src/Doc/Tutorial/Recdef/Nested1.thy
author wenzelm
Sat, 05 Apr 2014 15:03:40 +0200
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(*<*)
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theory Nested1 imports Nested0 begin
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(*>*)
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text{*\noindent
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Although the definition of @{term trev} below is quite natural, we will have
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to overcome a minor difficulty in convincing Isabelle of its termination.
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It is precisely this difficulty that is the \textit{raison d'\^etre} of
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this subsection.
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Defining @{term trev} by \isacommand{recdef} rather than \isacommand{primrec}
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simplifies matters because we are now free to use the recursion equation
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suggested at the end of \S\ref{sec:nested-datatype}:
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*}
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recdef (*<*)(permissive)(*>*)trev "measure size"
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 "trev (Var x)    = Var x"
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 "trev (App f ts) = App f (rev(map trev ts))"
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text{*\noindent
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Remember that function @{term size} is defined for each \isacommand{datatype}.
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However, the definition does not succeed. Isabelle complains about an
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unproved termination condition
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@{prop[display]"t : set ts --> size t < Suc (term_list_size ts)"}
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where @{term set} returns the set of elements of a list
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and @{text"term_list_size :: term list \<Rightarrow> nat"} is an auxiliary
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function automatically defined by Isabelle
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(while processing the declaration of @{text term}).  Why does the
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recursive call of @{const trev} lead to this
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condition?  Because \isacommand{recdef} knows that @{term map}
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will apply @{const trev} only to elements of @{term ts}. Thus the 
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condition expresses that the size of the argument @{prop"t : set ts"} of any
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recursive call of @{const trev} is strictly less than @{term"size(App f ts)"},
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which equals @{term"Suc(term_list_size ts)"}.  We will now prove the termination condition and
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continue with our definition.  Below we return to the question of how
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\isacommand{recdef} knows about @{term map}.
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The termination condition is easily proved by induction:
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*}
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(*<*)
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end
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(*>*)