doc-src/Tutorial/Misc/Exor.thy
author paulson
Tue, 19 Jan 1999 11:16:07 +0100
changeset 6139 26abad27b03c
parent 5377 efb799c5ed3c
permissions -rw-r--r--
simplified thanks to the arithmetic prover

Exor = Main +
constdefs
 exor :: bool => bool => bool
"exor A B == (A & ~B) | (~A & B)"
end