src/HOL/ex/PresburgerEx.thy
author kleing
Tue, 13 May 2003 08:59:21 +0200
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child 14353 79f9fbef9106
permissions -rw-r--r--
HOL-Real -> HOL-Complex
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(*  Title:      HOL/ex/PresburgerEx.thy
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    ID:         $Id$
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    Author:     Amine Chaieb, TU Muenchen
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    License:    GPL (GNU GENERAL PUBLIC LICENSE)
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Some examples for Presburger Arithmetic
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*)
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theory PresburgerEx = Main:
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theorem "(ALL (y::int). (3 dvd y)) ==> ALL (x::int). b < x --> a <= x"
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  by presburger
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theorem "!! (y::int) (z::int) (n::int). 3 dvd z ==> 2 dvd (y::int) ==>
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  (EX (x::int).  2*x =  y) & (EX (k::int). 3*k = z)"
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  by presburger
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theorem "!! (y::int) (z::int) n. Suc(n::nat) < 6 ==>  3 dvd z ==>
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  2 dvd (y::int) ==> (EX (x::int).  2*x =  y) & (EX (k::int). 3*k = z)"
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  by presburger
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theorem "ALL (x::nat). EX (y::nat). (0::nat) <= 5 --> y = 5 + x ";
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  by presburger
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theorem "ALL (x::nat). EX (y::nat). y = 5 + x | x div 6 + 1= 2";
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  by presburger
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theorem "EX (x::int). 0 < x" by presburger
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theorem "ALL (x::int) y. x < y --> 2 * x + 1 < 2 * y" by presburger
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theorem "ALL (x::int) y. ~(2 * x + 1 = 2 * y)" by presburger
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theorem
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   "EX (x::int) y. 0 < x  & 0 <= y  & 3 * x - 5 * y = 1" by presburger
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theorem "~ (EX (x::int) (y::int) (z::int). 4*x + (-6::int)*y = 1)"
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  by presburger
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theorem "ALL (x::int). b < x --> a <= x"
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  apply (presburger no_quantify)
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  oops
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theorem "ALL (x::int). b < x --> a <= x"
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  apply (presburger no_quantify)
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  oops
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theorem "~ (EX (x::int). False)"
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  by presburger
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theorem "ALL (x::int). (a::int) < 3 * x --> b < 3 * x"
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  apply (presburger no_quantify)
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  oops
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theorem "ALL (x::int). (2 dvd x) --> (EX (y::int). x = 2*y)" by presburger 
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theorem "ALL (x::int). (2 dvd x) --> (EX (y::int). x = 2*y)" by presburger 
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theorem "ALL (x::int). (2 dvd x) = (EX (y::int). x = 2*y)" by presburger 
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theorem "ALL (x::int). ((2 dvd x) = (ALL (y::int). ~(x = 2*y + 1)))" by presburger 
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theorem "ALL (x::int). ((2 dvd x) = (ALL (y::int). ~(x = 2*y + 1)))" by presburger 
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theorem "~ (ALL (x::int). ((2 dvd x) = (ALL (y::int). ~(x = 2*y+1))| (EX (q::int) (u::int) i. 3*i + 2*q - u < 17) --> 0 < x | ((~ 3 dvd x) &(x + 8 = 0))))"
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  by presburger
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theorem 
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   "~ (ALL (i::int). 4 <= i --> (EX (x::int) y. 0 <= x & 0 <= y & 3 * x + 5 * y = i))"
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  by presburger
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theorem
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    "ALL (i::int). 8 <= i --> (EX (x::int) y. 0 <= x & 0 <= y & 3 * x + 5 * y = i)" by presburger
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theorem
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   "EX (j::int). (ALL (i::int). j <= i --> (EX (x::int) y. 0 <= x & 0 <= y & 3 * x + 5 * y = i))" by presburger
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theorem
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   "~ (ALL j (i::int). j <= i --> (EX (x::int) y. 0 <= x & 0 <= y & 3 * x + 5 * y = i))"
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  by presburger
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theorem "(EX m::nat. n = 2 * m) --> (n + 1) div 2 = n div 2" by presburger
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theorem "(EX m::int. n = 2 * m) --> (n + 1) div 2 = n div 2" by presburger
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end