(* Title: HOL/ex/ReflectionEx.thy
Author: Amine Chaieb, TU Muenchen
*)
header {* Examples for generic reflection and reification *}
theory ReflectionEx
imports Reflection
begin
text{* This theory presents two methods: reify and reflection *}
text{*
Consider an HOL type 'a, the structure of which is not recongnisable on the theory level. This is the case of bool, arithmetical terms such as int, real etc \dots
In order to implement a simplification on terms of type 'a we often need its structure.
Traditionnaly such simplifications are written in ML, proofs are synthesized.
An other strategy is to declare an HOL-datatype tau and an HOL function (the interpretation) that maps elements of tau to elements of 'a. The functionality of @{text reify} is to compute a term s::tau, which is the representant of t. For this it needs equations for the interpretation.
NB: All the interpretations supported by @{text reify} must have the type @{text "'b list \<Rightarrow> tau \<Rightarrow> 'a"}.
The method @{text reify} can also be told which subterm of the current subgoal should be reified. The general call for @{text reify} is: @{text "reify eqs (t)"}, where @{text eqs} are the defining equations of the interpretation and @{text "(t)"} is an optional parameter which specifies the subterm to which reification should be applied to. If @{text "(t)"} is abscent, @{text reify} tries to reify the whole subgoal.
The method reflection uses @{text reify} and has a very similar signature: @{text "reflection corr_thm eqs (t)"}. Here again @{text eqs} and @{text "(t)"} are as described above and @{text corr_thm} is a thorem proving @{term "I vs (f t) = I vs t"}. We assume that @{text I} is the interpretation and @{text f} is some useful and executable simplification of type @{text "tau \<Rightarrow> tau"}. The method @{text reflection} applies reification and hence the theorem @{term "t = I xs s"} and hence using @{text corr_thm} derives @{term "t = I xs (f s)"}. It then uses normalization by evaluation to prove @{term "f s = s'"} which almost finishes the proof of @{term "t = t'"} where @{term "I xs s' = t'"}.
*}
text{* Example 1 : Propositional formulae and NNF.*}
text{* The type @{text fm} represents simple propositional formulae: *}
datatype form = TrueF | FalseF | Less nat nat |
And form form | Or form form | Neg form | ExQ form
fun interp :: "form \<Rightarrow> ('a::ord) list \<Rightarrow> bool" where
"interp TrueF e = True" |
"interp FalseF e = False" |
"interp (Less i j) e = (e!i < e!j)" |
"interp (And f1 f2) e = (interp f1 e & interp f2 e)" |
"interp (Or f1 f2) e = (interp f1 e | interp f2 e)" |
"interp (Neg f) e = (~ interp f e)" |
"interp (ExQ f) e = (EX x. interp f (x#e))"
lemmas interp_reify_eqs = interp.simps
declare interp_reify_eqs[reify]
lemma "EX x. x < y & x < z"
apply (reify )
oops
datatype fm = And fm fm | Or fm fm | Imp fm fm | Iff fm fm | NOT fm | At nat
consts Ifm :: "fm \<Rightarrow> bool list \<Rightarrow> bool"
primrec
"Ifm (At n) vs = vs!n"
"Ifm (And p q) vs = (Ifm p vs \<and> Ifm q vs)"
"Ifm (Or p q) vs = (Ifm p vs \<or> Ifm q vs)"
"Ifm (Imp p q) vs = (Ifm p vs \<longrightarrow> Ifm q vs)"
"Ifm (Iff p q) vs = (Ifm p vs = Ifm q vs)"
"Ifm (NOT p) vs = (\<not> (Ifm p vs))"
lemma "Q \<longrightarrow> (D & F & ((~ D) & (~ F)))"
apply (reify Ifm.simps)
oops
text{* Method @{text reify} maps a bool to an fm. For this it needs the
semantics of fm, i.e.\ the rewrite rules in @{text Ifm.simps}. *}
(* You can also just pick up a subterm to reify \<dots> *)
lemma "Q \<longrightarrow> (D & F & ((~ D) & (~ F)))"
apply (reify Ifm.simps ("((~ D) & (~ F))"))
oops
text{* Let's perform NNF. This is a version that tends to generate disjunctions *}
consts fmsize :: "fm \<Rightarrow> nat"
primrec
"fmsize (At n) = 1"
"fmsize (NOT p) = 1 + fmsize p"
"fmsize (And p q) = 1 + fmsize p + fmsize q"
"fmsize (Or p q) = 1 + fmsize p + fmsize q"
"fmsize (Imp p q) = 2 + fmsize p + fmsize q"
"fmsize (Iff p q) = 2 + 2* fmsize p + 2* fmsize q"
consts nnf :: "fm \<Rightarrow> fm"
recdef nnf "measure fmsize"
"nnf (At n) = At n"
"nnf (And p q) = And (nnf p) (nnf q)"
"nnf (Or p q) = Or (nnf p) (nnf q)"
"nnf (Imp p q) = Or (nnf (NOT p)) (nnf q)"
"nnf (Iff p q) = Or (And (nnf p) (nnf q)) (And (nnf (NOT p)) (nnf (NOT q)))"
"nnf (NOT (And p q)) = Or (nnf (NOT p)) (nnf (NOT q))"
"nnf (NOT (Or p q)) = And (nnf (NOT p)) (nnf (NOT q))"
"nnf (NOT (Imp p q)) = And (nnf p) (nnf (NOT q))"
"nnf (NOT (Iff p q)) = Or (And (nnf p) (nnf (NOT q))) (And (nnf (NOT p)) (nnf q))"
"nnf (NOT (NOT p)) = nnf p"
"nnf (NOT p) = NOT p"
text{* The correctness theorem of nnf: it preserves the semantics of fm *}
lemma nnf[reflection]: "Ifm (nnf p) vs = Ifm p vs"
by (induct p rule: nnf.induct) auto
text{* Now let's perform NNF using our @{term nnf} function defined above. First to the whole subgoal. *}
lemma "(\<not> (A = B)) \<and> (B \<longrightarrow> (A \<noteq> (B | C \<and> (B \<longrightarrow> A | D)))) \<longrightarrow> A \<or> B \<and> D"
apply (reflection Ifm.simps)
oops
text{* Now we specify on which subterm it should be applied*}
lemma "(\<not> (A = B)) \<and> (B \<longrightarrow> (A \<noteq> (B | C \<and> (B \<longrightarrow> A | D)))) \<longrightarrow> A \<or> B \<and> D"
apply (reflection Ifm.simps only: "(B | C \<and> (B \<longrightarrow> A | D))")
oops
(* Example 2 : Simple arithmetic formulae *)
text{* The type @{text num} reflects linear expressions over natural number *}
datatype num = C nat | Add num num | Mul nat num | Var nat | CN nat nat num
text{* This is just technical to make recursive definitions easier. *}
consts num_size :: "num \<Rightarrow> nat"
primrec
"num_size (C c) = 1"
"num_size (Var n) = 1"
"num_size (Add a b) = 1 + num_size a + num_size b"
"num_size (Mul c a) = 1 + num_size a"
"num_size (CN n c a) = 4 + num_size a "
text{* The semantics of num *}
consts Inum:: "num \<Rightarrow> nat list \<Rightarrow> nat"
primrec
Inum_C : "Inum (C i) vs = i"
Inum_Var: "Inum (Var n) vs = vs!n"
Inum_Add: "Inum (Add s t) vs = Inum s vs + Inum t vs "
Inum_Mul: "Inum (Mul c t) vs = c * Inum t vs "
Inum_CN : "Inum (CN n c t) vs = c*(vs!n) + Inum t vs "
text{* Let's reify some nat expressions \dots *}
lemma "4 * (2*x + (y::nat)) + f a \<noteq> 0"
apply (reify Inum.simps ("4 * (2*x + (y::nat)) + f a"))
oops
text{* We're in a bad situation!! x, y and f a have been recongnized as a constants, which is correct but does not correspond to our intuition of the constructor C. It should encapsulate constants, i.e. numbers, i.e. numerals.*}
text{* So let's leave the @{text "Inum_C"} equation at the end and see what happens \dots*}
lemma "4 * (2*x + (y::nat)) \<noteq> 0"
apply (reify Inum_Var Inum_Add Inum_Mul Inum_CN Inum_C ("4 * (2*x + (y::nat))"))
oops
text{* Hmmm let's specialize @{text Inum_C} with numerals.*}
lemma Inum_number: "Inum (C (number_of t)) vs = number_of t" by simp
lemmas Inum_eqs = Inum_Var Inum_Add Inum_Mul Inum_CN Inum_number
text{* Second attempt *}
lemma "1 * (2*x + (y::nat)) \<noteq> 0"
apply (reify Inum_eqs ("1 * (2*x + (y::nat))"))
oops
text{* That was fine, so let's try another one \dots *}
lemma "1 * (2* x + (y::nat) + 0 + 1) \<noteq> 0"
apply (reify Inum_eqs ("1 * (2*x + (y::nat) + 0 + 1)"))
oops
text{* Oh!! 0 is not a variable \dots\ Oh! 0 is not a @{text "number_of"} \dots\ thing. The same for 1. So let's add those equations too *}
lemma Inum_01: "Inum (C 0) vs = 0" "Inum (C 1) vs = 1" "Inum (C(Suc n)) vs = Suc n"
by simp+
lemmas Inum_eqs'= Inum_eqs Inum_01
text{* Third attempt: *}
lemma "1 * (2*x + (y::nat) + 0 + 1) \<noteq> 0"
apply (reify Inum_eqs' ("1 * (2*x + (y::nat) + 0 + 1)"))
oops
text{* Okay, let's try reflection. Some simplifications on num follow. You can skim until the main theorem @{text linum} *}
consts lin_add :: "num \<times> num \<Rightarrow> num"
recdef lin_add "measure (\<lambda>(x,y). ((size x) + (size y)))"
"lin_add (CN n1 c1 r1,CN n2 c2 r2) =
(if n1=n2 then
(let c = c1 + c2
in (if c=0 then lin_add(r1,r2) else CN n1 c (lin_add (r1,r2))))
else if n1 \<le> n2 then (CN n1 c1 (lin_add (r1,CN n2 c2 r2)))
else (CN n2 c2 (lin_add (CN n1 c1 r1,r2))))"
"lin_add (CN n1 c1 r1,t) = CN n1 c1 (lin_add (r1, t))"
"lin_add (t,CN n2 c2 r2) = CN n2 c2 (lin_add (t,r2))"
"lin_add (C b1, C b2) = C (b1+b2)"
"lin_add (a,b) = Add a b"
lemma lin_add: "Inum (lin_add (t,s)) bs = Inum (Add t s) bs"
apply (induct t s rule: lin_add.induct, simp_all add: Let_def)
apply (case_tac "c1+c2 = 0",case_tac "n1 \<le> n2", simp_all)
by (case_tac "n1 = n2", simp_all add: algebra_simps)
consts lin_mul :: "num \<Rightarrow> nat \<Rightarrow> num"
recdef lin_mul "measure size "
"lin_mul (C j) = (\<lambda> i. C (i*j))"
"lin_mul (CN n c a) = (\<lambda> i. if i=0 then (C 0) else CN n (i*c) (lin_mul a i))"
"lin_mul t = (\<lambda> i. Mul i t)"
lemma lin_mul: "Inum (lin_mul t i) bs = Inum (Mul i t) bs"
by (induct t arbitrary: i rule: lin_mul.induct, auto simp add: algebra_simps)
consts linum:: "num \<Rightarrow> num"
recdef linum "measure num_size"
"linum (C b) = C b"
"linum (Var n) = CN n 1 (C 0)"
"linum (Add t s) = lin_add (linum t, linum s)"
"linum (Mul c t) = lin_mul (linum t) c"
"linum (CN n c t) = lin_add (linum (Mul c (Var n)),linum t)"
lemma linum[reflection] : "Inum (linum t) bs = Inum t bs"
by (induct t rule: linum.induct, simp_all add: lin_mul lin_add)
text{* Now we can use linum to simplify nat terms using reflection *}
lemma "(Suc (Suc 1)) * (x + (Suc 1)*y) = 3*x + 6*y"
apply (reflection Inum_eqs' only: "(Suc (Suc 1)) * (x + (Suc 1)*y)")
oops
text{* Let's lift this to formulae and see what happens *}
datatype aform = Lt num num | Eq num num | Ge num num | NEq num num |
Conj aform aform | Disj aform aform | NEG aform | T | F
consts linaformsize:: "aform \<Rightarrow> nat"
recdef linaformsize "measure size"
"linaformsize T = 1"
"linaformsize F = 1"
"linaformsize (Lt a b) = 1"
"linaformsize (Ge a b) = 1"
"linaformsize (Eq a b) = 1"
"linaformsize (NEq a b) = 1"
"linaformsize (NEG p) = 2 + linaformsize p"
"linaformsize (Conj p q) = 1 + linaformsize p + linaformsize q"
"linaformsize (Disj p q) = 1 + linaformsize p + linaformsize q"
consts is_aform :: "aform => nat list => bool"
primrec
"is_aform T vs = True"
"is_aform F vs = False"
"is_aform (Lt a b) vs = (Inum a vs < Inum b vs)"
"is_aform (Eq a b) vs = (Inum a vs = Inum b vs)"
"is_aform (Ge a b) vs = (Inum a vs \<ge> Inum b vs)"
"is_aform (NEq a b) vs = (Inum a vs \<noteq> Inum b vs)"
"is_aform (NEG p) vs = (\<not> (is_aform p vs))"
"is_aform (Conj p q) vs = (is_aform p vs \<and> is_aform q vs)"
"is_aform (Disj p q) vs = (is_aform p vs \<or> is_aform q vs)"
text{* Let's reify and do reflection *}
lemma "(3::nat)*x + t < 0 \<and> (2 * x + y \<noteq> 17)"
apply (reify Inum_eqs' is_aform.simps)
oops
text{* Note that reification handles several interpretations at the same time*}
lemma "(3::nat)*x + t < 0 & x*x + t*x + 3 + 1 = z*t*4*z | x + x + 1 < 0"
apply (reflection Inum_eqs' is_aform.simps only:"x + x + 1")
oops
text{* For reflection we now define a simple transformation on aform: NNF + linum on atoms *}
consts linaform:: "aform \<Rightarrow> aform"
recdef linaform "measure linaformsize"
"linaform (Lt s t) = Lt (linum s) (linum t)"
"linaform (Eq s t) = Eq (linum s) (linum t)"
"linaform (Ge s t) = Ge (linum s) (linum t)"
"linaform (NEq s t) = NEq (linum s) (linum t)"
"linaform (Conj p q) = Conj (linaform p) (linaform q)"
"linaform (Disj p q) = Disj (linaform p) (linaform q)"
"linaform (NEG T) = F"
"linaform (NEG F) = T"
"linaform (NEG (Lt a b)) = Ge a b"
"linaform (NEG (Ge a b)) = Lt a b"
"linaform (NEG (Eq a b)) = NEq a b"
"linaform (NEG (NEq a b)) = Eq a b"
"linaform (NEG (NEG p)) = linaform p"
"linaform (NEG (Conj p q)) = Disj (linaform (NEG p)) (linaform (NEG q))"
"linaform (NEG (Disj p q)) = Conj (linaform (NEG p)) (linaform (NEG q))"
"linaform p = p"
lemma linaform: "is_aform (linaform p) vs = is_aform p vs"
by (induct p rule: linaform.induct) (auto simp add: linum)
lemma "(((Suc(Suc (Suc 0)))*((x::nat) + (Suc (Suc 0)))) + (Suc (Suc (Suc 0))) * ((Suc(Suc (Suc 0)))*((x::nat) + (Suc (Suc 0))))< 0) \<and> (Suc 0 + Suc 0< 0)"
apply (reflection Inum_eqs' is_aform.simps rules: linaform)
oops
declare linaform[reflection]
lemma "(((Suc(Suc (Suc 0)))*((x::nat) + (Suc (Suc 0)))) + (Suc (Suc (Suc 0))) * ((Suc(Suc (Suc 0)))*((x::nat) + (Suc (Suc 0))))< 0) \<and> (Suc 0 + Suc 0< 0)"
apply (reflection Inum_eqs' is_aform.simps)
oops
text{* We now give an example where Interpretaions have 0 or more than only one envornement of different types and show that automatic reification also deals with binding *}
datatype rb = BC bool| BAnd rb rb | BOr rb rb
consts Irb :: "rb \<Rightarrow> bool"
primrec
"Irb (BC p) = p"
"Irb (BAnd s t) = (Irb s \<and> Irb t)"
"Irb (BOr s t) = (Irb s \<or> Irb t)"
lemma "A \<and> (B \<or> D \<and> B) \<and> A \<and> (B \<or> D \<and> B) \<or> A \<and> (B \<or> D \<and> B) \<or> A \<and> (B \<or> D \<and> B)"
apply (reify Irb.simps)
oops
datatype rint = IC int| IVar nat | IAdd rint rint | IMult rint rint | INeg rint | ISub rint rint
consts Irint :: "rint \<Rightarrow> int list \<Rightarrow> int"
primrec
Irint_Var: "Irint (IVar n) vs = vs!n"
Irint_Neg: "Irint (INeg t) vs = - Irint t vs"
Irint_Add: "Irint (IAdd s t) vs = Irint s vs + Irint t vs"
Irint_Sub: "Irint (ISub s t) vs = Irint s vs - Irint t vs"
Irint_Mult: "Irint (IMult s t) vs = Irint s vs * Irint t vs"
Irint_C: "Irint (IC i) vs = i"
lemma Irint_C0: "Irint (IC 0) vs = 0"
by simp
lemma Irint_C1: "Irint (IC 1) vs = 1"
by simp
lemma Irint_Cnumberof: "Irint (IC (number_of x)) vs = number_of x"
by simp
lemmas Irint_simps = Irint_Var Irint_Neg Irint_Add Irint_Sub Irint_Mult Irint_C0 Irint_C1 Irint_Cnumberof
lemma "(3::int) * x + y*y - 9 + (- z) = 0"
apply (reify Irint_simps ("(3::int) * x + y*y - 9 + (- z)"))
oops
datatype rlist = LVar nat| LEmpty| LCons rint rlist | LAppend rlist rlist
consts Irlist :: "rlist \<Rightarrow> int list \<Rightarrow> (int list) list \<Rightarrow> (int list)"
primrec
"Irlist (LEmpty) is vs = []"
"Irlist (LVar n) is vs = vs!n"
"Irlist (LCons i t) is vs = ((Irint i is)#(Irlist t is vs))"
"Irlist (LAppend s t) is vs = (Irlist s is vs) @ (Irlist t is vs)"
lemma "[(1::int)] = []"
apply (reify Irlist.simps Irint_simps ("[1]:: int list"))
oops
lemma "([(3::int) * x + y*y - 9 + (- z)] @ []) @ xs = [y*y - z - 9 + (3::int) * x]"
apply (reify Irlist.simps Irint_simps ("([(3::int) * x + y*y - 9 + (- z)] @ []) @ xs"))
oops
datatype rnat = NC nat| NVar nat| NSuc rnat | NAdd rnat rnat | NMult rnat rnat | NNeg rnat | NSub rnat rnat | Nlgth rlist
consts Irnat :: "rnat \<Rightarrow> int list \<Rightarrow> (int list) list \<Rightarrow> nat list \<Rightarrow> nat"
primrec
Irnat_Suc: "Irnat (NSuc t) is ls vs = Suc (Irnat t is ls vs)"
Irnat_Var: "Irnat (NVar n) is ls vs = vs!n"
Irnat_Neg: "Irnat (NNeg t) is ls vs = 0"
Irnat_Add: "Irnat (NAdd s t) is ls vs = Irnat s is ls vs + Irnat t is ls vs"
Irnat_Sub: "Irnat (NSub s t) is ls vs = Irnat s is ls vs - Irnat t is ls vs"
Irnat_Mult: "Irnat (NMult s t) is ls vs = Irnat s is ls vs * Irnat t is ls vs"
Irnat_lgth: "Irnat (Nlgth rxs) is ls vs = length (Irlist rxs is ls)"
Irnat_C: "Irnat (NC i) is ls vs = i"
lemma Irnat_C0: "Irnat (NC 0) is ls vs = 0"
by simp
lemma Irnat_C1: "Irnat (NC 1) is ls vs = 1"
by simp
lemma Irnat_Cnumberof: "Irnat (NC (number_of x)) is ls vs = number_of x"
by simp
lemmas Irnat_simps = Irnat_Suc Irnat_Var Irnat_Neg Irnat_Add Irnat_Sub Irnat_Mult Irnat_lgth
Irnat_C0 Irnat_C1 Irnat_Cnumberof
lemma "(Suc n) * length (([(3::int) * x + y*y - 9 + (- z)] @ []) @ xs) = length xs"
apply (reify Irnat_simps Irlist.simps Irint_simps ("(Suc n) *length (([(3::int) * x + y*y - 9 + (- z)] @ []) @ xs)"))
oops
datatype rifm = RT | RF | RVar nat
| RNLT rnat rnat | RNILT rnat rint | RNEQ rnat rnat
|RAnd rifm rifm | ROr rifm rifm | RImp rifm rifm| RIff rifm rifm
| RNEX rifm | RIEX rifm| RLEX rifm | RNALL rifm | RIALL rifm| RLALL rifm
| RBEX rifm | RBALL rifm
consts Irifm :: "rifm \<Rightarrow> bool list \<Rightarrow> int list \<Rightarrow> (int list) list \<Rightarrow> nat list \<Rightarrow> bool"
primrec
"Irifm RT ps is ls ns = True"
"Irifm RF ps is ls ns = False"
"Irifm (RVar n) ps is ls ns = ps!n"
"Irifm (RNLT s t) ps is ls ns = (Irnat s is ls ns < Irnat t is ls ns)"
"Irifm (RNILT s t) ps is ls ns = (int (Irnat s is ls ns) < Irint t is)"
"Irifm (RNEQ s t) ps is ls ns = (Irnat s is ls ns = Irnat t is ls ns)"
"Irifm (RAnd p q) ps is ls ns = (Irifm p ps is ls ns \<and> Irifm q ps is ls ns)"
"Irifm (ROr p q) ps is ls ns = (Irifm p ps is ls ns \<or> Irifm q ps is ls ns)"
"Irifm (RImp p q) ps is ls ns = (Irifm p ps is ls ns \<longrightarrow> Irifm q ps is ls ns)"
"Irifm (RIff p q) ps is ls ns = (Irifm p ps is ls ns = Irifm q ps is ls ns)"
"Irifm (RNEX p) ps is ls ns = (\<exists>x. Irifm p ps is ls (x#ns))"
"Irifm (RIEX p) ps is ls ns = (\<exists>x. Irifm p ps (x#is) ls ns)"
"Irifm (RLEX p) ps is ls ns = (\<exists>x. Irifm p ps is (x#ls) ns)"
"Irifm (RBEX p) ps is ls ns = (\<exists>x. Irifm p (x#ps) is ls ns)"
"Irifm (RNALL p) ps is ls ns = (\<forall>x. Irifm p ps is ls (x#ns))"
"Irifm (RIALL p) ps is ls ns = (\<forall>x. Irifm p ps (x#is) ls ns)"
"Irifm (RLALL p) ps is ls ns = (\<forall>x. Irifm p ps is (x#ls) ns)"
"Irifm (RBALL p) ps is ls ns = (\<forall>x. Irifm p (x#ps) is ls ns)"
lemma " \<forall>x. \<exists>n. ((Suc n) * length (([(3::int) * x + (f t)*y - 9 + (- z)] @ []) @ xs) = length xs) \<and> m < 5*n - length (xs @ [2,3,4,x*z + 8 - y]) \<longrightarrow> (\<exists>p. \<forall>q. p \<and> q \<longrightarrow> r)"
apply (reify Irifm.simps Irnat_simps Irlist.simps Irint_simps)
oops
(* An example for equations containing type variables *)
datatype prod = Zero | One | Var nat | Mul prod prod
| Pw prod nat | PNM nat nat prod
consts Iprod :: " prod \<Rightarrow> ('a::{ordered_idom}) list \<Rightarrow>'a"
primrec
"Iprod Zero vs = 0"
"Iprod One vs = 1"
"Iprod (Var n) vs = vs!n"
"Iprod (Mul a b) vs = (Iprod a vs * Iprod b vs)"
"Iprod (Pw a n) vs = ((Iprod a vs) ^ n)"
"Iprod (PNM n k t) vs = (vs ! n)^k * Iprod t vs"
consts prodmul:: "prod \<times> prod \<Rightarrow> prod"
datatype sgn = Pos prod | Neg prod | ZeroEq prod | NZeroEq prod | Tr | F
| Or sgn sgn | And sgn sgn
consts Isgn :: " sgn \<Rightarrow> ('a::{ordered_idom}) list \<Rightarrow>bool"
primrec
"Isgn Tr vs = True"
"Isgn F vs = False"
"Isgn (ZeroEq t) vs = (Iprod t vs = 0)"
"Isgn (NZeroEq t) vs = (Iprod t vs \<noteq> 0)"
"Isgn (Pos t) vs = (Iprod t vs > 0)"
"Isgn (Neg t) vs = (Iprod t vs < 0)"
"Isgn (And p q) vs = (Isgn p vs \<and> Isgn q vs)"
"Isgn (Or p q) vs = (Isgn p vs \<or> Isgn q vs)"
lemmas eqs = Isgn.simps Iprod.simps
lemma "(x::'a::{ordered_idom})^4 * y * z * y^2 * z^23 > 0"
apply (reify eqs)
oops
end