diff -r 71af1fd6a5e4 -r be3e1cc5005c src/HOL/Hahn_Banach/Vector_Space.thy --- /dev/null Thu Jan 01 00:00:00 1970 +0000 +++ b/src/HOL/Hahn_Banach/Vector_Space.thy Wed Jun 24 21:46:54 2009 +0200 @@ -0,0 +1,418 @@ +(* Title: HOL/Hahn_Banach/Vector_Space.thy + Author: Gertrud Bauer, TU Munich +*) + +header {* Vector spaces *} + +theory Vector_Space +imports Real Bounds Zorn +begin + +subsection {* Signature *} + +text {* + For the definition of real vector spaces a type @{typ 'a} of the + sort @{text "{plus, minus, zero}"} is considered, on which a real + scalar multiplication @{text \} is declared. +*} + +consts + prod :: "real \ 'a::{plus, minus, zero} \ 'a" (infixr "'(*')" 70) + +notation (xsymbols) + prod (infixr "\" 70) +notation (HTML output) + prod (infixr "\" 70) + + +subsection {* Vector space laws *} + +text {* + A \emph{vector space} is a non-empty set @{text V} of elements from + @{typ 'a} with the following vector space laws: The set @{text V} is + closed under addition and scalar multiplication, addition is + associative and commutative; @{text "- x"} is the inverse of @{text + x} w.~r.~t.~addition and @{text 0} is the neutral element of + addition. Addition and multiplication are distributive; scalar + multiplication is associative and the real number @{text "1"} is + the neutral element of scalar multiplication. +*} + +locale var_V = fixes V + +locale vectorspace = var_V + + assumes non_empty [iff, intro?]: "V \ {}" + and add_closed [iff]: "x \ V \ y \ V \ x + y \ V" + and mult_closed [iff]: "x \ V \ a \ x \ V" + and add_assoc: "x \ V \ y \ V \ z \ V \ (x + y) + z = x + (y + z)" + and add_commute: "x \ V \ y \ V \ x + y = y + x" + and diff_self [simp]: "x \ V \ x - x = 0" + and add_zero_left [simp]: "x \ V \ 0 + x = x" + and add_mult_distrib1: "x \ V \ y \ V \ a \ (x + y) = a \ x + a \ y" + and add_mult_distrib2: "x \ V \ (a + b) \ x = a \ x + b \ x" + and mult_assoc: "x \ V \ (a * b) \ x = a \ (b \ x)" + and mult_1 [simp]: "x \ V \ 1 \ x = x" + and negate_eq1: "x \ V \ - x = (- 1) \ x" + and diff_eq1: "x \ V \ y \ V \ x - y = x + - y" + +lemma (in vectorspace) negate_eq2: "x \ V \ (- 1) \ x = - x" + by (rule negate_eq1 [symmetric]) + +lemma (in vectorspace) negate_eq2a: "x \ V \ -1 \ x = - x" + by (simp add: negate_eq1) + +lemma (in vectorspace) diff_eq2: "x \ V \ y \ V \ x + - y = x - y" + by (rule diff_eq1 [symmetric]) + +lemma (in vectorspace) diff_closed [iff]: "x \ V \ y \ V \ x - y \ V" + by (simp add: diff_eq1 negate_eq1) + +lemma (in vectorspace) neg_closed [iff]: "x \ V \ - x \ V" + by (simp add: negate_eq1) + +lemma (in vectorspace) add_left_commute: + "x \ V \ y \ V \ z \ V \ x + (y + z) = y + (x + z)" +proof - + assume xyz: "x \ V" "y \ V" "z \ V" + then have "x + (y + z) = (x + y) + z" + by (simp only: add_assoc) + also from xyz have "\ = (y + x) + z" by (simp only: add_commute) + also from xyz have "\ = y + (x + z)" by (simp only: add_assoc) + finally show ?thesis . +qed + +theorems (in vectorspace) add_ac = + add_assoc add_commute add_left_commute + + +text {* The existence of the zero element of a vector space + follows from the non-emptiness of carrier set. *} + +lemma (in vectorspace) zero [iff]: "0 \ V" +proof - + from non_empty obtain x where x: "x \ V" by blast + then have "0 = x - x" by (rule diff_self [symmetric]) + also from x x have "\ \ V" by (rule diff_closed) + finally show ?thesis . +qed + +lemma (in vectorspace) add_zero_right [simp]: + "x \ V \ x + 0 = x" +proof - + assume x: "x \ V" + from this and zero have "x + 0 = 0 + x" by (rule add_commute) + also from x have "\ = x" by (rule add_zero_left) + finally show ?thesis . +qed + +lemma (in vectorspace) mult_assoc2: + "x \ V \ a \ b \ x = (a * b) \ x" + by (simp only: mult_assoc) + +lemma (in vectorspace) diff_mult_distrib1: + "x \ V \ y \ V \ a \ (x - y) = a \ x - a \ y" + by (simp add: diff_eq1 negate_eq1 add_mult_distrib1 mult_assoc2) + +lemma (in vectorspace) diff_mult_distrib2: + "x \ V \ (a - b) \ x = a \ x - (b \ x)" +proof - + assume x: "x \ V" + have " (a - b) \ x = (a + - b) \ x" + by (simp add: real_diff_def) + also from x have "\ = a \ x + (- b) \ x" + by (rule add_mult_distrib2) + also from x have "\ = a \ x + - (b \ x)" + by (simp add: negate_eq1 mult_assoc2) + also from x have "\ = a \ x - (b \ x)" + by (simp add: diff_eq1) + finally show ?thesis . +qed + +lemmas (in vectorspace) distrib = + add_mult_distrib1 add_mult_distrib2 + diff_mult_distrib1 diff_mult_distrib2 + + +text {* \medskip Further derived laws: *} + +lemma (in vectorspace) mult_zero_left [simp]: + "x \ V \ 0 \ x = 0" +proof - + assume x: "x \ V" + have "0 \ x = (1 - 1) \ x" by simp + also have "\ = (1 + - 1) \ x" by simp + also from x have "\ = 1 \ x + (- 1) \ x" + by (rule add_mult_distrib2) + also from x have "\ = x + (- 1) \ x" by simp + also from x have "\ = x + - x" by (simp add: negate_eq2a) + also from x have "\ = x - x" by (simp add: diff_eq2) + also from x have "\ = 0" by simp + finally show ?thesis . +qed + +lemma (in vectorspace) mult_zero_right [simp]: + "a \ 0 = (0::'a)" +proof - + have "a \ 0 = a \ (0 - (0::'a))" by simp + also have "\ = a \ 0 - a \ 0" + by (rule diff_mult_distrib1) simp_all + also have "\ = 0" by simp + finally show ?thesis . +qed + +lemma (in vectorspace) minus_mult_cancel [simp]: + "x \ V \ (- a) \ - x = a \ x" + by (simp add: negate_eq1 mult_assoc2) + +lemma (in vectorspace) add_minus_left_eq_diff: + "x \ V \ y \ V \ - x + y = y - x" +proof - + assume xy: "x \ V" "y \ V" + then have "- x + y = y + - x" by (simp add: add_commute) + also from xy have "\ = y - x" by (simp add: diff_eq1) + finally show ?thesis . +qed + +lemma (in vectorspace) add_minus [simp]: + "x \ V \ x + - x = 0" + by (simp add: diff_eq2) + +lemma (in vectorspace) add_minus_left [simp]: + "x \ V \ - x + x = 0" + by (simp add: diff_eq2 add_commute) + +lemma (in vectorspace) minus_minus [simp]: + "x \ V \ - (- x) = x" + by (simp add: negate_eq1 mult_assoc2) + +lemma (in vectorspace) minus_zero [simp]: + "- (0::'a) = 0" + by (simp add: negate_eq1) + +lemma (in vectorspace) minus_zero_iff [simp]: + "x \ V \ (- x = 0) = (x = 0)" +proof + assume x: "x \ V" + { + from x have "x = - (- x)" by (simp add: minus_minus) + also assume "- x = 0" + also have "- \ = 0" by (rule minus_zero) + finally show "x = 0" . + next + assume "x = 0" + then show "- x = 0" by simp + } +qed + +lemma (in vectorspace) add_minus_cancel [simp]: + "x \ V \ y \ V \ x + (- x + y) = y" + by (simp add: add_assoc [symmetric] del: add_commute) + +lemma (in vectorspace) minus_add_cancel [simp]: + "x \ V \ y \ V \ - x + (x + y) = y" + by (simp add: add_assoc [symmetric] del: add_commute) + +lemma (in vectorspace) minus_add_distrib [simp]: + "x \ V \ y \ V \ - (x + y) = - x + - y" + by (simp add: negate_eq1 add_mult_distrib1) + +lemma (in vectorspace) diff_zero [simp]: + "x \ V \ x - 0 = x" + by (simp add: diff_eq1) + +lemma (in vectorspace) diff_zero_right [simp]: + "x \ V \ 0 - x = - x" + by (simp add: diff_eq1) + +lemma (in vectorspace) add_left_cancel: + "x \ V \ y \ V \ z \ V \ (x + y = x + z) = (y = z)" +proof + assume x: "x \ V" and y: "y \ V" and z: "z \ V" + { + from y have "y = 0 + y" by simp + also from x y have "\ = (- x + x) + y" by simp + also from x y have "\ = - x + (x + y)" + by (simp add: add_assoc neg_closed) + also assume "x + y = x + z" + also from x z have "- x + (x + z) = - x + x + z" + by (simp add: add_assoc [symmetric] neg_closed) + also from x z have "\ = z" by simp + finally show "y = z" . + next + assume "y = z" + then show "x + y = x + z" by (simp only:) + } +qed + +lemma (in vectorspace) add_right_cancel: + "x \ V \ y \ V \ z \ V \ (y + x = z + x) = (y = z)" + by (simp only: add_commute add_left_cancel) + +lemma (in vectorspace) add_assoc_cong: + "x \ V \ y \ V \ x' \ V \ y' \ V \ z \ V + \ x + y = x' + y' \ x + (y + z) = x' + (y' + z)" + by (simp only: add_assoc [symmetric]) + +lemma (in vectorspace) mult_left_commute: + "x \ V \ a \ b \ x = b \ a \ x" + by (simp add: real_mult_commute mult_assoc2) + +lemma (in vectorspace) mult_zero_uniq: + "x \ V \ x \ 0 \ a \ x = 0 \ a = 0" +proof (rule classical) + assume a: "a \ 0" + assume x: "x \ V" "x \ 0" and ax: "a \ x = 0" + from x a have "x = (inverse a * a) \ x" by simp + also from `x \ V` have "\ = inverse a \ (a \ x)" by (rule mult_assoc) + also from ax have "\ = inverse a \ 0" by simp + also have "\ = 0" by simp + finally have "x = 0" . + with `x \ 0` show "a = 0" by contradiction +qed + +lemma (in vectorspace) mult_left_cancel: + "x \ V \ y \ V \ a \ 0 \ (a \ x = a \ y) = (x = y)" +proof + assume x: "x \ V" and y: "y \ V" and a: "a \ 0" + from x have "x = 1 \ x" by simp + also from a have "\ = (inverse a * a) \ x" by simp + also from x have "\ = inverse a \ (a \ x)" + by (simp only: mult_assoc) + also assume "a \ x = a \ y" + also from a y have "inverse a \ \ = y" + by (simp add: mult_assoc2) + finally show "x = y" . +next + assume "x = y" + then show "a \ x = a \ y" by (simp only:) +qed + +lemma (in vectorspace) mult_right_cancel: + "x \ V \ x \ 0 \ (a \ x = b \ x) = (a = b)" +proof + assume x: "x \ V" and neq: "x \ 0" + { + from x have "(a - b) \ x = a \ x - b \ x" + by (simp add: diff_mult_distrib2) + also assume "a \ x = b \ x" + with x have "a \ x - b \ x = 0" by simp + finally have "(a - b) \ x = 0" . + with x neq have "a - b = 0" by (rule mult_zero_uniq) + then show "a = b" by simp + next + assume "a = b" + then show "a \ x = b \ x" by (simp only:) + } +qed + +lemma (in vectorspace) eq_diff_eq: + "x \ V \ y \ V \ z \ V \ (x = z - y) = (x + y = z)" +proof + assume x: "x \ V" and y: "y \ V" and z: "z \ V" + { + assume "x = z - y" + then have "x + y = z - y + y" by simp + also from y z have "\ = z + - y + y" + by (simp add: diff_eq1) + also have "\ = z + (- y + y)" + by (rule add_assoc) (simp_all add: y z) + also from y z have "\ = z + 0" + by (simp only: add_minus_left) + also from z have "\ = z" + by (simp only: add_zero_right) + finally show "x + y = z" . + next + assume "x + y = z" + then have "z - y = (x + y) - y" by simp + also from x y have "\ = x + y + - y" + by (simp add: diff_eq1) + also have "\ = x + (y + - y)" + by (rule add_assoc) (simp_all add: x y) + also from x y have "\ = x" by simp + finally show "x = z - y" .. + } +qed + +lemma (in vectorspace) add_minus_eq_minus: + "x \ V \ y \ V \ x + y = 0 \ x = - y" +proof - + assume x: "x \ V" and y: "y \ V" + from x y have "x = (- y + y) + x" by simp + also from x y have "\ = - y + (x + y)" by (simp add: add_ac) + also assume "x + y = 0" + also from y have "- y + 0 = - y" by simp + finally show "x = - y" . +qed + +lemma (in vectorspace) add_minus_eq: + "x \ V \ y \ V \ x - y = 0 \ x = y" +proof - + assume x: "x \ V" and y: "y \ V" + assume "x - y = 0" + with x y have eq: "x + - y = 0" by (simp add: diff_eq1) + with _ _ have "x = - (- y)" + by (rule add_minus_eq_minus) (simp_all add: x y) + with x y show "x = y" by simp +qed + +lemma (in vectorspace) add_diff_swap: + "a \ V \ b \ V \ c \ V \ d \ V \ a + b = c + d + \ a - c = d - b" +proof - + assume vs: "a \ V" "b \ V" "c \ V" "d \ V" + and eq: "a + b = c + d" + then have "- c + (a + b) = - c + (c + d)" + by (simp add: add_left_cancel) + also have "\ = d" using `c \ V` `d \ V` by (rule minus_add_cancel) + finally have eq: "- c + (a + b) = d" . + from vs have "a - c = (- c + (a + b)) + - b" + by (simp add: add_ac diff_eq1) + also from vs eq have "\ = d + - b" + by (simp add: add_right_cancel) + also from vs have "\ = d - b" by (simp add: diff_eq2) + finally show "a - c = d - b" . +qed + +lemma (in vectorspace) vs_add_cancel_21: + "x \ V \ y \ V \ z \ V \ u \ V + \ (x + (y + z) = y + u) = (x + z = u)" +proof + assume vs: "x \ V" "y \ V" "z \ V" "u \ V" + { + from vs have "x + z = - y + y + (x + z)" by simp + also have "\ = - y + (y + (x + z))" + by (rule add_assoc) (simp_all add: vs) + also from vs have "y + (x + z) = x + (y + z)" + by (simp add: add_ac) + also assume "x + (y + z) = y + u" + also from vs have "- y + (y + u) = u" by simp + finally show "x + z = u" . + next + assume "x + z = u" + with vs show "x + (y + z) = y + u" + by (simp only: add_left_commute [of x]) + } +qed + +lemma (in vectorspace) add_cancel_end: + "x \ V \ y \ V \ z \ V \ (x + (y + z) = y) = (x = - z)" +proof + assume vs: "x \ V" "y \ V" "z \ V" + { + assume "x + (y + z) = y" + with vs have "(x + z) + y = 0 + y" + by (simp add: add_ac) + with vs have "x + z = 0" + by (simp only: add_right_cancel add_closed zero) + with vs show "x = - z" by (simp add: add_minus_eq_minus) + next + assume eq: "x = - z" + then have "x + (y + z) = - z + (y + z)" by simp + also have "\ = y + (- z + z)" + by (rule add_left_commute) (simp_all add: vs) + also from vs have "\ = y" by simp + finally show "x + (y + z) = y" . + } +qed + +end