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doc-src/Tutorial/Misc/Exor.thy
author
nipkow
Wed, 15 May 2002 13:50:16 +0200
changeset 13153
4b052946b41c
parent 5377
efb799c5ed3c
permissions
-rw-r--r--
arith can now deal with div 2 and mod 2.
Exor = Main +
constdefs
exor :: bool => bool => bool
"exor A B == (A & ~B) | (~A & B)"
end