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| Tue, 11 Jun 2013 18:50:09 -0400 | |
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| 46879 | 1  | 
(* Title: HOL/Quickcheck_Examples/Quickcheck_Narrowing_Examples.thy  | 
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Author: Lukas Bulwahn  | 
3  | 
Copyright 2011 TU Muenchen  | 
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*)  | 
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header {* Examples for narrowing-based testing  *}
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theory Quickcheck_Narrowing_Examples  | 
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imports Main  | 
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begin  | 
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12  | 
declare [[quickcheck_timeout = 3600]]  | 
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13  | 
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14  | 
subsection {* Minimalistic examples *}
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16  | 
lemma  | 
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"x = y"  | 
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quickcheck[tester = narrowing, finite_types = false, default_type = int, expect = counterexample]  | 
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oops  | 
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parents: 
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21  | 
lemma  | 
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"x = y"  | 
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quickcheck[tester = narrowing, finite_types = false, default_type = nat, expect = counterexample]  | 
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oops  | 
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subsection {* Simple examples with existentials *}
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28  | 
lemma  | 
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"\<exists> y :: nat. \<forall> x. x = y"  | 
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quickcheck[tester = narrowing, finite_types = false, expect = counterexample]  | 
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oops  | 
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(*  | 
33  | 
lemma  | 
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"\<exists> y :: int. \<forall> x. x = y"  | 
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quickcheck[tester = narrowing, size = 2]  | 
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oops  | 
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*)  | 
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lemma  | 
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"x > 1 --> (\<exists>y :: nat. x < y & y <= 1)"  | 
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quickcheck[tester = narrowing, finite_types = false, expect = counterexample]  | 
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oops  | 
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lemma  | 
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"x > 2 --> (\<exists>y :: nat. x < y & y <= 2)"  | 
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quickcheck[tester = narrowing, finite_types = false, size = 10]  | 
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oops  | 
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lemma  | 
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"\<forall> x. \<exists> y :: nat. x > 3 --> (y < x & y > 3)"  | 
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quickcheck[tester = narrowing, finite_types = false, size = 7]  | 
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oops  | 
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text {* A false conjecture derived from an partial copy-n-paste of @{thm not_distinct_decomp} *}
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lemma  | 
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"~ distinct ws ==> EX xs ys zs y. ws = xs @ [y] @ ys @ [y]"  | 
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quickcheck[tester = narrowing, finite_types = false, default_type = nat, expect = counterexample]  | 
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oops  | 
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text {* A false conjecture derived from theorems @{thm split_list_first} and @{thm split_list_last} *}  
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lemma  | 
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"x : set xs ==> EX ys zs. xs = ys @ x # zs & x ~: set zs & x ~: set ys"  | 
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quickcheck[tester = narrowing, finite_types = false, default_type = nat, expect = counterexample]  | 
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oops  | 
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text {* A false conjecture derived from @{thm map_eq_Cons_conv} with a typo *}
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lemma  | 
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"(map f xs = y # ys) = (EX z zs. xs = z' # zs & f z = y & map f zs = ys)"  | 
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quickcheck[tester = narrowing, finite_types = false, default_type = nat, expect = counterexample]  | 
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oops  | 
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lemma "a # xs = ys @ [a] ==> EX zs. xs = zs @ [a] & ys = a#zs"  | 
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quickcheck[narrowing, expect = counterexample]  | 
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quickcheck[exhaustive, random, expect = no_counterexample]  | 
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oops  | 
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75  | 
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76  | 
subsection {* Simple list examples *}
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lemma "rev xs = xs"  | 
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quickcheck[tester = narrowing, finite_types = false, default_type = nat, expect = counterexample]  | 
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parents: 
41963 
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oops  | 
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2da02764d523
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bulwahn 
parents: 
41963 
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bulwahn 
parents: 
41963 
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lemma "rev xs = xs"  | 
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quickcheck[tester = narrowing, finite_types = false, default_type = int, expect = counterexample]  | 
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bulwahn 
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42020 
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oops  | 
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47108
 
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merged fork with new numeral representation (see NEWS)
 
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42020 
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lemma "rev xs = xs"  | 
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quickcheck[tester = narrowing, finite_types = true, expect = counterexample]  | 
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oops  | 
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parents: 
46879 
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90  | 
subsection {* Simple examples with functions *}
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lemma "map f xs = map g xs"  | 
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quickcheck[tester = narrowing, finite_types = false, expect = counterexample]  | 
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bulwahn 
parents: 
41963 
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94  | 
oops  | 
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bulwahn 
parents: 
41963 
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lemma "map f xs = map f ys ==> xs = ys"  | 
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quickcheck[tester = narrowing, finite_types = false, expect = counterexample]  | 
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oops  | 
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lemma  | 
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"list_all2 P (rev xs) (rev ys) = list_all2 P xs (rev ys)"  | 
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quickcheck[tester = narrowing, finite_types = false, expect = counterexample]  | 
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oops  | 
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lemma "map f xs = F f xs"  | 
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quickcheck[tester = narrowing, finite_types = false, expect = counterexample]  | 
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107  | 
oops  | 
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108  | 
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lemma "map f xs = F f xs"  | 
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quickcheck[tester = narrowing, finite_types = false, expect = counterexample]  | 
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oops  | 
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(* requires some work...*)  | 
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(*  | 
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115  | 
lemma "R O S = S O R"  | 
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quickcheck[tester = narrowing, size = 2]  | 
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oops  | 
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*)  | 
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119  | 
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120  | 
subsection {* Simple examples with inductive predicates *}
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inductive even where  | 
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"even 0" |  | 
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"even n ==> even (Suc (Suc n))"  | 
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126  | 
code_pred even .  | 
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128  | 
lemma "even (n - 2) ==> even n"  | 
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quickcheck[narrowing, expect = counterexample]  | 
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oops  | 
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132  | 
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subsection {* AVL Trees *}
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datatype 'a tree = ET | MKT 'a "'a tree" "'a tree" nat  | 
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primrec set_of :: "'a tree \<Rightarrow> 'a set"  | 
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where  | 
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"set_of ET = {}" |
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"set_of (MKT n l r h) = insert n (set_of l \<union> set_of r)"  | 
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primrec height :: "'a tree \<Rightarrow> nat"  | 
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where  | 
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"height ET = 0" |  | 
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"height (MKT x l r h) = max (height l) (height r) + 1"  | 
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primrec avl :: "'a tree \<Rightarrow> bool"  | 
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where  | 
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"avl ET = True" |  | 
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"avl (MKT x l r h) =  | 
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((height l = height r \<or> height l = 1+height r \<or> height r = 1+height l) \<and>  | 
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h = max (height l) (height r) + 1 \<and> avl l \<and> avl r)"  | 
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primrec is_ord :: "('a::order) tree \<Rightarrow> bool"
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where  | 
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"is_ord ET = True" |  | 
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"is_ord (MKT n l r h) =  | 
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((\<forall>n' \<in> set_of l. n' < n) \<and> (\<forall>n' \<in> set_of r. n < n') \<and> is_ord l \<and> is_ord r)"  | 
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primrec is_in :: "('a::order) \<Rightarrow> 'a tree \<Rightarrow> bool"
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where  | 
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"is_in k ET = False" |  | 
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"is_in k (MKT n l r h) = (if k = n then True else  | 
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if k < n then (is_in k l)  | 
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else (is_in k r))"  | 
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primrec ht :: "'a tree \<Rightarrow> nat"  | 
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where  | 
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"ht ET = 0" |  | 
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"ht (MKT x l r h) = h"  | 
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definition  | 
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mkt :: "'a \<Rightarrow> 'a tree \<Rightarrow> 'a tree \<Rightarrow> 'a tree" where  | 
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"mkt x l r = MKT x l r (max (ht l) (ht r) + 1)"  | 
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(* replaced MKT lrn lrl lrr by MKT lrr lrl *)  | 
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fun l_bal where  | 
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"l_bal(n, MKT ln ll lr h, r) =  | 
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179  | 
(if ht ll < ht lr  | 
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180  | 
then case lr of ET \<Rightarrow> ET (* impossible *)  | 
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181  | 
| MKT lrn lrr lrl lrh \<Rightarrow>  | 
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182  | 
mkt lrn (mkt ln ll lrl) (mkt n lrr r)  | 
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183  | 
else mkt ln ll (mkt n lr r))"  | 
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185  | 
fun r_bal where  | 
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186  | 
"r_bal(n, l, MKT rn rl rr h) =  | 
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187  | 
(if ht rl > ht rr  | 
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188  | 
then case rl of ET \<Rightarrow> ET (* impossible *)  | 
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189  | 
| MKT rln rll rlr h \<Rightarrow> mkt rln (mkt n l rll) (mkt rn rlr rr)  | 
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190  | 
else mkt rn (mkt n l rl) rr)"  | 
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192  | 
primrec insrt :: "'a::order \<Rightarrow> 'a tree \<Rightarrow> 'a tree"  | 
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193  | 
where  | 
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194  | 
"insrt x ET = MKT x ET ET 1" |  | 
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195  | 
"insrt x (MKT n l r h) =  | 
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196  | 
(if x=n  | 
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197  | 
then MKT n l r h  | 
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198  | 
else if x<n  | 
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199  | 
then let l' = insrt x l; hl' = ht l'; hr = ht r  | 
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200  | 
in if hl' = 2+hr then l_bal(n,l',r)  | 
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else MKT n l' r (1 + max hl' hr)  | 
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else let r' = insrt x r; hl = ht l; hr' = ht r'  | 
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203  | 
in if hr' = 2+hl then r_bal(n,l,r')  | 
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204  | 
else MKT n l r' (1 + max hl hr'))"  | 
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206  | 
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207  | 
subsubsection {* Necessary setup for code generation *}
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208  | 
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209  | 
primrec set_of'  | 
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210  | 
where  | 
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211  | 
"set_of' ET = []"  | 
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212  | 
| "set_of' (MKT n l r h) = n # (set_of' l @ set_of' r)"  | 
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213  | 
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214  | 
lemma set_of':  | 
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215  | 
"set (set_of' t) = set_of t"  | 
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by (induct t) auto  | 
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218  | 
lemma is_ord_mkt:  | 
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219  | 
"is_ord (MKT n l r h) = ((ALL n': set (set_of' l). n' < n) & (ALL n': set (set_of' r). n < n') & is_ord l & is_ord r)"  | 
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220  | 
by (simp add: set_of')  | 
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221  | 
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222  | 
declare is_ord.simps(1)[code] is_ord_mkt[code]  | 
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223  | 
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224  | 
subsubsection {* Invalid Lemma due to typo in lbal *}
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226  | 
lemma is_ord_l_bal:  | 
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"\<lbrakk> is_ord(MKT (x :: nat) l r h); height l = height r + 2 \<rbrakk> \<Longrightarrow> is_ord(l_bal(x,l,r))"  | 
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quickcheck[tester = narrowing, finite_types = false, default_type = nat, size = 6, expect = counterexample]  | 
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231  | 
subsection {* Examples with hd and last *}
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232  | 
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233  | 
lemma  | 
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234  | 
"hd (xs @ ys) = hd ys"  | 
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quickcheck[narrowing, expect = counterexample]  | 
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237  | 
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238  | 
lemma  | 
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"last(xs @ ys) = last xs"  | 
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quickcheck[narrowing, expect = counterexample]  | 
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242  | 
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243  | 
subsection {* Examples with underspecified/partial functions *}
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244  | 
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245  | 
lemma  | 
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"xs = [] ==> hd xs \<noteq> x"  | 
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quickcheck[narrowing, expect = no_counterexample]  | 
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249  | 
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250  | 
lemma  | 
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251  | 
"xs = [] ==> hd xs = x"  | 
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quickcheck[narrowing, expect = no_counterexample]  | 
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254  | 
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255  | 
lemma "xs = [] ==> hd xs = x ==> x = y"  | 
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quickcheck[narrowing, expect = no_counterexample]  | 
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259  | 
lemma  | 
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"hd (xs @ ys) = (if xs = [] then hd ys else hd xs)"  | 
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quickcheck[narrowing, expect = no_counterexample]  | 
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lemma  | 
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"hd (map f xs) = f (hd xs)"  | 
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quickcheck[narrowing, expect = no_counterexample]  | 
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