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(*  Title:      Substitution.thy
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    ID:         $Id$
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    Author:     Ole Rasmussen
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    Copyright   1995  University of Cambridge
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    Logic Image: ZF
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*)
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Substitution = Redex +
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consts
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  lift_aux  :: i=> i
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  lift          :: i=> i
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  subst_aux :: i=> i
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  "'/"          :: [i,i]=>i  (infixl 70)  (*subst*)
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constdefs
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  lift_rec      :: [i,i]=> i
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    "lift_rec(r,k) == lift_aux(r)`k"
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  subst_rec     :: [i,i,i]=> i	(**NOTE THE ARGUMENT ORDER BELOW**)
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    "subst_rec(u,r,k) == subst_aux(r)`u`k"
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translations
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  "lift(r)"  == "lift_rec(r,0)"
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  "u/v"      == "subst_rec(u,v,0)"
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(** The clumsy _aux functions are required because other arguments vary
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    in the recursive calls ***)
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primrec
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  "lift_aux(Var(i)) = (lam k:nat. if i<k then Var(i) else Var(succ(i)))"
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  "lift_aux(Fun(t)) = (lam k:nat. Fun(lift_aux(t) ` succ(k)))"
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  "lift_aux(App(b,f,a)) = (lam k:nat. App(b, lift_aux(f)`k, lift_aux(a)`k))"
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primrec
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  "subst_aux(Var(i)) =
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     (lam r:redexes. lam k:nat. if k<i then Var(i #- 1) 
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				else if k=i then r else Var(i))"
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  "subst_aux(Fun(t)) =
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     (lam r:redexes. lam k:nat. Fun(subst_rec(lift(r), t, succ(k))))"
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  "subst_aux(App(b,f,a)) = 
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     (lam r:redexes. lam k:nat. App(b, subst_rec(r,f,k), subst_rec(r,a,k)))"
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end
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