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(* Author: Tobias Nipkow *)
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header "Definite Assignment Analysis"
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theory Vars imports Util BExp
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begin
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subsection "The Variables in an Expression"
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text{* We need to collect the variables in both arithmetic and boolean
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expressions. For a change we do not introduce two functions, e.g.\ @{text
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avars} and @{text bvars}, but we overload the name @{text vars}
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via a \emph{type class}, a device that originated with Haskell: *}
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class vars =
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fixes vars :: "'a \<Rightarrow> name set"
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text{* This defines a type class ``vars'' with a single
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function of (coincidentally) the same name. Then we define two separated
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instances of the class, one for @{typ aexp} and one for @{typ bexp}: *}
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instantiation aexp :: vars
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begin
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fun vars_aexp :: "aexp \<Rightarrow> name set" where
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"vars_aexp (N n) = {}" |
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"vars_aexp (V x) = {x}" |
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"vars_aexp (Plus a\<^isub>1 a\<^isub>2) = vars_aexp a\<^isub>1 \<union> vars_aexp a\<^isub>2"
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instance ..
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end
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value "vars(Plus (V ''x'') (V ''y''))"
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text{* We need to convert functions to lists before we can view them: *}
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value "show (vars(Plus (V ''x'') (V ''y'')))"
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instantiation bexp :: vars
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begin
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fun vars_bexp :: "bexp \<Rightarrow> name set" where
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"vars_bexp (B bv) = {}" |
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"vars_bexp (Not b) = vars_bexp b" |
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"vars_bexp (And b\<^isub>1 b\<^isub>2) = vars_bexp b\<^isub>1 \<union> vars_bexp b\<^isub>2" |
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"vars_bexp (Less a\<^isub>1 a\<^isub>2) = vars a\<^isub>1 \<union> vars a\<^isub>2"
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instance ..
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end
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value "show (vars(Less (Plus (V ''z'') (V ''y'')) (V ''x'')))"
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abbreviation
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eq_on :: "('a \<Rightarrow> 'b) \<Rightarrow> ('a \<Rightarrow> 'b) \<Rightarrow> 'a set \<Rightarrow> bool"
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("(_ =/ _/ on _)" [50,0,50] 50) where
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"f = g on X == \<forall> x \<in> X. f x = g x"
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lemma aval_eq_if_eq_on_vars[simp]:
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"s\<^isub>1 = s\<^isub>2 on vars a \<Longrightarrow> aval a s\<^isub>1 = aval a s\<^isub>2"
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apply(induction a)
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apply simp_all
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done
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lemma bval_eq_if_eq_on_vars:
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"s\<^isub>1 = s\<^isub>2 on vars b \<Longrightarrow> bval b s\<^isub>1 = bval b s\<^isub>2"
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proof(induction b)
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case (Less a1 a2)
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hence "aval a1 s\<^isub>1 = aval a1 s\<^isub>2" and "aval a2 s\<^isub>1 = aval a2 s\<^isub>2" by simp_all
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thus ?case by simp
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qed simp_all
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end
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