author  wenzelm 
Mon, 16 Feb 2009 21:23:33 +0100  
changeset 29758  7a3b5bbed313 
parent 20049  f48c4a3a34bc 
child 31166  a90fe83f58ea 
permissions  rwrr 
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(* Title: Provers/quantifier1 
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ID: $Id$ 

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Author: Tobias Nipkow 

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Copyright 1997 TU Munich 

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Simplification procedures for turning 

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? x. ... & x = t & ... 

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into ? x. x = t & ... & ... 

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where the `? x. x = t &' in the latter formula must be eliminated 
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by ordinary simplification. 
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and ! x. (... & x = t & ...) > P x 

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into ! x. x = t > (... & ...) > P x 

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where the `!x. x=t >' in the latter formula is eliminated 

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by ordinary simplification. 

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And analogously for t=x, but the eqn is not turned around! 
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NB Simproc is only triggered by "!x. P(x) & P'(x) > Q(x)"; 
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"!x. x=t > P(x)" is covered by the congreunce rule for >; 

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"!x. t=x > P(x)" must be taken care of by an ordinary rewrite rule. 

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As must be "? x. t=x & P(x)". 
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And similarly for the bounded quantifiers. 
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Gries etc call this the "1 point rules" 
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*) 

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signature QUANTIFIER1_DATA = 

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sig 

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(*abstract syntax*) 

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val dest_eq: term > (term*term*term)option 

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val dest_conj: term > (term*term*term)option 

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val dest_imp: term > (term*term*term)option 
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val conj: term 
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val imp: term 

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(*rules*) 

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val iff_reflection: thm (* P <> Q ==> P == Q *) 

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val iffI: thm 

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val iff_trans: thm 
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val conjI: thm 
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val conjE: thm 

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val impI: thm 

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val mp: thm 

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val exI: thm 

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val exE: thm 

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val uncurry: thm (* P > Q > R ==> P & Q > R *) 
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val iff_allI: thm (* !!x. P x <> Q x ==> (!x. P x) = (!x. Q x) *) 

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val iff_exI: thm (* !!x. P x <> Q x ==> (? x. P x) = (? x. Q x) *) 
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val all_comm: thm (* (!x y. P x y) = (!y x. P x y) *) 
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val ex_comm: thm (* (? x y. P x y) = (? y x. P x y) *) 
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end; 
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signature QUANTIFIER1 = 

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sig 

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val prove_one_point_all_tac: tactic 
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val prove_one_point_ex_tac: tactic 

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val rearrange_all: theory > simpset > term > thm option 
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val rearrange_ex: theory > simpset > term > thm option 

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val rearrange_ball: (simpset > tactic) > theory > simpset > term > thm option 

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val rearrange_bex: (simpset > tactic) > theory > simpset > term > thm option 

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end; 
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functor Quantifier1Fun(Data: QUANTIFIER1_DATA): QUANTIFIER1 = 

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struct 

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open Data; 

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(* FIXME: only test! *) 
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fun def xs eq = 
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let val n = length xs 
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in case dest_eq eq of 
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SOME(c,s,t) => 
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s = Bound n andalso not(loose_bvar1(t,n)) orelse 
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t = Bound n andalso not(loose_bvar1(s,n)) 
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 NONE => false 
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end; 
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fun extract_conj xs t = case dest_conj t of NONE => NONE 
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 SOME(conj,P,Q) => 

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(if def xs P then SOME(xs,P,Q) else 

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if def xs Q then SOME(xs,Q,P) else 

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(case extract_conj xs P of 
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SOME(xs,eq,P') => SOME(xs,eq, conj $ P' $ Q) 
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 NONE => (case extract_conj xs Q of 

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SOME(xs,eq,Q') => SOME(xs,eq,conj $ P $ Q') 

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 NONE => NONE))); 

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fun extract_imp xs t = case dest_imp t of NONE => NONE 
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 SOME(imp,P,Q) => if def xs P then SOME(xs,P,Q) 

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else (case extract_conj xs P of 
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SOME(xs,eq,P') => SOME(xs, eq, imp $ P' $ Q) 
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 NONE => (case extract_imp xs Q of 

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NONE => NONE 

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 SOME(xs,eq,Q') => 

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SOME(xs,eq,imp$P$Q'))); 

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fun extract_quant extract q = 
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let fun exqu xs ((qC as Const(qa,_)) $ Abs(x,T,Q)) = 
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if qa = q then exqu ((qC,x,T)::xs) Q else NONE 
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 exqu xs P = extract xs P 
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in exqu end; 
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fun prove_conv tac thy tu = 
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Goal.prove (ProofContext.init thy) [] [] (Logic.mk_equals tu) 
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(K (rtac iff_reflection 1 THEN tac)); 

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fun qcomm_tac qcomm qI i = REPEAT_DETERM (rtac qcomm i THEN rtac qI i) 
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(* Proves (? x0..xn. ... & x0 = t & ...) = (? x1..xn x0. x0 = t & ... & ...) 
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Better: instantiate exI 
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*) 

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local 
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val excomm = ex_comm RS iff_trans 
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in 
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val prove_one_point_ex_tac = qcomm_tac excomm iff_exI 1 THEN rtac iffI 1 THEN 
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ALLGOALS(EVERY'[etac exE, REPEAT_DETERM o (etac conjE), rtac exI, 
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DEPTH_SOLVE_1 o (ares_tac [conjI])]) 
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end; 
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(* Proves (! x0..xn. (... & x0 = t & ...) > P x0) = 
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(! x1..xn x0. x0 = t > (... & ...) > P x0) 
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*) 
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local 
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val tac = SELECT_GOAL 

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(EVERY1[REPEAT o (dtac uncurry), REPEAT o (rtac impI), etac mp, 

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REPEAT o (etac conjE), REPEAT o (ares_tac [conjI])]) 

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val allcomm = all_comm RS iff_trans 
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in 
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val prove_one_point_all_tac = 
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EVERY1[qcomm_tac allcomm iff_allI,rtac iff_allI, rtac iffI, tac, tac] 
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end 
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fun renumber l u (Bound i) = Bound(if i < l orelse i > u then i else 
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if i=u then l else i+1) 
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 renumber l u (s$t) = renumber l u s $ renumber l u t 
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 renumber l u (Abs(x,T,t)) = Abs(x,T,renumber (l+1) (u+1) t) 
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 renumber _ _ atom = atom; 
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fun quantify qC x T xs P = 
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let fun quant [] P = P 
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 quant ((qC,x,T)::xs) P = quant xs (qC $ Abs(x,T,P)) 
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val n = length xs 
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val Q = if n=0 then P else renumber 0 n P 
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in quant xs (qC $ Abs(x,T,Q)) end; 
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fun rearrange_all thy _ (F as (all as Const(q,_)) $ Abs(x,T, P)) = 
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(case extract_quant extract_imp q [] P of 
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NONE => NONE 
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 SOME(xs,eq,Q) => 

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let val R = quantify all x T xs (imp $ eq $ Q) 
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in SOME(prove_conv prove_one_point_all_tac thy (F,R)) end) 
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 rearrange_all _ _ _ = NONE; 
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fun rearrange_ball tac thy ss (F as Ball $ A $ Abs(x,T,P)) = 
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(case extract_imp [] P of 
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NONE => NONE 
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 SOME(xs,eq,Q) => if not(null xs) then NONE else 

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let val R = imp $ eq $ Q 
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in SOME(prove_conv (tac ss) thy (F,Ball $ A $ Abs(x,T,R))) end) 
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 rearrange_ball _ _ _ _ = NONE; 
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fun rearrange_ex thy _ (F as (ex as Const(q,_)) $ Abs(x,T,P)) = 
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(case extract_quant extract_conj q [] P of 
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NONE => NONE 
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 SOME(xs,eq,Q) => 

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let val R = quantify ex x T xs (conj $ eq $ Q) 
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in SOME(prove_conv prove_one_point_ex_tac thy (F,R)) end) 
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 rearrange_ex _ _ _ = NONE; 
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fun rearrange_bex tac thy ss (F as Bex $ A $ Abs(x,T,P)) = 
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(case extract_conj [] P of 
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NONE => NONE 
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 SOME(xs,eq,Q) => if not(null xs) then NONE else 

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SOME(prove_conv (tac ss) thy (F,Bex $ A $ Abs(x,T,conj$eq$Q)))) 
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 rearrange_bex _ _ _ _ = NONE; 
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4319  180 
end; 