src/HOL/Eisbach/Examples.thy
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(*  Title:      Examples.thy
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    Author:     Daniel Matichuk, NICTA/UNSW
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*)
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section \<open>Basic Eisbach examples\<close>
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theory Examples
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imports Main Eisbach_Tools
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begin
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subsection \<open>Basic methods\<close>
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method my_intros = (rule conjI | rule impI)
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lemma "P \<and> Q \<longrightarrow> Z \<and> X"
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  apply my_intros+
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  oops
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method my_intros' uses intros = (rule conjI | rule impI | rule intros)
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lemma "P \<and> Q \<longrightarrow> Z \<or> X"
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  apply (my_intros' intros: disjI1)+
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  oops
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method my_spec for x :: 'a = (drule spec[where x="x"])
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lemma "\<forall>x. P x \<Longrightarrow> P x"
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  apply (my_spec x)
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  apply assumption
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  done
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subsection \<open>Focusing and matching\<close>
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method match_test =
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  (match premises in U: "P x \<and> Q x" for P Q x \<Rightarrow>
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    \<open>print_term P,
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     print_term Q,
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     print_term x,
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     print_fact U\<close>)
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lemma "\<And>x. P x \<and> Q x \<Longrightarrow> A x \<and> B x \<Longrightarrow> R x y \<Longrightarrow> True"
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  apply match_test  -- \<open>Valid match, but not quite what we were expecting..\<close>
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  back  -- \<open>Can backtrack over matches, exploring all bindings\<close>
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  back
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  back
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  back
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  back
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  back  -- \<open>Found the other conjunction\<close>
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  back
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  back
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  back
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  oops
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text \<open>Use matching to avoid "improper" methods\<close>
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lemma focus_test:
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  shows "\<And>x. \<forall>x. P x \<Longrightarrow> P x"
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  apply (my_spec "x :: 'a", assumption)?  -- \<open>Wrong x\<close>
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  apply (match conclusion in "P x" for x \<Rightarrow> \<open>my_spec x, assumption\<close>)
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  done
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text \<open>Matches are exclusive. Backtracking will not occur past a match\<close>
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method match_test' =
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  (match conclusion in
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    "P \<and> Q" for P Q \<Rightarrow>
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      \<open>print_term P, print_term Q, rule conjI[where P="P" and Q="Q"]; assumption\<close>
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    \<bar> "H" for H \<Rightarrow> \<open>print_term H\<close>
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  )
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text \<open>Solves goal\<close>
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lemma "P \<Longrightarrow> Q \<Longrightarrow> P \<and> Q"
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  apply match_test'
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  done
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text \<open>Fall-through case never taken\<close>
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lemma "P \<and> Q"
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  apply match_test'?
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  oops
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lemma "P"
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  apply match_test'
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  oops
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method my_spec_guess =
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  (match conclusion in "P (x :: 'a)" for P x \<Rightarrow>
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    \<open>drule spec[where x=x],
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     print_term P,
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     print_term x\<close>)
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lemma "\<forall>x. P (x :: nat) \<Longrightarrow> Q (x :: nat)"
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  apply my_spec_guess
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  oops
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method my_spec_guess2 =
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  (match premises in U[thin]:"\<forall>x. P x \<longrightarrow> Q x" and U':"P x" for P Q x \<Rightarrow>
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    \<open>insert spec[where x=x, OF U],
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     print_term P,
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     print_term Q\<close>)
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lemma "\<forall>x. P x \<longrightarrow> Q x \<Longrightarrow> Q x \<Longrightarrow> Q x"
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  apply my_spec_guess2?  -- \<open>Fails. Note that both "P"s must match\<close>
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  oops
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lemma "\<forall>x. P x \<longrightarrow> Q x \<Longrightarrow> P x \<Longrightarrow> Q x"
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  apply my_spec_guess2
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  apply (erule mp)
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  apply assumption
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  done
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subsection \<open>Higher-order methods\<close>
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method higher_order_example for x methods meth =
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  (cases x, meth, meth)
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lemma
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  assumes A: "x = Some a"
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  shows "the x = a"
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  by (higher_order_example x \<open>simp add: A\<close>)
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subsection \<open>Recursion\<close>
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method recursion_example for x :: bool =
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  (print_term x,
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     match (x) in "A \<and> B" for A B \<Rightarrow>
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    \<open>print_term A,
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     print_term B,
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     recursion_example A,
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     recursion_example B | -\<close>)
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lemma "P"
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  apply (recursion_example "(A \<and> D) \<and> (B \<and> C)")
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  oops
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subsection \<open>Solves combinator\<close>
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lemma "A \<Longrightarrow> B \<Longrightarrow> A \<and> B"
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  apply (solves \<open>rule conjI\<close>)?  -- \<open>Doesn't solve the goal!\<close>
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  apply (solves \<open>rule conjI, assumption, assumption\<close>)
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  done
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subsection \<open>Demo\<close>
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method solve methods m = (m; fail)
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named_theorems intros and elims and subst
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method prop_solver declares intros elims subst =
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  (assumption |
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    rule intros | erule elims |
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    subst subst | subst (asm) subst |
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    (erule notE; solve \<open>prop_solver\<close>))+
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lemmas [intros] =
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  conjI
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  impI
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  disjCI
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  iffI
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  notI
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lemmas [elims] =
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  impCE
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  conjE
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  disjE
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lemma "((A \<or> B) \<and> (A \<longrightarrow> C) \<and> (B \<longrightarrow> C)) \<longrightarrow> C"
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  apply prop_solver
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  done
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method guess_all =
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  (match premises in U[thin]:"\<forall>x. P (x :: 'a)" for P \<Rightarrow>
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    \<open>match premises in "?H (y :: 'a)" for y \<Rightarrow>
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       \<open>rule allE[where P = P and x = y, OF U]\<close>
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   | match conclusion in "?H (y :: 'a)" for y \<Rightarrow>
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       \<open>rule allE[where P = P and x = y, OF U]\<close>\<close>)
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lemma "(\<forall>x. P x \<longrightarrow> Q x) \<Longrightarrow> P y \<Longrightarrow> Q y"
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  apply guess_all
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  apply prop_solver
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  done
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lemma "(\<forall>x. P x \<longrightarrow> Q x) \<Longrightarrow>  P z \<Longrightarrow> P y \<Longrightarrow> Q y"
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  apply (solve \<open>guess_all, prop_solver\<close>)  -- \<open>Try it without solve\<close>
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  done
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method guess_ex =
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  (match conclusion in
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    "\<exists>x. P (x :: 'a)" for P \<Rightarrow>
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      \<open>match premises in "?H (x :: 'a)" for x \<Rightarrow>
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              \<open>rule exI[where x=x]\<close>\<close>)
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lemma "P x \<Longrightarrow> \<exists>x. P x"
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  apply guess_ex
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  apply prop_solver
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  done
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method fol_solver =
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  ((guess_ex | guess_all | prop_solver) ; solve \<open>fol_solver\<close>)
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declare
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  allI [intros]
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  exE [elims]
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  ex_simps [subst]
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  all_simps [subst]
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lemma "(\<forall>x. P x) \<and> (\<forall>x. Q x) \<Longrightarrow> (\<forall>x. P x \<and> Q x)"
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  and  "\<exists>x. P x \<longrightarrow> (\<forall>x. P x)"
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  and "(\<exists>x. \<forall>y. R x y) \<longrightarrow> (\<forall>y. \<exists>x. R x y)"
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  by fol_solver+
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end