(* Title: Formal_Power_Series.thy
Author: Amine Chaieb, University of Cambridge
*)
header{* A formalization of formal power series *}
theory Formal_Power_Series
imports Main Fact Parity
begin
subsection {* The type of formal power series*}
typedef (open) 'a fps = "{f :: nat \<Rightarrow> 'a. True}"
morphisms fps_nth Abs_fps
by simp
notation fps_nth (infixl "$" 75)
lemma expand_fps_eq: "p = q \<longleftrightarrow> (\<forall>n. p $ n = q $ n)"
by (simp add: fps_nth_inject [symmetric] expand_fun_eq)
lemma fps_ext: "(\<And>n. p $ n = q $ n) \<Longrightarrow> p = q"
by (simp add: expand_fps_eq)
lemma fps_nth_Abs_fps [simp]: "Abs_fps f $ n = f n"
by (simp add: Abs_fps_inverse)
text{* Definition of the basic elements 0 and 1 and the basic operations of addition, negation and multiplication *}
instantiation fps :: (zero) zero
begin
definition fps_zero_def:
"0 = Abs_fps (\<lambda>n. 0)"
instance ..
end
lemma fps_zero_nth [simp]: "0 $ n = 0"
unfolding fps_zero_def by simp
instantiation fps :: ("{one,zero}") one
begin
definition fps_one_def:
"1 = Abs_fps (\<lambda>n. if n = 0 then 1 else 0)"
instance ..
end
lemma fps_one_nth [simp]: "1 $ n = (if n = 0 then 1 else 0)"
unfolding fps_one_def by simp
instantiation fps :: (plus) plus
begin
definition fps_plus_def:
"op + = (\<lambda>f g. Abs_fps (\<lambda>n. f $ n + g $ n))"
instance ..
end
lemma fps_add_nth [simp]: "(f + g) $ n = f $ n + g $ n"
unfolding fps_plus_def by simp
instantiation fps :: (minus) minus
begin
definition fps_minus_def:
"op - = (\<lambda>f g. Abs_fps (\<lambda>n. f $ n - g $ n))"
instance ..
end
lemma fps_sub_nth [simp]: "(f - g) $ n = f $ n - g $ n"
unfolding fps_minus_def by simp
instantiation fps :: (uminus) uminus
begin
definition fps_uminus_def:
"uminus = (\<lambda>f. Abs_fps (\<lambda>n. - (f $ n)))"
instance ..
end
lemma fps_neg_nth [simp]: "(- f) $ n = - (f $ n)"
unfolding fps_uminus_def by simp
instantiation fps :: ("{comm_monoid_add, times}") times
begin
definition fps_times_def:
"op * = (\<lambda>f g. Abs_fps (\<lambda>n. \<Sum>i=0..n. f $ i * g $ (n - i)))"
instance ..
end
lemma fps_mult_nth: "(f * g) $ n = (\<Sum>i=0..n. f$i * g$(n - i))"
unfolding fps_times_def by simp
declare atLeastAtMost_iff[presburger]
declare Bex_def[presburger]
declare Ball_def[presburger]
lemma mult_delta_left:
fixes x y :: "'a::mult_zero"
shows "(if b then x else 0) * y = (if b then x * y else 0)"
by simp
lemma mult_delta_right:
fixes x y :: "'a::mult_zero"
shows "x * (if b then y else 0) = (if b then x * y else 0)"
by simp
lemma cond_value_iff: "f (if b then x else y) = (if b then f x else f y)"
by auto
lemma cond_application_beta: "(if b then f else g) x = (if b then f x else g x)"
by auto
subsection{* Formal power series form a commutative ring with unity, if the range of sequences
they represent is a commutative ring with unity*}
instance fps :: (semigroup_add) semigroup_add
proof
fix a b c :: "'a fps" show "a + b + c = a + (b + c)"
by (simp add: fps_ext add_assoc)
qed
instance fps :: (ab_semigroup_add) ab_semigroup_add
proof
fix a b :: "'a fps" show "a + b = b + a"
by (simp add: fps_ext add_commute)
qed
lemma fps_mult_assoc_lemma:
fixes k :: nat and f :: "nat \<Rightarrow> nat \<Rightarrow> nat \<Rightarrow> 'a::comm_monoid_add"
shows "(\<Sum>j=0..k. \<Sum>i=0..j. f i (j - i) (n - j)) =
(\<Sum>j=0..k. \<Sum>i=0..k - j. f j i (n - j - i))"
proof (induct k)
case 0 show ?case by simp
next
case (Suc k) thus ?case
by (simp add: Suc_diff_le setsum_addf add_assoc
cong: strong_setsum_cong)
qed
instance fps :: (semiring_0) semigroup_mult
proof
fix a b c :: "'a fps"
show "(a * b) * c = a * (b * c)"
proof (rule fps_ext)
fix n :: nat
have "(\<Sum>j=0..n. \<Sum>i=0..j. a$i * b$(j - i) * c$(n - j)) =
(\<Sum>j=0..n. \<Sum>i=0..n - j. a$j * b$i * c$(n - j - i))"
by (rule fps_mult_assoc_lemma)
thus "((a * b) * c) $ n = (a * (b * c)) $ n"
by (simp add: fps_mult_nth setsum_right_distrib
setsum_left_distrib mult_assoc)
qed
qed
lemma fps_mult_commute_lemma:
fixes n :: nat and f :: "nat \<Rightarrow> nat \<Rightarrow> 'a::comm_monoid_add"
shows "(\<Sum>i=0..n. f i (n - i)) = (\<Sum>i=0..n. f (n - i) i)"
proof (rule setsum_reindex_cong)
show "inj_on (\<lambda>i. n - i) {0..n}"
by (rule inj_onI) simp
show "{0..n} = (\<lambda>i. n - i) ` {0..n}"
by (auto, rule_tac x="n - x" in image_eqI, simp_all)
next
fix i assume "i \<in> {0..n}"
hence "n - (n - i) = i" by simp
thus "f (n - i) i = f (n - i) (n - (n - i))" by simp
qed
instance fps :: (comm_semiring_0) ab_semigroup_mult
proof
fix a b :: "'a fps"
show "a * b = b * a"
proof (rule fps_ext)
fix n :: nat
have "(\<Sum>i=0..n. a$i * b$(n - i)) = (\<Sum>i=0..n. a$(n - i) * b$i)"
by (rule fps_mult_commute_lemma)
thus "(a * b) $ n = (b * a) $ n"
by (simp add: fps_mult_nth mult_commute)
qed
qed
instance fps :: (monoid_add) monoid_add
proof
fix a :: "'a fps" show "0 + a = a "
by (simp add: fps_ext)
next
fix a :: "'a fps" show "a + 0 = a "
by (simp add: fps_ext)
qed
instance fps :: (comm_monoid_add) comm_monoid_add
proof
fix a :: "'a fps" show "0 + a = a "
by (simp add: fps_ext)
qed
instance fps :: (semiring_1) monoid_mult
proof
fix a :: "'a fps" show "1 * a = a"
by (simp add: fps_ext fps_mult_nth mult_delta_left setsum_delta)
next
fix a :: "'a fps" show "a * 1 = a"
by (simp add: fps_ext fps_mult_nth mult_delta_right setsum_delta')
qed
instance fps :: (cancel_semigroup_add) cancel_semigroup_add
proof
fix a b c :: "'a fps"
assume "a + b = a + c" then show "b = c"
by (simp add: expand_fps_eq)
next
fix a b c :: "'a fps"
assume "b + a = c + a" then show "b = c"
by (simp add: expand_fps_eq)
qed
instance fps :: (cancel_ab_semigroup_add) cancel_ab_semigroup_add
proof
fix a b c :: "'a fps"
assume "a + b = a + c" then show "b = c"
by (simp add: expand_fps_eq)
qed
instance fps :: (cancel_comm_monoid_add) cancel_comm_monoid_add ..
instance fps :: (group_add) group_add
proof
fix a :: "'a fps" show "- a + a = 0"
by (simp add: fps_ext)
next
fix a b :: "'a fps" show "a - b = a + - b"
by (simp add: fps_ext diff_minus)
qed
instance fps :: (ab_group_add) ab_group_add
proof
fix a :: "'a fps"
show "- a + a = 0"
by (simp add: fps_ext)
next
fix a b :: "'a fps"
show "a - b = a + - b"
by (simp add: fps_ext)
qed
instance fps :: (zero_neq_one) zero_neq_one
by default (simp add: expand_fps_eq)
instance fps :: (semiring_0) semiring
proof
fix a b c :: "'a fps"
show "(a + b) * c = a * c + b * c"
by (simp add: expand_fps_eq fps_mult_nth left_distrib setsum_addf)
next
fix a b c :: "'a fps"
show "a * (b + c) = a * b + a * c"
by (simp add: expand_fps_eq fps_mult_nth right_distrib setsum_addf)
qed
instance fps :: (semiring_0) semiring_0
proof
fix a:: "'a fps" show "0 * a = 0"
by (simp add: fps_ext fps_mult_nth)
next
fix a:: "'a fps" show "a * 0 = 0"
by (simp add: fps_ext fps_mult_nth)
qed
instance fps :: (semiring_0_cancel) semiring_0_cancel ..
subsection {* Selection of the nth power of the implicit variable in the infinite sum*}
lemma fps_nonzero_nth: "f \<noteq> 0 \<longleftrightarrow> (\<exists> n. f $n \<noteq> 0)"
by (simp add: expand_fps_eq)
lemma fps_nonzero_nth_minimal:
"f \<noteq> 0 \<longleftrightarrow> (\<exists>n. f $ n \<noteq> 0 \<and> (\<forall>m<n. f $ m = 0))"
proof
let ?n = "LEAST n. f $ n \<noteq> 0"
assume "f \<noteq> 0"
then have "\<exists>n. f $ n \<noteq> 0"
by (simp add: fps_nonzero_nth)
then have "f $ ?n \<noteq> 0"
by (rule LeastI_ex)
moreover have "\<forall>m<?n. f $ m = 0"
by (auto dest: not_less_Least)
ultimately have "f $ ?n \<noteq> 0 \<and> (\<forall>m<?n. f $ m = 0)" ..
then show "\<exists>n. f $ n \<noteq> 0 \<and> (\<forall>m<n. f $ m = 0)" ..
next
assume "\<exists>n. f $ n \<noteq> 0 \<and> (\<forall>m<n. f $ m = 0)"
then show "f \<noteq> 0" by (auto simp add: expand_fps_eq)
qed
lemma fps_eq_iff: "f = g \<longleftrightarrow> (\<forall>n. f $ n = g $n)"
by (rule expand_fps_eq)
lemma fps_setsum_nth: "(setsum f S) $ n = setsum (\<lambda>k. (f k) $ n) S"
proof (cases "finite S")
assume "\<not> finite S" then show ?thesis by simp
next
assume "finite S"
then show ?thesis by (induct set: finite) auto
qed
subsection{* Injection of the basic ring elements and multiplication by scalars *}
definition
"fps_const c = Abs_fps (\<lambda>n. if n = 0 then c else 0)"
lemma fps_nth_fps_const [simp]: "fps_const c $ n = (if n = 0 then c else 0)"
unfolding fps_const_def by simp
lemma fps_const_0_eq_0 [simp]: "fps_const 0 = 0"
by (simp add: fps_ext)
lemma fps_const_1_eq_1 [simp]: "fps_const 1 = 1"
by (simp add: fps_ext)
lemma fps_const_neg [simp]: "- (fps_const (c::'a::ring)) = fps_const (- c)"
by (simp add: fps_ext)
lemma fps_const_add [simp]: "fps_const (c::'a\<Colon>monoid_add) + fps_const d = fps_const (c + d)"
by (simp add: fps_ext)
lemma fps_const_sub [simp]: "fps_const (c::'a\<Colon>group_add) - fps_const d = fps_const (c - d)"
by (simp add: fps_ext)
lemma fps_const_mult[simp]: "fps_const (c::'a\<Colon>ring) * fps_const d = fps_const (c * d)"
by (simp add: fps_eq_iff fps_mult_nth setsum_0')
lemma fps_const_add_left: "fps_const (c::'a\<Colon>monoid_add) + f = Abs_fps (\<lambda>n. if n = 0 then c + f$0 else f$n)"
by (simp add: fps_ext)
lemma fps_const_add_right: "f + fps_const (c::'a\<Colon>monoid_add) = Abs_fps (\<lambda>n. if n = 0 then f$0 + c else f$n)"
by (simp add: fps_ext)
lemma fps_const_mult_left: "fps_const (c::'a\<Colon>semiring_0) * f = Abs_fps (\<lambda>n. c * f$n)"
unfolding fps_eq_iff fps_mult_nth
by (simp add: fps_const_def mult_delta_left setsum_delta)
lemma fps_const_mult_right: "f * fps_const (c::'a\<Colon>semiring_0) = Abs_fps (\<lambda>n. f$n * c)"
unfolding fps_eq_iff fps_mult_nth
by (simp add: fps_const_def mult_delta_right setsum_delta')
lemma fps_mult_left_const_nth [simp]: "(fps_const (c::'a::semiring_1) * f)$n = c* f$n"
by (simp add: fps_mult_nth mult_delta_left setsum_delta)
lemma fps_mult_right_const_nth [simp]: "(f * fps_const (c::'a::semiring_1))$n = f$n * c"
by (simp add: fps_mult_nth mult_delta_right setsum_delta')
subsection {* Formal power series form an integral domain*}
instance fps :: (ring) ring ..
instance fps :: (ring_1) ring_1
by (intro_classes, auto simp add: diff_minus left_distrib)
instance fps :: (comm_ring_1) comm_ring_1
by (intro_classes, auto simp add: diff_minus left_distrib)
instance fps :: (ring_no_zero_divisors) ring_no_zero_divisors
proof
fix a b :: "'a fps"
assume a0: "a \<noteq> 0" and b0: "b \<noteq> 0"
then obtain i j where i: "a$i\<noteq>0" "\<forall>k<i. a$k=0"
and j: "b$j \<noteq>0" "\<forall>k<j. b$k =0" unfolding fps_nonzero_nth_minimal
by blast+
have "(a * b) $ (i+j) = (\<Sum>k=0..i+j. a$k * b$(i+j-k))"
by (rule fps_mult_nth)
also have "\<dots> = (a$i * b$(i+j-i)) + (\<Sum>k\<in>{0..i+j}-{i}. a$k * b$(i+j-k))"
by (rule setsum_diff1') simp_all
also have "(\<Sum>k\<in>{0..i+j}-{i}. a$k * b$(i+j-k)) = 0"
proof (rule setsum_0' [rule_format])
fix k assume "k \<in> {0..i+j} - {i}"
then have "k < i \<or> i+j-k < j" by auto
then show "a$k * b$(i+j-k) = 0" using i j by auto
qed
also have "a$i * b$(i+j-i) + 0 = a$i * b$j" by simp
also have "a$i * b$j \<noteq> 0" using i j by simp
finally have "(a*b) $ (i+j) \<noteq> 0" .
then show "a*b \<noteq> 0" unfolding fps_nonzero_nth by blast
qed
instance fps :: (idom) idom ..
instantiation fps :: (comm_ring_1) number_ring
begin
definition number_of_fps_def: "(number_of k::'a fps) = of_int k"
instance
by (intro_classes, rule number_of_fps_def)
end
lemma number_of_fps_const: "(number_of k::('a::comm_ring_1) fps) = fps_const (of_int k)"
proof(induct k rule: int_induct[where k=0])
case base thus ?case unfolding number_of_fps_def of_int_0 by simp
next
case (step1 i) thus ?case unfolding number_of_fps_def
by (simp add: fps_const_add[symmetric] del: fps_const_add)
next
case (step2 i) thus ?case unfolding number_of_fps_def
by (simp add: fps_const_sub[symmetric] del: fps_const_sub)
qed
subsection{* Inverses of formal power series *}
declare setsum_cong[fundef_cong]
instantiation fps :: ("{comm_monoid_add,inverse, times, uminus}") inverse
begin
fun natfun_inverse:: "'a fps \<Rightarrow> nat \<Rightarrow> 'a" where
"natfun_inverse f 0 = inverse (f$0)"
| "natfun_inverse f n = - inverse (f$0) * setsum (\<lambda>i. f$i * natfun_inverse f (n - i)) {1..n}"
definition fps_inverse_def:
"inverse f = (if f$0 = 0 then 0 else Abs_fps (natfun_inverse f))"
definition fps_divide_def: "divide = (\<lambda>(f::'a fps) g. f * inverse g)"
instance ..
end
lemma fps_inverse_zero[simp]:
"inverse (0 :: 'a::{comm_monoid_add,inverse, times, uminus} fps) = 0"
by (simp add: fps_ext fps_inverse_def)
lemma fps_inverse_one[simp]: "inverse (1 :: 'a::{division_ring,zero_neq_one} fps) = 1"
apply (auto simp add: expand_fps_eq fps_inverse_def)
by (case_tac n, auto)
instance fps :: ("{comm_monoid_add,inverse, times, uminus}") division_by_zero
by default (rule fps_inverse_zero)
lemma inverse_mult_eq_1[intro]: assumes f0: "f$0 \<noteq> (0::'a::field)"
shows "inverse f * f = 1"
proof-
have c: "inverse f * f = f * inverse f" by (simp add: mult_commute)
from f0 have ifn: "\<And>n. inverse f $ n = natfun_inverse f n"
by (simp add: fps_inverse_def)
from f0 have th0: "(inverse f * f) $ 0 = 1"
by (simp add: fps_mult_nth fps_inverse_def)
{fix n::nat assume np: "n >0 "
from np have eq: "{0..n} = {0} \<union> {1 .. n}" by auto
have d: "{0} \<inter> {1 .. n} = {}" by auto
have f: "finite {0::nat}" "finite {1..n}" by auto
from f0 np have th0: "- (inverse f$n) =
(setsum (\<lambda>i. f$i * natfun_inverse f (n - i)) {1..n}) / (f$0)"
by (cases n, simp, simp add: divide_inverse fps_inverse_def)
from th0[symmetric, unfolded nonzero_divide_eq_eq[OF f0]]
have th1: "setsum (\<lambda>i. f$i * natfun_inverse f (n - i)) {1..n} =
- (f$0) * (inverse f)$n"
by (simp add: ring_simps)
have "(f * inverse f) $ n = (\<Sum>i = 0..n. f $i * natfun_inverse f (n - i))"
unfolding fps_mult_nth ifn ..
also have "\<dots> = f$0 * natfun_inverse f n
+ (\<Sum>i = 1..n. f$i * natfun_inverse f (n-i))"
unfolding setsum_Un_disjoint[OF f d, unfolded eq[symmetric]]
by simp
also have "\<dots> = 0" unfolding th1 ifn by simp
finally have "(inverse f * f)$n = 0" unfolding c . }
with th0 show ?thesis by (simp add: fps_eq_iff)
qed
lemma fps_inverse_0_iff[simp]: "(inverse f)$0 = (0::'a::division_ring) \<longleftrightarrow> f$0 = 0"
by (simp add: fps_inverse_def nonzero_imp_inverse_nonzero)
lemma fps_inverse_eq_0_iff[simp]: "inverse f = (0:: ('a::field) fps) \<longleftrightarrow> f $0 = 0"
proof-
{assume "f$0 = 0" hence "inverse f = 0" by (simp add: fps_inverse_def)}
moreover
{assume h: "inverse f = 0" and c: "f $0 \<noteq> 0"
from inverse_mult_eq_1[OF c] h have False by simp}
ultimately show ?thesis by blast
qed
lemma fps_inverse_idempotent[intro]: assumes f0: "f$0 \<noteq> (0::'a::field)"
shows "inverse (inverse f) = f"
proof-
from f0 have if0: "inverse f $ 0 \<noteq> 0" by simp
from inverse_mult_eq_1[OF f0] inverse_mult_eq_1[OF if0]
have th0: "inverse f * f = inverse f * inverse (inverse f)" by (simp add: mult_ac)
then show ?thesis using f0 unfolding mult_cancel_left by simp
qed
lemma fps_inverse_unique: assumes f0: "f$0 \<noteq> (0::'a::field)" and fg: "f*g = 1"
shows "inverse f = g"
proof-
from inverse_mult_eq_1[OF f0] fg
have th0: "inverse f * f = g * f" by (simp add: mult_ac)
then show ?thesis using f0 unfolding mult_cancel_right
by (auto simp add: expand_fps_eq)
qed
lemma fps_inverse_gp: "inverse (Abs_fps(\<lambda>n. (1::'a::field)))
= Abs_fps (\<lambda>n. if n= 0 then 1 else if n=1 then - 1 else 0)"
apply (rule fps_inverse_unique)
apply simp
apply (simp add: fps_eq_iff fps_mult_nth)
proof(clarsimp)
fix n::nat assume n: "n > 0"
let ?f = "\<lambda>i. if n = i then (1\<Colon>'a) else if n - i = 1 then - 1 else 0"
let ?g = "\<lambda>i. if i = n then 1 else if i=n - 1 then - 1 else 0"
let ?h = "\<lambda>i. if i=n - 1 then - 1 else 0"
have th1: "setsum ?f {0..n} = setsum ?g {0..n}"
by (rule setsum_cong2) auto
have th2: "setsum ?g {0..n - 1} = setsum ?h {0..n - 1}"
using n apply - by (rule setsum_cong2) auto
have eq: "{0 .. n} = {0.. n - 1} \<union> {n}" by auto
from n have d: "{0.. n - 1} \<inter> {n} = {}" by auto
have f: "finite {0.. n - 1}" "finite {n}" by auto
show "setsum ?f {0..n} = 0"
unfolding th1
apply (simp add: setsum_Un_disjoint[OF f d, unfolded eq[symmetric]] del: One_nat_def)
unfolding th2
by(simp add: setsum_delta)
qed
subsection{* Formal Derivatives, and the MacLaurin theorem around 0*}
definition "fps_deriv f = Abs_fps (\<lambda>n. of_nat (n + 1) * f $ (n + 1))"
lemma fps_deriv_nth[simp]: "fps_deriv f $ n = of_nat (n +1) * f $ (n+1)" by (simp add: fps_deriv_def)
lemma fps_deriv_linear[simp]: "fps_deriv (fps_const (a::'a::comm_semiring_1) * f + fps_const b * g) = fps_const a * fps_deriv f + fps_const b * fps_deriv g"
unfolding fps_eq_iff fps_add_nth fps_const_mult_left fps_deriv_nth by (simp add: ring_simps)
lemma fps_deriv_mult[simp]:
fixes f :: "('a :: comm_ring_1) fps"
shows "fps_deriv (f * g) = f * fps_deriv g + fps_deriv f * g"
proof-
let ?D = "fps_deriv"
{fix n::nat
let ?Zn = "{0 ..n}"
let ?Zn1 = "{0 .. n + 1}"
let ?f = "\<lambda>i. i + 1"
have fi: "inj_on ?f {0..n}" by (simp add: inj_on_def)
have eq: "{1.. n+1} = ?f ` {0..n}" by auto
let ?g = "\<lambda>i. of_nat (i+1) * g $ (i+1) * f $ (n - i) +
of_nat (i+1)* f $ (i+1) * g $ (n - i)"
let ?h = "\<lambda>i. of_nat i * g $ i * f $ ((n+1) - i) +
of_nat i* f $ i * g $ ((n + 1) - i)"
{fix k assume k: "k \<in> {0..n}"
have "?h (k + 1) = ?g k" using k by auto}
note th0 = this
have eq': "{0..n +1}- {1 .. n+1} = {0}" by auto
have s0: "setsum (\<lambda>i. of_nat i * f $ i * g $ (n + 1 - i)) ?Zn1 = setsum (\<lambda>i. of_nat (n + 1 - i) * f $ (n + 1 - i) * g $ i) ?Zn1"
apply (rule setsum_reindex_cong[where f="\<lambda>i. n + 1 - i"])
apply (simp add: inj_on_def Ball_def)
apply presburger
apply (rule set_ext)
apply (presburger add: image_iff)
by simp
have s1: "setsum (\<lambda>i. f $ i * g $ (n + 1 - i)) ?Zn1 = setsum (\<lambda>i. f $ (n + 1 - i) * g $ i) ?Zn1"
apply (rule setsum_reindex_cong[where f="\<lambda>i. n + 1 - i"])
apply (simp add: inj_on_def Ball_def)
apply presburger
apply (rule set_ext)
apply (presburger add: image_iff)
by simp
have "(f * ?D g + ?D f * g)$n = (?D g * f + ?D f * g)$n" by (simp only: mult_commute)
also have "\<dots> = (\<Sum>i = 0..n. ?g i)"
by (simp add: fps_mult_nth setsum_addf[symmetric])
also have "\<dots> = setsum ?h {1..n+1}"
using th0 setsum_reindex_cong[OF fi eq, of "?g" "?h"] by auto
also have "\<dots> = setsum ?h {0..n+1}"
apply (rule setsum_mono_zero_left)
apply simp
apply (simp add: subset_eq)
unfolding eq'
by simp
also have "\<dots> = (fps_deriv (f * g)) $ n"
apply (simp only: fps_deriv_nth fps_mult_nth setsum_addf)
unfolding s0 s1
unfolding setsum_addf[symmetric] setsum_right_distrib
apply (rule setsum_cong2)
by (auto simp add: of_nat_diff ring_simps)
finally have "(f * ?D g + ?D f * g) $ n = ?D (f*g) $ n" .}
then show ?thesis unfolding fps_eq_iff by auto
qed
lemma fps_deriv_neg[simp]: "fps_deriv (- (f:: ('a:: comm_ring_1) fps)) = - (fps_deriv f)"
by (simp add: fps_eq_iff fps_deriv_def)
lemma fps_deriv_add[simp]: "fps_deriv ((f:: ('a::comm_ring_1) fps) + g) = fps_deriv f + fps_deriv g"
using fps_deriv_linear[of 1 f 1 g] by simp
lemma fps_deriv_sub[simp]: "fps_deriv ((f:: ('a::comm_ring_1) fps) - g) = fps_deriv f - fps_deriv g"
unfolding diff_minus by simp
lemma fps_deriv_const[simp]: "fps_deriv (fps_const c) = 0"
by (simp add: fps_ext fps_deriv_def fps_const_def)
lemma fps_deriv_mult_const_left[simp]: "fps_deriv (fps_const (c::'a::comm_ring_1) * f) = fps_const c * fps_deriv f"
by simp
lemma fps_deriv_0[simp]: "fps_deriv 0 = 0"
by (simp add: fps_deriv_def fps_eq_iff)
lemma fps_deriv_1[simp]: "fps_deriv 1 = 0"
by (simp add: fps_deriv_def fps_eq_iff )
lemma fps_deriv_mult_const_right[simp]: "fps_deriv (f * fps_const (c::'a::comm_ring_1)) = fps_deriv f * fps_const c"
by simp
lemma fps_deriv_setsum: "fps_deriv (setsum f S) = setsum (\<lambda>i. fps_deriv (f i :: ('a::comm_ring_1) fps)) S"
proof-
{assume "\<not> finite S" hence ?thesis by simp}
moreover
{assume fS: "finite S"
have ?thesis by (induct rule: finite_induct[OF fS], simp_all)}
ultimately show ?thesis by blast
qed
lemma fps_deriv_eq_0_iff[simp]: "fps_deriv f = 0 \<longleftrightarrow> (f = fps_const (f$0 :: 'a::{idom,semiring_char_0}))"
proof-
{assume "f= fps_const (f$0)" hence "fps_deriv f = fps_deriv (fps_const (f$0))" by simp
hence "fps_deriv f = 0" by simp }
moreover
{assume z: "fps_deriv f = 0"
hence "\<forall>n. (fps_deriv f)$n = 0" by simp
hence "\<forall>n. f$(n+1) = 0" by (simp del: of_nat_Suc of_nat_add One_nat_def)
hence "f = fps_const (f$0)"
apply (clarsimp simp add: fps_eq_iff fps_const_def)
apply (erule_tac x="n - 1" in allE)
by simp}
ultimately show ?thesis by blast
qed
lemma fps_deriv_eq_iff:
fixes f:: "('a::{idom,semiring_char_0}) fps"
shows "fps_deriv f = fps_deriv g \<longleftrightarrow> (f = fps_const(f$0 - g$0) + g)"
proof-
have "fps_deriv f = fps_deriv g \<longleftrightarrow> fps_deriv (f - g) = 0" by simp
also have "\<dots> \<longleftrightarrow> f - g = fps_const ((f-g)$0)" unfolding fps_deriv_eq_0_iff ..
finally show ?thesis by (simp add: ring_simps)
qed
lemma fps_deriv_eq_iff_ex: "(fps_deriv f = fps_deriv g) \<longleftrightarrow> (\<exists>(c::'a::{idom,semiring_char_0}). f = fps_const c + g)"
apply auto unfolding fps_deriv_eq_iff by blast
fun fps_nth_deriv :: "nat \<Rightarrow> ('a::semiring_1) fps \<Rightarrow> 'a fps" where
"fps_nth_deriv 0 f = f"
| "fps_nth_deriv (Suc n) f = fps_nth_deriv n (fps_deriv f)"
lemma fps_nth_deriv_commute: "fps_nth_deriv (Suc n) f = fps_deriv (fps_nth_deriv n f)"
by (induct n arbitrary: f, auto)
lemma fps_nth_deriv_linear[simp]: "fps_nth_deriv n (fps_const (a::'a::comm_semiring_1) * f + fps_const b * g) = fps_const a * fps_nth_deriv n f + fps_const b * fps_nth_deriv n g"
by (induct n arbitrary: f g, auto simp add: fps_nth_deriv_commute)
lemma fps_nth_deriv_neg[simp]: "fps_nth_deriv n (- (f:: ('a:: comm_ring_1) fps)) = - (fps_nth_deriv n f)"
by (induct n arbitrary: f, simp_all)
lemma fps_nth_deriv_add[simp]: "fps_nth_deriv n ((f:: ('a::comm_ring_1) fps) + g) = fps_nth_deriv n f + fps_nth_deriv n g"
using fps_nth_deriv_linear[of n 1 f 1 g] by simp
lemma fps_nth_deriv_sub[simp]: "fps_nth_deriv n ((f:: ('a::comm_ring_1) fps) - g) = fps_nth_deriv n f - fps_nth_deriv n g"
unfolding diff_minus fps_nth_deriv_add by simp
lemma fps_nth_deriv_0[simp]: "fps_nth_deriv n 0 = 0"
by (induct n, simp_all )
lemma fps_nth_deriv_1[simp]: "fps_nth_deriv n 1 = (if n = 0 then 1 else 0)"
by (induct n, simp_all )
lemma fps_nth_deriv_const[simp]: "fps_nth_deriv n (fps_const c) = (if n = 0 then fps_const c else 0)"
by (cases n, simp_all)
lemma fps_nth_deriv_mult_const_left[simp]: "fps_nth_deriv n (fps_const (c::'a::comm_ring_1) * f) = fps_const c * fps_nth_deriv n f"
using fps_nth_deriv_linear[of n "c" f 0 0 ] by simp
lemma fps_nth_deriv_mult_const_right[simp]: "fps_nth_deriv n (f * fps_const (c::'a::comm_ring_1)) = fps_nth_deriv n f * fps_const c"
using fps_nth_deriv_linear[of n "c" f 0 0] by (simp add: mult_commute)
lemma fps_nth_deriv_setsum: "fps_nth_deriv n (setsum f S) = setsum (\<lambda>i. fps_nth_deriv n (f i :: ('a::comm_ring_1) fps)) S"
proof-
{assume "\<not> finite S" hence ?thesis by simp}
moreover
{assume fS: "finite S"
have ?thesis by (induct rule: finite_induct[OF fS], simp_all)}
ultimately show ?thesis by blast
qed
lemma fps_deriv_maclauren_0: "(fps_nth_deriv k (f:: ('a::comm_semiring_1) fps)) $ 0 = of_nat (fact k) * f$(k)"
by (induct k arbitrary: f) (auto simp add: ring_simps of_nat_mult)
subsection {* Powers*}
lemma fps_power_zeroth_eq_one: "a$0 =1 \<Longrightarrow> a^n $ 0 = (1::'a::semiring_1)"
by (induct n, auto simp add: expand_fps_eq fps_mult_nth)
lemma fps_power_first_eq: "(a:: 'a::comm_ring_1 fps)$0 =1 \<Longrightarrow> a^n $ 1 = of_nat n * a$1"
proof(induct n)
case 0 thus ?case by simp
next
case (Suc n)
note h = Suc.hyps[OF `a$0 = 1`]
show ?case unfolding power_Suc fps_mult_nth
using h `a$0 = 1` fps_power_zeroth_eq_one[OF `a$0=1`] by (simp add: ring_simps)
qed
lemma startsby_one_power:"a $ 0 = (1::'a::comm_ring_1) \<Longrightarrow> a^n $ 0 = 1"
by (induct n, auto simp add: fps_mult_nth)
lemma startsby_zero_power:"a $0 = (0::'a::comm_ring_1) \<Longrightarrow> n > 0 \<Longrightarrow> a^n $0 = 0"
by (induct n, auto simp add: fps_mult_nth)
lemma startsby_power:"a $0 = (v::'a::{comm_ring_1}) \<Longrightarrow> a^n $0 = v^n"
by (induct n, auto simp add: fps_mult_nth power_Suc)
lemma startsby_zero_power_iff[simp]:
"a^n $0 = (0::'a::{idom}) \<longleftrightarrow> (n \<noteq> 0 \<and> a$0 = 0)"
apply (rule iffI)
apply (induct n, auto simp add: power_Suc fps_mult_nth)
by (rule startsby_zero_power, simp_all)
lemma startsby_zero_power_prefix:
assumes a0: "a $0 = (0::'a::idom)"
shows "\<forall>n < k. a ^ k $ n = 0"
using a0
proof(induct k rule: nat_less_induct)
fix k assume H: "\<forall>m<k. a $0 = 0 \<longrightarrow> (\<forall>n<m. a ^ m $ n = 0)" and a0: "a $0 = (0\<Colon>'a)"
let ?ths = "\<forall>m<k. a ^ k $ m = 0"
{assume "k = 0" then have ?ths by simp}
moreover
{fix l assume k: "k = Suc l"
{fix m assume mk: "m < k"
{assume "m=0" hence "a^k $ m = 0" using startsby_zero_power[of a k] k a0
by simp}
moreover
{assume m0: "m \<noteq> 0"
have "a ^k $ m = (a^l * a) $m" by (simp add: k power_Suc mult_commute)
also have "\<dots> = (\<Sum>i = 0..m. a ^ l $ i * a $ (m - i))" by (simp add: fps_mult_nth)
also have "\<dots> = 0" apply (rule setsum_0')
apply auto
apply (case_tac "aa = m")
using a0
apply simp
apply (rule H[rule_format])
using a0 k mk by auto
finally have "a^k $ m = 0" .}
ultimately have "a^k $ m = 0" by blast}
hence ?ths by blast}
ultimately show ?ths by (cases k, auto)
qed
lemma startsby_zero_setsum_depends:
assumes a0: "a $0 = (0::'a::idom)" and kn: "n \<ge> k"
shows "setsum (\<lambda>i. (a ^ i)$k) {0 .. n} = setsum (\<lambda>i. (a ^ i)$k) {0 .. k}"
apply (rule setsum_mono_zero_right)
using kn apply auto
apply (rule startsby_zero_power_prefix[rule_format, OF a0])
by arith
lemma startsby_zero_power_nth_same: assumes a0: "a$0 = (0::'a::{idom})"
shows "a^n $ n = (a$1) ^ n"
proof(induct n)
case 0 thus ?case by (simp add: power_0)
next
case (Suc n)
have "a ^ Suc n $ (Suc n) = (a^n * a)$(Suc n)" by (simp add: ring_simps power_Suc)
also have "\<dots> = setsum (\<lambda>i. a^n$i * a $ (Suc n - i)) {0.. Suc n}" by (simp add: fps_mult_nth)
also have "\<dots> = setsum (\<lambda>i. a^n$i * a $ (Suc n - i)) {n .. Suc n}"
apply (rule setsum_mono_zero_right)
apply simp
apply clarsimp
apply clarsimp
apply (rule startsby_zero_power_prefix[rule_format, OF a0])
apply arith
done
also have "\<dots> = a^n $ n * a$1" using a0 by simp
finally show ?case using Suc.hyps by (simp add: power_Suc)
qed
lemma fps_inverse_power:
fixes a :: "('a::{field}) fps"
shows "inverse (a^n) = inverse a ^ n"
proof-
{assume a0: "a$0 = 0"
hence eq: "inverse a = 0" by (simp add: fps_inverse_def)
{assume "n = 0" hence ?thesis by simp}
moreover
{assume n: "n > 0"
from startsby_zero_power[OF a0 n] eq a0 n have ?thesis
by (simp add: fps_inverse_def)}
ultimately have ?thesis by blast}
moreover
{assume a0: "a$0 \<noteq> 0"
have ?thesis
apply (rule fps_inverse_unique)
apply (simp add: a0)
unfolding power_mult_distrib[symmetric]
apply (rule ssubst[where t = "a * inverse a" and s= 1])
apply simp_all
apply (subst mult_commute)
by (rule inverse_mult_eq_1[OF a0])}
ultimately show ?thesis by blast
qed
lemma fps_deriv_power: "fps_deriv (a ^ n) = fps_const (of_nat n :: 'a:: comm_ring_1) * fps_deriv a * a ^ (n - 1)"
apply (induct n, auto simp add: power_Suc ring_simps fps_const_add[symmetric] simp del: fps_const_add)
by (case_tac n, auto simp add: power_Suc ring_simps)
lemma fps_inverse_deriv:
fixes a:: "('a :: field) fps"
assumes a0: "a$0 \<noteq> 0"
shows "fps_deriv (inverse a) = - fps_deriv a * inverse a ^ 2"
proof-
from inverse_mult_eq_1[OF a0]
have "fps_deriv (inverse a * a) = 0" by simp
hence "inverse a * fps_deriv a + fps_deriv (inverse a) * a = 0" by simp
hence "inverse a * (inverse a * fps_deriv a + fps_deriv (inverse a) * a) = 0" by simp
with inverse_mult_eq_1[OF a0]
have "inverse a ^ 2 * fps_deriv a + fps_deriv (inverse a) = 0"
unfolding power2_eq_square
apply (simp add: ring_simps)
by (simp add: mult_assoc[symmetric])
hence "inverse a ^ 2 * fps_deriv a + fps_deriv (inverse a) - fps_deriv a * inverse a ^ 2 = 0 - fps_deriv a * inverse a ^ 2"
by simp
then show "fps_deriv (inverse a) = - fps_deriv a * inverse a ^ 2" by (simp add: ring_simps)
qed
lemma fps_inverse_mult:
fixes a::"('a :: field) fps"
shows "inverse (a * b) = inverse a * inverse b"
proof-
{assume a0: "a$0 = 0" hence ab0: "(a*b)$0 = 0" by (simp add: fps_mult_nth)
from a0 ab0 have th: "inverse a = 0" "inverse (a*b) = 0" by simp_all
have ?thesis unfolding th by simp}
moreover
{assume b0: "b$0 = 0" hence ab0: "(a*b)$0 = 0" by (simp add: fps_mult_nth)
from b0 ab0 have th: "inverse b = 0" "inverse (a*b) = 0" by simp_all
have ?thesis unfolding th by simp}
moreover
{assume a0: "a$0 \<noteq> 0" and b0: "b$0 \<noteq> 0"
from a0 b0 have ab0:"(a*b) $ 0 \<noteq> 0" by (simp add: fps_mult_nth)
from inverse_mult_eq_1[OF ab0]
have "inverse (a*b) * (a*b) * inverse a * inverse b = 1 * inverse a * inverse b" by simp
then have "inverse (a*b) * (inverse a * a) * (inverse b * b) = inverse a * inverse b"
by (simp add: ring_simps)
then have ?thesis using inverse_mult_eq_1[OF a0] inverse_mult_eq_1[OF b0] by simp}
ultimately show ?thesis by blast
qed
lemma fps_inverse_deriv':
fixes a:: "('a :: field) fps"
assumes a0: "a$0 \<noteq> 0"
shows "fps_deriv (inverse a) = - fps_deriv a / a ^ 2"
using fps_inverse_deriv[OF a0]
unfolding power2_eq_square fps_divide_def
fps_inverse_mult by simp
lemma inverse_mult_eq_1': assumes f0: "f$0 \<noteq> (0::'a::field)"
shows "f * inverse f= 1"
by (metis mult_commute inverse_mult_eq_1 f0)
lemma fps_divide_deriv: fixes a:: "('a :: field) fps"
assumes a0: "b$0 \<noteq> 0"
shows "fps_deriv (a / b) = (fps_deriv a * b - a * fps_deriv b) / b ^ 2"
using fps_inverse_deriv[OF a0]
by (simp add: fps_divide_def ring_simps power2_eq_square fps_inverse_mult inverse_mult_eq_1'[OF a0])
subsection{* The eXtractor series X*}
lemma minus_one_power_iff: "(- (1::'a :: {comm_ring_1})) ^ n = (if even n then 1 else - 1)"
by (induct n, auto)
definition "X = Abs_fps (\<lambda>n. if n = 1 then 1 else 0)"
lemma fps_inverse_gp': "inverse (Abs_fps(\<lambda>n. (1::'a::field)))
= 1 - X"
by (simp add: fps_inverse_gp fps_eq_iff X_def)
lemma X_mult_nth[simp]: "(X * (f :: ('a::semiring_1) fps)) $n = (if n = 0 then 0 else f $ (n - 1))"
proof-
{assume n: "n \<noteq> 0"
have fN: "finite {0 .. n}" by simp
have "(X * f) $n = (\<Sum>i = 0..n. X $ i * f $ (n - i))" by (simp add: fps_mult_nth)
also have "\<dots> = f $ (n - 1)"
using n by (simp add: X_def mult_delta_left setsum_delta [OF fN])
finally have ?thesis using n by simp }
moreover
{assume n: "n=0" hence ?thesis by (simp add: fps_mult_nth X_def)}
ultimately show ?thesis by blast
qed
lemma X_mult_right_nth[simp]: "((f :: ('a::comm_semiring_1) fps) * X) $n = (if n = 0 then 0 else f $ (n - 1))"
by (metis X_mult_nth mult_commute)
lemma X_power_iff: "X^k = Abs_fps (\<lambda>n. if n = k then (1::'a::comm_ring_1) else 0)"
proof(induct k)
case 0 thus ?case by (simp add: X_def fps_eq_iff)
next
case (Suc k)
{fix m
have "(X^Suc k) $ m = (if m = 0 then (0::'a) else (X^k) $ (m - 1))"
by (simp add: power_Suc del: One_nat_def)
then have "(X^Suc k) $ m = (if m = Suc k then (1::'a) else 0)"
using Suc.hyps by (auto cong del: if_weak_cong)}
then show ?case by (simp add: fps_eq_iff)
qed
lemma X_power_mult_nth: "(X^k * (f :: ('a::comm_ring_1) fps)) $n = (if n < k then 0 else f $ (n - k))"
apply (induct k arbitrary: n)
apply (simp)
unfolding power_Suc mult_assoc
by (case_tac n, auto)
lemma X_power_mult_right_nth: "((f :: ('a::comm_ring_1) fps) * X^k) $n = (if n < k then 0 else f $ (n - k))"
by (metis X_power_mult_nth mult_commute)
lemma fps_deriv_X[simp]: "fps_deriv X = 1"
by (simp add: fps_deriv_def X_def fps_eq_iff)
lemma fps_nth_deriv_X[simp]: "fps_nth_deriv n X = (if n = 0 then X else if n=1 then 1 else 0)"
by (cases "n", simp_all)
lemma X_nth[simp]: "X$n = (if n = 1 then 1 else 0)" by (simp add: X_def)
lemma X_power_nth[simp]: "(X^k) $n = (if n = k then 1 else (0::'a::comm_ring_1))"
by (simp add: X_power_iff)
lemma fps_inverse_X_plus1:
"inverse (1 + X) = Abs_fps (\<lambda>n. (- (1::'a::{field})) ^ n)" (is "_ = ?r")
proof-
have eq: "(1 + X) * ?r = 1"
unfolding minus_one_power_iff
by (auto simp add: ring_simps fps_eq_iff)
show ?thesis by (auto simp add: eq intro: fps_inverse_unique)
qed
subsection{* Integration *}
definition "fps_integral a a0 = Abs_fps (\<lambda>n. if n = 0 then a0 else (a$(n - 1) / of_nat n))"
lemma fps_deriv_fps_integral: "fps_deriv (fps_integral a (a0 :: 'a :: {field, ring_char_0})) = a"
by (simp add: fps_integral_def fps_deriv_def fps_eq_iff field_simps del: of_nat_Suc)
lemma fps_integral_linear: "fps_integral (fps_const (a::'a::{field, ring_char_0}) * f + fps_const b * g) (a*a0 + b*b0) = fps_const a * fps_integral f a0 + fps_const b * fps_integral g b0" (is "?l = ?r")
proof-
have "fps_deriv ?l = fps_deriv ?r" by (simp add: fps_deriv_fps_integral)
moreover have "?l$0 = ?r$0" by (simp add: fps_integral_def)
ultimately show ?thesis
unfolding fps_deriv_eq_iff by auto
qed
subsection {* Composition of FPSs *}
definition fps_compose :: "('a::semiring_1) fps \<Rightarrow> 'a fps \<Rightarrow> 'a fps" (infixl "oo" 55) where
fps_compose_def: "a oo b = Abs_fps (\<lambda>n. setsum (\<lambda>i. a$i * (b^i$n)) {0..n})"
lemma fps_compose_nth: "(a oo b)$n = setsum (\<lambda>i. a$i * (b^i$n)) {0..n}" by (simp add: fps_compose_def)
lemma fps_compose_X[simp]: "a oo X = (a :: ('a :: comm_ring_1) fps)"
by (simp add: fps_ext fps_compose_def mult_delta_right setsum_delta')
lemma fps_const_compose[simp]:
"fps_const (a::'a::{comm_ring_1}) oo b = fps_const (a)"
by (simp add: fps_eq_iff fps_compose_nth mult_delta_left setsum_delta)
lemma number_of_compose[simp]: "(number_of k::('a::{comm_ring_1}) fps) oo b = number_of k"
unfolding number_of_fps_const by simp
lemma X_fps_compose_startby0[simp]: "a$0 = 0 \<Longrightarrow> X oo a = (a :: ('a :: comm_ring_1) fps)"
by (simp add: fps_eq_iff fps_compose_def mult_delta_left setsum_delta
power_Suc not_le)
subsection {* Rules from Herbert Wilf's Generatingfunctionology*}
subsubsection {* Rule 1 *}
(* {a_{n+k}}_0^infty Corresponds to (f - setsum (\<lambda>i. a_i * x^i))/x^h, for h>0*)
lemma fps_power_mult_eq_shift:
"X^Suc k * Abs_fps (\<lambda>n. a (n + Suc k)) = Abs_fps a - setsum (\<lambda>i. fps_const (a i :: 'a:: comm_ring_1) * X^i) {0 .. k}" (is "?lhs = ?rhs")
proof-
{fix n:: nat
have "?lhs $ n = (if n < Suc k then 0 else a n)"
unfolding X_power_mult_nth by auto
also have "\<dots> = ?rhs $ n"
proof(induct k)
case 0 thus ?case by (simp add: fps_setsum_nth power_Suc)
next
case (Suc k)
note th = Suc.hyps[symmetric]
have "(Abs_fps a - setsum (\<lambda>i. fps_const (a i :: 'a) * X^i) {0 .. Suc k})$n = (Abs_fps a - setsum (\<lambda>i. fps_const (a i :: 'a) * X^i) {0 .. k} - fps_const (a (Suc k)) * X^ Suc k) $ n" by (simp add: ring_simps)
also have "\<dots> = (if n < Suc k then 0 else a n) - (fps_const (a (Suc k)) * X^ Suc k)$n"
using th
unfolding fps_sub_nth by simp
also have "\<dots> = (if n < Suc (Suc k) then 0 else a n)"
unfolding X_power_mult_right_nth
apply (auto simp add: not_less fps_const_def)
apply (rule cong[of a a, OF refl])
by arith
finally show ?case by simp
qed
finally have "?lhs $ n = ?rhs $ n" .}
then show ?thesis by (simp add: fps_eq_iff)
qed
subsubsection{* Rule 2*}
(* We can not reach the form of Wilf, but still near to it using rewrite rules*)
(* If f reprents {a_n} and P is a polynomial, then
P(xD) f represents {P(n) a_n}*)
definition "XD = op * X o fps_deriv"
lemma XD_add[simp]:"XD (a + b) = XD a + XD (b :: ('a::comm_ring_1) fps)"
by (simp add: XD_def ring_simps)
lemma XD_mult_const[simp]:"XD (fps_const (c::'a::comm_ring_1) * a) = fps_const c * XD a"
by (simp add: XD_def ring_simps)
lemma XD_linear[simp]: "XD (fps_const c * a + fps_const d * b) = fps_const c * XD a + fps_const d * XD (b :: ('a::comm_ring_1) fps)"
by simp
lemma XDN_linear:
"(XD ^^ n) (fps_const c * a + fps_const d * b) = fps_const c * (XD ^^ n) a + fps_const d * (XD ^^ n) (b :: ('a::comm_ring_1) fps)"
by (induct n, simp_all)
lemma fps_mult_X_deriv_shift: "X* fps_deriv a = Abs_fps (\<lambda>n. of_nat n* a$n)" by (simp add: fps_eq_iff)
lemma fps_mult_XD_shift:
"(XD ^^ k) (a:: ('a::{comm_ring_1}) fps) = Abs_fps (\<lambda>n. (of_nat n ^ k) * a$n)"
by (induct k arbitrary: a) (simp_all add: power_Suc XD_def fps_eq_iff ring_simps del: One_nat_def)
subsubsection{* Rule 3 is trivial and is given by @{text fps_times_def}*}
subsubsection{* Rule 5 --- summation and "division" by (1 - X)*}
lemma fps_divide_X_minus1_setsum_lemma:
"a = ((1::('a::comm_ring_1) fps) - X) * Abs_fps (\<lambda>n. setsum (\<lambda>i. a $ i) {0..n})"
proof-
let ?X = "X::('a::comm_ring_1) fps"
let ?sa = "Abs_fps (\<lambda>n. setsum (\<lambda>i. a $ i) {0..n})"
have th0: "\<And>i. (1 - (X::'a fps)) $ i = (if i = 0 then 1 else if i = 1 then - 1 else 0)" by simp
{fix n:: nat
{assume "n=0" hence "a$n = ((1 - ?X) * ?sa) $ n"
by (simp add: fps_mult_nth)}
moreover
{assume n0: "n \<noteq> 0"
then have u: "{0} \<union> ({1} \<union> {2..n}) = {0..n}" "{1}\<union>{2..n} = {1..n}"
"{0..n - 1}\<union>{n} = {0..n}"
apply (simp_all add: expand_set_eq) by presburger+
have d: "{0} \<inter> ({1} \<union> {2..n}) = {}" "{1} \<inter> {2..n} = {}"
"{0..n - 1}\<inter>{n} ={}" using n0
by (simp_all add: expand_set_eq, presburger+)
have f: "finite {0}" "finite {1}" "finite {2 .. n}"
"finite {0 .. n - 1}" "finite {n}" by simp_all
have "((1 - ?X) * ?sa) $ n = setsum (\<lambda>i. (1 - ?X)$ i * ?sa $ (n - i)) {0 .. n}"
by (simp add: fps_mult_nth)
also have "\<dots> = a$n" unfolding th0
unfolding setsum_Un_disjoint[OF f(1) finite_UnI[OF f(2,3)] d(1), unfolded u(1)]
unfolding setsum_Un_disjoint[OF f(2) f(3) d(2)]
apply (simp)
unfolding setsum_Un_disjoint[OF f(4,5) d(3), unfolded u(3)]
by simp
finally have "a$n = ((1 - ?X) * ?sa) $ n" by simp}
ultimately have "a$n = ((1 - ?X) * ?sa) $ n" by blast}
then show ?thesis
unfolding fps_eq_iff by blast
qed
lemma fps_divide_X_minus1_setsum:
"a /((1::('a::field) fps) - X) = Abs_fps (\<lambda>n. setsum (\<lambda>i. a $ i) {0..n})"
proof-
let ?X = "1 - (X::('a::field) fps)"
have th0: "?X $ 0 \<noteq> 0" by simp
have "a /?X = ?X * Abs_fps (\<lambda>n\<Colon>nat. setsum (op $ a) {0..n}) * inverse ?X"
using fps_divide_X_minus1_setsum_lemma[of a, symmetric] th0
by (simp add: fps_divide_def mult_assoc)
also have "\<dots> = (inverse ?X * ?X) * Abs_fps (\<lambda>n\<Colon>nat. setsum (op $ a) {0..n}) "
by (simp add: mult_ac)
finally show ?thesis by (simp add: inverse_mult_eq_1[OF th0])
qed
subsubsection{* Rule 4 in its more general form: generalizes Rule 3 for an arbitrary
finite product of FPS, also the relvant instance of powers of a FPS*}
definition "natpermute n k = {l:: nat list. length l = k \<and> foldl op + 0 l = n}"
lemma natlist_trivial_1: "natpermute n 1 = {[n]}"
apply (auto simp add: natpermute_def)
apply (case_tac x, auto)
done
lemma foldl_add_start0:
"foldl op + x xs = x + foldl op + (0::nat) xs"
apply (induct xs arbitrary: x)
apply simp
unfolding foldl.simps
apply atomize
apply (subgoal_tac "\<forall>x\<Colon>nat. foldl op + x xs = x + foldl op + (0\<Colon>nat) xs")
apply (erule_tac x="x + a" in allE)
apply (erule_tac x="a" in allE)
apply simp
apply assumption
done
lemma foldl_add_append: "foldl op + (x::nat) (xs@ys) = foldl op + x xs + foldl op + 0 ys"
apply (induct ys arbitrary: x xs)
apply auto
apply (subst (2) foldl_add_start0)
apply simp
apply (subst (2) foldl_add_start0)
by simp
lemma foldl_add_setsum: "foldl op + (x::nat) xs = x + setsum (nth xs) {0..<length xs}"
proof(induct xs arbitrary: x)
case Nil thus ?case by simp
next
case (Cons a as x)
have eq: "setsum (op ! (a#as)) {1..<length (a#as)} = setsum (op ! as) {0..<length as}"
apply (rule setsum_reindex_cong [where f=Suc])
by (simp_all add: inj_on_def)
have f: "finite {0}" "finite {1 ..< length (a#as)}" by simp_all
have d: "{0} \<inter> {1..<length (a#as)} = {}" by simp
have seq: "{0} \<union> {1..<length(a#as)} = {0 ..<length (a#as)}" by auto
have "foldl op + x (a#as) = x + foldl op + a as "
apply (subst foldl_add_start0) by simp
also have "\<dots> = x + a + setsum (op ! as) {0..<length as}" unfolding Cons.hyps by simp
also have "\<dots> = x + setsum (op ! (a#as)) {0..<length (a#as)}"
unfolding eq[symmetric]
unfolding setsum_Un_disjoint[OF f d, unfolded seq]
by simp
finally show ?case .
qed
lemma append_natpermute_less_eq:
assumes h: "xs@ys \<in> natpermute n k" shows "foldl op + 0 xs \<le> n" and "foldl op + 0 ys \<le> n"
proof-
{from h have "foldl op + 0 (xs@ ys) = n" by (simp add: natpermute_def)
hence "foldl op + 0 xs + foldl op + 0 ys = n" unfolding foldl_add_append .}
note th = this
{from th show "foldl op + 0 xs \<le> n" by simp}
{from th show "foldl op + 0 ys \<le> n" by simp}
qed
lemma natpermute_split:
assumes mn: "h \<le> k"
shows "natpermute n k = (\<Union>m \<in>{0..n}. {l1 @ l2 |l1 l2. l1 \<in> natpermute m h \<and> l2 \<in> natpermute (n - m) (k - h)})" (is "?L = ?R" is "?L = (\<Union>m \<in>{0..n}. ?S m)")
proof-
{fix l assume l: "l \<in> ?R"
from l obtain m xs ys where h: "m \<in> {0..n}" and xs: "xs \<in> natpermute m h" and ys: "ys \<in> natpermute (n - m) (k - h)" and leq: "l = xs@ys" by blast
from xs have xs': "foldl op + 0 xs = m" by (simp add: natpermute_def)
from ys have ys': "foldl op + 0 ys = n - m" by (simp add: natpermute_def)
have "l \<in> ?L" using leq xs ys h
apply simp
apply (clarsimp simp add: natpermute_def simp del: foldl_append)
apply (simp add: foldl_add_append[unfolded foldl_append])
unfolding xs' ys'
using mn xs ys
unfolding natpermute_def by simp}
moreover
{fix l assume l: "l \<in> natpermute n k"
let ?xs = "take h l"
let ?ys = "drop h l"
let ?m = "foldl op + 0 ?xs"
from l have ls: "foldl op + 0 (?xs @ ?ys) = n" by (simp add: natpermute_def)
have xs: "?xs \<in> natpermute ?m h" using l mn by (simp add: natpermute_def)
have ys: "?ys \<in> natpermute (n - ?m) (k - h)" using l mn ls[unfolded foldl_add_append]
by (simp add: natpermute_def)
from ls have m: "?m \<in> {0..n}" unfolding foldl_add_append by simp
from xs ys ls have "l \<in> ?R"
apply auto
apply (rule bexI[where x = "?m"])
apply (rule exI[where x = "?xs"])
apply (rule exI[where x = "?ys"])
using ls l unfolding foldl_add_append
by (auto simp add: natpermute_def)}
ultimately show ?thesis by blast
qed
lemma natpermute_0: "natpermute n 0 = (if n = 0 then {[]} else {})"
by (auto simp add: natpermute_def)
lemma natpermute_0'[simp]: "natpermute 0 k = (if k = 0 then {[]} else {replicate k 0})"
apply (auto simp add: set_replicate_conv_if natpermute_def)
apply (rule nth_equalityI)
by simp_all
lemma natpermute_finite: "finite (natpermute n k)"
proof(induct k arbitrary: n)
case 0 thus ?case
apply (subst natpermute_split[of 0 0, simplified])
by (simp add: natpermute_0)
next
case (Suc k)
then show ?case unfolding natpermute_split[of k "Suc k", simplified]
apply -
apply (rule finite_UN_I)
apply simp
unfolding One_nat_def[symmetric] natlist_trivial_1
apply simp
unfolding image_Collect[symmetric]
unfolding Collect_def mem_def
apply (rule finite_imageI)
apply blast
done
qed
lemma natpermute_contain_maximal:
"{xs \<in> natpermute n (k+1). n \<in> set xs} = UNION {0 .. k} (\<lambda>i. {(replicate (k+1) 0) [i:=n]})"
(is "?A = ?B")
proof-
{fix xs assume H: "xs \<in> natpermute n (k+1)" and n: "n \<in> set xs"
from n obtain i where i: "i \<in> {0.. k}" "xs!i = n" using H
unfolding in_set_conv_nth by (auto simp add: less_Suc_eq_le natpermute_def)
have eqs: "({0..k} - {i}) \<union> {i} = {0..k}" using i by auto
have f: "finite({0..k} - {i})" "finite {i}" by auto
have d: "({0..k} - {i}) \<inter> {i} = {}" using i by auto
from H have "n = setsum (nth xs) {0..k}" apply (simp add: natpermute_def)
unfolding foldl_add_setsum by (auto simp add: atLeastLessThanSuc_atLeastAtMost)
also have "\<dots> = n + setsum (nth xs) ({0..k} - {i})"
unfolding setsum_Un_disjoint[OF f d, unfolded eqs] using i by simp
finally have zxs: "\<forall> j\<in> {0..k} - {i}. xs!j = 0" by auto
from H have xsl: "length xs = k+1" by (simp add: natpermute_def)
from i have i': "i < length (replicate (k+1) 0)" "i < k+1"
unfolding length_replicate by arith+
have "xs = replicate (k+1) 0 [i := n]"
apply (rule nth_equalityI)
unfolding xsl length_list_update length_replicate
apply simp
apply clarify
unfolding nth_list_update[OF i'(1)]
using i zxs
by (case_tac "ia=i", auto simp del: replicate.simps)
then have "xs \<in> ?B" using i by blast}
moreover
{fix i assume i: "i \<in> {0..k}"
let ?xs = "replicate (k+1) 0 [i:=n]"
have nxs: "n \<in> set ?xs"
apply (rule set_update_memI) using i by simp
have xsl: "length ?xs = k+1" by (simp only: length_replicate length_list_update)
have "foldl op + 0 ?xs = setsum (nth ?xs) {0..<k+1}"
unfolding foldl_add_setsum add_0 length_replicate length_list_update ..
also have "\<dots> = setsum (\<lambda>j. if j = i then n else 0) {0..< k+1}"
apply (rule setsum_cong2) by (simp del: replicate.simps)
also have "\<dots> = n" using i by (simp add: setsum_delta)
finally
have "?xs \<in> natpermute n (k+1)" using xsl unfolding natpermute_def Collect_def mem_def
by blast
then have "?xs \<in> ?A" using nxs by blast}
ultimately show ?thesis by auto
qed
(* The general form *)
lemma fps_setprod_nth:
fixes m :: nat and a :: "nat \<Rightarrow> ('a::comm_ring_1) fps"
shows "(setprod a {0 .. m})$n = setsum (\<lambda>v. setprod (\<lambda>j. (a j) $ (v!j)) {0..m}) (natpermute n (m+1))"
(is "?P m n")
proof(induct m arbitrary: n rule: nat_less_induct)
fix m n assume H: "\<forall>m' < m. \<forall>n. ?P m' n"
{assume m0: "m = 0"
hence "?P m n" apply simp
unfolding natlist_trivial_1[where n = n, unfolded One_nat_def] by simp}
moreover
{fix k assume k: "m = Suc k"
have km: "k < m" using k by arith
have u0: "{0 .. k} \<union> {m} = {0..m}" using k apply (simp add: expand_set_eq) by presburger
have f0: "finite {0 .. k}" "finite {m}" by auto
have d0: "{0 .. k} \<inter> {m} = {}" using k by auto
have "(setprod a {0 .. m}) $ n = (setprod a {0 .. k} * a m) $ n"
unfolding setprod_Un_disjoint[OF f0 d0, unfolded u0] by simp
also have "\<dots> = (\<Sum>i = 0..n. (\<Sum>v\<in>natpermute i (k + 1). \<Prod>j\<in>{0..k}. a j $ v ! j) * a m $ (n - i))"
unfolding fps_mult_nth H[rule_format, OF km] ..
also have "\<dots> = (\<Sum>v\<in>natpermute n (m + 1). \<Prod>j\<in>{0..m}. a j $ v ! j)"
apply (simp add: k)
unfolding natpermute_split[of m "m + 1", simplified, of n, unfolded natlist_trivial_1[unfolded One_nat_def] k]
apply (subst setsum_UN_disjoint)
apply simp
apply simp
unfolding image_Collect[symmetric]
apply clarsimp
apply (rule finite_imageI)
apply (rule natpermute_finite)
apply (clarsimp simp add: expand_set_eq)
apply auto
apply (rule setsum_cong2)
unfolding setsum_left_distrib
apply (rule sym)
apply (rule_tac f="\<lambda>xs. xs @[n - x]" in setsum_reindex_cong)
apply (simp add: inj_on_def)
apply auto
unfolding setprod_Un_disjoint[OF f0 d0, unfolded u0, unfolded k]
apply (clarsimp simp add: natpermute_def nth_append)
done
finally have "?P m n" .}
ultimately show "?P m n " by (cases m, auto)
qed
text{* The special form for powers *}
lemma fps_power_nth_Suc:
fixes m :: nat and a :: "('a::comm_ring_1) fps"
shows "(a ^ Suc m)$n = setsum (\<lambda>v. setprod (\<lambda>j. a $ (v!j)) {0..m}) (natpermute n (m+1))"
proof-
have f: "finite {0 ..m}" by simp
have th0: "a^Suc m = setprod (\<lambda>i. a) {0..m}" unfolding setprod_constant[OF f, of a] by simp
show ?thesis unfolding th0 fps_setprod_nth ..
qed
lemma fps_power_nth:
fixes m :: nat and a :: "('a::comm_ring_1) fps"
shows "(a ^m)$n = (if m=0 then 1$n else setsum (\<lambda>v. setprod (\<lambda>j. a $ (v!j)) {0..m - 1}) (natpermute n m))"
by (cases m, simp_all add: fps_power_nth_Suc del: power_Suc)
lemma fps_nth_power_0:
fixes m :: nat and a :: "('a::{comm_ring_1}) fps"
shows "(a ^m)$0 = (a$0) ^ m"
proof-
{assume "m=0" hence ?thesis by simp}
moreover
{fix n assume m: "m = Suc n"
have c: "m = card {0..n}" using m by simp
have "(a ^m)$0 = setprod (\<lambda>i. a$0) {0..n}"
by (simp add: m fps_power_nth del: replicate.simps power_Suc)
also have "\<dots> = (a$0) ^ m"
unfolding c by (rule setprod_constant, simp)
finally have ?thesis .}
ultimately show ?thesis by (cases m, auto)
qed
lemma fps_compose_inj_right:
assumes a0: "a$0 = (0::'a::{idom})"
and a1: "a$1 \<noteq> 0"
shows "(b oo a = c oo a) \<longleftrightarrow> b = c" (is "?lhs \<longleftrightarrow>?rhs")
proof-
{assume ?rhs then have "?lhs" by simp}
moreover
{assume h: ?lhs
{fix n have "b$n = c$n"
proof(induct n rule: nat_less_induct)
fix n assume H: "\<forall>m<n. b$m = c$m"
{assume n0: "n=0"
from h have "(b oo a)$n = (c oo a)$n" by simp
hence "b$n = c$n" using n0 by (simp add: fps_compose_nth)}
moreover
{fix n1 assume n1: "n = Suc n1"
have f: "finite {0 .. n1}" "finite {n}" by simp_all
have eq: "{0 .. n1} \<union> {n} = {0 .. n}" using n1 by auto
have d: "{0 .. n1} \<inter> {n} = {}" using n1 by auto
have seq: "(\<Sum>i = 0..n1. b $ i * a ^ i $ n) = (\<Sum>i = 0..n1. c $ i * a ^ i $ n)"
apply (rule setsum_cong2)
using H n1 by auto
have th0: "(b oo a) $n = (\<Sum>i = 0..n1. c $ i * a ^ i $ n) + b$n * (a$1)^n"
unfolding fps_compose_nth setsum_Un_disjoint[OF f d, unfolded eq] seq
using startsby_zero_power_nth_same[OF a0]
by simp
have th1: "(c oo a) $n = (\<Sum>i = 0..n1. c $ i * a ^ i $ n) + c$n * (a$1)^n"
unfolding fps_compose_nth setsum_Un_disjoint[OF f d, unfolded eq]
using startsby_zero_power_nth_same[OF a0]
by simp
from h[unfolded fps_eq_iff, rule_format, of n] th0 th1 a1
have "b$n = c$n" by auto}
ultimately show "b$n = c$n" by (cases n, auto)
qed}
then have ?rhs by (simp add: fps_eq_iff)}
ultimately show ?thesis by blast
qed
subsection {* Radicals *}
declare setprod_cong[fundef_cong]
function radical :: "(nat \<Rightarrow> 'a \<Rightarrow> 'a) \<Rightarrow> nat \<Rightarrow> ('a::{field}) fps \<Rightarrow> nat \<Rightarrow> 'a" where
"radical r 0 a 0 = 1"
| "radical r 0 a (Suc n) = 0"
| "radical r (Suc k) a 0 = r (Suc k) (a$0)"
| "radical r (Suc k) a (Suc n) = (a$ Suc n - setsum (\<lambda>xs. setprod (\<lambda>j. radical r (Suc k) a (xs ! j)) {0..k}) {xs. xs \<in> natpermute (Suc n) (Suc k) \<and> Suc n \<notin> set xs}) / (of_nat (Suc k) * (radical r (Suc k) a 0)^k)"
by pat_completeness auto
termination radical
proof
let ?R = "measure (\<lambda>(r, k, a, n). n)"
{
show "wf ?R" by auto}
{fix r k a n xs i
assume xs: "xs \<in> {xs \<in> natpermute (Suc n) (Suc k). Suc n \<notin> set xs}" and i: "i \<in> {0..k}"
{assume c: "Suc n \<le> xs ! i"
from xs i have "xs !i \<noteq> Suc n" by (auto simp add: in_set_conv_nth natpermute_def)
with c have c': "Suc n < xs!i" by arith
have fths: "finite {0 ..< i}" "finite {i}" "finite {i+1..<Suc k}" by simp_all
have d: "{0 ..< i} \<inter> ({i} \<union> {i+1 ..< Suc k}) = {}" "{i} \<inter> {i+1..< Suc k} = {}" by auto
have eqs: "{0..<Suc k} = {0 ..< i} \<union> ({i} \<union> {i+1 ..< Suc k})" using i by auto
from xs have "Suc n = foldl op + 0 xs" by (simp add: natpermute_def)
also have "\<dots> = setsum (nth xs) {0..<Suc k}" unfolding foldl_add_setsum using xs
by (simp add: natpermute_def)
also have "\<dots> = xs!i + setsum (nth xs) {0..<i} + setsum (nth xs) {i+1..<Suc k}"
unfolding eqs setsum_Un_disjoint[OF fths(1) finite_UnI[OF fths(2,3)] d(1)]
unfolding setsum_Un_disjoint[OF fths(2) fths(3) d(2)]
by simp
finally have False using c' by simp}
then show "((r,Suc k,a,xs!i), r, Suc k, a, Suc n) \<in> ?R"
apply auto by (metis not_less)}
{fix r k a n
show "((r,Suc k, a, 0),r, Suc k, a, Suc n) \<in> ?R" by simp}
qed
definition "fps_radical r n a = Abs_fps (radical r n a)"
lemma fps_radical0[simp]: "fps_radical r 0 a = 1"
apply (auto simp add: fps_eq_iff fps_radical_def) by (case_tac n, auto)
lemma fps_radical_nth_0[simp]: "fps_radical r n a $ 0 = (if n=0 then 1 else r n (a$0))"
by (cases n, simp_all add: fps_radical_def)
lemma fps_radical_power_nth[simp]:
assumes r: "(r k (a$0)) ^ k = a$0"
shows "fps_radical r k a ^ k $ 0 = (if k = 0 then 1 else a$0)"
proof-
{assume "k=0" hence ?thesis by simp }
moreover
{fix h assume h: "k = Suc h"
have fh: "finite {0..h}" by simp
have eq1: "fps_radical r k a ^ k $ 0 = (\<Prod>j\<in>{0..h}. fps_radical r k a $ (replicate k 0) ! j)"
unfolding fps_power_nth h by simp
also have "\<dots> = (\<Prod>j\<in>{0..h}. r k (a$0))"
apply (rule setprod_cong)
apply simp
using h
apply (subgoal_tac "replicate k (0::nat) ! x = 0")
by (auto intro: nth_replicate simp del: replicate.simps)
also have "\<dots> = a$0"
unfolding setprod_constant[OF fh] using r by (simp add: h)
finally have ?thesis using h by simp}
ultimately show ?thesis by (cases k, auto)
qed
lemma natpermute_max_card: assumes n0: "n\<noteq>0"
shows "card {xs \<in> natpermute n (k+1). n \<in> set xs} = k+1"
unfolding natpermute_contain_maximal
proof-
let ?A= "\<lambda>i. {replicate (k + 1) 0[i := n]}"
let ?K = "{0 ..k}"
have fK: "finite ?K" by simp
have fAK: "\<forall>i\<in>?K. finite (?A i)" by auto
have d: "\<forall>i\<in> ?K. \<forall>j\<in> ?K. i \<noteq> j \<longrightarrow> {replicate (k + 1) 0[i := n]} \<inter> {replicate (k + 1) 0[j := n]} = {}"
proof(clarify)
fix i j assume i: "i \<in> ?K" and j: "j\<in> ?K" and ij: "i\<noteq>j"
{assume eq: "replicate (k+1) 0 [i:=n] = replicate (k+1) 0 [j:= n]"
have "(replicate (k+1) 0 [i:=n] ! i) = n" using i by (simp del: replicate.simps)
moreover
have "(replicate (k+1) 0 [j:=n] ! i) = 0" using i ij by (simp del: replicate.simps)
ultimately have False using eq n0 by (simp del: replicate.simps)}
then show "{replicate (k + 1) 0[i := n]} \<inter> {replicate (k + 1) 0[j := n]} = {}"
by auto
qed
from card_UN_disjoint[OF fK fAK d]
show "card (\<Union>i\<in>{0..k}. {replicate (k + 1) 0[i := n]}) = k+1" by simp
qed
lemma power_radical:
fixes a:: "'a ::{field, ring_char_0} fps"
assumes a0: "a$0 \<noteq> 0"
shows "(r (Suc k) (a$0)) ^ Suc k = a$0 \<longleftrightarrow> (fps_radical r (Suc k) a) ^ (Suc k) = a"
proof-
let ?r = "fps_radical r (Suc k) a"
{assume r0: "(r (Suc k) (a$0)) ^ Suc k = a$0"
from a0 r0 have r00: "r (Suc k) (a$0) \<noteq> 0" by auto
{fix z have "?r ^ Suc k $ z = a$z"
proof(induct z rule: nat_less_induct)
fix n assume H: "\<forall>m<n. ?r ^ Suc k $ m = a$m"
{assume "n = 0" hence "?r ^ Suc k $ n = a $n"
using fps_radical_power_nth[of r "Suc k" a, OF r0] by simp}
moreover
{fix n1 assume n1: "n = Suc n1"
have fK: "finite {0..k}" by simp
have nz: "n \<noteq> 0" using n1 by arith
let ?Pnk = "natpermute n (k + 1)"
let ?Pnkn = "{xs \<in> ?Pnk. n \<in> set xs}"
let ?Pnknn = "{xs \<in> ?Pnk. n \<notin> set xs}"
have eq: "?Pnkn \<union> ?Pnknn = ?Pnk" by blast
have d: "?Pnkn \<inter> ?Pnknn = {}" by blast
have f: "finite ?Pnkn" "finite ?Pnknn"
using finite_Un[of ?Pnkn ?Pnknn, unfolded eq]
by (metis natpermute_finite)+
let ?f = "\<lambda>v. \<Prod>j\<in>{0..k}. ?r $ v ! j"
have "setsum ?f ?Pnkn = setsum (\<lambda>v. ?r $ n * r (Suc k) (a $ 0) ^ k) ?Pnkn"
proof(rule setsum_cong2)
fix v assume v: "v \<in> {xs \<in> natpermute n (k + 1). n \<in> set xs}"
let ?ths = "(\<Prod>j\<in>{0..k}. fps_radical r (Suc k) a $ v ! j) = fps_radical r (Suc k) a $ n * r (Suc k) (a $ 0) ^ k"
from v obtain i where i: "i \<in> {0..k}" "v = replicate (k+1) 0 [i:= n]"
unfolding natpermute_contain_maximal by auto
have "(\<Prod>j\<in>{0..k}. fps_radical r (Suc k) a $ v ! j) = (\<Prod>j\<in>{0..k}. if j = i then fps_radical r (Suc k) a $ n else r (Suc k) (a$0))"
apply (rule setprod_cong, simp)
using i r0 by (simp del: replicate.simps)
also have "\<dots> = (fps_radical r (Suc k) a $ n) * r (Suc k) (a$0) ^ k"
unfolding setprod_gen_delta[OF fK] using i r0 by simp
finally show ?ths .
qed
then have "setsum ?f ?Pnkn = of_nat (k+1) * ?r $ n * r (Suc k) (a $ 0) ^ k"
by (simp add: natpermute_max_card[OF nz, simplified])
also have "\<dots> = a$n - setsum ?f ?Pnknn"
unfolding n1 using r00 a0 by (simp add: field_simps fps_radical_def del: of_nat_Suc )
finally have fn: "setsum ?f ?Pnkn = a$n - setsum ?f ?Pnknn" .
have "(?r ^ Suc k)$n = setsum ?f ?Pnkn + setsum ?f ?Pnknn"
unfolding fps_power_nth_Suc setsum_Un_disjoint[OF f d, unfolded eq] ..
also have "\<dots> = a$n" unfolding fn by simp
finally have "?r ^ Suc k $ n = a $n" .}
ultimately show "?r ^ Suc k $ n = a $n" by (cases n, auto)
qed }
then have ?thesis using r0 by (simp add: fps_eq_iff)}
moreover
{ assume h: "(fps_radical r (Suc k) a) ^ (Suc k) = a"
hence "((fps_radical r (Suc k) a) ^ (Suc k))$0 = a$0" by simp
then have "(r (Suc k) (a$0)) ^ Suc k = a$0"
unfolding fps_power_nth_Suc
by (simp add: setprod_constant del: replicate.simps)}
ultimately show ?thesis by blast
qed
(*
lemma power_radical:
fixes a:: "'a ::{field, ring_char_0} fps"
assumes r0: "(r (Suc k) (a$0)) ^ Suc k = a$0" and a0: "a$0 \<noteq> 0"
shows "(fps_radical r (Suc k) a) ^ (Suc k) = a"
proof-
let ?r = "fps_radical r (Suc k) a"
from a0 r0 have r00: "r (Suc k) (a$0) \<noteq> 0" by auto
{fix z have "?r ^ Suc k $ z = a$z"
proof(induct z rule: nat_less_induct)
fix n assume H: "\<forall>m<n. ?r ^ Suc k $ m = a$m"
{assume "n = 0" hence "?r ^ Suc k $ n = a $n"
using fps_radical_power_nth[of r "Suc k" a, OF r0] by simp}
moreover
{fix n1 assume n1: "n = Suc n1"
have fK: "finite {0..k}" by simp
have nz: "n \<noteq> 0" using n1 by arith
let ?Pnk = "natpermute n (k + 1)"
let ?Pnkn = "{xs \<in> ?Pnk. n \<in> set xs}"
let ?Pnknn = "{xs \<in> ?Pnk. n \<notin> set xs}"
have eq: "?Pnkn \<union> ?Pnknn = ?Pnk" by blast
have d: "?Pnkn \<inter> ?Pnknn = {}" by blast
have f: "finite ?Pnkn" "finite ?Pnknn"
using finite_Un[of ?Pnkn ?Pnknn, unfolded eq]
by (metis natpermute_finite)+
let ?f = "\<lambda>v. \<Prod>j\<in>{0..k}. ?r $ v ! j"
have "setsum ?f ?Pnkn = setsum (\<lambda>v. ?r $ n * r (Suc k) (a $ 0) ^ k) ?Pnkn"
proof(rule setsum_cong2)
fix v assume v: "v \<in> {xs \<in> natpermute n (k + 1). n \<in> set xs}"
let ?ths = "(\<Prod>j\<in>{0..k}. fps_radical r (Suc k) a $ v ! j) = fps_radical r (Suc k) a $ n * r (Suc k) (a $ 0) ^ k"
from v obtain i where i: "i \<in> {0..k}" "v = replicate (k+1) 0 [i:= n]"
unfolding natpermute_contain_maximal by auto
have "(\<Prod>j\<in>{0..k}. fps_radical r (Suc k) a $ v ! j) = (\<Prod>j\<in>{0..k}. if j = i then fps_radical r (Suc k) a $ n else r (Suc k) (a$0))"
apply (rule setprod_cong, simp)
using i r0 by (simp del: replicate.simps)
also have "\<dots> = (fps_radical r (Suc k) a $ n) * r (Suc k) (a$0) ^ k"
unfolding setprod_gen_delta[OF fK] using i r0 by simp
finally show ?ths .
qed
then have "setsum ?f ?Pnkn = of_nat (k+1) * ?r $ n * r (Suc k) (a $ 0) ^ k"
by (simp add: natpermute_max_card[OF nz, simplified])
also have "\<dots> = a$n - setsum ?f ?Pnknn"
unfolding n1 using r00 a0 by (simp add: field_simps fps_radical_def del: of_nat_Suc )
finally have fn: "setsum ?f ?Pnkn = a$n - setsum ?f ?Pnknn" .
have "(?r ^ Suc k)$n = setsum ?f ?Pnkn + setsum ?f ?Pnknn"
unfolding fps_power_nth_Suc setsum_Un_disjoint[OF f d, unfolded eq] ..
also have "\<dots> = a$n" unfolding fn by simp
finally have "?r ^ Suc k $ n = a $n" .}
ultimately show "?r ^ Suc k $ n = a $n" by (cases n, auto)
qed }
then show ?thesis by (simp add: fps_eq_iff)
qed
*)
lemma eq_divide_imp': assumes c0: "(c::'a::field) ~= 0" and eq: "a * c = b"
shows "a = b / c"
proof-
from eq have "a * c * inverse c = b * inverse c" by simp
hence "a * (inverse c * c) = b/c" by (simp only: field_simps divide_inverse)
then show "a = b/c" unfolding field_inverse[OF c0] by simp
qed
lemma radical_unique:
assumes r0: "(r (Suc k) (b$0)) ^ Suc k = b$0"
and a0: "r (Suc k) (b$0 ::'a::{field, ring_char_0}) = a$0" and b0: "b$0 \<noteq> 0"
shows "a^(Suc k) = b \<longleftrightarrow> a = fps_radical r (Suc k) b"
proof-
let ?r = "fps_radical r (Suc k) b"
have r00: "r (Suc k) (b$0) \<noteq> 0" using b0 r0 by auto
{assume H: "a = ?r"
from H have "a^Suc k = b" using power_radical[OF b0, of r k, unfolded r0] by simp}
moreover
{assume H: "a^Suc k = b"
have ceq: "card {0..k} = Suc k" by simp
have fk: "finite {0..k}" by simp
from a0 have a0r0: "a$0 = ?r$0" by simp
{fix n have "a $ n = ?r $ n"
proof(induct n rule: nat_less_induct)
fix n assume h: "\<forall>m<n. a$m = ?r $m"
{assume "n = 0" hence "a$n = ?r $n" using a0 by simp }
moreover
{fix n1 assume n1: "n = Suc n1"
have fK: "finite {0..k}" by simp
have nz: "n \<noteq> 0" using n1 by arith
let ?Pnk = "natpermute n (Suc k)"
let ?Pnkn = "{xs \<in> ?Pnk. n \<in> set xs}"
let ?Pnknn = "{xs \<in> ?Pnk. n \<notin> set xs}"
have eq: "?Pnkn \<union> ?Pnknn = ?Pnk" by blast
have d: "?Pnkn \<inter> ?Pnknn = {}" by blast
have f: "finite ?Pnkn" "finite ?Pnknn"
using finite_Un[of ?Pnkn ?Pnknn, unfolded eq]
by (metis natpermute_finite)+
let ?f = "\<lambda>v. \<Prod>j\<in>{0..k}. ?r $ v ! j"
let ?g = "\<lambda>v. \<Prod>j\<in>{0..k}. a $ v ! j"
have "setsum ?g ?Pnkn = setsum (\<lambda>v. a $ n * (?r$0)^k) ?Pnkn"
proof(rule setsum_cong2)
fix v assume v: "v \<in> {xs \<in> natpermute n (Suc k). n \<in> set xs}"
let ?ths = "(\<Prod>j\<in>{0..k}. a $ v ! j) = a $ n * (?r$0)^k"
from v obtain i where i: "i \<in> {0..k}" "v = replicate (k+1) 0 [i:= n]"
unfolding Suc_plus1 natpermute_contain_maximal by (auto simp del: replicate.simps)
have "(\<Prod>j\<in>{0..k}. a $ v ! j) = (\<Prod>j\<in>{0..k}. if j = i then a $ n else r (Suc k) (b$0))"
apply (rule setprod_cong, simp)
using i a0 by (simp del: replicate.simps)
also have "\<dots> = a $ n * (?r $ 0)^k"
unfolding setprod_gen_delta[OF fK] using i by simp
finally show ?ths .
qed
then have th0: "setsum ?g ?Pnkn = of_nat (k+1) * a $ n * (?r $ 0)^k"
by (simp add: natpermute_max_card[OF nz, simplified])
have th1: "setsum ?g ?Pnknn = setsum ?f ?Pnknn"
proof (rule setsum_cong2, rule setprod_cong, simp)
fix xs i assume xs: "xs \<in> ?Pnknn" and i: "i \<in> {0..k}"
{assume c: "n \<le> xs ! i"
from xs i have "xs !i \<noteq> n" by (auto simp add: in_set_conv_nth natpermute_def)
with c have c': "n < xs!i" by arith
have fths: "finite {0 ..< i}" "finite {i}" "finite {i+1..<Suc k}" by simp_all
have d: "{0 ..< i} \<inter> ({i} \<union> {i+1 ..< Suc k}) = {}" "{i} \<inter> {i+1..< Suc k} = {}" by auto
have eqs: "{0..<Suc k} = {0 ..< i} \<union> ({i} \<union> {i+1 ..< Suc k})" using i by auto
from xs have "n = foldl op + 0 xs" by (simp add: natpermute_def)
also have "\<dots> = setsum (nth xs) {0..<Suc k}" unfolding foldl_add_setsum using xs
by (simp add: natpermute_def)
also have "\<dots> = xs!i + setsum (nth xs) {0..<i} + setsum (nth xs) {i+1..<Suc k}"
unfolding eqs setsum_Un_disjoint[OF fths(1) finite_UnI[OF fths(2,3)] d(1)]
unfolding setsum_Un_disjoint[OF fths(2) fths(3) d(2)]
by simp
finally have False using c' by simp}
then have thn: "xs!i < n" by arith
from h[rule_format, OF thn]
show "a$(xs !i) = ?r$(xs!i)" .
qed
have th00: "\<And>(x::'a). of_nat (Suc k) * (x * inverse (of_nat (Suc k))) = x"
by (simp add: field_simps del: of_nat_Suc)
from H have "b$n = a^Suc k $ n" by (simp add: fps_eq_iff)
also have "a ^ Suc k$n = setsum ?g ?Pnkn + setsum ?g ?Pnknn"
unfolding fps_power_nth_Suc
using setsum_Un_disjoint[OF f d, unfolded Suc_plus1[symmetric],
unfolded eq, of ?g] by simp
also have "\<dots> = of_nat (k+1) * a $ n * (?r $ 0)^k + setsum ?f ?Pnknn" unfolding th0 th1 ..
finally have "of_nat (k+1) * a $ n * (?r $ 0)^k = b$n - setsum ?f ?Pnknn" by simp
then have "a$n = (b$n - setsum ?f ?Pnknn) / (of_nat (k+1) * (?r $ 0)^k)"
apply -
apply (rule eq_divide_imp')
using r00
apply (simp del: of_nat_Suc)
by (simp add: mult_ac)
then have "a$n = ?r $n"
apply (simp del: of_nat_Suc)
unfolding fps_radical_def n1
by (simp add: field_simps n1 th00 del: of_nat_Suc)}
ultimately show "a$n = ?r $ n" by (cases n, auto)
qed}
then have "a = ?r" by (simp add: fps_eq_iff)}
ultimately show ?thesis by blast
qed
lemma radical_power:
assumes r0: "r (Suc k) ((a$0) ^ Suc k) = a$0"
and a0: "(a$0 ::'a::{field, ring_char_0}) \<noteq> 0"
shows "(fps_radical r (Suc k) (a ^ Suc k)) = a"
proof-
let ?ak = "a^ Suc k"
have ak0: "?ak $ 0 = (a$0) ^ Suc k" by (simp add: fps_nth_power_0 del: power_Suc)
from r0 have th0: "r (Suc k) (a ^ Suc k $ 0) ^ Suc k = a ^ Suc k $ 0" using ak0 by auto
from r0 ak0 have th1: "r (Suc k) (a ^ Suc k $ 0) = a $ 0" by auto
from ak0 a0 have ak00: "?ak $ 0 \<noteq>0 " by auto
from radical_unique[of r k ?ak a, OF th0 th1 ak00] show ?thesis by metis
qed
lemma fps_deriv_radical:
fixes a:: "'a ::{field, ring_char_0} fps"
assumes r0: "(r (Suc k) (a$0)) ^ Suc k = a$0" and a0: "a$0 \<noteq> 0"
shows "fps_deriv (fps_radical r (Suc k) a) = fps_deriv a / (fps_const (of_nat (Suc k)) * (fps_radical r (Suc k) a) ^ k)"
proof-
let ?r= "fps_radical r (Suc k) a"
let ?w = "(fps_const (of_nat (Suc k)) * ?r ^ k)"
from a0 r0 have r0': "r (Suc k) (a$0) \<noteq> 0" by auto
from r0' have w0: "?w $ 0 \<noteq> 0" by (simp del: of_nat_Suc)
note th0 = inverse_mult_eq_1[OF w0]
let ?iw = "inverse ?w"
from iffD1[OF power_radical[of a r], OF a0 r0]
have "fps_deriv (?r ^ Suc k) = fps_deriv a" by simp
hence "fps_deriv ?r * ?w = fps_deriv a"
by (simp add: fps_deriv_power mult_ac del: power_Suc)
hence "?iw * fps_deriv ?r * ?w = ?iw * fps_deriv a" by simp
hence "fps_deriv ?r * (?iw * ?w) = fps_deriv a / ?w"
by (simp add: fps_divide_def)
then show ?thesis unfolding th0 by simp
qed
lemma radical_mult_distrib:
fixes a:: "'a ::{field, ring_char_0} fps"
assumes
k: "k > 0"
and ra0: "r k (a $ 0) ^ k = a $ 0"
and rb0: "r k (b $ 0) ^ k = b $ 0"
and a0: "a$0 \<noteq> 0"
and b0: "b$0 \<noteq> 0"
shows "r k ((a * b) $ 0) = r k (a $ 0) * r k (b $ 0) \<longleftrightarrow> fps_radical r (k) (a*b) = fps_radical r (k) a * fps_radical r (k) (b)"
proof-
{assume r0': "r k ((a * b) $ 0) = r k (a $ 0) * r k (b $ 0)"
from r0' have r0: "(r (k) ((a*b)$0)) ^ k = (a*b)$0"
by (simp add: fps_mult_nth ra0 rb0 power_mult_distrib)
{assume "k=0" hence ?thesis using r0' by simp}
moreover
{fix h assume k: "k = Suc h"
let ?ra = "fps_radical r (Suc h) a"
let ?rb = "fps_radical r (Suc h) b"
have th0: "r (Suc h) ((a * b) $ 0) = (fps_radical r (Suc h) a * fps_radical r (Suc h) b) $ 0"
using r0' k by (simp add: fps_mult_nth)
have ab0: "(a*b) $ 0 \<noteq> 0" using a0 b0 by (simp add: fps_mult_nth)
from radical_unique[of r h "a*b" "fps_radical r (Suc h) a * fps_radical r (Suc h) b", OF r0[unfolded k] th0 ab0, symmetric]
iffD1[OF power_radical[of _ r], OF a0 ra0[unfolded k]] iffD1[OF power_radical[of _ r], OF b0 rb0[unfolded k]] k r0'
have ?thesis by (auto simp add: power_mult_distrib simp del: power_Suc)}
ultimately have ?thesis by (cases k, auto)}
moreover
{assume h: "fps_radical r k (a*b) = fps_radical r k a * fps_radical r k b"
hence "(fps_radical r k (a*b))$0 = (fps_radical r k a * fps_radical r k b)$0" by simp
then have "r k ((a * b) $ 0) = r k (a $ 0) * r k (b $ 0)"
using k by (simp add: fps_mult_nth)}
ultimately show ?thesis by blast
qed
(*
lemma radical_mult_distrib:
fixes a:: "'a ::{field, ring_char_0} fps"
assumes
ra0: "r k (a $ 0) ^ k = a $ 0"
and rb0: "r k (b $ 0) ^ k = b $ 0"
and r0': "r k ((a * b) $ 0) = r k (a $ 0) * r k (b $ 0)"
and a0: "a$0 \<noteq> 0"
and b0: "b$0 \<noteq> 0"
shows "fps_radical r (k) (a*b) = fps_radical r (k) a * fps_radical r (k) (b)"
proof-
from r0' have r0: "(r (k) ((a*b)$0)) ^ k = (a*b)$0"
by (simp add: fps_mult_nth ra0 rb0 power_mult_distrib)
{assume "k=0" hence ?thesis by simp}
moreover
{fix h assume k: "k = Suc h"
let ?ra = "fps_radical r (Suc h) a"
let ?rb = "fps_radical r (Suc h) b"
have th0: "r (Suc h) ((a * b) $ 0) = (fps_radical r (Suc h) a * fps_radical r (Suc h) b) $ 0"
using r0' k by (simp add: fps_mult_nth)
have ab0: "(a*b) $ 0 \<noteq> 0" using a0 b0 by (simp add: fps_mult_nth)
from radical_unique[of r h "a*b" "fps_radical r (Suc h) a * fps_radical r (Suc h) b", OF r0[unfolded k] th0 ab0, symmetric]
power_radical[of r, OF ra0[unfolded k] a0] power_radical[of r, OF rb0[unfolded k] b0] k
have ?thesis by (auto simp add: power_mult_distrib simp del: power_Suc)}
ultimately show ?thesis by (cases k, auto)
qed
*)
lemma fps_divide_1[simp]: "(a:: ('a::field) fps) / 1 = a"
by (simp add: fps_divide_def)
lemma radical_divide:
fixes a:: "'a ::{field, ring_char_0} fps"
assumes
kp: "k>0"
and ra0: "(r k (a $ 0)) ^ k = a $ 0"
and rb0: "(r k (b $ 0)) ^ k = b $ 0"
and a0: "a$0 \<noteq> 0"
and b0: "b$0 \<noteq> 0"
shows "r k ((a $ 0) / (b$0)) = r k (a$0) / r k (b $ 0) \<longleftrightarrow> fps_radical r k (a/b) = fps_radical r k a / fps_radical r k b" (is "?lhs = ?rhs")
proof-
let ?r = "fps_radical r k"
from kp obtain h where k: "k = Suc h" by (cases k, auto)
have ra0': "r k (a$0) \<noteq> 0" using a0 ra0 k by auto
have rb0': "r k (b$0) \<noteq> 0" using b0 rb0 k by auto
{assume ?rhs
then have "?r (a/b) $ 0 = (?r a / ?r b)$0" by simp
then have ?lhs using k a0 b0 rb0'
by (simp add: fps_divide_def fps_mult_nth fps_inverse_def divide_inverse) }
moreover
{assume h: ?lhs
from a0 b0 have ab0[simp]: "(a/b)$0 = a$0 / b$0"
by (simp add: fps_divide_def fps_mult_nth divide_inverse fps_inverse_def)
have th0: "r k ((a/b)$0) ^ k = (a/b)$0"
by (simp add: h nonzero_power_divide[OF rb0'] ra0 rb0 del: k)
from a0 b0 ra0' rb0' kp h
have th1: "r k ((a / b) $ 0) = (fps_radical r k a / fps_radical r k b) $ 0"
by (simp add: fps_divide_def fps_mult_nth fps_inverse_def divide_inverse del: k)
from a0 b0 ra0' rb0' kp have ab0': "(a / b) $ 0 \<noteq> 0"
by (simp add: fps_divide_def fps_mult_nth fps_inverse_def nonzero_imp_inverse_nonzero)
note tha[simp] = iffD1[OF power_radical[where r=r and k=h], OF a0 ra0[unfolded k], unfolded k[symmetric]]
note thb[simp] = iffD1[OF power_radical[where r=r and k=h], OF b0 rb0[unfolded k], unfolded k[symmetric]]
have th2: "(?r a / ?r b)^k = a/b"
by (simp add: fps_divide_def power_mult_distrib fps_inverse_power[symmetric])
from iffD1[OF radical_unique[where r=r and a="?r a / ?r b" and b="a/b" and k=h], symmetric, unfolded k[symmetric], OF th0 th1 ab0' th2] have ?rhs .}
ultimately show ?thesis by blast
qed
lemma radical_inverse:
fixes a:: "'a ::{field, ring_char_0} fps"
assumes
k: "k>0"
and ra0: "r k (a $ 0) ^ k = a $ 0"
and r1: "(r k 1)^k = 1"
and a0: "a$0 \<noteq> 0"
shows "r k (inverse (a $ 0)) = r k 1 / (r k (a $ 0)) \<longleftrightarrow> fps_radical r k (inverse a) = fps_radical r k 1 / fps_radical r k a"
using radical_divide[where k=k and r=r and a=1 and b=a, OF k ] ra0 r1 a0
by (simp add: divide_inverse fps_divide_def)
subsection{* Derivative of composition *}
lemma fps_compose_deriv:
fixes a:: "('a::idom) fps"
assumes b0: "b$0 = 0"
shows "fps_deriv (a oo b) = ((fps_deriv a) oo b) * (fps_deriv b)"
proof-
{fix n
have "(fps_deriv (a oo b))$n = setsum (\<lambda>i. a $ i * (fps_deriv (b^i))$n) {0.. Suc n}"
by (simp add: fps_compose_def ring_simps setsum_right_distrib del: of_nat_Suc)
also have "\<dots> = setsum (\<lambda>i. a$i * ((fps_const (of_nat i)) * (fps_deriv b * (b^(i - 1))))$n) {0.. Suc n}"
by (simp add: ring_simps fps_deriv_power del: fps_mult_left_const_nth of_nat_Suc)
also have "\<dots> = setsum (\<lambda>i. of_nat i * a$i * (((b^(i - 1)) * fps_deriv b))$n) {0.. Suc n}"
unfolding fps_mult_left_const_nth by (simp add: ring_simps)
also have "\<dots> = setsum (\<lambda>i. of_nat i * a$i * (setsum (\<lambda>j. (b^ (i - 1))$j * (fps_deriv b)$(n - j)) {0..n})) {0.. Suc n}"
unfolding fps_mult_nth ..
also have "\<dots> = setsum (\<lambda>i. of_nat i * a$i * (setsum (\<lambda>j. (b^ (i - 1))$j * (fps_deriv b)$(n - j)) {0..n})) {1.. Suc n}"
apply (rule setsum_mono_zero_right)
apply (auto simp add: mult_delta_left setsum_delta not_le)
done
also have "\<dots> = setsum (\<lambda>i. of_nat (i + 1) * a$(i+1) * (setsum (\<lambda>j. (b^ i)$j * of_nat (n - j + 1) * b$(n - j + 1)) {0..n})) {0.. n}"
unfolding fps_deriv_nth
apply (rule setsum_reindex_cong[where f="Suc"])
by (auto simp add: mult_assoc)
finally have th0: "(fps_deriv (a oo b))$n = setsum (\<lambda>i. of_nat (i + 1) * a$(i+1) * (setsum (\<lambda>j. (b^ i)$j * of_nat (n - j + 1) * b$(n - j + 1)) {0..n})) {0.. n}" .
have "(((fps_deriv a) oo b) * (fps_deriv b))$n = setsum (\<lambda>i. (fps_deriv b)$ (n - i) * ((fps_deriv a) oo b)$i) {0..n}"
unfolding fps_mult_nth by (simp add: mult_ac)
also have "\<dots> = setsum (\<lambda>i. setsum (\<lambda>j. of_nat (n - i +1) * b$(n - i + 1) * of_nat (j + 1) * a$(j+1) * (b^j)$i) {0..n}) {0..n}"
unfolding fps_deriv_nth fps_compose_nth setsum_right_distrib mult_assoc
apply (rule setsum_cong2)
apply (rule setsum_mono_zero_left)
apply (simp_all add: subset_eq)
apply clarify
apply (subgoal_tac "b^i$x = 0")
apply simp
apply (rule startsby_zero_power_prefix[OF b0, rule_format])
by simp
also have "\<dots> = setsum (\<lambda>i. of_nat (i + 1) * a$(i+1) * (setsum (\<lambda>j. (b^ i)$j * of_nat (n - j + 1) * b$(n - j + 1)) {0..n})) {0.. n}"
unfolding setsum_right_distrib
apply (subst setsum_commute)
by ((rule setsum_cong2)+) simp
finally have "(fps_deriv (a oo b))$n = (((fps_deriv a) oo b) * (fps_deriv b)) $n"
unfolding th0 by simp}
then show ?thesis by (simp add: fps_eq_iff)
qed
lemma fps_mult_X_plus_1_nth:
"((1+X)*a) $n = (if n = 0 then (a$n :: 'a::comm_ring_1) else a$n + a$(n - 1))"
proof-
{assume "n = 0" hence ?thesis by (simp add: fps_mult_nth )}
moreover
{fix m assume m: "n = Suc m"
have "((1+X)*a) $n = setsum (\<lambda>i. (1+X)$i * a$(n-i)) {0..n}"
by (simp add: fps_mult_nth)
also have "\<dots> = setsum (\<lambda>i. (1+X)$i * a$(n-i)) {0.. 1}"
unfolding m
apply (rule setsum_mono_zero_right)
by (auto simp add: )
also have "\<dots> = (if n = 0 then (a$n :: 'a::comm_ring_1) else a$n + a$(n - 1))"
unfolding m
by (simp add: )
finally have ?thesis .}
ultimately show ?thesis by (cases n, auto)
qed
subsection{* Finite FPS (i.e. polynomials) and X *}
lemma fps_poly_sum_X:
assumes z: "\<forall>i > n. a$i = (0::'a::comm_ring_1)"
shows "a = setsum (\<lambda>i. fps_const (a$i) * X^i) {0..n}" (is "a = ?r")
proof-
{fix i
have "a$i = ?r$i"
unfolding fps_setsum_nth fps_mult_left_const_nth X_power_nth
by (simp add: mult_delta_right setsum_delta' z)
}
then show ?thesis unfolding fps_eq_iff by blast
qed
subsection{* Compositional inverses *}
fun compinv :: "'a fps \<Rightarrow> nat \<Rightarrow> 'a::{field}" where
"compinv a 0 = X$0"
| "compinv a (Suc n) = (X$ Suc n - setsum (\<lambda>i. (compinv a i) * (a^i)$Suc n) {0 .. n}) / (a$1) ^ Suc n"
definition "fps_inv a = Abs_fps (compinv a)"
lemma fps_inv: assumes a0: "a$0 = 0" and a1: "a$1 \<noteq> 0"
shows "fps_inv a oo a = X"
proof-
let ?i = "fps_inv a oo a"
{fix n
have "?i $n = X$n"
proof(induct n rule: nat_less_induct)
fix n assume h: "\<forall>m<n. ?i$m = X$m"
{assume "n=0" hence "?i $n = X$n" using a0
by (simp add: fps_compose_nth fps_inv_def)}
moreover
{fix n1 assume n1: "n = Suc n1"
have "?i $ n = setsum (\<lambda>i. (fps_inv a $ i) * (a^i)$n) {0 .. n1} + fps_inv a $ Suc n1 * (a $ 1)^ Suc n1"
by (simp add: fps_compose_nth n1 startsby_zero_power_nth_same[OF a0]
del: power_Suc)
also have "\<dots> = setsum (\<lambda>i. (fps_inv a $ i) * (a^i)$n) {0 .. n1} + (X$ Suc n1 - setsum (\<lambda>i. (fps_inv a $ i) * (a^i)$n) {0 .. n1})"
using a0 a1 n1 by (simp add: fps_inv_def)
also have "\<dots> = X$n" using n1 by simp
finally have "?i $ n = X$n" .}
ultimately show "?i $ n = X$n" by (cases n, auto)
qed}
then show ?thesis by (simp add: fps_eq_iff)
qed
fun gcompinv :: "'a fps \<Rightarrow> 'a fps \<Rightarrow> nat \<Rightarrow> 'a::{field}" where
"gcompinv b a 0 = b$0"
| "gcompinv b a (Suc n) = (b$ Suc n - setsum (\<lambda>i. (gcompinv b a i) * (a^i)$Suc n) {0 .. n}) / (a$1) ^ Suc n"
definition "fps_ginv b a = Abs_fps (gcompinv b a)"
lemma fps_ginv: assumes a0: "a$0 = 0" and a1: "a$1 \<noteq> 0"
shows "fps_ginv b a oo a = b"
proof-
let ?i = "fps_ginv b a oo a"
{fix n
have "?i $n = b$n"
proof(induct n rule: nat_less_induct)
fix n assume h: "\<forall>m<n. ?i$m = b$m"
{assume "n=0" hence "?i $n = b$n" using a0
by (simp add: fps_compose_nth fps_ginv_def)}
moreover
{fix n1 assume n1: "n = Suc n1"
have "?i $ n = setsum (\<lambda>i. (fps_ginv b a $ i) * (a^i)$n) {0 .. n1} + fps_ginv b a $ Suc n1 * (a $ 1)^ Suc n1"
by (simp add: fps_compose_nth n1 startsby_zero_power_nth_same[OF a0]
del: power_Suc)
also have "\<dots> = setsum (\<lambda>i. (fps_ginv b a $ i) * (a^i)$n) {0 .. n1} + (b$ Suc n1 - setsum (\<lambda>i. (fps_ginv b a $ i) * (a^i)$n) {0 .. n1})"
using a0 a1 n1 by (simp add: fps_ginv_def)
also have "\<dots> = b$n" using n1 by simp
finally have "?i $ n = b$n" .}
ultimately show "?i $ n = b$n" by (cases n, auto)
qed}
then show ?thesis by (simp add: fps_eq_iff)
qed
lemma fps_inv_ginv: "fps_inv = fps_ginv X"
apply (auto simp add: expand_fun_eq fps_eq_iff fps_inv_def fps_ginv_def)
apply (induct_tac n rule: nat_less_induct, auto)
apply (case_tac na)
apply simp
apply simp
done
lemma fps_compose_1[simp]: "1 oo a = 1"
by (simp add: fps_eq_iff fps_compose_nth mult_delta_left setsum_delta)
lemma fps_compose_0[simp]: "0 oo a = 0"
by (simp add: fps_eq_iff fps_compose_nth)
lemma fps_compose_0_right[simp]: "a oo 0 = fps_const (a$0)"
by (auto simp add: fps_eq_iff fps_compose_nth power_0_left setsum_0')
lemma fps_compose_add_distrib: "(a + b) oo c = (a oo c) + (b oo c)"
by (simp add: fps_eq_iff fps_compose_nth ring_simps setsum_addf)
lemma fps_compose_setsum_distrib: "(setsum f S) oo a = setsum (\<lambda>i. f i oo a) S"
proof-
{assume "\<not> finite S" hence ?thesis by simp}
moreover
{assume fS: "finite S"
have ?thesis
proof(rule finite_induct[OF fS])
show "setsum f {} oo a = (\<Sum>i\<in>{}. f i oo a)" by simp
next
fix x F assume fF: "finite F" and xF: "x \<notin> F" and h: "setsum f F oo a = setsum (\<lambda>i. f i oo a) F"
show "setsum f (insert x F) oo a = setsum (\<lambda>i. f i oo a) (insert x F)"
using fF xF h by (simp add: fps_compose_add_distrib)
qed}
ultimately show ?thesis by blast
qed
lemma convolution_eq:
"setsum (%i. a (i :: nat) * b (n - i)) {0 .. n} = setsum (%(i,j). a i * b j) {(i,j). i <= n \<and> j \<le> n \<and> i + j = n}"
apply (rule setsum_reindex_cong[where f=fst])
apply (clarsimp simp add: inj_on_def)
apply (auto simp add: expand_set_eq image_iff)
apply (rule_tac x= "x" in exI)
apply clarsimp
apply (rule_tac x="n - x" in exI)
apply arith
done
lemma product_composition_lemma:
assumes c0: "c$0 = (0::'a::idom)" and d0: "d$0 = 0"
shows "((a oo c) * (b oo d))$n = setsum (%(k,m). a$k * b$m * (c^k * d^m) $ n) {(k,m). k + m \<le> n}" (is "?l = ?r")
proof-
let ?S = "{(k\<Colon>nat, m\<Colon>nat). k + m \<le> n}"
have s: "?S \<subseteq> {0..n} <*> {0..n}" by (auto simp add: subset_eq)
have f: "finite {(k\<Colon>nat, m\<Colon>nat). k + m \<le> n}"
apply (rule finite_subset[OF s])
by auto
have "?r = setsum (%i. setsum (%(k,m). a$k * (c^k)$i * b$m * (d^m) $ (n - i)) {(k,m). k + m \<le> n}) {0..n}"
apply (simp add: fps_mult_nth setsum_right_distrib)
apply (subst setsum_commute)
apply (rule setsum_cong2)
by (auto simp add: ring_simps)
also have "\<dots> = ?l"
apply (simp add: fps_mult_nth fps_compose_nth setsum_product)
apply (rule setsum_cong2)
apply (simp add: setsum_cartesian_product mult_assoc)
apply (rule setsum_mono_zero_right[OF f])
apply (simp add: subset_eq) apply presburger
apply clarsimp
apply (rule ccontr)
apply (clarsimp simp add: not_le)
apply (case_tac "x < aa")
apply simp
apply (frule_tac startsby_zero_power_prefix[rule_format, OF c0])
apply blast
apply simp
apply (frule_tac startsby_zero_power_prefix[rule_format, OF d0])
apply blast
done
finally show ?thesis by simp
qed
lemma product_composition_lemma':
assumes c0: "c$0 = (0::'a::idom)" and d0: "d$0 = 0"
shows "((a oo c) * (b oo d))$n = setsum (%k. setsum (%m. a$k * b$m * (c^k * d^m) $ n) {0..n}) {0..n}" (is "?l = ?r")
unfolding product_composition_lemma[OF c0 d0]
unfolding setsum_cartesian_product
apply (rule setsum_mono_zero_left)
apply simp
apply (clarsimp simp add: subset_eq)
apply clarsimp
apply (rule ccontr)
apply (subgoal_tac "(c^aa * d^ba) $ n = 0")
apply simp
unfolding fps_mult_nth
apply (rule setsum_0')
apply (clarsimp simp add: not_le)
apply (case_tac "aaa < aa")
apply (rule startsby_zero_power_prefix[OF c0, rule_format])
apply simp
apply (subgoal_tac "n - aaa < ba")
apply (frule_tac k = "ba" in startsby_zero_power_prefix[OF d0, rule_format])
apply simp
apply arith
done
lemma setsum_pair_less_iff:
"setsum (%((k::nat),m). a k * b m * c (k + m)) {(k,m). k + m \<le> n} = setsum (%s. setsum (%i. a i * b (s - i) * c s) {0..s}) {0..n}" (is "?l = ?r")
proof-
let ?KM= "{(k,m). k + m \<le> n}"
let ?f = "%s. UNION {(0::nat)..s} (%i. {(i,s - i)})"
have th0: "?KM = UNION {0..n} ?f"
apply (simp add: expand_set_eq)
apply arith (* FIXME: VERY slow! *)
done
show "?l = ?r "
unfolding th0
apply (subst setsum_UN_disjoint)
apply auto
apply (subst setsum_UN_disjoint)
apply auto
done
qed
lemma fps_compose_mult_distrib_lemma:
assumes c0: "c$0 = (0::'a::idom)"
shows "((a oo c) * (b oo c))$n = setsum (%s. setsum (%i. a$i * b$(s - i) * (c^s) $ n) {0..s}) {0..n}" (is "?l = ?r")
unfolding product_composition_lemma[OF c0 c0] power_add[symmetric]
unfolding setsum_pair_less_iff[where a = "%k. a$k" and b="%m. b$m" and c="%s. (c ^ s)$n" and n = n] ..
lemma fps_compose_mult_distrib:
assumes c0: "c$0 = (0::'a::idom)"
shows "(a * b) oo c = (a oo c) * (b oo c)" (is "?l = ?r")
apply (simp add: fps_eq_iff fps_compose_mult_distrib_lemma[OF c0])
by (simp add: fps_compose_nth fps_mult_nth setsum_left_distrib)
lemma fps_compose_setprod_distrib:
assumes c0: "c$0 = (0::'a::idom)"
shows "(setprod a S) oo c = setprod (%k. a k oo c) S" (is "?l = ?r")
apply (cases "finite S")
apply simp_all
apply (induct S rule: finite_induct)
apply simp
apply (simp add: fps_compose_mult_distrib[OF c0])
done
lemma fps_compose_power: assumes c0: "c$0 = (0::'a::idom)"
shows "(a oo c)^n = a^n oo c" (is "?l = ?r")
proof-
{assume "n=0" then have ?thesis by simp}
moreover
{fix m assume m: "n = Suc m"
have th0: "a^n = setprod (%k. a) {0..m}" "(a oo c) ^ n = setprod (%k. a oo c) {0..m}"
by (simp_all add: setprod_constant m)
then have ?thesis
by (simp add: fps_compose_setprod_distrib[OF c0])}
ultimately show ?thesis by (cases n, auto)
qed
lemma fps_compose_uminus: "- (a::'a::ring_1 fps) oo c = - (a oo c)"
by (simp add: fps_eq_iff fps_compose_nth ring_simps setsum_negf[symmetric])
lemma fps_compose_sub_distrib:
shows "(a - b) oo (c::'a::ring_1 fps) = (a oo c) - (b oo c)"
unfolding diff_minus fps_compose_uminus fps_compose_add_distrib ..
lemma X_fps_compose:"X oo a = Abs_fps (\<lambda>n. if n = 0 then (0::'a::comm_ring_1) else a$n)"
by (simp add: fps_eq_iff fps_compose_nth mult_delta_left setsum_delta power_Suc)
lemma fps_inverse_compose:
assumes b0: "(b$0 :: 'a::field) = 0" and a0: "a$0 \<noteq> 0"
shows "inverse a oo b = inverse (a oo b)"
proof-
let ?ia = "inverse a"
let ?ab = "a oo b"
let ?iab = "inverse ?ab"
from a0 have ia0: "?ia $ 0 \<noteq> 0" by (simp )
from a0 have ab0: "?ab $ 0 \<noteq> 0" by (simp add: fps_compose_def)
thm inverse_mult_eq_1[OF ab0]
have "(?ia oo b) * (a oo b) = 1"
unfolding fps_compose_mult_distrib[OF b0, symmetric]
unfolding inverse_mult_eq_1[OF a0]
fps_compose_1 ..
then have "(?ia oo b) * (a oo b) * ?iab = 1 * ?iab" by simp
then have "(?ia oo b) * (?iab * (a oo b)) = ?iab" by simp
then show ?thesis
unfolding inverse_mult_eq_1[OF ab0] by simp
qed
lemma fps_divide_compose:
assumes c0: "(c$0 :: 'a::field) = 0" and b0: "b$0 \<noteq> 0"
shows "(a/b) oo c = (a oo c) / (b oo c)"
unfolding fps_divide_def fps_compose_mult_distrib[OF c0]
fps_inverse_compose[OF c0 b0] ..
lemma gp: assumes a0: "a$0 = (0::'a::field)"
shows "(Abs_fps (\<lambda>n. 1)) oo a = 1/(1 - a)" (is "?one oo a = _")
proof-
have o0: "?one $ 0 \<noteq> 0" by simp
have th0: "(1 - X) $ 0 \<noteq> (0::'a)" by simp
from fps_inverse_gp[where ?'a = 'a]
have "inverse ?one = 1 - X" by (simp add: fps_eq_iff)
hence "inverse (inverse ?one) = inverse (1 - X)" by simp
hence th: "?one = 1/(1 - X)" unfolding fps_inverse_idempotent[OF o0]
by (simp add: fps_divide_def)
show ?thesis unfolding th
unfolding fps_divide_compose[OF a0 th0]
fps_compose_1 fps_compose_sub_distrib X_fps_compose_startby0[OF a0] ..
qed
lemma fps_const_power[simp]: "fps_const (c::'a::ring_1) ^ n = fps_const (c^n)"
by (induct n, auto)
lemma fps_compose_radical:
assumes b0: "b$0 = (0::'a::{field, ring_char_0})"
and ra0: "r (Suc k) (a$0) ^ Suc k = a$0"
and a0: "a$0 \<noteq> 0"
shows "fps_radical r (Suc k) a oo b = fps_radical r (Suc k) (a oo b)"
proof-
let ?r = "fps_radical r (Suc k)"
let ?ab = "a oo b"
have ab0: "?ab $ 0 = a$0" by (simp add: fps_compose_def)
from ab0 a0 ra0 have rab0: "?ab $ 0 \<noteq> 0" "r (Suc k) (?ab $ 0) ^ Suc k = ?ab $ 0" by simp_all
have th00: "r (Suc k) ((a oo b) $ 0) = (fps_radical r (Suc k) a oo b) $ 0"
by (simp add: ab0 fps_compose_def)
have th0: "(?r a oo b) ^ (Suc k) = a oo b"
unfolding fps_compose_power[OF b0]
unfolding iffD1[OF power_radical[of a r k], OF a0 ra0] ..
from iffD1[OF radical_unique[where r=r and k=k and b= ?ab and a = "?r a oo b", OF rab0(2) th00 rab0(1)], OF th0] show ?thesis .
qed
lemma fps_const_mult_apply_left:
"fps_const c * (a oo b) = (fps_const c * a) oo b"
by (simp add: fps_eq_iff fps_compose_nth setsum_right_distrib mult_assoc)
lemma fps_const_mult_apply_right:
"(a oo b) * fps_const (c::'a::comm_semiring_1) = (fps_const c * a) oo b"
by (auto simp add: fps_const_mult_apply_left mult_commute)
lemma fps_compose_assoc:
assumes c0: "c$0 = (0::'a::idom)" and b0: "b$0 = 0"
shows "a oo (b oo c) = a oo b oo c" (is "?l = ?r")
proof-
{fix n
have "?l$n = (setsum (\<lambda>i. (fps_const (a$i) * b^i) oo c) {0..n})$n"
by (simp add: fps_compose_nth fps_compose_power[OF c0] fps_const_mult_apply_left setsum_right_distrib mult_assoc fps_setsum_nth)
also have "\<dots> = ((setsum (\<lambda>i. fps_const (a$i) * b^i) {0..n}) oo c)$n"
by (simp add: fps_compose_setsum_distrib)
also have "\<dots> = ?r$n"
apply (simp add: fps_compose_nth fps_setsum_nth setsum_left_distrib mult_assoc)
apply (rule setsum_cong2)
apply (rule setsum_mono_zero_right)
apply (auto simp add: not_le)
by (erule startsby_zero_power_prefix[OF b0, rule_format])
finally have "?l$n = ?r$n" .}
then show ?thesis by (simp add: fps_eq_iff)
qed
lemma fps_X_power_compose:
assumes a0: "a$0=0" shows "X^k oo a = (a::('a::idom fps))^k" (is "?l = ?r")
proof-
{assume "k=0" hence ?thesis by simp}
moreover
{fix h assume h: "k = Suc h"
{fix n
{assume kn: "k>n" hence "?l $ n = ?r $n" using a0 startsby_zero_power_prefix[OF a0] h
by (simp add: fps_compose_nth del: power_Suc)}
moreover
{assume kn: "k \<le> n"
hence "?l$n = ?r$n"
by (simp add: fps_compose_nth mult_delta_left setsum_delta)}
moreover have "k >n \<or> k\<le> n" by arith
ultimately have "?l$n = ?r$n" by blast}
then have ?thesis unfolding fps_eq_iff by blast}
ultimately show ?thesis by (cases k, auto)
qed
lemma fps_inv_right: assumes a0: "a$0 = 0" and a1: "a$1 \<noteq> 0"
shows "a oo fps_inv a = X"
proof-
let ?ia = "fps_inv a"
let ?iaa = "a oo fps_inv a"
have th0: "?ia $ 0 = 0" by (simp add: fps_inv_def)
have th1: "?iaa $ 0 = 0" using a0 a1
by (simp add: fps_inv_def fps_compose_nth)
have th2: "X$0 = 0" by simp
from fps_inv[OF a0 a1] have "a oo (fps_inv a oo a) = a oo X" by simp
then have "(a oo fps_inv a) oo a = X oo a"
by (simp add: fps_compose_assoc[OF a0 th0] X_fps_compose_startby0[OF a0])
with fps_compose_inj_right[OF a0 a1]
show ?thesis by simp
qed
lemma fps_inv_deriv:
assumes a0:"a$0 = (0::'a::{field})" and a1: "a$1 \<noteq> 0"
shows "fps_deriv (fps_inv a) = inverse (fps_deriv a oo fps_inv a)"
proof-
let ?ia = "fps_inv a"
let ?d = "fps_deriv a oo ?ia"
let ?dia = "fps_deriv ?ia"
have ia0: "?ia$0 = 0" by (simp add: fps_inv_def)
have th0: "?d$0 \<noteq> 0" using a1 by (simp add: fps_compose_nth fps_deriv_nth)
from fps_inv_right[OF a0 a1] have "?d * ?dia = 1"
by (simp add: fps_compose_deriv[OF ia0, of a, symmetric] )
hence "inverse ?d * ?d * ?dia = inverse ?d * 1" by simp
with inverse_mult_eq_1[OF th0]
show "?dia = inverse ?d" by simp
qed
lemma fps_inv_idempotent:
assumes a0: "a$0 = 0" and a1: "a$1 \<noteq> 0"
shows "fps_inv (fps_inv a) = a"
proof-
let ?r = "fps_inv"
have ra0: "?r a $ 0 = 0" by (simp add: fps_inv_def)
from a1 have ra1: "?r a $ 1 \<noteq> 0" by (simp add: fps_inv_def field_simps)
have X0: "X$0 = 0" by simp
from fps_inv[OF ra0 ra1] have "?r (?r a) oo ?r a = X" .
then have "?r (?r a) oo ?r a oo a = X oo a" by simp
then have "?r (?r a) oo (?r a oo a) = a"
unfolding X_fps_compose_startby0[OF a0]
unfolding fps_compose_assoc[OF a0 ra0, symmetric] .
then show ?thesis unfolding fps_inv[OF a0 a1] by simp
qed
lemma fps_ginv_ginv:
assumes a0: "a$0 = 0" and a1: "a$1 \<noteq> 0"
and c0: "c$0 = 0" and c1: "c$1 \<noteq> 0"
shows "fps_ginv b (fps_ginv c a) = b oo a oo fps_inv c"
proof-
let ?r = "fps_ginv"
from c0 have rca0: "?r c a $0 = 0" by (simp add: fps_ginv_def)
from a1 c1 have rca1: "?r c a $ 1 \<noteq> 0" by (simp add: fps_ginv_def field_simps)
from fps_ginv[OF rca0 rca1]
have "?r b (?r c a) oo ?r c a = b" .
then have "?r b (?r c a) oo ?r c a oo a = b oo a" by simp
then have "?r b (?r c a) oo (?r c a oo a) = b oo a"
apply (subst fps_compose_assoc)
using a0 c0 by (auto simp add: fps_ginv_def)
then have "?r b (?r c a) oo c = b oo a"
unfolding fps_ginv[OF a0 a1] .
then have "?r b (?r c a) oo c oo fps_inv c= b oo a oo fps_inv c" by simp
then have "?r b (?r c a) oo (c oo fps_inv c) = b oo a oo fps_inv c"
apply (subst fps_compose_assoc)
using a0 c0 by (auto simp add: fps_inv_def)
then show ?thesis unfolding fps_inv_right[OF c0 c1] by simp
qed
subsection{* Elementary series *}
subsubsection{* Exponential series *}
definition "E x = Abs_fps (\<lambda>n. x^n / of_nat (fact n))"
lemma E_deriv[simp]: "fps_deriv (E a) = fps_const (a::'a::{field, ring_char_0}) * E a" (is "?l = ?r")
proof-
{fix n
have "?l$n = ?r $ n"
apply (auto simp add: E_def field_simps power_Suc[symmetric]simp del: fact_Suc of_nat_Suc power_Suc)
by (simp add: of_nat_mult ring_simps)}
then show ?thesis by (simp add: fps_eq_iff)
qed
lemma E_unique_ODE:
"fps_deriv a = fps_const c * a \<longleftrightarrow> a = fps_const (a$0) * E (c :: 'a::{field, ring_char_0})"
(is "?lhs \<longleftrightarrow> ?rhs")
proof-
{assume d: ?lhs
from d have th: "\<And>n. a $ Suc n = c * a$n / of_nat (Suc n)"
by (simp add: fps_deriv_def fps_eq_iff field_simps del: of_nat_Suc)
{fix n have "a$n = a$0 * c ^ n/ (of_nat (fact n))"
apply (induct n)
apply simp
unfolding th
using fact_gt_zero
apply (simp add: field_simps del: of_nat_Suc fact.simps)
apply (drule sym)
by (simp add: ring_simps of_nat_mult power_Suc)}
note th' = this
have ?rhs
by (auto simp add: fps_eq_iff fps_const_mult_left E_def intro : th')}
moreover
{assume h: ?rhs
have ?lhs
apply (subst h)
apply simp
apply (simp only: h[symmetric])
by simp}
ultimately show ?thesis by blast
qed
lemma E_add_mult: "E (a + b) = E (a::'a::{ring_char_0, field}) * E b" (is "?l = ?r")
proof-
have "fps_deriv (?r) = fps_const (a+b) * ?r"
by (simp add: fps_const_add[symmetric] ring_simps del: fps_const_add)
then have "?r = ?l" apply (simp only: E_unique_ODE)
by (simp add: fps_mult_nth E_def)
then show ?thesis ..
qed
lemma E_nth[simp]: "E a $ n = a^n / of_nat (fact n)"
by (simp add: E_def)
lemma E0[simp]: "E (0::'a::{field}) = 1"
by (simp add: fps_eq_iff power_0_left)
lemma E_neg: "E (- a) = inverse (E (a::'a::{ring_char_0, field}))"
proof-
from E_add_mult[of a "- a"] have th0: "E a * E (- a) = 1"
by (simp )
have th1: "E a $ 0 \<noteq> 0" by simp
from fps_inverse_unique[OF th1 th0] show ?thesis by simp
qed
lemma E_nth_deriv[simp]: "fps_nth_deriv n (E (a::'a::{field, ring_char_0})) = (fps_const a)^n * (E a)"
by (induct n, auto simp add: power_Suc)
lemma X_compose_E[simp]: "X oo E (a::'a::{field}) = E a - 1"
by (simp add: fps_eq_iff X_fps_compose)
lemma LE_compose:
assumes a: "a\<noteq>0"
shows "fps_inv (E a - 1) oo (E a - 1) = X"
and "(E a - 1) oo fps_inv (E a - 1) = X"
proof-
let ?b = "E a - 1"
have b0: "?b $ 0 = 0" by simp
have b1: "?b $ 1 \<noteq> 0" by (simp add: a)
from fps_inv[OF b0 b1] show "fps_inv (E a - 1) oo (E a - 1) = X" .
from fps_inv_right[OF b0 b1] show "(E a - 1) oo fps_inv (E a - 1) = X" .
qed
lemma fps_const_inverse:
"a \<noteq> 0 \<Longrightarrow> inverse (fps_const (a::'a::field)) = fps_const (inverse a)"
apply (auto simp add: fps_eq_iff fps_inverse_def) by (case_tac "n", auto)
lemma inverse_one_plus_X:
"inverse (1 + X) = Abs_fps (\<lambda>n. (- 1 ::'a::{field})^n)"
(is "inverse ?l = ?r")
proof-
have th: "?l * ?r = 1"
by (auto simp add: ring_simps fps_eq_iff minus_one_power_iff)
have th': "?l $ 0 \<noteq> 0" by (simp add: )
from fps_inverse_unique[OF th' th] show ?thesis .
qed
lemma E_power_mult: "(E (c::'a::{field,ring_char_0}))^n = E (of_nat n * c)"
by (induct n, auto simp add: ring_simps E_add_mult power_Suc)
lemma assumes r: "r (Suc k) 1 = 1"
shows "fps_radical r (Suc k) (E (c::'a::{field, ring_char_0})) = E (c / of_nat (Suc k))"
proof-
let ?ck = "(c / of_nat (Suc k))"
let ?r = "fps_radical r (Suc k)"
have eq0[simp]: "?ck * of_nat (Suc k) = c" "of_nat (Suc k) * ?ck = c"
by (simp_all del: of_nat_Suc)
have th0: "E ?ck ^ (Suc k) = E c" unfolding E_power_mult eq0 ..
have th: "r (Suc k) (E c $0) ^ Suc k = E c $ 0"
"r (Suc k) (E c $ 0) = E ?ck $ 0" "E c $ 0 \<noteq> 0" using r by simp_all
from th0 radical_unique[where r=r and k=k, OF th]
show ?thesis by auto
qed
lemma Ec_E1_eq:
"E (1::'a::{field, ring_char_0}) oo (fps_const c * X) = E c"
apply (auto simp add: fps_eq_iff E_def fps_compose_def power_mult_distrib)
by (simp add: cond_value_iff cond_application_beta setsum_delta' cong del: if_weak_cong)
subsubsection{* Logarithmic series *}
lemma Abs_fps_if_0:
"Abs_fps(%n. if n=0 then (v::'a::ring_1) else f n) = fps_const v + X * Abs_fps (%n. f (Suc n))"
by (auto simp add: fps_eq_iff)
definition L:: "'a::{field, ring_char_0} \<Rightarrow> 'a fps" where
"L c \<equiv> fps_const (1/c) * Abs_fps (\<lambda>n. if n = 0 then 0 else (- 1) ^ (n - 1) / of_nat n)"
lemma fps_deriv_L: "fps_deriv (L c) = fps_const (1/c) * inverse (1 + X)"
unfolding inverse_one_plus_X
by (simp add: L_def fps_eq_iff del: of_nat_Suc)
lemma L_nth: "L c $ n = (if n=0 then 0 else 1/c * ((- 1) ^ (n - 1) / of_nat n))"
by (simp add: L_def field_simps)
lemma L_0[simp]: "L c $ 0 = 0" by (simp add: L_def)
lemma L_E_inv:
assumes a: "a\<noteq> (0::'a::{field,ring_char_0})"
shows "L a = fps_inv (E a - 1)" (is "?l = ?r")
proof-
let ?b = "E a - 1"
have b0: "?b $ 0 = 0" by simp
have b1: "?b $ 1 \<noteq> 0" by (simp add: a)
have "fps_deriv (E a - 1) oo fps_inv (E a - 1) = (fps_const a * (E a - 1) + fps_const a) oo fps_inv (E a - 1)"
by (simp add: ring_simps)
also have "\<dots> = fps_const a * (X + 1)" apply (simp add: fps_compose_add_distrib fps_const_mult_apply_left[symmetric] fps_inv_right[OF b0 b1])
by (simp add: ring_simps)
finally have eq: "fps_deriv (E a - 1) oo fps_inv (E a - 1) = fps_const a * (X + 1)" .
from fps_inv_deriv[OF b0 b1, unfolded eq]
have "fps_deriv (fps_inv ?b) = fps_const (inverse a) / (X + 1)"
using a
by (simp add: fps_const_inverse eq fps_divide_def fps_inverse_mult)
hence "fps_deriv ?l = fps_deriv ?r"
by (simp add: fps_deriv_L add_commute fps_divide_def divide_inverse)
then show ?thesis unfolding fps_deriv_eq_iff
by (simp add: L_nth fps_inv_def)
qed
lemma L_mult_add:
assumes c0: "c\<noteq>0" and d0: "d\<noteq>0"
shows "L c + L d = fps_const (c+d) * L (c*d)"
(is "?r = ?l")
proof-
from c0 d0 have eq: "1/c + 1/d = (c+d)/(c*d)" by (simp add: field_simps)
have "fps_deriv ?r = fps_const (1/c + 1/d) * inverse (1 + X)"
by (simp add: fps_deriv_L fps_const_add[symmetric] algebra_simps del: fps_const_add)
also have "\<dots> = fps_deriv ?l"
apply (simp add: fps_deriv_L)
by (simp add: fps_eq_iff eq)
finally show ?thesis
unfolding fps_deriv_eq_iff by simp
qed
subsubsection{* Formal trigonometric functions *}
definition "fps_sin (c::'a::{field, ring_char_0}) =
Abs_fps (\<lambda>n. if even n then 0 else (- 1) ^((n - 1) div 2) * c^n /(of_nat (fact n)))"
definition "fps_cos (c::'a::{field, ring_char_0}) = Abs_fps (\<lambda>n. if even n then (- 1) ^ (n div 2) * c^n / (of_nat (fact n)) else 0)"
lemma fps_sin_deriv:
"fps_deriv (fps_sin c) = fps_const c * fps_cos c"
(is "?lhs = ?rhs")
proof-
{fix n::nat
{assume en: "even n"
have "?lhs$n = of_nat (n+1) * (fps_sin c $ (n+1))" by simp
also have "\<dots> = of_nat (n+1) * ((- 1)^(n div 2) * c^Suc n / of_nat (fact (Suc n)))"
using en by (simp add: fps_sin_def)
also have "\<dots> = (- 1)^(n div 2) * c^Suc n * (of_nat (n+1) / (of_nat (Suc n) * of_nat (fact n)))"
unfolding fact_Suc of_nat_mult
by (simp add: field_simps del: of_nat_add of_nat_Suc)
also have "\<dots> = (- 1)^(n div 2) *c^Suc n / of_nat (fact n)"
by (simp add: field_simps del: of_nat_add of_nat_Suc)
finally have "?lhs $n = ?rhs$n" using en
by (simp add: fps_cos_def ring_simps power_Suc )}
then have "?lhs $ n = ?rhs $ n"
by (cases "even n", simp_all add: fps_deriv_def fps_sin_def fps_cos_def) }
then show ?thesis by (auto simp add: fps_eq_iff)
qed
lemma fps_cos_deriv:
"fps_deriv (fps_cos c) = fps_const (- c)* (fps_sin c)"
(is "?lhs = ?rhs")
proof-
have th0: "\<And>n. - ((- 1::'a) ^ n) = (- 1)^Suc n" by (simp add: power_Suc)
have th1: "\<And>n. odd n\<Longrightarrow> Suc ((n - 1) div 2) = Suc n div 2" by presburger (* FIXME: VERY slow! *)
{fix n::nat
{assume en: "odd n"
from en have n0: "n \<noteq>0 " by presburger
have "?lhs$n = of_nat (n+1) * (fps_cos c $ (n+1))" by simp
also have "\<dots> = of_nat (n+1) * ((- 1)^((n + 1) div 2) * c^Suc n / of_nat (fact (Suc n)))"
using en by (simp add: fps_cos_def)
also have "\<dots> = (- 1)^((n + 1) div 2)*c^Suc n * (of_nat (n+1) / (of_nat (Suc n) * of_nat (fact n)))"
unfolding fact_Suc of_nat_mult
by (simp add: field_simps del: of_nat_add of_nat_Suc)
also have "\<dots> = (- 1)^((n + 1) div 2) * c^Suc n / of_nat (fact n)"
by (simp add: field_simps del: of_nat_add of_nat_Suc)
also have "\<dots> = (- ((- 1)^((n - 1) div 2))) * c^Suc n / of_nat (fact n)"
unfolding th0 unfolding th1[OF en] by simp
finally have "?lhs $n = ?rhs$n" using en
by (simp add: fps_sin_def ring_simps power_Suc)}
then have "?lhs $ n = ?rhs $ n"
by (cases "even n", simp_all add: fps_deriv_def fps_sin_def
fps_cos_def) }
then show ?thesis by (auto simp add: fps_eq_iff)
qed
lemma fps_sin_cos_sum_of_squares:
"fps_cos c ^ 2 + fps_sin c ^ 2 = 1" (is "?lhs = 1")
proof-
have "fps_deriv ?lhs = 0"
apply (simp add: fps_deriv_power fps_sin_deriv fps_cos_deriv power_Suc)
by (simp add: ring_simps fps_const_neg[symmetric] del: fps_const_neg)
then have "?lhs = fps_const (?lhs $ 0)"
unfolding fps_deriv_eq_0_iff .
also have "\<dots> = 1"
by (auto simp add: fps_eq_iff numeral_2_eq_2 fps_mult_nth fps_cos_def fps_sin_def)
finally show ?thesis .
qed
definition "fps_tan c = fps_sin c / fps_cos c"
lemma fps_tan_deriv: "fps_deriv(fps_tan c) = fps_const c/ (fps_cos c ^ 2)"
proof-
have th0: "fps_cos c $ 0 \<noteq> 0" by (simp add: fps_cos_def)
show ?thesis
using fps_sin_cos_sum_of_squares[of c]
apply (simp add: fps_tan_def fps_divide_deriv[OF th0] fps_sin_deriv fps_cos_deriv add: fps_const_neg[symmetric] ring_simps power2_eq_square del: fps_const_neg)
unfolding right_distrib[symmetric]
by simp
qed
end