diff -r ca430e6aee1c -r 9b535493ac8d src/HOL/NewNumberTheory/Binomial.thy
--- a/src/HOL/NewNumberTheory/Binomial.thy	Tue Sep 29 22:15:54 2009 +0200
+++ /dev/null	Thu Jan 01 00:00:00 1970 +0000
@@ -1,373 +0,0 @@
-(*  Title:      Binomial.thy
-    Authors:    Lawrence C. Paulson, Jeremy Avigad, Tobias Nipkow
-
-
-Defines the "choose" function, and establishes basic properties.
-
-The original theory "Binomial" was by Lawrence C. Paulson, based on
-the work of Andy Gordon and Florian Kammueller. The approach here,
-which derives the definition of binomial coefficients in terms of the
-factorial function, is due to Jeremy Avigad. The binomial theorem was
-formalized by Tobias Nipkow.
-
-*)
-
-
-header {* Binomial *}
-
-theory Binomial
-imports Cong Fact
-begin
-
-
-subsection {* Main definitions *}
-
-class binomial =
-
-fixes 
-  binomial :: "'a \<Rightarrow> 'a \<Rightarrow> 'a" (infixl "choose" 65)
-
-(* definitions for the natural numbers *)
-
-instantiation nat :: binomial
-
-begin 
-
-fun
-  binomial_nat :: "nat \<Rightarrow> nat \<Rightarrow> nat"
-where
-  "binomial_nat n k =
-   (if k = 0 then 1 else
-    if n = 0 then 0 else
-      (binomial (n - 1) k) + (binomial (n - 1) (k - 1)))"
-
-instance proof qed
-
-end
-
-(* definitions for the integers *)
-
-instantiation int :: binomial
-
-begin 
-
-definition
-  binomial_int :: "int => int \<Rightarrow> int"
-where
-  "binomial_int n k = (if n \<ge> 0 \<and> k \<ge> 0 then int (binomial (nat n) (nat k))
-      else 0)"
-instance proof qed
-
-end
-
-
-subsection {* Set up Transfer *}
-
-lemma transfer_nat_int_binomial:
-  "(n::int) >= 0 \<Longrightarrow> k >= 0 \<Longrightarrow> binomial (nat n) (nat k) = 
-      nat (binomial n k)"
-  unfolding binomial_int_def 
-  by auto
-
-lemma transfer_nat_int_binomial_closure:
-  "n >= (0::int) \<Longrightarrow> k >= 0 \<Longrightarrow> binomial n k >= 0"
-  by (auto simp add: binomial_int_def)
-
-declare TransferMorphism_nat_int[transfer add return: 
-    transfer_nat_int_binomial transfer_nat_int_binomial_closure]
-
-lemma transfer_int_nat_binomial:
-  "binomial (int n) (int k) = int (binomial n k)"
-  unfolding fact_int_def binomial_int_def by auto
-
-lemma transfer_int_nat_binomial_closure:
-  "is_nat n \<Longrightarrow> is_nat k \<Longrightarrow> binomial n k >= 0"
-  by (auto simp add: binomial_int_def)
-
-declare TransferMorphism_int_nat[transfer add return: 
-    transfer_int_nat_binomial transfer_int_nat_binomial_closure]
-
-
-subsection {* Binomial coefficients *}
-
-lemma choose_zero_nat [simp]: "(n::nat) choose 0 = 1"
-  by simp
-
-lemma choose_zero_int [simp]: "n \<ge> 0 \<Longrightarrow> (n::int) choose 0 = 1"
-  by (simp add: binomial_int_def)
-
-lemma zero_choose_nat [rule_format,simp]: "ALL (k::nat) > n. n choose k = 0"
-  by (induct n rule: induct'_nat, auto)
-
-lemma zero_choose_int [rule_format,simp]: "(k::int) > n \<Longrightarrow> n choose k = 0"
-  unfolding binomial_int_def apply (case_tac "n < 0")
-  apply force
-  apply (simp del: binomial_nat.simps)
-done
-
-lemma choose_reduce_nat: "(n::nat) > 0 \<Longrightarrow> 0 < k \<Longrightarrow>
-    (n choose k) = ((n - 1) choose k) + ((n - 1) choose (k - 1))"
-  by simp
-
-lemma choose_reduce_int: "(n::int) > 0 \<Longrightarrow> 0 < k \<Longrightarrow>
-    (n choose k) = ((n - 1) choose k) + ((n - 1) choose (k - 1))"
-  unfolding binomial_int_def apply (subst choose_reduce_nat)
-    apply (auto simp del: binomial_nat.simps 
-      simp add: nat_diff_distrib)
-done
-
-lemma choose_plus_one_nat: "((n::nat) + 1) choose (k + 1) = 
-    (n choose (k + 1)) + (n choose k)"
-  by (simp add: choose_reduce_nat)
-
-lemma choose_Suc_nat: "(Suc n) choose (Suc k) = 
-    (n choose (Suc k)) + (n choose k)"
-  by (simp add: choose_reduce_nat One_nat_def)
-
-lemma choose_plus_one_int: "n \<ge> 0 \<Longrightarrow> k \<ge> 0 \<Longrightarrow> ((n::int) + 1) choose (k + 1) = 
-    (n choose (k + 1)) + (n choose k)"
-  by (simp add: binomial_int_def choose_plus_one_nat nat_add_distrib del: binomial_nat.simps)
-
-declare binomial_nat.simps [simp del]
-
-lemma choose_self_nat [simp]: "((n::nat) choose n) = 1"
-  by (induct n rule: induct'_nat, auto simp add: choose_plus_one_nat)
-
-lemma choose_self_int [simp]: "n \<ge> 0 \<Longrightarrow> ((n::int) choose n) = 1"
-  by (auto simp add: binomial_int_def)
-
-lemma choose_one_nat [simp]: "(n::nat) choose 1 = n"
-  by (induct n rule: induct'_nat, auto simp add: choose_reduce_nat)
-
-lemma choose_one_int [simp]: "n \<ge> 0 \<Longrightarrow> (n::int) choose 1 = n"
-  by (auto simp add: binomial_int_def)
-
-lemma plus_one_choose_self_nat [simp]: "(n::nat) + 1 choose n = n + 1"
-  apply (induct n rule: induct'_nat, force)
-  apply (case_tac "n = 0")
-  apply auto
-  apply (subst choose_reduce_nat)
-  apply (auto simp add: One_nat_def)  
-  (* natdiff_cancel_numerals introduces Suc *)
-done
-
-lemma Suc_choose_self_nat [simp]: "(Suc n) choose n = Suc n"
-  using plus_one_choose_self_nat by (simp add: One_nat_def)
-
-lemma plus_one_choose_self_int [rule_format, simp]: 
-    "(n::int) \<ge> 0 \<longrightarrow> n + 1 choose n = n + 1"
-   by (auto simp add: binomial_int_def nat_add_distrib)
-
-(* bounded quantification doesn't work with the unicode characters? *)
-lemma choose_pos_nat [rule_format]: "ALL k <= (n::nat). 
-    ((n::nat) choose k) > 0"
-  apply (induct n rule: induct'_nat) 
-  apply force
-  apply clarify
-  apply (case_tac "k = 0")
-  apply force
-  apply (subst choose_reduce_nat)
-  apply auto
-done
-
-lemma choose_pos_int: "n \<ge> 0 \<Longrightarrow> k >= 0 \<Longrightarrow> k \<le> n \<Longrightarrow>
-    ((n::int) choose k) > 0"
-  by (auto simp add: binomial_int_def choose_pos_nat)
-
-lemma binomial_induct [rule_format]: "(ALL (n::nat). P n n) \<longrightarrow> 
-    (ALL n. P (n + 1) 0) \<longrightarrow> (ALL n. (ALL k < n. P n k \<longrightarrow> P n (k + 1) \<longrightarrow>
-    P (n + 1) (k + 1))) \<longrightarrow> (ALL k <= n. P n k)"
-  apply (induct n rule: induct'_nat)
-  apply auto
-  apply (case_tac "k = 0")
-  apply auto
-  apply (case_tac "k = n + 1")
-  apply auto
-  apply (drule_tac x = n in spec) back back 
-  apply (drule_tac x = "k - 1" in spec) back back back
-  apply auto
-done
-
-lemma choose_altdef_aux_nat: "(k::nat) \<le> n \<Longrightarrow> 
-    fact k * fact (n - k) * (n choose k) = fact n"
-  apply (rule binomial_induct [of _ k n])
-  apply auto
-proof -
-  fix k :: nat and n
-  assume less: "k < n"
-  assume ih1: "fact k * fact (n - k) * (n choose k) = fact n"
-  hence one: "fact (k + 1) * fact (n - k) * (n choose k) = (k + 1) * fact n"
-    by (subst fact_plus_one_nat, auto)
-  assume ih2: "fact (k + 1) * fact (n - (k + 1)) * (n choose (k + 1)) = 
-      fact n"
-  with less have "fact (k + 1) * fact ((n - (k + 1)) + 1) * 
-      (n choose (k + 1)) = (n - k) * fact n"
-    by (subst (2) fact_plus_one_nat, auto)
-  with less have two: "fact (k + 1) * fact (n - k) * (n choose (k + 1)) = 
-      (n - k) * fact n" by simp
-  have "fact (k + 1) * fact (n - k) * (n + 1 choose (k + 1)) =
-      fact (k + 1) * fact (n - k) * (n choose (k + 1)) + 
-      fact (k + 1) * fact (n - k) * (n choose k)" 
-    by (subst choose_reduce_nat, auto simp add: ring_simps)
-  also note one
-  also note two
-  also with less have "(n - k) * fact n + (k + 1) * fact n= fact (n + 1)" 
-    apply (subst fact_plus_one_nat)
-    apply (subst left_distrib [symmetric])
-    apply simp
-    done
-  finally show "fact (k + 1) * fact (n - k) * (n + 1 choose (k + 1)) = 
-    fact (n + 1)" .
-qed
-
-lemma choose_altdef_nat: "(k::nat) \<le> n \<Longrightarrow> 
-    n choose k = fact n div (fact k * fact (n - k))"
-  apply (frule choose_altdef_aux_nat)
-  apply (erule subst)
-  apply (simp add: mult_ac)
-done
-
-
-lemma choose_altdef_int: 
-  assumes "(0::int) <= k" and "k <= n"
-  shows "n choose k = fact n div (fact k * fact (n - k))"
-  
-  apply (subst tsub_eq [symmetric], rule prems)
-  apply (rule choose_altdef_nat [transferred])
-  using prems apply auto
-done
-
-lemma choose_dvd_nat: "(k::nat) \<le> n \<Longrightarrow> fact k * fact (n - k) dvd fact n"
-  unfolding dvd_def apply (frule choose_altdef_aux_nat)
-  (* why don't blast and auto get this??? *)
-  apply (rule exI)
-  apply (erule sym)
-done
-
-lemma choose_dvd_int: 
-  assumes "(0::int) <= k" and "k <= n"
-  shows "fact k * fact (n - k) dvd fact n"
- 
-  apply (subst tsub_eq [symmetric], rule prems)
-  apply (rule choose_dvd_nat [transferred])
-  using prems apply auto
-done
-
-(* generalizes Tobias Nipkow's proof to any commutative semiring *)
-theorem binomial: "(a+b::'a::{comm_ring_1,power})^n = 
-  (SUM k=0..n. (of_nat (n choose k)) * a^k * b^(n-k))" (is "?P n")
-proof (induct n rule: induct'_nat)
-  show "?P 0" by simp
-next
-  fix n
-  assume ih: "?P n"
-  have decomp: "{0..n+1} = {0} Un {n+1} Un {1..n}"
-    by auto
-  have decomp2: "{0..n} = {0} Un {1..n}"
-    by auto
-  have decomp3: "{1..n+1} = {n+1} Un {1..n}"
-    by auto
-  have "(a+b)^(n+1) = 
-      (a+b) * (SUM k=0..n. of_nat (n choose k) * a^k * b^(n-k))"
-    using ih by (simp add: power_plus_one)
-  also have "... =  a*(SUM k=0..n. of_nat (n choose k) * a^k * b^(n-k)) +
-                   b*(SUM k=0..n. of_nat (n choose k) * a^k * b^(n-k))"
-    by (rule distrib)
-  also have "... = (SUM k=0..n. of_nat (n choose k) * a^(k+1) * b^(n-k)) +
-                  (SUM k=0..n. of_nat (n choose k) * a^k * b^(n-k+1))"
-    by (subst (1 2) power_plus_one, simp add: setsum_right_distrib mult_ac)
-  also have "... = (SUM k=0..n. of_nat (n choose k) * a^k * b^(n+1-k)) +
-                  (SUM k=1..n+1. of_nat (n choose (k - 1)) * a^k * b^(n+1-k))"
-    by (simp add:setsum_shift_bounds_cl_Suc_ivl Suc_diff_le 
-             power_Suc ring_simps One_nat_def del:setsum_cl_ivl_Suc)
-  also have "... = a^(n+1) + b^(n+1) +
-                  (SUM k=1..n. of_nat (n choose (k - 1)) * a^k * b^(n+1-k)) +
-                  (SUM k=1..n. of_nat (n choose k) * a^k * b^(n+1-k))"
-    by (simp add: decomp2 decomp3)
-  also have
-      "... = a^(n+1) + b^(n+1) + 
-         (SUM k=1..n. of_nat(n+1 choose k) * a^k * b^(n+1-k))"
-    by (auto simp add: ring_simps setsum_addf [symmetric]
-      choose_reduce_nat)
-  also have "... = (SUM k=0..n+1. of_nat (n+1 choose k) * a^k * b^(n+1-k))"
-    using decomp by (simp add: ring_simps)
-  finally show "?P (n + 1)" by simp
-qed
-
-lemma set_explicit: "{S. S = T \<and> P S} = (if P T then {T} else {})"
-  by auto
-
-lemma card_subsets_nat [rule_format]:
-  fixes S :: "'a set"
-  assumes "finite S"
-  shows "ALL k. card {T. T \<le> S \<and> card T = k} = card S choose k" 
-      (is "?P S")
-using `finite S`
-proof (induct set: finite)
-  show "?P {}" by (auto simp add: set_explicit)
-  next fix x :: "'a" and F
-  assume iassms: "finite F" "x ~: F"
-  assume ih: "?P F"
-  show "?P (insert x F)" (is "ALL k. ?Q k")
-  proof
-    fix k
-    show "card {T. T \<subseteq> (insert x F) \<and> card T = k} = 
-        card (insert x F) choose k" (is "?Q k")
-    proof (induct k rule: induct'_nat)
-      from iassms have "{T. T \<le> (insert x F) \<and> card T = 0} = {{}}"
-        apply auto
-        apply (subst (asm) card_0_eq)
-        apply (auto elim: finite_subset)
-        done
-      thus "?Q 0" 
-        by auto
-      next fix k
-      show "?Q (k + 1)"
-      proof -
-        from iassms have fin: "finite (insert x F)" by auto
-        hence "{ T. T \<subseteq> insert x F \<and> card T = k + 1} =
-          {T. T \<le> F & card T = k + 1} Un 
-          {T. T \<le> insert x F & x : T & card T = k + 1}"
-          by (auto intro!: subsetI)
-        with iassms fin have "card ({T. T \<le> insert x F \<and> card T = k + 1}) = 
-          card ({T. T \<subseteq> F \<and> card T = k + 1}) + 
-          card ({T. T \<subseteq> insert x F \<and> x : T \<and> card T = k + 1})"
-          apply (subst card_Un_disjoint [symmetric])
-          apply auto
-          (* note: nice! Didn't have to say anything here *)
-          done
-        also from ih have "card ({T. T \<subseteq> F \<and> card T = k + 1}) = 
-          card F choose (k+1)" by auto
-        also have "card ({T. T \<subseteq> insert x F \<and> x : T \<and> card T = k + 1}) =
-          card ({T. T <= F & card T = k})"
-        proof -
-          let ?f = "%T. T Un {x}"
-          from iassms have "inj_on ?f {T. T <= F & card T = k}"
-            unfolding inj_on_def by (auto intro!: subsetI)
-          hence "card ({T. T <= F & card T = k}) = 
-            card(?f ` {T. T <= F & card T = k})"
-            by (rule card_image [symmetric])
-          also from iassms fin have "?f ` {T. T <= F & card T = k} = 
-            {T. T \<subseteq> insert x F \<and> x : T \<and> card T = k + 1}"
-            unfolding image_def 
-            (* I can't figure out why this next line takes so long *)
-            apply auto
-            apply (frule (1) finite_subset, force)
-            apply (rule_tac x = "xa - {x}" in exI)
-            apply (subst card_Diff_singleton)
-            apply (auto elim: finite_subset)
-            done
-          finally show ?thesis by (rule sym)
-        qed
-        also from ih have "card ({T. T <= F & card T = k}) = card F choose k"
-          by auto
-        finally have "card ({T. T \<le> insert x F \<and> card T = k + 1}) = 
-          card F choose (k + 1) + (card F choose k)".
-        with iassms choose_plus_one_nat show ?thesis
-          by auto
-      qed
-    qed
-  qed
-qed
-
-end