src/HOL/Data_Structures/Braun_Tree.thy
author nipkow
Fri, 26 Oct 2018 15:58:41 +0200
changeset 69195 b6434dce1126
parent 69192 2c4bf4d84de5
child 69196 930dbc6610d0
permissions -rw-r--r--
avoid abbreviation that is used only locally
Ignore whitespace changes - Everywhere: Within whitespace: At end of lines:
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(* Author: Tobias Nipkow *)
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section \<open>Braun Trees\<close>
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theory Braun_Tree
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imports "HOL-Library.Tree_Real"
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begin
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text \<open>Braun Trees were studied by Braun and Rem~\cite{BraunRem}
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and later Hoogerwoord~\cite{Hoogerwoord}.\<close>
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fun braun :: "'a tree \<Rightarrow> bool" where
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"braun Leaf = True" |
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"braun (Node l x r) = ((size l = size r \<or> size l = size r + 1) \<and> braun l \<and> braun r)"
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lemma braun_Node':
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  "braun (Node l x r) = (size r \<le> size l \<and> size l \<le> size r + 1 \<and> braun l \<and> braun r)"
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by auto
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text \<open>The shape of a Braun-tree is uniquely determined by its size:\<close>
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lemma braun_unique: "\<lbrakk> braun (t1::unit tree); braun t2; size t1 = size t2 \<rbrakk> \<Longrightarrow> t1 = t2"
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proof (induction t1 arbitrary: t2)
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  case Leaf thus ?case by simp
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next
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  case (Node l1 _ r1)
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  from Node.prems(3) have "t2 \<noteq> Leaf" by auto
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  then obtain l2 x2 r2 where [simp]: "t2 = Node l2 x2 r2" by (meson neq_Leaf_iff)
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  with Node.prems have "size l1 = size l2 \<and> size r1 = size r2" by auto
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  thus ?case using Node.prems(1,2) Node.IH by auto
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qed
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text \<open>Braun trees are balanced:\<close>
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lemma balanced_if_braun: "braun t \<Longrightarrow> balanced t"
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proof(induction t)
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  case Leaf show ?case by (simp add: balanced_def)
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next
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  case (Node l x r)
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  have "size l = size r \<or> size l = size r + 1" (is "?A \<or> ?B")
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    using Node.prems by simp
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  thus ?case
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  proof
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    assume "?A"
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    thus ?thesis using Node
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      apply(simp add: balanced_def min_def max_def)
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      by (metis Node.IH balanced_optimal le_antisym le_refl)
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  next
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    assume "?B"
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    thus ?thesis using Node by(intro balanced_Node_if_wbal1) auto
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  qed
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qed
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subsection \<open>Numbering Nodes\<close>
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text \<open>We show that a tree is a Braun tree iff a parity-based
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numbering (\<open>braun_indices\<close>) of nodes yields an interval of numbers.\<close>
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fun braun_indices :: "'a tree \<Rightarrow> nat set" where
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"braun_indices Leaf = {}" |
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"braun_indices (Node l _ r) = {1} \<union> (*) 2 ` braun_indices l \<union> Suc ` (*) 2 ` braun_indices r"
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lemma braun_indices_if_braun: "braun t \<Longrightarrow> braun_indices t = {1..size t}"
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proof(induction t)
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  case Leaf thus ?case by simp
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next
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  have *: "(*) 2 ` {a..b} \<union> Suc ` (*) 2 ` {a..b} = {2*a..2*b+1}" (is "?l = ?r") for a b
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  proof
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    show "?l \<subseteq> ?r" by auto
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  next
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    have "\<exists>x2\<in>{a..b}. x \<in> {Suc (2*x2), 2*x2}" if *: "x \<in> {2*a .. 2*b+1}" for x
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    proof -
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      have "x div 2 \<in> {a..b}" using * by auto
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      moreover have "x \<in> {2 * (x div 2), Suc(2 * (x div 2))}" by auto
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      ultimately show ?thesis by blast
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    qed
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    thus "?r \<subseteq> ?l" by fastforce
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  qed
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  case (Node l x r)
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  hence "size l = size r \<or> size l = size r + 1" (is "?A \<or> ?B") by auto
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  thus ?case
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  proof
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    assume ?A
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    with Node show ?thesis by (auto simp: *)
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  next
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    assume ?B
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    with Node show ?thesis by (auto simp: * atLeastAtMostSuc_conv)
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  qed
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qed
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text \<open>How many even/odd natural numbers are there between m and n?\<close>
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lemma card_atLeastAtMost_even:
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  "card {i \<in> {m..n::nat}. even i} = (n+1-m + (m+1) mod 2) div 2" (is "?l m n = ?r m n")
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proof(induction "n+1 - m" arbitrary: n m)
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   case 0 thus ?case by simp
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next
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  case Suc
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  have "m \<le> n" using Suc(2) by arith
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  hence "{m..n} = insert m {m+1..n}" by auto
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  hence "?l m n = card {i \<in> insert m {m+1..n}. even i}" by simp
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  also have "\<dots> = ?r m n" (is "?l = ?r")
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  proof (cases)
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    assume "even m"
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    hence "{i \<in> insert m {m+1..n}. even i} = insert m {i \<in> {m+1..n}. even i}" by auto
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    hence "?l = card {i \<in> {m+1..n}. even i} + 1" by simp
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    also have "\<dots> = (n-m + (m+2) mod 2) div 2 + 1" using Suc(1)[of n "m+1"] Suc(2) by simp
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    also have "\<dots> = ?r" using \<open>even m\<close> \<open>m \<le> n\<close> by auto
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    finally show ?thesis .
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  next
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    assume "odd m"
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    hence "{i \<in> insert m {m+1..n}. even i} = {i \<in> {m+1..n}. even i}" by auto
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    hence "?l = card ..." by simp
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    also have "\<dots> = (n-m + (m+2) mod 2) div 2" using Suc(1)[of n "m+1"] Suc(2) by simp
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    also have "\<dots> = ?r" using \<open>odd m\<close> \<open>m \<le> n\<close> even_iff_mod_2_eq_zero[of m] by simp
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    finally show ?thesis .
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  qed
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  finally show ?case .
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qed
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lemma card_atLeastAtMost_odd: "card {i \<in> {m..n::nat}. odd i} = (n+1-m + m mod 2) div 2"
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proof -
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  let ?A = "{i \<in> {m..n}. odd i}"
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  let ?B = "{i \<in> {m+1..n+1}. even i}"
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  have "card ?A = card (Suc ` ?A)" by (simp add: card_image)
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  also have "Suc ` ?A = ?B" using Suc_le_D by(force simp: image_iff)
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  also have "card ?B = (n+1-m + (m) mod 2) div 2"
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    using card_atLeastAtMost_even[of "m+1" "n+1"] by simp
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  finally show ?thesis .
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qed
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lemma mod2_iff: "x mod 2 = (if even x then 0 else 1)"
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by (simp add: odd_iff_mod_2_eq_one)
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lemma compact_ivl_even: assumes "A = {i \<in> {m..n}. even i}"
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shows "A = (\<lambda>j. 2*(j-1) + m + m mod 2) ` {1..card A}" (is "_ = ?A")
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proof
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  let ?a = "(n+1-m + (m+1) mod 2) div 2"
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  have "\<exists>j \<in> {1..?a}. i = 2*(j-1) + m + m mod 2" if *: "i \<in> {m..n}" "even i" for i
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  proof -
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    let ?j = "(i - (m + m mod 2)) div 2 + 1"
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    have "?j \<in> {1..?a} \<and> i = 2*(?j-1) + m + m mod 2" using * by(auto simp: mod2_iff) presburger+
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    thus ?thesis by blast
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  qed
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  thus "A \<subseteq> ?A" using assms
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    by(auto simp: image_iff card_atLeastAtMost_even simp del: atLeastAtMost_iff)
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next
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  let ?a = "(n+1-m + (m+1) mod 2) div 2"
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  have 1: "2 * (j - 1) + m + m mod 2 \<in> {m..n}" if *: "j \<in> {1..?a}" for j
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    using * by(auto simp: mod2_iff)
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  have 2: "even (2 * (j - 1) + m + m mod 2)" for j by presburger
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  show "?A \<subseteq> A"
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    apply(simp add: assms card_atLeastAtMost_even del: atLeastAtMost_iff One_nat_def)
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    using 1 2 by blast
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qed
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lemma compact_ivl_odd:
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  assumes "B = {i \<in> {m..n}. odd i}" shows "B = (\<lambda>i. 2*(i-1) + m + (m+1) mod 2) ` {1..card B}"
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   159
proof -
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  define A :: " nat set" where "A = Suc ` B"
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  have "A = {i \<in> {m+1..n+1}. even i}"
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    using Suc_le_D by(force simp add: A_def assms image_iff)
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  from compact_ivl_even[OF this]
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  have "A = Suc ` (\<lambda>i. 2 * (i - 1) + m + (m + 1) mod 2) ` {1..card A}"
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    by (simp add: image_comp o_def)
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  hence B: "B = (\<lambda>i. 2 * (i - 1) + m + (m + 1) mod 2) ` {1..card A}"
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    using A_def by (simp add: inj_image_eq_iff)
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  have "card A = card B" by (metis A_def bij_betw_Suc bij_betw_same_card) 
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  with B show ?thesis by simp
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qed
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   171
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lemma even_odd_decomp: assumes "\<forall>x \<in> A. even x" "\<forall>x \<in> B. odd x"  "A \<union> B = {m..n}"
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shows "(let a = card A; b = card B in
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   a + b = n+1-m \<and>
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   A = (\<lambda>i. 2*(i-1) + m + m mod 2) ` {1..a} \<and>
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   B = (\<lambda>i. 2*(i-1) + m + (m+1) mod 2) ` {1..b} \<and>
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   (a = b \<or> a = b+1 \<and> even m \<or> a+1 = b \<and> odd m))"
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   178
proof -
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  let ?a = "card A" let ?b = "card B"
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  have "finite A \<and> finite B"
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    by (metis \<open>A \<union> B = {m..n}\<close> finite_Un finite_atLeastAtMost)
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  hence ab: "?a + ?b = Suc n - m"
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    by (metis Int_emptyI assms card_Un_disjoint card_atLeastAtMost)
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  have A: "A = {i \<in> {m..n}. even i}" using assms by auto
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  hence A': "A = (\<lambda>i. 2*(i-1) + m + m mod 2) ` {1..?a}" by(rule compact_ivl_even)
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  have B: "B = {i \<in> {m..n}. odd i}" using assms by auto
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  hence B': "B = (\<lambda>i. 2*(i-1) + m + (m+1) mod 2) ` {1..?b}" by(rule compact_ivl_odd)
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  have "?a = ?b \<or> ?a = ?b+1 \<and> even m \<or> ?a+1 = ?b \<and> odd m"
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    apply(simp add: Let_def mod2_iff
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      card_atLeastAtMost_even[of m n, simplified A[symmetric]]
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      card_atLeastAtMost_odd[of m n, simplified B[symmetric]] split!: if_splits)
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    by linarith
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  with ab A' B' show ?thesis by simp
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qed
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   195
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lemma braun_indices1: "i \<in> braun_indices t \<Longrightarrow> i \<ge> 1"
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by (induction t arbitrary: i) auto
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   198
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lemma finite_braun_indices: "finite(braun_indices t)"
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by (induction t) auto
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lemma evens_odds_disj: "(*) 2 ` braun_indices A \<inter> Suc ` (*) 2 ` B = {}"
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   203
using double_not_eq_Suc_double by auto
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   204
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lemma card_braun_indices: "card (braun_indices t) = size t"
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proof (induction t)
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  case Leaf thus ?case by simp
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next
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  case Node
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  thus ?case
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    by(auto simp: UNION_singleton_eq_range finite_braun_indices card_Un_disjoint
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                  card_insert_if evens_odds_disj card_image inj_on_def dest: braun_indices1)
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qed
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   214
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lemma eq: "insert (Suc 0) M = {Suc 0..n} \<Longrightarrow> Suc 0 \<notin> M \<Longrightarrow> M = {2..n}"
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by (metis Suc_n_not_le_n atLeastAtMost_iff atLeastAtMost_insertL insertI1 insert_ident numeral_2_eq_2)
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   217
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lemma inj_on_Suc: "inj_on f N \<Longrightarrow> inj_on (\<lambda>n. Suc(f n)) N"
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by (simp add: inj_on_def)
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lemma braun_if_braun_indices: "braun_indices t = {1..size t} \<Longrightarrow> braun t"
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proof(induction t)
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case Leaf
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  then show ?case by simp
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next
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  case (Node t1 x2 t2)
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  have 1: "i > 0 \<Longrightarrow> Suc(Suc(2 * (i - Suc 0))) = 2*i" for i::nat by(simp add: algebra_simps)
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  have 2: "i > 0 \<Longrightarrow> 2 * (i - Suc 0) + 3 = 2*i + 1" for i::nat by(simp add: algebra_simps)
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  have 3: "(*) 2 ` braun_indices t1 \<union> Suc ` (*) 2 ` braun_indices t2 =
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     {2..size t1 + size t2 + 1}" using Node.prems braun_indices1[of 0 t2]
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    apply simp
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    apply(drule eq)
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     apply auto
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    done
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  thus ?case using Node.IH even_odd_decomp[OF _ _ 3]
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   236
    by(simp add: card_image inj_on_def card_braun_indices Let_def 1 2 inj_image_eq_iff image_comp
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   237
           cong: image_cong_strong)
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qed
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   239
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lemma braun_iff_braun_indices: "braun t \<longleftrightarrow> braun_indices t = {1..size t}"
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   241
using braun_if_braun_indices braun_indices_if_braun by blast
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   242
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end