(* Title: HOL/Divides.thy
Author: Lawrence C Paulson, Cambridge University Computer Laboratory
Copyright 1999 University of Cambridge
*)
section \<open>More on quotient and remainder\<close>
theory Divides
imports Parity
begin
subsection \<open>Numeral division with a pragmatic type class\<close>
text \<open>
The following type class contains everything necessary to formulate
a division algorithm in ring structures with numerals, restricted
to its positive segments. This is its primary motivation, and it
could surely be formulated using a more fine-grained, more algebraic
and less technical class hierarchy.
\<close>
class unique_euclidean_semiring_numeral = semiring_parity + linordered_semidom +
assumes div_less: "0 \<le> a \<Longrightarrow> a < b \<Longrightarrow> a div b = 0"
and mod_less: " 0 \<le> a \<Longrightarrow> a < b \<Longrightarrow> a mod b = a"
and div_positive: "0 < b \<Longrightarrow> b \<le> a \<Longrightarrow> a div b > 0"
and mod_less_eq_dividend: "0 \<le> a \<Longrightarrow> a mod b \<le> a"
and pos_mod_bound: "0 < b \<Longrightarrow> a mod b < b"
and pos_mod_sign: "0 < b \<Longrightarrow> 0 \<le> a mod b"
and mod_mult2_eq: "0 \<le> c \<Longrightarrow> a mod (b * c) = b * (a div b mod c) + a mod b"
and div_mult2_eq: "0 \<le> c \<Longrightarrow> a div (b * c) = a div b div c"
assumes discrete: "a < b \<longleftrightarrow> a + 1 \<le> b"
fixes divmod :: "num \<Rightarrow> num \<Rightarrow> 'a \<times> 'a"
and divmod_step :: "num \<Rightarrow> 'a \<times> 'a \<Rightarrow> 'a \<times> 'a"
assumes divmod_def: "divmod m n = (numeral m div numeral n, numeral m mod numeral n)"
and divmod_step_def: "divmod_step l qr = (let (q, r) = qr
in if r \<ge> numeral l then (2 * q + 1, r - numeral l)
else (2 * q, r))"
\<comment> \<open>These are conceptually definitions but force generated code
to be monomorphic wrt. particular instances of this class which
yields a significant speedup.\<close>
begin
lemma divmod_digit_1:
assumes "0 \<le> a" "0 < b" and "b \<le> a mod (2 * b)"
shows "2 * (a div (2 * b)) + 1 = a div b" (is "?P")
and "a mod (2 * b) - b = a mod b" (is "?Q")
proof -
from assms mod_less_eq_dividend [of a "2 * b"] have "b \<le> a"
by (auto intro: trans)
with \<open>0 < b\<close> have "0 < a div b" by (auto intro: div_positive)
then have [simp]: "1 \<le> a div b" by (simp add: discrete)
with \<open>0 < b\<close> have mod_less: "a mod b < b" by (simp add: pos_mod_bound)
define w where "w = a div b mod 2"
then have w_exhaust: "w = 0 \<or> w = 1" by auto
have mod_w: "a mod (2 * b) = a mod b + b * w"
by (simp add: w_def mod_mult2_eq ac_simps)
from assms w_exhaust have "w = 1"
by (auto simp add: mod_w) (insert mod_less, auto)
with mod_w have mod: "a mod (2 * b) = a mod b + b" by simp
have "2 * (a div (2 * b)) = a div b - w"
by (simp add: w_def div_mult2_eq minus_mod_eq_mult_div ac_simps)
with \<open>w = 1\<close> have div: "2 * (a div (2 * b)) = a div b - 1" by simp
then show ?P and ?Q
by (simp_all add: div mod add_implies_diff [symmetric])
qed
lemma divmod_digit_0:
assumes "0 < b" and "a mod (2 * b) < b"
shows "2 * (a div (2 * b)) = a div b" (is "?P")
and "a mod (2 * b) = a mod b" (is "?Q")
proof -
define w where "w = a div b mod 2"
then have w_exhaust: "w = 0 \<or> w = 1" by auto
have mod_w: "a mod (2 * b) = a mod b + b * w"
by (simp add: w_def mod_mult2_eq ac_simps)
moreover have "b \<le> a mod b + b"
proof -
from \<open>0 < b\<close> pos_mod_sign have "0 \<le> a mod b" by blast
then have "0 + b \<le> a mod b + b" by (rule add_right_mono)
then show ?thesis by simp
qed
moreover note assms w_exhaust
ultimately have "w = 0" by auto
with mod_w have mod: "a mod (2 * b) = a mod b" by simp
have "2 * (a div (2 * b)) = a div b - w"
by (simp add: w_def div_mult2_eq minus_mod_eq_mult_div ac_simps)
with \<open>w = 0\<close> have div: "2 * (a div (2 * b)) = a div b" by simp
then show ?P and ?Q
by (simp_all add: div mod)
qed
lemma fst_divmod:
"fst (divmod m n) = numeral m div numeral n"
by (simp add: divmod_def)
lemma snd_divmod:
"snd (divmod m n) = numeral m mod numeral n"
by (simp add: divmod_def)
text \<open>
This is a formulation of one step (referring to one digit position)
in school-method division: compare the dividend at the current
digit position with the remainder from previous division steps
and evaluate accordingly.
\<close>
lemma divmod_step_eq [simp]:
"divmod_step l (q, r) = (if numeral l \<le> r
then (2 * q + 1, r - numeral l) else (2 * q, r))"
by (simp add: divmod_step_def)
text \<open>
This is a formulation of school-method division.
If the divisor is smaller than the dividend, terminate.
If not, shift the dividend to the right until termination
occurs and then reiterate single division steps in the
opposite direction.
\<close>
lemma divmod_divmod_step:
"divmod m n = (if m < n then (0, numeral m)
else divmod_step n (divmod m (Num.Bit0 n)))"
proof (cases "m < n")
case True then have "numeral m < numeral n" by simp
then show ?thesis
by (simp add: prod_eq_iff div_less mod_less fst_divmod snd_divmod)
next
case False
have "divmod m n =
divmod_step n (numeral m div (2 * numeral n),
numeral m mod (2 * numeral n))"
proof (cases "numeral n \<le> numeral m mod (2 * numeral n)")
case True
with divmod_step_eq
have "divmod_step n (numeral m div (2 * numeral n), numeral m mod (2 * numeral n)) =
(2 * (numeral m div (2 * numeral n)) + 1, numeral m mod (2 * numeral n) - numeral n)"
by simp
moreover from True divmod_digit_1 [of "numeral m" "numeral n"]
have "2 * (numeral m div (2 * numeral n)) + 1 = numeral m div numeral n"
and "numeral m mod (2 * numeral n) - numeral n = numeral m mod numeral n"
by simp_all
ultimately show ?thesis by (simp only: divmod_def)
next
case False then have *: "numeral m mod (2 * numeral n) < numeral n"
by (simp add: not_le)
with divmod_step_eq
have "divmod_step n (numeral m div (2 * numeral n), numeral m mod (2 * numeral n)) =
(2 * (numeral m div (2 * numeral n)), numeral m mod (2 * numeral n))"
by auto
moreover from * divmod_digit_0 [of "numeral n" "numeral m"]
have "2 * (numeral m div (2 * numeral n)) = numeral m div numeral n"
and "numeral m mod (2 * numeral n) = numeral m mod numeral n"
by (simp_all only: zero_less_numeral)
ultimately show ?thesis by (simp only: divmod_def)
qed
then have "divmod m n =
divmod_step n (numeral m div numeral (Num.Bit0 n),
numeral m mod numeral (Num.Bit0 n))"
by (simp only: numeral.simps distrib mult_1)
then have "divmod m n = divmod_step n (divmod m (Num.Bit0 n))"
by (simp add: divmod_def)
with False show ?thesis by simp
qed
text \<open>The division rewrite proper -- first, trivial results involving \<open>1\<close>\<close>
lemma divmod_trivial [simp]:
"divmod Num.One Num.One = (numeral Num.One, 0)"
"divmod (Num.Bit0 m) Num.One = (numeral (Num.Bit0 m), 0)"
"divmod (Num.Bit1 m) Num.One = (numeral (Num.Bit1 m), 0)"
"divmod num.One (num.Bit0 n) = (0, Numeral1)"
"divmod num.One (num.Bit1 n) = (0, Numeral1)"
using divmod_divmod_step [of "Num.One"] by (simp_all add: divmod_def)
text \<open>Division by an even number is a right-shift\<close>
lemma divmod_cancel [simp]:
"divmod (Num.Bit0 m) (Num.Bit0 n) = (case divmod m n of (q, r) \<Rightarrow> (q, 2 * r))" (is ?P)
"divmod (Num.Bit1 m) (Num.Bit0 n) = (case divmod m n of (q, r) \<Rightarrow> (q, 2 * r + 1))" (is ?Q)
proof -
have *: "\<And>q. numeral (Num.Bit0 q) = 2 * numeral q"
"\<And>q. numeral (Num.Bit1 q) = 2 * numeral q + 1"
by (simp_all only: numeral_mult numeral.simps distrib) simp_all
have "1 div 2 = 0" "1 mod 2 = 1" by (auto intro: div_less mod_less)
then show ?P and ?Q
by (simp_all add: fst_divmod snd_divmod prod_eq_iff split_def * [of m] * [of n] mod_mult_mult1
div_mult2_eq [of _ _ 2] mod_mult2_eq [of _ _ 2]
add.commute del: numeral_times_numeral)
qed
text \<open>The really hard work\<close>
lemma divmod_steps [simp]:
"divmod (num.Bit0 m) (num.Bit1 n) =
(if m \<le> n then (0, numeral (num.Bit0 m))
else divmod_step (num.Bit1 n)
(divmod (num.Bit0 m)
(num.Bit0 (num.Bit1 n))))"
"divmod (num.Bit1 m) (num.Bit1 n) =
(if m < n then (0, numeral (num.Bit1 m))
else divmod_step (num.Bit1 n)
(divmod (num.Bit1 m)
(num.Bit0 (num.Bit1 n))))"
by (simp_all add: divmod_divmod_step)
lemmas divmod_algorithm_code = divmod_step_eq divmod_trivial divmod_cancel divmod_steps
text \<open>Special case: divisibility\<close>
definition divides_aux :: "'a \<times> 'a \<Rightarrow> bool"
where
"divides_aux qr \<longleftrightarrow> snd qr = 0"
lemma divides_aux_eq [simp]:
"divides_aux (q, r) \<longleftrightarrow> r = 0"
by (simp add: divides_aux_def)
lemma dvd_numeral_simp [simp]:
"numeral m dvd numeral n \<longleftrightarrow> divides_aux (divmod n m)"
by (simp add: divmod_def mod_eq_0_iff_dvd)
text \<open>Generic computation of quotient and remainder\<close>
lemma numeral_div_numeral [simp]:
"numeral k div numeral l = fst (divmod k l)"
by (simp add: fst_divmod)
lemma numeral_mod_numeral [simp]:
"numeral k mod numeral l = snd (divmod k l)"
by (simp add: snd_divmod)
lemma one_div_numeral [simp]:
"1 div numeral n = fst (divmod num.One n)"
by (simp add: fst_divmod)
lemma one_mod_numeral [simp]:
"1 mod numeral n = snd (divmod num.One n)"
by (simp add: snd_divmod)
text \<open>Computing congruences modulo \<open>2 ^ q\<close>\<close>
lemma cong_exp_iff_simps:
"numeral n mod numeral Num.One = 0
\<longleftrightarrow> True"
"numeral (Num.Bit0 n) mod numeral (Num.Bit0 q) = 0
\<longleftrightarrow> numeral n mod numeral q = 0"
"numeral (Num.Bit1 n) mod numeral (Num.Bit0 q) = 0
\<longleftrightarrow> False"
"numeral m mod numeral Num.One = (numeral n mod numeral Num.One)
\<longleftrightarrow> True"
"numeral Num.One mod numeral (Num.Bit0 q) = (numeral Num.One mod numeral (Num.Bit0 q))
\<longleftrightarrow> True"
"numeral Num.One mod numeral (Num.Bit0 q) = (numeral (Num.Bit0 n) mod numeral (Num.Bit0 q))
\<longleftrightarrow> False"
"numeral Num.One mod numeral (Num.Bit0 q) = (numeral (Num.Bit1 n) mod numeral (Num.Bit0 q))
\<longleftrightarrow> (numeral n mod numeral q) = 0"
"numeral (Num.Bit0 m) mod numeral (Num.Bit0 q) = (numeral Num.One mod numeral (Num.Bit0 q))
\<longleftrightarrow> False"
"numeral (Num.Bit0 m) mod numeral (Num.Bit0 q) = (numeral (Num.Bit0 n) mod numeral (Num.Bit0 q))
\<longleftrightarrow> numeral m mod numeral q = (numeral n mod numeral q)"
"numeral (Num.Bit0 m) mod numeral (Num.Bit0 q) = (numeral (Num.Bit1 n) mod numeral (Num.Bit0 q))
\<longleftrightarrow> False"
"numeral (Num.Bit1 m) mod numeral (Num.Bit0 q) = (numeral Num.One mod numeral (Num.Bit0 q))
\<longleftrightarrow> (numeral m mod numeral q) = 0"
"numeral (Num.Bit1 m) mod numeral (Num.Bit0 q) = (numeral (Num.Bit0 n) mod numeral (Num.Bit0 q))
\<longleftrightarrow> False"
"numeral (Num.Bit1 m) mod numeral (Num.Bit0 q) = (numeral (Num.Bit1 n) mod numeral (Num.Bit0 q))
\<longleftrightarrow> numeral m mod numeral q = (numeral n mod numeral q)"
by (auto simp add: case_prod_beta dest: arg_cong [of _ _ even])
end
hide_fact (open) div_less mod_less mod_less_eq_dividend mod_mult2_eq div_mult2_eq
subsection \<open>More on division\<close>
instantiation nat :: unique_euclidean_semiring_numeral
begin
definition divmod_nat :: "num \<Rightarrow> num \<Rightarrow> nat \<times> nat"
where
divmod'_nat_def: "divmod_nat m n = (numeral m div numeral n, numeral m mod numeral n)"
definition divmod_step_nat :: "num \<Rightarrow> nat \<times> nat \<Rightarrow> nat \<times> nat"
where
"divmod_step_nat l qr = (let (q, r) = qr
in if r \<ge> numeral l then (2 * q + 1, r - numeral l)
else (2 * q, r))"
instance by standard
(auto simp add: divmod'_nat_def divmod_step_nat_def div_greater_zero_iff div_mult2_eq mod_mult2_eq)
end
declare divmod_algorithm_code [where ?'a = nat, code]
lemma Suc_0_div_numeral [simp]:
fixes k l :: num
shows "Suc 0 div numeral k = fst (divmod Num.One k)"
by (simp_all add: fst_divmod)
lemma Suc_0_mod_numeral [simp]:
fixes k l :: num
shows "Suc 0 mod numeral k = snd (divmod Num.One k)"
by (simp_all add: snd_divmod)
definition divmod_nat :: "nat \<Rightarrow> nat \<Rightarrow> nat \<times> nat"
where "divmod_nat m n = (m div n, m mod n)"
lemma fst_divmod_nat [simp]:
"fst (divmod_nat m n) = m div n"
by (simp add: divmod_nat_def)
lemma snd_divmod_nat [simp]:
"snd (divmod_nat m n) = m mod n"
by (simp add: divmod_nat_def)
lemma divmod_nat_if [code]:
"Divides.divmod_nat m n = (if n = 0 \<or> m < n then (0, m) else
let (q, r) = Divides.divmod_nat (m - n) n in (Suc q, r))"
by (simp add: prod_eq_iff case_prod_beta not_less le_div_geq le_mod_geq)
lemma [code]:
"m div n = fst (divmod_nat m n)"
"m mod n = snd (divmod_nat m n)"
by simp_all
inductive eucl_rel_int :: "int \<Rightarrow> int \<Rightarrow> int \<times> int \<Rightarrow> bool"
where eucl_rel_int_by0: "eucl_rel_int k 0 (0, k)"
| eucl_rel_int_dividesI: "l \<noteq> 0 \<Longrightarrow> k = q * l \<Longrightarrow> eucl_rel_int k l (q, 0)"
| eucl_rel_int_remainderI: "sgn r = sgn l \<Longrightarrow> \<bar>r\<bar> < \<bar>l\<bar>
\<Longrightarrow> k = q * l + r \<Longrightarrow> eucl_rel_int k l (q, r)"
lemma eucl_rel_int_iff:
"eucl_rel_int k l (q, r) \<longleftrightarrow>
k = l * q + r \<and>
(if 0 < l then 0 \<le> r \<and> r < l else if l < 0 then l < r \<and> r \<le> 0 else q = 0)"
by (cases "r = 0")
(auto elim!: eucl_rel_int.cases intro: eucl_rel_int_by0 eucl_rel_int_dividesI eucl_rel_int_remainderI
simp add: ac_simps sgn_1_pos sgn_1_neg)
lemma unique_quotient_lemma:
"b * q' + r' \<le> b * q + r \<Longrightarrow> 0 \<le> r' \<Longrightarrow> r' < b \<Longrightarrow> r < b \<Longrightarrow> q' \<le> (q::int)"
apply (subgoal_tac "r' + b * (q'-q) \<le> r")
prefer 2 apply (simp add: right_diff_distrib)
apply (subgoal_tac "0 < b * (1 + q - q') ")
apply (erule_tac [2] order_le_less_trans)
prefer 2 apply (simp add: right_diff_distrib distrib_left)
apply (subgoal_tac "b * q' < b * (1 + q) ")
prefer 2 apply (simp add: right_diff_distrib distrib_left)
apply (simp add: mult_less_cancel_left)
done
lemma unique_quotient_lemma_neg:
"b * q' + r' \<le> b*q + r \<Longrightarrow> r \<le> 0 \<Longrightarrow> b < r \<Longrightarrow> b < r' \<Longrightarrow> q \<le> (q'::int)"
by (rule_tac b = "-b" and r = "-r'" and r' = "-r" in unique_quotient_lemma) auto
lemma unique_quotient:
"eucl_rel_int a b (q, r) \<Longrightarrow> eucl_rel_int a b (q', r') \<Longrightarrow> q = q'"
apply (simp add: eucl_rel_int_iff linorder_neq_iff split: if_split_asm)
apply (blast intro: order_antisym
dest: order_eq_refl [THEN unique_quotient_lemma]
order_eq_refl [THEN unique_quotient_lemma_neg] sym)+
done
lemma unique_remainder:
"eucl_rel_int a b (q, r) \<Longrightarrow> eucl_rel_int a b (q', r') \<Longrightarrow> r = r'"
apply (subgoal_tac "q = q'")
apply (simp add: eucl_rel_int_iff)
apply (blast intro: unique_quotient)
done
lemma eucl_rel_int:
"eucl_rel_int k l (k div l, k mod l)"
proof (cases k rule: int_cases3)
case zero
then show ?thesis
by (simp add: eucl_rel_int_iff divide_int_def modulo_int_def)
next
case (pos n)
then show ?thesis
using div_mult_mod_eq [of n]
by (cases l rule: int_cases3)
(auto simp del: of_nat_mult of_nat_add
simp add: mod_greater_zero_iff_not_dvd of_nat_mult [symmetric] of_nat_add [symmetric] algebra_simps
eucl_rel_int_iff divide_int_def modulo_int_def)
next
case (neg n)
then show ?thesis
using div_mult_mod_eq [of n]
by (cases l rule: int_cases3)
(auto simp del: of_nat_mult of_nat_add
simp add: mod_greater_zero_iff_not_dvd of_nat_mult [symmetric] of_nat_add [symmetric] algebra_simps
eucl_rel_int_iff divide_int_def modulo_int_def)
qed
lemma divmod_int_unique:
assumes "eucl_rel_int k l (q, r)"
shows div_int_unique: "k div l = q" and mod_int_unique: "k mod l = r"
using assms eucl_rel_int [of k l]
using unique_quotient [of k l] unique_remainder [of k l]
by auto
lemma div_abs_eq_div_nat:
"\<bar>k\<bar> div \<bar>l\<bar> = int (nat \<bar>k\<bar> div nat \<bar>l\<bar>)"
by (simp add: divide_int_def)
lemma mod_abs_eq_div_nat:
"\<bar>k\<bar> mod \<bar>l\<bar> = int (nat \<bar>k\<bar> mod nat \<bar>l\<bar>)"
by (simp add: modulo_int_def)
lemma zdiv_int:
"int (a div b) = int a div int b"
by (simp add: divide_int_def sgn_1_pos)
lemma zmod_int:
"int (a mod b) = int a mod int b"
by (simp add: modulo_int_def sgn_1_pos)
lemma div_sgn_abs_cancel:
fixes k l v :: int
assumes "v \<noteq> 0"
shows "(sgn v * \<bar>k\<bar>) div (sgn v * \<bar>l\<bar>) = \<bar>k\<bar> div \<bar>l\<bar>"
proof -
from assms have "sgn v = - 1 \<or> sgn v = 1"
by (cases "v \<ge> 0") auto
then show ?thesis
using assms unfolding divide_int_def [of "sgn v * \<bar>k\<bar>" "sgn v * \<bar>l\<bar>"]
by (fastforce simp add: not_less div_abs_eq_div_nat)
qed
lemma div_eq_sgn_abs:
fixes k l v :: int
assumes "sgn k = sgn l"
shows "k div l = \<bar>k\<bar> div \<bar>l\<bar>"
proof (cases "l = 0")
case True
then show ?thesis
by simp
next
case False
with assms have "(sgn k * \<bar>k\<bar>) div (sgn l * \<bar>l\<bar>) = \<bar>k\<bar> div \<bar>l\<bar>"
using div_sgn_abs_cancel [of l k l] by simp
then show ?thesis
by (simp add: sgn_mult_abs)
qed
lemma div_dvd_sgn_abs:
fixes k l :: int
assumes "l dvd k"
shows "k div l = (sgn k * sgn l) * (\<bar>k\<bar> div \<bar>l\<bar>)"
proof (cases "k = 0 \<or> l = 0")
case True
then show ?thesis
by auto
next
case False
then have "k \<noteq> 0" and "l \<noteq> 0"
by auto
show ?thesis
proof (cases "sgn l = sgn k")
case True
then show ?thesis
by (simp add: div_eq_sgn_abs)
next
case False
with \<open>k \<noteq> 0\<close> \<open>l \<noteq> 0\<close>
have "sgn l * sgn k = - 1"
by (simp add: sgn_if split: if_splits)
with assms show ?thesis
unfolding divide_int_def [of k l]
by (auto simp add: zdiv_int ac_simps)
qed
qed
lemma div_noneq_sgn_abs:
fixes k l :: int
assumes "l \<noteq> 0"
assumes "sgn k \<noteq> sgn l"
shows "k div l = - (\<bar>k\<bar> div \<bar>l\<bar>) - of_bool (\<not> l dvd k)"
using assms
by (simp only: divide_int_def [of k l], auto simp add: not_less zdiv_int)
text\<open>Basic laws about division and remainder\<close>
lemma pos_mod_conj: "(0::int) < b \<Longrightarrow> 0 \<le> a mod b \<and> a mod b < b"
using eucl_rel_int [of a b]
by (auto simp add: eucl_rel_int_iff prod_eq_iff)
lemmas pos_mod_sign = pos_mod_conj [THEN conjunct1]
and pos_mod_bound = pos_mod_conj [THEN conjunct2]
lemma neg_mod_conj: "b < (0::int) \<Longrightarrow> a mod b \<le> 0 \<and> b < a mod b"
using eucl_rel_int [of a b]
by (auto simp add: eucl_rel_int_iff prod_eq_iff)
lemmas neg_mod_sign [simp] = neg_mod_conj [THEN conjunct1]
and neg_mod_bound [simp] = neg_mod_conj [THEN conjunct2]
subsubsection \<open>General Properties of div and mod\<close>
lemma div_pos_pos_trivial [simp]:
"k div l = 0" if "k \<ge> 0" and "k < l" for k l :: int
using that by (auto intro!: div_int_unique [of _ _ _ k] simp add: eucl_rel_int_iff)
lemma div_neg_neg_trivial [simp]:
"k div l = 0" if "k \<le> 0" and "l < k" for k l :: int
using that by (auto intro!: div_int_unique [of _ _ _ k] simp add: eucl_rel_int_iff)
lemma div_pos_neg_trivial: "[| (0::int) < a; a+b \<le> 0 |] ==> a div b = -1"
apply (rule div_int_unique)
apply (auto simp add: eucl_rel_int_iff)
done
lemma div_positive_int:
"k div l > 0" if "k \<ge> l" and "l > 0" for k l :: int
using that by (simp add: divide_int_def div_positive)
(*There is no div_neg_pos_trivial because 0 div b = 0 would supersede it*)
lemma mod_pos_pos_trivial [simp]:
"k mod l = k" if "k \<ge> 0" and "k < l" for k l :: int
using that by (auto intro!: mod_int_unique [of _ _ 0] simp add: eucl_rel_int_iff)
lemma mod_neg_neg_trivial [simp]:
"k mod l = k" if "k \<le> 0" and "l < k" for k l :: int
using that by (auto intro!: mod_int_unique [of _ _ 0] simp add: eucl_rel_int_iff)
lemma mod_pos_neg_trivial: "[| (0::int) < a; a+b \<le> 0 |] ==> a mod b = a+b"
apply (rule_tac q = "-1" in mod_int_unique)
apply (auto simp add: eucl_rel_int_iff)
done
text\<open>There is no \<open>mod_neg_pos_trivial\<close>.\<close>
subsubsection \<open>Laws for div and mod with Unary Minus\<close>
lemma zminus1_lemma:
"eucl_rel_int a b (q, r) ==> b \<noteq> 0
==> eucl_rel_int (-a) b (if r=0 then -q else -q - 1,
if r=0 then 0 else b-r)"
by (force simp add: eucl_rel_int_iff right_diff_distrib)
lemma zdiv_zminus1_eq_if:
"b \<noteq> (0::int)
==> (-a) div b =
(if a mod b = 0 then - (a div b) else - (a div b) - 1)"
by (blast intro: eucl_rel_int [THEN zminus1_lemma, THEN div_int_unique])
lemma zmod_zminus1_eq_if:
"(-a::int) mod b = (if a mod b = 0 then 0 else b - (a mod b))"
apply (case_tac "b = 0", simp)
apply (blast intro: eucl_rel_int [THEN zminus1_lemma, THEN mod_int_unique])
done
lemma zmod_zminus1_not_zero:
fixes k l :: int
shows "- k mod l \<noteq> 0 \<Longrightarrow> k mod l \<noteq> 0"
by (simp add: mod_eq_0_iff_dvd)
lemma zmod_zminus2_not_zero:
fixes k l :: int
shows "k mod - l \<noteq> 0 \<Longrightarrow> k mod l \<noteq> 0"
by (simp add: mod_eq_0_iff_dvd)
lemma zdiv_zminus2_eq_if:
"b \<noteq> (0::int)
==> a div (-b) =
(if a mod b = 0 then - (a div b) else - (a div b) - 1)"
by (auto simp add: zdiv_zminus1_eq_if div_minus_right)
lemma zmod_zminus2_eq_if:
"a mod (-b::int) = (if a mod b = 0 then 0 else (a mod b) - b)"
by (auto simp add: zmod_zminus1_eq_if mod_minus_right)
subsubsection \<open>Monotonicity in the First Argument (Dividend)\<close>
lemma zdiv_mono1: "[| a \<le> a'; 0 < (b::int) |] ==> a div b \<le> a' div b"
using mult_div_mod_eq [symmetric, of a b]
using mult_div_mod_eq [symmetric, of a' b]
apply -
apply (rule unique_quotient_lemma)
apply (erule subst)
apply (erule subst, simp_all)
done
lemma zdiv_mono1_neg: "[| a \<le> a'; (b::int) < 0 |] ==> a' div b \<le> a div b"
using mult_div_mod_eq [symmetric, of a b]
using mult_div_mod_eq [symmetric, of a' b]
apply -
apply (rule unique_quotient_lemma_neg)
apply (erule subst)
apply (erule subst, simp_all)
done
subsubsection \<open>Monotonicity in the Second Argument (Divisor)\<close>
lemma q_pos_lemma:
"[| 0 \<le> b'*q' + r'; r' < b'; 0 < b' |] ==> 0 \<le> (q'::int)"
apply (subgoal_tac "0 < b'* (q' + 1) ")
apply (simp add: zero_less_mult_iff)
apply (simp add: distrib_left)
done
lemma zdiv_mono2_lemma:
"[| b*q + r = b'*q' + r'; 0 \<le> b'*q' + r';
r' < b'; 0 \<le> r; 0 < b'; b' \<le> b |]
==> q \<le> (q'::int)"
apply (frule q_pos_lemma, assumption+)
apply (subgoal_tac "b*q < b* (q' + 1) ")
apply (simp add: mult_less_cancel_left)
apply (subgoal_tac "b*q = r' - r + b'*q'")
prefer 2 apply simp
apply (simp (no_asm_simp) add: distrib_left)
apply (subst add.commute, rule add_less_le_mono, arith)
apply (rule mult_right_mono, auto)
done
lemma zdiv_mono2:
"[| (0::int) \<le> a; 0 < b'; b' \<le> b |] ==> a div b \<le> a div b'"
apply (subgoal_tac "b \<noteq> 0")
prefer 2 apply arith
using mult_div_mod_eq [symmetric, of a b]
using mult_div_mod_eq [symmetric, of a b']
apply -
apply (rule zdiv_mono2_lemma)
apply (erule subst)
apply (erule subst, simp_all)
done
lemma q_neg_lemma:
"[| b'*q' + r' < 0; 0 \<le> r'; 0 < b' |] ==> q' \<le> (0::int)"
apply (subgoal_tac "b'*q' < 0")
apply (simp add: mult_less_0_iff, arith)
done
lemma zdiv_mono2_neg_lemma:
"[| b*q + r = b'*q' + r'; b'*q' + r' < 0;
r < b; 0 \<le> r'; 0 < b'; b' \<le> b |]
==> q' \<le> (q::int)"
apply (frule q_neg_lemma, assumption+)
apply (subgoal_tac "b*q' < b* (q + 1) ")
apply (simp add: mult_less_cancel_left)
apply (simp add: distrib_left)
apply (subgoal_tac "b*q' \<le> b'*q'")
prefer 2 apply (simp add: mult_right_mono_neg, arith)
done
lemma zdiv_mono2_neg:
"[| a < (0::int); 0 < b'; b' \<le> b |] ==> a div b' \<le> a div b"
using mult_div_mod_eq [symmetric, of a b]
using mult_div_mod_eq [symmetric, of a b']
apply -
apply (rule zdiv_mono2_neg_lemma)
apply (erule subst)
apply (erule subst, simp_all)
done
subsubsection \<open>More Algebraic Laws for div and mod\<close>
lemma zdiv_zmult1_eq: "(a*b) div c = a*(b div c) + a*(b mod c) div (c::int)"
by (fact div_mult1_eq)
(*NOT suitable for rewriting: the RHS has an instance of the LHS*)
lemma zdiv_zadd1_eq:
"(a+b) div (c::int) = a div c + b div c + ((a mod c + b mod c) div c)"
by (fact div_add1_eq)
lemma zmod_eq_0_iff: "(m mod d = 0) = (\<exists>q::int. m = d*q)"
by (simp add: dvd_eq_mod_eq_0 [symmetric] dvd_def)
(* REVISIT: should this be generalized to all semiring_div types? *)
lemmas zmod_eq_0D [dest!] = zmod_eq_0_iff [THEN iffD1]
subsubsection \<open>Proving @{term "a div (b * c) = (a div b) div c"}\<close>
(*The condition c>0 seems necessary. Consider that 7 div ~6 = ~2 but
7 div 2 div ~3 = 3 div ~3 = ~1. The subcase (a div b) mod c = 0 seems
to cause particular problems.*)
text\<open>first, four lemmas to bound the remainder for the cases b<0 and b>0\<close>
lemma zmult2_lemma_aux1: "[| (0::int) < c; b < r; r \<le> 0 |] ==> b * c < b * (q mod c) + r"
apply (subgoal_tac "b * (c - q mod c) < r * 1")
apply (simp add: algebra_simps)
apply (rule order_le_less_trans)
apply (erule_tac [2] mult_strict_right_mono)
apply (rule mult_left_mono_neg)
using add1_zle_eq[of "q mod c"]apply(simp add: algebra_simps)
apply (simp)
apply (simp)
done
lemma zmult2_lemma_aux2:
"[| (0::int) < c; b < r; r \<le> 0 |] ==> b * (q mod c) + r \<le> 0"
apply (subgoal_tac "b * (q mod c) \<le> 0")
apply arith
apply (simp add: mult_le_0_iff)
done
lemma zmult2_lemma_aux3: "[| (0::int) < c; 0 \<le> r; r < b |] ==> 0 \<le> b * (q mod c) + r"
apply (subgoal_tac "0 \<le> b * (q mod c) ")
apply arith
apply (simp add: zero_le_mult_iff)
done
lemma zmult2_lemma_aux4: "[| (0::int) < c; 0 \<le> r; r < b |] ==> b * (q mod c) + r < b * c"
apply (subgoal_tac "r * 1 < b * (c - q mod c) ")
apply (simp add: right_diff_distrib)
apply (rule order_less_le_trans)
apply (erule mult_strict_right_mono)
apply (rule_tac [2] mult_left_mono)
apply simp
using add1_zle_eq[of "q mod c"] apply (simp add: algebra_simps)
apply simp
done
lemma zmult2_lemma: "[| eucl_rel_int a b (q, r); 0 < c |]
==> eucl_rel_int a (b * c) (q div c, b*(q mod c) + r)"
by (auto simp add: mult.assoc eucl_rel_int_iff linorder_neq_iff
zero_less_mult_iff distrib_left [symmetric]
zmult2_lemma_aux1 zmult2_lemma_aux2 zmult2_lemma_aux3 zmult2_lemma_aux4 mult_less_0_iff split: if_split_asm)
lemma zdiv_zmult2_eq:
fixes a b c :: int
shows "0 \<le> c \<Longrightarrow> a div (b * c) = (a div b) div c"
apply (case_tac "b = 0", simp)
apply (force simp add: le_less eucl_rel_int [THEN zmult2_lemma, THEN div_int_unique])
done
lemma zmod_zmult2_eq:
fixes a b c :: int
shows "0 \<le> c \<Longrightarrow> a mod (b * c) = b * (a div b mod c) + a mod b"
apply (case_tac "b = 0", simp)
apply (force simp add: le_less eucl_rel_int [THEN zmult2_lemma, THEN mod_int_unique])
done
lemma div_pos_geq:
fixes k l :: int
assumes "0 < l" and "l \<le> k"
shows "k div l = (k - l) div l + 1"
proof -
have "k = (k - l) + l" by simp
then obtain j where k: "k = j + l" ..
with assms show ?thesis by (simp add: div_add_self2)
qed
lemma mod_pos_geq:
fixes k l :: int
assumes "0 < l" and "l \<le> k"
shows "k mod l = (k - l) mod l"
proof -
have "k = (k - l) + l" by simp
then obtain j where k: "k = j + l" ..
with assms show ?thesis by simp
qed
subsubsection \<open>Splitting Rules for div and mod\<close>
text\<open>The proofs of the two lemmas below are essentially identical\<close>
lemma split_pos_lemma:
"0<k \<Longrightarrow>
P(n div k :: int)(n mod k) = (\<forall>i j. 0\<le>j \<and> j<k \<and> n = k*i + j \<longrightarrow> P i j)"
by auto
lemma split_neg_lemma:
"k<0 \<Longrightarrow>
P(n div k :: int)(n mod k) = (\<forall>i j. k<j \<and> j\<le>0 \<and> n = k*i + j \<longrightarrow> P i j)"
by auto
lemma split_zdiv:
"P(n div k :: int) =
((k = 0 \<longrightarrow> P 0) \<and>
(0<k \<longrightarrow> (\<forall>i j. 0\<le>j \<and> j<k \<and> n = k*i + j \<longrightarrow> P i)) \<and>
(k<0 \<longrightarrow> (\<forall>i j. k<j \<and> j\<le>0 \<and> n = k*i + j \<longrightarrow> P i)))"
apply (cases "k = 0")
apply simp
apply (simp only: linorder_neq_iff)
apply (auto simp add: split_pos_lemma [of concl: "%x y. P x"]
split_neg_lemma [of concl: "%x y. P x"])
done
lemma split_zmod:
"P(n mod k :: int) =
((k = 0 \<longrightarrow> P n) \<and>
(0<k \<longrightarrow> (\<forall>i j. 0\<le>j \<and> j<k \<and> n = k*i + j \<longrightarrow> P j)) \<and>
(k<0 \<longrightarrow> (\<forall>i j. k<j \<and> j\<le>0 \<and> n = k*i + j \<longrightarrow> P j)))"
apply (case_tac "k=0", simp)
apply (simp only: linorder_neq_iff)
apply (erule disjE)
apply (simp_all add: split_pos_lemma [of concl: "%x y. P y"]
split_neg_lemma [of concl: "%x y. P y"])
done
text \<open>Enable (lin)arith to deal with @{const divide} and @{const modulo}
when these are applied to some constant that is of the form
@{term "numeral k"}:\<close>
declare split_zdiv [of _ _ "numeral k", arith_split] for k
declare split_zmod [of _ _ "numeral k", arith_split] for k
subsubsection \<open>Computing \<open>div\<close> and \<open>mod\<close> with shifting\<close>
lemma pos_eucl_rel_int_mult_2:
assumes "0 \<le> b"
assumes "eucl_rel_int a b (q, r)"
shows "eucl_rel_int (1 + 2*a) (2*b) (q, 1 + 2*r)"
using assms unfolding eucl_rel_int_iff by auto
lemma neg_eucl_rel_int_mult_2:
assumes "b \<le> 0"
assumes "eucl_rel_int (a + 1) b (q, r)"
shows "eucl_rel_int (1 + 2*a) (2*b) (q, 2*r - 1)"
using assms unfolding eucl_rel_int_iff by auto
text\<open>computing div by shifting\<close>
lemma pos_zdiv_mult_2: "(0::int) \<le> a ==> (1 + 2*b) div (2*a) = b div a"
using pos_eucl_rel_int_mult_2 [OF _ eucl_rel_int]
by (rule div_int_unique)
lemma neg_zdiv_mult_2:
assumes A: "a \<le> (0::int)" shows "(1 + 2*b) div (2*a) = (b+1) div a"
using neg_eucl_rel_int_mult_2 [OF A eucl_rel_int]
by (rule div_int_unique)
(* FIXME: add rules for negative numerals *)
lemma zdiv_numeral_Bit0 [simp]:
"numeral (Num.Bit0 v) div numeral (Num.Bit0 w) =
numeral v div (numeral w :: int)"
unfolding numeral.simps unfolding mult_2 [symmetric]
by (rule div_mult_mult1, simp)
lemma zdiv_numeral_Bit1 [simp]:
"numeral (Num.Bit1 v) div numeral (Num.Bit0 w) =
(numeral v div (numeral w :: int))"
unfolding numeral.simps
unfolding mult_2 [symmetric] add.commute [of _ 1]
by (rule pos_zdiv_mult_2, simp)
lemma pos_zmod_mult_2:
fixes a b :: int
assumes "0 \<le> a"
shows "(1 + 2 * b) mod (2 * a) = 1 + 2 * (b mod a)"
using pos_eucl_rel_int_mult_2 [OF assms eucl_rel_int]
by (rule mod_int_unique)
lemma neg_zmod_mult_2:
fixes a b :: int
assumes "a \<le> 0"
shows "(1 + 2 * b) mod (2 * a) = 2 * ((b + 1) mod a) - 1"
using neg_eucl_rel_int_mult_2 [OF assms eucl_rel_int]
by (rule mod_int_unique)
(* FIXME: add rules for negative numerals *)
lemma zmod_numeral_Bit0 [simp]:
"numeral (Num.Bit0 v) mod numeral (Num.Bit0 w) =
(2::int) * (numeral v mod numeral w)"
unfolding numeral_Bit0 [of v] numeral_Bit0 [of w]
unfolding mult_2 [symmetric] by (rule mod_mult_mult1)
lemma zmod_numeral_Bit1 [simp]:
"numeral (Num.Bit1 v) mod numeral (Num.Bit0 w) =
2 * (numeral v mod numeral w) + (1::int)"
unfolding numeral_Bit1 [of v] numeral_Bit0 [of w]
unfolding mult_2 [symmetric] add.commute [of _ 1]
by (rule pos_zmod_mult_2, simp)
lemma zdiv_eq_0_iff:
"i div k = 0 \<longleftrightarrow> k = 0 \<or> 0 \<le> i \<and> i < k \<or> i \<le> 0 \<and> k < i" (is "?L = ?R")
for i k :: int
proof
assume ?L
moreover have "?L \<longrightarrow> ?R"
by (rule split_zdiv [THEN iffD2]) simp
ultimately show ?R
by blast
next
assume ?R then show ?L
by auto
qed
lemma zmod_trival_iff:
fixes i k :: int
shows "i mod k = i \<longleftrightarrow> k = 0 \<or> 0 \<le> i \<and> i < k \<or> i \<le> 0 \<and> k < i"
proof -
have "i mod k = i \<longleftrightarrow> i div k = 0"
by safe (insert div_mult_mod_eq [of i k], auto)
with zdiv_eq_0_iff
show ?thesis
by simp
qed
subsubsection \<open>Quotients of Signs\<close>
lemma div_eq_minus1: "0 < b \<Longrightarrow> - 1 div b = - 1" for b :: int
by (simp add: divide_int_def)
lemma zmod_minus1: "0 < b \<Longrightarrow> - 1 mod b = b - 1" for b :: int
by (auto simp add: modulo_int_def)
lemma div_neg_pos_less0: "[| a < (0::int); 0 < b |] ==> a div b < 0"
apply (subgoal_tac "a div b \<le> -1", force)
apply (rule order_trans)
apply (rule_tac a' = "-1" in zdiv_mono1)
apply (auto simp add: div_eq_minus1)
done
lemma div_nonneg_neg_le0: "[| (0::int) \<le> a; b < 0 |] ==> a div b \<le> 0"
by (drule zdiv_mono1_neg, auto)
lemma div_nonpos_pos_le0: "[| (a::int) \<le> 0; b > 0 |] ==> a div b \<le> 0"
by (drule zdiv_mono1, auto)
text\<open>Now for some equivalences of the form \<open>a div b >=< 0 \<longleftrightarrow> \<dots>\<close>
conditional upon the sign of \<open>a\<close> or \<open>b\<close>. There are many more.
They should all be simp rules unless that causes too much search.\<close>
lemma pos_imp_zdiv_nonneg_iff: "(0::int) < b ==> (0 \<le> a div b) = (0 \<le> a)"
apply auto
apply (drule_tac [2] zdiv_mono1)
apply (auto simp add: linorder_neq_iff)
apply (simp (no_asm_use) add: linorder_not_less [symmetric])
apply (blast intro: div_neg_pos_less0)
done
lemma pos_imp_zdiv_pos_iff:
"0<k \<Longrightarrow> 0 < (i::int) div k \<longleftrightarrow> k \<le> i"
using pos_imp_zdiv_nonneg_iff[of k i] zdiv_eq_0_iff[of i k]
by arith
lemma neg_imp_zdiv_nonneg_iff:
"b < (0::int) ==> (0 \<le> a div b) = (a \<le> (0::int))"
apply (subst div_minus_minus [symmetric])
apply (subst pos_imp_zdiv_nonneg_iff, auto)
done
(*But not (a div b \<le> 0 iff a\<le>0); consider a=1, b=2 when a div b = 0.*)
lemma pos_imp_zdiv_neg_iff: "(0::int) < b ==> (a div b < 0) = (a < 0)"
by (simp add: linorder_not_le [symmetric] pos_imp_zdiv_nonneg_iff)
(*Again the law fails for \<le>: consider a = -1, b = -2 when a div b = 0*)
lemma neg_imp_zdiv_neg_iff: "b < (0::int) ==> (a div b < 0) = (0 < a)"
by (simp add: linorder_not_le [symmetric] neg_imp_zdiv_nonneg_iff)
lemma nonneg1_imp_zdiv_pos_iff:
"(0::int) \<le> a \<Longrightarrow> (a div b > 0) = (a \<ge> b \<and> b>0)"
apply rule
apply rule
using div_pos_pos_trivial[of a b]apply arith
apply(cases "b=0")apply simp
using div_nonneg_neg_le0[of a b]apply arith
using int_one_le_iff_zero_less[of "a div b"] zdiv_mono1[of b a b]apply simp
done
lemma zmod_le_nonneg_dividend: "(m::int) \<ge> 0 ==> m mod k \<le> m"
apply (rule split_zmod[THEN iffD2])
apply(fastforce dest: q_pos_lemma intro: split_mult_pos_le)
done
subsubsection \<open>Computation of Division and Remainder\<close>
instantiation int :: unique_euclidean_semiring_numeral
begin
definition divmod_int :: "num \<Rightarrow> num \<Rightarrow> int \<times> int"
where
"divmod_int m n = (numeral m div numeral n, numeral m mod numeral n)"
definition divmod_step_int :: "num \<Rightarrow> int \<times> int \<Rightarrow> int \<times> int"
where
"divmod_step_int l qr = (let (q, r) = qr
in if r \<ge> numeral l then (2 * q + 1, r - numeral l)
else (2 * q, r))"
instance
by standard (auto intro: zmod_le_nonneg_dividend simp add: divmod_int_def divmod_step_int_def
pos_imp_zdiv_pos_iff zmod_zmult2_eq zdiv_zmult2_eq)
end
declare divmod_algorithm_code [where ?'a = int, code]
context
begin
qualified definition adjust_div :: "int \<times> int \<Rightarrow> int"
where
"adjust_div qr = (let (q, r) = qr in q + of_bool (r \<noteq> 0))"
qualified lemma adjust_div_eq [simp, code]:
"adjust_div (q, r) = q + of_bool (r \<noteq> 0)"
by (simp add: adjust_div_def)
qualified definition adjust_mod :: "int \<Rightarrow> int \<Rightarrow> int"
where
[simp]: "adjust_mod l r = (if r = 0 then 0 else l - r)"
lemma minus_numeral_div_numeral [simp]:
"- numeral m div numeral n = - (adjust_div (divmod m n) :: int)"
proof -
have "int (fst (divmod m n)) = fst (divmod m n)"
by (simp only: fst_divmod divide_int_def) auto
then show ?thesis
by (auto simp add: split_def Let_def adjust_div_def divides_aux_def divide_int_def)
qed
lemma minus_numeral_mod_numeral [simp]:
"- numeral m mod numeral n = adjust_mod (numeral n) (snd (divmod m n) :: int)"
proof (cases "snd (divmod m n) = (0::int)")
case True
then show ?thesis
by (simp add: mod_eq_0_iff_dvd divides_aux_def)
next
case False
then have "int (snd (divmod m n)) = snd (divmod m n)" if "snd (divmod m n) \<noteq> (0::int)"
by (simp only: snd_divmod modulo_int_def) auto
then show ?thesis
by (simp add: divides_aux_def adjust_div_def)
(simp add: divides_aux_def modulo_int_def)
qed
lemma numeral_div_minus_numeral [simp]:
"numeral m div - numeral n = - (adjust_div (divmod m n) :: int)"
proof -
have "int (fst (divmod m n)) = fst (divmod m n)"
by (simp only: fst_divmod divide_int_def) auto
then show ?thesis
by (auto simp add: split_def Let_def adjust_div_def divides_aux_def divide_int_def)
qed
lemma numeral_mod_minus_numeral [simp]:
"numeral m mod - numeral n = - adjust_mod (numeral n) (snd (divmod m n) :: int)"
proof (cases "snd (divmod m n) = (0::int)")
case True
then show ?thesis
by (simp add: mod_eq_0_iff_dvd divides_aux_def)
next
case False
then have "int (snd (divmod m n)) = snd (divmod m n)" if "snd (divmod m n) \<noteq> (0::int)"
by (simp only: snd_divmod modulo_int_def) auto
then show ?thesis
by (simp add: divides_aux_def adjust_div_def)
(simp add: divides_aux_def modulo_int_def)
qed
lemma minus_one_div_numeral [simp]:
"- 1 div numeral n = - (adjust_div (divmod Num.One n) :: int)"
using minus_numeral_div_numeral [of Num.One n] by simp
lemma minus_one_mod_numeral [simp]:
"- 1 mod numeral n = adjust_mod (numeral n) (snd (divmod Num.One n) :: int)"
using minus_numeral_mod_numeral [of Num.One n] by simp
lemma one_div_minus_numeral [simp]:
"1 div - numeral n = - (adjust_div (divmod Num.One n) :: int)"
using numeral_div_minus_numeral [of Num.One n] by simp
lemma one_mod_minus_numeral [simp]:
"1 mod - numeral n = - adjust_mod (numeral n) (snd (divmod Num.One n) :: int)"
using numeral_mod_minus_numeral [of Num.One n] by simp
end
subsubsection \<open>Further properties\<close>
lemma div_int_pos_iff:
"k div l \<ge> 0 \<longleftrightarrow> k = 0 \<or> l = 0 \<or> k \<ge> 0 \<and> l \<ge> 0
\<or> k < 0 \<and> l < 0"
for k l :: int
apply (cases "k = 0 \<or> l = 0")
apply (auto simp add: pos_imp_zdiv_nonneg_iff neg_imp_zdiv_nonneg_iff)
apply (rule ccontr)
apply (simp add: neg_imp_zdiv_nonneg_iff)
done
lemma mod_int_pos_iff:
"k mod l \<ge> 0 \<longleftrightarrow> l dvd k \<or> l = 0 \<and> k \<ge> 0 \<or> l > 0"
for k l :: int
apply (cases "l > 0")
apply (simp_all add: dvd_eq_mod_eq_0)
apply (use neg_mod_conj [of l k] in \<open>auto simp add: le_less not_less\<close>)
done
text \<open>Simplify expresions in which div and mod combine numerical constants\<close>
lemma int_div_pos_eq: "\<lbrakk>(a::int) = b * q + r; 0 \<le> r; r < b\<rbrakk> \<Longrightarrow> a div b = q"
by (rule div_int_unique [of a b q r]) (simp add: eucl_rel_int_iff)
lemma int_div_neg_eq: "\<lbrakk>(a::int) = b * q + r; r \<le> 0; b < r\<rbrakk> \<Longrightarrow> a div b = q"
by (rule div_int_unique [of a b q r],
simp add: eucl_rel_int_iff)
lemma int_mod_pos_eq: "\<lbrakk>(a::int) = b * q + r; 0 \<le> r; r < b\<rbrakk> \<Longrightarrow> a mod b = r"
by (rule mod_int_unique [of a b q r],
simp add: eucl_rel_int_iff)
lemma int_mod_neg_eq: "\<lbrakk>(a::int) = b * q + r; r \<le> 0; b < r\<rbrakk> \<Longrightarrow> a mod b = r"
by (rule mod_int_unique [of a b q r],
simp add: eucl_rel_int_iff)
lemma abs_div: "(y::int) dvd x \<Longrightarrow> \<bar>x div y\<bar> = \<bar>x\<bar> div \<bar>y\<bar>"
by (unfold dvd_def, cases "y=0", auto simp add: abs_mult)
text\<open>Suggested by Matthias Daum\<close>
lemma int_power_div_base:
"\<lbrakk>0 < m; 0 < k\<rbrakk> \<Longrightarrow> k ^ m div k = (k::int) ^ (m - Suc 0)"
apply (subgoal_tac "k ^ m = k ^ ((m - Suc 0) + Suc 0)")
apply (erule ssubst)
apply (simp only: power_add)
apply simp_all
done
text \<open>Distributive laws for function \<open>nat\<close>.\<close>
lemma nat_div_distrib: "0 \<le> x \<Longrightarrow> nat (x div y) = nat x div nat y"
apply (rule linorder_cases [of y 0])
apply (simp add: div_nonneg_neg_le0)
apply simp
apply (simp add: nat_eq_iff pos_imp_zdiv_nonneg_iff zdiv_int)
done
(*Fails if y<0: the LHS collapses to (nat z) but the RHS doesn't*)
lemma nat_mod_distrib:
"\<lbrakk>0 \<le> x; 0 \<le> y\<rbrakk> \<Longrightarrow> nat (x mod y) = nat x mod nat y"
apply (case_tac "y = 0", simp)
apply (simp add: nat_eq_iff zmod_int)
done
text\<open>Suggested by Matthias Daum\<close>
lemma int_div_less_self: "\<lbrakk>0 < x; 1 < k\<rbrakk> \<Longrightarrow> x div k < (x::int)"
apply (subgoal_tac "nat x div nat k < nat x")
apply (simp add: nat_div_distrib [symmetric])
apply (rule div_less_dividend, simp_all)
done
lemma mod_eq_dvd_iff_nat:
"m mod q = n mod q \<longleftrightarrow> q dvd m - n" if "m \<ge> n" for m n q :: nat
proof -
have "int m mod int q = int n mod int q \<longleftrightarrow> int q dvd int m - int n"
by (simp add: mod_eq_dvd_iff)
with that have "int (m mod q) = int (n mod q) \<longleftrightarrow> int q dvd int (m - n)"
by (simp only: of_nat_mod of_nat_diff)
then show ?thesis
by simp
qed
lemma mod_eq_nat1E:
fixes m n q :: nat
assumes "m mod q = n mod q" and "m \<ge> n"
obtains s where "m = n + q * s"
proof -
from assms have "q dvd m - n"
by (simp add: mod_eq_dvd_iff_nat)
then obtain s where "m - n = q * s" ..
with \<open>m \<ge> n\<close> have "m = n + q * s"
by simp
with that show thesis .
qed
lemma mod_eq_nat2E:
fixes m n q :: nat
assumes "m mod q = n mod q" and "n \<ge> m"
obtains s where "n = m + q * s"
using assms mod_eq_nat1E [of n q m] by (auto simp add: ac_simps)
lemma nat_mod_eq_lemma:
assumes "(x::nat) mod n = y mod n" and "y \<le> x"
shows "\<exists>q. x = y + n * q"
using assms by (rule mod_eq_nat1E) rule
lemma nat_mod_eq_iff: "(x::nat) mod n = y mod n \<longleftrightarrow> (\<exists>q1 q2. x + n * q1 = y + n * q2)"
(is "?lhs = ?rhs")
proof
assume H: "x mod n = y mod n"
{assume xy: "x \<le> y"
from H have th: "y mod n = x mod n" by simp
from nat_mod_eq_lemma[OF th xy] have ?rhs
apply clarify apply (rule_tac x="q" in exI) by (rule exI[where x="0"], simp)}
moreover
{assume xy: "y \<le> x"
from nat_mod_eq_lemma[OF H xy] have ?rhs
apply clarify apply (rule_tac x="0" in exI) by (rule_tac x="q" in exI, simp)}
ultimately show ?rhs using linear[of x y] by blast
next
assume ?rhs then obtain q1 q2 where q12: "x + n * q1 = y + n * q2" by blast
hence "(x + n * q1) mod n = (y + n * q2) mod n" by simp
thus ?lhs by simp
qed
subsubsection \<open>Dedicated simproc for calculation\<close>
text \<open>
There is space for improvement here: the calculation itself
could be carried out outside the logic, and a generic simproc
(simplifier setup) for generic calculation would be helpful.
\<close>
simproc_setup numeral_divmod
("0 div 0 :: 'a :: unique_euclidean_semiring_numeral" | "0 mod 0 :: 'a :: unique_euclidean_semiring_numeral" |
"0 div 1 :: 'a :: unique_euclidean_semiring_numeral" | "0 mod 1 :: 'a :: unique_euclidean_semiring_numeral" |
"0 div - 1 :: int" | "0 mod - 1 :: int" |
"0 div numeral b :: 'a :: unique_euclidean_semiring_numeral" | "0 mod numeral b :: 'a :: unique_euclidean_semiring_numeral" |
"0 div - numeral b :: int" | "0 mod - numeral b :: int" |
"1 div 0 :: 'a :: unique_euclidean_semiring_numeral" | "1 mod 0 :: 'a :: unique_euclidean_semiring_numeral" |
"1 div 1 :: 'a :: unique_euclidean_semiring_numeral" | "1 mod 1 :: 'a :: unique_euclidean_semiring_numeral" |
"1 div - 1 :: int" | "1 mod - 1 :: int" |
"1 div numeral b :: 'a :: unique_euclidean_semiring_numeral" | "1 mod numeral b :: 'a :: unique_euclidean_semiring_numeral" |
"1 div - numeral b :: int" |"1 mod - numeral b :: int" |
"- 1 div 0 :: int" | "- 1 mod 0 :: int" | "- 1 div 1 :: int" | "- 1 mod 1 :: int" |
"- 1 div - 1 :: int" | "- 1 mod - 1 :: int" | "- 1 div numeral b :: int" | "- 1 mod numeral b :: int" |
"- 1 div - numeral b :: int" | "- 1 mod - numeral b :: int" |
"numeral a div 0 :: 'a :: unique_euclidean_semiring_numeral" | "numeral a mod 0 :: 'a :: unique_euclidean_semiring_numeral" |
"numeral a div 1 :: 'a :: unique_euclidean_semiring_numeral" | "numeral a mod 1 :: 'a :: unique_euclidean_semiring_numeral" |
"numeral a div - 1 :: int" | "numeral a mod - 1 :: int" |
"numeral a div numeral b :: 'a :: unique_euclidean_semiring_numeral" | "numeral a mod numeral b :: 'a :: unique_euclidean_semiring_numeral" |
"numeral a div - numeral b :: int" | "numeral a mod - numeral b :: int" |
"- numeral a div 0 :: int" | "- numeral a mod 0 :: int" |
"- numeral a div 1 :: int" | "- numeral a mod 1 :: int" |
"- numeral a div - 1 :: int" | "- numeral a mod - 1 :: int" |
"- numeral a div numeral b :: int" | "- numeral a mod numeral b :: int" |
"- numeral a div - numeral b :: int" | "- numeral a mod - numeral b :: int") =
\<open> let
val if_cong = the (Code.get_case_cong @{theory} @{const_name If});
fun successful_rewrite ctxt ct =
let
val thm = Simplifier.rewrite ctxt ct
in if Thm.is_reflexive thm then NONE else SOME thm end;
in fn phi =>
let
val simps = Morphism.fact phi (@{thms div_0 mod_0 div_by_0 mod_by_0 div_by_1 mod_by_1
one_div_numeral one_mod_numeral minus_one_div_numeral minus_one_mod_numeral
one_div_minus_numeral one_mod_minus_numeral
numeral_div_numeral numeral_mod_numeral minus_numeral_div_numeral minus_numeral_mod_numeral
numeral_div_minus_numeral numeral_mod_minus_numeral
div_minus_minus mod_minus_minus Divides.adjust_div_eq of_bool_eq one_neq_zero
numeral_neq_zero neg_equal_0_iff_equal arith_simps arith_special divmod_trivial
divmod_cancel divmod_steps divmod_step_eq fst_conv snd_conv numeral_One
case_prod_beta rel_simps Divides.adjust_mod_def div_minus1_right mod_minus1_right
minus_minus numeral_times_numeral mult_zero_right mult_1_right}
@ [@{lemma "0 = 0 \<longleftrightarrow> True" by simp}]);
fun prepare_simpset ctxt = HOL_ss |> Simplifier.simpset_map ctxt
(Simplifier.add_cong if_cong #> fold Simplifier.add_simp simps)
in fn ctxt => successful_rewrite (Simplifier.put_simpset (prepare_simpset ctxt) ctxt) end
end;
\<close>
subsubsection \<open>Code generation\<close>
lemma [code]:
fixes k :: int
shows
"k div 0 = 0"
"k mod 0 = k"
"0 div k = 0"
"0 mod k = 0"
"k div Int.Pos Num.One = k"
"k mod Int.Pos Num.One = 0"
"k div Int.Neg Num.One = - k"
"k mod Int.Neg Num.One = 0"
"Int.Pos m div Int.Pos n = (fst (divmod m n) :: int)"
"Int.Pos m mod Int.Pos n = (snd (divmod m n) :: int)"
"Int.Neg m div Int.Pos n = - (Divides.adjust_div (divmod m n) :: int)"
"Int.Neg m mod Int.Pos n = Divides.adjust_mod (Int.Pos n) (snd (divmod m n) :: int)"
"Int.Pos m div Int.Neg n = - (Divides.adjust_div (divmod m n) :: int)"
"Int.Pos m mod Int.Neg n = - Divides.adjust_mod (Int.Pos n) (snd (divmod m n) :: int)"
"Int.Neg m div Int.Neg n = (fst (divmod m n) :: int)"
"Int.Neg m mod Int.Neg n = - (snd (divmod m n) :: int)"
by simp_all
code_identifier
code_module Divides \<rightharpoonup> (SML) Arith and (OCaml) Arith and (Haskell) Arith
lemma dvd_eq_mod_eq_0_numeral:
"numeral x dvd (numeral y :: 'a) \<longleftrightarrow> numeral y mod numeral x = (0 :: 'a::semidom_modulo)"
by (fact dvd_eq_mod_eq_0)
declare minus_div_mult_eq_mod [symmetric, nitpick_unfold]
subsubsection \<open>Lemmas of doubtful value\<close>
lemma mod_mult_self3':
"Suc (k * n + m) mod n = Suc m mod n"
by (fact Suc_mod_mult_self3)
lemma mod_Suc_eq_Suc_mod:
"Suc m mod n = Suc (m mod n) mod n"
by (simp add: mod_simps)
lemma div_geq:
"m div n = Suc ((m - n) div n)" if "0 < n" and " \<not> m < n" for m n :: nat
by (rule le_div_geq) (use that in \<open>simp_all add: not_less\<close>)
lemma mod_geq:
"m mod n = (m - n) mod n" if "\<not> m < n" for m n :: nat
by (rule le_mod_geq) (use that in \<open>simp add: not_less\<close>)
lemma mod_eq_0_iff: "(m mod d = 0) = (\<exists>q::nat. m = d*q)"
by (auto simp add: dvd_eq_mod_eq_0 [symmetric] dvd_def)
lemmas mod_eq_0D [dest!] = mod_eq_0_iff [THEN iffD1]
(*Loses information, namely we also have r<d provided d is nonzero*)
lemma mod_eqD:
fixes m d r q :: nat
assumes "m mod d = r"
shows "\<exists>q. m = r + q * d"
proof -
from div_mult_mod_eq obtain q where "q * d + m mod d = m" by blast
with assms have "m = r + q * d" by simp
then show ?thesis ..
qed
lemmas even_times_iff = even_mult_iff \<comment> \<open>FIXME duplicate\<close>
lemma mod_2_not_eq_zero_eq_one_nat:
fixes n :: nat
shows "n mod 2 \<noteq> 0 \<longleftrightarrow> n mod 2 = 1"
by (fact not_mod_2_eq_0_eq_1)
lemma even_int_iff [simp]: "even (int n) \<longleftrightarrow> even n"
by (fact even_of_nat)
lemma is_unit_int:
"is_unit (k::int) \<longleftrightarrow> k = 1 \<or> k = - 1"
by auto
end