(* Title: HOL/Typedef.thy
ID: $Id$
Author: Markus Wenzel, TU Munich
*)
header {* HOL type definitions *}
theory Typedef
imports Set
uses
("Tools/typedef_package.ML")
("Tools/typecopy_package.ML")
("Tools/typedef_codegen.ML")
begin
ML {*
structure HOL = struct val thy = theory "HOL" end;
*} -- "belongs to theory HOL"
locale type_definition =
fixes Rep and Abs and A
assumes Rep: "Rep x \<in> A"
and Rep_inverse: "Abs (Rep x) = x"
and Abs_inverse: "y \<in> A ==> Rep (Abs y) = y"
-- {* This will be axiomatized for each typedef! *}
begin
lemma Rep_inject:
"(Rep x = Rep y) = (x = y)"
proof
assume "Rep x = Rep y"
then have "Abs (Rep x) = Abs (Rep y)" by (simp only:)
moreover have "Abs (Rep x) = x" by (rule Rep_inverse)
moreover have "Abs (Rep y) = y" by (rule Rep_inverse)
ultimately show "x = y" by simp
next
assume "x = y"
thus "Rep x = Rep y" by (simp only:)
qed
lemma Abs_inject:
assumes x: "x \<in> A" and y: "y \<in> A"
shows "(Abs x = Abs y) = (x = y)"
proof
assume "Abs x = Abs y"
then have "Rep (Abs x) = Rep (Abs y)" by (simp only:)
moreover from x have "Rep (Abs x) = x" by (rule Abs_inverse)
moreover from y have "Rep (Abs y) = y" by (rule Abs_inverse)
ultimately show "x = y" by simp
next
assume "x = y"
thus "Abs x = Abs y" by (simp only:)
qed
lemma Rep_cases [cases set]:
assumes y: "y \<in> A"
and hyp: "!!x. y = Rep x ==> P"
shows P
proof (rule hyp)
from y have "Rep (Abs y) = y" by (rule Abs_inverse)
thus "y = Rep (Abs y)" ..
qed
lemma Abs_cases [cases type]:
assumes r: "!!y. x = Abs y ==> y \<in> A ==> P"
shows P
proof (rule r)
have "Abs (Rep x) = x" by (rule Rep_inverse)
thus "x = Abs (Rep x)" ..
show "Rep x \<in> A" by (rule Rep)
qed
lemma Rep_induct [induct set]:
assumes y: "y \<in> A"
and hyp: "!!x. P (Rep x)"
shows "P y"
proof -
have "P (Rep (Abs y))" by (rule hyp)
moreover from y have "Rep (Abs y) = y" by (rule Abs_inverse)
ultimately show "P y" by simp
qed
lemma Abs_induct [induct type]:
assumes r: "!!y. y \<in> A ==> P (Abs y)"
shows "P x"
proof -
have "Rep x \<in> A" by (rule Rep)
then have "P (Abs (Rep x))" by (rule r)
moreover have "Abs (Rep x) = x" by (rule Rep_inverse)
ultimately show "P x" by simp
qed
lemma Rep_range:
assumes "type_definition Rep Abs A"
shows "range Rep = A"
proof -
from assms have A1: "!!x. Rep x : A"
and A2: "!!y. y : A ==> y = Rep(Abs y)"
by (auto simp add: type_definition_def)
have "range Rep <= A" using A1 by (auto simp add: image_def)
moreover have "A <= range Rep"
proof
fix x assume "x : A"
hence "x = Rep (Abs x)" by (rule A2)
thus "x : range Rep" by (auto simp add: image_def)
qed
ultimately show ?thesis ..
qed
end
use "Tools/typedef_package.ML"
use "Tools/typecopy_package.ML"
use "Tools/typedef_codegen.ML"
setup {*
TypecopyPackage.setup
#> TypedefCodegen.setup
*}
end