src/Provers/quantifier1.ML
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(*  Title:      Provers/quantifier1
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    ID:         $Id$
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    Author:     Tobias Nipkow
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    Copyright   1997  TU Munich
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Simplification procedures for turning
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            ? x. ... & x = t & ...
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     into   ? x. x = t & ... & ...
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     where the `? x. x = t &' in the latter formula must be eliminated
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           by ordinary simplification. 
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     and   ! x. (... & x = t & ...) --> P x
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     into  ! x. x = t --> (... & ...) --> P x
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     where the `!x. x=t -->' in the latter formula is eliminated
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           by ordinary simplification.
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     And analogously for t=x, but the eqn is not turned around!
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     NB Simproc is only triggered by "!x. P(x) & P'(x) --> Q(x)";
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        "!x. x=t --> P(x)" is covered by the congreunce rule for -->;
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        "!x. t=x --> P(x)" must be taken care of by an ordinary rewrite rule.
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        As must be "? x. t=x & P(x)".
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     And similarly for the bounded quantifiers.
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Gries etc call this the "1 point rules"
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*)
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signature QUANTIFIER1_DATA =
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sig
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  (*abstract syntax*)
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  val dest_eq: term -> (term*term*term)option
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  val dest_conj: term -> (term*term*term)option
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  val dest_imp:  term -> (term*term*term)option
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  val conj: term
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  val imp:  term
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  (*rules*)
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  val iff_reflection: thm (* P <-> Q ==> P == Q *)
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  val iffI:  thm
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  val iff_trans: thm
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  val conjI: thm
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  val conjE: thm
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  val impI:  thm
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  val mp:    thm
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  val exI:   thm
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  val exE:   thm
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  val uncurry: thm (* P --> Q --> R ==> P & Q --> R *)
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  val iff_allI: thm (* !!x. P x <-> Q x ==> (!x. P x) = (!x. Q x) *)
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  val iff_exI: thm (* !!x. P x <-> Q x ==> (? x. P x) = (? x. Q x) *)
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  val all_comm: thm (* (!x y. P x y) = (!y x. P x y) *)
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  val ex_comm: thm (* (? x y. P x y) = (? y x. P x y) *)
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end;
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signature QUANTIFIER1 =
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sig
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  val prove_one_point_all_tac: tactic
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  val prove_one_point_ex_tac: tactic
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  val rearrange_all: theory -> simpset -> term -> thm option
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  val rearrange_ex:  theory -> simpset -> term -> thm option
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  val rearrange_ball: (simpset -> tactic) -> theory -> simpset -> term -> thm option
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  val rearrange_bex:  (simpset -> tactic) -> theory -> simpset -> term -> thm option
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end;
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functor Quantifier1Fun(Data: QUANTIFIER1_DATA): QUANTIFIER1 =
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struct
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open Data;
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(* FIXME: only test! *)
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fun def xs eq =
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  let val n = length xs
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  in case dest_eq eq of
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      SOME(c,s,t) =>
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        s = Bound n andalso not(loose_bvar1(t,n)) orelse
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        t = Bound n andalso not(loose_bvar1(s,n))
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    | NONE => false
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  end;
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fun extract_conj xs t = case dest_conj t of NONE => NONE
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    | SOME(conj,P,Q) =>
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        (if def xs P then SOME(xs,P,Q) else
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         if def xs Q then SOME(xs,Q,P) else
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         (case extract_conj xs P of
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            SOME(xs,eq,P') => SOME(xs,eq, conj $ P' $ Q)
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          | NONE => (case extract_conj xs Q of
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                       SOME(xs,eq,Q') => SOME(xs,eq,conj $ P $ Q')
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                     | NONE => NONE)));
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fun extract_imp xs t = case dest_imp t of NONE => NONE
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    | SOME(imp,P,Q) => if def xs P then SOME(xs,P,Q)
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                       else (case extract_conj xs P of
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                               SOME(xs,eq,P') => SOME(xs, eq, imp $ P' $ Q)
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                             | NONE => (case extract_imp xs Q of
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                                          NONE => NONE
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                                        | SOME(xs,eq,Q') =>
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                                            SOME(xs,eq,imp$P$Q')));
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fun extract_quant extract q =
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  let fun exqu xs ((qC as Const(qa,_)) $ Abs(x,T,Q)) =
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            if qa = q then exqu ((qC,x,T)::xs) Q else NONE
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        | exqu xs P = extract xs P
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  in exqu end;
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fun prove_conv tac thy tu =
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  Goal.prove (ProofContext.init thy) [] [] (Logic.mk_equals tu)
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    (K (rtac iff_reflection 1 THEN tac));
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fun qcomm_tac qcomm qI i = REPEAT_DETERM (rtac qcomm i THEN rtac qI i) 
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(* Proves (? x0..xn. ... & x0 = t & ...) = (? x1..xn x0. x0 = t & ... & ...)
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   Better: instantiate exI
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*)
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local
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val excomm = ex_comm RS iff_trans
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in
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val prove_one_point_ex_tac = qcomm_tac excomm iff_exI 1 THEN rtac iffI 1 THEN
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    ALLGOALS(EVERY'[etac exE, REPEAT_DETERM o (etac conjE), rtac exI,
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                    DEPTH_SOLVE_1 o (ares_tac [conjI])])
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end;
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(* Proves (! x0..xn. (... & x0 = t & ...) --> P x0) =
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          (! x1..xn x0. x0 = t --> (... & ...) --> P x0)
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*)
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local
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val tac = SELECT_GOAL
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          (EVERY1[REPEAT o (dtac uncurry), REPEAT o (rtac impI), etac mp,
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                  REPEAT o (etac conjE), REPEAT o (ares_tac [conjI])])
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val allcomm = all_comm RS iff_trans
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in
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val prove_one_point_all_tac =
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      EVERY1[qcomm_tac allcomm iff_allI,rtac iff_allI, rtac iffI, tac, tac]
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end
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fun renumber l u (Bound i) = Bound(if i < l orelse i > u then i else
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                                   if i=u then l else i+1)
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  | renumber l u (s$t) = renumber l u s $ renumber l u t
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  | renumber l u (Abs(x,T,t)) = Abs(x,T,renumber (l+1) (u+1) t)
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  | renumber _ _ atom = atom;
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fun quantify qC x T xs P =
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  let fun quant [] P = P
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        | quant ((qC,x,T)::xs) P = quant xs (qC $ Abs(x,T,P))
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      val n = length xs
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      val Q = if n=0 then P else renumber 0 n P
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  in quant xs (qC $ Abs(x,T,Q)) end;
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fun rearrange_all thy _ (F as (all as Const(q,_)) $ Abs(x,T, P)) =
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     (case extract_quant extract_imp q [] P of
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        NONE => NONE
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      | SOME(xs,eq,Q) =>
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          let val R = quantify all x T xs (imp $ eq $ Q)
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          in SOME(prove_conv prove_one_point_all_tac thy (F,R)) end)
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  | rearrange_all _ _ _ = NONE;
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fun rearrange_ball tac thy ss (F as Ball $ A $ Abs(x,T,P)) =
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     (case extract_imp [] P of
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        NONE => NONE
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      | SOME(xs,eq,Q) => if not(null xs) then NONE else
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          let val R = imp $ eq $ Q
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          in SOME(prove_conv (tac ss) thy (F,Ball $ A $ Abs(x,T,R))) end)
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  | rearrange_ball _ _ _ _ = NONE;
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fun rearrange_ex thy _ (F as (ex as Const(q,_)) $ Abs(x,T,P)) =
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     (case extract_quant extract_conj q [] P of
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        NONE => NONE
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      | SOME(xs,eq,Q) =>
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          let val R = quantify ex x T xs (conj $ eq $ Q)
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          in SOME(prove_conv prove_one_point_ex_tac thy (F,R)) end)
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  | rearrange_ex _ _ _ = NONE;
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fun rearrange_bex tac thy ss (F as Bex $ A $ Abs(x,T,P)) =
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     (case extract_conj [] P of
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        NONE => NONE
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      | SOME(xs,eq,Q) => if not(null xs) then NONE else
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          SOME(prove_conv (tac ss) thy (F,Bex $ A $ Abs(x,T,conj$eq$Q))))
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  | rearrange_bex _ _ _ _ = NONE;
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end;