src/HOL/Isar_Examples/Knaster_Tarski.thy

unused;

(*  Title:      HOL/Isar_Examples/Knaster_Tarski.thy
    Author:     Markus Wenzel, TU Muenchen

Typical textbook proof example.
*)

section \<open>Textbook-style reasoning: the Knaster-Tarski Theorem\<close>

theory Knaster_Tarski
imports Main "~~/src/HOL/Library/Lattice_Syntax"
begin


subsection \<open>Prose version\<close>

text \<open>According to the textbook @{cite \<open>pages 93--94\<close> "davey-priestley"},
  the Knaster-Tarski fixpoint theorem is as follows.\footnote{We have
  dualized the argument, and tuned the notation a little bit.}

  \<^bold>\<open>The Knaster-Tarski Fixpoint Theorem.\<close> Let \<open>L\<close> be a complete lattice and
  \<open>f: L \<rightarrow> L\<close> an order-preserving map. Then \<open>\<Sqinter>{x \<in> L | f(x) \<le> x}\<close> is a
  fixpoint of \<open>f\<close>.

  \<^bold>\<open>Proof.\<close> Let \<open>H = {x \<in> L | f(x) \<le> x}\<close> and \<open>a = \<Sqinter>H\<close>. For all \<open>x \<in> H\<close> we
  have \<open>a \<le> x\<close>, so \<open>f(a) \<le> f(x) \<le> x\<close>. Thus \<open>f(a)\<close> is a lower bound of \<open>H\<close>,
  whence \<open>f(a) \<le> a\<close>. We now use this inequality to prove the reverse one (!)
  and thereby complete the proof that \<open>a\<close> is a fixpoint. Since \<open>f\<close> is
  order-preserving, \<open>f(f(a)) \<le> f(a)\<close>. This says \<open>f(a) \<in> H\<close>, so \<open>a \<le> f(a)\<close>.\<close>


subsection \<open>Formal versions\<close>

text \<open>The Isar proof below closely follows the original presentation.
  Virtually all of the prose narration has been rephrased in terms of formal
  Isar language elements. Just as many textbook-style proofs, there is a
  strong bias towards forward proof, and several bends in the course of
  reasoning.\<close>

theorem Knaster_Tarski:
  fixes f :: "'a::complete_lattice \<Rightarrow> 'a"
  assumes "mono f"
  shows "\<exists>a. f a = a"
proof
  let ?H = "{u. f u \<le> u}"
  let ?a = "\<Sqinter>?H"
  show "f ?a = ?a"
  proof -
    {
      fix x
      assume "x \<in> ?H"
      then have "?a \<le> x" by (rule Inf_lower)
      with \<open>mono f\<close> have "f ?a \<le> f x" ..
      also from \<open>x \<in> ?H\<close> have "\<dots> \<le> x" ..
      finally have "f ?a \<le> x" .
    }
    then have "f ?a \<le> ?a" by (rule Inf_greatest)
    {
      also presume "\<dots> \<le> f ?a"
      finally (order_antisym) show ?thesis .
    }
    from \<open>mono f\<close> and \<open>f ?a \<le> ?a\<close> have "f (f ?a) \<le> f ?a" ..
    then have "f ?a \<in> ?H" ..
    then show "?a \<le> f ?a" by (rule Inf_lower)
  qed
qed

text \<open>Above we have used several advanced Isar language elements, such as
  explicit block structure and weak assumptions. Thus we have mimicked the
  particular way of reasoning of the original text.

  In the subsequent version the order of reasoning is changed to achieve
  structured top-down decomposition of the problem at the outer level, while
  only the inner steps of reasoning are done in a forward manner. We are
  certainly more at ease here, requiring only the most basic features of the
  Isar language.\<close>

theorem Knaster_Tarski':
  fixes f :: "'a::complete_lattice \<Rightarrow> 'a"
  assumes "mono f"
  shows "\<exists>a. f a = a"
proof
  let ?H = "{u. f u \<le> u}"
  let ?a = "\<Sqinter>?H"
  show "f ?a = ?a"
  proof (rule order_antisym)
    show "f ?a \<le> ?a"
    proof (rule Inf_greatest)
      fix x
      assume "x \<in> ?H"
      then have "?a \<le> x" by (rule Inf_lower)
      with \<open>mono f\<close> have "f ?a \<le> f x" ..
      also from \<open>x \<in> ?H\<close> have "\<dots> \<le> x" ..
      finally show "f ?a \<le> x" .
    qed
    show "?a \<le> f ?a"
    proof (rule Inf_lower)
      from \<open>mono f\<close> and \<open>f ?a \<le> ?a\<close> have "f (f ?a) \<le> f ?a" ..
      then show "f ?a \<in> ?H" ..
    qed
  qed
qed

end