| author | wenzelm | 
| Thu, 13 Mar 2025 11:19:27 +0100 | |
| changeset 82266 | cca7113dcafc | 
| parent 80914 | d97fdabd9e2b | 
| permissions | -rw-r--r-- | 
| 21107 | 1  | 
theory Lam_Funs  | 
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session-qualified theory imports: isabelle imports -U -i -d '~~/src/Benchmarks' -a;
 
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2  | 
imports "HOL-Nominal.Nominal"  | 
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begin  | 
4  | 
||
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text \<open>  | 
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6  | 
Provides useful definitions for reasoning  | 
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7  | 
with lambda-terms.  | 
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\<close>  | 
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atom_decl name  | 
11  | 
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12  | 
nominal_datatype lam =  | 
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13  | 
Var "name"  | 
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14  | 
| App "lam" "lam"  | 
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15  | 
| Lam "\<guillemotleft>name\<guillemotright>lam" (\<open>Lam [_]._\<close> [100,100] 100)  | 
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text \<open>The depth of a lambda-term.\<close>  | 
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18  | 
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19  | 
nominal_primrec  | 
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depth :: "lam \<Rightarrow> nat"  | 
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21  | 
where  | 
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22  | 
"depth (Var x) = 1"  | 
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23  | 
| "depth (App t1 t2) = (max (depth t1) (depth t2)) + 1"  | 
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24  | 
| "depth (Lam [a].t) = (depth t) + 1"  | 
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by(finite_guess | simp | fresh_guess)+  | 
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text \<open>  | 
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28  | 
The free variables of a lambda-term. A complication in this  | 
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29  | 
function arises from the fact that it returns a name set, which  | 
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30  | 
is not a finitely supported type. Therefore we have to prove  | 
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31  | 
the invariant that frees always returns a finite set of names.  | 
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\<close>  | 
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33  | 
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34  | 
nominal_primrec (invariant: "\<lambda>s::name set. finite s")  | 
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35  | 
frees :: "lam \<Rightarrow> name set"  | 
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36  | 
where  | 
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37  | 
  "frees (Var a) = {a}"
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38  | 
| "frees (App t1 t2) = (frees t1) \<union> (frees t2)"  | 
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39  | 
| "frees (Lam [a].t) = (frees t) - {a}"
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apply(finite_guess | simp add: fresh_def | fresh_guess)+  | 
41  | 
apply (simp add: at_fin_set_supp at_name_inst)  | 
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apply(fresh_guess)+  | 
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43  | 
done  | 
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44  | 
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text \<open>  | 
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46  | 
We can avoid the definition of frees by  | 
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47  | 
using the build in notion of support.  | 
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\<close>  | 
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49  | 
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50  | 
lemma frees_equals_support:  | 
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51  | 
shows "frees t = supp t"  | 
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52  | 
by (nominal_induct t rule: lam.strong_induct)  | 
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53  | 
(simp_all add: lam.supp supp_atm abs_supp)  | 
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54  | 
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text \<open>Parallel and single capture-avoiding substitution.\<close>  | 
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56  | 
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fun  | 
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58  | 
lookup :: "(name\<times>lam) list \<Rightarrow> name \<Rightarrow> lam"  | 
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59  | 
where  | 
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60  | 
"lookup [] x = Var x"  | 
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61  | 
| "lookup ((y,e)#\<theta>) x = (if x=y then e else lookup \<theta> x)"  | 
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62  | 
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63  | 
lemma lookup_eqvt[eqvt]:  | 
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64  | 
fixes pi::"name prm"  | 
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65  | 
and \<theta>::"(name\<times>lam) list"  | 
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66  | 
and X::"name"  | 
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shows "pi\<bullet>(lookup \<theta> X) = lookup (pi\<bullet>\<theta>) (pi\<bullet>X)"  | 
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by (induct \<theta>) (auto simp add: eqvts)  | 
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69  | 
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nominal_primrec  | 
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71  | 
psubst :: "(name\<times>lam) list \<Rightarrow> lam \<Rightarrow> lam" (\<open>_<_>\<close> [95,95] 105)  | 
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72  | 
where  | 
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"\<theta><(Var x)> = (lookup \<theta> x)"  | 
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74  | 
| "\<theta><(App e\<^sub>1 e\<^sub>2)> = App (\<theta><e\<^sub>1>) (\<theta><e\<^sub>2>)"  | 
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75  | 
| "x\<sharp>\<theta> \<Longrightarrow> \<theta><(Lam [x].e)> = Lam [x].(\<theta><e>)"  | 
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by (finite_guess | simp add: abs_fresh | fresh_guess)+  | 
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78  | 
lemma psubst_eqvt[eqvt]:  | 
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79  | 
fixes pi::"name prm"  | 
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and t::"lam"  | 
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shows "pi\<bullet>(\<theta><t>) = (pi\<bullet>\<theta>)<(pi\<bullet>t)>"  | 
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82  | 
by (nominal_induct t avoiding: \<theta> rule: lam.strong_induct)  | 
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83  | 
(simp_all add: eqvts fresh_bij)  | 
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84  | 
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85  | 
abbreviation  | 
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86  | 
subst :: "lam \<Rightarrow> name \<Rightarrow> lam \<Rightarrow> lam" (\<open>_[_::=_]\<close> [100,100,100] 100)  | 
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87  | 
where  | 
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88  | 
"t[x::=t'] \<equiv> ([(x,t')])<t>"  | 
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89  | 
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lemma subst[simp]:  | 
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91  | 
shows "(Var x)[y::=t'] = (if x=y then t' else (Var x))"  | 
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and "(App t1 t2)[y::=t'] = App (t1[y::=t']) (t2[y::=t'])"  | 
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93  | 
and "x\<sharp>(y,t') \<Longrightarrow> (Lam [x].t)[y::=t'] = Lam [x].(t[y::=t'])"  | 
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94  | 
by (simp_all add: fresh_list_cons fresh_list_nil)  | 
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96  | 
lemma subst_supp:  | 
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  shows "supp(t1[a::=t2]) \<subseteq> (((supp(t1)-{a})\<union>supp(t2))::name set)"
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proof (nominal_induct t1 avoiding: a t2 rule: lam.strong_induct)  | 
99  | 
case (Var name)  | 
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100  | 
then show ?case  | 
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101  | 
by (simp add: lam.supp(1) supp_atm)  | 
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102  | 
next  | 
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103  | 
case (App lam1 lam2)  | 
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104  | 
then show ?case  | 
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105  | 
using lam.supp(2) by fastforce  | 
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106  | 
next  | 
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107  | 
case (Lam name lam)  | 
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108  | 
then show ?case  | 
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109  | 
using frees.simps(3) frees_equals_support by auto  | 
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110  | 
qed  | 
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text \<open>  | 
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113  | 
Contexts - lambda-terms with a single hole.  | 
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114  | 
Note that the lambda case in contexts does not bind a  | 
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115  | 
name, even if we introduce the notation [_]._ for CLam.  | 
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\<close>  | 
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nominal_datatype clam =  | 
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118  | 
Hole (\<open>\<box>\<close> 1000)  | 
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119  | 
| CAppL "clam" "lam"  | 
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120  | 
| CAppR "lam" "clam"  | 
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121  | 
| CLam "name" "clam" (\<open>CLam [_]._\<close> [100,100] 100)  | 
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text \<open>Filling a lambda-term into a context.\<close>  | 
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nominal_primrec  | 
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126  | 
filling :: "clam \<Rightarrow> lam \<Rightarrow> lam" (\<open>_\<lbrakk>_\<rbrakk>\<close> [100,100] 100)  | 
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127  | 
where  | 
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128  | 
"\<box>\<lbrakk>t\<rbrakk> = t"  | 
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129  | 
| "(CAppL E t')\<lbrakk>t\<rbrakk> = App (E\<lbrakk>t\<rbrakk>) t'"  | 
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130  | 
| "(CAppR t' E)\<lbrakk>t\<rbrakk> = App t' (E\<lbrakk>t\<rbrakk>)"  | 
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131  | 
| "(CLam [x].E)\<lbrakk>t\<rbrakk> = Lam [x].(E\<lbrakk>t\<rbrakk>)"  | 
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132  | 
by (rule TrueI)+  | 
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133  | 
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text \<open>Composition od two contexts\<close>  | 
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135  | 
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136  | 
nominal_primrec  | 
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137  | 
clam_compose :: "clam \<Rightarrow> clam \<Rightarrow> clam" (\<open>_ \<circ> _\<close> [100,100] 100)  | 
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138  | 
where  | 
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139  | 
"\<box> \<circ> E' = E'"  | 
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140  | 
| "(CAppL E t') \<circ> E' = CAppL (E \<circ> E') t'"  | 
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141  | 
| "(CAppR t' E) \<circ> E' = CAppR t' (E \<circ> E')"  | 
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142  | 
| "(CLam [x].E) \<circ> E' = CLam [x].(E \<circ> E')"  | 
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143  | 
by (rule TrueI)+  | 
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144  | 
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145  | 
lemma clam_compose:  | 
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146  | 
shows "(E1 \<circ> E2)\<lbrakk>t\<rbrakk> = E1\<lbrakk>E2\<lbrakk>t\<rbrakk>\<rbrakk>"  | 
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147  | 
by (induct E1 rule: clam.induct) (auto)  | 
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149  | 
end  |