doc-src/Tutorial/Misc/Exor.thy
author paulson
Fri, 02 Mar 2001 13:14:37 +0100
changeset 11188 5d539f1682c3
parent 5377 efb799c5ed3c
permissions -rw-r--r--
streamlined a proof

Exor = Main +
constdefs
 exor :: bool => bool => bool
"exor A B == (A & ~B) | (~A & B)"
end