src/FOL/ex/Foundation.thy
author wenzelm
Thu, 03 Jan 2019 22:19:19 +0100
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isabelle update_inner_syntax_cartouches;
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(*  Title:      FOL/ex/Foundation.thy
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    Author:     Lawrence C Paulson, Cambridge University Computer Laboratory
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    Copyright   1991  University of Cambridge
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*)
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section "Intuitionistic FOL: Examples from The Foundation of a Generic Theorem Prover"
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theory Foundation
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imports IFOL
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begin
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lemma \<open>A \<and> B \<longrightarrow> (C \<longrightarrow> A \<and> C)\<close>
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apply (rule impI)
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apply (rule impI)
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apply (rule conjI)
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prefer 2 apply assumption
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apply (rule conjunct1)
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apply assumption
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done
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text \<open>A form of conj-elimination\<close>
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lemma
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  assumes \<open>A \<and> B\<close>
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    and \<open>A \<Longrightarrow> B \<Longrightarrow> C\<close>
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  shows \<open>C\<close>
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apply (rule assms)
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apply (rule conjunct1)
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apply (rule assms)
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apply (rule conjunct2)
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apply (rule assms)
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done
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lemma
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  assumes \<open>\<And>A. \<not> \<not> A \<Longrightarrow> A\<close>
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  shows \<open>B \<or> \<not> B\<close>
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apply (rule assms)
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apply (rule notI)
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apply (rule_tac P = \<open>\<not> B\<close> in notE)
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apply (rule_tac [2] notI)
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apply (rule_tac [2] P = \<open>B \<or> \<not> B\<close> in notE)
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prefer 2 apply assumption
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apply (rule_tac [2] disjI1)
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prefer 2 apply assumption
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apply (rule notI)
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apply (rule_tac P = \<open>B \<or> \<not> B\<close> in notE)
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apply assumption
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apply (rule disjI2)
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apply assumption
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done
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lemma
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  assumes \<open>\<And>A. \<not> \<not> A \<Longrightarrow> A\<close>
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  shows \<open>B \<or> \<not> B\<close>
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apply (rule assms)
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apply (rule notI)
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apply (rule notE)
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apply (rule_tac [2] notI)
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apply (erule_tac [2] notE)
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apply (erule_tac [2] disjI1)
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apply (rule notI)
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apply (erule notE)
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apply (erule disjI2)
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done
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lemma
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  assumes \<open>A \<or> \<not> A\<close>
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    and \<open>\<not> \<not> A\<close>
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  shows \<open>A\<close>
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apply (rule disjE)
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apply (rule assms)
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apply assumption
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apply (rule FalseE)
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apply (rule_tac P = \<open>\<not> A\<close> in notE)
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apply (rule assms)
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apply assumption
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done
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subsection "Examples with quantifiers"
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lemma
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  assumes \<open>\<forall>z. G(z)\<close>
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  shows \<open>\<forall>z. G(z) \<or> H(z)\<close>
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apply (rule allI)
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apply (rule disjI1)
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apply (rule assms [THEN spec])
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done
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lemma \<open>\<forall>x. \<exists>y. x = y\<close>
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apply (rule allI)
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apply (rule exI)
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apply (rule refl)
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done
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lemma \<open>\<exists>y. \<forall>x. x = y\<close>
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apply (rule exI)
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apply (rule allI)
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apply (rule refl)?
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oops
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text \<open>Parallel lifting example.\<close>
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lemma \<open>\<exists>u. \<forall>x. \<exists>v. \<forall>y. \<exists>w. P(u,x,v,y,w)\<close>
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apply (rule exI allI)
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apply (rule exI allI)
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apply (rule exI allI)
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apply (rule exI allI)
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apply (rule exI allI)
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oops
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lemma
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  assumes \<open>(\<exists>z. F(z)) \<and> B\<close>
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  shows \<open>\<exists>z. F(z) \<and> B\<close>
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apply (rule conjE)
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apply (rule assms)
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apply (rule exE)
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apply assumption
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apply (rule exI)
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apply (rule conjI)
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apply assumption
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apply assumption
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done
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text \<open>A bigger demonstration of quantifiers -- not in the paper.\<close>
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lemma \<open>(\<exists>y. \<forall>x. Q(x,y)) \<longrightarrow> (\<forall>x. \<exists>y. Q(x,y))\<close>
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apply (rule impI)
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apply (rule allI)
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apply (rule exE, assumption)
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apply (rule exI)
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apply (rule allE, assumption)
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apply assumption
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done
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end