src/Tools/Nbe/Nbe.thy
author wenzelm
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(*  ID:         $Id$
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    Authors:    Klaus Aehlig, Tobias Nipkow
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*)
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header {* Alternativ implementation of "normalization by evaluation" for HOL, including test examples *}
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theory Nbe
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imports Main
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uses
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  "~~/src/Tools/Nbe/nbe_eval.ML"
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  "~~/src/Tools/Nbe/nbe_package.ML"
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begin
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lemma [code inline]: "If b f g = bool_case f g b" by auto
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lemma [code func]: "null xs \<longleftrightarrow> (case xs of [] \<Rightarrow> True | _ \<Rightarrow> False)"
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by (cases xs) auto
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ML {* reset Toplevel.debug *}
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setup Nbe_Package.setup
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method_setup normalization = {*
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  Method.no_args (Method.SIMPLE_METHOD'
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    (CONVERSION (ObjectLogic.judgment_conv Nbe_Package.normalization_conv)
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      THEN' resolve_tac [TrueI, refl]))
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*} "solve goal by normalization"
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text {* lazy @{const If} *}
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definition
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  if_delayed :: "bool \<Rightarrow> (bool \<Rightarrow> 'a) \<Rightarrow> (bool \<Rightarrow> 'a) \<Rightarrow> 'a" where
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  [code func del]: "if_delayed b f g = (if b then f True else g False)"
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lemma [code func]:
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  shows "if_delayed True f g = f True"
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    and "if_delayed False f g = g False"
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  unfolding if_delayed_def by simp_all
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lemma [normal pre, symmetric, normal post]:
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  "(if b then x else y) = if_delayed b (\<lambda>_. x) (\<lambda>_. y)"
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  unfolding if_delayed_def ..
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hide (open) const if_delayed
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lemma "True"
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by normalization
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lemma "x = x" by normalization
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lemma "True \<or> False"
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by normalization
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lemma "True \<or> p" by normalization
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lemma "p \<longrightarrow> True"
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by normalization
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declare disj_assoc [code func]
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lemma "((P | Q) | R) = (P | (Q | R))" by normalization
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declare disj_assoc [code func del]
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lemma "0 + (n::nat) = n" by normalization
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lemma "0 + Suc n = Suc n" by normalization
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lemma "Suc n + Suc m = n + Suc (Suc m)" by normalization
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lemma "~((0::nat) < (0::nat))" by normalization
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datatype n = Z | S n
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consts
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  add :: "n \<Rightarrow> n \<Rightarrow> n"
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  add2 :: "n \<Rightarrow> n \<Rightarrow> n"
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  mul :: "n \<Rightarrow> n \<Rightarrow> n"
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  mul2 :: "n \<Rightarrow> n \<Rightarrow> n"
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  exp :: "n \<Rightarrow> n \<Rightarrow> n"
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primrec
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  "add Z = id"
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  "add (S m) = S o add m"
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primrec
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  "add2 Z n = n"
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  "add2 (S m) n = S(add2 m n)"
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lemma [code]: "add2 (add2 n m) k = add2 n (add2 m k)"
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  by(induct n) auto
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lemma [code]: "add2 n (S m) =  S (add2 n m)"
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  by(induct n) auto
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lemma [code]: "add2 n Z = n"
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  by(induct n) auto
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lemma "add2 (add2 n m) k = add2 n (add2 m k)" by normalization
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lemma "add2 (add2 (S n) (S m)) (S k) = S(S(S(add2 n (add2 m k))))" by normalization
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lemma "add2 (add2 (S n) (add2 (S m) Z)) (S k) = S(S(S(add2 n (add2 m k))))" by normalization
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primrec
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  "mul Z = (%n. Z)"
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  "mul (S m) = (%n. add (mul m n) n)"
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primrec
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  "mul2 Z n = Z"
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  "mul2 (S m) n = add2 n (mul2 m n)"
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primrec
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  "exp m Z = S Z"
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  "exp m (S n) = mul (exp m n) m"
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lemma "mul2 (S(S(S(S(S Z))))) (S(S(S Z))) = S(S(S(S(S(S(S(S(S(S(S(S(S(S(S Z))))))))))))))" by normalization
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lemma "mul (S(S(S(S(S Z))))) (S(S(S Z))) = S(S(S(S(S(S(S(S(S(S(S(S(S(S(S Z))))))))))))))" by normalization
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lemma "exp (S(S Z)) (S(S(S(S Z)))) = exp (S(S(S(S Z)))) (S(S Z))" by normalization
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normal_form "f"
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normal_form "f x"
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normal_form "(f o g) x"
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normal_form "(f o id) x"
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normal_form "id"
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normal_form "\<lambda>x. x"
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lemma "[] @ [] = []" by normalization
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lemma "[] @ xs = xs" by normalization
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normal_form "[a, b, c] @ xs = a # b # c # xs"
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normal_form "map f [x,y,z::'x] = [f x, f y, f z]"
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normal_form "map (%f. f True) [id, g, Not] = [True, g True, False]"
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normal_form "map (%f. f True) ([id, g, Not] @ fs) = [True, g True, False] @ map (%f. f True) fs"
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normal_form "rev [a, b, c] = [c, b, a]"
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normal_form "rev (a#b#cs) = rev cs @ [b, a]"
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normal_form "map (%F. F [a,b,c::'x]) (map map [f,g,h])"
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normal_form "map (%F. F ([a,b,c] @ ds)) (map map ([f,g,h]@fs))"
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normal_form "map (%F. F [Z,S Z,S(S Z)]) (map map [S,add (S Z),mul (S(S Z)),id])"
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normal_form "filter (%x. x) ([True,False,x]@xs)"
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normal_form "filter Not ([True,False,x]@xs)"
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normal_form "[x,y,z] @ [a,b,c] = [x, y, z, a, b ,c]"
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lemma "(2::int) + 3 - 1 + (- k) * 2 = 4 + - k * 2" by normalization
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lemma "(-4::int) * 2 = -8" by normalization
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lemma "abs ((-4::int) + 2 * 1) = 2" by normalization
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lemma "(2::int) + 3 = 5" by normalization
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lemma "(2::int) + 3 * (- 4) * (- 1) = 14" by normalization
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lemma "(2::int) + 3 * (- 4) * 1 + 0 = -10" by normalization
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lemma "(2::int) < 3" by normalization
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lemma "(2::int) <= 3" by normalization
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lemma "abs ((-4::int) + 2 * 1) = 2" by normalization
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lemma "4 - 42 * abs (3 + (-7\<Colon>int)) = -164" by normalization
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lemma "(if (0\<Colon>nat) \<le> (x\<Colon>nat) then 0\<Colon>nat else x) = 0" by normalization
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lemma "last [a, b, c] = c"
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  by normalization
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lemma "last ([a, b, c] @ xs) = (if null xs then c else last xs)"
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  by normalization
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lemma "(%((x,y),(u,v)). add (add x y) (add u v)) ((Z,Z),(Z,Z)) = Z" by normalization
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lemma "split (%x y. x) (a, b) = a" by normalization
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lemma "case Z of Z \<Rightarrow> True | S x \<Rightarrow> False" by normalization
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lemma "(let ((x,y),(u,v)) = ((Z,Z),(Z,Z)) in add (add x y) (add u v)) = Z" 
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by normalization
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normal_form "map (%x. case x of None \<Rightarrow> False | Some y \<Rightarrow> True) [None, Some ()]"
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normal_form "case xs of [] \<Rightarrow> True | x#xs \<Rightarrow> False"
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normal_form "map (%x. case x of None \<Rightarrow> False | Some y \<Rightarrow> True) xs"
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normal_form "let x = y::'x in [x,x]"
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normal_form "Let y (%x. [x,x])"
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normal_form "case n of Z \<Rightarrow> True | S x \<Rightarrow> False"
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normal_form "(%(x,y). add x y) (S z,S z)"
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normal_form "(%(xs, ys). xs @ ys) ([a, b, c], [d, e, f]) = [a, b, c, d, e, f]"
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normal_form "map (%x. case x of None \<Rightarrow> False | Some y \<Rightarrow> True) [None, Some ()] = [False, True]"
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normal_form "Suc 0 \<in> set ms"
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(* Church numerals: *)
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normal_form "(%m n f x. m f (n f x)) (%f x. f(f(f(x)))) (%f x. f(f(f(x))))"
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normal_form "(%m n f x. m (n f) x) (%f x. f(f(f(x)))) (%f x. f(f(f(x))))"
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normal_form "(%m n. n m) (%f x. f(f(f(x)))) (%f x. f(f(f(x))))"
23998
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lemma "nat 4 = Suc (Suc (Suc (Suc 0)))" by normalization
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lemma "4 = Suc (Suc (Suc (Suc 0)))" by normalization
23999
393dd64d0d04 *** empty log message ***
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lemma "null [x] = False" by normalization