fix bug in cancel_factor simprocs so they will work on goals like 'x * y < x * z' where the common term is already on the left
(* Title: HOL/Old_Number_Theory/Fib.thy
Author: Lawrence C Paulson, Cambridge University Computer Laboratory
Copyright 1997 University of Cambridge
*)
header {* The Fibonacci function *}
theory Fib
imports Primes
begin
text {*
Fibonacci numbers: proofs of laws taken from:
R. L. Graham, D. E. Knuth, O. Patashnik. Concrete Mathematics.
(Addison-Wesley, 1989)
\bigskip
*}
fun fib :: "nat \<Rightarrow> nat"
where
"fib 0 = 0"
| "fib (Suc 0) = 1"
| fib_2: "fib (Suc (Suc n)) = fib n + fib (Suc n)"
text {*
\medskip The difficulty in these proofs is to ensure that the
induction hypotheses are applied before the definition of @{term
fib}. Towards this end, the @{term fib} equations are not declared
to the Simplifier and are applied very selectively at first.
*}
text{*We disable @{text fib.fib_2fib_2} for simplification ...*}
declare fib_2 [simp del]
text{*...then prove a version that has a more restrictive pattern.*}
lemma fib_Suc3: "fib (Suc (Suc (Suc n))) = fib (Suc n) + fib (Suc (Suc n))"
by (rule fib_2)
text {* \medskip Concrete Mathematics, page 280 *}
lemma fib_add: "fib (Suc (n + k)) = fib (Suc k) * fib (Suc n) + fib k * fib n"
proof (induct n rule: fib.induct)
case 1 show ?case by simp
next
case 2 show ?case by (simp add: fib_2)
next
case 3 thus ?case by (simp add: fib_2 add_mult_distrib2)
qed
lemma fib_Suc_neq_0: "fib (Suc n) \<noteq> 0"
apply (induct n rule: fib.induct)
apply (simp_all add: fib_2)
done
lemma fib_Suc_gr_0: "0 < fib (Suc n)"
by (insert fib_Suc_neq_0 [of n], simp)
lemma fib_gr_0: "0 < n ==> 0 < fib n"
by (case_tac n, auto simp add: fib_Suc_gr_0)
text {*
\medskip Concrete Mathematics, page 278: Cassini's identity. The proof is
much easier using integers, not natural numbers!
*}
lemma fib_Cassini_int:
"int (fib (Suc (Suc n)) * fib n) =
(if n mod 2 = 0 then int (fib (Suc n) * fib (Suc n)) - 1
else int (fib (Suc n) * fib (Suc n)) + 1)"
proof(induct n rule: fib.induct)
case 1 thus ?case by (simp add: fib_2)
next
case 2 thus ?case by (simp add: fib_2 mod_Suc)
next
case (3 x)
have "Suc 0 \<noteq> x mod 2 \<longrightarrow> x mod 2 = 0" by presburger
with "3.hyps" show ?case by (simp add: fib.simps add_mult_distrib add_mult_distrib2)
qed
text{*We now obtain a version for the natural numbers via the coercion
function @{term int}.*}
theorem fib_Cassini:
"fib (Suc (Suc n)) * fib n =
(if n mod 2 = 0 then fib (Suc n) * fib (Suc n) - 1
else fib (Suc n) * fib (Suc n) + 1)"
apply (rule int_int_eq [THEN iffD1])
apply (simp add: fib_Cassini_int)
apply (subst of_nat_diff)
apply (insert fib_Suc_gr_0 [of n], simp_all)
done
text {* \medskip Toward Law 6.111 of Concrete Mathematics *}
lemma gcd_fib_Suc_eq_1: "gcd (fib n) (fib (Suc n)) = Suc 0"
apply (induct n rule: fib.induct)
prefer 3
apply (simp add: gcd_commute fib_Suc3)
apply (simp_all add: fib_2)
done
lemma gcd_fib_add: "gcd (fib m) (fib (n + m)) = gcd (fib m) (fib n)"
apply (simp add: gcd_commute [of "fib m"])
apply (case_tac m)
apply simp
apply (simp add: fib_add)
apply (simp add: add_commute gcd_non_0 [OF fib_Suc_gr_0])
apply (simp add: gcd_non_0 [OF fib_Suc_gr_0, symmetric])
apply (simp add: gcd_fib_Suc_eq_1 gcd_mult_cancel)
done
lemma gcd_fib_diff: "m \<le> n ==> gcd (fib m) (fib (n - m)) = gcd (fib m) (fib n)"
by (simp add: gcd_fib_add [symmetric, of _ "n-m"])
lemma gcd_fib_mod: "0 < m ==> gcd (fib m) (fib (n mod m)) = gcd (fib m) (fib n)"
proof (induct n rule: less_induct)
case (less n)
from less.prems have pos_m: "0 < m" .
show "gcd (fib m) (fib (n mod m)) = gcd (fib m) (fib n)"
proof (cases "m < n")
case True note m_n = True
then have m_n': "m \<le> n" by auto
with pos_m have pos_n: "0 < n" by auto
with pos_m m_n have diff: "n - m < n" by auto
have "gcd (fib m) (fib (n mod m)) = gcd (fib m) (fib ((n - m) mod m))"
by (simp add: mod_if [of n]) (insert m_n, auto)
also have "\<dots> = gcd (fib m) (fib (n - m))" by (simp add: less.hyps diff pos_m)
also have "\<dots> = gcd (fib m) (fib n)" by (simp add: gcd_fib_diff m_n')
finally show "gcd (fib m) (fib (n mod m)) = gcd (fib m) (fib n)" .
next
case False then show "gcd (fib m) (fib (n mod m)) = gcd (fib m) (fib n)"
by (cases "m = n") auto
qed
qed
lemma fib_gcd: "fib (gcd m n) = gcd (fib m) (fib n)" -- {* Law 6.111 *}
apply (induct m n rule: gcd_induct)
apply (simp_all add: gcd_non_0 gcd_commute gcd_fib_mod)
done
theorem fib_mult_eq_setsum:
"fib (Suc n) * fib n = (\<Sum>k \<in> {..n}. fib k * fib k)"
apply (induct n rule: fib.induct)
apply (auto simp add: atMost_Suc fib_2)
apply (simp add: add_mult_distrib add_mult_distrib2)
done
end