  1125
text{*These lemmas collapse some needless occurrences of Suc:
haftmann@33296
  1126
    at least three Sucs, since two and fewer are rewritten back to Suc again!
haftmann@33296
  1127
    We already have some rules to simplify operands smaller than 3.*}
haftmann@33296
  1128
haftmann@33296
  1129
lemma div_Suc_eq_div_add3 [simp]: "m div (Suc (Suc (Suc n))) = m div (3+n)"
haftmann@33296
  1130
by (simp add: Suc3_eq_add_3)
haftmann@33296
  1131
haftmann@33296
  1132
lemma mod_Suc_eq_mod_add3 [simp]: "m mod (Suc (Suc (Suc n))) = m mod (3+n)"
haftmann@33296
  1133
by (simp add: Suc3_eq_add_3)
haftmann@33296
  1134
haftmann@33296
  1135
lemma Suc_div_eq_add3_div: "(Suc (Suc (Suc m))) div n = (3+m) div n"
haftmann@33296
  1136
by (simp add: Suc3_eq_add_3)
haftmann@33296
  1137
haftmann@33296
  1138
lemma Suc_mod_eq_add3_mod: "(Suc (Suc (Suc m))) mod n = (3+m) mod n"
haftmann@33296
  1139
by (simp add: Suc3_eq_add_3)
haftmann@33296
  1140
wenzelm@45607
  1141
lemmas Suc_div_eq_add3_div_number_of [simp] = Suc_div_eq_add3_div [of _ "number_of v"] for v
wenzelm@45607
  1142
lemmas Suc_mod_eq_add3_mod_number_of [simp] = Suc_mod_eq_add3_mod [of _ "number_of v"] for v
haftmann@33296
  1143
haftmann@33361
  1144
haftmann@33361
  1145
lemma Suc_times_mod_eq: "1<k ==> Suc (k * m) mod k = 1" 
haftmann@33361
  1146
apply (induct "m")
haftmann@33361
  1147
apply (simp_all add: mod_Suc)
haftmann@33361
  1148
done
haftmann@33361
  1149
wenzelm@45607
  1150
declare Suc_times_mod_eq [of "number_of w", simp] for w
haftmann@33361
  1151
haftmann@33361
  1152
lemma [simp]: "n div k \<le> (Suc n) div k"
haftmann@33361
  1153
by (simp add: div_le_mono) 
haftmann@33361
  1154
haftmann@33361
  1155
lemma Suc_n_div_2_gt_zero [simp]: "(0::nat) < n ==> 0 < (n + 1) div 2"
haftmann@33361
  1156
by (cases n) simp_all
haftmann@33361
  1157
boehmes@35815
  1158
lemma div_2_gt_zero [simp]: assumes A: "(1::nat) < n" shows "0 < n div 2"
boehmes@35815
  1159
proof -
boehmes@35815
  1160
  from A have B: "0 < n - 1" and C: "n - 1 + 1 = n" by simp_all
boehmes@35815
  1161
  from Suc_n_div_2_gt_zero [OF B] C show ?thesis by simp 
boehmes@35815
  1162
qed
haftmann@33361
  1163
haftmann@33361
  1164
  (* Potential use of algebra : Equality modulo n*)
haftmann@33361
  1165
lemma mod_mult_self3 [simp]: "(k*n + m) mod n = m mod (n::nat)"
haftmann@33361
  1166
by (simp add: mult_ac add_ac)
haftmann@33361
  1167
haftmann@33361
  1168
lemma mod_mult_self4 [simp]: "Suc (k*n + m) mod n = Suc m mod n"
haftmann@33361
  1169
proof -
haftmann@33361
  1170
  have "Suc (k * n + m) mod n = (k * n + Suc m) mod n" by simp
haftmann@33361
  1171
  also have "... = Suc m mod n" by (rule mod_mult_self3) 
haftmann@33361
  1172
  finally show ?thesis .
haftmann@33361
  1173
qed
haftmann@33361
  1174
haftmann@33361
  1175
lemma mod_Suc_eq_Suc_mod: "Suc m mod n = Suc (m mod n) mod n"
haftmann@33361
  1176
apply (subst mod_Suc [of m]) 
haftmann@33361
  1177
apply (subst mod_Suc [of "m mod n"], simp) 
haftmann@33361
  1178
done
haftmann@33361
  1179
haftmann@33361
  1180
haftmann@33361
  1181
subsection {* Division on @{typ int} *}
haftmann@33361
  1182
haftmann@33361
  1183
definition divmod_int_rel :: "int \<Rightarrow> int \<Rightarrow> int \<times> int \<Rightarrow> bool" where
haftmann@33361
  1184
    --{*definition of quotient and remainder*}
haftmann@33361
  1185
    [code]: "divmod_int_rel a b = (\<lambda>(q, r). a = b * q + r \<and>
haftmann@33361
  1186
               (if 0 < b then 0 \<le> r \<and> r < b else b < r \<and> r \<le> 0))"
haftmann@33361
  1187
haftmann@33361
  1188
definition adjust :: "int \<Rightarrow> int \<times> int \<Rightarrow> int \<times> int" where
haftmann@33361
  1189
    --{*for the division algorithm*}
haftmann@33361
  1190
    [code]: "adjust b = (\<lambda>(q, r). if 0 \<le> r - b then (2 * q + 1, r - b)
haftmann@33361
  1191
                         else (2 * q, r))"
haftmann@33361
  1192
haftmann@33361
  1193
text{*algorithm for the case @{text "a\<ge>0, b>0"}*}
haftmann@33361
  1194
function posDivAlg :: "int \<Rightarrow> int \<Rightarrow> int \<times> int" where
haftmann@33361
  1195
  "posDivAlg a b = (if a < b \<or>  b \<le> 0 then (0, a)
haftmann@33361
  1196
     else adjust b (posDivAlg a (2 * b)))"
haftmann@33361
  1197
by auto
haftmann@33361
  1198
termination by (relation "measure (\<lambda>(a, b). nat (a - b + 1))")
haftmann@33361
  1199
  (auto simp add: mult_2)
haftmann@33361
  1200
haftmann@33361
  1201
text{*algorithm for the case @{text "a<0, b>0"}*}
haftmann@33361
  1202
function negDivAlg :: "int \<Rightarrow> int \<Rightarrow> int \<times> int" where
haftmann@33361
  1203
  "negDivAlg a b = (if 0 \<le>a + b \<or> b \<le> 0  then (-1, a + b)
haftmann@33361
  1204
     else adjust b (negDivAlg a (2 * b)))"
haftmann@33361
  1205
by auto
haftmann@33361
  1206
termination by (relation "measure (\<lambda>(a, b). nat (- a - b))")
haftmann@33361
  1207
  (auto simp add: mult_2)
haftmann@33361
  1208
haftmann@33361
  1209
text{*algorithm for the general case @{term "b\<noteq>0"}*}
haftmann@33361
  1210
definition negateSnd :: "int \<times> int \<Rightarrow> int \<times> int" where
haftmann@33361
  1211
  [code_unfold]: "negateSnd = apsnd uminus"
haftmann@33361
  1212
haftmann@33361
  1213
definition divmod_int :: "int \<Rightarrow> int \<Rightarrow> int \<times> int" where
haftmann@33361
  1214
    --{*The full division algorithm considers all possible signs for a, b
haftmann@33361
  1215
       including the special case @{text "a=0, b<0"} because 
haftmann@33361
  1216
       @{term negDivAlg} requires @{term "a<0"}.*}
haftmann@33361
  1217
  "divmod_int a b = (if 0 \<le> a then if 0 \<le> b then posDivAlg a b
haftmann@33361
  1218
                  else if a = 0 then (0, 0)
haftmann@33361
  1219
                       else negateSnd (negDivAlg (-a) (-b))
haftmann@33361
  1220
               else 
haftmann@33361
  1221
                  if 0 < b then negDivAlg a b
haftmann@33361
  1222
                  else negateSnd (posDivAlg (-a) (-b)))"
haftmann@33361
  1223
haftmann@33361
  1224
instantiation int :: Divides.div
haftmann@33361
  1225
begin
haftmann@33361
  1226
huffman@46551
  1227
definition div_int where
haftmann@33361
  1228
  "a div b = fst (divmod_int a b)"
haftmann@33361
  1229
huffman@46551
  1230
lemma fst_divmod_int [simp]:
huffman@46551
  1231
  "fst (divmod_int a b) = a div b"
huffman@46551
  1232
  by (simp add: div_int_def)
huffman@46551
  1233
huffman@46551
  1234
definition mod_int where
haftmann@33361
  1235
 "a mod b = snd (divmod_int a b)"
haftmann@33361
  1236
huffman@46551
  1237
lemma snd_divmod_int [simp]:
huffman@46551
  1238
  "snd (divmod_int a b) = a mod b"
huffman@46551
  1239
  by (simp add: mod_int_def)
huffman@46551
  1240
haftmann@33361
  1241
instance ..
haftmann@33361
  1242
paulson@3366
  1243
end
haftmann@33361
  1244
haftmann@33361
  1245
lemma divmod_int_mod_div:
haftmann@33361
  1246
  "divmod_int p q = (p div q, p mod q)"
huffman@46551
  1247
  by (simp add: prod_eq_iff)
haftmann@33361
  1248
haftmann@33361
  1249
text{*
haftmann@33361
  1250
Here is the division algorithm in ML:
haftmann@33361
  1251
haftmann@33361
  1252
\begin{verbatim}
haftmann@33361
  1253
    fun posDivAlg (a,b) =
haftmann@33361
  1254
      if a<b then (0,a)
haftmann@33361
  1255
      else let val (q,r) = posDivAlg(a, 2*b)
haftmann@33361
  1256
               in  if 0\<le>r-b then (2*q+1, r-b) else (2*q, r)
haftmann@33361
  1257
           end
haftmann@33361
  1258
haftmann@33361
  1259
    fun negDivAlg (a,b) =
haftmann@33361
  1260
      if 0\<le>a+b then (~1,a+b)
haftmann@33361
  1261
      else let val (q,r) = negDivAlg(a, 2*b)
haftmann@33361
  1262
               in  if 0\<le>r-b then (2*q+1, r-b) else (2*q, r)
haftmann@33361
  1263
           end;
haftmann@33361
  1264
haftmann@33361
  1265
    fun negateSnd (q,r:int) = (q,~r);
haftmann@33361
  1266
haftmann@33361
  1267
    fun divmod (a,b) = if 0\<le>a then 
haftmann@33361
  1268
                          if b>0 then posDivAlg (a,b) 
haftmann@33361
  1269
                           else if a=0 then (0,0)
haftmann@33361
  1270
                                else negateSnd (negDivAlg (~a,~b))
haftmann@33361
  1271
                       else 
haftmann@33361
  1272
                          if 0<b then negDivAlg (a,b)
haftmann@33361
  1273
                          else        negateSnd (posDivAlg (~a,~b));
haftmann@33361
  1274
\end{verbatim}
haftmann@33361
  1275
*}
haftmann@33361
  1276
haftmann@33361
  1277
huffman@46551
  1278
subsubsection {* Uniqueness and Monotonicity of Quotients and Remainders *}
haftmann@33361
  1279
haftmann@33361
  1280
lemma unique_quotient_lemma:
haftmann@33361
  1281
     "[| b*q' + r'  \<le> b*q + r;  0 \<le> r';  r' < b;  r < b |]  
haftmann@33361
  1282
      ==> q' \<le> (q::int)"
haftmann@33361
  1283
apply (subgoal_tac "r' + b * (q'-q) \<le> r")
haftmann@33361
  1284
 prefer 2 apply (simp add: right_diff_distrib)
haftmann@33361
  1285
apply (subgoal_tac "0 < b * (1 + q - q') ")
haftmann@33361
  1286
apply (erule_tac [2] order_le_less_trans)
haftmann@33361
  1287
 prefer 2 apply (simp add: right_diff_distrib right_distrib)
haftmann@33361
  1288
apply (subgoal_tac "b * q' < b * (1 + q) ")
haftmann@33361
  1289
 prefer 2 apply (simp add: right_diff_distrib right_distrib)
haftmann@33361
  1290
apply (simp add: mult_less_cancel_left)
haftmann@33361
  1291
done
haftmann@33361
  1292
haftmann@33361
  1293
lemma unique_quotient_lemma_neg:
haftmann@33361
  1294
     "[| b*q' + r' \<le> b*q + r;  r \<le> 0;  b < r;  b < r' |]  
haftmann@33361
  1295
      ==> q \<le> (q'::int)"
haftmann@33361
  1296
by (rule_tac b = "-b" and r = "-r'" and r' = "-r" in unique_quotient_lemma, 
haftmann@33361
  1297
    auto)
haftmann@33361
  1298
haftmann@33361
  1299
lemma unique_quotient:
bulwahn@46552
  1300
     "[| divmod_int_rel a b (q, r); divmod_int_rel a b (q', r') |]  
haftmann@33361
  1301
      ==> q = q'"
haftmann@33361
  1302
apply (simp add: divmod_int_rel_def linorder_neq_iff split: split_if_asm)
haftmann@33361
  1303
apply (blast intro: order_antisym
haftmann@33361
  1304
             dest: order_eq_refl [THEN unique_quotient_lemma] 
haftmann@33361
  1305
             order_eq_refl [THEN unique_quotient_lemma_neg] sym)+
haftmann@33361
  1306
done
haftmann@33361
  1307
haftmann@33361
  1308
haftmann@33361
  1309
lemma unique_remainder:
bulwahn@46552
  1310
     "[| divmod_int_rel a b (q, r); divmod_int_rel a b (q', r') |]  
haftmann@33361
  1311
      ==> r = r'"
haftmann@33361
  1312
apply (subgoal_tac "q = q'")
haftmann@33361
  1313
 apply (simp add: divmod_int_rel_def)
haftmann@33361
  1314
apply (blast intro: unique_quotient)
haftmann@33361
  1315
done
haftmann@33361
  1316
haftmann@33361
  1317
huffman@46551
  1318
subsubsection {* Correctness of @{term posDivAlg}, the Algorithm for Non-Negative Dividends *}
haftmann@33361
  1319
haftmann@33361
  1320
text{*And positive divisors*}
haftmann@33361
  1321
haftmann@33361
  1322
lemma adjust_eq [simp]:
haftmann@33361
  1323
     "adjust b (q,r) = 
haftmann@33361
  1324
      (let diff = r-b in  
haftmann@33361
  1325
        if 0 \<le> diff then (2*q + 1, diff)   
haftmann@33361
  1326
                     else (2*q, r))"
haftmann@33361
  1327
by (simp add: Let_def adjust_def)
haftmann@33361
  1328
haftmann@33361
  1329
declare posDivAlg.simps [simp del]
haftmann@33361
  1330
haftmann@33361
  1331
text{*use with a simproc to avoid repeatedly proving the premise*}
haftmann@33361
  1332
lemma posDivAlg_eqn:
haftmann@33361
  1333
     "0 < b ==>  
haftmann@33361
  1334
      posDivAlg a b = (if a<b then (0,a) else adjust b (posDivAlg a (2*b)))"
haftmann@33361
  1335
by (rule posDivAlg.simps [THEN trans], simp)
haftmann@33361
  1336
haftmann@33361
  1337
text{*Correctness of @{term posDivAlg}: it computes quotients correctly*}
haftmann@33361
  1338
theorem posDivAlg_correct:
haftmann@33361
  1339
  assumes "0 \<le> a" and "0 < b"
haftmann@33361
  1340
  shows "divmod_int_rel a b (posDivAlg a b)"
wenzelm@41550
  1341
  using assms
wenzelm@41550
  1342
  apply (induct a b rule: posDivAlg.induct)
wenzelm@41550
  1343
  apply auto
wenzelm@41550
  1344
  apply (simp add: divmod_int_rel_def)
wenzelm@41550
  1345
  apply (subst posDivAlg_eqn, simp add: right_distrib)
wenzelm@41550
  1346
  apply (case_tac "a < b")
wenzelm@41550
  1347
  apply simp_all
wenzelm@41550
  1348
  apply (erule splitE)
wenzelm@41550
  1349
  apply (auto simp add: right_distrib Let_def mult_ac mult_2_right)
wenzelm@41550
  1350
  done
haftmann@33361
  1351
haftmann@33361
  1352
huffman@46551
  1353
subsubsection {* Correctness of @{term negDivAlg}, the Algorithm for Negative Dividends *}
haftmann@33361
  1354
haftmann@33361
  1355
text{*And positive divisors*}
haftmann@33361
  1356
haftmann@33361
  1357
declare negDivAlg.simps [simp del]
haftmann@33361
  1358
haftmann@33361
  1359
text{*use with a simproc to avoid repeatedly proving the premise*}
haftmann@33361
  1360
lemma negDivAlg_eqn:
haftmann@33361
  1361
     "0 < b ==>  
haftmann@33361
  1362
      negDivAlg a b =       
haftmann@33361
  1363
       (if 0\<le>a+b then (-1,a+b) else adjust b (negDivAlg a (2*b)))"
haftmann@33361
  1364
by (rule negDivAlg.simps [THEN trans], simp)
haftmann@33361
  1365
haftmann@33361
  1366
(*Correctness of negDivAlg: it computes quotients correctly
haftmann@33361
  1367
  It doesn't work if a=0 because the 0/b equals 0, not -1*)
haftmann@33361
  1368
lemma negDivAlg_correct:
haftmann@33361
  1369
  assumes "a < 0" and "b > 0"
haftmann@33361
  1370
  shows "divmod_int_rel a b (negDivAlg a b)"
wenzelm@41550
  1371
  using assms
wenzelm@41550
  1372
  apply (induct a b rule: negDivAlg.induct)
wenzelm@41550
  1373
  apply (auto simp add: linorder_not_le)
wenzelm@41550
  1374
  apply (simp add: divmod_int_rel_def)
wenzelm@41550
  1375
  apply (subst negDivAlg_eqn, assumption)
wenzelm@41550
  1376
  apply (case_tac "a + b < (0\<Colon>int)")
wenzelm@41550
  1377
  apply simp_all
wenzelm@41550
  1378
  apply (erule splitE)
wenzelm@41550
  1379
  apply (auto simp add: right_distrib Let_def mult_ac mult_2_right)
wenzelm@41550
  1380
  done
haftmann@33361
  1381
haftmann@33361
  1382
huffman@46551
  1383
subsubsection {* Existence Shown by Proving the Division Algorithm to be Correct *}
haftmann@33361
  1384
haftmann@33361
  1385
(*the case a=0*)
haftmann@33361
  1386
lemma divmod_int_rel_0: "b \<noteq> 0 ==> divmod_int_rel 0 b (0, 0)"
haftmann@33361
  1387
by (auto simp add: divmod_int_rel_def linorder_neq_iff)
haftmann@33361
  1388
haftmann@33361
  1389
lemma posDivAlg_0 [simp]: "posDivAlg 0 b = (0, 0)"
haftmann@33361
  1390
by (subst posDivAlg.simps, auto)
haftmann@33361
  1391
haftmann@33361
  1392
lemma negDivAlg_minus1 [simp]: "negDivAlg -1 b = (-1, b - 1)"
haftmann@33361
  1393
by (subst negDivAlg.simps, auto)
haftmann@33361
  1394
haftmann@33361
  1395
lemma negateSnd_eq [simp]: "negateSnd(q,r) = (q,-r)"
haftmann@33361
  1396
by (simp add: negateSnd_def)
haftmann@33361
  1397
haftmann@33361
  1398
lemma divmod_int_rel_neg: "divmod_int_rel (-a) (-b) qr ==> divmod_int_rel a b (negateSnd qr)"
haftmann@33361
  1399
by (auto simp add: split_ifs divmod_int_rel_def)
haftmann@33361
  1400
haftmann@33361
  1401
lemma divmod_int_correct: "b \<noteq> 0 ==> divmod_int_rel a b (divmod_int a b)"
haftmann@33361
  1402
by (force simp add: linorder_neq_iff divmod_int_rel_0 divmod_int_def divmod_int_rel_neg
haftmann@33361
  1403
                    posDivAlg_correct negDivAlg_correct)
haftmann@33361
  1404
haftmann@33361
  1405
text{*Arbitrary definitions for division by zero.  Useful to simplify 
haftmann@33361
  1406
    certain equations.*}
haftmann@33361
  1407
haftmann@33361
  1408
lemma DIVISION_BY_ZERO [simp]: "a div (0::int) = 0 & a mod (0::int) = a"
haftmann@33361
  1409
by (simp add: div_int_def mod_int_def divmod_int_def posDivAlg.simps)  
haftmann@33361
  1410
haftmann@33361
  1411
haftmann@33361
  1412
text{*Basic laws about division and remainder*}
haftmann@33361
  1413
haftmann@33361
  1414
lemma zmod_zdiv_equality: "(a::int) = b * (a div b) + (a mod b)"
haftmann@33361
  1415
apply (case_tac "b = 0", simp)
haftmann@33361
  1416
apply (cut_tac a = a and b = b in divmod_int_correct)
huffman@46551
  1417
apply (auto simp add: divmod_int_rel_def prod_eq_iff)
haftmann@33361
  1418
done
haftmann@33361
  1419
haftmann@33361
  1420
lemma zdiv_zmod_equality: "(b * (a div b) + (a mod b)) + k = (a::int)+k"
haftmann@33361
  1421
by(simp add: zmod_zdiv_equality[symmetric])
haftmann@33361
  1422
haftmann@33361
  1423
lemma zdiv_zmod_equality2: "((a div b) * b + (a mod b)) + k = (a::int)+k"
haftmann@33361
  1424
by(simp add: mult_commute zmod_zdiv_equality[symmetric])
haftmann@33361
  1425
haftmann@33361
  1426
text {* Tool setup *}
haftmann@33361
  1427
haftmann@33361
  1428
ML {*
wenzelm@43594
  1429
structure Cancel_Div_Mod_Int = Cancel_Div_Mod
wenzelm@41550
  1430
(
haftmann@33361
  1431
  val div_name = @{const_name div};
haftmann@33361
  1432
  val mod_name = @{const_name mod};
haftmann@33361
  1433
  val mk_binop = HOLogic.mk_binop;
haftmann@33361
  1434
  val mk_sum = Arith_Data.mk_sum HOLogic.intT;
haftmann@33361
  1435
  val dest_sum = Arith_Data.dest_sum;
haftmann@33361
  1436
haftmann@33361
  1437
  val div_mod_eqs = map mk_meta_eq [@{thm zdiv_zmod_equality}, @{thm zdiv_zmod_equality2}];
haftmann@33361
  1438
haftmann@33361
  1439
  val prove_eq_sums = Arith_Data.prove_conv2 all_tac (Arith_Data.simp_all_tac 
haftmann@33361
  1440
    (@{thm diff_minus} :: @{thms add_0s} @ @{thms add_ac}))
wenzelm@41550
  1441
)
haftmann@33361
  1442
*}
haftmann@33361
  1443
wenzelm@43594
  1444
simproc_setup cancel_div_mod_int ("(k::int) + l") = {* K Cancel_Div_Mod_Int.proc *}
wenzelm@43594
  1445
haftmann@33361
  1446
lemma pos_mod_conj : "(0::int) < b ==> 0 \<le> a mod b & a mod b < b"
haftmann@33361
  1447
apply (cut_tac a = a and b = b in divmod_int_correct)
huffman@46551
  1448
apply (auto simp add: divmod_int_rel_def prod_eq_iff)
haftmann@33361
  1449
done
haftmann@33361
  1450
wenzelm@45607
  1451
lemmas pos_mod_sign [simp] = pos_mod_conj [THEN conjunct1]
wenzelm@45607
  1452
   and pos_mod_bound [simp] = pos_mod_conj [THEN conjunct2]
haftmann@33361
  1453
haftmann@33361
  1454
lemma neg_mod_conj : "b < (0::int) ==> a mod b \<le> 0 & b < a mod b"
haftmann@33361
  1455
apply (cut_tac a = a and b = b in divmod_int_correct)
huffman@46551
  1456
apply (auto simp add: divmod_int_rel_def prod_eq_iff)
haftmann@33361
  1457
done
haftmann@33361
  1458
wenzelm@45607
  1459
lemmas neg_mod_sign [simp] = neg_mod_conj [THEN conjunct1]
wenzelm@45607
  1460
   and neg_mod_bound [simp] = neg_mod_conj [THEN conjunct2]
haftmann@33361
  1461
haftmann@33361
  1462
huffman@46551
  1463
subsubsection {* General Properties of div and mod *}
haftmann@33361
  1464
haftmann@33361
  1465
lemma divmod_int_rel_div_mod: "b \<noteq> 0 ==> divmod_int_rel a b (a div b, a mod b)"
haftmann@33361
  1466
apply (cut_tac a = a and b = b in zmod_zdiv_equality)
haftmann@33361
  1467
apply (force simp add: divmod_int_rel_def linorder_neq_iff)
haftmann@33361
  1468
done
haftmann@33361
  1469
bulwahn@46552
  1470
lemma divmod_int_rel_div: "[| divmod_int_rel a b (q, r) |] ==> a div b = q"
bulwahn@46552
  1471
apply (cases "b = 0")
bulwahn@46552
  1472
apply (simp add: divmod_int_rel_def)
haftmann@33361
  1473
by (simp add: divmod_int_rel_div_mod [THEN unique_quotient])
haftmann@33361
  1474
bulwahn@46552
  1475
lemma divmod_int_rel_mod: "[| divmod_int_rel a b (q, r) |] ==> a mod b = r"
bulwahn@46552
  1476
apply (cases "b = 0")
bulwahn@46552
  1477
apply (simp add: divmod_int_rel_def)
haftmann@33361
  1478
by (simp add: divmod_int_rel_div_mod [THEN unique_remainder])
haftmann@33361
  1479
haftmann@33361
  1480
lemma div_pos_pos_trivial: "[| (0::int) \<le> a;  a < b |] ==> a div b = 0"
haftmann@33361
  1481
apply (rule divmod_int_rel_div)
haftmann@33361
  1482
apply (auto simp add: divmod_int_rel_def)
haftmann@33361
  1483
done
haftmann@33361
  1484
haftmann@33361
  1485
lemma div_neg_neg_trivial: "[| a \<le> (0::int);  b < a |] ==> a div b = 0"
haftmann@33361
  1486
apply (rule divmod_int_rel_div)
haftmann@33361
  1487
apply (auto simp add: divmod_int_rel_def)
haftmann@33361
  1488
done
haftmann@33361
  1489
haftmann@33361
  1490
lemma div_pos_neg_trivial: "[| (0::int) < a;  a+b \<le> 0 |] ==> a div b = -1"
haftmann@33361
  1491
apply (rule divmod_int_rel_div)
haftmann@33361
  1492
apply (auto simp add: divmod_int_rel_def)
haftmann@33361
  1493
done
haftmann@33361
  1494
haftmann@33361
  1495
(*There is no div_neg_pos_trivial because  0 div b = 0 would supersede it*)
haftmann@33361
  1496
haftmann@33361
  1497
lemma mod_pos_pos_trivial: "[| (0::int) \<le> a;  a < b |] ==> a mod b = a"
haftmann@33361
  1498
apply (rule_tac q = 0 in divmod_int_rel_mod)
haftmann@33361
  1499
apply (auto simp add: divmod_int_rel_def)
haftmann@33361
  1500
done
haftmann@33361
  1501
haftmann@33361
  1502
lemma mod_neg_neg_trivial: "[| a \<le> (0::int);  b < a |] ==> a mod b = a"
haftmann@33361
  1503
apply (rule_tac q = 0 in divmod_int_rel_mod)
haftmann@33361
  1504
apply (auto simp add: divmod_int_rel_def)
haftmann@33361
  1505
done
haftmann@33361
  1506
haftmann@33361
  1507
lemma mod_pos_neg_trivial: "[| (0::int) < a;  a+b \<le> 0 |] ==> a mod b = a+b"
haftmann@33361
  1508
apply (rule_tac q = "-1" in divmod_int_rel_mod)
haftmann@33361
  1509
apply (auto simp add: divmod_int_rel_def)
haftmann@33361
  1510
done
haftmann@33361
  1511
haftmann@33361
  1512
text{*There is no @{text mod_neg_pos_trivial}.*}
haftmann@33361
  1513
haftmann@33361
  1514
haftmann@33361
  1515
(*Simpler laws such as -a div b = -(a div b) FAIL, but see just below*)
haftmann@33361
  1516
lemma zdiv_zminus_zminus [simp]: "(-a) div (-b) = a div (b::int)"
haftmann@33361
  1517
apply (case_tac "b = 0", simp)
haftmann@33361
  1518
apply (simp add: divmod_int_rel_div_mod [THEN divmod_int_rel_neg, simplified, 
haftmann@33361
  1519
                                 THEN divmod_int_rel_div, THEN sym])
haftmann@33361
  1520
haftmann@33361
  1521
done
haftmann@33361
  1522
haftmann@33361
  1523
(*Simpler laws such as -a mod b = -(a mod b) FAIL, but see just below*)
haftmann@33361
  1524
lemma zmod_zminus_zminus [simp]: "(-a) mod (-b) = - (a mod (b::int))"
haftmann@33361
  1525
apply (case_tac "b = 0", simp)
haftmann@33361
  1526
apply (subst divmod_int_rel_div_mod [THEN divmod_int_rel_neg, simplified, THEN divmod_int_rel_mod],
haftmann@33361
  1527
       auto)
haftmann@33361
  1528
done
haftmann@33361
  1529
haftmann@33361
  1530
huffman@46551
  1531
subsubsection {* Laws for div and mod with Unary Minus *}
haftmann@33361
  1532
haftmann@33361
  1533
lemma zminus1_lemma:
haftmann@33361
  1534
     "divmod_int_rel a b (q, r)
haftmann@33361
  1535
      ==> divmod_int_rel (-a) b (if r=0 then -q else -q - 1,  
haftmann@33361
  1536
                          if r=0 then 0 else b-r)"
haftmann@33361
  1537
by (force simp add: split_ifs divmod_int_rel_def linorder_neq_iff right_diff_distrib)
haftmann@33361
  1538
haftmann@33361
  1539
haftmann@33361
  1540
lemma zdiv_zminus1_eq_if:
haftmann@33361
  1541
     "b \<noteq> (0::int)  
haftmann@33361
  1542
      ==> (-a) div b =  
haftmann@33361
  1543
          (if a mod b = 0 then - (a div b) else  - (a div b) - 1)"
haftmann@33361
  1544
by (blast intro: divmod_int_rel_div_mod [THEN zminus1_lemma, THEN divmod_int_rel_div])
haftmann@33361
  1545
haftmann@33361
  1546
lemma zmod_zminus1_eq_if:
haftmann@33361
  1547
     "(-a::int) mod b = (if a mod b = 0 then 0 else  b - (a mod b))"
haftmann@33361
  1548
apply (case_tac "b = 0", simp)
haftmann@33361
  1549
apply (blast intro: divmod_int_rel_div_mod [THEN zminus1_lemma, THEN divmod_int_rel_mod])
haftmann@33361
  1550
done
haftmann@33361
  1551
haftmann@33361
  1552
lemma zmod_zminus1_not_zero:
haftmann@33361
  1553
  fixes k l :: int
haftmann@33361
  1554
  shows "- k mod l \<noteq> 0 \<Longrightarrow> k mod l \<noteq> 0"
haftmann@33361
  1555
  unfolding zmod_zminus1_eq_if by auto
haftmann@33361
  1556
haftmann@33361
  1557
lemma zdiv_zminus2: "a div (-b) = (-a::int) div b"
haftmann@33361
  1558
by (cut_tac a = "-a" in zdiv_zminus_zminus, auto)
haftmann@33361
  1559
haftmann@33361
  1560
lemma zmod_zminus2: "a mod (-b) = - ((-a::int) mod b)"
haftmann@33361
  1561
by (cut_tac a = "-a" and b = b in zmod_zminus_zminus, auto)
haftmann@33361
  1562
haftmann@33361
  1563
lemma zdiv_zminus2_eq_if:
haftmann@33361
  1564
     "b \<noteq> (0::int)  
haftmann@33361
  1565
      ==> a div (-b) =  
haftmann@33361
  1566
          (if a mod b = 0 then - (a div b) else  - (a div b) - 1)"
haftmann@33361
  1567
by (simp add: zdiv_zminus1_eq_if zdiv_zminus2)
haftmann@33361
  1568
haftmann@33361
  1569
lemma zmod_zminus2_eq_if:
haftmann@33361
  1570
     "a mod (-b::int) = (if a mod b = 0 then 0 else  (a mod b) - b)"
haftmann@33361
  1571
by (simp add: zmod_zminus1_eq_if zmod_zminus2)
haftmann@33361
  1572
haftmann@33361
  1573
lemma zmod_zminus2_not_zero:
haftmann@33361
  1574
  fixes k l :: int
haftmann@33361
  1575
  shows "k mod - l \<noteq> 0 \<Longrightarrow> k mod l \<noteq> 0"
haftmann@33361
  1576
  unfolding zmod_zminus2_eq_if by auto 
haftmann@33361
  1577
haftmann@33361
  1578
huffman@46551
  1579
subsubsection {* Division of a Number by Itself *}
haftmann@33361
  1580
haftmann@33361
  1581
lemma self_quotient_aux1: "[| (0::int) < a; a = r + a*q; r < a |] ==> 1 \<le> q"
haftmann@33361
  1582
apply (subgoal_tac "0 < a*q")
haftmann@33361
  1583
 apply (simp add: zero_less_mult_iff, arith)
haftmann@33361
  1584
done
haftmann@33361
  1585
haftmann@33361
  1586
lemma self_quotient_aux2: "[| (0::int) < a; a = r + a*q; 0 \<le> r |] ==> q \<le> 1"
haftmann@33361
  1587
apply (subgoal_tac "0 \<le> a* (1-q) ")
haftmann@33361
  1588
 apply (simp add: zero_le_mult_iff)
haftmann@33361
  1589
apply (simp add: right_diff_distrib)
haftmann@33361
  1590
done
haftmann@33361
  1591
bulwahn@46552
  1592
lemma self_quotient: "[| divmod_int_rel a a (q, r) |] ==> q = 1"
haftmann@33361
  1593
apply (simp add: split_ifs divmod_int_rel_def linorder_neq_iff)
haftmann@33361
  1594
apply (rule order_antisym, safe, simp_all)
haftmann@33361
  1595
apply (rule_tac [3] a = "-a" and r = "-r" in self_quotient_aux1)
haftmann@33361
  1596
apply (rule_tac a = "-a" and r = "-r" in self_quotient_aux2)
haftmann@33361
  1597
apply (force intro: self_quotient_aux1 self_quotient_aux2 simp add: add_commute)+
haftmann@33361
  1598
done
haftmann@33361
  1599
bulwahn@46552
  1600
lemma self_remainder: "[| divmod_int_rel a a (q, r) |] ==> r = 0"
bulwahn@46552
  1601
apply (frule self_quotient)
haftmann@33361
  1602
apply (simp add: divmod_int_rel_def)
haftmann@33361
  1603
done
haftmann@33361
  1604
haftmann@33361
  1605
lemma zdiv_self [simp]: "a \<noteq> 0 ==> a div a = (1::int)"
haftmann@33361
  1606
by (simp add: divmod_int_rel_div_mod [THEN self_quotient])
haftmann@33361
  1607
haftmann@33361
  1608
(*Here we have 0 mod 0 = 0, also assumed by Knuth (who puts m mod 0 = 0) *)
haftmann@33361
  1609
lemma zmod_self [simp]: "a mod a = (0::int)"
haftmann@33361
  1610
apply (case_tac "a = 0", simp)
haftmann@33361
  1611
apply (simp add: divmod_int_rel_div_mod [THEN self_remainder])
haftmann@33361
  1612
done
haftmann@33361
  1613
haftmann@33361
  1614
huffman@46551
  1615
subsubsection {* Computation of Division and Remainder *}
haftmann@33361
  1616
haftmann@33361
  1617
lemma zdiv_zero [simp]: "(0::int) div b = 0"
haftmann@33361
  1618
by (simp add: div_int_def divmod_int_def)
haftmann@33361
  1619
haftmann@33361
  1620
lemma div_eq_minus1: "(0::int) < b ==> -1 div b = -1"
haftmann@33361
  1621
by (simp add: div_int_def divmod_int_def)
haftmann@33361
  1622
haftmann@33361
  1623
lemma zmod_zero [simp]: "(0::int) mod b = 0"
haftmann@33361
  1624
by (simp add: mod_int_def divmod_int_def)
haftmann@33361
  1625
haftmann@33361
  1626
lemma zmod_minus1: "(0::int) < b ==> -1 mod b = b - 1"
haftmann@33361
  1627
by (simp add: mod_int_def divmod_int_def)
haftmann@33361
  1628
haftmann@33361
  1629
text{*a positive, b positive *}
haftmann@33361
  1630
haftmann@33361
  1631
lemma div_pos_pos: "[| 0 < a;  0 \<le> b |] ==> a div b = fst (posDivAlg a b)"
haftmann@33361
  1632
by (simp add: div_int_def divmod_int_def)
haftmann@33361
  1633
haftmann@33361
  1634
lemma mod_pos_pos: "[| 0 < a;  0 \<le> b |] ==> a mod b = snd (posDivAlg a b)"
haftmann@33361
  1635
by (simp add: mod_int_def divmod_int_def)
haftmann@33361
  1636
haftmann@33361
  1637
text{*a negative, b positive *}
haftmann@33361
  1638
haftmann@33361
  1639
lemma div_neg_pos: "[| a < 0;  0 < b |] ==> a div b = fst (negDivAlg a b)"
haftmann@33361
  1640
by (simp add: div_int_def divmod_int_def)
haftmann@33361
  1641
haftmann@33361
  1642
lemma mod_neg_pos: "[| a < 0;  0 < b |] ==> a mod b = snd (negDivAlg a b)"
haftmann@33361
  1643
by (simp add: mod_int_def divmod_int_def)
haftmann@33361
  1644
haftmann@33361
  1645
text{*a positive, b negative *}
haftmann@33361
  1646
haftmann@33361
  1647
lemma div_pos_neg:
haftmann@33361
  1648
     "[| 0 < a;  b < 0 |] ==> a div b = fst (negateSnd (negDivAlg (-a) (-b)))"
haftmann@33361
  1649
by (simp add: div_int_def divmod_int_def)
haftmann@33361
  1650
haftmann@33361
  1651
lemma mod_pos_neg:
haftmann@33361
  1652
     "[| 0 < a;  b < 0 |] ==> a mod b = snd (negateSnd (negDivAlg (-a) (-b)))"
haftmann@33361
  1653
by (simp add: mod_int_def divmod_int_def)
haftmann@33361
  1654
haftmann@33361
  1655
text{*a negative, b negative *}
haftmann@33361
  1656
haftmann@33361
  1657
lemma div_neg_neg:
haftmann@33361
  1658
     "[| a < 0;  b \<le> 0 |] ==> a div b = fst (negateSnd (posDivAlg (-a) (-b)))"
haftmann@33361
  1659
by (simp add: div_int_def divmod_int_def)
haftmann@33361
  1660
haftmann@33361
  1661
lemma mod_neg_neg:
haftmann@33361
  1662
     "[| a < 0;  b \<le> 0 |] ==> a mod b = snd (negateSnd (posDivAlg (-a) (-b)))"
haftmann@33361
  1663
by (simp add: mod_int_def divmod_int_def)
haftmann@33361
  1664
haftmann@33361
  1665
text {*Simplify expresions in which div and mod combine numerical constants*}
haftmann@33361
  1666
huffman@45530
  1667
lemma int_div_pos_eq: "\<lbrakk>(a::int) = b * q + r; 0 \<le> r; r < b\<rbrakk> \<Longrightarrow> a div b = q"
bulwahn@46552
  1668
  by (rule divmod_int_rel_div [of a b q r]) (simp add: divmod_int_rel_def)
huffman@45530
  1669
huffman@45530
  1670
lemma int_div_neg_eq: "\<lbrakk>(a::int) = b * q + r; r \<le> 0; b < r\<rbrakk> \<Longrightarrow> a div b = q"
huffman@45530
  1671
  by (rule divmod_int_rel_div [of a b q r],
bulwahn@46552
  1672
    simp add: divmod_int_rel_def)
huffman@45530
  1673
huffman@45530
  1674
lemma int_mod_pos_eq: "\<lbrakk>(a::int) = b * q + r; 0 \<le> r; r < b\<rbrakk> \<Longrightarrow> a mod b = r"
huffman@45530
  1675
  by (rule divmod_int_rel_mod [of a b q r],
bulwahn@46552
  1676
    simp add: divmod_int_rel_def)
huffman@45530
  1677
huffman@45530
  1678
lemma int_mod_neg_eq: "\<lbrakk>(a::int) = b * q + r; r \<le> 0; b < r\<rbrakk> \<Longrightarrow> a mod b = r"
huffman@45530
  1679
  by (rule divmod_int_rel_mod [of a b q r],
bulwahn@46552
  1680
    simp add: divmod_int_rel_def)
huffman@45530
  1681
haftmann@33361
  1682
lemmas arithmetic_simps =
haftmann@33361
  1683
  arith_simps
haftmann@33361
  1684
  add_special
haftmann@35050
  1685
  add_0_left
haftmann@35050
  1686
  add_0_right
haftmann@33361
  1687
  mult_zero_left
haftmann@33361
  1688
  mult_zero_right
haftmann@33361
  1689
  mult_1_left
haftmann@33361
  1690
  mult_1_right
haftmann@33361
  1691
haftmann@33361
  1692
(* simprocs adapted from HOL/ex/Binary.thy *)
haftmann@33361
  1693
ML {*
haftmann@33361
  1694
local
huffman@45530
  1695
  val mk_number = HOLogic.mk_number HOLogic.intT
huffman@45530
  1696
  val plus = @{term "plus :: int \<Rightarrow> int \<Rightarrow> int"}
huffman@45530
  1697
  val times = @{term "times :: int \<Rightarrow> int \<Rightarrow> int"}
huffman@45530
  1698
  val zero = @{term "0 :: int"}
huffman@45530
  1699
  val less = @{term "op < :: int \<Rightarrow> int \<Rightarrow> bool"}
huffman@45530
  1700
  val le = @{term "op \<le> :: int \<Rightarrow> int \<Rightarrow> bool"}
huffman@45530
  1701
  val simps = @{thms arith_simps} @ @{thms rel_simps} @
huffman@45530
  1702
    map (fn th => th RS sym) [@{thm numeral_0_eq_0}, @{thm numeral_1_eq_1}]
huffman@45530
  1703
  fun prove ctxt goal = Goal.prove ctxt [] [] (HOLogic.mk_Trueprop goal)
huffman@45530
  1704
    (K (ALLGOALS (full_simp_tac (HOL_basic_ss addsimps simps))));
haftmann@33361
  1705
  fun binary_proc proc ss ct =
haftmann@33361
  1706
    (case Thm.term_of ct of
haftmann@33361
  1707
      _ $ t $ u =>
haftmann@33361
  1708
      (case try (pairself (`(snd o HOLogic.dest_number))) (t, u) of
haftmann@33361
  1709
        SOME args => proc (Simplifier.the_context ss) args
haftmann@33361
  1710
      | NONE => NONE)
haftmann@33361
  1711
    | _ => NONE);
haftmann@33361
  1712
in
huffman@45530
  1713
  fun divmod_proc posrule negrule =
huffman@45530
  1714
    binary_proc (fn ctxt => fn ((a, t), (b, u)) =>
huffman@45530
  1715
      if b = 0 then NONE else let
huffman@45530
  1716
        val (q, r) = pairself mk_number (Integer.div_mod a b)
huffman@45530
  1717
        val goal1 = HOLogic.mk_eq (t, plus $ (times $ u $ q) $ r)
huffman@45530
  1718
        val (goal2, goal3, rule) = if b > 0
huffman@45530
  1719
          then (le $ zero $ r, less $ r $ u, posrule RS eq_reflection)
huffman@45530
  1720
          else (le $ r $ zero, less $ u $ r, negrule RS eq_reflection)
huffman@45530
  1721
      in SOME (rule OF map (prove ctxt) [goal1, goal2, goal3]) end)
haftmann@33361
  1722
end
haftmann@33361
  1723
*}
haftmann@33361
  1724
haftmann@33361
  1725
simproc_setup binary_int_div ("number_of m div number_of n :: int") =
huffman@45530
  1726
  {* K (divmod_proc @{thm int_div_pos_eq} @{thm int_div_neg_eq}) *}
haftmann@33361
  1727
haftmann@33361
  1728
simproc_setup binary_int_mod ("number_of m mod number_of n :: int") =
huffman@45530
  1729
  {* K (divmod_proc @{thm int_mod_pos_eq} @{thm int_mod_neg_eq}) *}
haftmann@33361
  1730
wenzelm@45607
  1731
lemmas posDivAlg_eqn_number_of [simp] = posDivAlg_eqn [of "number_of v" "number_of w"] for v w
wenzelm@45607
  1732
lemmas negDivAlg_eqn_number_of [simp] = negDivAlg_eqn [of "number_of v" "number_of w"] for v w
haftmann@33361
  1733
haftmann@33361
  1734
haftmann@33361
  1735
text{*Special-case simplification *}
haftmann@33361
  1736
haftmann@33361
  1737
lemma zmod_minus1_right [simp]: "a mod (-1::int) = 0"
haftmann@33361
  1738
apply (cut_tac a = a and b = "-1" in neg_mod_sign)
haftmann@33361
  1739
apply (cut_tac [2] a = a and b = "-1" in neg_mod_bound)
haftmann@33361
  1740
apply (auto simp del: neg_mod_sign neg_mod_bound)
haftmann@33361
  1741
done
haftmann@33361
  1742
haftmann@33361
  1743
lemma zdiv_minus1_right [simp]: "a div (-1::int) = -a"
haftmann@33361
  1744
by (cut_tac a = a and b = "-1" in zmod_zdiv_equality, auto)
haftmann@33361
  1745
haftmann@33361
  1746
(** The last remaining special cases for constant arithmetic:
haftmann@33361
  1747
    1 div z and 1 mod z **)
haftmann@33361
  1748
wenzelm@45607
  1749
lemmas div_pos_pos_1_number_of [simp] = div_pos_pos [OF zero_less_one, of "number_of w"] for w
wenzelm@45607
  1750
lemmas div_pos_neg_1_number_of [simp] = div_pos_neg [OF zero_less_one, of "number_of w"] for w
wenzelm@45607
  1751
lemmas mod_pos_pos_1_number_of [simp] = mod_pos_pos [OF zero_less_one, of "number_of w"] for w
wenzelm@45607
  1752
lemmas mod_pos_neg_1_number_of [simp] = mod_pos_neg [OF zero_less_one, of "number_of w"] for w
wenzelm@45607
  1753
lemmas posDivAlg_eqn_1_number_of [simp] = posDivAlg_eqn [of concl: 1 "number_of w"] for w
wenzelm@45607
  1754
lemmas negDivAlg_eqn_1_number_of [simp] = negDivAlg_eqn [of concl: 1 "number_of w"] for w
haftmann@33361
  1755
haftmann@33361
  1756
huffman@46551
  1757
subsubsection {* Monotonicity in the First Argument (Dividend) *}
haftmann@33361
  1758
haftmann@33361
  1759
lemma zdiv_mono1: "[| a \<le> a';  0 < (b::int) |] ==> a div b \<le> a' div b"
haftmann@33361
  1760
apply (cut_tac a = a and b = b in zmod_zdiv_equality)
haftmann@33361
  1761
apply (cut_tac a = a' and b = b in zmod_zdiv_equality)
haftmann@33361
  1762
apply (rule unique_quotient_lemma)
haftmann@33361
  1763
apply (erule subst)
haftmann@33361
  1764
apply (erule subst, simp_all)
haftmann@33361
  1765
done
haftmann@33361
  1766
haftmann@33361
  1767
lemma zdiv_mono1_neg: "[| a \<le> a';  (b::int) < 0 |] ==> a' div b \<le> a div b"
haftmann@33361
  1768
apply (cut_tac a = a and b = b in zmod_zdiv_equality)
haftmann@33361
  1769
apply (cut_tac a = a' and b = b in zmod_zdiv_equality)
haftmann@33361
  1770
apply (rule unique_quotient_lemma_neg)
haftmann@33361
  1771
apply (erule subst)
haftmann@33361
  1772
apply (erule subst, simp_all)
haftmann@33361
  1773
done
haftmann@33361
  1774
haftmann@33361
  1775
huffman@46551
  1776
subsubsection {* Monotonicity in the Second Argument (Divisor) *}
haftmann@33361
  1777
haftmann@33361
  1778
lemma q_pos_lemma:
haftmann@33361
  1779
     "[| 0 \<le> b'*q' + r'; r' < b';  0 < b' |] ==> 0 \<le> (q'::int)"
haftmann@33361
  1780
apply (subgoal_tac "0 < b'* (q' + 1) ")
haftmann@33361
  1781
 apply (simp add: zero_less_mult_iff)
haftmann@33361
  1782
apply (simp add: right_distrib)
haftmann@33361
  1783
done
haftmann@33361
  1784
haftmann@33361
  1785
lemma zdiv_mono2_lemma:
haftmann@33361
  1786
     "[| b*q + r = b'*q' + r';  0 \<le> b'*q' + r';   
haftmann@33361
  1787
         r' < b';  0 \<le> r;  0 < b';  b' \<le> b |]   
haftmann@33361
  1788
      ==> q \<le> (q'::int)"
haftmann@33361
  1789
apply (frule q_pos_lemma, assumption+) 
haftmann@33361
  1790
apply (subgoal_tac "b*q < b* (q' + 1) ")
haftmann@33361
  1791
 apply (simp add: mult_less_cancel_left)
haftmann@33361
  1792
apply (subgoal_tac "b*q = r' - r + b'*q'")
haftmann@33361
  1793
 prefer 2 apply simp
haftmann@33361
  1794
apply (simp (no_asm_simp) add: right_distrib)
huffman@44766
  1795
apply (subst add_commute, rule add_less_le_mono, arith)
haftmann@33361
  1796
apply (rule mult_right_mono, auto)
haftmann@33361
  1797
done
haftmann@33361
  1798
haftmann@33361
  1799
lemma zdiv_mono2:
haftmann@33361
  1800
     "[| (0::int) \<le> a;  0 < b';  b' \<le> b |] ==> a div b \<le> a div b'"
haftmann@33361
  1801
apply (subgoal_tac "b \<noteq> 0")
haftmann@33361
  1802
 prefer 2 apply arith
haftmann@33361
  1803
apply (cut_tac a = a and b = b in zmod_zdiv_equality)
haftmann@33361
  1804
apply (cut_tac a = a and b = b' in zmod_zdiv_equality)
haftmann@33361
  1805
apply (rule zdiv_mono2_lemma)
haftmann@33361
  1806
apply (erule subst)
haftmann@33361
  1807
apply (erule subst, simp_all)
haftmann@33361
  1808
done
haftmann@33361
  1809
haftmann@33361
  1810
lemma q_neg_lemma:
haftmann@33361
  1811
     "[| b'*q' + r' < 0;  0 \<le> r';  0 < b' |] ==> q' \<le> (0::int)"
haftmann@33361
  1812
apply (subgoal_tac "b'*q' < 0")
haftmann@33361
  1813
 apply (simp add: mult_less_0_iff, arith)
haftmann@33361
  1814
done
haftmann@33361
  1815
haftmann@33361
  1816
lemma zdiv_mono2_neg_lemma:
haftmann@33361
  1817
     "[| b*q + r = b'*q' + r';  b'*q' + r' < 0;   
haftmann@33361
  1818
         r < b;  0 \<le> r';  0 < b';  b' \<le> b |]   
haftmann@33361
  1819
      ==> q' \<le> (q::int)"
haftmann@33361
  1820
apply (frule q_neg_lemma, assumption+) 
haftmann@33361
  1821
apply (subgoal_tac "b*q' < b* (q + 1) ")
haftmann@33361
  1822
 apply (simp add: mult_less_cancel_left)
haftmann@33361
  1823
apply (simp add: right_distrib)
haftmann@33361
  1824
apply (subgoal_tac "b*q' \<le> b'*q'")
haftmann@33361
  1825
 prefer 2 apply (simp add: mult_right_mono_neg, arith)
haftmann@33361
  1826
done
haftmann@33361
  1827
haftmann@33361
  1828
lemma zdiv_mono2_neg:
haftmann@33361
  1829
     "[| a < (0::int);  0 < b';  b' \<le> b |] ==> a div b' \<le> a div b"
haftmann@33361
  1830
apply (cut_tac a = a and b = b in zmod_zdiv_equality)
haftmann@33361
  1831
apply (cut_tac a = a and b = b' in zmod_zdiv_equality)
haftmann@33361
  1832
apply (rule zdiv_mono2_neg_lemma)
haftmann@33361
  1833
apply (erule subst)
haftmann@33361
  1834
apply (erule subst, simp_all)
haftmann@33361
  1835
done
haftmann@33361
  1836
haftmann@33361
  1837
huffman@46551
  1838
subsubsection {* More Algebraic Laws for div and mod *}
haftmann@33361
  1839
haftmann@33361
  1840
text{*proving (a*b) div c = a * (b div c) + a * (b mod c) *}
haftmann@33361
  1841
haftmann@33361
  1842
lemma zmult1_lemma:
bulwahn@46552
  1843
     "[| divmod_int_rel b c (q, r) |]  
haftmann@33361
  1844
      ==> divmod_int_rel (a * b) c (a*q + a*r div c, a*r mod c)"
haftmann@33361
  1845
by (auto simp add: split_ifs divmod_int_rel_def linorder_neq_iff right_distrib mult_ac)
haftmann@33361
  1846
haftmann@33361
  1847
lemma zdiv_zmult1_eq: "(a*b) div c = a*(b div c) + a*(b mod c) div (c::int)"
haftmann@33361
  1848
apply (case_tac "c = 0", simp)
haftmann@33361
  1849
apply (blast intro: divmod_int_rel_div_mod [THEN zmult1_lemma, THEN divmod_int_rel_div])
haftmann@33361
  1850
done
haftmann@33361
  1851
haftmann@33361
  1852
lemma zmod_zmult1_eq: "(a*b) mod c = a*(b mod c) mod (c::int)"
haftmann@33361
  1853
apply (case_tac "c = 0", simp)
haftmann@33361
  1854
apply (blast intro: divmod_int_rel_div_mod [THEN zmult1_lemma, THEN divmod_int_rel_mod])
haftmann@33361
  1855
done
haftmann@33361
  1856
haftmann@33361
  1857
lemma zmod_zdiv_trivial: "(a mod b) div b = (0::int)"
haftmann@33361
  1858
apply (case_tac "b = 0", simp)
haftmann@33361
  1859
apply (auto simp add: linorder_neq_iff div_pos_pos_trivial div_neg_neg_trivial)
haftmann@33361
  1860
done
haftmann@33361
  1861
haftmann@33361
  1862
text{*proving (a+b) div c = a div c + b div c + ((a mod c + b mod c) div c) *}
haftmann@33361
  1863
haftmann@33361
  1864
lemma zadd1_lemma:
bulwahn@46552
  1865
     "[| divmod_int_rel a c (aq, ar);  divmod_int_rel b c (bq, br) |]  
haftmann@33361
  1866
      ==> divmod_int_rel (a+b) c (aq + bq + (ar+br) div c, (ar+br) mod c)"
haftmann@33361
  1867
by (force simp add: split_ifs divmod_int_rel_def linorder_neq_iff right_distrib)
haftmann@33361
  1868
haftmann@33361
  1869
(*NOT suitable for rewriting: the RHS has an instance of the LHS*)
haftmann@33361
  1870
lemma zdiv_zadd1_eq:
haftmann@33361
  1871
     "(a+b) div (c::int) = a div c + b div c + ((a mod c + b mod c) div c)"
haftmann@33361
  1872
apply (case_tac "c = 0", simp)
haftmann@33361
  1873
apply (blast intro: zadd1_lemma [OF divmod_int_rel_div_mod divmod_int_rel_div_mod] divmod_int_rel_div)
haftmann@33361
  1874
done
haftmann@33361
  1875
haftmann@33361
  1876
instance int :: ring_div
haftmann@33361
  1877
proof
haftmann@33361
  1878
  fix a b c :: int
haftmann@33361
  1879
  assume not0: "b \<noteq> 0"
haftmann@33361
  1880
  show "(a + c * b) div b = c + a div b"
haftmann@33361
  1881
    unfolding zdiv_zadd1_eq [of a "c * b"] using not0 
haftmann@33361
  1882
      by (simp add: zmod_zmult1_eq zmod_zdiv_trivial zdiv_zmult1_eq)
haftmann@33361
  1883
next
haftmann@33361
  1884
  fix a b c :: int
haftmann@33361
  1885
  assume "a \<noteq> 0"
haftmann@33361
  1886
  then show "(a * b) div (a * c) = b div c"
haftmann@33361
  1887
  proof (cases "b \<noteq> 0 \<and> c \<noteq> 0")
haftmann@33361
  1888
    case False then show ?thesis by auto
haftmann@33361
  1889
  next
haftmann@33361
  1890
    case True then have "b \<noteq> 0" and "c \<noteq> 0" by auto
haftmann@33361
  1891
    with `a \<noteq> 0`
haftmann@33361
  1892
    have "\<And>q r. divmod_int_rel b c (q, r) \<Longrightarrow> divmod_int_rel (a * b) (a * c) (q, a * r)"
haftmann@33361
  1893
      apply (auto simp add: divmod_int_rel_def) 
haftmann@33361
  1894
      apply (auto simp add: algebra_simps)
haftmann@33361
  1895
      apply (auto simp add: zero_less_mult_iff zero_le_mult_iff mult_le_0_iff mult_commute [of a] mult_less_cancel_right)
haftmann@33361
  1896
      done
haftmann@33361
  1897
    moreover with `c \<noteq> 0` divmod_int_rel_div_mod have "divmod_int_rel b c (b div c, b mod c)" by auto
haftmann@33361
  1898
    ultimately have "divmod_int_rel (a * b) (a * c) (b div c, a * (b mod c))" .
bulwahn@46552
  1899
    from this show ?thesis by (rule divmod_int_rel_div)
haftmann@33361
  1900
  qed
haftmann@33361
  1901
qed auto
haftmann@33361
  1902
haftmann@33361
  1903
lemma posDivAlg_div_mod:
haftmann@33361
  1904
  assumes "k \<ge> 0"
haftmann@33361
  1905
  and "l \<ge> 0"
haftmann@33361
  1906
  shows "posDivAlg k l = (k div l, k mod l)"
haftmann@33361
  1907
proof (cases "l = 0")
haftmann@33361
  1908
  case True then show ?thesis by (simp add: posDivAlg.simps)
haftmann@33361
  1909
next
haftmann@33361
  1910
  case False with assms posDivAlg_correct
haftmann@33361
  1911
    have "divmod_int_rel k l (fst (posDivAlg k l), snd (posDivAlg k l))"
haftmann@33361
  1912
    by simp
bulwahn@46552
  1913
  from divmod_int_rel_div [OF this] divmod_int_rel_mod [OF this]
haftmann@33361
  1914
  show ?thesis by simp
haftmann@33361
  1915
qed
haftmann@33361
  1916
haftmann@33361
  1917
lemma negDivAlg_div_mod:
haftmann@33361
  1918
  assumes "k < 0"
haftmann@33361
  1919
  and "l > 0"
haftmann@33361
  1920
  shows "negDivAlg k l = (k div l, k mod l)"
haftmann@33361
  1921
proof -
haftmann@33361
  1922
  from assms have "l \<noteq> 0" by simp
haftmann@33361
  1923
  from assms negDivAlg_correct
haftmann@33361
  1924
    have "divmod_int_rel k l (fst (negDivAlg k l), snd (negDivAlg k l))"
haftmann@33361
  1925
    by simp
bulwahn@46552
  1926
  from divmod_int_rel_div [OF this] divmod_int_rel_mod [OF this]
haftmann@33361
  1927
  show ?thesis by simp
haftmann@33361
  1928
qed
haftmann@33361
  1929
haftmann@33361
  1930
lemma zmod_eq_0_iff: "(m mod d = 0) = (EX q::int. m = d*q)"
haftmann@33361
  1931
by (simp add: dvd_eq_mod_eq_0 [symmetric] dvd_def)
haftmann@33361
  1932
haftmann@33361
  1933
(* REVISIT: should this be generalized to all semiring_div types? *)
haftmann@33361
  1934
lemmas zmod_eq_0D [dest!] = zmod_eq_0_iff [THEN iffD1]
haftmann@33361
  1935
haftmann@33361
  1936
huffman@46551
  1937
subsubsection {* Proving  @{term "a div (b*c) = (a div b) div c"} *}
haftmann@33361
  1938
haftmann@33361
  1939
(*The condition c>0 seems necessary.  Consider that 7 div ~6 = ~2 but
haftmann@33361
  1940
  7 div 2 div ~3 = 3 div ~3 = ~1.  The subcase (a div b) mod c = 0 seems
haftmann@33361
  1941
  to cause particular problems.*)
haftmann@33361
  1942
haftmann@33361
  1943
text{*first, four lemmas to bound the remainder for the cases b<0 and b>0 *}
haftmann@33361
  1944
haftmann@33361
  1945
lemma zmult2_lemma_aux1: "[| (0::int) < c;  b < r;  r \<le> 0 |] ==> b*c < b*(q mod c) + r"
haftmann@33361
  1946
apply (subgoal_tac "b * (c - q mod c) < r * 1")
haftmann@33361
  1947
 apply (simp add: algebra_simps)
haftmann@33361
  1948
apply (rule order_le_less_trans)
haftmann@33361
  1949
 apply (erule_tac [2] mult_strict_right_mono)
haftmann@33361
  1950
 apply (rule mult_left_mono_neg)
huffman@35216
  1951
  using add1_zle_eq[of "q mod c"]apply(simp add: algebra_simps)
haftmann@33361
  1952
 apply (simp)
haftmann@33361
  1953
apply (simp)
haftmann@33361
  1954
done
haftmann@33361
  1955
haftmann@33361
  1956
lemma zmult2_lemma_aux2:
haftmann@33361
  1957
     "[| (0::int) < c;   b < r;  r \<le> 0 |] ==> b * (q mod c) + r \<le> 0"
haftmann@33361
  1958
apply (subgoal_tac "b * (q mod c) \<le> 0")
haftmann@33361
  1959
 apply arith
haftmann@33361
  1960
apply (simp add: mult_le_0_iff)
haftmann@33361
  1961
done
haftmann@33361
  1962
haftmann@33361
  1963
lemma zmult2_lemma_aux3: "[| (0::int) < c;  0 \<le> r;  r < b |] ==> 0 \<le> b * (q mod c) + r"
haftmann@33361
  1964
apply (subgoal_tac "0 \<le> b * (q mod c) ")
haftmann@33361
  1965
apply arith
haftmann@33361
  1966
apply (simp add: zero_le_mult_iff)
haftmann@33361
  1967
done
haftmann@33361
  1968
haftmann@33361
  1969
lemma zmult2_lemma_aux4: "[| (0::int) < c; 0 \<le> r; r < b |] ==> b * (q mod c) + r < b * c"
haftmann@33361
  1970
apply (subgoal_tac "r * 1 < b * (c - q mod c) ")
haftmann@33361
  1971
 apply (simp add: right_diff_distrib)
haftmann@33361
  1972
apply (rule order_less_le_trans)
haftmann@33361
  1973
 apply (erule mult_strict_right_mono)
haftmann@33361
  1974
 apply (rule_tac [2] mult_left_mono)
haftmann@33361
  1975
  apply simp
huffman@35216
  1976
 using add1_zle_eq[of "q mod c"] apply (simp add: algebra_simps)
haftmann@33361
  1977
apply simp
haftmann@33361
  1978
done
haftmann@33361
  1979
bulwahn@46552
  1980
lemma zmult2_lemma: "[| divmod_int_rel a b (q, r); 0 < c |]  
haftmann@33361
  1981
      ==> divmod_int_rel a (b * c) (q div c, b*(q mod c) + r)"
haftmann@33361
  1982
by (auto simp add: mult_ac divmod_int_rel_def linorder_neq_iff
haftmann@33361
  1983
                   zero_less_mult_iff right_distrib [symmetric] 
haftmann@33361
  1984
                   zmult2_lemma_aux1 zmult2_lemma_aux2 zmult2_lemma_aux3 zmult2_lemma_aux4)
haftmann@33361
  1985
haftmann@33361
  1986
lemma zdiv_zmult2_eq: "(0::int) < c ==> a div (b*c) = (a div b) div c"
haftmann@33361
  1987
apply (case_tac "b = 0", simp)
haftmann@33361
  1988
apply (force simp add: divmod_int_rel_div_mod [THEN zmult2_lemma, THEN divmod_int_rel_div])
haftmann@33361
  1989
done
haftmann@33361
  1990
haftmann@33361
  1991
lemma zmod_zmult2_eq:
haftmann@33361
  1992
     "(0::int) < c ==> a mod (b*c) = b*(a div b mod c) + a mod b"
haftmann@33361
  1993
apply (case_tac "b = 0", simp)
haftmann@33361
  1994
apply (force simp add: divmod_int_rel_div_mod [THEN zmult2_lemma, THEN divmod_int_rel_mod])
haftmann@33361
  1995
done
haftmann@33361
  1996
haftmann@33361
  1997
huffman@46551
  1998
subsubsection {* Splitting Rules for div and mod *}
haftmann@33361
  1999
haftmann@33361
  2000
text{*The proofs of the two lemmas below are essentially identical*}
haftmann@33361
  2001
haftmann@33361
  2002
lemma split_pos_lemma:
haftmann@33361
  2003
 "0<k ==> 
haftmann@33361
  2004
    P(n div k :: int)(n mod k) = (\<forall>i j. 0\<le>j & j<k & n = k*i + j --> P i j)"
haftmann@33361
  2005
apply (rule iffI, clarify)
haftmann@33361
  2006
 apply (erule_tac P="P ?x ?y" in rev_mp)  
haftmann@33361
  2007
 apply (subst mod_add_eq) 
haftmann@33361
  2008
 apply (subst zdiv_zadd1_eq) 
haftmann@33361
  2009
 apply (simp add: div_pos_pos_trivial mod_pos_pos_trivial)  
haftmann@33361
  2010
txt{*converse direction*}
haftmann@33361
  2011
apply (drule_tac x = "n div k" in spec) 
haftmann@33361
  2012
apply (drule_tac x = "n mod k" in spec, simp)
haftmann@33361
  2013
done
haftmann@33361
  2014
haftmann@33361
  2015
lemma split_neg_lemma:
haftmann@33361
  2016
 "k<0 ==>
haftmann@33361
  2017
    P(n div k :: int)(n mod k) = (\<forall>i j. k<j & j\<le>0 & n = k*i + j --> P i j)"
haftmann@33361
  2018
apply (rule iffI, clarify)
haftmann@33361
  2019
 apply (erule_tac P="P ?x ?y" in rev_mp)  
haftmann@33361
  2020
 apply (subst mod_add_eq) 
haftmann@33361
  2021
 apply (subst zdiv_zadd1_eq) 
haftmann@33361
  2022
 apply (simp add: div_neg_neg_trivial mod_neg_neg_trivial)  
haftmann@33361
  2023
txt{*converse direction*}
haftmann@33361
  2024
apply (drule_tac x = "n div k" in spec) 
haftmann@33361
  2025
apply (drule_tac x = "n mod k" in spec, simp)
haftmann@33361
  2026
done
haftmann@33361
  2027
haftmann@33361
  2028
lemma split_zdiv:
haftmann@33361
  2029
 "P(n div k :: int) =
haftmann@33361
  2030
  ((k = 0 --> P 0) & 
haftmann@33361
  2031
   (0<k --> (\<forall>i j. 0\<le>j & j<k & n = k*i + j --> P i)) & 
haftmann@33361
  2032
   (k<0 --> (\<forall>i j. k<j & j\<le>0 & n = k*i + j --> P i)))"
haftmann@33361
  2033
apply (case_tac "k=0", simp)
haftmann@33361
  2034
apply (simp only: linorder_neq_iff)
haftmann@33361
  2035
apply (erule disjE) 
haftmann@33361
  2036
 apply (simp_all add: split_pos_lemma [of concl: "%x y. P x"] 
haftmann@33361
  2037
                      split_neg_lemma [of concl: "%x y. P x"])
haftmann@33361
  2038
done
haftmann@33361
  2039
haftmann@33361
  2040
lemma split_zmod:
haftmann@33361
  2041
 "P(n mod k :: int) =
haftmann@33361
  2042
  ((k = 0 --> P n) & 
haftmann@33361
  2043
   (0<k --> (\<forall>i j. 0\<le>j & j<k & n = k*i + j --> P j)) & 
haftmann@33361
  2044
   (k<0 --> (\<forall>i j. k<j & j\<le>0 & n = k*i + j --> P j)))"
haftmann@33361
  2045
apply (case_tac "k=0", simp)
haftmann@33361
  2046
apply (simp only: linorder_neq_iff)
haftmann@33361
  2047
apply (erule disjE) 
haftmann@33361
  2048
 apply (simp_all add: split_pos_lemma [of concl: "%x y. P y"] 
haftmann@33361
  2049
                      split_neg_lemma [of concl: "%x y. P y"])
haftmann@33361
  2050
done
haftmann@33361
  2051
webertj@33730
  2052
text {* Enable (lin)arith to deal with @{const div} and @{const mod}
webertj@33730
  2053
  when these are applied to some constant that is of the form
webertj@33730
  2054
  @{term "number_of k"}: *}
wenzelm@45607
  2055
declare split_zdiv [of _ _ "number_of k", arith_split] for k
wenzelm@45607
  2056
declare split_zmod [of _ _ "number_of k", arith_split] for k
haftmann@33361
  2057
haftmann@33361
  2058
huffman@46551
  2059
subsubsection {* Speeding up the Division Algorithm with Shifting *}
haftmann@33361
  2060
haftmann@33361
  2061
text{*computing div by shifting *}
haftmann@33361
  2062
haftmann@33361
  2063
lemma pos_zdiv_mult_2: "(0::int) \<le> a ==> (1 + 2*b) div (2*a) = b div a"
haftmann@33361
  2064
proof cases
haftmann@33361
  2065
  assume "a=0"
haftmann@33361
  2066
    thus ?thesis by simp
haftmann@33361
  2067
next
haftmann@33361
  2068
  assume "a\<noteq>0" and le_a: "0\<le>a"   
haftmann@33361
  2069
  hence a_pos: "1 \<le> a" by arith
haftmann@33361
  2070
  hence one_less_a2: "1 < 2 * a" by arith
haftmann@33361
  2071
  hence le_2a: "2 * (1 + b mod a) \<le> 2 * a"
haftmann@33361
  2072
    unfolding mult_le_cancel_left
haftmann@33361
  2073
    by (simp add: add1_zle_eq add_commute [of 1])
haftmann@33361
  2074
  with a_pos have "0 \<le> b mod a" by simp
haftmann@33361
  2075
  hence le_addm: "0 \<le> 1 mod (2*a) + 2*(b mod a)"
haftmann@33361
  2076
    by (simp add: mod_pos_pos_trivial one_less_a2)
haftmann@33361
  2077
  with  le_2a
haftmann@33361
  2078
  have "(1 mod (2*a) + 2*(b mod a)) div (2*a) = 0"
haftmann@33361
  2079
    by (simp add: div_pos_pos_trivial le_addm mod_pos_pos_trivial one_less_a2
haftmann@33361
  2080
                  right_distrib) 
haftmann@33361
  2081
  thus ?thesis
haftmann@33361
  2082
    by (subst zdiv_zadd1_eq,
haftmann@33361
  2083
        simp add: mod_mult_mult1 one_less_a2
haftmann@33361
  2084
                  div_pos_pos_trivial)
haftmann@33361
  2085
qed
haftmann@33361
  2086
boehmes@35815
  2087
lemma neg_zdiv_mult_2: 
boehmes@35815
  2088
  assumes A: "a \<le> (0::int)" shows "(1 + 2*b) div (2*a) = (b+1) div a"
boehmes@35815
  2089
proof -
boehmes@35815
  2090
  have R: "1 + - (2 * (b + 1)) = - (1 + 2 * b)" by simp
boehmes@35815
  2091
  have "(1 + 2 * (-b - 1)) div (2 * (-a)) = (-b - 1) div (-a)"
boehmes@35815
  2092
    by (rule pos_zdiv_mult_2, simp add: A)
boehmes@35815
  2093
  thus ?thesis
boehmes@35815
  2094
    by (simp only: R zdiv_zminus_zminus diff_minus
boehmes@35815
  2095
      minus_add_distrib [symmetric] mult_minus_right)
boehmes@35815
  2096
qed
haftmann@33361
  2097
haftmann@33361
  2098
lemma zdiv_number_of_Bit0 [simp]:
haftmann@33361
  2099
     "number_of (Int.Bit0 v) div number_of (Int.Bit0 w) =  
haftmann@33361
  2100
          number_of v div (number_of w :: int)"
haftmann@33361
  2101
by (simp only: number_of_eq numeral_simps) (simp add: mult_2 [symmetric])
haftmann@33361
  2102
haftmann@33361
  2103
lemma zdiv_number_of_Bit1 [simp]:
haftmann@33361
  2104
     "number_of (Int.Bit1 v) div number_of (Int.Bit0 w) =  
haftmann@33361
  2105
          (if (0::int) \<le> number_of w                    
haftmann@33361
  2106
           then number_of v div (number_of w)     
haftmann@33361
  2107
           else (number_of v + (1::int)) div (number_of w))"
haftmann@33361
  2108
apply (simp only: number_of_eq numeral_simps UNIV_I split: split_if) 
haftmann@33361
  2109
apply (simp add: pos_zdiv_mult_2 neg_zdiv_mult_2 add_ac mult_2 [symmetric])
haftmann@33361
  2110
done
haftmann@33361
  2111
haftmann@33361
  2112
huffman@46551
  2113
subsubsection {* Computing mod by Shifting (proofs resemble those for div) *}
haftmann@33361
  2114
haftmann@33361
  2115
lemma pos_zmod_mult_2:
haftmann@33361
  2116
  fixes a b :: int
haftmann@33361
  2117
  assumes "0 \<le> a"
haftmann@33361
  2118
  shows "(1 + 2 * b) mod (2 * a) = 1 + 2 * (b mod a)"
haftmann@33361
  2119
proof (cases "0 < a")
haftmann@33361
  2120
  case False with assms show ?thesis by simp
haftmann@33361
  2121
next
haftmann@33361
  2122
  case True
haftmann@33361
  2123
  then have "b mod a < a" by (rule pos_mod_bound)
haftmann@33361
  2124
  then have "1 + b mod a \<le> a" by simp
haftmann@33361
  2125
  then have A: "2 * (1 + b mod a) \<le> 2 * a" by simp
haftmann@33361
  2126
  from `0 < a` have "0 \<le> b mod a" by (rule pos_mod_sign)
haftmann@33361
  2127
  then have B: "0 \<le> 1 + 2 * (b mod a)" by simp
haftmann@33361
  2128
  have "((1\<Colon>int) mod ((2\<Colon>int) * a) + (2\<Colon>int) * b mod ((2\<Colon>int) * a)) mod ((2\<Colon>int) * a) = (1\<Colon>int) + (2\<Colon>int) * (b mod a)"
haftmann@33361
  2129
    using `0 < a` and A
haftmann@33361
  2130
    by (auto simp add: mod_mult_mult1 mod_pos_pos_trivial ring_distribs intro!: mod_pos_pos_trivial B)
haftmann@33361
  2131
  then show ?thesis by (subst mod_add_eq)
haftmann@33361
  2132
qed
haftmann@33361
  2133
haftmann@33361
  2134
lemma neg_zmod_mult_2:
haftmann@33361
  2135
  fixes a b :: int
haftmann@33361
  2136
  assumes "a \<le> 0"
haftmann@33361
  2137
  shows "(1 + 2 * b) mod (2 * a) = 2 * ((b + 1) mod a) - 1"
haftmann@33361
  2138
proof -
haftmann@33361
  2139
  from assms have "0 \<le> - a" by auto
haftmann@33361
  2140
  then have "(1 + 2 * (- b - 1)) mod (2 * (- a)) = 1 + 2 * ((- b - 1) mod (- a))"
haftmann@33361
  2141
    by (rule pos_zmod_mult_2)
haftmann@33361
  2142
  then show ?thesis by (simp add: zmod_zminus2 algebra_simps)
haftmann@33361
  2143
     (simp add: diff_minus add_ac)
haftmann@33361
  2144
qed
haftmann@33361
  2145
haftmann@33361
  2146
lemma zmod_number_of_Bit0 [simp]:
haftmann@33361
  2147
     "number_of (Int.Bit0 v) mod number_of (Int.Bit0 w) =  
haftmann@33361
  2148
      (2::int) * (number_of v mod number_of w)"
haftmann@33361
  2149
apply (simp only: number_of_eq numeral_simps) 
haftmann@33361
  2150
apply (simp add: mod_mult_mult1 pos_zmod_mult_2 
haftmann@33361
  2151
                 neg_zmod_mult_2 add_ac mult_2 [symmetric])
haftmann@33361
  2152
done
haftmann@33361
  2153
haftmann@33361
  2154
lemma zmod_number_of_Bit1 [simp]:
haftmann@33361
  2155
     "number_of (Int.Bit1 v) mod number_of (Int.Bit0 w) =  
haftmann@33361
  2156
      (if (0::int) \<le> number_of w  
haftmann@33361
  2157
                then 2 * (number_of v mod number_of w) + 1     
haftmann@33361
  2158
                else 2 * ((number_of v + (1::int)) mod number_of w) - 1)"
haftmann@33361
  2159
apply (simp only: number_of_eq numeral_simps) 
haftmann@33361
  2160
apply (simp add: mod_mult_mult1 pos_zmod_mult_2 
haftmann@33361
  2161
                 neg_zmod_mult_2 add_ac mult_2 [symmetric])
haftmann@33361
  2162
done
haftmann@33361
  2163
haftmann@33361
  2164
nipkow@39489
  2165
lemma zdiv_eq_0_iff:
nipkow@39489
  2166
 "(i::int) div k = 0 \<longleftrightarrow> k=0 \<or> 0\<le>i \<and> i<k \<or> i\<le>0 \<and> k<i" (is "?L = ?R")
nipkow@39489
  2167
proof
nipkow@39489
  2168
  assume ?L
nipkow@39489
  2169
  have "?L \<longrightarrow> ?R" by (rule split_zdiv[THEN iffD2]) simp
nipkow@39489
  2170
  with `?L` show ?R by blast
nipkow@39489
  2171
next
nipkow@39489
  2172
  assume ?R thus ?L
nipkow@39489
  2173
    by(auto simp: div_pos_pos_trivial div_neg_neg_trivial)
nipkow@39489
  2174
qed
nipkow@39489
  2175
nipkow@39489
  2176
huffman@46551
  2177
subsubsection {* Quotients of Signs *}
haftmann@33361
  2178
haftmann@33361
  2179
lemma div_neg_pos_less0: "[| a < (0::int);  0 < b |] ==> a div b < 0"
haftmann@33361
  2180
apply (subgoal_tac "a div b \<le> -1", force)
haftmann@33361
  2181
apply (rule order_trans)
haftmann@33361
  2182
apply (rule_tac a' = "-1" in zdiv_mono1)
haftmann@33361
  2183
apply (auto simp add: div_eq_minus1)
haftmann@33361
  2184
done
haftmann@33361
  2185
haftmann@33361
  2186
lemma div_nonneg_neg_le0: "[| (0::int) \<le> a; b < 0 |] ==> a div b \<le> 0"
haftmann@33361
  2187
by (drule zdiv_mono1_neg, auto)
haftmann@33361
  2188
haftmann@33361
  2189
lemma div_nonpos_pos_le0: "[| (a::int) \<le> 0; b > 0 |] ==> a div b \<le> 0"
haftmann@33361
  2190
by (drule zdiv_mono1, auto)
haftmann@33361
  2191
nipkow@33804
  2192
text{* Now for some equivalences of the form @{text"a div b >=< 0 \<longleftrightarrow> \<dots>"}
nipkow@33804
  2193
conditional upon the sign of @{text a} or @{text b}. There are many more.
nipkow@33804
  2194
They should all be simp rules unless that causes too much search. *}
nipkow@33804
  2195
haftmann@33361
  2196
lemma pos_imp_zdiv_nonneg_iff: "(0::int) < b ==> (0 \<le> a div b) = (0 \<le> a)"
haftmann@33361
  2197
apply auto
haftmann@33361
  2198
apply (drule_tac [2] zdiv_mono1)
haftmann@33361
  2199
apply (auto simp add: linorder_neq_iff)
haftmann@33361
  2200
apply (simp (no_asm_use) add: linorder_not_less [symmetric])
haftmann@33361
  2201
apply (blast intro: div_neg_pos_less0)
haftmann@33361
  2202
done
haftmann@33361
  2203
haftmann@33361
  2204
lemma neg_imp_zdiv_nonneg_iff:
nipkow@33804
  2205
  "b < (0::int) ==> (0 \<le> a div b) = (a \<le> (0::int))"
haftmann@33361
  2206
apply (subst zdiv_zminus_zminus [symmetric])
haftmann@33361
  2207
apply (subst pos_imp_zdiv_nonneg_iff, auto)
haftmann@33361
  2208
done
haftmann@33361
  2209
haftmann@33361
  2210
(*But not (a div b \<le> 0 iff a\<le>0); consider a=1, b=2 when a div b = 0.*)
haftmann@33361
  2211
lemma pos_imp_zdiv_neg_iff: "(0::int) < b ==> (a div b < 0) = (a < 0)"
haftmann@33361
  2212
by (simp add: linorder_not_le [symmetric] pos_imp_zdiv_nonneg_iff)
haftmann@33361
  2213
nipkow@39489
  2214
lemma pos_imp_zdiv_pos_iff:
nipkow@39489
  2215
  "0<k \<Longrightarrow> 0 < (i::int) div k \<longleftrightarrow> k \<le> i"
nipkow@39489
  2216
using pos_imp_zdiv_nonneg_iff[of k i] zdiv_eq_0_iff[of i k]
nipkow@39489
  2217
by arith
nipkow@39489
  2218
haftmann@33361
  2219
(*Again the law fails for \<le>: consider a = -1, b = -2 when a div b = 0*)
haftmann@33361
  2220
lemma neg_imp_zdiv_neg_iff: "b < (0::int) ==> (a div b < 0) = (0 < a)"
haftmann@33361
  2221
by (simp add: linorder_not_le [symmetric] neg_imp_zdiv_nonneg_iff)
haftmann@33361
  2222
nipkow@33804
  2223
lemma nonneg1_imp_zdiv_pos_iff:
nipkow@33804
  2224
  "(0::int) <= a \<Longrightarrow> (a div b > 0) = (a >= b & b>0)"
nipkow@33804
  2225
apply rule
nipkow@33804
  2226
 apply rule
nipkow@33804
  2227
  using div_pos_pos_trivial[of a b]apply arith
nipkow@33804
  2228
 apply(cases "b=0")apply simp
nipkow@33804
  2229
 using div_nonneg_neg_le0[of a b]apply arith
nipkow@33804
  2230
using int_one_le_iff_zero_less[of "a div b"] zdiv_mono1[of b a b]apply simp
nipkow@33804
  2231
done
nipkow@33804
  2232
nipkow@39489
  2233
lemma zmod_le_nonneg_dividend: "(m::int) \<ge> 0 ==> m mod k \<le> m"
nipkow@39489
  2234
apply (rule split_zmod[THEN iffD2])
nipkow@44890
  2235
apply(fastforce dest: q_pos_lemma intro: split_mult_pos_le)
nipkow@39489
  2236
done
nipkow@39489
  2237
nipkow@39489
  2238
haftmann@33361
  2239
subsubsection {* The Divides Relation *}
haftmann@33361
  2240
haftmann@33361
  2241
lemmas zdvd_iff_zmod_eq_0_number_of [simp] =
wenzelm@45607
  2242
  dvd_eq_mod_eq_0 [of "number_of x" "number_of y"] for x y :: int
haftmann@33361
  2243
haftmann@33361
  2244
lemma zdvd_zmod: "f dvd m ==> f dvd (n::int) ==> f dvd m mod n"
haftmann@33361
  2245
  by (rule dvd_mod) (* TODO: remove *)
haftmann@33361
  2246
haftmann@33361
  2247
lemma zdvd_zmod_imp_zdvd: "k dvd m mod n ==> k dvd n ==> k dvd (m::int)"
haftmann@33361
  2248
  by (rule dvd_mod_imp_dvd) (* TODO: remove *)
haftmann@33361
  2249
haftmann@33361
  2250
lemma zmult_div_cancel: "(n::int) * (m div n) = m - (m mod n)"
haftmann@33361
  2251
  using zmod_zdiv_equality[where a="m" and b="n"]
haftmann@33361
  2252
  by (simp add: algebra_simps)
haftmann@33361
  2253
haftmann@33361
  2254
lemma zpower_zmod: "((x::int) mod m)^y mod m = x^y mod m"
haftmann@33361
  2255
apply (induct "y", auto)
haftmann@33361
  2256
apply (rule zmod_zmult1_eq [THEN trans])
haftmann@33361
  2257
apply (simp (no_asm_simp))
haftmann@33361
  2258
apply (rule mod_mult_eq [symmetric])
haftmann@33361
  2259
done
haftmann@33361
  2260
haftmann@33361
  2261
lemma zdiv_int: "int (a div b) = (int a) div (int b)"
haftmann@33361
  2262
apply (subst split_div, auto)
haftmann@33361
  2263
apply (subst split_zdiv, auto)
haftmann@33361
  2264
apply (rule_tac a="int (b * i) + int j" and b="int b" and r="int j" and r'=ja in unique_quotient)
haftmann@33361
  2265
apply (auto simp add: divmod_int_rel_def of_nat_mult)
haftmann@33361
  2266
done
haftmann@33361
  2267
haftmann@33361
  2268
lemma zmod_int: "int (a mod b) = (int a) mod (int b)"
haftmann@33361
  2269
apply (subst split_mod, auto)
haftmann@33361
  2270
apply (subst split_zmod, auto)
haftmann@33361
  2271
apply (rule_tac a="int (b * i) + int j" and b="int b" and q="int i" and q'=ia 
haftmann@33361
  2272
       in unique_remainder)
haftmann@33361
  2273
apply (auto simp add: divmod_int_rel_def of_nat_mult)
haftmann@33361
  2274
done
haftmann@33361
  2275
haftmann@33361
  2276
lemma abs_div: "(y::int) dvd x \<Longrightarrow> abs (x div y) = abs x div abs y"
haftmann@33361
  2277
by (unfold dvd_def, cases "y=0", auto simp add: abs_mult)
haftmann@33361
  2278
haftmann@33361
  2279
lemma zdvd_mult_div_cancel:"(n::int) dvd m \<Longrightarrow> n * (m div n) = m"
haftmann@33361
  2280
apply (subgoal_tac "m mod n = 0")
haftmann@33361
  2281
 apply (simp add: zmult_div_cancel)
haftmann@33361
  2282
apply (simp only: dvd_eq_mod_eq_0)
haftmann@33361
  2283
done
haftmann@33361
  2284
haftmann@33361
  2285
text{*Suggested by Matthias Daum*}
haftmann@33361
  2286
lemma int_power_div_base:
haftmann@33361
  2287
     "\<lbrakk>0 < m; 0 < k\<rbrakk> \<Longrightarrow> k ^ m div k = (k::int) ^ (m - Suc 0)"
haftmann@33361
  2288
apply (subgoal_tac "k ^ m = k ^ ((m - Suc 0) + Suc 0)")
haftmann@33361
  2289
 apply (erule ssubst)
haftmann@33361
  2290
 apply (simp only: power_add)
haftmann@33361
  2291
 apply simp_all
haftmann@33361
  2292
done
haftmann@33361
  2293
haftmann@33361
  2294
text {* by Brian Huffman *}
haftmann@33361
  2295
lemma zminus_zmod: "- ((x::int) mod m) mod m = - x mod m"
haftmann@33361
  2296
by (rule mod_minus_eq [symmetric])
haftmann@33361
  2297
haftmann@33361
  2298
lemma zdiff_zmod_left: "(x mod m - y) mod m = (x - y) mod (m::int)"
haftmann@33361
  2299
by (rule mod_diff_left_eq [symmetric])
haftmann@33361
  2300
haftmann@33361
  2301
lemma zdiff_zmod_right: "(x - y mod m) mod m = (x - y) mod (m::int)"
haftmann@33361
  2302
by (rule mod_diff_right_eq [symmetric])
haftmann@33361
  2303
haftmann@33361
  2304
lemmas zmod_simps =
haftmann@33361
  2305
  mod_add_left_eq  [symmetric]
haftmann@33361
  2306
  mod_add_right_eq [symmetric]
haftmann@33361
  2307
  zmod_zmult1_eq   [symmetric]
haftmann@33361
  2308
  mod_mult_left_eq [symmetric]
haftmann@33361
  2309
  zpower_zmod
haftmann@33361
  2310
  zminus_zmod zdiff_zmod_left zdiff_zmod_right
haftmann@33361
  2311
haftmann@33361
  2312
text {* Distributive laws for function @{text nat}. *}
haftmann@33361
  2313
haftmann@33361
  2314
lemma nat_div_distrib: "0 \<le> x \<Longrightarrow> nat (x div y) = nat x div nat y"
haftmann@33361
  2315
apply (rule linorder_cases [of y 0])
haftmann@33361
  2316
apply (simp add: div_nonneg_neg_le0)
haftmann@33361
  2317
apply simp
haftmann@33361
  2318
apply (simp add: nat_eq_iff pos_imp_zdiv_nonneg_iff zdiv_int)
haftmann@33361
  2319
done
haftmann@33361
  2320
haftmann@33361
  2321
(*Fails if y<0: the LHS collapses to (nat z) but the RHS doesn't*)
haftmann@33361
  2322
lemma nat_mod_distrib:
haftmann@33361
  2323
  "\<lbrakk>0 \<le> x; 0 \<le> y\<rbrakk> \<Longrightarrow> nat (x mod y) = nat x mod nat y"
haftmann@33361
  2324
apply (case_tac "y = 0", simp)
haftmann@33361
  2325
apply (simp add: nat_eq_iff zmod_int)
haftmann@33361
  2326
done
haftmann@33361
  2327
haftmann@33361
  2328
text  {* transfer setup *}
haftmann@33361
  2329
haftmann@33361
  2330
lemma transfer_nat_int_functions:
haftmann@33361
  2331
    "(x::int) >= 0 \<Longrightarrow> y >= 0 \<Longrightarrow> (nat x) div (nat y) = nat (x div y)"
haftmann@33361
  2332
    "(x::int) >= 0 \<Longrightarrow> y >= 0 \<Longrightarrow> (nat x) mod (nat y) = nat (x mod y)"
haftmann@33361
  2333
  by (auto simp add: nat_div_distrib nat_mod_distrib)
haftmann@33361
  2334
haftmann@33361
  2335
lemma transfer_nat_int_function_closures:
haftmann@33361
  2336
    "(x::int) >= 0 \<Longrightarrow> y >= 0 \<Longrightarrow> x div y >= 0"
haftmann@33361
  2337
    "(x::int) >= 0 \<Longrightarrow> y >= 0 \<Longrightarrow> x mod y >= 0"
haftmann@33361
  2338
  apply (cases "y = 0")
haftmann@33361
  2339
  apply (auto simp add: pos_imp_zdiv_nonneg_iff)
haftmann@33361
  2340
  apply (cases "y = 0")
haftmann@33361
  2341
  apply auto
haftmann@33361
  2342
done
haftmann@33361
  2343
haftmann@35644
  2344
declare transfer_morphism_nat_int [transfer add return:
haftmann@33361
  2345
  transfer_nat_int_functions
haftmann@33361
  2346
  transfer_nat_int_function_closures
haftmann@33361
  2347
]
haftmann@33361
  2348
haftmann@33361
  2349
lemma transfer_int_nat_functions:
haftmann@33361
  2350
    "(int x) div (int y) = int (x div y)"
haftmann@33361
  2351
    "(int x) mod (int y) = int (x mod y)"
haftmann@33361
  2352
  by (auto simp add: zdiv_int zmod_int)
haftmann@33361
  2353
haftmann@33361
  2354
lemma transfer_int_nat_function_closures:
haftmann@33361
  2355
    "is_nat x \<Longrightarrow> is_nat y \<Longrightarrow> is_nat (x div y)"
haftmann@33361
  2356
    "is_nat x \<Longrightarrow> is_nat y \<Longrightarrow> is_nat (x mod y)"
haftmann@33361
  2357
  by (simp_all only: is_nat_def transfer_nat_int_function_closures)
haftmann@33361
  2358
haftmann@35644
  2359
declare transfer_morphism_int_nat [transfer add return:
haftmann@33361
  2360
  transfer_int_nat_functions
haftmann@33361
  2361
  transfer_int_nat_function_closures
haftmann@33361
  2362
]
haftmann@33361
  2363
haftmann@33361
  2364
text{*Suggested by Matthias Daum*}
haftmann@33361
  2365
lemma int_div_less_self: "\<lbrakk>0 < x; 1 < k\<rbrakk> \<Longrightarrow> x div k < (x::int)"
haftmann@33361
  2366
apply (subgoal_tac "nat x div nat k < nat x")
nipkow@34225
  2367
 apply (simp add: nat_div_distrib [symmetric])
haftmann@33361
  2368
apply (rule Divides.div_less_dividend, simp_all)
haftmann@33361
  2369
done
haftmann@33361
  2370
haftmann@33361
  2371
lemma zmod_eq_dvd_iff: "(x::int) mod n = y mod n \<longleftrightarrow> n dvd x - y"
haftmann@33361
  2372
proof
haftmann@33361
  2373
  assume H: "x mod n = y mod n"
haftmann@33361
  2374
  hence "x mod n - y mod n = 0" by simp
haftmann@33361
  2375
  hence "(x mod n - y mod n) mod n = 0" by simp 
haftmann@33361
  2376
  hence "(x - y) mod n = 0" by (simp add: mod_diff_eq[symmetric])
haftmann@33361
  2377
  thus "n dvd x - y" by (simp add: dvd_eq_mod_eq_0)
haftmann@33361
  2378
next
haftmann@33361
  2379
  assume H: "n dvd x - y"
haftmann@33361
  2380
  then obtain k where k: "x-y = n*k" unfolding dvd_def by blast
haftmann@33361
  2381
  hence "x = n*k + y" by simp
haftmann@33361
  2382
  hence "x mod n = (n*k + y) mod n" by simp
haftmann@33361
  2383
  thus "x mod n = y mod n" by (simp add: mod_add_left_eq)
haftmann@33361
  2384
qed
haftmann@33361
  2385
haftmann@33361
  2386
lemma nat_mod_eq_lemma: assumes xyn: "(x::nat) mod n = y  mod n" and xy:"y \<le> x"
haftmann@33361
  2387
  shows "\<exists>q. x = y + n * q"
haftmann@33361
  2388
proof-
haftmann@33361
  2389
  from xy have th: "int x - int y = int (x - y)" by simp 
haftmann@33361
  2390
  from xyn have "int x mod int n = int y mod int n" 
huffman@46551
  2391
    by (simp add: zmod_int [symmetric])
haftmann@33361
  2392
  hence "int n dvd int x - int y" by (simp only: zmod_eq_dvd_iff[symmetric]) 
haftmann@33361
  2393
  hence "n dvd x - y" by (simp add: th zdvd_int)
haftmann@33361
  2394
  then show ?thesis using xy unfolding dvd_def apply clarsimp apply (rule_tac x="k" in exI) by arith
haftmann@33361
  2395
qed
haftmann@33361
  2396
haftmann@33361
  2397
lemma nat_mod_eq_iff: "(x::nat) mod n = y mod n \<longleftrightarrow> (\<exists>q1 q2. x + n * q1 = y + n * q2)" 
haftmann@33361
  2398
  (is "?lhs = ?rhs")
haftmann@33361
  2399
proof
haftmann@33361
  2400
  assume H: "x mod n = y mod n"
haftmann@33361
  2401
  {assume xy: "x \<le> y"
haftmann@33361
  2402
    from H have th: "y mod n = x mod n" by simp
haftmann@33361
  2403
    from nat_mod_eq_lemma[OF th xy] have ?rhs 
haftmann@33361
  2404
      apply clarify  apply (rule_tac x="q" in exI) by (rule exI[where x="0"], simp)}
haftmann@33361
  2405
  moreover
haftmann@33361
  2406
  {assume xy: "y \<le> x"
haftmann@33361
  2407
    from nat_mod_eq_lemma[OF H xy] have ?rhs 
haftmann@33361
  2408
      apply clarify  apply (rule_tac x="0" in exI) by (rule_tac x="q" in exI, simp)}
haftmann@33361
  2409
  ultimately  show ?rhs using linear[of x y] by blast  
haftmann@33361
  2410
next
haftmann@33361
  2411
  assume ?rhs then obtain q1 q2 where q12: "x + n * q1 = y + n * q2" by blast
haftmann@33361
  2412
  hence "(x + n * q1) mod n = (y + n * q2) mod n" by simp
haftmann@33361
  2413
  thus  ?lhs by simp
haftmann@33361
  2414
qed
haftmann@33361
  2415
haftmann@33361
  2416
lemma div_nat_number_of [simp]:
haftmann@33361
  2417
     "(number_of v :: nat)  div  number_of v' =  
haftmann@33361
  2418
          (if neg (number_of v :: int) then 0  
haftmann@33361
  2419
           else nat (number_of v div number_of v'))"
haftmann@33361
  2420
  unfolding nat_number_of_def number_of_is_id neg_def
haftmann@33361
  2421
  by (simp add: nat_div_distrib)
haftmann@33361
  2422
haftmann@33361
  2423
lemma one_div_nat_number_of [simp]:
haftmann@33361
  2424
     "Suc 0 div number_of v' = nat (1 div number_of v')" 
haftmann@46026
  2425
  by (simp del: semiring_numeral_1_eq_1 add: numeral_1_eq_Suc_0 [symmetric] semiring_numeral_1_eq_1 [symmetric]) 
haftmann@33361
  2426
haftmann@33361
  2427
lemma mod_nat_number_of [simp]:
haftmann@33361
  2428
     "(number_of v :: nat)  mod  number_of v' =  
haftmann@33361
  2429
        (if neg (number_of v :: int) then 0  
haftmann@33361
  2430
         else if neg (number_of v' :: int) then number_of v  
haftmann@33361
  2431
         else nat (number_of v mod number_of v'))"
haftmann@33361
  2432
  unfolding nat_number_of_def number_of_is_id neg_def
haftmann@33361
  2433
  by (simp add: nat_mod_distrib)
haftmann@33361
  2434
haftmann@33361
  2435
lemma one_mod_nat_number_of [simp]:
haftmann@33361
  2436
     "Suc 0 mod number_of v' =  
haftmann@33361
  2437
        (if neg (number_of v' :: int) then Suc 0
haftmann@33361
  2438
         else nat (1 mod number_of v'))"
haftmann@46026
  2439
by (simp del: semiring_numeral_1_eq_1 add: numeral_1_eq_Suc_0 [symmetric] semiring_numeral_1_eq_1 [symmetric]) 
haftmann@33361
  2440
wenzelm@45607
  2441
lemmas dvd_eq_mod_eq_0_number_of [simp] =
wenzelm@45607
  2442
  dvd_eq_mod_eq_0 [of "number_of x" "number_of y"] for x y
haftmann@33361
  2443
haftmann@33361
  2444
blanchet@34126
  2445
subsubsection {* Nitpick *}
blanchet@34126
  2446
blanchet@34126
  2447
lemma zmod_zdiv_equality':
blanchet@34126
  2448
"(m\<Colon>int) mod n = m - (m div n) * n"
blanchet@34126
  2449
by (rule_tac P="%x. m mod n = x - (m div n) * n"
blanchet@34126
  2450
    in subst [OF mod_div_equality [of _ n]])
blanchet@34126
  2451
   arith
blanchet@34126
  2452
blanchet@41792
  2453
lemmas [nitpick_unfold] = dvd_eq_mod_eq_0 mod_div_equality' zmod_zdiv_equality'
blanchet@34126
  2454
haftmann@35673
  2455
haftmann@33361
  2456
subsubsection {* Code generation *}
haftmann@33361
  2457
haftmann@33361
  2458
definition pdivmod :: "int \<Rightarrow> int \<Rightarrow> int \<times> int" where
haftmann@33361
  2459
  "pdivmod k l = (\<bar>k\<bar> div \<bar>l\<bar>, \<bar>k\<bar> mod \<bar>l\<bar>)"
haftmann@33361
  2460
haftmann@33361
  2461
lemma pdivmod_posDivAlg [code]:
haftmann@33361
  2462
  "pdivmod k l = (if l = 0 then (0, \<bar>k\<bar>) else posDivAlg \<bar>k\<bar> \<bar>l\<bar>)"
haftmann@33361
  2463
by (subst posDivAlg_div_mod) (simp_all add: pdivmod_def)
haftmann@33361
  2464
haftmann@33361
  2465
lemma divmod_int_pdivmod: "divmod_int k l = (if k = 0 then (0, 0) else if l = 0 then (0, k) else
haftmann@33361
  2466
  apsnd ((op *) (sgn l)) (if 0 < l \<and> 0 \<le> k \<or> l < 0 \<and> k < 0
haftmann@33361
  2467
    then pdivmod k l
haftmann@33361
  2468
    else (let (r, s) = pdivmod k l in
haftmann@33361
  2469
      if s = 0 then (- r, 0) else (- r - 1, \<bar>l\<bar> - s))))"
haftmann@33361
  2470
proof -
haftmann@33361
  2471
  have aux: "\<And>q::int. - k = l * q \<longleftrightarrow> k = l * - q" by auto
haftmann@33361
  2472
  show ?thesis
haftmann@33361
  2473
    by (simp add: divmod_int_mod_div pdivmod_def)
haftmann@33361
  2474
      (auto simp add: aux not_less not_le zdiv_zminus1_eq_if
haftmann@33361
  2475
      zmod_zminus1_eq_if zdiv_zminus2_eq_if zmod_zminus2_eq_if)
haftmann@33361
  2476
qed
haftmann@33361
  2477
haftmann@33361
  2478
lemma divmod_int_code [code]: "divmod_int k l = (if k = 0 then (0, 0) else if l = 0 then (0, k) else
haftmann@33361
  2479
  apsnd ((op *) (sgn l)) (if sgn k = sgn l
haftmann@33361
  2480
    then pdivmod k l
haftmann@33361
  2481
    else (let (r, s) = pdivmod k l in
haftmann@33361
  2482
      if s = 0 then (- r, 0) else (- r - 1, \<bar>l\<bar> - s))))"
haftmann@33361
  2483
proof -
haftmann@33361
  2484
  have "k \<noteq> 0 \<Longrightarrow> l \<noteq> 0 \<Longrightarrow> 0 < l \<and> 0 \<le> k \<or> l < 0 \<and> k < 0 \<longleftrightarrow> sgn k = sgn l"
haftmann@33361
  2485
    by (auto simp add: not_less sgn_if)
haftmann@33361
  2486
  then show ?thesis by (simp add: divmod_int_pdivmod)
haftmann@33361
  2487
qed
haftmann@33361
  2488
haftmann@35673
  2489
context ring_1
haftmann@35673
  2490
begin
haftmann@35673
  2491
haftmann@35673
  2492
lemma of_int_num [code]:
haftmann@35673
  2493
  "of_int k = (if k = 0 then 0 else if k < 0 then
haftmann@35673
  2494
     - of_int (- k) else let
haftmann@35673
  2495
       (l, m) = divmod_int k 2;
haftmann@35673
  2496
       l' = of_int l
haftmann@35673
  2497
     in if m = 0 then l' + l' else l' + l' + 1)"
haftmann@35673
  2498
proof -
haftmann@35673
  2499
  have aux1: "k mod (2\<Colon>int) \<noteq> (0\<Colon>int) \<Longrightarrow> 
haftmann@35673
  2500
    of_int k = of_int (k div 2 * 2 + 1)"