src/HOL/Real/ex/Sqrt.thy
changeset 13030 5765aa72afac
parent 13029 84e4ba7fb033
child 13031 3f7824dd8ddf
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     1 (*  Title:      HOL/Real/ex/Sqrt.thy
       
     2     ID:         $Id$
       
     3     Author:     Markus Wenzel, TU Muenchen
       
     4     License:    GPL (GNU GENERAL PUBLIC LICENSE)
       
     5 *)
       
     6 
       
     7 header {*  Square roots of primes are irrational *}
       
     8 
       
     9 theory Sqrt = Primes + Real:
       
    10 
       
    11 subsection {* The set of rational numbers *}
       
    12 
       
    13 constdefs
       
    14   rationals :: "real set"    ("\<rat>")
       
    15   "\<rat> == {x. \<exists>m n. n \<noteq> 0 \<and> \<bar>x\<bar> = real (m::nat) / real (n::nat)}"
       
    16 
       
    17 theorem rationals_rep: "x \<in> \<rat> ==>
       
    18   \<exists>m n. n \<noteq> 0 \<and> \<bar>x\<bar> = real m / real n \<and> gcd (m, n) = 1"
       
    19 proof -
       
    20   assume "x \<in> \<rat>"
       
    21   then obtain m n :: nat where n: "n \<noteq> 0" and x_rat: "\<bar>x\<bar> = real m / real n"
       
    22     by (unfold rationals_def) blast
       
    23   let ?gcd = "gcd (m, n)"
       
    24   from n have gcd: "?gcd \<noteq> 0" by (simp add: gcd_zero)
       
    25   let ?k = "m div ?gcd"
       
    26   let ?l = "n div ?gcd"
       
    27   let ?gcd' = "gcd (?k, ?l)"
       
    28   have "?gcd dvd m" .. hence gcd_k: "?gcd * ?k = m"
       
    29     by (rule dvd_mult_div_cancel)
       
    30   have "?gcd dvd n" .. hence gcd_l: "?gcd * ?l = n"
       
    31     by (rule dvd_mult_div_cancel)
       
    32 
       
    33   from n gcd_l have "?l \<noteq> 0"
       
    34     by (auto iff del: neq0_conv)
       
    35   moreover
       
    36   have "\<bar>x\<bar> = real ?k / real ?l"
       
    37   proof -
       
    38     from gcd have "real ?k / real ?l = real (?gcd * ?k) / real (?gcd * ?l)"
       
    39       by (simp add: real_mult_div_cancel1)
       
    40     also from gcd_k gcd_l have "... = real m / real n" by simp
       
    41     also from x_rat have "... = \<bar>x\<bar>" ..
       
    42     finally show ?thesis ..
       
    43   qed
       
    44   moreover
       
    45   have "?gcd' = 1"
       
    46   proof -
       
    47     have "?gcd * ?gcd' = gcd (?gcd * ?k, ?gcd * ?l)"
       
    48       by (rule gcd_mult_distrib2)
       
    49     with gcd_k gcd_l have "?gcd * ?gcd' = ?gcd" by simp
       
    50     with gcd show ?thesis by simp
       
    51   qed
       
    52   ultimately show ?thesis by blast
       
    53 qed
       
    54 
       
    55 lemma [elim?]: "r \<in> \<rat> ==>
       
    56   (!!m n. n \<noteq> 0 ==> \<bar>r\<bar> = real m / real n ==> gcd (m, n) = 1 ==> C)
       
    57     ==> C"
       
    58   by (insert rationals_rep) blast
       
    59 
       
    60 
       
    61 subsection {* Main theorem *}
       
    62 
       
    63 text {*
       
    64   The square root of any prime number (including @{text 2}) is
       
    65   irrational.
       
    66 *}
       
    67 
       
    68 theorem sqrt_prime_irrational: "x\<twosuperior> = real p ==> p \<in> prime ==> x \<notin> \<rat>"
       
    69 proof
       
    70   assume x_sqrt: "x\<twosuperior> = real p"
       
    71   assume p_prime: "p \<in> prime"
       
    72   hence p: "1 < p" by (simp add: prime_def)
       
    73   assume "x \<in> \<rat>"
       
    74   then obtain m n where
       
    75     n: "n \<noteq> 0" and x_rat: "\<bar>x\<bar> = real m / real n" and gcd: "gcd (m, n) = 1" ..
       
    76   have eq: "m\<twosuperior> = p * n\<twosuperior>"
       
    77   proof -
       
    78     from n x_rat have "real m = \<bar>x\<bar> * real n" by simp
       
    79     hence "real (m\<twosuperior>) = x\<twosuperior> * real (n\<twosuperior>)"
       
    80       by (simp add: power_two real_power_two split: abs_split)
       
    81     also from x_sqrt have "... = real (p * n\<twosuperior>)" by simp
       
    82     finally show ?thesis ..
       
    83   qed
       
    84   have "p dvd m \<and> p dvd n"
       
    85   proof
       
    86     from eq have "p dvd m\<twosuperior>" ..
       
    87     with p_prime show "p dvd m" by (rule prime_dvd_power_two)
       
    88     then obtain k where "m = p * k" ..
       
    89     with eq have "p * n\<twosuperior> = p\<twosuperior> * k\<twosuperior>" by (auto simp add: power_two mult_ac)
       
    90     with p have "n\<twosuperior> = p * k\<twosuperior>" by (simp add: power_two)
       
    91     hence "p dvd n\<twosuperior>" ..
       
    92     with p_prime show "p dvd n" by (rule prime_dvd_power_two)
       
    93   qed
       
    94   hence "p dvd gcd (m, n)" ..
       
    95   with gcd have "p dvd 1" by simp
       
    96   hence "p \<le> 1" by (simp add: dvd_imp_le)
       
    97   with p show False by simp
       
    98 qed
       
    99 
       
   100 
       
   101 subsection {* Variations *}
       
   102 
       
   103 text {*
       
   104   Just for the record: we instantiate the main theorem for the
       
   105   specific prime number @{text 2} (real mathematicians would never do
       
   106   this formally :-).
       
   107 *}
       
   108 
       
   109 theorem "x\<twosuperior> = real (2::nat) ==> x \<notin> \<rat>"
       
   110 proof (rule sqrt_prime_irrational)
       
   111   {
       
   112     fix m :: nat assume dvd: "m dvd 2"
       
   113     hence "m \<le> 2" by (simp add: dvd_imp_le)
       
   114     moreover from dvd have "m \<noteq> 0" by (auto iff del: neq0_conv)
       
   115     ultimately have "m = 1 \<or> m = 2" by arith
       
   116   }
       
   117   thus "2 \<in> prime" by (simp add: prime_def)
       
   118 qed
       
   119 
       
   120 text {*
       
   121   \medskip An alternative version of the main proof, using mostly
       
   122   linear forward-reasoning.  While this results in less top-down
       
   123   structure, it is probably closer to proofs seen in mathematics.
       
   124 *}
       
   125 
       
   126 theorem "x\<twosuperior> = real p ==> p \<in> prime ==> x \<notin> \<rat>"
       
   127 proof
       
   128   assume x_sqrt: "x\<twosuperior> = real p"
       
   129   assume p_prime: "p \<in> prime"
       
   130   hence p: "1 < p" by (simp add: prime_def)
       
   131   assume "x \<in> \<rat>"
       
   132   then obtain m n where
       
   133     n: "n \<noteq> 0" and x_rat: "\<bar>x\<bar> = real m / real n" and gcd: "gcd (m, n) = 1" ..
       
   134   from n x_rat have "real m = \<bar>x\<bar> * real n" by simp
       
   135   hence "real (m\<twosuperior>) = x\<twosuperior> * real (n\<twosuperior>)"
       
   136     by (simp add: power_two real_power_two split: abs_split)
       
   137   also from x_sqrt have "... = real (p * n\<twosuperior>)" by simp
       
   138   finally have eq: "m\<twosuperior> = p * n\<twosuperior>" ..
       
   139   hence "p dvd m\<twosuperior>" ..
       
   140   with p_prime have dvd_m: "p dvd m" by (rule prime_dvd_power_two)
       
   141   then obtain k where "m = p * k" ..
       
   142   with eq have "p * n\<twosuperior> = p\<twosuperior> * k\<twosuperior>" by (auto simp add: power_two mult_ac)
       
   143   with p have "n\<twosuperior> = p * k\<twosuperior>" by (simp add: power_two)
       
   144   hence "p dvd n\<twosuperior>" ..
       
   145   with p_prime have "p dvd n" by (rule prime_dvd_power_two)
       
   146   with dvd_m have "p dvd gcd (m, n)" by (rule gcd_greatest)
       
   147   with gcd have "p dvd 1" by simp
       
   148   hence "p \<le> 1" by (simp add: dvd_imp_le)
       
   149   with p show False by simp
       
   150 qed
       
   151 
       
   152 end