src/HOL/Metis_Examples/Abstraction.thy
author haftmann
Sat, 24 Dec 2011 15:53:11 +0100
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child 46076 a109eb27f54f
permissions -rw-r--r--
commented out examples which choke on strict set/pred distinction
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(*  Title:      HOL/Metis_Examples/Abstraction.thy
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    Author:     Lawrence C. Paulson, Cambridge University Computer Laboratory
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    Author:     Jasmin Blanchette, TU Muenchen
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Example featuring Metis's support for lambda-abstractions.
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*)
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header {* Example Featuring Metis's Support for Lambda-Abstractions *}
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theory Abstraction
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imports "~~/src/HOL/Library/FuncSet"
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begin
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(* For Christoph Benzmüller *)
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lemma "x < 1 \<and> ((op =) = (op =)) \<Longrightarrow> ((op =) = (op =)) \<and> x < (2::nat)"
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by (metis nat_1_add_1 trans_less_add2)
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lemma "(op = ) = (\<lambda>x y. y = x)"
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by metis
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consts
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  monotone :: "['a => 'a, 'a set, ('a *'a)set] => bool"
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  pset  :: "'a set => 'a set"
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  order :: "'a set => ('a * 'a) set"
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(*lemma "a \<in> {x. P x} \<Longrightarrow> P a"
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proof -
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  assume "a \<in> {x. P x}"
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  thus "P a" by metis
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qed*)
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lemma Collect_triv: "a \<in> {x. P x} \<Longrightarrow> P a"
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by (metis mem_Collect_eq)
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lemma "a \<in> {x. P x --> Q x} \<Longrightarrow> a \<in> {x. P x} \<Longrightarrow> a \<in> {x. Q x}"
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by (metis Collect_imp_eq ComplD UnE)
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(*lemma "(a, b) \<in> Sigma A B \<Longrightarrow> a \<in> A & b \<in> B a"
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proof -
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  assume A1: "(a, b) \<in> Sigma A B"
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  hence F1: "b \<in> B a" by (metis mem_Sigma_iff)
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  have F2: "a \<in> A" by (metis A1 mem_Sigma_iff)
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  have "b \<in> B a" by (metis F1)
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  thus "a \<in> A \<and> b \<in> B a" by (metis F2)
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qed*)
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lemma Sigma_triv: "(a, b) \<in> Sigma A B \<Longrightarrow> a \<in> A & b \<in> B a"
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by (metis SigmaD1 SigmaD2)
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lemma "(a, b) \<in> (SIGMA x:A. {y. x = f y}) \<Longrightarrow> a \<in> A \<and> a = f b"
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by (metis (full_types, lam_lifting) CollectD SigmaD1 SigmaD2)
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(*lemma "(a, b) \<in> (SIGMA x:A. {y. x = f y}) \<Longrightarrow> a \<in> A \<and> a = f b"
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proof -
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  assume A1: "(a, b) \<in> (SIGMA x:A. {y. x = f y})"
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  hence F1: "a \<in> A" by (metis mem_Sigma_iff)
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  have "b \<in> {R. a = f R}" by (metis A1 mem_Sigma_iff)
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  hence F2: "b \<in> (\<lambda>R. a = f R)" by (metis Collect_def)
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  hence "a = f b" by (unfold mem_def)
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  thus "a \<in> A \<and> a = f b" by (metis F1)
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qed*)
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lemma "(cl, f) \<in> CLF \<Longrightarrow> CLF = (SIGMA cl: CL.{f. f \<in> pset cl}) \<Longrightarrow> f \<in> pset cl"
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by (metis Collect_mem_eq SigmaD2)
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(*lemma "(cl, f) \<in> CLF \<Longrightarrow> CLF = (SIGMA cl: CL.{f. f \<in> pset cl}) \<Longrightarrow> f \<in> pset cl"
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proof -
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  assume A1: "(cl, f) \<in> CLF"
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  assume A2: "CLF = (SIGMA cl:CL. {f. f \<in> pset cl})"
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  have F1: "\<forall>v. (\<lambda>R. R \<in> v) = v" by (metis Collect_mem_eq Collect_def)
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  have "\<forall>v u. (u, v) \<in> CLF \<longrightarrow> v \<in> {R. R \<in> pset u}" by (metis A2 mem_Sigma_iff)
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  hence "\<forall>v u. (u, v) \<in> CLF \<longrightarrow> v \<in> pset u" by (metis F1 Collect_def)
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  thus "f \<in> pset cl" by (metis A1)
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qed*)
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(*lemma
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  "(cl, f) \<in> (SIGMA cl: CL. {f. f \<in> pset cl \<rightarrow> pset cl}) \<Longrightarrow>
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   f \<in> pset cl \<rightarrow> pset cl"
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by (metis (no_types) Sigma_triv)*)
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(*lemma
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  "(cl, f) \<in> (SIGMA cl: CL. {f. f \<in> pset cl \<rightarrow> pset cl}) \<Longrightarrow>
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   f \<in> pset cl \<rightarrow> pset cl"
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proof -
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  assume A1: "(cl, f) \<in> (SIGMA cl:CL. {f. f \<in> pset cl \<rightarrow> pset cl})"
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  have F1: "\<forall>v. (\<lambda>R. R \<in> v) = v" by (metis Collect_mem_eq Collect_def)
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  have "f \<in> {R. R \<in> pset cl \<rightarrow> pset cl}" using A1 by simp
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  thus "f \<in> pset cl \<rightarrow> pset cl" by (metis F1 Collect_def)
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qed*)
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lemma
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  "(cl, f) \<in> (SIGMA cl: CL. {f. f \<in> pset cl \<inter> cl}) \<Longrightarrow>
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   f \<in> pset cl \<inter> cl"
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by (metis (no_types) Collect_conj_eq Int_def Sigma_triv inf_idem)
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(*lemma
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  "(cl, f) \<in> (SIGMA cl: CL. {f. f \<in> pset cl \<inter> cl}) \<Longrightarrow>
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   f \<in> pset cl \<inter> cl"
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proof -
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  assume A1: "(cl, f) \<in> (SIGMA cl:CL. {f. f \<in> pset cl \<inter> cl})"
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  have F1: "\<forall>v. (\<lambda>R. R \<in> v) = v" by (metis Collect_mem_eq Collect_def)
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  have "f \<in> {R. R \<in> pset cl \<inter> cl}" using A1 by simp
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  hence "f \<in> Id_on cl `` pset cl" by (metis F1 Int_commute Image_Id_on Collect_def)
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  hence "f \<in> Id_on cl `` pset cl" by metis
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  hence "f \<in> cl \<inter> pset cl" by (metis Image_Id_on)
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  thus "f \<in> pset cl \<inter> cl" by (metis Int_commute)
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qed*)
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lemma
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  "(cl, f) \<in> (SIGMA cl: CL. {f. f \<in> pset cl \<rightarrow> pset cl & monotone f (pset cl) (order cl)}) \<Longrightarrow>
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   (f \<in> pset cl \<rightarrow> pset cl)  &  (monotone f (pset cl) (order cl))"
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by auto
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(*lemma
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  "(cl, f) \<in> CLF \<Longrightarrow>
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   CLF \<subseteq> (SIGMA cl: CL. {f. f \<in> pset cl \<inter> cl}) \<Longrightarrow>
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   f \<in> pset cl \<inter> cl"
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by (metis (lam_lifting) Sigma_triv subsetD)*)
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(*lemma
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  "(cl, f) \<in> CLF \<Longrightarrow>
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   CLF = (SIGMA cl: CL. {f. f \<in> pset cl \<inter> cl}) \<Longrightarrow>
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   f \<in> pset cl \<inter> cl"
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by (metis (lam_lifting) Int_Collect SigmaD2 inf1I mem_def)*)
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(*lemma
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  "(cl, f) \<in> CLF \<Longrightarrow>
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   CLF \<subseteq> (SIGMA cl': CL. {f. f \<in> pset cl' \<rightarrow> pset cl'}) \<Longrightarrow>
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   f \<in> pset cl \<rightarrow> pset cl"
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by (metis (lam_lifting) Collect_def Sigma_triv mem_def subsetD)*)
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(*lemma
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  "(cl, f) \<in> CLF \<Longrightarrow>
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   CLF = (SIGMA cl: CL. {f. f \<in> pset cl \<rightarrow> pset cl}) \<Longrightarrow>
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   f \<in> pset cl \<rightarrow> pset cl"
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by (metis (lam_lifting) Collect_def Sigma_triv mem_def)*)
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(*lemma
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  "(cl, f) \<in> CLF \<Longrightarrow>
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   CLF = (SIGMA cl: CL. {f. f \<in> pset cl \<rightarrow> pset cl & monotone f (pset cl) (order cl)}) \<Longrightarrow>
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   (f \<in> pset cl \<rightarrow> pset cl) & (monotone f (pset cl) (order cl))"
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by auto*)
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lemma "map (\<lambda>x. (f x, g x)) xs = zip (map f xs) (map g xs)"
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apply (induct xs)
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 apply (metis map.simps(1) zip_Nil)
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by auto
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lemma
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  "map (\<lambda>w. (w -> w, w \<times> w)) xs =
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   zip (map (\<lambda>w. w -> w) xs) (map (\<lambda>w. w \<times> w) xs)"
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apply (induct xs)
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 apply (metis map.simps(1) zip_Nil)
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by auto
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(*lemma "(\<lambda>x. Suc (f x)) ` {x. even x} \<subseteq> A \<Longrightarrow> \<forall>x. even x --> Suc (f x) \<in> A"
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by (metis Collect_def image_eqI mem_def subsetD)*)
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(*lemma
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  "(\<lambda>x. f (f x)) ` ((\<lambda>x. Suc(f x)) ` {x. even x}) \<subseteq> A \<Longrightarrow>
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   (\<forall>x. even x --> f (f (Suc(f x))) \<in> A)"
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by (metis Collect_def imageI mem_def set_rev_mp)*)
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(*lemma "f \<in> (\<lambda>u v. b \<times> u \<times> v) ` A \<Longrightarrow> \<forall>u v. P (b \<times> u \<times> v) \<Longrightarrow> P(f y)"
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by (metis (lam_lifting) imageE)*)
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lemma image_TimesA: "(\<lambda>(x, y). (f x, g y)) ` (A \<times> B) = (f ` A) \<times> (g ` B)"
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by (metis map_pair_def map_pair_surj_on)
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lemma image_TimesB:
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    "(\<lambda>(x, y, z). (f x, g y, h z)) ` (A \<times> B \<times> C) = (f ` A) \<times> (g ` B) \<times> (h ` C)"
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by force
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lemma image_TimesC:
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  "(\<lambda>(x, y). (x \<rightarrow> x, y \<times> y)) ` (A \<times> B) =
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   ((\<lambda>x. x \<rightarrow> x) ` A) \<times> ((\<lambda>y. y \<times> y) ` B)"
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by (metis image_TimesA)
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end