src/HOL/Induct/Comb.thy
author wenzelm
Sun, 31 Oct 1999 20:11:23 +0100
changeset 7990 0a604b2fc2b1
parent 5184 9b8547a9496a
child 9101 b643f4d7b9e9
permissions -rw-r--r--
updated;

(*  Title:      HOL/ex/Comb.thy
    ID:         $Id$
    Author:     Lawrence C Paulson
    Copyright   1996  University of Cambridge

Combinatory Logic example: the Church-Rosser Theorem
Curiously, combinators do not include free variables.

Example taken from
    J. Camilleri and T. F. Melham.
    Reasoning with Inductively Defined Relations in the HOL Theorem Prover.
    Report 265, University of Cambridge Computer Laboratory, 1992.
*)


Comb = Datatype +

(** Datatype definition of combinators S and K, with infixed application **)
datatype comb = K
              | S
              | "#" comb comb (infixl 90)

(** Inductive definition of contractions, -1->
             and (multi-step) reductions, --->
**)
consts
  contract  :: "(comb*comb) set"
  "-1->"    :: [comb,comb] => bool   (infixl 50)
  "--->"    :: [comb,comb] => bool   (infixl 50)

translations
  "x -1-> y" == "(x,y) : contract"
  "x ---> y" == "(x,y) : contract^*"

inductive contract
  intrs
    K     "K#x#y -1-> x"
    S     "S#x#y#z -1-> (x#z)#(y#z)"
    Ap1   "x-1->y ==> x#z -1-> y#z"
    Ap2   "x-1->y ==> z#x -1-> z#y"


(** Inductive definition of parallel contractions, =1=>
             and (multi-step) parallel reductions, ===>
**)
consts
  parcontract :: "(comb*comb) set"
  "=1=>"    :: [comb,comb] => bool   (infixl 50)
  "===>"    :: [comb,comb] => bool   (infixl 50)

translations
  "x =1=> y" == "(x,y) : parcontract"
  "x ===> y" == "(x,y) : parcontract^*"

inductive parcontract
  intrs
    refl  "x =1=> x"
    K     "K#x#y =1=> x"
    S     "S#x#y#z =1=> (x#z)#(y#z)"
    Ap    "[| x=1=>y;  z=1=>w |] ==> x#z =1=> y#w"


(*Misc definitions*)
constdefs
  I :: comb
  "I == S#K#K"

  (*confluence; Lambda/Commutation treats this more abstractly*)
  diamond   :: "('a * 'a)set => bool"	
  "diamond(r) == ALL x y. (x,y):r --> 
                  (ALL y'. (x,y'):r --> 
                    (EX z. (y,z):r & (y',z) : r))"

end