src/HOL/Typedef.thy
 author wenzelm Sat, 07 Apr 2012 16:41:59 +0200 changeset 47389 e8552cba702d parent 46950 d0181abdbdac child 48891 c0eafbd55de3 permissions -rw-r--r--
explicit checks stable_finished_theory/stable_command allow parallel asynchronous command transactions; tuned;
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(*  Title:      HOL/Typedef.thy
Author:     Markus Wenzel, TU Munich
*)

header {* HOL type definitions *}

theory Typedef
imports Set
keywords "typedef" :: thy_goal and "morphisms"
uses ("Tools/typedef.ML")
begin

locale type_definition =
fixes Rep and Abs and A
assumes Rep: "Rep x \<in> A"
and Rep_inverse: "Abs (Rep x) = x"
and Abs_inverse: "y \<in> A ==> Rep (Abs y) = y"
-- {* This will be axiomatized for each typedef! *}
begin

lemma Rep_inject:
"(Rep x = Rep y) = (x = y)"
proof
assume "Rep x = Rep y"
then have "Abs (Rep x) = Abs (Rep y)" by (simp only:)
moreover have "Abs (Rep x) = x" by (rule Rep_inverse)
moreover have "Abs (Rep y) = y" by (rule Rep_inverse)
ultimately show "x = y" by simp
next
assume "x = y"
thus "Rep x = Rep y" by (simp only:)
qed

lemma Abs_inject:
assumes x: "x \<in> A" and y: "y \<in> A"
shows "(Abs x = Abs y) = (x = y)"
proof
assume "Abs x = Abs y"
then have "Rep (Abs x) = Rep (Abs y)" by (simp only:)
moreover from x have "Rep (Abs x) = x" by (rule Abs_inverse)
moreover from y have "Rep (Abs y) = y" by (rule Abs_inverse)
ultimately show "x = y" by simp
next
assume "x = y"
thus "Abs x = Abs y" by (simp only:)
qed

lemma Rep_cases [cases set]:
assumes y: "y \<in> A"
and hyp: "!!x. y = Rep x ==> P"
shows P
proof (rule hyp)
from y have "Rep (Abs y) = y" by (rule Abs_inverse)
thus "y = Rep (Abs y)" ..
qed

lemma Abs_cases [cases type]:
assumes r: "!!y. x = Abs y ==> y \<in> A ==> P"
shows P
proof (rule r)
have "Abs (Rep x) = x" by (rule Rep_inverse)
thus "x = Abs (Rep x)" ..
show "Rep x \<in> A" by (rule Rep)
qed

lemma Rep_induct [induct set]:
assumes y: "y \<in> A"
and hyp: "!!x. P (Rep x)"
shows "P y"
proof -
have "P (Rep (Abs y))" by (rule hyp)
moreover from y have "Rep (Abs y) = y" by (rule Abs_inverse)
ultimately show "P y" by simp
qed

lemma Abs_induct [induct type]:
assumes r: "!!y. y \<in> A ==> P (Abs y)"
shows "P x"
proof -
have "Rep x \<in> A" by (rule Rep)
then have "P (Abs (Rep x))" by (rule r)
moreover have "Abs (Rep x) = x" by (rule Rep_inverse)
ultimately show "P x" by simp
qed

lemma Rep_range: "range Rep = A"
proof
show "range Rep <= A" using Rep by (auto simp add: image_def)
show "A <= range Rep"
proof
fix x assume "x : A"
hence "x = Rep (Abs x)" by (rule Abs_inverse [symmetric])
thus "x : range Rep" by (rule range_eqI)
qed
qed

lemma Abs_image: "Abs ` A = UNIV"
proof
show "Abs ` A <= UNIV" by (rule subset_UNIV)
next
show "UNIV <= Abs ` A"
proof
fix x
have "x = Abs (Rep x)" by (rule Rep_inverse [symmetric])
moreover have "Rep x : A" by (rule Rep)
ultimately show "x : Abs ` A" by (rule image_eqI)
qed
qed

end

use "Tools/typedef.ML" setup Typedef.setup

end
```