doc-src/TutorialI/Recdef/Nested1.thy
author nipkow
Mon, 09 Oct 2000 10:18:21 +0200
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(*<*)
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theory Nested1 = Nested0:;
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(*>*)
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consts trev  :: "('a,'b)term \<Rightarrow> ('a,'b)term";
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text{*\noindent
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Although the definition of @{term trev} is quite natural, we will have
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overcome a minor difficulty in convincing Isabelle of is termination.
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It is precisely this difficulty that is the \textit{raison d'\^etre} of
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this subsection.
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Defining @{term trev} by \isacommand{recdef} rather than \isacommand{primrec}
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simplifies matters because we are now free to use the recursion equation
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suggested at the end of \S\ref{sec:nested-datatype}:
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*};
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recdef trev "measure size"
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 "trev (Var x)    = Var x"
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 "trev (App f ts) = App f (rev(map trev ts))";
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text{*\noindent
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Remember that function @{term size} is defined for each \isacommand{datatype}.
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However, the definition does not succeed. Isabelle complains about an
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unproved termination condition
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@{term[display]"t : set ts --> size t < Suc (term_list_size ts)"}
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where @{term set} returns the set of elements of a list
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and @{text"term_list_size :: term list \<Rightarrow> nat"} is an auxiliary
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function automatically defined by Isabelle
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(when @{text term} was defined).  First we have to understand why the
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recursive call of @{term trev} underneath @{term map} leads to the above
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condition. The reason is that \isacommand{recdef} ``knows'' that @{term map}
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will apply @{term trev} only to elements of @{term ts}. Thus the above
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condition expresses that the size of the argument @{prop"t : set ts"} of any
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recursive call of @{term trev} is strictly less than @{prop"size(App f ts) =
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Suc(term_list_size ts)"}.  We will now prove the termination condition and
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continue with our definition.  Below we return to the question of how
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\isacommand{recdef} ``knows'' about @{term map}.
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*};
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(*<*)
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end;
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(*>*)