src/HOL/Archimedean_Field.thy
author nipkow
Wed, 26 Aug 2009 16:13:19 +0200
changeset 32408 a1a85b0a26f7
parent 30102 799b687e4aac
child 35028 108662d50512
permissions -rw-r--r--
new interval lemma CCS example for predicate compiler
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(* Title:      Archimedean_Field.thy
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   Author:     Brian Huffman
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*)
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header {* Archimedean Fields, Floor and Ceiling Functions *}
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theory Archimedean_Field
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imports Main
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begin
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subsection {* Class of Archimedean fields *}
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text {* Archimedean fields have no infinite elements. *}
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class archimedean_field = ordered_field + number_ring +
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  assumes ex_le_of_int: "\<exists>z. x \<le> of_int z"
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lemma ex_less_of_int:
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  fixes x :: "'a::archimedean_field" shows "\<exists>z. x < of_int z"
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proof -
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  from ex_le_of_int obtain z where "x \<le> of_int z" ..
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  then have "x < of_int (z + 1)" by simp
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  then show ?thesis ..
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qed
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lemma ex_of_int_less:
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  fixes x :: "'a::archimedean_field" shows "\<exists>z. of_int z < x"
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proof -
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  from ex_less_of_int obtain z where "- x < of_int z" ..
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  then have "of_int (- z) < x" by simp
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  then show ?thesis ..
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qed
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lemma ex_less_of_nat:
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  fixes x :: "'a::archimedean_field" shows "\<exists>n. x < of_nat n"
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proof -
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  obtain z where "x < of_int z" using ex_less_of_int ..
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  also have "\<dots> \<le> of_int (int (nat z))" by simp
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  also have "\<dots> = of_nat (nat z)" by (simp only: of_int_of_nat_eq)
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  finally show ?thesis ..
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qed
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lemma ex_le_of_nat:
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  fixes x :: "'a::archimedean_field" shows "\<exists>n. x \<le> of_nat n"
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proof -
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  obtain n where "x < of_nat n" using ex_less_of_nat ..
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  then have "x \<le> of_nat n" by simp
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  then show ?thesis ..
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qed
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text {* Archimedean fields have no infinitesimal elements. *}
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lemma ex_inverse_of_nat_Suc_less:
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  fixes x :: "'a::archimedean_field"
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  assumes "0 < x" shows "\<exists>n. inverse (of_nat (Suc n)) < x"
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proof -
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  from `0 < x` have "0 < inverse x"
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    by (rule positive_imp_inverse_positive)
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  obtain n where "inverse x < of_nat n"
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    using ex_less_of_nat ..
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  then obtain m where "inverse x < of_nat (Suc m)"
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    using `0 < inverse x` by (cases n) (simp_all del: of_nat_Suc)
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  then have "inverse (of_nat (Suc m)) < inverse (inverse x)"
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    using `0 < inverse x` by (rule less_imp_inverse_less)
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  then have "inverse (of_nat (Suc m)) < x"
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    using `0 < x` by (simp add: nonzero_inverse_inverse_eq)
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  then show ?thesis ..
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qed
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lemma ex_inverse_of_nat_less:
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  fixes x :: "'a::archimedean_field"
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  assumes "0 < x" shows "\<exists>n>0. inverse (of_nat n) < x"
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  using ex_inverse_of_nat_Suc_less [OF `0 < x`] by auto
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lemma ex_less_of_nat_mult:
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  fixes x :: "'a::archimedean_field"
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  assumes "0 < x" shows "\<exists>n. y < of_nat n * x"
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proof -
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  obtain n where "y / x < of_nat n" using ex_less_of_nat ..
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  with `0 < x` have "y < of_nat n * x" by (simp add: pos_divide_less_eq)
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  then show ?thesis ..
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qed
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subsection {* Existence and uniqueness of floor function *}
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lemma exists_least_lemma:
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  assumes "\<not> P 0" and "\<exists>n. P n"
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  shows "\<exists>n. \<not> P n \<and> P (Suc n)"
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proof -
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  from `\<exists>n. P n` have "P (Least P)" by (rule LeastI_ex)
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  with `\<not> P 0` obtain n where "Least P = Suc n"
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    by (cases "Least P") auto
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  then have "n < Least P" by simp
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  then have "\<not> P n" by (rule not_less_Least)
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  then have "\<not> P n \<and> P (Suc n)"
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    using `P (Least P)` `Least P = Suc n` by simp
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  then show ?thesis ..
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qed
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lemma floor_exists:
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  fixes x :: "'a::archimedean_field"
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  shows "\<exists>z. of_int z \<le> x \<and> x < of_int (z + 1)"
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proof (cases)
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  assume "0 \<le> x"
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  then have "\<not> x < of_nat 0" by simp
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  then have "\<exists>n. \<not> x < of_nat n \<and> x < of_nat (Suc n)"
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    using ex_less_of_nat by (rule exists_least_lemma)
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  then obtain n where "\<not> x < of_nat n \<and> x < of_nat (Suc n)" ..
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  then have "of_int (int n) \<le> x \<and> x < of_int (int n + 1)" by simp
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  then show ?thesis ..
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next
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  assume "\<not> 0 \<le> x"
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  then have "\<not> - x \<le> of_nat 0" by simp
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  then have "\<exists>n. \<not> - x \<le> of_nat n \<and> - x \<le> of_nat (Suc n)"
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    using ex_le_of_nat by (rule exists_least_lemma)
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  then obtain n where "\<not> - x \<le> of_nat n \<and> - x \<le> of_nat (Suc n)" ..
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  then have "of_int (- int n - 1) \<le> x \<and> x < of_int (- int n - 1 + 1)" by simp
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  then show ?thesis ..
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qed
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lemma floor_exists1:
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  fixes x :: "'a::archimedean_field"
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  shows "\<exists>!z. of_int z \<le> x \<and> x < of_int (z + 1)"
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proof (rule ex_ex1I)
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  show "\<exists>z. of_int z \<le> x \<and> x < of_int (z + 1)"
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    by (rule floor_exists)
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next
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  fix y z assume
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    "of_int y \<le> x \<and> x < of_int (y + 1)"
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    "of_int z \<le> x \<and> x < of_int (z + 1)"
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  then have
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    "of_int y \<le> x" "x < of_int (y + 1)"
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    "of_int z \<le> x" "x < of_int (z + 1)"
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    by simp_all
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  from le_less_trans [OF `of_int y \<le> x` `x < of_int (z + 1)`]
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       le_less_trans [OF `of_int z \<le> x` `x < of_int (y + 1)`]
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  show "y = z" by (simp del: of_int_add)
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qed
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subsection {* Floor function *}
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definition
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  floor :: "'a::archimedean_field \<Rightarrow> int" where
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  [code del]: "floor x = (THE z. of_int z \<le> x \<and> x < of_int (z + 1))"
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notation (xsymbols)
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  floor  ("\<lfloor>_\<rfloor>")
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notation (HTML output)
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  floor  ("\<lfloor>_\<rfloor>")
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lemma floor_correct: "of_int (floor x) \<le> x \<and> x < of_int (floor x + 1)"
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  unfolding floor_def using floor_exists1 by (rule theI')
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lemma floor_unique: "\<lbrakk>of_int z \<le> x; x < of_int z + 1\<rbrakk> \<Longrightarrow> floor x = z"
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  using floor_correct [of x] floor_exists1 [of x] by auto
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lemma of_int_floor_le: "of_int (floor x) \<le> x"
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  using floor_correct ..
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lemma le_floor_iff: "z \<le> floor x \<longleftrightarrow> of_int z \<le> x"
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proof
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  assume "z \<le> floor x"
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  then have "(of_int z :: 'a) \<le> of_int (floor x)" by simp
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  also have "of_int (floor x) \<le> x" by (rule of_int_floor_le)
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  finally show "of_int z \<le> x" .
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next
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  assume "of_int z \<le> x"
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  also have "x < of_int (floor x + 1)" using floor_correct ..
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  finally show "z \<le> floor x" by (simp del: of_int_add)
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qed
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lemma floor_less_iff: "floor x < z \<longleftrightarrow> x < of_int z"
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  by (simp add: not_le [symmetric] le_floor_iff)
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lemma less_floor_iff: "z < floor x \<longleftrightarrow> of_int z + 1 \<le> x"
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  using le_floor_iff [of "z + 1" x] by auto
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lemma floor_le_iff: "floor x \<le> z \<longleftrightarrow> x < of_int z + 1"
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  by (simp add: not_less [symmetric] less_floor_iff)
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lemma floor_mono: assumes "x \<le> y" shows "floor x \<le> floor y"
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proof -
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  have "of_int (floor x) \<le> x" by (rule of_int_floor_le)
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  also note `x \<le> y`
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  finally show ?thesis by (simp add: le_floor_iff)
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qed
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lemma floor_less_cancel: "floor x < floor y \<Longrightarrow> x < y"
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  by (auto simp add: not_le [symmetric] floor_mono)
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lemma floor_of_int [simp]: "floor (of_int z) = z"
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  by (rule floor_unique) simp_all
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lemma floor_of_nat [simp]: "floor (of_nat n) = int n"
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  using floor_of_int [of "of_nat n"] by simp
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text {* Floor with numerals *}
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lemma floor_zero [simp]: "floor 0 = 0"
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  using floor_of_int [of 0] by simp
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lemma floor_one [simp]: "floor 1 = 1"
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  using floor_of_int [of 1] by simp
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lemma floor_number_of [simp]: "floor (number_of v) = number_of v"
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  using floor_of_int [of "number_of v"] by simp
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lemma zero_le_floor [simp]: "0 \<le> floor x \<longleftrightarrow> 0 \<le> x"
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  by (simp add: le_floor_iff)
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lemma one_le_floor [simp]: "1 \<le> floor x \<longleftrightarrow> 1 \<le> x"
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  by (simp add: le_floor_iff)
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lemma number_of_le_floor [simp]: "number_of v \<le> floor x \<longleftrightarrow> number_of v \<le> x"
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  by (simp add: le_floor_iff)
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lemma zero_less_floor [simp]: "0 < floor x \<longleftrightarrow> 1 \<le> x"
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  by (simp add: less_floor_iff)
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lemma one_less_floor [simp]: "1 < floor x \<longleftrightarrow> 2 \<le> x"
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  by (simp add: less_floor_iff)
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lemma number_of_less_floor [simp]:
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  "number_of v < floor x \<longleftrightarrow> number_of v + 1 \<le> x"
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  by (simp add: less_floor_iff)
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lemma floor_le_zero [simp]: "floor x \<le> 0 \<longleftrightarrow> x < 1"
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  by (simp add: floor_le_iff)
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lemma floor_le_one [simp]: "floor x \<le> 1 \<longleftrightarrow> x < 2"
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  by (simp add: floor_le_iff)
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lemma floor_le_number_of [simp]:
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  "floor x \<le> number_of v \<longleftrightarrow> x < number_of v + 1"
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  by (simp add: floor_le_iff)
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lemma floor_less_zero [simp]: "floor x < 0 \<longleftrightarrow> x < 0"
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  by (simp add: floor_less_iff)
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lemma floor_less_one [simp]: "floor x < 1 \<longleftrightarrow> x < 1"
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  by (simp add: floor_less_iff)
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lemma floor_less_number_of [simp]:
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  "floor x < number_of v \<longleftrightarrow> x < number_of v"
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  by (simp add: floor_less_iff)
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text {* Addition and subtraction of integers *}
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lemma floor_add_of_int [simp]: "floor (x + of_int z) = floor x + z"
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  using floor_correct [of x] by (simp add: floor_unique)
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lemma floor_add_number_of [simp]:
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    "floor (x + number_of v) = floor x + number_of v"
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  using floor_add_of_int [of x "number_of v"] by simp
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lemma floor_add_one [simp]: "floor (x + 1) = floor x + 1"
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  using floor_add_of_int [of x 1] by simp
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lemma floor_diff_of_int [simp]: "floor (x - of_int z) = floor x - z"
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  using floor_add_of_int [of x "- z"] by (simp add: algebra_simps)
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lemma floor_diff_number_of [simp]:
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  "floor (x - number_of v) = floor x - number_of v"
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  using floor_diff_of_int [of x "number_of v"] by simp
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lemma floor_diff_one [simp]: "floor (x - 1) = floor x - 1"
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  using floor_diff_of_int [of x 1] by simp
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subsection {* Ceiling function *}
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definition
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  ceiling :: "'a::archimedean_field \<Rightarrow> int" where
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  [code del]: "ceiling x = - floor (- x)"
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notation (xsymbols)
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  ceiling  ("\<lceil>_\<rceil>")
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notation (HTML output)
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  ceiling  ("\<lceil>_\<rceil>")
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lemma ceiling_correct: "of_int (ceiling x) - 1 < x \<and> x \<le> of_int (ceiling x)"
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  unfolding ceiling_def using floor_correct [of "- x"] by simp
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lemma ceiling_unique: "\<lbrakk>of_int z - 1 < x; x \<le> of_int z\<rbrakk> \<Longrightarrow> ceiling x = z"
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  unfolding ceiling_def using floor_unique [of "- z" "- x"] by simp
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lemma le_of_int_ceiling: "x \<le> of_int (ceiling x)"
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  using ceiling_correct ..
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lemma ceiling_le_iff: "ceiling x \<le> z \<longleftrightarrow> x \<le> of_int z"
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  unfolding ceiling_def using le_floor_iff [of "- z" "- x"] by auto
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lemma less_ceiling_iff: "z < ceiling x \<longleftrightarrow> of_int z < x"
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  by (simp add: not_le [symmetric] ceiling_le_iff)
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lemma ceiling_less_iff: "ceiling x < z \<longleftrightarrow> x \<le> of_int z - 1"
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  using ceiling_le_iff [of x "z - 1"] by simp
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lemma le_ceiling_iff: "z \<le> ceiling x \<longleftrightarrow> of_int z - 1 < x"
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  by (simp add: not_less [symmetric] ceiling_less_iff)
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lemma ceiling_mono: "x \<ge> y \<Longrightarrow> ceiling x \<ge> ceiling y"
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  unfolding ceiling_def by (simp add: floor_mono)
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lemma ceiling_less_cancel: "ceiling x < ceiling y \<Longrightarrow> x < y"
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  by (auto simp add: not_le [symmetric] ceiling_mono)
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lemma ceiling_of_int [simp]: "ceiling (of_int z) = z"
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  by (rule ceiling_unique) simp_all
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lemma ceiling_of_nat [simp]: "ceiling (of_nat n) = int n"
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  using ceiling_of_int [of "of_nat n"] by simp
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text {* Ceiling with numerals *}
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lemma ceiling_zero [simp]: "ceiling 0 = 0"
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  using ceiling_of_int [of 0] by simp
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lemma ceiling_one [simp]: "ceiling 1 = 1"
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  using ceiling_of_int [of 1] by simp
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lemma ceiling_number_of [simp]: "ceiling (number_of v) = number_of v"
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  using ceiling_of_int [of "number_of v"] by simp
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lemma ceiling_le_zero [simp]: "ceiling x \<le> 0 \<longleftrightarrow> x \<le> 0"
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  by (simp add: ceiling_le_iff)
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lemma ceiling_le_one [simp]: "ceiling x \<le> 1 \<longleftrightarrow> x \<le> 1"
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  by (simp add: ceiling_le_iff)
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lemma ceiling_le_number_of [simp]:
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  "ceiling x \<le> number_of v \<longleftrightarrow> x \<le> number_of v"
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  by (simp add: ceiling_le_iff)
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lemma ceiling_less_zero [simp]: "ceiling x < 0 \<longleftrightarrow> x \<le> -1"
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  by (simp add: ceiling_less_iff)
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lemma ceiling_less_one [simp]: "ceiling x < 1 \<longleftrightarrow> x \<le> 0"
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  by (simp add: ceiling_less_iff)
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lemma ceiling_less_number_of [simp]:
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  "ceiling x < number_of v \<longleftrightarrow> x \<le> number_of v - 1"
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  by (simp add: ceiling_less_iff)
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lemma zero_le_ceiling [simp]: "0 \<le> ceiling x \<longleftrightarrow> -1 < x"
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  by (simp add: le_ceiling_iff)
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lemma one_le_ceiling [simp]: "1 \<le> ceiling x \<longleftrightarrow> 0 < x"
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  by (simp add: le_ceiling_iff)
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lemma number_of_le_ceiling [simp]:
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  "number_of v \<le> ceiling x\<longleftrightarrow> number_of v - 1 < x"
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  by (simp add: le_ceiling_iff)
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lemma zero_less_ceiling [simp]: "0 < ceiling x \<longleftrightarrow> 0 < x"
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  by (simp add: less_ceiling_iff)
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lemma one_less_ceiling [simp]: "1 < ceiling x \<longleftrightarrow> 1 < x"
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  by (simp add: less_ceiling_iff)
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lemma number_of_less_ceiling [simp]:
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  "number_of v < ceiling x \<longleftrightarrow> number_of v < x"
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  by (simp add: less_ceiling_iff)
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text {* Addition and subtraction of integers *}
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lemma ceiling_add_of_int [simp]: "ceiling (x + of_int z) = ceiling x + z"
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  using ceiling_correct [of x] by (simp add: ceiling_unique)
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lemma ceiling_add_number_of [simp]:
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    "ceiling (x + number_of v) = ceiling x + number_of v"
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  using ceiling_add_of_int [of x "number_of v"] by simp
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lemma ceiling_add_one [simp]: "ceiling (x + 1) = ceiling x + 1"
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  using ceiling_add_of_int [of x 1] by simp
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lemma ceiling_diff_of_int [simp]: "ceiling (x - of_int z) = ceiling x - z"
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  using ceiling_add_of_int [of x "- z"] by (simp add: algebra_simps)
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lemma ceiling_diff_number_of [simp]:
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  "ceiling (x - number_of v) = ceiling x - number_of v"
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  using ceiling_diff_of_int [of x "number_of v"] by simp
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lemma ceiling_diff_one [simp]: "ceiling (x - 1) = ceiling x - 1"
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  using ceiling_diff_of_int [of x 1] by simp
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subsection {* Negation *}
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lemma floor_minus: "floor (- x) = - ceiling x"
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  unfolding ceiling_def by simp
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lemma ceiling_minus: "ceiling (- x) = - floor x"
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  unfolding ceiling_def by simp
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end