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doc-src/Tutorial/Misc/Exor.thy
author
nipkow
Fri, 12 Nov 1999 17:45:36 +0100
changeset 8016
b7713108ffd8
parent 5377
efb799c5ed3c
permissions
-rw-r--r--
Added the proof by Nielson & Nielson.
Exor = Main +
constdefs
exor :: bool => bool => bool
"exor A B == (A & ~B) | (~A & B)"
end