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doc-src/TutorialI/CTL/CTL.thy

author | wenzelm |

Thu, 09 Nov 2006 11:58:43 +0100 | |

changeset 21260 | 11ba04d15f36 |

parent 18724 | cb6e0064c88c |

child 27015 | f8537d69f514 |

permissions | -rw-r--r-- |

lfp_induct_set;

(*<*)theory CTL imports Base begin(*>*) subsection{*Computation Tree Logic --- CTL*}; text{*\label{sec:CTL} \index{CTL|(}% The semantics of PDL only needs reflexive transitive closure. Let us be adventurous and introduce a more expressive temporal operator. We extend the datatype @{text formula} by a new constructor *}; (*<*) datatype formula = Atom "atom" | Neg formula | And formula formula | AX formula | EF formula(*>*) | AF formula; text{*\noindent which stands for ``\emph{A}lways in the \emph{F}uture'': on all infinite paths, at some point the formula holds. Formalizing the notion of an infinite path is easy in HOL: it is simply a function from @{typ nat} to @{typ state}. *}; constdefs Paths :: "state \<Rightarrow> (nat \<Rightarrow> state)set" "Paths s \<equiv> {p. s = p 0 \<and> (\<forall>i. (p i, p(i+1)) \<in> M)}"; text{*\noindent This definition allows a succinct statement of the semantics of @{const AF}: \footnote{Do not be misled: neither datatypes nor recursive functions can be extended by new constructors or equations. This is just a trick of the presentation (see \S\ref{sec:doc-prep-suppress}). In reality one has to define a new datatype and a new function.} *}; (*<*) consts valid :: "state \<Rightarrow> formula \<Rightarrow> bool" ("(_ \<Turnstile> _)" [80,80] 80); primrec "s \<Turnstile> Atom a = (a \<in> L s)" "s \<Turnstile> Neg f = (~(s \<Turnstile> f))" "s \<Turnstile> And f g = (s \<Turnstile> f \<and> s \<Turnstile> g)" "s \<Turnstile> AX f = (\<forall>t. (s,t) \<in> M \<longrightarrow> t \<Turnstile> f)" "s \<Turnstile> EF f = (\<exists>t. (s,t) \<in> M\<^sup>* \<and> t \<Turnstile> f)" (*>*) "s \<Turnstile> AF f = (\<forall>p \<in> Paths s. \<exists>i. p i \<Turnstile> f)"; text{*\noindent Model checking @{const AF} involves a function which is just complicated enough to warrant a separate definition: *}; constdefs af :: "state set \<Rightarrow> state set \<Rightarrow> state set" "af A T \<equiv> A \<union> {s. \<forall>t. (s, t) \<in> M \<longrightarrow> t \<in> T}"; text{*\noindent Now we define @{term "mc(AF f)"} as the least set @{term T} that includes @{term"mc f"} and all states all of whose direct successors are in @{term T}: *}; (*<*) consts mc :: "formula \<Rightarrow> state set"; primrec "mc(Atom a) = {s. a \<in> L s}" "mc(Neg f) = -mc f" "mc(And f g) = mc f \<inter> mc g" "mc(AX f) = {s. \<forall>t. (s,t) \<in> M \<longrightarrow> t \<in> mc f}" "mc(EF f) = lfp(\<lambda>T. mc f \<union> M\<inverse> `` T)"(*>*) "mc(AF f) = lfp(af(mc f))"; text{*\noindent Because @{const af} is monotone in its second argument (and also its first, but that is irrelevant), @{term"af A"} has a least fixed point: *}; lemma mono_af: "mono(af A)"; apply(simp add: mono_def af_def); apply blast; done (*<*) lemma mono_ef: "mono(\<lambda>T. A \<union> M\<inverse> `` T)"; apply(rule monoI); by(blast); lemma EF_lemma: "lfp(\<lambda>T. A \<union> M\<inverse> `` T) = {s. \<exists>t. (s,t) \<in> M\<^sup>* \<and> t \<in> A}"; apply(rule equalityI); apply(rule subsetI); apply(simp); apply(erule lfp_induct_set); apply(rule mono_ef); apply(simp); apply(blast intro: rtrancl_trans); apply(rule subsetI); apply(simp, clarify); apply(erule converse_rtrancl_induct); apply(subst lfp_unfold[OF mono_ef]); apply(blast); apply(subst lfp_unfold[OF mono_ef]); by(blast); (*>*) text{* All we need to prove now is @{prop"mc(AF f) = {s. s \<Turnstile> AF f}"}, which states that @{term mc} and @{text"\<Turnstile>"} agree for @{const AF}\@. This time we prove the two inclusions separately, starting with the easy one: *}; theorem AF_lemma1: "lfp(af A) \<subseteq> {s. \<forall>p \<in> Paths s. \<exists>i. p i \<in> A}"; txt{*\noindent In contrast to the analogous proof for @{const EF}, and just for a change, we do not use fixed point induction. Park-induction, named after David Park, is weaker but sufficient for this proof: \begin{center} @{thm lfp_lowerbound[of _ "S",no_vars]} \hfill (@{thm[source]lfp_lowerbound}) \end{center} The instance of the premise @{prop"f S \<subseteq> S"} is proved pointwise, a decision that \isa{auto} takes for us: *}; apply(rule lfp_lowerbound); apply(auto simp add: af_def Paths_def); txt{* @{subgoals[display,indent=0,margin=70,goals_limit=1]} In this remaining case, we set @{term t} to @{term"p(1::nat)"}. The rest is automatic, which is surprising because it involves finding the instantiation @{term"\<lambda>i::nat. p(i+1)"} for @{text"\<forall>p"}. *}; apply(erule_tac x = "p 1" in allE); apply(auto); done; text{* The opposite inclusion is proved by contradiction: if some state @{term s} is not in @{term"lfp(af A)"}, then we can construct an infinite @{term A}-avoiding path starting from~@{term s}. The reason is that by unfolding @{const lfp} we find that if @{term s} is not in @{term"lfp(af A)"}, then @{term s} is not in @{term A} and there is a direct successor of @{term s} that is again not in \mbox{@{term"lfp(af A)"}}. Iterating this argument yields the promised infinite @{term A}-avoiding path. Let us formalize this sketch. The one-step argument in the sketch above is proved by a variant of contraposition: *}; lemma not_in_lfp_afD: "s \<notin> lfp(af A) \<Longrightarrow> s \<notin> A \<and> (\<exists> t. (s,t) \<in> M \<and> t \<notin> lfp(af A))"; apply(erule contrapos_np); apply(subst lfp_unfold[OF mono_af]); apply(simp add: af_def); done; text{*\noindent We assume the negation of the conclusion and prove @{term"s : lfp(af A)"}. Unfolding @{const lfp} once and simplifying with the definition of @{const af} finishes the proof. Now we iterate this process. The following construction of the desired path is parameterized by a predicate @{term Q} that should hold along the path: *}; consts path :: "state \<Rightarrow> (state \<Rightarrow> bool) \<Rightarrow> (nat \<Rightarrow> state)"; primrec "path s Q 0 = s" "path s Q (Suc n) = (SOME t. (path s Q n,t) \<in> M \<and> Q t)"; text{*\noindent Element @{term"n+1::nat"} on this path is some arbitrary successor @{term t} of element @{term n} such that @{term"Q t"} holds. Remember that @{text"SOME t. R t"} is some arbitrary but fixed @{term t} such that @{prop"R t"} holds (see \S\ref{sec:SOME}). Of course, such a @{term t} need not exist, but that is of no concern to us since we will only use @{const path} when a suitable @{term t} does exist. Let us show that if each state @{term s} that satisfies @{term Q} has a successor that again satisfies @{term Q}, then there exists an infinite @{term Q}-path: *}; lemma infinity_lemma: "\<lbrakk> Q s; \<forall>s. Q s \<longrightarrow> (\<exists> t. (s,t) \<in> M \<and> Q t) \<rbrakk> \<Longrightarrow> \<exists>p\<in>Paths s. \<forall>i. Q(p i)"; txt{*\noindent First we rephrase the conclusion slightly because we need to prove simultaneously both the path property and the fact that @{term Q} holds: *}; apply(subgoal_tac "\<exists>p. s = p 0 \<and> (\<forall>i::nat. (p i, p(i+1)) \<in> M \<and> Q(p i))"); txt{*\noindent From this proposition the original goal follows easily: *}; apply(simp add: Paths_def, blast); txt{*\noindent The new subgoal is proved by providing the witness @{term "path s Q"} for @{term p}: *}; apply(rule_tac x = "path s Q" in exI); apply(clarsimp); txt{*\noindent After simplification and clarification, the subgoal has the following form: @{subgoals[display,indent=0,margin=70,goals_limit=1]} It invites a proof by induction on @{term i}: *}; apply(induct_tac i); apply(simp); txt{*\noindent After simplification, the base case boils down to @{subgoals[display,indent=0,margin=70,goals_limit=1]} The conclusion looks exceedingly trivial: after all, @{term t} is chosen such that @{prop"(s,t):M"} holds. However, we first have to show that such a @{term t} actually exists! This reasoning is embodied in the theorem @{thm[source]someI2_ex}: @{thm[display,eta_contract=false]someI2_ex} When we apply this theorem as an introduction rule, @{text"?P x"} becomes @{prop"(s, x) : M & Q x"} and @{text"?Q x"} becomes @{prop"(s,x) : M"} and we have to prove two subgoals: @{prop"EX a. (s, a) : M & Q a"}, which follows from the assumptions, and @{prop"(s, x) : M & Q x ==> (s,x) : M"}, which is trivial. Thus it is not surprising that @{text fast} can prove the base case quickly: *}; apply(fast intro: someI2_ex); txt{*\noindent What is worth noting here is that we have used \methdx{fast} rather than @{text blast}. The reason is that @{text blast} would fail because it cannot cope with @{thm[source]someI2_ex}: unifying its conclusion with the current subgoal is non-trivial because of the nested schematic variables. For efficiency reasons @{text blast} does not even attempt such unifications. Although @{text fast} can in principle cope with complicated unification problems, in practice the number of unifiers arising is often prohibitive and the offending rule may need to be applied explicitly rather than automatically. This is what happens in the step case. The induction step is similar, but more involved, because now we face nested occurrences of @{text SOME}. As a result, @{text fast} is no longer able to solve the subgoal and we apply @{thm[source]someI2_ex} by hand. We merely show the proof commands but do not describe the details: *}; apply(simp); apply(rule someI2_ex); apply(blast); apply(rule someI2_ex); apply(blast); apply(blast); done; text{* Function @{const path} has fulfilled its purpose now and can be forgotten. It was merely defined to provide the witness in the proof of the @{thm[source]infinity_lemma}. Aficionados of minimal proofs might like to know that we could have given the witness without having to define a new function: the term @{term[display]"nat_rec s (\<lambda>n t. SOME u. (t,u)\<in>M \<and> Q u)"} is extensionally equal to @{term"path s Q"}, where @{term nat_rec} is the predefined primitive recursor on @{typ nat}. *}; (*<*) lemma "\<lbrakk> Q s; \<forall> s. Q s \<longrightarrow> (\<exists> t. (s,t)\<in>M \<and> Q t) \<rbrakk> \<Longrightarrow> \<exists> p\<in>Paths s. \<forall> i. Q(p i)"; apply(subgoal_tac "\<exists> p. s = p 0 \<and> (\<forall> i. (p i,p(Suc i))\<in>M \<and> Q(p i))"); apply(simp add: Paths_def); apply(blast); apply(rule_tac x = "nat_rec s (\<lambda>n t. SOME u. (t,u)\<in>M \<and> Q u)" in exI); apply(simp); apply(intro strip); apply(induct_tac i); apply(simp); apply(fast intro: someI2_ex); apply(simp); apply(rule someI2_ex); apply(blast); apply(rule someI2_ex); apply(blast); by(blast); (*>*) text{* At last we can prove the opposite direction of @{thm[source]AF_lemma1}: *}; theorem AF_lemma2: "{s. \<forall>p \<in> Paths s. \<exists>i. p i \<in> A} \<subseteq> lfp(af A)"; txt{*\noindent The proof is again pointwise and then by contraposition: *}; apply(rule subsetI); apply(erule contrapos_pp); apply simp; txt{* @{subgoals[display,indent=0,goals_limit=1]} Applying the @{thm[source]infinity_lemma} as a destruction rule leaves two subgoals, the second premise of @{thm[source]infinity_lemma} and the original subgoal: *}; apply(drule infinity_lemma); txt{* @{subgoals[display,indent=0,margin=65]} Both are solved automatically: *}; apply(auto dest: not_in_lfp_afD); done; text{* If you find these proofs too complicated, we recommend that you read \S\ref{sec:CTL-revisited}, where we show how inductive definitions lead to simpler arguments. The main theorem is proved as for PDL, except that we also derive the necessary equality @{text"lfp(af A) = ..."} by combining @{thm[source]AF_lemma1} and @{thm[source]AF_lemma2} on the spot: *} theorem "mc f = {s. s \<Turnstile> f}"; apply(induct_tac f); apply(auto simp add: EF_lemma equalityI[OF AF_lemma1 AF_lemma2]); done text{* The language defined above is not quite CTL\@. The latter also includes an until-operator @{term"EU f g"} with semantics ``there \emph{E}xists a path where @{term f} is true \emph{U}ntil @{term g} becomes true''. We need an auxiliary function: *} consts until:: "state set \<Rightarrow> state set \<Rightarrow> state \<Rightarrow> state list \<Rightarrow> bool" primrec "until A B s [] = (s \<in> B)" "until A B s (t#p) = (s \<in> A \<and> (s,t) \<in> M \<and> until A B t p)" (*<*)constdefs eusem :: "state set \<Rightarrow> state set \<Rightarrow> state set" "eusem A B \<equiv> {s. \<exists>p. until A B s p}"(*>*) text{*\noindent Expressing the semantics of @{term EU} is now straightforward: @{prop[display]"s \<Turnstile> EU f g = (\<exists>p. until {t. t \<Turnstile> f} {t. t \<Turnstile> g} s p)"} Note that @{term EU} is not definable in terms of the other operators! Model checking @{term EU} is again a least fixed point construction: @{text[display]"mc(EU f g) = lfp(\<lambda>T. mc g \<union> mc f \<inter> (M\<inverse> `` T))"} \begin{exercise} Extend the datatype of formulae by the above until operator and prove the equivalence between semantics and model checking, i.e.\ that @{prop[display]"mc(EU f g) = {s. s \<Turnstile> EU f g}"} %For readability you may want to annotate {term EU} with its customary syntax %{text[display]"| EU formula formula E[_ U _]"} %which enables you to read and write {text"E[f U g]"} instead of {term"EU f g"}. \end{exercise} For more CTL exercises see, for example, Huth and Ryan \cite{Huth-Ryan-book}. *} (*<*) constdefs eufix :: "state set \<Rightarrow> state set \<Rightarrow> state set \<Rightarrow> state set" "eufix A B T \<equiv> B \<union> A \<inter> (M\<inverse> `` T)" lemma "lfp(eufix A B) \<subseteq> eusem A B" apply(rule lfp_lowerbound) apply(auto simp add: eusem_def eufix_def); apply(rule_tac x = "[]" in exI); apply simp apply(rule_tac x = "y#xc" in exI); apply simp; done lemma mono_eufix: "mono(eufix A B)"; apply(simp add: mono_def eufix_def); apply blast; done lemma "eusem A B \<subseteq> lfp(eufix A B)"; apply(clarsimp simp add: eusem_def); apply(erule rev_mp); apply(rule_tac x = x in spec); apply(induct_tac p); apply(subst lfp_unfold[OF mono_eufix]) apply(simp add: eufix_def); apply(clarsimp); apply(subst lfp_unfold[OF mono_eufix]) apply(simp add: eufix_def); apply blast; done (* constdefs eusem :: "state set \<Rightarrow> state set \<Rightarrow> state set" "eusem A B \<equiv> {s. \<exists>p\<in>Paths s. \<exists>j. p j \<in> B \<and> (\<forall>i < j. p i \<in> A)}" axioms M_total: "\<exists>t. (s,t) \<in> M" consts apath :: "state \<Rightarrow> (nat \<Rightarrow> state)" primrec "apath s 0 = s" "apath s (Suc i) = (SOME t. (apath s i,t) \<in> M)" lemma [iff]: "apath s \<in> Paths s"; apply(simp add: Paths_def); apply(blast intro: M_total[THEN someI_ex]) done constdefs pcons :: "state \<Rightarrow> (nat \<Rightarrow> state) \<Rightarrow> (nat \<Rightarrow> state)" "pcons s p == \<lambda>i. case i of 0 \<Rightarrow> s | Suc j \<Rightarrow> p j" lemma pcons_PathI: "[| (s,t) : M; p \<in> Paths t |] ==> pcons s p \<in> Paths s"; by(simp add: Paths_def pcons_def split: nat.split); lemma "lfp(eufix A B) \<subseteq> eusem A B" apply(rule lfp_lowerbound) apply(clarsimp simp add: eusem_def eufix_def); apply(erule disjE); apply(rule_tac x = "apath x" in bexI); apply(rule_tac x = 0 in exI); apply simp; apply simp; apply(clarify); apply(rule_tac x = "pcons xb p" in bexI); apply(rule_tac x = "j+1" in exI); apply (simp add: pcons_def split: nat.split); apply (simp add: pcons_PathI) done *) (*>*) text{* Let us close this section with a few words about the executability of our model checkers. It is clear that if all sets are finite, they can be represented as lists and the usual set operations are easily implemented. Only @{const lfp} requires a little thought. Fortunately, theory @{text While_Combinator} in the Library~\cite{HOL-Library} provides a theorem stating that in the case of finite sets and a monotone function~@{term F}, the value of \mbox{@{term"lfp F"}} can be computed by iterated application of @{term F} to~@{term"{}"} until a fixed point is reached. It is actually possible to generate executable functional programs from HOL definitions, but that is beyond the scope of the tutorial.% \index{CTL|)} *} (*<*)end(*>*)