src/HOL/Data_Structures/Set2_Join_RBT.thy
author nipkow
Thu, 24 May 2018 14:42:47 +0200
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parent 68243 src/HOL/Data_Structures/Set2_BST2_Join_RBT.thy@ddf1ead7b182
child 69597 ff784d5a5bfb
permissions -rw-r--r--
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(* Author: Tobias Nipkow *)
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section "Join-Based Implementation of Sets via RBTs"
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theory Set2_Join_RBT
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imports
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  Set2_Join
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  RBT_Set
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begin
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subsection "Code"
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text \<open>
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Function \<open>joinL\<close> joins two trees (and an element).
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Precondition: @{prop "bheight l \<le> bheight r"}.
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Method:
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Descend along the left spine of \<open>r\<close>
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until you find a subtree with the same \<open>bheight\<close> as \<open>l\<close>,
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then combine them into a new red node.
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\<close>
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fun joinL :: "'a rbt \<Rightarrow> 'a \<Rightarrow> 'a rbt \<Rightarrow> 'a rbt" where
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"joinL l x r =
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  (if bheight l = bheight r then R l x r
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   else case r of
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     B l' x' r' \<Rightarrow> baliL (joinL l x l') x' r' |
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     R l' x' r' \<Rightarrow> R (joinL l x l') x' r')"
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fun joinR :: "'a rbt \<Rightarrow> 'a \<Rightarrow> 'a rbt \<Rightarrow> 'a rbt" where
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"joinR l x r =
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  (if bheight l \<le> bheight r then R l x r
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   else case l of
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     B l' x' r' \<Rightarrow> baliR l' x' (joinR r' x r) |
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     R l' x' r' \<Rightarrow> R l' x' (joinR r' x r))"
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fun join :: "'a rbt \<Rightarrow> 'a \<Rightarrow> 'a rbt \<Rightarrow> 'a rbt" where
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"join l x r =
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  (if bheight l > bheight r
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   then paint Black (joinR l x r)
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   else if bheight l < bheight r
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   then paint Black (joinL l x r)
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   else B l x r)"
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declare joinL.simps[simp del]
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declare joinR.simps[simp del]
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text \<open>
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One would expect @{const joinR} to be be completely dual to @{const joinL}.
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Thus the condition should be @{prop"bheight l = bheight r"}. What we have done
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is totalize the function. On the intended domain (@{prop "bheight l \<ge> bheight r"})
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the two versions behave exactly the same, including complexity. Thus from a programmer's
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perspective they are equivalent. However, not from a verifier's perspective:
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the total version of @{const joinR} is easier
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to reason about because lemmas about it may not require preconditions. In particular
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@{prop"set_tree (joinR l x r) = set_tree l \<union> {x} \<union> set_tree r"}
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is provable outright and hence also
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@{prop"set_tree (join l x r) = set_tree l \<union> {x} \<union> set_tree r"}.
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This is necessary because locale @{locale Set2_Join} unconditionally assumes
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exactly that. Adding preconditions to this assumptions significantly complicates
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the proofs within @{locale Set2_Join}, which we want to avoid.
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Why not work with the partial version of @{const joinR} and add the precondition
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@{prop "bheight l \<ge> bheight r"} to lemmas about @{const joinR}? After all, that is how
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we worked with @{const joinL}, and @{const join} ensures that @{const joinL} and @{const joinR}
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are only called under the respective precondition. But function @{const bheight}
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makes the difference: it descends along the left spine, just like @{const joinL}.
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Function @{const joinR}, however, descends along the right spine and thus @{const bheight}
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may change all the time. Thus we would need the further precondition @{prop "invh l"}.
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This is what we really wanted to avoid in order to satisfy the unconditional assumption
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in @{locale Set2_Join}.
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\<close>
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subsection "Properties"
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subsubsection "Color and height invariants"
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lemma invc2_joinL:
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 "\<lbrakk> invc l; invc r; bheight l \<le> bheight r \<rbrakk> \<Longrightarrow>
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  invc2 (joinL l x r)
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  \<and> (bheight l \<noteq> bheight r \<and> color r = Black \<longrightarrow> invc(joinL l x r))"
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proof (induct l x r rule: joinL.induct)
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  case (1 l x r) thus ?case
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    by(auto simp: invc_baliL invc2I joinL.simps[of l x r] split!: tree.splits if_splits)
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qed
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lemma invc2_joinR:
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  "\<lbrakk> invc l; invh l; invc r; invh r; bheight l \<ge> bheight r \<rbrakk> \<Longrightarrow>
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  invc2 (joinR l x r)
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  \<and> (bheight l \<noteq> bheight r \<and> color l = Black \<longrightarrow> invc(joinR l x r))"
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proof (induct l x r rule: joinR.induct)
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  case (1 l x r) thus ?case
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    by(fastforce simp: invc_baliR invc2I joinR.simps[of l x r] split!: tree.splits if_splits)
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qed
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lemma bheight_joinL:
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  "\<lbrakk> invh l; invh r; bheight l \<le> bheight r \<rbrakk> \<Longrightarrow> bheight (joinL l x r) = bheight r"
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proof (induct l x r rule: joinL.induct)
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  case (1 l x r) thus ?case
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    by(auto simp: bheight_baliL joinL.simps[of l x r] split!: tree.split)
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qed
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lemma invh_joinL:
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  "\<lbrakk> invh l;  invh r;  bheight l \<le> bheight r \<rbrakk> \<Longrightarrow> invh (joinL l x r)"
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proof (induct l x r rule: joinL.induct)
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  case (1 l x r) thus ?case
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    by(auto simp: invh_baliL bheight_joinL joinL.simps[of l x r] split!: tree.split color.split)
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qed
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lemma bheight_baliR:
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  "bheight l = bheight r \<Longrightarrow> bheight (baliR l a r) = Suc (bheight l)"
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by (cases "(l,a,r)" rule: baliR.cases) auto
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lemma bheight_joinR:
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  "\<lbrakk> invh l;  invh r;  bheight l \<ge> bheight r \<rbrakk> \<Longrightarrow> bheight (joinR l x r) = bheight l"
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proof (induct l x r rule: joinR.induct)
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  case (1 l x r) thus ?case
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    by(fastforce simp: bheight_baliR joinR.simps[of l x r] split!: tree.split)
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qed
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lemma invh_joinR:
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  "\<lbrakk> invh l; invh r; bheight l \<ge> bheight r \<rbrakk> \<Longrightarrow> invh (joinR l x r)"
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proof (induct l x r rule: joinR.induct)
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  case (1 l x r) thus ?case
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    by(fastforce simp: invh_baliR bheight_joinR joinR.simps[of l x r]
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        split!: tree.split color.split)
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qed
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(* unused *)
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lemma rbt_join: "\<lbrakk> invc l; invh l; invc r; invh r \<rbrakk> \<Longrightarrow> rbt(join l x r)"
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by(simp add: invc2_joinL invc2_joinR invc_paint_Black invh_joinL invh_joinR invh_paint rbt_def
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    color_paint_Black)
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text \<open>To make sure the the black height is not increased unnecessarily:\<close>
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lemma bheight_paint_Black: "bheight(paint Black t) \<le> bheight t + 1"
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by(cases t) auto
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lemma "\<lbrakk> rbt l; rbt r \<rbrakk> \<Longrightarrow> bheight(join l x r) \<le> max (bheight l) (bheight r) + 1"
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using bheight_paint_Black[of "joinL l x r"] bheight_paint_Black[of "joinR l x r"]
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  bheight_joinL[of l r x] bheight_joinR[of l r x]
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by(auto simp: max_def rbt_def)
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subsubsection "Inorder properties"
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text "Currently unused. Instead @{const set_tree} and @{const bst} properties are proved directly."
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lemma inorder_joinL: "bheight l \<le> bheight r \<Longrightarrow> inorder(joinL l x r) = inorder l @ x # inorder r"
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proof(induction l x r rule: joinL.induct)
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  case (1 l x r)
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  thus ?case by(auto simp: inorder_baliL joinL.simps[of l x r] split!: tree.splits color.splits)
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qed
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lemma inorder_joinR:
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  "inorder(joinR l x r) = inorder l @ x # inorder r"
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proof(induction l x r rule: joinR.induct)
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  case (1 l x r)
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  thus ?case by (force simp: inorder_baliR joinR.simps[of l x r] split!: tree.splits color.splits)
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qed
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lemma "inorder(join l x r) = inorder l @ x # inorder r"
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by(auto simp: inorder_joinL inorder_joinR inorder_paint split!: tree.splits color.splits if_splits
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      dest!: arg_cong[where f = inorder])
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subsubsection "Set and bst properties"
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lemma set_baliL:
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  "set_tree(baliL l a r) = set_tree l \<union> {a} \<union> set_tree r"
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by(cases "(l,a,r)" rule: baliL.cases) (auto)
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lemma set_joinL:
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  "bheight l \<le> bheight r \<Longrightarrow> set_tree (joinL l x r) = set_tree l \<union> {x} \<union> set_tree r"
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proof(induction l x r rule: joinL.induct)
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  case (1 l x r)
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  thus ?case by(auto simp: set_baliL joinL.simps[of l x r] split!: tree.splits color.splits)
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qed
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lemma set_baliR:
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  "set_tree(baliR l a r) = set_tree l \<union> {a} \<union> set_tree r"
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by(cases "(l,a,r)" rule: baliR.cases) (auto)
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lemma set_joinR:
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  "set_tree (joinR l x r) = set_tree l \<union> {x} \<union> set_tree r"
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proof(induction l x r rule: joinR.induct)
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  case (1 l x r)
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  thus ?case by(force simp: set_baliR joinR.simps[of l x r] split!: tree.splits color.splits)
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qed
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lemma set_paint: "set_tree (paint c t) = set_tree t"
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by (cases t) auto
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lemma set_join: "set_tree (join l x r) = set_tree l \<union> {x} \<union> set_tree r"
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by(simp add: set_joinL set_joinR set_paint)
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lemma bst_baliL:
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  "\<lbrakk>bst l; bst r; \<forall>x\<in>set_tree l. x < k; \<forall>x\<in>set_tree r. k < x\<rbrakk>
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   \<Longrightarrow> bst (baliL l k r)"
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by(cases "(l,k,r)" rule: baliL.cases) (auto simp: ball_Un)
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lemma bst_baliR:
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  "\<lbrakk>bst l; bst r; \<forall>x\<in>set_tree l. x < k; \<forall>x\<in>set_tree r. k < x\<rbrakk>
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   \<Longrightarrow> bst (baliR l k r)"
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by(cases "(l,k,r)" rule: baliR.cases) (auto simp: ball_Un)
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lemma bst_joinL:
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  "\<lbrakk>bst l; bst r; \<forall>x\<in>set_tree l. x < k; \<forall>y\<in>set_tree r. k < y; bheight l \<le> bheight r\<rbrakk>
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  \<Longrightarrow> bst (joinL l k r)"
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proof(induction l k r rule: joinL.induct)
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  case (1 l x r)
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  thus ?case
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    by(auto simp: set_baliL joinL.simps[of l x r] set_joinL ball_Un intro!: bst_baliL
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        split!: tree.splits color.splits)
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qed
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lemma bst_joinR:
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  "\<lbrakk>bst l; bst r; \<forall>x\<in>set_tree l. x < k; \<forall>y\<in>set_tree r. k < y \<rbrakk>
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  \<Longrightarrow> bst (joinR l k r)"
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proof(induction l k r rule: joinR.induct)
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  case (1 l x r)
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  thus ?case
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    by(auto simp: set_baliR joinR.simps[of l x r] set_joinR ball_Un intro!: bst_baliR
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        split!: tree.splits color.splits)
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qed
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lemma bst_paint: "bst (paint c t) = bst t"
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by(cases t) auto
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lemma bst_join:
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  "\<lbrakk>bst l; bst r; \<forall>x\<in>set_tree l. x < k; \<forall>y\<in>set_tree r. k < y \<rbrakk>
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  \<Longrightarrow> bst (join l k r)"
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by(auto simp: bst_paint bst_joinL bst_joinR)
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subsubsection "Interpretation of @{locale Set2_Join} with Red-Black Tree"
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global_interpretation RBT: Set2_Join
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where join = join and inv = "\<lambda>t. invc t \<and> invh t"
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defines insert_rbt = RBT.insert and delete_rbt = RBT.delete and split_rbt = RBT.split
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and join2_rbt = RBT.join2 and split_min_rbt = RBT.split_min
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proof (standard, goal_cases)
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  case 1 show ?case by (rule set_join)
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next
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  case 2 thus ?case by (rule bst_join)
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next
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  case 3 show ?case by simp
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next
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  case 4 thus ?case
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    by (simp add: invc2_joinL invc2_joinR invc_paint_Black invh_joinL invh_joinR invh_paint)
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next
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  case 5 thus ?case by simp
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qed
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text \<open>The invariant does not guarantee that the root node is black. This is not required
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to guarantee that the height is logarithmic in the size --- Exercise.\<close>
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end