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author | nipkow |

Mon, 23 Sep 2019 17:15:29 +0200 | |

changeset 70747 | 548420d389ea |

parent 70745 | be8e617b6eb3 |

child 70748 | b3b84b71e398 |

Enforced precodition "n <= length xs" to avoid relying on "hd []".

--- a/src/HOL/Data_Structures/Balance.thy Mon Sep 23 08:43:52 2019 +0200 +++ b/src/HOL/Data_Structures/Balance.thy Mon Sep 23 17:15:29 2019 +0200 @@ -38,43 +38,32 @@ in (Node l (hd ys) r, zs))" by(simp_all add: bal.simps) -text\<open>Some of the following lemmas take advantage of the fact -that \<open>bal xs n\<close> yields a result even if \<open>n > length xs\<close>.\<close> - -lemma size_bal: "bal n xs = (t,ys) \<Longrightarrow> size t = n" -proof(induction n xs arbitrary: t ys rule: bal.induct) - case (1 n xs) - thus ?case - by(cases "n=0") - (auto simp add: bal_simps Let_def split: prod.splits) -qed - lemma bal_inorder: - "\<lbrakk> bal n xs = (t,ys); n \<le> length xs \<rbrakk> - \<Longrightarrow> inorder t = take n xs \<and> ys = drop n xs" -proof(induction n xs arbitrary: t ys rule: bal.induct) + "\<lbrakk> n \<le> length xs; bal n xs = (t,zs) \<rbrakk> + \<Longrightarrow> inorder t = take n xs \<and> zs = drop n xs" +proof(induction n xs arbitrary: t zs rule: bal.induct) case (1 n xs) show ?case proof cases assume "n = 0" thus ?thesis using 1 by (simp add: bal_simps) next assume [arith]: "n \<noteq> 0" - let ?n1 = "n div 2" let ?n2 = "n - 1 - ?n1" - from "1.prems" obtain l r xs' where - b1: "bal ?n1 xs = (l,xs')" and - b2: "bal ?n2 (tl xs') = (r,ys)" and - t: "t = \<langle>l, hd xs', r\<rangle>" + let ?m = "n div 2" let ?m' = "n - 1 - ?m" + from "1.prems"(2) obtain l r ys where + b1: "bal ?m xs = (l,ys)" and + b2: "bal ?m' (tl ys) = (r,zs)" and + t: "t = \<langle>l, hd ys, r\<rangle>" by(auto simp: Let_def bal_simps split: prod.splits) - have IH1: "inorder l = take ?n1 xs \<and> xs' = drop ?n1 xs" - using b1 "1.prems" by(intro "1.IH"(1)) auto - have IH2: "inorder r = take ?n2 (tl xs') \<and> ys = drop ?n2 (tl xs')" - using b1 b2 IH1 "1.prems" by(intro "1.IH"(2)) auto - have "drop (n div 2) xs \<noteq> []" using "1.prems"(2) by simp - hence "hd (drop ?n1 xs) # take ?n2 (tl (drop ?n1 xs)) = take (?n2 + 1) (drop ?n1 xs)" + have IH1: "inorder l = take ?m xs \<and> ys = drop ?m xs" + using b1 "1.prems"(1) by(intro "1.IH"(1)) auto + have IH2: "inorder r = take ?m' (tl ys) \<and> zs = drop ?m' (tl ys)" + using b1 b2 IH1 "1.prems"(1) by(intro "1.IH"(2)) auto + have "drop (n div 2) xs \<noteq> []" using "1.prems"(1) by simp + hence "hd (drop ?m xs) # take ?m' (tl (drop ?m xs)) = take (?m' + 1) (drop ?m xs)" by (metis Suc_eq_plus1 take_Suc) hence *: "inorder t = take n xs" using t IH1 IH2 - using take_add[of ?n1 "?n2+1" xs] by(simp) + using take_add[of ?m "?m'+1" xs] by(simp) have "n - n div 2 + n div 2 = n" by simp - hence "ys = drop n xs" using IH1 IH2 by (simp add: drop_Suc[symmetric]) + hence "zs = drop n xs" using IH1 IH2 by (simp add: drop_Suc[symmetric]) thus ?thesis using * by blast qed qed @@ -93,41 +82,56 @@ corollary inorder_balance_tree[simp]: "inorder(balance_tree t) = inorder t" by(simp add: balance_tree_def inorder_bal_tree) -corollary size_bal_list[simp]: "size(bal_list n xs) = n" + +text\<open>The size lemmas below do not require the precondition @{prop"n \<le> length xs"} +(or @{prop"n \<le> size t"}) that they come with. They could take advantage of the fact +that @{term "bal xs n"} yields a result even if @{prop "n > length xs"}. +In that case the result will contain one or more occurrences of @{term "hd []"}. +However, this is counter-intuitive and does not reflect the execution +in an eager functional language.\<close> + +lemma size_bal: "\<lbrakk> n \<le> length xs; bal n xs = (t,zs) \<rbrakk> \<Longrightarrow> size t = n \<and> length zs = length xs - n" +by (metis bal_inorder length_drop length_inorder length_take min.absorb2) + +corollary size_bal_list[simp]: "n \<le> length xs \<Longrightarrow> size(bal_list n xs) = n" unfolding bal_list_def by (metis prod.collapse size_bal) corollary size_balance_list[simp]: "size(balance_list xs) = length xs" by (simp add: balance_list_def) -corollary size_bal_tree[simp]: "size(bal_tree n t) = n" +corollary size_bal_tree[simp]: "n \<le> size t \<Longrightarrow> size(bal_tree n t) = n" by(simp add: bal_tree_def) corollary size_balance_tree[simp]: "size(balance_tree t) = size t" by(simp add: balance_tree_def) +lemma pre_rec2: "\<lbrakk> n \<le> length xs; bal (n div 2) xs = (l, ys) \<rbrakk> + \<Longrightarrow> (n - 1 - n div 2) \<le> length(tl ys)" +using size_bal[of "n div 2" xs l ys] by simp + lemma min_height_bal: - "bal n xs = (t,ys) \<Longrightarrow> min_height t = nat(\<lfloor>log 2 (n + 1)\<rfloor>)" -proof(induction n xs arbitrary: t ys rule: bal.induct) - case (1 n xs) show ?case + "\<lbrakk> n \<le> length xs; bal n xs = (t,zs) \<rbrakk> \<Longrightarrow> min_height t = nat(\<lfloor>log 2 (n + 1)\<rfloor>)" +proof(induction n xs arbitrary: t zs rule: bal.induct) + case (1 n xs) + show ?case proof cases - assume "n = 0" thus ?thesis - using "1.prems" by (simp add: bal_simps) + assume "n = 0" thus ?thesis using "1.prems"(2) by (simp add: bal_simps) next assume [arith]: "n \<noteq> 0" - from "1.prems" obtain l r xs' where - b1: "bal (n div 2) xs = (l,xs')" and - b2: "bal (n - 1 - n div 2) (tl xs') = (r,ys)" and - t: "t = \<langle>l, hd xs', r\<rangle>" + from "1.prems" obtain l r ys where + b1: "bal (n div 2) xs = (l,ys)" and + b2: "bal (n - 1 - n div 2) (tl ys) = (r,zs)" and + t: "t = \<langle>l, hd ys, r\<rangle>" by(auto simp: bal_simps Let_def split: prod.splits) let ?log1 = "nat (floor(log 2 (n div 2 + 1)))" let ?log2 = "nat (floor(log 2 (n - 1 - n div 2 + 1)))" - have IH1: "min_height l = ?log1" using "1.IH"(1) b1 by simp - have IH2: "min_height r = ?log2" using "1.IH"(2) b1 b2 by simp + have IH1: "min_height l = ?log1" using "1.IH"(1) b1 "1.prems"(1) by simp + have IH2: "min_height r = ?log2" + using "1.prems"(1) size_bal[OF _ b1] size_bal[OF _ b2] b1 b2 by(intro "1.IH"(2)) auto have "(n+1) div 2 \<ge> 1" by arith hence 0: "log 2 ((n+1) div 2) \<ge> 0" by simp have "n - 1 - n div 2 + 1 \<le> n div 2 + 1" by arith - hence le: "?log2 \<le> ?log1" - by(simp add: nat_mono floor_mono) + hence le: "?log2 \<le> ?log1" by(simp add: nat_mono floor_mono) have "min_height t = min ?log1 ?log2 + 1" by (simp add: t IH1 IH2) also have "\<dots> = ?log2 + 1" using le by (simp add: min_absorb2) also have "n - 1 - n div 2 + 1 = (n+1) div 2" by linarith @@ -141,24 +145,27 @@ qed lemma height_bal: - "bal n xs = (t,ys) \<Longrightarrow> height t = nat \<lceil>log 2 (n + 1)\<rceil>" -proof(induction n xs arbitrary: t ys rule: bal.induct) + "\<lbrakk> n \<le> length xs; bal n xs = (t,zs) \<rbrakk> \<Longrightarrow> height t = nat \<lceil>log 2 (n + 1)\<rceil>" +proof(induction n xs arbitrary: t zs rule: bal.induct) case (1 n xs) show ?case proof cases assume "n = 0" thus ?thesis using "1.prems" by (simp add: bal_simps) next assume [arith]: "n \<noteq> 0" - from "1.prems" obtain l r xs' where - b1: "bal (n div 2) xs = (l,xs')" and - b2: "bal (n - 1 - n div 2) (tl xs') = (r,ys)" and - t: "t = \<langle>l, hd xs', r\<rangle>" + from "1.prems" obtain l r ys where + b1: "bal (n div 2) xs = (l,ys)" and + b2: "bal (n - 1 - n div 2) (tl ys) = (r,zs)" and + t: "t = \<langle>l, hd ys, r\<rangle>" by(auto simp: bal_simps Let_def split: prod.splits) let ?log1 = "nat \<lceil>log 2 (n div 2 + 1)\<rceil>" let ?log2 = "nat \<lceil>log 2 (n - 1 - n div 2 + 1)\<rceil>" - have IH1: "height l = ?log1" using "1.IH"(1) b1 by simp - have IH2: "height r = ?log2" using "1.IH"(2) b1 b2 by simp - have 0: "log 2 (n div 2 + 1) \<ge> 0" by auto + have 1: "n div 2 \<le> length xs" using "1.prems"(1) by linarith + have 2: "n - 1 - n div 2 \<le> length (tl ys)" using "1.prems"(1) size_bal[OF 1 b1] by simp + have IH1: "height l = ?log1" using "1.IH"(1) b1 "1.prems"(1) by simp + have IH2: "height r = ?log2" + using b1 b2 size_bal[OF _ b1] size_bal[OF _ b2] "1.prems"(1) by(intro "1.IH"(2)) auto + have 0: "log 2 (n div 2 + 1) \<ge> 0" by simp have "n - 1 - n div 2 + 1 \<le> n div 2 + 1" by arith hence le: "?log2 \<le> ?log1" by(simp add: nat_mono ceiling_mono del: nat_ceiling_le_eq) @@ -172,7 +179,7 @@ qed lemma balanced_bal: - assumes "bal n xs = (t,ys)" shows "balanced t" + assumes "n \<le> length xs" "bal n xs = (t,ys)" shows "balanced t" unfolding balanced_def using height_bal[OF assms] min_height_bal[OF assms] by linarith @@ -186,59 +193,59 @@ by (simp add: balance_list_def height_bal_list) corollary height_bal_tree: - "n \<le> length xs \<Longrightarrow> height (bal_tree n t) = nat\<lceil>log 2 (n + 1)\<rceil>" + "n \<le> size t \<Longrightarrow> height (bal_tree n t) = nat\<lceil>log 2 (n + 1)\<rceil>" unfolding bal_list_def bal_tree_def -using height_bal prod.exhaust_sel by blast +by (metis bal_list_def height_bal_list length_inorder) corollary height_balance_tree: "height (balance_tree t) = nat\<lceil>log 2 (size t + 1)\<rceil>" by (simp add: bal_tree_def balance_tree_def height_bal_list) -corollary balanced_bal_list[simp]: "balanced (bal_list n xs)" +corollary balanced_bal_list[simp]: "n \<le> length xs \<Longrightarrow> balanced (bal_list n xs)" unfolding bal_list_def by (metis balanced_bal prod.collapse) corollary balanced_balance_list[simp]: "balanced (balance_list xs)" by (simp add: balance_list_def) -corollary balanced_bal_tree[simp]: "balanced (bal_tree n t)" +corollary balanced_bal_tree[simp]: "n \<le> size t \<Longrightarrow> balanced (bal_tree n t)" by (simp add: bal_tree_def) corollary balanced_balance_tree[simp]: "balanced (balance_tree t)" by (simp add: balance_tree_def) -lemma wbalanced_bal: "bal n xs = (t,ys) \<Longrightarrow> wbalanced t" +lemma wbalanced_bal: "\<lbrakk> n \<le> length xs; bal n xs = (t,ys) \<rbrakk> \<Longrightarrow> wbalanced t" proof(induction n xs arbitrary: t ys rule: bal.induct) case (1 n xs) show ?case proof cases assume "n = 0" - thus ?thesis - using "1.prems" by(simp add: bal_simps) + thus ?thesis using "1.prems"(2) by(simp add: bal_simps) next - assume "n \<noteq> 0" + assume [arith]: "n \<noteq> 0" with "1.prems" obtain l ys r zs where rec1: "bal (n div 2) xs = (l, ys)" and rec2: "bal (n - 1 - n div 2) (tl ys) = (r, zs)" and t: "t = \<langle>l, hd ys, r\<rangle>" by(auto simp add: bal_simps Let_def split: prod.splits) - have l: "wbalanced l" using "1.IH"(1)[OF \<open>n\<noteq>0\<close> refl rec1] . - have "wbalanced r" using "1.IH"(2)[OF \<open>n\<noteq>0\<close> refl rec1[symmetric] refl rec2] . - with l t size_bal[OF rec1] size_bal[OF rec2] + have l: "wbalanced l" using "1.IH"(1)[OF \<open>n\<noteq>0\<close> refl _ rec1] "1.prems"(1) by linarith + have "wbalanced r" + using rec1 rec2 pre_rec2[OF "1.prems"(1) rec1] by(intro "1.IH"(2)) auto + with l t size_bal[OF _ rec1] size_bal[OF _ rec2] "1.prems"(1) show ?thesis by auto qed qed text\<open>An alternative proof via @{thm balanced_if_wbalanced}:\<close> -lemma "bal n xs = (t,ys) \<Longrightarrow> balanced t" +lemma "\<lbrakk> n \<le> length xs; bal n xs = (t,ys) \<rbrakk> \<Longrightarrow> balanced t" by(rule balanced_if_wbalanced[OF wbalanced_bal]) -lemma wbalanced_bal_list[simp]: "wbalanced (bal_list n xs)" +lemma wbalanced_bal_list[simp]: "n \<le> length xs \<Longrightarrow> wbalanced (bal_list n xs)" by(simp add: bal_list_def) (metis prod.collapse wbalanced_bal) lemma wbalanced_balance_list[simp]: "wbalanced (balance_list xs)" by(simp add: balance_list_def) -lemma wbalanced_bal_tree[simp]: "wbalanced (bal_tree n t)" +lemma wbalanced_bal_tree[simp]: "n \<le> size t \<Longrightarrow> wbalanced (bal_tree n t)" by(simp add: bal_tree_def) lemma wbalanced_balance_tree: "wbalanced (balance_tree t)"