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(*<*)
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theory a3 = Main:
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(*>*)
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subsection{* Computing with natural numbers - Magical Methods *}
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text{*
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A book about Vedic Mathematics describes three methods to make the calculation of squares of natural numbers easier:
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\begin{itemize}
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\item {\em MM1}: Numbers whose predecessors have squares that are known or can easily be calculated. For example:
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\\ Needed: $61^2$
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\\ Given: $60^2 = 3600$
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\\ Observe: $61^2 = 3600 + 60 + 61 = 3721$
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\item {\em MM2}: Numbers greater than, but near 100. For example:
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\\ Needed: $102^2$
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\\ Let $h = 102 - 100 = 2$ , $h^2 = 4$
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\\ Observe: $102^2 = (102+h)$ shifted two places to the left $ + h^2 = 10404$
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\item {\em MM3}: Numbers ending in $5$. For example:
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\\ Needed: $85^2$
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\\ Observe: $85^2 = (8 * 9)$ appended to $ 25 = 7225$
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\\ Needed: $995^2$
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\\ Observe: $995^2 = (99 * 100)$ appended to $ 25 = 990025 $
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\end{itemize}
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In this exercise we will show that these methods are not so magical after all!
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\begin{itemize}
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\item Based on {\em MM1} define a function @{term "sq"} that calculates the square of a natural number.
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\item Prove the correctness of @{term "sq"} (i.e.\ @{term "sq n = n * n"}).
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\item Formulate and prove the correctness of {\em MM2}.\\ Hints:
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\begin{itemize}
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\item Generalise {\em MM2} for an arbitrary constant (instead of $100$).
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\item Universally quantify all variables other than the induction variable.
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\end{itemize}
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\item Formulate and prove the correctness of {\em MM3}.\\ Hints:
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\begin{itemize}
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\item Try to formulate the property `numbers ending in $5$' such that it is easy to get to the rest of the number.
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\item Proving the binomial formula for $(a+b)^2$ can be of some help.
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\end{itemize}
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\end{itemize}
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*}
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(*<*) end (*>*) |