# HG changeset patch # User haftmann # Date 1275485714 -7200 # Node ID 2b1c6dd4899593bd99e6e1807ea2ddbc4bca6938 # Parent 9834c21c4ba1c8ac55c51483c6e8c2d480583a4f removed dependency of Euclid on Old_Number_Theory diff -r 9834c21c4ba1 -r 2b1c6dd48995 src/HOL/Extraction/Euclid.thy --- a/src/HOL/Extraction/Euclid.thy Wed Jun 02 15:35:13 2010 +0200 +++ b/src/HOL/Extraction/Euclid.thy Wed Jun 02 15:35:14 2010 +0200 @@ -7,16 +7,43 @@ header {* Euclid's theorem *} theory Euclid -imports "~~/src/HOL/Old_Number_Theory/Factorization" Util Efficient_Nat +imports "~~/src/HOL/Number_Theory/UniqueFactorization" Util Efficient_Nat begin +lemma list_nonempty_induct [consumes 1, case_names single cons]: + assumes "xs \ []" + assumes single: "\x. P [x]" + assumes cons: "\x xs. xs \ [] \ P xs \ P (x # xs)" + shows "P xs" +using `xs \ []` proof (induct xs) + case Nil then show ?case by simp +next + case (Cons x xs) show ?case proof (cases xs) + case Nil with single show ?thesis by simp + next + case Cons then have "xs \ []" by simp + moreover with Cons.hyps have "P xs" . + ultimately show ?thesis by (rule cons) + qed +qed + text {* A constructive version of the proof of Euclid's theorem by Markus Wenzel and Freek Wiedijk \cite{Wenzel-Wiedijk-JAR2002}. *} -lemma prime_eq: "prime p = (1 < p \ (\m. m dvd p \ 1 < m \ m = p))" - apply (simp add: prime_def) +lemma factor_greater_one1: "n = m * k \ m < n \ k < n \ Suc 0 < m" + by (induct m) auto + +lemma factor_greater_one2: "n = m * k \ m < n \ k < n \ Suc 0 < k" + by (induct k) auto + +lemma prod_mn_less_k: + "(0::nat) < n ==> 0 < k ==> Suc 0 < m ==> m * n = k ==> n < k" + by (induct m) auto + +lemma prime_eq: "prime (p::nat) = (1 < p \ (\m. m dvd p \ 1 < m \ m = p))" + apply (simp add: prime_nat_def) apply (rule iffI) apply blast apply (erule conjE) @@ -33,15 +60,9 @@ apply simp done -lemma prime_eq': "prime p = (1 < p \ (\m k. p = m * k \ 1 < m \ m = p))" +lemma prime_eq': "prime (p::nat) = (1 < p \ (\m k. p = m * k \ 1 < m \ m = p))" by (simp add: prime_eq dvd_def all_simps [symmetric] del: all_simps) -lemma factor_greater_one1: "n = m * k \ m < n \ k < n \ Suc 0 < m" - by (induct m) auto - -lemma factor_greater_one2: "n = m * k \ m < n \ k < n \ Suc 0 < k" - by (induct k) auto - lemma not_prime_ex_mk: assumes n: "Suc 0 < n" shows "(\m k. Suc 0 < m \ Suc 0 < k \ m < n \ k < n \ n = m * k) \ prime n" @@ -96,7 +117,55 @@ qed qed -lemma factor_exists: "Suc 0 < n \ (\l. primel l \ prod l = n)" +lemma dvd_factorial: "0 < m \ m \ n \ m dvd fact (n::nat)" +proof (induct n rule: nat_induct) + case 0 + then show ?case by simp +next + case (Suc n) + from `m \ Suc n` show ?case + proof (rule le_SucE) + assume "m \ n" + with `0 < m` have "m dvd fact n" by (rule Suc) + then have "m dvd (fact n * Suc n)" by (rule dvd_mult2) + then show ?thesis by (simp add: mult_commute) + next + assume "m = Suc n" + then have "m dvd (fact n * Suc n)" + by (auto intro: dvdI simp: mult_ac) + then show ?thesis by (simp add: mult_commute) + qed +qed + +lemma dvd_prod [iff]: "n dvd (PROD m\nat:#multiset_of (n # ns). m)" + by (simp add: msetprod_Un msetprod_singleton) + +abbreviation (input) "primel ps \ (\(p::nat)\set ps. prime p)" + +lemma prime_primel: "prime n \ primel [n]" + by simp + +lemma split_primel: + assumes "primel ms" and "primel ns" + shows "\qs. primel qs \ (PROD m\nat:#multiset_of qs. m) = + (PROD m\nat:#multiset_of ms. m) * (PROD m\nat:#multiset_of ns. m)" (is "\qs. ?P qs \ ?Q qs") +proof - + from assms have "primel (ms @ ns)" + unfolding set_append ball_Un by iprover + moreover from assms have "(PROD m\nat:#multiset_of (ms @ ns). m) = + (PROD m\nat:#multiset_of ms. m) * (PROD m\nat:#multiset_of ns. m)" + by (simp add: msetprod_Un) + ultimately have "?P (ms @ ns) \ ?Q (ms @ ns)" .. + then show ?thesis .. +qed + +lemma primel_nempty_g_one: + assumes "primel ps" and "ps \ []" + shows "Suc 0 < (PROD m\nat:#multiset_of ps. m)" + using `ps \ []` `primel ps` unfolding One_nat_def [symmetric] by (induct ps rule: list_nonempty_induct) + (simp_all add: msetprod_singleton msetprod_Un prime_gt_1_nat less_1_mult del: One_nat_def) + +lemma factor_exists: "Suc 0 < n \ (\l. primel l \ (PROD m\nat:#multiset_of l. m) = n)" proof (induct n rule: nat_wf_ind) case (1 n) from `Suc 0 < n` @@ -107,51 +176,22 @@ assume "\m k. Suc 0 < m \ Suc 0 < k \ m < n \ k < n \ n = m * k" then obtain m k where m: "Suc 0 < m" and k: "Suc 0 < k" and mn: "m < n" and kn: "k < n" and nmk: "n = m * k" by iprover - from mn and m have "\l. primel l \ prod l = m" by (rule 1) - then obtain l1 where primel_l1: "primel l1" and prod_l1_m: "prod l1 = m" + from mn and m have "\l. primel l \ (PROD m\nat:#multiset_of l. m) = m" by (rule 1) + then obtain l1 where primel_l1: "primel l1" and prod_l1_m: "(PROD m\nat:#multiset_of l1. m) = m" by iprover - from kn and k have "\l. primel l \ prod l = k" by (rule 1) - then obtain l2 where primel_l2: "primel l2" and prod_l2_k: "prod l2 = k" + from kn and k have "\l. primel l \ (PROD m\nat:#multiset_of l. m) = k" by (rule 1) + then obtain l2 where primel_l2: "primel l2" and prod_l2_k: "(PROD m\nat:#multiset_of l2. m) = k" by iprover from primel_l1 primel_l2 - have "\l. primel l \ prod l = prod l1 * prod l2" + have "\l. primel l \ (PROD m\nat:#multiset_of l. m) = + (PROD m\nat:#multiset_of l1. m) * (PROD m\nat:#multiset_of l2. m)" by (rule split_primel) with prod_l1_m prod_l2_k nmk show ?thesis by simp next - assume "prime n" - hence "primel [n] \ prod [n] = n" by (rule prime_primel) - thus ?thesis .. - qed -qed - -lemma dvd_prod [iff]: "n dvd prod (n # ns)" - by simp - -primrec fact :: "nat \ nat" ("(_!)" [1000] 999) -where - "0! = 1" - | "(Suc n)! = n! * Suc n" - -lemma fact_greater_0 [iff]: "0 < n!" - by (induct n) simp_all - -lemma dvd_factorial: "0 < m \ m \ n \ m dvd n!" -proof (induct n) - case 0 - then show ?case by simp -next - case (Suc n) - from `m \ Suc n` show ?case - proof (rule le_SucE) - assume "m \ n" - with `0 < m` have "m dvd n!" by (rule Suc) - then have "m dvd (n! * Suc n)" by (rule dvd_mult2) - then show ?thesis by simp - next - assume "m = Suc n" - then have "m dvd (n! * Suc n)" - by (auto intro: dvdI simp: mult_ac) - then show ?thesis by simp + assume "prime n" then have "primel [n]" by (rule prime_primel) + moreover have "(PROD m\nat:#multiset_of [n]. m) = n" by (simp add: msetprod_singleton) + ultimately have "primel [n] \ (PROD m\nat:#multiset_of [n]. m) = n" .. + then show ?thesis .. qed qed @@ -160,13 +200,14 @@ shows "\p. prime p \ p dvd n" proof - from N obtain l where primel_l: "primel l" - and prod_l: "n = prod l" using factor_exists + and prod_l: "n = (PROD m\nat:#multiset_of l. m)" using factor_exists by simp iprover - from prems have "l \ []" - by (auto simp add: primel_nempty_g_one) + with N have "l \ []" + by (auto simp add: primel_nempty_g_one msetprod_empty) then obtain x xs where l: "l = x # xs" by (cases l) simp - from primel_l l have "prime x" by (simp add: primel_hd_tl) + then have "x \ set l" by (simp only: insert_def set.simps) (iprover intro: UnI1 CollectI) + with primel_l have "prime x" .. moreover from primel_l l prod_l have "x dvd n" by (simp only: dvd_prod) ultimately show ?thesis by iprover @@ -176,21 +217,21 @@ Euclid's theorem: there are infinitely many primes. *} -lemma Euclid: "\p. prime p \ n < p" +lemma Euclid: "\p::nat. prime p \ n < p" proof - - let ?k = "n! + 1" - have "1 < n! + 1" by simp + let ?k = "fact n + 1" + have "1 < fact n + 1" by simp then obtain p where prime: "prime p" and dvd: "p dvd ?k" using prime_factor_exists by iprover have "n < p" proof - have "\ p \ n" proof assume pn: "p \ n" - from `prime p` have "0 < p" by (rule prime_g_zero) - then have "p dvd n!" using pn by (rule dvd_factorial) - with dvd have "p dvd ?k - n!" by (rule dvd_diff_nat) + from `prime p` have "0 < p" by (rule prime_gt_0_nat) + then have "p dvd fact n" using pn by (rule dvd_factorial) + with dvd have "p dvd ?k - fact n" by (rule dvd_diff_nat) then have "p dvd 1" by simp - with prime show False using prime_nd_one by auto + with prime show False by auto qed then show ?thesis by simp qed @@ -224,29 +265,26 @@ end +primrec iterate :: "nat \ ('a \ 'a) \ 'a \ 'a list" where + "iterate 0 f x = []" + | "iterate (Suc n) f x = (let y = f x in y # iterate n f y)" + +lemma "factor_exists 1007 = [53, 19]" by eval +lemma "factor_exists 567 = [7, 3, 3, 3, 3]" by eval +lemma "factor_exists 345 = [23, 5, 3]" by eval +lemma "factor_exists 999 = [37, 3, 3, 3]" by eval +lemma "factor_exists 876 = [73, 3, 2, 2]" by eval + +lemma "iterate 4 Euclid 0 = [2, 3, 7, 71]" by eval + consts_code default ("(error \"default\")") lemma "factor_exists 1007 = [53, 19]" by evaluation -lemma "factor_exists 1007 = [53, 19]" by eval - lemma "factor_exists 567 = [7, 3, 3, 3, 3]" by evaluation -lemma "factor_exists 567 = [7, 3, 3, 3, 3]" by eval - lemma "factor_exists 345 = [23, 5, 3]" by evaluation -lemma "factor_exists 345 = [23, 5, 3]" by eval - lemma "factor_exists 999 = [37, 3, 3, 3]" by evaluation -lemma "factor_exists 999 = [37, 3, 3, 3]" by eval - lemma "factor_exists 876 = [73, 3, 2, 2]" by evaluation -lemma "factor_exists 876 = [73, 3, 2, 2]" by eval - -primrec iterate :: "nat \ ('a \ 'a) \ 'a \ 'a list" where - "iterate 0 f x = []" - | "iterate (Suc n) f x = (let y = f x in y # iterate n f y)" - lemma "iterate 4 Euclid 0 = [2, 3, 7, 71]" by evaluation -lemma "iterate 4 Euclid 0 = [2, 3, 7, 71]" by eval end diff -r 9834c21c4ba1 -r 2b1c6dd48995 src/HOL/Extraction/ROOT.ML --- a/src/HOL/Extraction/ROOT.ML Wed Jun 02 15:35:13 2010 +0200 +++ b/src/HOL/Extraction/ROOT.ML Wed Jun 02 15:35:14 2010 +0200 @@ -2,5 +2,5 @@ Proofterm.proofs := 2; -no_document use_thys ["Efficient_Nat", "~~/src/HOL/Old_Number_Theory/Factorization"]; +no_document use_thys ["Efficient_Nat", "~~/src/HOL/Number_Theory/UniqueFactorization"]; use_thys ["Greatest_Common_Divisor", "Warshall", "Higman", "Pigeonhole", "Euclid"];