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doc-src/Tutorial/Recdef/fib
author paulson
Thu, 17 Aug 2000 11:56:47 +0200
changeset 9634 61b57cc1cb5a
parent 6100 40d66bc3e83f
permissions -rw-r--r--
modified proofs: better rules for cancellation of common factors across comparisons

consts fib :: nat => nat
recdef fib "measure(%n. n)"
  "fib 0 = 0"
  "fib 1 = 1"
  "fib (Suc(Suc x)) = fib x + fib (Suc x)"
isabelle