src/HOL/Number_Theory/Cong.thy
 author haftmann Sun, 09 Nov 2014 10:03:18 +0100 changeset 58954 18750e86d5b8 parent 58937 49e8115f70d8 child 59010 ec2b4270a502 permissions -rw-r--r--
reverted 1ebf0a1f12a4 after successful re-tuning of simp rules for divisibility
```
(*  Title:      HOL/Number_Theory/Cong.thy
Authors:    Christophe Tabacznyj, Lawrence C. Paulson, Amine Chaieb,

Defines congruence (notation: [x = y] (mod z)) for natural numbers and
integers.

This file combines and revises a number of prior developments.

The original theories "GCD" and "Primes" were by Christophe Tabacznyj
and Lawrence C. Paulson, based on @{cite davenport92}. They introduced
gcd, lcm, and prime for the natural numbers.

The original theory "IntPrimes" was by Thomas M. Rasmussen, and
extended gcd, lcm, primes to the integers. Amine Chaieb provided
another extension of the notions to the integers, and added a number
of results to "Primes" and "GCD".

The original theory, "IntPrimes", by Thomas M. Rasmussen, defined and
developed the congruence relations on the integers. The notion was
extended to the natural numbers by Chaieb. Jeremy Avigad combined
these, revised and tidied them, made the development uniform for the
natural numbers and the integers, and added a number of new theorems.
*)

section {* Congruence *}

theory Cong
imports Primes
begin

subsection {* Turn off @{text One_nat_def} *}

lemma power_eq_one_eq_nat [simp]: "((x::nat)^m = 1) = (m = 0 | x = 1)"
by (induct m) auto

declare mod_pos_pos_trivial [simp]

subsection {* Main definitions *}

class cong =
fixes cong :: "'a \<Rightarrow> 'a \<Rightarrow> 'a \<Rightarrow> bool" ("(1[_ = _] '(()mod _'))")
begin

abbreviation notcong :: "'a \<Rightarrow> 'a \<Rightarrow> 'a \<Rightarrow> bool"  ("(1[_ \<noteq> _] '(()mod _'))")
where "notcong x y m \<equiv> \<not> cong x y m"

end

(* definitions for the natural numbers *)

instantiation nat :: cong
begin

definition cong_nat :: "nat \<Rightarrow> nat \<Rightarrow> nat \<Rightarrow> bool"
where "cong_nat x y m = ((x mod m) = (y mod m))"

instance ..

end

(* definitions for the integers *)

instantiation int :: cong
begin

definition cong_int :: "int \<Rightarrow> int \<Rightarrow> int \<Rightarrow> bool"
where "cong_int x y m = ((x mod m) = (y mod m))"

instance ..

end

subsection {* Set up Transfer *}

lemma transfer_nat_int_cong:
"(x::int) >= 0 \<Longrightarrow> y >= 0 \<Longrightarrow> m >= 0 \<Longrightarrow>
([(nat x) = (nat y)] (mod (nat m))) = ([x = y] (mod m))"
unfolding cong_int_def cong_nat_def
by (metis Divides.transfer_int_nat_functions(2) nat_0_le nat_mod_distrib)

transfer_nat_int_cong]

lemma transfer_int_nat_cong:
"[(int x) = (int y)] (mod (int m)) = [x = y] (mod m)"
apply (auto simp add: cong_int_def cong_nat_def)
apply (auto simp add: zmod_int [symmetric])
done

transfer_int_nat_cong]

subsection {* Congruence *}

(* was zcong_0, etc. *)
lemma cong_0_nat [simp, presburger]: "([(a::nat) = b] (mod 0)) = (a = b)"
unfolding cong_nat_def by auto

lemma cong_0_int [simp, presburger]: "([(a::int) = b] (mod 0)) = (a = b)"
unfolding cong_int_def by auto

lemma cong_1_nat [simp, presburger]: "[(a::nat) = b] (mod 1)"
unfolding cong_nat_def by auto

lemma cong_Suc_0_nat [simp, presburger]: "[(a::nat) = b] (mod Suc 0)"
unfolding cong_nat_def by auto

lemma cong_1_int [simp, presburger]: "[(a::int) = b] (mod 1)"
unfolding cong_int_def by auto

lemma cong_refl_nat [simp]: "[(k::nat) = k] (mod m)"
unfolding cong_nat_def by auto

lemma cong_refl_int [simp]: "[(k::int) = k] (mod m)"
unfolding cong_int_def by auto

lemma cong_sym_nat: "[(a::nat) = b] (mod m) \<Longrightarrow> [b = a] (mod m)"
unfolding cong_nat_def by auto

lemma cong_sym_int: "[(a::int) = b] (mod m) \<Longrightarrow> [b = a] (mod m)"
unfolding cong_int_def by auto

lemma cong_sym_eq_nat: "[(a::nat) = b] (mod m) = [b = a] (mod m)"
unfolding cong_nat_def by auto

lemma cong_sym_eq_int: "[(a::int) = b] (mod m) = [b = a] (mod m)"
unfolding cong_int_def by auto

lemma cong_trans_nat [trans]:
"[(a::nat) = b] (mod m) \<Longrightarrow> [b = c] (mod m) \<Longrightarrow> [a = c] (mod m)"
unfolding cong_nat_def by auto

lemma cong_trans_int [trans]:
"[(a::int) = b] (mod m) \<Longrightarrow> [b = c] (mod m) \<Longrightarrow> [a = c] (mod m)"
unfolding cong_int_def by auto

"[(a::nat) = b] (mod m) \<Longrightarrow> [c = d] (mod m) \<Longrightarrow> [a + c = b + d] (mod m)"

"[(a::int) = b] (mod m) \<Longrightarrow> [c = d] (mod m) \<Longrightarrow> [a + c = b + d] (mod m)"

lemma cong_diff_int:
"[(a::int) = b] (mod m) \<Longrightarrow> [c = d] (mod m) \<Longrightarrow> [a - c = b - d] (mod m)"
unfolding cong_int_def  by (metis mod_diff_cong)

lemma cong_diff_aux_int:
"[(a::int) = b] (mod m) \<Longrightarrow> [c = d] (mod m) \<Longrightarrow>
(a::int) >= c \<Longrightarrow> b >= d \<Longrightarrow> [tsub a c = tsub b d] (mod m)"
by (metis cong_diff_int tsub_eq)

lemma cong_diff_nat:
assumes"[a = b] (mod m)" "[c = d] (mod m)" "(a::nat) >= c" "b >= d"
shows "[a - c = b - d] (mod m)"
using assms by (rule cong_diff_aux_int [transferred])

lemma cong_mult_nat:
"[(a::nat) = b] (mod m) \<Longrightarrow> [c = d] (mod m) \<Longrightarrow> [a * c = b * d] (mod m)"
unfolding cong_nat_def  by (metis mod_mult_cong)

lemma cong_mult_int:
"[(a::int) = b] (mod m) \<Longrightarrow> [c = d] (mod m) \<Longrightarrow> [a * c = b * d] (mod m)"
unfolding cong_int_def  by (metis mod_mult_cong)

lemma cong_exp_nat: "[(x::nat) = y] (mod n) \<Longrightarrow> [x^k = y^k] (mod n)"
by (induct k) (auto simp add: cong_mult_nat)

lemma cong_exp_int: "[(x::int) = y] (mod n) \<Longrightarrow> [x^k = y^k] (mod n)"
by (induct k) (auto simp add: cong_mult_int)

lemma cong_setsum_nat [rule_format]:
"(ALL x: A. [((f x)::nat) = g x] (mod m)) \<longrightarrow>
[(SUM x:A. f x) = (SUM x:A. g x)] (mod m)"
apply (cases "finite A")
apply (induct set: finite)
done

lemma cong_setsum_int [rule_format]:
"(ALL x: A. [((f x)::int) = g x] (mod m)) \<longrightarrow>
[(SUM x:A. f x) = (SUM x:A. g x)] (mod m)"
apply (cases "finite A")
apply (induct set: finite)
done

lemma cong_setprod_nat [rule_format]:
"(ALL x: A. [((f x)::nat) = g x] (mod m)) \<longrightarrow>
[(PROD x:A. f x) = (PROD x:A. g x)] (mod m)"
apply (cases "finite A")
apply (induct set: finite)
apply (auto intro: cong_mult_nat)
done

lemma cong_setprod_int [rule_format]:
"(ALL x: A. [((f x)::int) = g x] (mod m)) \<longrightarrow>
[(PROD x:A. f x) = (PROD x:A. g x)] (mod m)"
apply (cases "finite A")
apply (induct set: finite)
apply (auto intro: cong_mult_int)
done

lemma cong_scalar_nat: "[(a::nat)= b] (mod m) \<Longrightarrow> [a * k = b * k] (mod m)"
by (rule cong_mult_nat) simp_all

lemma cong_scalar_int: "[(a::int)= b] (mod m) \<Longrightarrow> [a * k = b * k] (mod m)"
by (rule cong_mult_int) simp_all

lemma cong_scalar2_nat: "[(a::nat)= b] (mod m) \<Longrightarrow> [k * a = k * b] (mod m)"
by (rule cong_mult_nat) simp_all

lemma cong_scalar2_int: "[(a::int)= b] (mod m) \<Longrightarrow> [k * a = k * b] (mod m)"
by (rule cong_mult_int) simp_all

lemma cong_mult_self_nat: "[(a::nat) * m = 0] (mod m)"
unfolding cong_nat_def by auto

lemma cong_mult_self_int: "[(a::int) * m = 0] (mod m)"
unfolding cong_int_def by auto

lemma cong_eq_diff_cong_0_int: "[(a::int) = b] (mod m) = [a - b = 0] (mod m)"

lemma cong_eq_diff_cong_0_aux_int: "a >= b \<Longrightarrow>
[(a::int) = b] (mod m) = [tsub a b = 0] (mod m)"
by (subst tsub_eq, assumption, rule cong_eq_diff_cong_0_int)

lemma cong_eq_diff_cong_0_nat:
assumes "(a::nat) >= b"
shows "[a = b] (mod m) = [a - b = 0] (mod m)"
using assms by (rule cong_eq_diff_cong_0_aux_int [transferred])

lemma cong_diff_cong_0'_nat:
"[(x::nat) = y] (mod n) \<longleftrightarrow>
(if x <= y then [y - x = 0] (mod n) else [x - y = 0] (mod n))"
by (metis cong_eq_diff_cong_0_nat cong_sym_nat nat_le_linear)

lemma cong_altdef_nat: "(a::nat) >= b \<Longrightarrow> [a = b] (mod m) = (m dvd (a - b))"
apply (subst cong_eq_diff_cong_0_nat, assumption)
apply (unfold cong_nat_def)
done

lemma cong_altdef_int: "[(a::int) = b] (mod m) = (m dvd (a - b))"
by (metis cong_int_def zmod_eq_dvd_iff)

lemma cong_abs_int: "[(x::int) = y] (mod abs m) = [x = y] (mod m)"

lemma cong_square_int:
fixes a::int
shows "\<lbrakk> prime p; 0 < a; [a * a = 1] (mod p) \<rbrakk>
\<Longrightarrow> [a = 1] (mod p) \<or> [a = - 1] (mod p)"
apply (simp only: cong_altdef_int)
apply (subst prime_dvd_mult_eq_int [symmetric], assumption)
done

lemma cong_mult_rcancel_int:
"coprime k (m::int) \<Longrightarrow> [a * k = b * k] (mod m) = [a = b] (mod m)"
by (metis cong_altdef_int left_diff_distrib coprime_dvd_mult_iff_int gcd_int.commute)

lemma cong_mult_rcancel_nat:
"coprime k (m::nat) \<Longrightarrow> [a * k = b * k] (mod m) = [a = b] (mod m)"
by (metis cong_mult_rcancel_int [transferred])

lemma cong_mult_lcancel_nat:
"coprime k (m::nat) \<Longrightarrow> [k * a = k * b ] (mod m) = [a = b] (mod m)"

lemma cong_mult_lcancel_int:
"coprime k (m::int) \<Longrightarrow> [k * a = k * b] (mod m) = [a = b] (mod m)"

(* was zcong_zgcd_zmult_zmod *)
lemma coprime_cong_mult_int:
"[(a::int) = b] (mod m) \<Longrightarrow> [a = b] (mod n) \<Longrightarrow> coprime m n
\<Longrightarrow> [a = b] (mod m * n)"
by (metis divides_mult_int cong_altdef_int)

lemma coprime_cong_mult_nat:
assumes "[(a::nat) = b] (mod m)" and "[a = b] (mod n)" and "coprime m n"
shows "[a = b] (mod m * n)"
by (metis assms coprime_cong_mult_int [transferred])

lemma cong_less_imp_eq_nat: "0 \<le> (a::nat) \<Longrightarrow>
a < m \<Longrightarrow> 0 \<le> b \<Longrightarrow> b < m \<Longrightarrow> [a = b] (mod m) \<Longrightarrow> a = b"

lemma cong_less_imp_eq_int: "0 \<le> (a::int) \<Longrightarrow>
a < m \<Longrightarrow> 0 \<le> b \<Longrightarrow> b < m \<Longrightarrow> [a = b] (mod m) \<Longrightarrow> a = b"

lemma cong_less_unique_nat:
"0 < (m::nat) \<Longrightarrow> (\<exists>!b. 0 \<le> b \<and> b < m \<and> [a = b] (mod m))"
by (auto simp: cong_nat_def) (metis mod_less_divisor mod_mod_trivial)

lemma cong_less_unique_int:
"0 < (m::int) \<Longrightarrow> (\<exists>!b. 0 \<le> b \<and> b < m \<and> [a = b] (mod m))"
by (auto simp: cong_int_def)  (metis mod_mod_trivial pos_mod_conj)

lemma cong_iff_lin_int: "([(a::int) = b] (mod m)) = (\<exists>k. b = a + m * k)"
apply (auto simp add: cong_altdef_int dvd_def)
apply (rule_tac [!] x = "-k" in exI, auto)
done

lemma cong_iff_lin_nat:
"([(a::nat) = b] (mod m)) \<longleftrightarrow> (\<exists>k1 k2. b + k1 * m = a + k2 * m)" (is "?lhs = ?rhs")
proof (rule iffI)
assume eqm: ?lhs
show ?rhs
proof (cases "b \<le> a")
case True
then show ?rhs using eqm
next
case False
then show ?rhs using eqm
apply (subst (asm) cong_sym_eq_nat)
apply (auto simp: cong_altdef_nat)
done
qed
next
assume ?rhs
then show ?lhs
by (metis cong_nat_def mod_mult_self2 mult.commute)
qed

lemma cong_gcd_eq_int: "[(a::int) = b] (mod m) \<Longrightarrow> gcd a m = gcd b m"
by (metis cong_int_def gcd_red_int)

lemma cong_gcd_eq_nat:
"[(a::nat) = b] (mod m) \<Longrightarrow>gcd a m = gcd b m"
by (metis assms cong_gcd_eq_int [transferred])

lemma cong_imp_coprime_nat: "[(a::nat) = b] (mod m) \<Longrightarrow> coprime a m \<Longrightarrow> coprime b m"

lemma cong_imp_coprime_int: "[(a::int) = b] (mod m) \<Longrightarrow> coprime a m \<Longrightarrow> coprime b m"

lemma cong_cong_mod_nat: "[(a::nat) = b] (mod m) = [a mod m = b mod m] (mod m)"

lemma cong_cong_mod_int: "[(a::int) = b] (mod m) = [a mod m = b mod m] (mod m)"

lemma cong_minus_int [iff]: "[(a::int) = b] (mod -m) = [a = b] (mod m)"
by (metis cong_iff_lin_int minus_equation_iff mult_minus_left mult_minus_right)

(*
lemma mod_dvd_mod_int:
"0 < (m::int) \<Longrightarrow> m dvd b \<Longrightarrow> (a mod b mod m) = (a mod m)"
apply (unfold dvd_def, auto)
apply (rule mod_mod_cancel)
apply auto
done

lemma mod_dvd_mod:
assumes "0 < (m::nat)" and "m dvd b"
shows "(a mod b mod m) = (a mod m)"

apply (rule mod_dvd_mod_int [transferred])
using assms apply auto
done
*)

"[(a::nat) + x = a + y] (mod n) \<longleftrightarrow> [x = y] (mod n)"

"[(a::int) + x = a + y] (mod n) \<longleftrightarrow> [x = y] (mod n)"

lemma cong_add_rcancel_nat: "[(x::nat) + a = y + a] (mod n) \<longleftrightarrow> [x = y] (mod n)"

lemma cong_add_rcancel_int: "[(x::int) + a = y + a] (mod n) \<longleftrightarrow> [x = y] (mod n)"

lemma cong_add_lcancel_0_nat: "[(a::nat) + x = a] (mod n) \<longleftrightarrow> [x = 0] (mod n)"

lemma cong_add_lcancel_0_int: "[(a::int) + x = a] (mod n) \<longleftrightarrow> [x = 0] (mod n)"

lemma cong_add_rcancel_0_nat: "[x + (a::nat) = a] (mod n) \<longleftrightarrow> [x = 0] (mod n)"

lemma cong_add_rcancel_0_int: "[x + (a::int) = a] (mod n) \<longleftrightarrow> [x = 0] (mod n)"

lemma cong_dvd_modulus_nat: "[(x::nat) = y] (mod m) \<Longrightarrow> n dvd m \<Longrightarrow>
[x = y] (mod n)"
apply (auto simp add: cong_iff_lin_nat dvd_def)
apply (rule_tac x="k1 * k" in exI)
apply (rule_tac x="k2 * k" in exI)
done

lemma cong_dvd_modulus_int: "[(x::int) = y] (mod m) \<Longrightarrow> n dvd m \<Longrightarrow> [x = y] (mod n)"
by (auto simp add: cong_altdef_int dvd_def)

lemma cong_dvd_eq_nat: "[(x::nat) = y] (mod n) \<Longrightarrow> n dvd x \<longleftrightarrow> n dvd y"
unfolding cong_nat_def by (auto simp add: dvd_eq_mod_eq_0)

lemma cong_dvd_eq_int: "[(x::int) = y] (mod n) \<Longrightarrow> n dvd x \<longleftrightarrow> n dvd y"
unfolding cong_int_def by (auto simp add: dvd_eq_mod_eq_0)

lemma cong_mod_nat: "(n::nat) ~= 0 \<Longrightarrow> [a mod n = a] (mod n)"

lemma cong_mod_int: "(n::int) ~= 0 \<Longrightarrow> [a mod n = a] (mod n)"

lemma mod_mult_cong_nat: "(a::nat) ~= 0 \<Longrightarrow> b ~= 0
\<Longrightarrow> [x mod (a * b) = y] (mod a) \<longleftrightarrow> [x = y] (mod a)"

lemma neg_cong_int: "([(a::int) = b] (mod m)) = ([-a = -b] (mod m))"
by (metis cong_int_def minus_minus zminus_zmod)

lemma cong_modulus_neg_int: "([(a::int) = b] (mod m)) = ([a = b] (mod -m))"

lemma mod_mult_cong_int: "(a::int) ~= 0 \<Longrightarrow> b ~= 0
\<Longrightarrow> [x mod (a * b) = y] (mod a) \<longleftrightarrow> [x = y] (mod a)"
apply (subst (1 2) cong_modulus_neg_int)
apply (unfold cong_int_def)
apply (subgoal_tac "a * b = (-a * -b)")
apply (erule ssubst)
apply (subst zmod_zmult2_eq)
apply (metis mod_diff_left_eq mod_diff_right_eq mod_mult_self1_is_0 semiring_numeral_div_class.diff_zero)+
done

lemma cong_to_1_nat: "([(a::nat) = 1] (mod n)) \<Longrightarrow> (n dvd (a - 1))"
apply (cases "a = 0", force)
by (metis cong_altdef_nat leI less_one)

lemma cong_0_1_nat': "[(0::nat) = Suc 0] (mod n) = (n = Suc 0)"
unfolding cong_nat_def by auto

lemma cong_0_1_nat: "[(0::nat) = 1] (mod n) = (n = 1)"
unfolding cong_nat_def by auto

lemma cong_0_1_int: "[(0::int) = 1] (mod n) = ((n = 1) | (n = -1))"
unfolding cong_int_def by (auto simp add: zmult_eq_1_iff)

lemma cong_to_1'_nat: "[(a::nat) = 1] (mod n) \<longleftrightarrow>
a = 0 \<and> n = 1 \<or> (\<exists>m. a = 1 + m * n)"
apply (cases "n = 1")
apply auto [1]
apply (drule_tac x = "a - 1" in spec)
apply force
apply (cases "a = 0", simp add: cong_0_1_nat)
apply (rule iffI)
apply (metis cong_to_1_nat dvd_def monoid_mult_class.mult.right_neutral mult.commute mult_eq_if)
done

lemma cong_le_nat: "(y::nat) <= x \<Longrightarrow> [x = y] (mod n) \<longleftrightarrow> (\<exists>q. x = q * n + y)"
by (metis cong_altdef_nat Nat.le_imp_diff_is_add dvd_def mult.commute)

lemma cong_solve_nat: "(a::nat) \<noteq> 0 \<Longrightarrow> EX x. [a * x = gcd a n] (mod n)"
apply (cases "n = 0")
apply force
apply (frule bezout_nat [of a n], auto)

lemma cong_solve_int: "(a::int) \<noteq> 0 \<Longrightarrow> EX x. [a * x = gcd a n] (mod n)"
apply (cases "n = 0")
apply (cases "a \<ge> 0")
apply auto
apply (rule_tac x = "-1" in exI)
apply auto
apply (insert bezout_int [of a n], auto)
by (metis cong_iff_lin_int mult.commute)

lemma cong_solve_dvd_nat:
assumes a: "(a::nat) \<noteq> 0" and b: "gcd a n dvd d"
shows "EX x. [a * x = d] (mod n)"
proof -
from cong_solve_nat [OF a] obtain x where "[a * x = gcd a n](mod n)"
by auto
then have "[(d div gcd a n) * (a * x) = (d div gcd a n) * gcd a n] (mod n)"
by (elim cong_scalar2_nat)
also from b have "(d div gcd a n) * gcd a n = d"
by (rule dvd_div_mult_self)
also have "(d div gcd a n) * (a * x) = a * (d div gcd a n * x)"
by auto
finally show ?thesis
by auto
qed

lemma cong_solve_dvd_int:
assumes a: "(a::int) \<noteq> 0" and b: "gcd a n dvd d"
shows "EX x. [a * x = d] (mod n)"
proof -
from cong_solve_int [OF a] obtain x where "[a * x = gcd a n](mod n)"
by auto
then have "[(d div gcd a n) * (a * x) = (d div gcd a n) * gcd a n] (mod n)"
by (elim cong_scalar2_int)
also from b have "(d div gcd a n) * gcd a n = d"
by (rule dvd_div_mult_self)
also have "(d div gcd a n) * (a * x) = a * (d div gcd a n * x)"
by auto
finally show ?thesis
by auto
qed

lemma cong_solve_coprime_nat: "coprime (a::nat) n \<Longrightarrow> EX x. [a * x = 1] (mod n)"
apply (cases "a = 0")
apply force
apply (metis cong_solve_nat)
done

lemma cong_solve_coprime_int: "coprime (a::int) n \<Longrightarrow> EX x. [a * x = 1] (mod n)"
apply (cases "a = 0")
apply auto
apply (cases "n \<ge> 0")
apply auto
apply (metis cong_solve_int)
done

lemma coprime_iff_invertible_nat: "m > 0 \<Longrightarrow> coprime a m = (EX x. [a * x = Suc 0] (mod m))"
apply (auto intro: cong_solve_coprime_nat simp: One_nat_def)
apply (metis cong_Suc_0_nat cong_solve_nat gcd_nat.left_neutral)
apply (metis One_nat_def cong_gcd_eq_nat coprime_lmult_nat
gcd_lcm_complete_lattice_nat.inf_bot_right gcd_nat.commute)
done

lemma coprime_iff_invertible_int: "m > (0::int) \<Longrightarrow> coprime a m = (EX x. [a * x = 1] (mod m))"
apply (auto intro: cong_solve_coprime_int)
apply (metis cong_int_def coprime_mul_eq_int gcd_1_int gcd_int.commute gcd_red_int)
done

lemma coprime_iff_invertible'_nat: "m > 0 \<Longrightarrow> coprime a m =
(EX x. 0 \<le> x & x < m & [a * x = Suc 0] (mod m))"
apply (subst coprime_iff_invertible_nat)
apply auto
apply (metis mod_less_divisor mod_mult_right_eq)
done

lemma coprime_iff_invertible'_int: "m > (0::int) \<Longrightarrow> coprime a m =
(EX x. 0 <= x & x < m & [a * x = 1] (mod m))"
apply (subst coprime_iff_invertible_int)
apply (metis mod_mult_right_eq pos_mod_conj)
done

lemma cong_cong_lcm_nat: "[(x::nat) = y] (mod a) \<Longrightarrow>
[x = y] (mod b) \<Longrightarrow> [x = y] (mod lcm a b)"
apply (cases "y \<le> x")
apply (metis cong_altdef_nat lcm_least_nat)
apply (metis cong_altdef_nat cong_diff_cong_0'_nat lcm_semilattice_nat.sup.bounded_iff le0 minus_nat.diff_0)
done

lemma cong_cong_lcm_int: "[(x::int) = y] (mod a) \<Longrightarrow>
[x = y] (mod b) \<Longrightarrow> [x = y] (mod lcm a b)"
by (auto simp add: cong_altdef_int lcm_least_int) [1]

lemma cong_cong_setprod_coprime_nat [rule_format]: "finite A \<Longrightarrow>
(ALL i:A. (ALL j:A. i \<noteq> j \<longrightarrow> coprime (m i) (m j))) \<longrightarrow>
(ALL i:A. [(x::nat) = y] (mod m i)) \<longrightarrow>
[x = y] (mod (PROD i:A. m i))"
apply (induct set: finite)
apply auto
apply (metis coprime_cong_mult_nat gcd_semilattice_nat.inf_commute setprod_coprime_nat)
done

lemma cong_cong_setprod_coprime_int [rule_format]: "finite A \<Longrightarrow>
(ALL i:A. (ALL j:A. i \<noteq> j \<longrightarrow> coprime (m i) (m j))) \<longrightarrow>
(ALL i:A. [(x::int) = y] (mod m i)) \<longrightarrow>
[x = y] (mod (PROD i:A. m i))"
apply (induct set: finite)
apply auto
apply (metis coprime_cong_mult_int gcd_int.commute setprod_coprime_int)
done

lemma binary_chinese_remainder_aux_nat:
assumes a: "coprime (m1::nat) m2"
shows "EX b1 b2. [b1 = 1] (mod m1) \<and> [b1 = 0] (mod m2) \<and>
[b2 = 0] (mod m1) \<and> [b2 = 1] (mod m2)"
proof -
from cong_solve_coprime_nat [OF a] obtain x1 where one: "[m1 * x1 = 1] (mod m2)"
by auto
from a have b: "coprime m2 m1"
by (subst gcd_commute_nat)
from cong_solve_coprime_nat [OF b] obtain x2 where two: "[m2 * x2 = 1] (mod m1)"
by auto
have "[m1 * x1 = 0] (mod m1)"
by (subst mult.commute, rule cong_mult_self_nat)
moreover have "[m2 * x2 = 0] (mod m2)"
by (subst mult.commute, rule cong_mult_self_nat)
moreover note one two
ultimately show ?thesis by blast
qed

lemma binary_chinese_remainder_aux_int:
assumes a: "coprime (m1::int) m2"
shows "EX b1 b2. [b1 = 1] (mod m1) \<and> [b1 = 0] (mod m2) \<and>
[b2 = 0] (mod m1) \<and> [b2 = 1] (mod m2)"
proof -
from cong_solve_coprime_int [OF a] obtain x1 where one: "[m1 * x1 = 1] (mod m2)"
by auto
from a have b: "coprime m2 m1"
by (subst gcd_commute_int)
from cong_solve_coprime_int [OF b] obtain x2 where two: "[m2 * x2 = 1] (mod m1)"
by auto
have "[m1 * x1 = 0] (mod m1)"
by (subst mult.commute, rule cong_mult_self_int)
moreover have "[m2 * x2 = 0] (mod m2)"
by (subst mult.commute, rule cong_mult_self_int)
moreover note one two
ultimately show ?thesis by blast
qed

lemma binary_chinese_remainder_nat:
assumes a: "coprime (m1::nat) m2"
shows "EX x. [x = u1] (mod m1) \<and> [x = u2] (mod m2)"
proof -
from binary_chinese_remainder_aux_nat [OF a] obtain b1 b2
where "[b1 = 1] (mod m1)" and "[b1 = 0] (mod m2)" and
"[b2 = 0] (mod m1)" and "[b2 = 1] (mod m2)"
by blast
let ?x = "u1 * b1 + u2 * b2"
have "[?x = u1 * 1 + u2 * 0] (mod m1)"
apply (rule cong_scalar2_nat)
apply (rule `[b1 = 1] (mod m1)`)
apply (rule cong_scalar2_nat)
apply (rule `[b2 = 0] (mod m1)`)
done
then have "[?x = u1] (mod m1)" by simp
have "[?x = u1 * 0 + u2 * 1] (mod m2)"
apply (rule cong_scalar2_nat)
apply (rule `[b1 = 0] (mod m2)`)
apply (rule cong_scalar2_nat)
apply (rule `[b2 = 1] (mod m2)`)
done
then have "[?x = u2] (mod m2)" by simp
with `[?x = u1] (mod m1)` show ?thesis by blast
qed

lemma binary_chinese_remainder_int:
assumes a: "coprime (m1::int) m2"
shows "EX x. [x = u1] (mod m1) \<and> [x = u2] (mod m2)"
proof -
from binary_chinese_remainder_aux_int [OF a] obtain b1 b2
where "[b1 = 1] (mod m1)" and "[b1 = 0] (mod m2)" and
"[b2 = 0] (mod m1)" and "[b2 = 1] (mod m2)"
by blast
let ?x = "u1 * b1 + u2 * b2"
have "[?x = u1 * 1 + u2 * 0] (mod m1)"
apply (rule cong_scalar2_int)
apply (rule `[b1 = 1] (mod m1)`)
apply (rule cong_scalar2_int)
apply (rule `[b2 = 0] (mod m1)`)
done
then have "[?x = u1] (mod m1)" by simp
have "[?x = u1 * 0 + u2 * 1] (mod m2)"
apply (rule cong_scalar2_int)
apply (rule `[b1 = 0] (mod m2)`)
apply (rule cong_scalar2_int)
apply (rule `[b2 = 1] (mod m2)`)
done
then have "[?x = u2] (mod m2)" by simp
with `[?x = u1] (mod m1)` show ?thesis by blast
qed

lemma cong_modulus_mult_nat: "[(x::nat) = y] (mod m * n) \<Longrightarrow>
[x = y] (mod m)"
apply (cases "y \<le> x")
apply (erule dvd_mult_left)
apply (rule cong_sym_nat)
apply (subst (asm) cong_sym_eq_nat)
apply (erule dvd_mult_left)
done

lemma cong_modulus_mult_int: "[(x::int) = y] (mod m * n) \<Longrightarrow>
[x = y] (mod m)"
apply (erule dvd_mult_left)
done

lemma cong_less_modulus_unique_nat:
"[(x::nat) = y] (mod m) \<Longrightarrow> x < m \<Longrightarrow> y < m \<Longrightarrow> x = y"

lemma binary_chinese_remainder_unique_nat:
assumes a: "coprime (m1::nat) m2"
and nz: "m1 \<noteq> 0" "m2 \<noteq> 0"
shows "EX! x. x < m1 * m2 \<and> [x = u1] (mod m1) \<and> [x = u2] (mod m2)"
proof -
from binary_chinese_remainder_nat [OF a] obtain y where
"[y = u1] (mod m1)" and "[y = u2] (mod m2)"
by blast
let ?x = "y mod (m1 * m2)"
from nz have less: "?x < m1 * m2"
by auto
have one: "[?x = u1] (mod m1)"
apply (rule cong_trans_nat)
prefer 2
apply (rule `[y = u1] (mod m1)`)
apply (rule cong_modulus_mult_nat)
apply (rule cong_mod_nat)
using nz apply auto
done
have two: "[?x = u2] (mod m2)"
apply (rule cong_trans_nat)
prefer 2
apply (rule `[y = u2] (mod m2)`)
apply (subst mult.commute)
apply (rule cong_modulus_mult_nat)
apply (rule cong_mod_nat)
using nz apply auto
done
have "ALL z. z < m1 * m2 \<and> [z = u1] (mod m1) \<and> [z = u2] (mod m2) \<longrightarrow> z = ?x"
proof clarify
fix z
assume "z < m1 * m2"
assume "[z = u1] (mod m1)" and  "[z = u2] (mod m2)"
have "[?x = z] (mod m1)"
apply (rule cong_trans_nat)
apply (rule `[?x = u1] (mod m1)`)
apply (rule cong_sym_nat)
apply (rule `[z = u1] (mod m1)`)
done
moreover have "[?x = z] (mod m2)"
apply (rule cong_trans_nat)
apply (rule `[?x = u2] (mod m2)`)
apply (rule cong_sym_nat)
apply (rule `[z = u2] (mod m2)`)
done
ultimately have "[?x = z] (mod m1 * m2)"
by (auto intro: coprime_cong_mult_nat a)
with `z < m1 * m2` `?x < m1 * m2` show "z = ?x"
apply (intro cong_less_modulus_unique_nat)
apply (auto, erule cong_sym_nat)
done
qed
with less one two show ?thesis by auto
qed

lemma chinese_remainder_aux_nat:
fixes A :: "'a set"
and m :: "'a \<Rightarrow> nat"
assumes fin: "finite A"
and cop: "ALL i : A. (ALL j : A. i \<noteq> j \<longrightarrow> coprime (m i) (m j))"
shows "EX b. (ALL i : A. [b i = 1] (mod m i) \<and> [b i = 0] (mod (PROD j : A - {i}. m j)))"
proof (rule finite_set_choice, rule fin, rule ballI)
fix i
assume "i : A"
with cop have "coprime (PROD j : A - {i}. m j) (m i)"
by (intro setprod_coprime_nat, auto)
then have "EX x. [(PROD j : A - {i}. m j) * x = 1] (mod m i)"
by (elim cong_solve_coprime_nat)
then obtain x where "[(PROD j : A - {i}. m j) * x = 1] (mod m i)"
by auto
moreover have "[(PROD j : A - {i}. m j) * x = 0]
(mod (PROD j : A - {i}. m j))"
by (subst mult.commute, rule cong_mult_self_nat)
ultimately show "\<exists>a. [a = 1] (mod m i) \<and> [a = 0]
(mod setprod m (A - {i}))"
by blast
qed

lemma chinese_remainder_nat:
fixes A :: "'a set"
and m :: "'a \<Rightarrow> nat"
and u :: "'a \<Rightarrow> nat"
assumes fin: "finite A"
and cop: "ALL i:A. (ALL j : A. i \<noteq> j \<longrightarrow> coprime (m i) (m j))"
shows "EX x. (ALL i:A. [x = u i] (mod m i))"
proof -
from chinese_remainder_aux_nat [OF fin cop] obtain b where
bprop: "ALL i:A. [b i = 1] (mod m i) \<and>
[b i = 0] (mod (PROD j : A - {i}. m j))"
by blast
let ?x = "SUM i:A. (u i) * (b i)"
show "?thesis"
proof (rule exI, clarify)
fix i
assume a: "i : A"
show "[?x = u i] (mod m i)"
proof -
from fin a have "?x = (SUM j:{i}. u j * b j) +
(SUM j:A-{i}. u j * b j)"
by (subst setsum.union_disjoint [symmetric], auto intro: setsum.cong)
then have "[?x = u i * b i + (SUM j:A-{i}. u j * b j)] (mod m i)"
by auto
also have "[u i * b i + (SUM j:A-{i}. u j * b j) =
u i * 1 + (SUM j:A-{i}. u j * 0)] (mod m i)"
apply (rule cong_scalar2_nat)
using bprop a apply blast
apply (rule cong_setsum_nat)
apply (rule cong_scalar2_nat)
using bprop apply auto
apply (rule cong_dvd_modulus_nat)
apply (drule (1) bspec)
apply (erule conjE)
apply assumption
apply (rule dvd_setprod)
using fin a apply auto
done
finally show ?thesis
by simp
qed
qed
qed

lemma coprime_cong_prod_nat [rule_format]: "finite A \<Longrightarrow>
(ALL i: A. (ALL j: A. i \<noteq> j \<longrightarrow> coprime (m i) (m j))) \<longrightarrow>
(ALL i: A. [(x::nat) = y] (mod m i)) \<longrightarrow>
[x = y] (mod (PROD i:A. m i))"
apply (induct set: finite)
apply auto
apply (metis coprime_cong_mult_nat mult.commute setprod_coprime_nat)
done

lemma chinese_remainder_unique_nat:
fixes A :: "'a set"
and m :: "'a \<Rightarrow> nat"
and u :: "'a \<Rightarrow> nat"
assumes fin: "finite A"
and nz: "ALL i:A. m i \<noteq> 0"
and cop: "ALL i:A. (ALL j : A. i \<noteq> j \<longrightarrow> coprime (m i) (m j))"
shows "EX! x. x < (PROD i:A. m i) \<and> (ALL i:A. [x = u i] (mod m i))"
proof -
from chinese_remainder_nat [OF fin cop]
obtain y where one: "(ALL i:A. [y = u i] (mod m i))"
by blast
let ?x = "y mod (PROD i:A. m i)"
from fin nz have prodnz: "(PROD i:A. m i) \<noteq> 0"
by auto
then have less: "?x < (PROD i:A. m i)"
by auto
have cong: "ALL i:A. [?x = u i] (mod m i)"
apply auto
apply (rule cong_trans_nat)
prefer 2
using one apply auto
apply (rule cong_dvd_modulus_nat)
apply (rule cong_mod_nat)
using prodnz apply auto
apply (rule dvd_setprod)
apply (rule fin)
apply assumption
done
have unique: "ALL z. z < (PROD i:A. m i) \<and>
(ALL i:A. [z = u i] (mod m i)) \<longrightarrow> z = ?x"
proof (clarify)
fix z
assume zless: "z < (PROD i:A. m i)"
assume zcong: "(ALL i:A. [z = u i] (mod m i))"
have "ALL i:A. [?x = z] (mod m i)"
apply clarify
apply (rule cong_trans_nat)
using cong apply (erule bspec)
apply (rule cong_sym_nat)
using zcong apply auto
done
with fin cop have "[?x = z] (mod (PROD i:A. m i))"
apply (intro coprime_cong_prod_nat)
apply auto
done
with zless less show "z = ?x"
apply (intro cong_less_modulus_unique_nat)
apply (auto, erule cong_sym_nat)
done
qed
from less cong unique show ?thesis by blast
qed

end
```