src/HOL/Number_Theory/Residues.thy
 author wenzelm Mon, 22 May 2017 14:08:22 +0200 changeset 65899 ab7d8c999531 parent 65726 f5d64d094efe child 66304 cde6ceffcbc7 permissions -rw-r--r--
removed junk;
```
(*  Title:      HOL/Number_Theory/Residues.thy

An algebraic treatment of residue rings, and resulting proofs of
Euler's theorem and Wilson's theorem.
*)

section \<open>Residue rings\<close>

theory Residues
imports
Cong
"~~/src/HOL/Algebra/More_Group"
"~~/src/HOL/Algebra/More_Ring"
"~~/src/HOL/Algebra/More_Finite_Product"
"~~/src/HOL/Algebra/Multiplicative_Group"
Totient
begin

definition QuadRes :: "int \<Rightarrow> int \<Rightarrow> bool" where
"QuadRes p a = (\<exists>y. ([y^2 = a] (mod p)))"

definition Legendre :: "int \<Rightarrow> int \<Rightarrow> int" where
"Legendre a p = (if ([a = 0] (mod p)) then 0
else if QuadRes p a then 1
else -1)"

subsection \<open>A locale for residue rings\<close>

definition residue_ring :: "int \<Rightarrow> int ring"
where
"residue_ring m =
\<lparr>carrier = {0..m - 1},
monoid.mult = \<lambda>x y. (x * y) mod m,
one = 1,
zero = 0,
add = \<lambda>x y. (x + y) mod m\<rparr>"

locale residues =
fixes m :: int and R (structure)
assumes m_gt_one: "m > 1"
defines "R \<equiv> residue_ring m"
begin

lemma abelian_group: "abelian_group R"
proof -
have "\<exists>y\<in>{0..m - 1}. (x + y) mod m = 0" if "0 \<le> x" "x < m" for x
proof (cases "x = 0")
case True
with m_gt_one show ?thesis by simp
next
case False
then have "(x + (m - x)) mod m = 0"
by simp
with m_gt_one that show ?thesis
by (metis False atLeastAtMost_iff diff_ge_0_iff_ge diff_left_mono int_one_le_iff_zero_less less_le)
qed
with m_gt_one show ?thesis
qed

lemma comm_monoid: "comm_monoid R"
unfolding R_def residue_ring_def
apply (rule comm_monoidI)
using m_gt_one  apply auto
apply (metis mod_mult_right_eq mult.assoc mult.commute)
apply (metis mult.commute)
done

lemma cring: "cring R"
apply (intro cringI abelian_group comm_monoid)
unfolding R_def residue_ring_def
done

end

sublocale residues < cring
by (rule cring)

context residues
begin

text \<open>
These lemmas translate back and forth between internal and
external concepts.
\<close>

lemma res_carrier_eq: "carrier R = {0..m - 1}"
unfolding R_def residue_ring_def by auto

lemma res_add_eq: "x \<oplus> y = (x + y) mod m"
unfolding R_def residue_ring_def by auto

lemma res_mult_eq: "x \<otimes> y = (x * y) mod m"
unfolding R_def residue_ring_def by auto

lemma res_zero_eq: "\<zero> = 0"
unfolding R_def residue_ring_def by auto

lemma res_one_eq: "\<one> = 1"
unfolding R_def residue_ring_def units_of_def by auto

lemma res_units_eq: "Units R = {x. 0 < x \<and> x < m \<and> coprime x m}"
using m_gt_one
unfolding Units_def R_def residue_ring_def
apply auto
apply (subgoal_tac "x \<noteq> 0")
apply auto
apply (metis invertible_coprime_int)
apply (subst (asm) coprime_iff_invertible'_int)
apply (auto simp add: cong_int_def mult.commute)
done

lemma res_neg_eq: "\<ominus> x = (- x) mod m"
using m_gt_one unfolding R_def a_inv_def m_inv_def residue_ring_def
apply simp
apply (rule the_equality)
done

lemma finite [iff]: "finite (carrier R)"

lemma finite_Units [iff]: "finite (Units R)"

text \<open>
The function \<open>a \<mapsto> a mod m\<close> maps the integers to the
residue classes. The following lemmas show that this mapping
respects addition and multiplication on the integers.
\<close>

lemma mod_in_carrier [iff]: "a mod m \<in> carrier R"
unfolding res_carrier_eq
using insert m_gt_one by auto

lemma add_cong: "(x mod m) \<oplus> (y mod m) = (x + y) mod m"
unfolding R_def residue_ring_def

lemma mult_cong: "(x mod m) \<otimes> (y mod m) = (x * y) mod m"
unfolding R_def residue_ring_def

lemma zero_cong: "\<zero> = 0"
unfolding R_def residue_ring_def by auto

lemma one_cong: "\<one> = 1 mod m"
using m_gt_one unfolding R_def residue_ring_def by auto

(* FIXME revise algebra library to use 1? *)
lemma pow_cong: "(x mod m) (^) n = x^n mod m"
using m_gt_one
apply (induct n)
apply (auto simp add: nat_pow_def one_cong)
apply (metis mult.commute mult_cong)
done

lemma neg_cong: "\<ominus> (x mod m) = (- x) mod m"
by (metis mod_minus_eq res_neg_eq)

lemma (in residues) prod_cong: "finite A \<Longrightarrow> (\<Otimes>i\<in>A. (f i) mod m) = (\<Prod>i\<in>A. f i) mod m"
by (induct set: finite) (auto simp: one_cong mult_cong)

lemma (in residues) sum_cong: "finite A \<Longrightarrow> (\<Oplus>i\<in>A. (f i) mod m) = (\<Sum>i\<in>A. f i) mod m"
by (induct set: finite) (auto simp: zero_cong add_cong)

lemma mod_in_res_units [simp]:
assumes "1 < m" and "coprime a m"
shows "a mod m \<in> Units R"
proof (cases "a mod m = 0")
case True with assms show ?thesis
by (auto simp add: res_units_eq gcd_red_int [symmetric])
next
case False
from assms have "0 < m" by simp
with pos_mod_sign [of m a] have "0 \<le> a mod m" .
with False have "0 < a mod m" by simp
with assms show ?thesis
by (auto simp add: res_units_eq gcd_red_int [symmetric] ac_simps)
qed

lemma res_eq_to_cong: "(a mod m) = (b mod m) \<longleftrightarrow> [a = b] (mod m)"
unfolding cong_int_def by auto

text \<open>Simplifying with these will translate a ring equation in R to a congruence.\<close>
lemmas res_to_cong_simps = add_cong mult_cong pow_cong one_cong
prod_cong sum_cong neg_cong res_eq_to_cong

text \<open>Other useful facts about the residue ring.\<close>
lemma one_eq_neg_one: "\<one> = \<ominus> \<one> \<Longrightarrow> m = 2"
zero_neq_one zmod_zminus1_eq_if)
done

end

subsection \<open>Prime residues\<close>

locale residues_prime =
fixes p :: nat and R (structure)
assumes p_prime [intro]: "prime p"
defines "R \<equiv> residue_ring (int p)"

sublocale residues_prime < residues p
unfolding R_def residues_def
using p_prime apply auto
apply (metis (full_types) of_nat_1 of_nat_less_iff prime_gt_1_nat)
done

context residues_prime
begin

lemma is_field: "field R"
proof -
have "\<And>x. \<lbrakk>gcd x (int p) \<noteq> 1; 0 \<le> x; x < int p\<rbrakk> \<Longrightarrow> x = 0"
by (metis dual_order.order_iff_strict gcd.commute less_le_not_le p_prime prime_imp_coprime prime_nat_int_transfer zdvd_imp_le)
then show ?thesis
apply (intro cring.field_intro2 cring)
apply (auto simp add: res_carrier_eq res_one_eq res_zero_eq res_units_eq)
done
qed

lemma res_prime_units_eq: "Units R = {1..p - 1}"
apply (subst res_units_eq)
apply auto
apply (subst gcd.commute)
apply (auto simp add: p_prime prime_imp_coprime_int zdvd_not_zless)
done

end

sublocale residues_prime < field
by (rule is_field)

section \<open>Test cases: Euler's theorem and Wilson's theorem\<close>

subsection \<open>Euler's theorem\<close>

lemma (in residues) totient_eq:
"totient (nat m) = card (Units R)"
proof -
have *: "inj_on nat (Units R)"
by (rule inj_onI) (auto simp add: res_units_eq)
define m' where "m' = nat m"
from m_gt_one have m: "m = int m'" "m' > 1" by (simp_all add: m'_def)
from m have "x \<in> Units R \<longleftrightarrow> x \<in> int ` totatives m'" for x
unfolding res_units_eq
by (cases x; cases "x = m") (auto simp: totatives_def transfer_int_nat_gcd)
hence "Units R = int ` totatives m'" by blast
hence "totatives m' = nat ` Units R" by (simp add: image_image)
then have "card (totatives (nat m)) = card (nat ` Units R)"
also have "\<dots> = card (Units R)"
using * card_image [of nat "Units R"] by auto
finally show ?thesis by (simp add: totient_def)
qed

lemma (in residues_prime) totient_eq: "totient p = p - 1"
using totient_eq by (simp add: res_prime_units_eq)

lemma (in residues) euler_theorem:
assumes "coprime a m"
shows "[a ^ totient (nat m) = 1] (mod m)"
proof -
have "a ^ totient (nat m) mod m = 1 mod m"
by (metis assms finite_Units m_gt_one mod_in_res_units one_cong totient_eq pow_cong units_power_order_eq_one)
then show ?thesis
using res_eq_to_cong by blast
qed

lemma euler_theorem:
fixes a m :: nat
assumes "coprime a m"
shows "[a ^ totient m = 1] (mod m)"
proof (cases "m = 0 | m = 1")
case True
then show ?thesis by auto
next
case False
with assms show ?thesis
using residues.euler_theorem [of "int m" "int a"] transfer_int_nat_cong
by (auto simp add: residues_def transfer_int_nat_gcd(1)) force
qed

lemma fermat_theorem:
fixes p a :: nat
assumes "prime p" and "\<not> p dvd a"
shows "[a ^ (p - 1) = 1] (mod p)"
proof -
from assms prime_imp_coprime [of p a] have "coprime a p"
then have "[a ^ totient p = 1] (mod p)"
by (rule euler_theorem)
also have "totient p = p - 1"
by (rule totient_prime) (rule assms)
finally show ?thesis .
qed

subsection \<open>Wilson's theorem\<close>

lemma (in field) inv_pair_lemma: "x \<in> Units R \<Longrightarrow> y \<in> Units R \<Longrightarrow>
{x, inv x} \<noteq> {y, inv y} \<Longrightarrow> {x, inv x} \<inter> {y, inv y} = {}"
apply auto
apply (metis Units_inv_inv)+
done

lemma (in residues_prime) wilson_theorem1:
assumes a: "p > 2"
shows "[fact (p - 1) = (-1::int)] (mod p)"
proof -
let ?Inverse_Pairs = "{{x, inv x}| x. x \<in> Units R - {\<one>, \<ominus> \<one>}}"
have UR: "Units R = {\<one>, \<ominus> \<one>} \<union> \<Union>?Inverse_Pairs"
by auto
have "(\<Otimes>i\<in>Units R. i) = (\<Otimes>i\<in>{\<one>, \<ominus> \<one>}. i) \<otimes> (\<Otimes>i\<in>\<Union>?Inverse_Pairs. i)"
apply (subst UR)
apply (subst finprod_Un_disjoint)
apply (auto intro: funcsetI)
using inv_one apply auto[1]
using inv_eq_neg_one_eq apply auto
done
also have "(\<Otimes>i\<in>{\<one>, \<ominus> \<one>}. i) = \<ominus> \<one>"
apply (subst finprod_insert)
apply auto
apply (frule one_eq_neg_one)
using a apply force
done
also have "(\<Otimes>i\<in>(\<Union>?Inverse_Pairs). i) = (\<Otimes>A\<in>?Inverse_Pairs. (\<Otimes>y\<in>A. y))"
apply (subst finprod_Union_disjoint)
apply auto
apply (metis Units_inv_inv)+
done
also have "\<dots> = \<one>"
apply (rule finprod_one)
apply auto
apply (subst finprod_insert)
apply auto
apply (metis inv_eq_self)
done
finally have "(\<Otimes>i\<in>Units R. i) = \<ominus> \<one>"
by simp
also have "(\<Otimes>i\<in>Units R. i) = (\<Otimes>i\<in>Units R. i mod p)"
by (rule finprod_cong') (auto simp: res_units_eq)
also have "\<dots> = (\<Prod>i\<in>Units R. i) mod p"
by (rule prod_cong) auto
also have "\<dots> = fact (p - 1) mod p"
using assms
apply (subst res_prime_units_eq)
apply (simp add: int_prod zmod_int prod_int_eq)
done
finally have "fact (p - 1) mod p = \<ominus> \<one>" .
then show ?thesis
by (metis of_nat_fact Divides.transfer_int_nat_functions(2)
cong_int_def res_neg_eq res_one_eq)
qed

lemma wilson_theorem:
assumes "prime p"
shows "[fact (p - 1) = - 1] (mod p)"
proof (cases "p = 2")
case True
then show ?thesis
next
case False
then show ?thesis
using assms prime_ge_2_nat
by (metis residues_prime.wilson_theorem1 residues_prime.intro le_eq_less_or_eq)
qed

text {*
This result can be transferred to the multiplicative group of
\$\mathbb{Z}/p\mathbb{Z}\$ for \$p\$ prime. *}

lemma mod_nat_int_pow_eq:
fixes n :: nat and p a :: int
assumes "a \<ge> 0" "p \<ge> 0"
shows "(nat a ^ n) mod (nat p) = nat ((a ^ n) mod p)"
using assms
by (simp add: int_one_le_iff_zero_less nat_mod_distrib order_less_imp_le nat_power_eq[symmetric])

theorem residue_prime_mult_group_has_gen :
fixes p :: nat
assumes prime_p : "prime p"
shows "\<exists>a \<in> {1 .. p - 1}. {1 .. p - 1} = {a^i mod p|i . i \<in> UNIV}"
proof -
have "p\<ge>2" using prime_gt_1_nat[OF prime_p] by simp
interpret R:residues_prime "p" "residue_ring p" unfolding residues_prime_def
have car: "carrier (residue_ring (int p)) - {\<zero>\<^bsub>residue_ring (int p)\<^esub>} =  {1 .. int p - 1}"
by (auto simp add: R.zero_cong R.res_carrier_eq)
obtain a where a:"a \<in> {1 .. int p - 1}"
and a_gen:"{1 .. int p - 1} = {a(^)\<^bsub>residue_ring (int p)\<^esub>i|i::nat . i \<in> UNIV}"
apply atomize_elim using field.finite_field_mult_group_has_gen[OF R.is_field]
by (auto simp add: car[symmetric] carrier_mult_of)
{ fix x fix i :: nat assume x: "x \<in> {1 .. int p - 1}"
hence "x (^)\<^bsub>residue_ring (int p)\<^esub> i = x ^ i mod (int p)" using R.pow_cong[of x i] by auto}
note * = this
have **:"nat ` {1 .. int p - 1} = {1 .. p - 1}" (is "?L = ?R")
proof
{ fix n assume n: "n \<in> ?L"
then have "n \<in> ?R" using `p\<ge>2` by force
} thus "?L \<subseteq> ?R" by blast
{ fix n assume n: "n \<in> ?R"
then have "n \<in> ?L" using `p\<ge>2` Set_Interval.transfer_nat_int_set_functions(2) by fastforce
} thus "?R \<subseteq> ?L" by blast
qed
have "nat ` {a^i mod (int p) | i::nat. i \<in> UNIV} = {nat a^i mod p | i . i \<in> UNIV}" (is "?L = ?R")
proof
{ fix x assume x: "x \<in> ?L"
then obtain i where i:"x = nat (a^i mod (int p))" by blast
hence "x = nat a ^ i mod p" using mod_nat_int_pow_eq[of a "int p" i] a `p\<ge>2` by auto
hence "x \<in> ?R" using i by blast
} thus "?L \<subseteq> ?R" by blast
{ fix x assume x: "x \<in> ?R"
then obtain i where i:"x = nat a^i mod p" by blast
hence "x \<in> ?L" using mod_nat_int_pow_eq[of a "int p" i] a `p\<ge>2` by auto
} thus "?R \<subseteq> ?L" by blast
qed
hence "{1 .. p - 1} = {nat a^i mod p | i. i \<in> UNIV}"
using * a a_gen ** by presburger
moreover
have "nat a \<in> {1 .. p - 1}" using a by force
ultimately show ?thesis ..
qed

end
```