src/HOL/Library/Ring_and_Field.thy
author wenzelm
Fri, 08 Mar 2002 16:24:06 +0100
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child 13438 527811f00c56
permissions -rw-r--r--
tuned;
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(*  Title:      HOL/Library/Ring_and_Field.thy
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    ID:         $Id$
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    Author:     Gertrud Bauer and Markus Wenzel, TU Muenchen
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    License:    GPL (GNU GENERAL PUBLIC LICENSE)
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*)
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header {*
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  \title{Ring and field structures}
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  \author{Gertrud Bauer and Markus Wenzel}
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*}
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theory Ring_and_Field = Main: 
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subsection {* Abstract algebraic structures *}
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axclass ring \<subseteq> zero, one, plus, minus, times
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  add_assoc: "(a + b) + c = a + (b + c)"
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  add_commute: "a + b = b + a"
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  left_zero [simp]: "0 + a = a"
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  left_minus [simp]: "- a + a = 0"
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  diff_minus: "a - b = a + (-b)"
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  mult_assoc: "(a * b) * c = a * (b * c)"
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  mult_commute: "a * b = b * a"
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  left_one [simp]: "1 * a = a"
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  left_distrib: "(a + b) * c = a * c + b * c"
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axclass ordered_ring \<subseteq> ring, linorder
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  add_left_mono: "a \<le> b ==> c + a \<le> c + b"
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  mult_strict_left_mono: "a < b ==> 0 < c ==> c * a < c * b"
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  abs_if: "\<bar>a\<bar> = (if a < 0 then -a else a)"
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axclass field \<subseteq> ring, inverse
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  left_inverse [simp]: "a \<noteq> 0 ==> inverse a * a = 1"
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  divide_inverse: "b \<noteq> 0 ==> a / b = a * inverse b"
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axclass ordered_field \<subseteq> ordered_ring, field
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axclass division_by_zero \<subseteq> zero, inverse
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  inverse_zero: "inverse 0 = 0"
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  divide_zero: "a / 0 = 0"
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subsection {* Derived rules *}
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subsubsection {* Derived rules for addition *}
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lemma right_zero [simp]: "a + 0 = (a::'a::ring)" 
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proof -
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  have "a + 0 = 0 + a" by (simp only: add_commute)
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  also have "... = a" by simp
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  finally show ?thesis .
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qed
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lemma add_left_commute: "a + (b + c) = b + (a + (c::'a::ring))"
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proof -
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  have "a + (b + c) = (a + b) + c" by (simp only: add_assoc)
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  also have "... = (b + a) + c" by (simp only: add_commute)
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  finally show ?thesis by (simp only: add_assoc) 
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qed
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theorems ring_add_ac = add_assoc add_commute add_left_commute
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lemma right_minus [simp]: "a + -(a::'a::ring) = 0" 
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proof -
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  have "a + -a = -a + a" by (simp add: ring_add_ac)
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  also have "... = 0" by simp
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  finally show ?thesis .
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qed
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lemma right_minus_eq: "(a - b = 0) = (a = (b::'a::ring))"
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proof 
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  have "a = a - b + b" by (simp add: diff_minus ring_add_ac)
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  also assume "a - b = 0"
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  finally show "a = b" by simp
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next
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  assume "a = b"
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  thus "a - b = 0" by (simp add: diff_minus)
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qed
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lemma diff_self [simp]: "a - (a::'a::ring) = 0"
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  by (simp add: diff_minus)
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subsubsection {* Derived rules for multiplication *}
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lemma right_one [simp]: "a = a * (1::'a::field)"
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proof -
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  have "a = 1 * a" by simp
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  also have "... = a * 1" by (simp add: mult_commute)
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  finally show ?thesis .
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qed
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lemma mult_left_commute: "a * (b * c) = b * (a * (c::'a::ring))"
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proof -
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  have "a * (b * c) = (a * b) * c" by (simp only: mult_assoc)
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  also have "... = (b * a) * c" by (simp only: mult_commute)
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  finally show ?thesis by (simp only: mult_assoc)
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qed
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theorems ring_mult_ac = mult_assoc mult_commute mult_left_commute
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lemma right_inverse [simp]: "a \<noteq> 0 ==>  a * inverse (a::'a::field) = 1" 
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proof -
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  have "a * inverse a = inverse a * a" by (simp add: ring_mult_ac)
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  also assume "a \<noteq> 0"
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  hence "inverse a * a = 1" by simp
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  finally show ?thesis .
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qed
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lemma right_inverse_eq: "b \<noteq> 0 ==> (a / b = 1) = (a = (b::'a::field))"
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proof 
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  assume neq: "b \<noteq> 0"
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  {
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    hence "a = (a / b) * b" by (simp add: divide_inverse ring_mult_ac)
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    also assume "a / b = 1"
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    finally show "a = b" by simp
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  next
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    assume "a = b"
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    with neq show "a / b = 1" by (simp add: divide_inverse)
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  }
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qed
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lemma divide_self [simp]: "a \<noteq> 0 ==> a / (a::'a::field) = 1"
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  by (simp add: divide_inverse)
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subsubsection {* Distribution rules *}
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lemma right_distrib: "a * (b + c) = a * b + a * (c::'a::ring)"
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proof -
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  have "a * (b + c) = (b + c) * a" by (simp add: ring_mult_ac)
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  also have "... = b * a + c * a" by (simp only: left_distrib)
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  also have "... = a * b + a * c" by (simp add: ring_mult_ac)
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  finally show ?thesis .
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qed
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theorems ring_distrib = right_distrib left_distrib
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end