src/HOL/Old_Number_Theory/Finite2.thy
author haftmann
Tue, 01 Sep 2009 15:39:33 +0200
changeset 32479 521cc9bf2958
parent 25592 src/HOL/NumberTheory/Finite2.thy@e8ddaf6bf5df
child 38159 e9b4835a54ee
permissions -rw-r--r--
some reorganization of number theory
Ignore whitespace changes - Everywhere: Within whitespace: At end of lines:
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(*  Title:      HOL/Quadratic_Reciprocity/Finite2.thy
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    ID:         $Id$
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    Authors:    Jeremy Avigad, David Gray, and Adam Kramer
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*)
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header {*Finite Sets and Finite Sums*}
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theory Finite2
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imports Main IntFact Infinite_Set
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begin
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text{*
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  These are useful for combinatorial and number-theoretic counting
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  arguments.
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*}
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subsection {* Useful properties of sums and products *}
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lemma setsum_same_function_zcong:
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  assumes a: "\<forall>x \<in> S. [f x = g x](mod m)"
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  shows "[setsum f S = setsum g S] (mod m)"
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proof cases
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  assume "finite S"
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  thus ?thesis using a by induct (simp_all add: zcong_zadd)
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next
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  assume "infinite S" thus ?thesis by(simp add:setsum_def)
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qed
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lemma setprod_same_function_zcong:
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  assumes a: "\<forall>x \<in> S. [f x = g x](mod m)"
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  shows "[setprod f S = setprod g S] (mod m)"
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proof cases
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  assume "finite S"
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  thus ?thesis using a by induct (simp_all add: zcong_zmult)
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next
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  assume "infinite S" thus ?thesis by(simp add:setprod_def)
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qed
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lemma setsum_const: "finite X ==> setsum (%x. (c :: int)) X = c * int(card X)"
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  apply (induct set: finite)
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  apply (auto simp add: left_distrib right_distrib int_eq_of_nat)
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  done
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lemma setsum_const2: "finite X ==> int (setsum (%x. (c :: nat)) X) =
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    int(c) * int(card X)"
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  apply (induct set: finite)
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  apply (auto simp add: zadd_zmult_distrib2)
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  done
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lemma setsum_const_mult: "finite A ==> setsum (%x. c * ((f x)::int)) A =
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    c * setsum f A"
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  by (induct set: finite) (auto simp add: zadd_zmult_distrib2)
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subsection {* Cardinality of explicit finite sets *}
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lemma finite_surjI: "[| B \<subseteq> f ` A; finite A |] ==> finite B"
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  by (simp add: finite_subset finite_imageI)
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lemma bdd_nat_set_l_finite: "finite {y::nat . y < x}"
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  by (rule bounded_nat_set_is_finite) blast
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lemma bdd_nat_set_le_finite: "finite {y::nat . y \<le> x}"
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proof -
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  have "{y::nat . y \<le> x} = {y::nat . y < Suc x}" by auto
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  then show ?thesis by (auto simp add: bdd_nat_set_l_finite)
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qed
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lemma  bdd_int_set_l_finite: "finite {x::int. 0 \<le> x & x < n}"
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  apply (subgoal_tac " {(x :: int). 0 \<le> x & x < n} \<subseteq>
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      int ` {(x :: nat). x < nat n}")
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   apply (erule finite_surjI)
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   apply (auto simp add: bdd_nat_set_l_finite image_def)
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  apply (rule_tac x = "nat x" in exI, simp)
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  done
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lemma bdd_int_set_le_finite: "finite {x::int. 0 \<le> x & x \<le> n}"
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  apply (subgoal_tac "{x. 0 \<le> x & x \<le> n} = {x. 0 \<le> x & x < n + 1}")
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   apply (erule ssubst)
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   apply (rule bdd_int_set_l_finite)
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  apply auto
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  done
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lemma bdd_int_set_l_l_finite: "finite {x::int. 0 < x & x < n}"
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    86
proof -
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  have "{x::int. 0 < x & x < n} \<subseteq> {x::int. 0 \<le> x & x < n}"
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    88
    by auto
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    89
  then show ?thesis by (auto simp add: bdd_int_set_l_finite finite_subset)
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    90
qed
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lemma bdd_int_set_l_le_finite: "finite {x::int. 0 < x & x \<le> n}"
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    93
proof -
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    94
  have "{x::int. 0 < x & x \<le> n} \<subseteq> {x::int. 0 \<le> x & x \<le> n}"
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    95
    by auto
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    96
  then show ?thesis by (auto simp add: bdd_int_set_le_finite finite_subset)
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    97
qed
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    98
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lemma card_bdd_nat_set_l: "card {y::nat . y < x} = x"
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   100
proof (induct x)
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  case 0
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  show "card {y::nat . y < 0} = 0" by simp
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   103
next
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   104
  case (Suc n)
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   105
  have "{y. y < Suc n} = insert n {y. y < n}"
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   106
    by auto
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   107
  then have "card {y. y < Suc n} = card (insert n {y. y < n})"
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   108
    by auto
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   109
  also have "... = Suc (card {y. y < n})"
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   110
    by (rule card_insert_disjoint) (auto simp add: bdd_nat_set_l_finite)
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  finally show "card {y. y < Suc n} = Suc n"
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   112
    using `card {y. y < n} = n` by simp
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   113
qed
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   114
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lemma card_bdd_nat_set_le: "card { y::nat. y \<le> x} = Suc x"
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   116
proof -
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   117
  have "{y::nat. y \<le> x} = { y::nat. y < Suc x}"
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   118
    by auto
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   119
  then show ?thesis by (auto simp add: card_bdd_nat_set_l)
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   120
qed
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   121
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lemma card_bdd_int_set_l: "0 \<le> (n::int) ==> card {y. 0 \<le> y & y < n} = nat n"
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   123
proof -
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   124
  assume "0 \<le> n"
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   125
  have "inj_on (%y. int y) {y. y < nat n}"
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parents:
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   126
    by (auto simp add: inj_on_def)
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   127
  hence "card (int ` {y. y < nat n}) = card {y. y < nat n}"
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   128
    by (rule card_image)
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   129
  also from `0 \<le> n` have "int ` {y. y < nat n} = {y. 0 \<le> y & y < n}"
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   130
    apply (auto simp add: zless_nat_eq_int_zless image_def)
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   131
    apply (rule_tac x = "nat x" in exI)
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   132
    apply (auto simp add: nat_0_le)
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   133
    done
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   134
  also have "card {y. y < nat n} = nat n"
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   135
    by (rule card_bdd_nat_set_l)
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   136
  finally show "card {y. 0 \<le> y & y < n} = nat n" .
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   137
qed
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paulson
parents:
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   138
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   139
lemma card_bdd_int_set_le: "0 \<le> (n::int) ==> card {y. 0 \<le> y & y \<le> n} =
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   140
  nat n + 1"
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   141
proof -
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   142
  assume "0 \<le> n"
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diff changeset
   143
  moreover have "{y. 0 \<le> y & y \<le> n} = {y. 0 \<le> y & y < n+1}" by auto
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   144
  ultimately show ?thesis
694ea14ab4f2 tuned sources and proofs
wenzelm
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   145
    using card_bdd_int_set_l [of "n + 1"]
694ea14ab4f2 tuned sources and proofs
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   146
    by (auto simp add: nat_add_distrib)
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diff changeset
   147
qed
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lemma card_bdd_int_set_l_le: "0 \<le> (n::int) ==>
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    card {x. 0 < x & x \<le> n} = nat n"
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proof -
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  assume "0 \<le> n"
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  have "inj_on (%x. x+1) {x. 0 \<le> x & x < n}"
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    by (auto simp add: inj_on_def)
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  hence "card ((%x. x+1) ` {x. 0 \<le> x & x < n}) =
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     card {x. 0 \<le> x & x < n}"
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    by (rule card_image)
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  also from `0 \<le> n` have "... = nat n"
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    by (rule card_bdd_int_set_l)
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  also have "(%x. x + 1) ` {x. 0 \<le> x & x < n} = {x. 0 < x & x<= n}"
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    apply (auto simp add: image_def)
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    apply (rule_tac x = "x - 1" in exI)
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    apply arith
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    done
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  finally show "card {x. 0 < x & x \<le> n} = nat n" .
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qed
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lemma card_bdd_int_set_l_l: "0 < (n::int) ==>
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  card {x. 0 < x & x < n} = nat n - 1"
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proof -
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  assume "0 < n"
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  moreover have "{x. 0 < x & x < n} = {x. 0 < x & x \<le> n - 1}"
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    by simp
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  ultimately show ?thesis
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    using insert card_bdd_int_set_l_le [of "n - 1"]
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    by (auto simp add: nat_diff_distrib)
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qed
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lemma int_card_bdd_int_set_l_l: "0 < n ==>
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    int(card {x. 0 < x & x < n}) = n - 1"
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  apply (auto simp add: card_bdd_int_set_l_l)
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  done
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lemma int_card_bdd_int_set_l_le: "0 \<le> n ==>
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    int(card {x. 0 < x & x \<le> n}) = n"
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  by (auto simp add: card_bdd_int_set_l_le)
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26e5f5e624f6 Gauss's law of quadratic reciprocity by Avigad, Gray and Kramer
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subsection {* Cardinality of finite cartesian products *}
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(* FIXME could be useful in general but not needed here
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lemma insert_Sigma [simp]: "(insert x A) <*> B = ({ x } <*> B) \<union> (A <*> B)"
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  by blast
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 *)
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text {* Lemmas for counting arguments. *}
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lemma setsum_bij_eq: "[| finite A; finite B; f ` A \<subseteq> B; inj_on f A;
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    g ` B \<subseteq> A; inj_on g B |] ==> setsum g B = setsum (g \<circ> f) A"
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  apply (frule_tac h = g and f = f in setsum_reindex)
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  apply (subgoal_tac "setsum g B = setsum g (f ` A)")
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   apply (simp add: inj_on_def)
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  apply (subgoal_tac "card A = card B")
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   apply (drule_tac A = "f ` A" and B = B in card_seteq)
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     apply (auto simp add: card_image)
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  apply (frule_tac A = A and B = B and f = f in card_inj_on_le, auto)
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  apply (frule_tac A = B and B = A and f = g in card_inj_on_le)
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    apply auto
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  done
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lemma setprod_bij_eq: "[| finite A; finite B; f ` A \<subseteq> B; inj_on f A;
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    g ` B \<subseteq> A; inj_on g B |] ==> setprod g B = setprod (g \<circ> f) A"
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  apply (frule_tac h = g and f = f in setprod_reindex)
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  apply (subgoal_tac "setprod g B = setprod g (f ` A)")
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   apply (simp add: inj_on_def)
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  apply (subgoal_tac "card A = card B")
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   apply (drule_tac A = "f ` A" and B = B in card_seteq)
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     apply (auto simp add: card_image)
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  apply (frule_tac A = A and B = B and f = f in card_inj_on_le, auto)
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  apply (frule_tac A = B and B = A and f = g in card_inj_on_le, auto)
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  done
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end