src/HOL/Data_Structures/Sorting.thy
author nipkow
Fri, 07 Sep 2018 21:30:55 +0200
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(* Author: Tobias Nipkow *)
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theory Sorting
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imports
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  Complex_Main
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  "HOL-Library.Multiset"
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begin
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hide_const List.insort
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declare Let_def [simp]
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subsection "Insertion Sort"
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fun insort :: "'a::linorder \<Rightarrow> 'a list \<Rightarrow> 'a list" where
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"insort x [] = [x]" |
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"insort x (y#ys) =
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  (if x \<le> y then x#y#ys else y#(insort x ys))"
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fun isort :: "'a::linorder list \<Rightarrow> 'a list" where
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"isort [] = []" |
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"isort (x#xs) = insort x (isort xs)"
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subsubsection "Functional Correctness"
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lemma mset_insort: "mset (insort x xs) = add_mset x (mset xs)"
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apply(induction xs)
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apply auto
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done
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lemma mset_isort: "mset (isort xs) = mset xs"
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apply(induction xs)
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apply simp
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apply (simp add: mset_insort)
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done
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lemma set_insort: "set (insort x xs) = insert x (set xs)"
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by (metis mset_insort set_mset_add_mset_insert set_mset_mset)
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lemma sorted_insort: "sorted (insort a xs) = sorted xs"
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apply(induction xs)
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apply(auto simp add: set_insort)
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done
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lemma sorted_isort: "sorted (isort xs)"
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apply(induction xs)
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apply(auto simp: sorted_insort)
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done
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subsubsection "Time Complexity"
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text \<open>We count the number of function calls.\<close>
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text\<open>
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\<open>insort x [] = [x]\<close>
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\<open>insort x (y#ys) =
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  (if x \<le> y then x#y#ys else y#(insort x ys))\<close>
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\<close>
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fun t_insort :: "'a::linorder \<Rightarrow> 'a list \<Rightarrow> nat" where
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"t_insort x [] = 1" |
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"t_insort x (y#ys) =
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  (if x \<le> y then 0 else t_insort x ys) + 1"
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text\<open>
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\<open>isort [] = []\<close>
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\<open>isort (x#xs) = insort x (isort xs)\<close>
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\<close>
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fun t_isort :: "'a::linorder list \<Rightarrow> nat" where
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"t_isort [] = 1" |
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"t_isort (x#xs) = t_isort xs + t_insort x (isort xs) + 1"
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lemma t_insort_length: "t_insort x xs \<le> length xs + 1"
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apply(induction xs)
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apply auto
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done
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lemma length_insort: "length (insort x xs) = length xs + 1"
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apply(induction xs)
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apply auto
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done
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lemma length_isort: "length (isort xs) = length xs"
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apply(induction xs)
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apply (auto simp: length_insort)
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done
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lemma t_isort_length: "t_isort xs \<le> (length xs + 1) ^ 2"
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proof(induction xs)
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  case Nil show ?case by simp
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next
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  case (Cons x xs)
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  have "t_isort (x#xs) = t_isort xs + t_insort x (isort xs) + 1" by simp
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  also have "\<dots> \<le> (length xs + 1) ^ 2 + t_insort x (isort xs) + 1"
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    using Cons.IH by simp
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  also have "\<dots> \<le> (length xs + 1) ^ 2 + length xs + 1 + 1"
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    using t_insort_length[of x "isort xs"] by (simp add: length_isort)
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  also have "\<dots> \<le> (length(x#xs) + 1) ^ 2"
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    by (simp add: power2_eq_square)
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  finally show ?case .
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qed
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subsection "Merge Sort"
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fun merge :: "'a::linorder list \<Rightarrow> 'a list \<Rightarrow> 'a list" where
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"merge [] ys = ys" |
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"merge xs [] = xs" |
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"merge (x#xs) (y#ys) = (if x \<le> y then x # merge xs (y#ys) else y # merge (x#xs) ys)"
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fun msort :: "'a::linorder list \<Rightarrow> 'a list" where
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"msort xs = (let n = length xs in
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  if n \<le> 1 then xs
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  else merge (msort (take (n div 2) xs)) (msort (drop (n div 2) xs)))"
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declare msort.simps [simp del]
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subsubsection "Functional Correctness"
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lemma mset_merge: "mset(merge xs ys) = mset xs + mset ys"
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by(induction xs ys rule: merge.induct) auto
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lemma "mset (msort xs) = mset xs"
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proof(induction xs rule: msort.induct)
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  case (1 xs)
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  let ?n = "length xs"
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  let ?xs1 = "take (?n div 2) xs"
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  let ?xs2 = "drop (?n div 2) xs"
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  show ?case
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  proof cases
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    assume "?n \<le> 1"
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    thus ?thesis by(simp add: msort.simps[of xs])
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  next
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    assume "\<not> ?n \<le> 1"
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    hence "mset (msort xs) = mset (msort ?xs1) + mset (msort ?xs2)"
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      by(simp add: msort.simps[of xs] mset_merge)
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    also have "\<dots> = mset ?xs1 + mset ?xs2"
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      using \<open>\<not> ?n \<le> 1\<close> by(simp add: "1.IH")
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    also have "\<dots> = mset (?xs1 @ ?xs2)" by (simp del: append_take_drop_id)
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    also have "\<dots> = mset xs" by simp
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    finally show ?thesis .
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  qed
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qed
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lemma set_merge: "set(merge xs ys) = set xs \<union> set ys"
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by(induction xs ys rule: merge.induct) (auto)
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lemma sorted_merge: "sorted (merge xs ys) \<longleftrightarrow> (sorted xs \<and> sorted ys)"
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by(induction xs ys rule: merge.induct) (auto simp: set_merge)
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lemma "sorted (msort xs)"
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proof(induction xs rule: msort.induct)
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  case (1 xs)
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  let ?n = "length xs"
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  show ?case
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  proof cases
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    assume "?n \<le> 1"
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    thus ?thesis by(simp add: msort.simps[of xs] sorted01)
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  next
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    assume "\<not> ?n \<le> 1"
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    thus ?thesis using "1.IH"
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      by(simp add: sorted_merge  msort.simps[of xs] mset_merge)
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  qed
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qed
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subsubsection "Time Complexity"
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text \<open>We only count the number of comparisons between list elements.\<close>
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fun c_merge :: "'a::linorder list \<Rightarrow> 'a list \<Rightarrow> nat" where
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"c_merge [] ys = 0" |
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"c_merge xs [] = 0" |
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"c_merge (x#xs) (y#ys) = 1 + (if x \<le> y then c_merge xs (y#ys) else c_merge (x#xs) ys)"
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lemma c_merge_ub: "c_merge xs ys \<le> length xs + length ys"
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by (induction xs ys rule: c_merge.induct) auto
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fun c_msort :: "'a::linorder list \<Rightarrow> nat" where
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"c_msort xs =
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  (let n = length xs;
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       ys = take (n div 2) xs;
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       zs = drop (n div 2) xs
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   in if n \<le> 1 then 0
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      else c_msort ys + c_msort zs + c_merge (msort ys) (msort zs))"
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declare c_msort.simps [simp del]
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lemma length_merge: "length(merge xs ys) = length xs + length ys"
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apply (induction xs ys rule: merge.induct)
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apply auto
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done
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lemma length_msort: "length(msort xs) = length xs"
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proof (induction xs rule: msort.induct)
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  case (1 xs)
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  thus ?case by (auto simp: msort.simps[of xs] length_merge)
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qed
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text \<open>Why structured proof?
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   To have the name "xs" to specialize msort.simps with xs
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   to ensure that msort.simps cannot be used recursively.
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Also works without this precaution, but that is just luck.\<close>
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lemma c_msort_le: "length xs = 2^k \<Longrightarrow> c_msort xs \<le> k * 2^k"
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proof(induction k arbitrary: xs)
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  case 0 thus ?case by (simp add: c_msort.simps)
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next
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  case (Suc k)
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  let ?n = "length xs"
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  let ?ys = "take (?n div 2) xs"
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  let ?zs = "drop (?n div 2) xs"
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  show ?case
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  proof (cases "?n \<le> 1")
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    case True
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    thus ?thesis by(simp add: c_msort.simps)
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  next
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    case False
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    have "c_msort(xs) =
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      c_msort ?ys + c_msort ?zs + c_merge (msort ?ys) (msort ?zs)"
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      by (simp add: c_msort.simps msort.simps)
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    also have "\<dots> \<le> c_msort ?ys + c_msort ?zs + length ?ys + length ?zs"
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      using c_merge_ub[of "msort ?ys" "msort ?zs"] length_msort[of ?ys] length_msort[of ?zs]
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      by arith
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    also have "\<dots> \<le> k * 2^k + c_msort ?zs + length ?ys + length ?zs"
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      using Suc.IH[of ?ys] Suc.prems by simp
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    also have "\<dots> \<le> k * 2^k + k * 2^k + length ?ys + length ?zs"
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      using Suc.IH[of ?zs] Suc.prems by simp
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    also have "\<dots> = 2 * k * 2^k + 2 * 2 ^ k"
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      using Suc.prems by simp
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    finally show ?thesis by simp
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  qed
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qed
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(* Beware of conversions: *)
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lemma "length xs = 2^k \<Longrightarrow> c_msort xs \<le> length xs * log 2 (length xs)"
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using c_msort_le[of xs k] apply (simp add: log_nat_power algebra_simps)
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by (metis (mono_tags) numeral_power_eq_of_nat_cancel_iff of_nat_le_iff of_nat_mult)
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subsection "Bottom-Up Merge Sort"
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(* Exercise: make tail recursive *)
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fun merge_adj :: "('a::linorder) list list \<Rightarrow> 'a list list" where
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"merge_adj [] = []" |
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"merge_adj [xs] = [xs]" |
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"merge_adj (xs # ys # zss) = merge xs ys # merge_adj zss"
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text \<open>For the termination proof of \<open>merge_all\<close> below.\<close>
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lemma length_merge_adjacent[simp]: "length (merge_adj xs) = (length xs + 1) div 2"
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by (induction xs rule: merge_adj.induct) auto
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fun merge_all :: "('a::linorder) list list \<Rightarrow> 'a list" where
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"merge_all [] = undefined" |
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"merge_all [xs] = xs" |
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"merge_all xss = merge_all (merge_adj xss)"
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definition msort_bu :: "('a::linorder) list \<Rightarrow> 'a list" where
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"msort_bu xs = (if xs = [] then [] else merge_all (map (\<lambda>x. [x]) xs))"
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subsubsection "Functional Correctness"
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lemma mset_merge_adj:
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  "\<Union># image_mset mset (mset (merge_adj xss)) = \<Union># image_mset mset (mset xss)"
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by(induction xss rule: merge_adj.induct) (auto simp: mset_merge)
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lemma msec_merge_all:
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  "xss \<noteq> [] \<Longrightarrow> mset (merge_all xss) = (\<Union># (mset (map mset xss)))"
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by(induction xss rule: merge_all.induct) (auto simp: mset_merge mset_merge_adj)
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lemma sorted_merge_adj:
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  "\<forall>xs \<in> set xss. sorted xs \<Longrightarrow> \<forall>xs \<in> set (merge_adj xss). sorted xs"
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by(induction xss rule: merge_adj.induct) (auto simp: sorted_merge)
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lemma sorted_merge_all:
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  "\<forall>xs \<in> set xss. sorted xs \<Longrightarrow> xss \<noteq> [] \<Longrightarrow> sorted (merge_all xss)"
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apply(induction xss rule: merge_all.induct)
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using [[simp_depth_limit=3]] by (auto simp add: sorted_merge_adj)
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lemma sorted_msort_bu: "sorted (msort_bu xs)"
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by(simp add: msort_bu_def sorted_merge_all)
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lemma mset_msort: "mset (msort_bu xs) = mset xs"
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by(simp add: msort_bu_def msec_merge_all comp_def)
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subsubsection "Time Complexity"
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fun c_merge_adj :: "('a::linorder) list list \<Rightarrow> nat" where
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"c_merge_adj [] = 0" |
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"c_merge_adj [xs] = 0" |
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"c_merge_adj (xs # ys # zss) = c_merge xs ys + c_merge_adj zss"
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fun c_merge_all :: "('a::linorder) list list \<Rightarrow> nat" where
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"c_merge_all [] = undefined" |
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"c_merge_all [xs] = 0" |
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"c_merge_all xss = c_merge_adj xss + c_merge_all (merge_adj xss)"
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definition c_msort_bu :: "('a::linorder) list \<Rightarrow> nat" where
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"c_msort_bu xs = (if xs = [] then 0 else c_merge_all (map (\<lambda>x. [x]) xs))"
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lemma length_merge_adj:
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  "\<lbrakk> even(length xss); \<forall>x \<in> set xss. length x = m \<rbrakk> \<Longrightarrow> \<forall>xs \<in> set (merge_adj xss). length xs = 2*m"
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by(induction xss rule: merge_adj.induct) (auto simp: length_merge)
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lemma c_merge_adj: "\<forall>xs \<in> set xss. length xs = m \<Longrightarrow> c_merge_adj xss \<le> m * length xss"
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proof(induction xss rule: c_merge_adj.induct)
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  case 1 thus ?case by simp
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next
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  case 2 thus ?case by simp
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next
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  case (3 x y) thus ?case using c_merge_ub[of x y] by (simp add: algebra_simps)
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qed
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lemma c_merge_all: "\<lbrakk> \<forall>xs \<in> set xss. length xs = m; length xss = 2^k \<rbrakk>
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  \<Longrightarrow> c_merge_all xss \<le> m * k * 2^k"
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proof (induction xss arbitrary: k m rule: c_merge_all.induct)
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  case 1 thus ?case by simp
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next
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  case 2 thus ?case by simp
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next
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  case (3 xs ys xss)
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  let ?xss = "xs # ys # xss"
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  let ?xss2 = "merge_adj ?xss"
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  obtain k' where k': "k = Suc k'" using "3.prems"(2)
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    by (metis length_Cons nat.inject nat_power_eq_Suc_0_iff nat.exhaust)
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  have "even (length xss)" using "3.prems"(2) even_Suc_Suc_iff by fastforce
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   332
  from "3.prems"(1) length_merge_adj[OF this]
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   333
  have *: "\<forall>x \<in> set(merge_adj ?xss). length x = 2*m" by(auto simp: length_merge)
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   334
  have **: "length ?xss2 = 2 ^ k'" using "3.prems"(2) k' by auto
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   335
  have "c_merge_all ?xss = c_merge_adj ?xss + c_merge_all ?xss2" by simp
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   336
  also have "\<dots> \<le> m * 2^k + c_merge_all ?xss2"
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   337
    using "3.prems"(2) c_merge_adj[OF "3.prems"(1)] by (auto simp: algebra_simps)
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   338
  also have "\<dots> \<le> m * 2^k + (2*m) * k' * 2^k'"
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   339
    using "3.IH"[OF * **] by simp
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  also have "\<dots> = m * k * 2^k"
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   341
    using k' by (simp add: algebra_simps)
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  finally show ?case .
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qed
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   344
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corollary c_msort_bu: "length xs = 2 ^ k \<Longrightarrow> c_msort_bu xs \<le> k * 2 ^ k"
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using c_merge_all[of "map (\<lambda>x. [x]) xs" 1] by (simp add: c_msort_bu_def)
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   347
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end