author | wenzelm |
Thu, 22 Dec 2005 00:28:52 +0100 | |
changeset 18466 | 389a6f9c31f4 |
parent 18019 | d1ff9ebb8bcb |
child 18663 | 8474756e4cbf |
permissions | -rw-r--r-- |
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(* Title: Pure/Pure.thy |
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ID: $Id$ |
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*) |
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header {* The Pure theory *} |
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theory Pure |
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imports ProtoPure |
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begin |
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setup "Context.setup ()" |
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subsection {* Meta-level connectives in assumptions *} |
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lemma meta_mp: |
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assumes "PROP P ==> PROP Q" and "PROP P" |
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shows "PROP Q" |
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by (rule `PROP P ==> PROP Q` [OF `PROP P`]) |
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lemma meta_spec: |
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assumes "!!x. PROP P(x)" |
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shows "PROP P(x)" |
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by (rule `!!x. PROP P(x)`) |
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lemmas meta_allE = meta_spec [elim_format] |
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subsection {* Meta-level conjunction *} |
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locale (open) meta_conjunction_syntax = |
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fixes meta_conjunction :: "prop => prop => prop" (infixr "&&" 2) |
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parse_translation {* |
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[("\<^fixed>meta_conjunction", fn [t, u] => Logic.mk_conjunction (t, u))] |
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*} |
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lemma all_conjunction: |
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includes meta_conjunction_syntax |
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shows "(!!x. PROP A(x) && PROP B(x)) == ((!!x. PROP A(x)) && (!!x. PROP B(x)))" |
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proof |
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assume conj: "!!x. PROP A(x) && PROP B(x)" |
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fix X assume r: "(!!x. PROP A(x)) ==> (!!x. PROP B(x)) ==> PROP X" |
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show "PROP X" |
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proof (rule r) |
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fix x |
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from conj show "PROP A(x)" . |
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from conj show "PROP B(x)" . |
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qed |
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next |
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assume conj: "(!!x. PROP A(x)) && (!!x. PROP B(x))" |
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fix x |
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fix X assume r: "PROP A(x) ==> PROP B(x) ==> PROP X" |
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show "PROP X" |
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proof (rule r) |
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show "PROP A(x)" |
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proof (rule conj) |
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assume "!!x. PROP A(x)" |
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then show "PROP A(x)" . |
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qed |
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show "PROP B(x)" |
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proof (rule conj) |
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assume "!!x. PROP B(x)" |
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then show "PROP B(x)" . |
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qed |
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qed |
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qed |
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lemma imp_conjunction [unfolded prop_def]: |
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includes meta_conjunction_syntax |
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shows "(PROP A ==> PROP prop (PROP B && PROP C)) == (PROP A ==> PROP B) && (PROP A ==> PROP C)" |
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proof (unfold prop_def, rule) |
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assume conj: "PROP A ==> PROP B && PROP C" |
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fix X assume r: "(PROP A ==> PROP B) ==> (PROP A ==> PROP C) ==> PROP X" |
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show "PROP X" |
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proof (rule r) |
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assume "PROP A" |
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from conj [OF `PROP A`] show "PROP B" . |
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from conj [OF `PROP A`] show "PROP C" . |
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qed |
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next |
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assume conj: "(PROP A ==> PROP B) && (PROP A ==> PROP C)" |
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assume "PROP A" |
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fix X assume r: "PROP B ==> PROP C ==> PROP X" |
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show "PROP X" |
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proof (rule r) |
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show "PROP B" |
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proof (rule conj) |
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assume "PROP A ==> PROP B" |
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from this [OF `PROP A`] show "PROP B" . |
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qed |
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show "PROP C" |
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proof (rule conj) |
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assume "PROP A ==> PROP C" |
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from this [OF `PROP A`] show "PROP C" . |
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qed |
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qed |
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qed |
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lemma conjunction_imp: |
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includes meta_conjunction_syntax |
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shows "(PROP A && PROP B ==> PROP C) == (PROP A ==> PROP B ==> PROP C)" |
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proof |
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assume r: "PROP A && PROP B ==> PROP C" |
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assume "PROP A" and "PROP B" |
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show "PROP C" by (rule r) - |
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next |
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assume r: "PROP A ==> PROP B ==> PROP C" |
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assume conj: "PROP A && PROP B" |
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show "PROP C" |
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proof (rule r) |
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from conj show "PROP A" . |
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from conj show "PROP B" . |
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qed |
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qed |
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lemma conjunction_assoc: |
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includes meta_conjunction_syntax |
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shows "((PROP A && PROP B) && PROP C) == (PROP A && (PROP B && PROP C))" |
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by (rule equal_intr_rule) (unfold imp_conjunction conjunction_imp) |
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end |