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doc-src/Tutorial/Misc/Exor.thy
author
paulson
Thu, 19 Feb 2004 10:40:28 +0100
changeset 14395
cc96cc06abf9
parent 5377
efb799c5ed3c
permissions
-rw-r--r--
new theorem
Exor = Main +
constdefs
exor :: bool => bool => bool
"exor A B == (A & ~B) | (~A & B)"
end