doc-src/IsarAdvanced/Codegen/Thy/examples/lexicographic.ML
author wenzelm
Fri, 17 Nov 2006 02:20:03 +0100
changeset 21404 eb85850d3eb7
parent 21190 08ec81dfc7fb
child 21452 f825e0b4d566
permissions -rw-r--r--
more robust syntax for definition/abbreviation/notation;
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structure ROOT = 
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struct
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structure Code_Generator = 
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struct
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type 'a eq = {eq_ : 'a -> 'a -> bool};
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fun eq (A_:'a eq) = #eq_ A_;
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end; (*struct Code_Generator*)
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structure Product_Type = 
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struct
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fun eq_prod (A_:'a Code_Generator.eq) (B_:'b Code_Generator.eq) (x1, y1)
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  (x2, y2) = Code_Generator.eq A_ x1 x2 andalso Code_Generator.eq B_ y1 y2;
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end; (*struct Product_Type*)
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structure Orderings = 
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struct
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type 'a ord = {less_eq_ : 'a -> 'a -> bool, less_ : 'a -> 'a -> bool};
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fun less_eq (A_:'a ord) = #less_eq_ A_;
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fun less (A_:'a ord) = #less_ A_;
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end; (*struct Orderings*)
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structure Codegen = 
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struct
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fun less_prod (B_:'b Code_Generator.eq * 'b Orderings.ord)
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  (C_:'c Code_Generator.eq * 'c Orderings.ord) p1 p2 =
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  let
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    val (x1a, y1a) = p1;
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    val (x2a, y2a) = p2;
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  in
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    Orderings.less (#2 B_) x1a x2a orelse
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      Code_Generator.eq (#1 B_) x1a x2a andalso
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        Orderings.less (#2 C_) y1a y2a
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  end;
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fun less_eq_prod (B_:'b Code_Generator.eq * 'b Orderings.ord)
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  (C_:'c Code_Generator.eq * 'c Orderings.ord) p1 p2 =
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  less_prod ((#1 B_), (#2 B_)) ((#1 C_), (#2 C_)) p1 p2 orelse
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    Product_Type.eq_prod (#1 B_) (#1 C_) p1 p2;
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end; (*struct Codegen*)
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end; (*struct ROOT*)