src/HOL/Isar_examples/Fibonacci.thy
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     1 (*  Title:      HOL/Isar_examples/Fibonacci.thy
       
     2     Author:     Gertrud Bauer
       
     3     Copyright   1999 Technische Universitaet Muenchen
       
     4 
       
     5 The Fibonacci function.  Demonstrates the use of recdef.  Original
       
     6 tactic script by Lawrence C Paulson.
       
     7 
       
     8 Fibonacci numbers: proofs of laws taken from
       
     9 
       
    10   R. L. Graham, D. E. Knuth, O. Patashnik.
       
    11   Concrete Mathematics.
       
    12   (Addison-Wesley, 1989)
       
    13 *)
       
    14 
       
    15 header {* Fib and Gcd commute *}
       
    16 
       
    17 theory Fibonacci
       
    18 imports Primes
       
    19 begin
       
    20 
       
    21 text_raw {*
       
    22  \footnote{Isar version by Gertrud Bauer.  Original tactic script by
       
    23  Larry Paulson.  A few proofs of laws taken from
       
    24  \cite{Concrete-Math}.}
       
    25 *}
       
    26 
       
    27 
       
    28 subsection {* Fibonacci numbers *}
       
    29 
       
    30 fun fib :: "nat \<Rightarrow> nat" where
       
    31   "fib 0 = 0"
       
    32   | "fib (Suc 0) = 1"
       
    33   | "fib (Suc (Suc x)) = fib x + fib (Suc x)"
       
    34 
       
    35 lemma [simp]: "0 < fib (Suc n)"
       
    36   by (induct n rule: fib.induct) simp_all
       
    37 
       
    38 
       
    39 text {* Alternative induction rule. *}
       
    40 
       
    41 theorem fib_induct:
       
    42     "P 0 ==> P 1 ==> (!!n. P (n + 1) ==> P n ==> P (n + 2)) ==> P (n::nat)"
       
    43   by (induct rule: fib.induct) simp_all
       
    44 
       
    45 
       
    46 subsection {* Fib and gcd commute *}
       
    47 
       
    48 text {* A few laws taken from \cite{Concrete-Math}. *}
       
    49 
       
    50 lemma fib_add:
       
    51   "fib (n + k + 1) = fib (k + 1) * fib (n + 1) + fib k * fib n"
       
    52   (is "?P n")
       
    53   -- {* see \cite[page 280]{Concrete-Math} *}
       
    54 proof (induct n rule: fib_induct)
       
    55   show "?P 0" by simp
       
    56   show "?P 1" by simp
       
    57   fix n
       
    58   have "fib (n + 2 + k + 1)
       
    59     = fib (n + k + 1) + fib (n + 1 + k + 1)" by simp
       
    60   also assume "fib (n + k + 1)
       
    61     = fib (k + 1) * fib (n + 1) + fib k * fib n"
       
    62       (is " _ = ?R1")
       
    63   also assume "fib (n + 1 + k + 1)
       
    64     = fib (k + 1) * fib (n + 1 + 1) + fib k * fib (n + 1)"
       
    65       (is " _ = ?R2")
       
    66   also have "?R1 + ?R2
       
    67     = fib (k + 1) * fib (n + 2 + 1) + fib k * fib (n + 2)"
       
    68     by (simp add: add_mult_distrib2)
       
    69   finally show "?P (n + 2)" .
       
    70 qed
       
    71 
       
    72 lemma gcd_fib_Suc_eq_1: "gcd (fib n) (fib (n + 1)) = 1" (is "?P n")
       
    73 proof (induct n rule: fib_induct)
       
    74   show "?P 0" by simp
       
    75   show "?P 1" by simp
       
    76   fix n
       
    77   have "fib (n + 2 + 1) = fib (n + 1) + fib (n + 2)"
       
    78     by simp
       
    79   also have "gcd (fib (n + 2)) ... = gcd (fib (n + 2)) (fib (n + 1))"
       
    80     by (simp only: gcd_add2')
       
    81   also have "... = gcd (fib (n + 1)) (fib (n + 1 + 1))"
       
    82     by (simp add: gcd_commute)
       
    83   also assume "... = 1"
       
    84   finally show "?P (n + 2)" .
       
    85 qed
       
    86 
       
    87 lemma gcd_mult_add: "0 < n ==> gcd (n * k + m) n = gcd m n"
       
    88 proof -
       
    89   assume "0 < n"
       
    90   then have "gcd (n * k + m) n = gcd n (m mod n)"
       
    91     by (simp add: gcd_non_0 add_commute)
       
    92   also from `0 < n` have "... = gcd m n" by (simp add: gcd_non_0)
       
    93   finally show ?thesis .
       
    94 qed
       
    95 
       
    96 lemma gcd_fib_add: "gcd (fib m) (fib (n + m)) = gcd (fib m) (fib n)"
       
    97 proof (cases m)
       
    98   case 0
       
    99   then show ?thesis by simp
       
   100 next
       
   101   case (Suc k)
       
   102   then have "gcd (fib m) (fib (n + m)) = gcd (fib (n + k + 1)) (fib (k + 1))"
       
   103     by (simp add: gcd_commute)
       
   104   also have "fib (n + k + 1)
       
   105     = fib (k + 1) * fib (n + 1) + fib k * fib n"
       
   106     by (rule fib_add)
       
   107   also have "gcd ... (fib (k + 1)) = gcd (fib k * fib n) (fib (k + 1))"
       
   108     by (simp add: gcd_mult_add)
       
   109   also have "... = gcd (fib n) (fib (k + 1))"
       
   110     by (simp only: gcd_fib_Suc_eq_1 gcd_mult_cancel)
       
   111   also have "... = gcd (fib m) (fib n)"
       
   112     using Suc by (simp add: gcd_commute)
       
   113   finally show ?thesis .
       
   114 qed
       
   115 
       
   116 lemma gcd_fib_diff:
       
   117   assumes "m <= n"
       
   118   shows "gcd (fib m) (fib (n - m)) = gcd (fib m) (fib n)"
       
   119 proof -
       
   120   have "gcd (fib m) (fib (n - m)) = gcd (fib m) (fib (n - m + m))"
       
   121     by (simp add: gcd_fib_add)
       
   122   also from `m <= n` have "n - m + m = n" by simp
       
   123   finally show ?thesis .
       
   124 qed
       
   125 
       
   126 lemma gcd_fib_mod:
       
   127   assumes "0 < m"
       
   128   shows "gcd (fib m) (fib (n mod m)) = gcd (fib m) (fib n)"
       
   129 proof (induct n rule: nat_less_induct)
       
   130   case (1 n) note hyp = this
       
   131   show ?case
       
   132   proof -
       
   133     have "n mod m = (if n < m then n else (n - m) mod m)"
       
   134       by (rule mod_if)
       
   135     also have "gcd (fib m) (fib ...) = gcd (fib m) (fib n)"
       
   136     proof (cases "n < m")
       
   137       case True then show ?thesis by simp
       
   138     next
       
   139       case False then have "m <= n" by simp
       
   140       from `0 < m` and False have "n - m < n" by simp
       
   141       with hyp have "gcd (fib m) (fib ((n - m) mod m))
       
   142         = gcd (fib m) (fib (n - m))" by simp
       
   143       also have "... = gcd (fib m) (fib n)"
       
   144         using `m <= n` by (rule gcd_fib_diff)
       
   145       finally have "gcd (fib m) (fib ((n - m) mod m)) =
       
   146         gcd (fib m) (fib n)" .
       
   147       with False show ?thesis by simp
       
   148     qed
       
   149     finally show ?thesis .
       
   150   qed
       
   151 qed
       
   152 
       
   153 
       
   154 theorem fib_gcd: "fib (gcd m n) = gcd (fib m) (fib n)" (is "?P m n")
       
   155 proof (induct m n rule: gcd_induct)
       
   156   fix m show "fib (gcd m 0) = gcd (fib m) (fib 0)" by simp
       
   157   fix n :: nat assume n: "0 < n"
       
   158   then have "gcd m n = gcd n (m mod n)" by (rule gcd_non_0)
       
   159   also assume hyp: "fib ... = gcd (fib n) (fib (m mod n))"
       
   160   also from n have "... = gcd (fib n) (fib m)" by (rule gcd_fib_mod)
       
   161   also have "... = gcd (fib m) (fib n)" by (rule gcd_commute)
       
   162   finally show "fib (gcd m n) = gcd (fib m) (fib n)" .
       
   163 qed
       
   164 
       
   165 end