doc-src/Exercises/2003/a2/generated/a2.tex

removed norm_typ; improved output; refer to Pretty.pp;

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\begin{isabellebody}%
\def\isabellecontext{a{\isadigit{2}}}%
\isamarkupfalse%
%
\isamarkupsubsection{Trees%
}
\isamarkuptrue%
%
\begin{isamarkuptext}%
Define a datatype \isa{{\isacharprime}a\ tree} for binary trees. Both leaf
and internal nodes store information.%
\end{isamarkuptext}%
\isamarkuptrue%
\isacommand{datatype}\ {\isacharprime}a\ tree\isamarkupfalse%
%
\begin{isamarkuptext}%
Define the functions \isa{preOrder}, \isa{postOrder}, and \isa{inOrder} that traverse an \isa{{\isacharprime}a\ tree} in the respective order.%
\end{isamarkuptext}%
\isamarkuptrue%
\ \ preOrder\ {\isacharcolon}{\isacharcolon}\ {\isachardoublequote}{\isacharprime}a\ tree\ {\isasymRightarrow}\ {\isacharprime}a\ list{\isachardoublequote}\isanewline
\ \ postOrder\ {\isacharcolon}{\isacharcolon}\ {\isachardoublequote}{\isacharprime}a\ tree\ {\isasymRightarrow}\ {\isacharprime}a\ list{\isachardoublequote}\isanewline
\ \ inOrder\ {\isacharcolon}{\isacharcolon}\ {\isachardoublequote}{\isacharprime}a\ tree\ {\isasymRightarrow}\ {\isacharprime}a\ list{\isachardoublequote}\isamarkupfalse%
%
\begin{isamarkuptext}%
Define a function \isa{mirror} that returns the mirror image of an \isa{{\isacharprime}a\ tree}.%
\end{isamarkuptext}%
\isamarkuptrue%
\ \ mirror\ {\isacharcolon}{\isacharcolon}\ {\isachardoublequote}{\isacharprime}a\ tree\ {\isasymRightarrow}\ {\isacharprime}a\ tree{\isachardoublequote}\isamarkupfalse%
%
\begin{isamarkuptext}%
Suppose that \isa{xOrder} and \isa{yOrder} are tree traversal
functions chosen from \isa{preOrder}, \isa{postOrder}, and \isa{inOrder}. Formulate and prove all valid properties of the form
\mbox{\isa{xOrder\ {\isacharparenleft}mirror\ xt{\isacharparenright}\ {\isacharequal}\ rev\ {\isacharparenleft}yOrder\ xt{\isacharparenright}}}.%
\end{isamarkuptext}%
\isamarkuptrue%
%
\begin{isamarkuptext}%
Define the functions \isa{root}, \isa{leftmost} and \isa{rightmost}, that return the root, leftmost, and rightmost element
respectively.%
\end{isamarkuptext}%
\isamarkuptrue%
\ \ root\ {\isacharcolon}{\isacharcolon}\ {\isachardoublequote}{\isacharprime}a\ tree\ {\isasymRightarrow}\ {\isacharprime}a{\isachardoublequote}\isanewline
\ \ leftmost\ {\isacharcolon}{\isacharcolon}\ {\isachardoublequote}{\isacharprime}a\ tree\ {\isasymRightarrow}\ {\isacharprime}a{\isachardoublequote}\isanewline
\ \ rightmost\ {\isacharcolon}{\isacharcolon}\ {\isachardoublequote}{\isacharprime}a\ tree\ {\isasymRightarrow}\ {\isacharprime}a{\isachardoublequote}\isamarkupfalse%
%
\begin{isamarkuptext}%
Prove or disprove (by counter example) the theorems that follow. You may have to prove some lemmas first.%
\end{isamarkuptext}%
\isamarkuptrue%
\isacommand{theorem}\ {\isachardoublequote}last{\isacharparenleft}inOrder\ xt{\isacharparenright}\ {\isacharequal}\ rightmost\ xt{\isachardoublequote}\isamarkupfalse%
\ \isanewline
\isamarkupfalse%
\isacommand{theorem}\ {\isachardoublequote}hd\ {\isacharparenleft}inOrder\ xt{\isacharparenright}\ {\isacharequal}\ leftmost\ xt\ {\isachardoublequote}\isamarkupfalse%
\ \isanewline
\isamarkupfalse%
\isacommand{theorem}\ {\isachardoublequote}hd{\isacharparenleft}preOrder\ xt{\isacharparenright}\ {\isacharequal}\ last{\isacharparenleft}postOrder\ xt{\isacharparenright}{\isachardoublequote}\isamarkupfalse%
\ \isanewline
\isamarkupfalse%
\isacommand{theorem}\ {\isachardoublequote}hd{\isacharparenleft}preOrder\ xt{\isacharparenright}\ {\isacharequal}\ root\ xt{\isachardoublequote}\isamarkupfalse%
\ \isanewline
\isamarkupfalse%
\isacommand{theorem}\ {\isachardoublequote}hd{\isacharparenleft}inOrder\ xt{\isacharparenright}\ {\isacharequal}\ root\ xt\ {\isachardoublequote}\isamarkupfalse%
\ \isanewline
\isamarkupfalse%
\isacommand{theorem}\ {\isachardoublequote}last{\isacharparenleft}postOrder\ xt{\isacharparenright}\ {\isacharequal}\ root\ xt{\isachardoublequote}\isamarkupfalse%
\ \isanewline
\isanewline
\isamarkupfalse%
\isamarkupfalse%
\end{isabellebody}%
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