--- /dev/null Thu Jan 01 00:00:00 1970 +0000
+++ b/src/HOL/Isar_Examples/Group_Context.thy Tue Apr 03 16:53:32 2012 +0200
@@ -0,0 +1,94 @@
+(* Title: HOL/Isar_Examples/Group_Context.thy
+ Author: Makarius
+*)
+
+header {* Some algebraic identities derived from group axioms -- theory context version *}
+
+theory Group_Context
+imports Main
+begin
+
+text {* hypothetical group axiomatization *}
+
+context
+ fixes prod :: "'a \<Rightarrow> 'a \<Rightarrow> 'a" (infixl "**" 70)
+ and one :: "'a"
+ and inverse :: "'a => 'a"
+ assumes assoc: "\<And>x y z. (x ** y) ** z = x ** (y ** z)"
+ and left_one: "\<And>x. one ** x = x"
+ and left_inverse: "\<And>x. inverse x ** x = one"
+begin
+
+text {* some consequences *}
+
+lemma right_inverse: "x ** inverse x = one"
+proof -
+ have "x ** inverse x = one ** (x ** inverse x)"
+ by (simp only: left_one)
+ also have "\<dots> = one ** x ** inverse x"
+ by (simp only: assoc)
+ also have "\<dots> = inverse (inverse x) ** inverse x ** x ** inverse x"
+ by (simp only: left_inverse)
+ also have "\<dots> = inverse (inverse x) ** (inverse x ** x) ** inverse x"
+ by (simp only: assoc)
+ also have "\<dots> = inverse (inverse x) ** one ** inverse x"
+ by (simp only: left_inverse)
+ also have "\<dots> = inverse (inverse x) ** (one ** inverse x)"
+ by (simp only: assoc)
+ also have "\<dots> = inverse (inverse x) ** inverse x"
+ by (simp only: left_one)
+ also have "\<dots> = one"
+ by (simp only: left_inverse)
+ finally show "x ** inverse x = one" .
+qed
+
+lemma right_one: "x ** one = x"
+proof -
+ have "x ** one = x ** (inverse x ** x)"
+ by (simp only: left_inverse)
+ also have "\<dots> = x ** inverse x ** x"
+ by (simp only: assoc)
+ also have "\<dots> = one ** x"
+ by (simp only: right_inverse)
+ also have "\<dots> = x"
+ by (simp only: left_one)
+ finally show "x ** one = x" .
+qed
+
+lemma one_equality: "e ** x = x \<Longrightarrow> one = e"
+proof -
+ fix e x
+ assume eq: "e ** x = x"
+ have "one = x ** inverse x"
+ by (simp only: right_inverse)
+ also have "\<dots> = (e ** x) ** inverse x"
+ by (simp only: eq)
+ also have "\<dots> = e ** (x ** inverse x)"
+ by (simp only: assoc)
+ also have "\<dots> = e ** one"
+ by (simp only: right_inverse)
+ also have "\<dots> = e"
+ by (simp only: right_one)
+ finally show "one = e" .
+qed
+
+lemma inverse_equality: "x' ** x = one \<Longrightarrow> inverse x = x'"
+proof -
+ fix x x'
+ assume eq: "x' ** x = one"
+ have "inverse x = one ** inverse x"
+ by (simp only: left_one)
+ also have "\<dots> = (x' ** x) ** inverse x"
+ by (simp only: eq)
+ also have "\<dots> = x' ** (x ** inverse x)"
+ by (simp only: assoc)
+ also have "\<dots> = x' ** one"
+ by (simp only: right_inverse)
+ also have "\<dots> = x'"
+ by (simp only: right_one)
+ finally show "inverse x = x'" .
+qed
+
+end
+
+end