src/Doc/Tutorial/CTL/CTL.thy
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(*<*)theory CTL imports Base begin(*>*)
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subsection{*Computation Tree Logic --- CTL*}
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text{*\label{sec:CTL}
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\index{CTL|(}%
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The semantics of PDL only needs reflexive transitive closure.
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Let us be adventurous and introduce a more expressive temporal operator.
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We extend the datatype
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@{text formula} by a new constructor
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*}
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(*<*)
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datatype formula = Atom "atom"
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                  | Neg formula
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                  | And formula formula
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                  | AX formula
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                  | EF formula(*>*)
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                  | AF formula
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text{*\noindent
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which stands for ``\emph{A}lways in the \emph{F}uture'':
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on all infinite paths, at some point the formula holds.
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Formalizing the notion of an infinite path is easy
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in HOL: it is simply a function from @{typ nat} to @{typ state}.
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*}
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definition Paths :: "state \<Rightarrow> (nat \<Rightarrow> state)set" where
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"Paths s \<equiv> {p. s = p 0 \<and> (\<forall>i. (p i, p(i+1)) \<in> M)}"
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text{*\noindent
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This definition allows a succinct statement of the semantics of @{const AF}:
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\footnote{Do not be misled: neither datatypes nor recursive functions can be
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extended by new constructors or equations. This is just a trick of the
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presentation (see \S\ref{sec:doc-prep-suppress}). In reality one has to define
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a new datatype and a new function.}
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*}
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(*<*)
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primrec valid :: "state \<Rightarrow> formula \<Rightarrow> bool" ("(_ \<Turnstile> _)" [80,80] 80) where
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"s \<Turnstile> Atom a  =  (a \<in> L s)" |
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"s \<Turnstile> Neg f   = (~(s \<Turnstile> f))" |
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"s \<Turnstile> And f g = (s \<Turnstile> f \<and> s \<Turnstile> g)" |
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"s \<Turnstile> AX f    = (\<forall>t. (s,t) \<in> M \<longrightarrow> t \<Turnstile> f)" |
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"s \<Turnstile> EF f    = (\<exists>t. (s,t) \<in> M\<^sup>* \<and> t \<Turnstile> f)" |
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(*>*)
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"s \<Turnstile> AF f    = (\<forall>p \<in> Paths s. \<exists>i. p i \<Turnstile> f)"
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text{*\noindent
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Model checking @{const AF} involves a function which
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is just complicated enough to warrant a separate definition:
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*}
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definition af :: "state set \<Rightarrow> state set \<Rightarrow> state set" where
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"af A T \<equiv> A \<union> {s. \<forall>t. (s, t) \<in> M \<longrightarrow> t \<in> T}"
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text{*\noindent
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Now we define @{term "mc(AF f)"} as the least set @{term T} that includes
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@{term"mc f"} and all states all of whose direct successors are in @{term T}:
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*}
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(*<*)
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primrec mc :: "formula \<Rightarrow> state set" where
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"mc(Atom a)  = {s. a \<in> L s}" |
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"mc(Neg f)   = -mc f" |
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"mc(And f g) = mc f \<inter> mc g" |
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"mc(AX f)    = {s. \<forall>t. (s,t) \<in> M  \<longrightarrow> t \<in> mc f}" |
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"mc(EF f)    = lfp(\<lambda>T. mc f \<union> M\<inverse> `` T)"|(*>*)
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"mc(AF f)    = lfp(af(mc f))"
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text{*\noindent
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Because @{const af} is monotone in its second argument (and also its first, but
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that is irrelevant), @{term"af A"} has a least fixed point:
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*}
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lemma mono_af: "mono(af A)"
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apply(simp add: mono_def af_def)
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apply blast
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done
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(*<*)
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lemma mono_ef: "mono(\<lambda>T. A \<union> M\<inverse> `` T)"
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apply(rule monoI)
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by(blast)
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lemma EF_lemma:
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  "lfp(\<lambda>T. A \<union> M\<inverse> `` T) = {s. \<exists>t. (s,t) \<in> M\<^sup>* \<and> t \<in> A}"
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apply(rule equalityI)
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 apply(rule subsetI)
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 apply(simp)
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 apply(erule lfp_induct_set)
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  apply(rule mono_ef)
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 apply(simp)
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 apply(blast intro: rtrancl_trans)
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apply(rule subsetI)
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apply(simp, clarify)
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apply(erule converse_rtrancl_induct)
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 apply(subst lfp_unfold[OF mono_ef])
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 apply(blast)
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apply(subst lfp_unfold[OF mono_ef])
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by(blast)
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(*>*)
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text{*
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All we need to prove now is  @{prop"mc(AF f) = {s. s \<Turnstile> AF f}"}, which states
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that @{term mc} and @{text"\<Turnstile>"} agree for @{const AF}\@.
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This time we prove the two inclusions separately, starting
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with the easy one:
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*}
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theorem AF_lemma1: "lfp(af A) \<subseteq> {s. \<forall>p \<in> Paths s. \<exists>i. p i \<in> A}"
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txt{*\noindent
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In contrast to the analogous proof for @{const EF}, and just
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for a change, we do not use fixed point induction.  Park-induction,
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named after David Park, is weaker but sufficient for this proof:
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\begin{center}
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@{thm lfp_lowerbound[of _ "S",no_vars]} \hfill (@{thm[source]lfp_lowerbound})
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\end{center}
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The instance of the premise @{prop"f S \<subseteq> S"} is proved pointwise,
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a decision that \isa{auto} takes for us:
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*}
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apply(rule lfp_lowerbound)
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apply(auto simp add: af_def Paths_def)
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txt{*
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@{subgoals[display,indent=0,margin=70,goals_limit=1]}
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In this remaining case, we set @{term t} to @{term"p(1::nat)"}.
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The rest is automatic, which is surprising because it involves
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finding the instantiation @{term"\<lambda>i::nat. p(i+1)"}
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for @{text"\<forall>p"}.
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*}
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apply(erule_tac x = "p 1" in allE)
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apply(auto)
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done
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text{*
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The opposite inclusion is proved by contradiction: if some state
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@{term s} is not in @{term"lfp(af A)"}, then we can construct an
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infinite @{term A}-avoiding path starting from~@{term s}. The reason is
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that by unfolding @{const lfp} we find that if @{term s} is not in
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@{term"lfp(af A)"}, then @{term s} is not in @{term A} and there is a
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direct successor of @{term s} that is again not in \mbox{@{term"lfp(af
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A)"}}. Iterating this argument yields the promised infinite
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@{term A}-avoiding path. Let us formalize this sketch.
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The one-step argument in the sketch above
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is proved by a variant of contraposition:
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*}
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lemma not_in_lfp_afD:
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 "s \<notin> lfp(af A) \<Longrightarrow> s \<notin> A \<and> (\<exists> t. (s,t) \<in> M \<and> t \<notin> lfp(af A))"
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apply(erule contrapos_np)
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apply(subst lfp_unfold[OF mono_af])
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apply(simp add: af_def)
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done
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text{*\noindent
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We assume the negation of the conclusion and prove @{term"s : lfp(af A)"}.
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Unfolding @{const lfp} once and
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simplifying with the definition of @{const af} finishes the proof.
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Now we iterate this process. The following construction of the desired
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path is parameterized by a predicate @{term Q} that should hold along the path:
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*}
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primrec path :: "state \<Rightarrow> (state \<Rightarrow> bool) \<Rightarrow> (nat \<Rightarrow> state)" where
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"path s Q 0 = s" |
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"path s Q (Suc n) = (SOME t. (path s Q n,t) \<in> M \<and> Q t)"
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text{*\noindent
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Element @{term"n+1::nat"} on this path is some arbitrary successor
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@{term t} of element @{term n} such that @{term"Q t"} holds.  Remember that @{text"SOME t. R t"}
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is some arbitrary but fixed @{term t} such that @{prop"R t"} holds (see \S\ref{sec:SOME}). Of
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course, such a @{term t} need not exist, but that is of no
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concern to us since we will only use @{const path} when a
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suitable @{term t} does exist.
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Let us show that if each state @{term s} that satisfies @{term Q}
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has a successor that again satisfies @{term Q}, then there exists an infinite @{term Q}-path:
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*}
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lemma infinity_lemma:
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  "\<lbrakk> Q s; \<forall>s. Q s \<longrightarrow> (\<exists> t. (s,t) \<in> M \<and> Q t) \<rbrakk> \<Longrightarrow>
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   \<exists>p\<in>Paths s. \<forall>i. Q(p i)"
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txt{*\noindent
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First we rephrase the conclusion slightly because we need to prove simultaneously
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both the path property and the fact that @{term Q} holds:
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*}
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apply(subgoal_tac
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  "\<exists>p. s = p 0 \<and> (\<forall>i::nat. (p i, p(i+1)) \<in> M \<and> Q(p i))")
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txt{*\noindent
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From this proposition the original goal follows easily:
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*}
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 apply(simp add: Paths_def, blast)
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txt{*\noindent
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The new subgoal is proved by providing the witness @{term "path s Q"} for @{term p}:
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*}
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apply(rule_tac x = "path s Q" in exI)
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apply(clarsimp)
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txt{*\noindent
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After simplification and clarification, the subgoal has the following form:
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@{subgoals[display,indent=0,margin=70,goals_limit=1]}
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It invites a proof by induction on @{term i}:
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*}
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apply(induct_tac i)
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 apply(simp)
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txt{*\noindent
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After simplification, the base case boils down to
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@{subgoals[display,indent=0,margin=70,goals_limit=1]}
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The conclusion looks exceedingly trivial: after all, @{term t} is chosen such that @{prop"(s,t):M"}
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holds. However, we first have to show that such a @{term t} actually exists! This reasoning
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is embodied in the theorem @{thm[source]someI2_ex}:
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@{thm[display,eta_contract=false]someI2_ex}
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When we apply this theorem as an introduction rule, @{text"?P x"} becomes
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@{prop"(s, x) : M & Q x"} and @{text"?Q x"} becomes @{prop"(s,x) : M"} and we have to prove
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two subgoals: @{prop"EX a. (s, a) : M & Q a"}, which follows from the assumptions, and
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@{prop"(s, x) : M & Q x ==> (s,x) : M"}, which is trivial. Thus it is not surprising that
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@{text fast} can prove the base case quickly:
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*}
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 apply(fast intro: someI2_ex)
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txt{*\noindent
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What is worth noting here is that we have used \methdx{fast} rather than
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@{text blast}.  The reason is that @{text blast} would fail because it cannot
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cope with @{thm[source]someI2_ex}: unifying its conclusion with the current
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subgoal is non-trivial because of the nested schematic variables. For
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efficiency reasons @{text blast} does not even attempt such unifications.
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Although @{text fast} can in principle cope with complicated unification
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problems, in practice the number of unifiers arising is often prohibitive and
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the offending rule may need to be applied explicitly rather than
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automatically. This is what happens in the step case.
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The induction step is similar, but more involved, because now we face nested
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occurrences of @{text SOME}. As a result, @{text fast} is no longer able to
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solve the subgoal and we apply @{thm[source]someI2_ex} by hand.  We merely
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show the proof commands but do not describe the details:
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*}
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apply(simp)
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apply(rule someI2_ex)
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 apply(blast)
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apply(rule someI2_ex)
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 apply(blast)
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apply(blast)
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done
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text{*
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Function @{const path} has fulfilled its purpose now and can be forgotten.
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It was merely defined to provide the witness in the proof of the
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@{thm[source]infinity_lemma}. Aficionados of minimal proofs might like to know
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that we could have given the witness without having to define a new function:
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the term
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@{term[display]"rec_nat s (\<lambda>n t. SOME u. (t,u)\<in>M \<and> Q u)"}
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is extensionally equal to @{term"path s Q"},
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where @{term rec_nat} is the predefined primitive recursor on @{typ nat}.
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*}
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(*<*)
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lemma
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"\<lbrakk> Q s; \<forall> s. Q s \<longrightarrow> (\<exists> t. (s,t)\<in>M \<and> Q t) \<rbrakk> \<Longrightarrow>
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 \<exists> p\<in>Paths s. \<forall> i. Q(p i)"
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apply(subgoal_tac
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 "\<exists> p. s = p 0 \<and> (\<forall> i. (p i,p(Suc i))\<in>M \<and> Q(p i))")
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 apply(simp add: Paths_def)
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 apply(blast)
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apply(rule_tac x = "rec_nat s (\<lambda>n t. SOME u. (t,u)\<in>M \<and> Q u)" in exI)
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apply(simp)
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apply(intro strip)
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apply(induct_tac i)
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 apply(simp)
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 apply(fast intro: someI2_ex)
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apply(simp)
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apply(rule someI2_ex)
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 apply(blast)
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apply(rule someI2_ex)
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 apply(blast)
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by(blast)
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(*>*)
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text{*
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At last we can prove the opposite direction of @{thm[source]AF_lemma1}:
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*}
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theorem AF_lemma2: "{s. \<forall>p \<in> Paths s. \<exists>i. p i \<in> A} \<subseteq> lfp(af A)"
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txt{*\noindent
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The proof is again pointwise and then by contraposition:
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*}
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apply(rule subsetI)
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apply(erule contrapos_pp)
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apply simp
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txt{*
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@{subgoals[display,indent=0,goals_limit=1]}
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Applying the @{thm[source]infinity_lemma} as a destruction rule leaves two subgoals, the second
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premise of @{thm[source]infinity_lemma} and the original subgoal:
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*}
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apply(drule infinity_lemma)
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txt{*
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@{subgoals[display,indent=0,margin=65]}
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Both are solved automatically:
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*}
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 apply(auto dest: not_in_lfp_afD)
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done
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text{*
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If you find these proofs too complicated, we recommend that you read
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\S\ref{sec:CTL-revisited}, where we show how inductive definitions lead to
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simpler arguments.
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The main theorem is proved as for PDL, except that we also derive the
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necessary equality @{text"lfp(af A) = ..."} by combining
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@{thm[source]AF_lemma1} and @{thm[source]AF_lemma2} on the spot:
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*}
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theorem "mc f = {s. s \<Turnstile> f}"
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apply(induct_tac f)
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apply(auto simp add: EF_lemma equalityI[OF AF_lemma1 AF_lemma2])
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done
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text{*
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The language defined above is not quite CTL\@. The latter also includes an
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until-operator @{term"EU f g"} with semantics ``there \emph{E}xists a path
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where @{term f} is true \emph{U}ntil @{term g} becomes true''.  We need
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an auxiliary function:
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*}
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primrec
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until:: "state set \<Rightarrow> state set \<Rightarrow> state \<Rightarrow> state list \<Rightarrow> bool" where
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"until A B s []    = (s \<in> B)" |
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"until A B s (t#p) = (s \<in> A \<and> (s,t) \<in> M \<and> until A B t p)"
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(*<*)definition
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 eusem :: "state set \<Rightarrow> state set \<Rightarrow> state set" where
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"eusem A B \<equiv> {s. \<exists>p. until A B s p}"(*>*)
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text{*\noindent
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Expressing the semantics of @{term EU} is now straightforward:
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@{prop[display]"s \<Turnstile> EU f g = (\<exists>p. until {t. t \<Turnstile> f} {t. t \<Turnstile> g} s p)"}
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Note that @{term EU} is not definable in terms of the other operators!
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Model checking @{term EU} is again a least fixed point construction:
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@{text[display]"mc(EU f g) = lfp(\<lambda>T. mc g \<union> mc f \<inter> (M\<inverse> `` T))"}
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\begin{exercise}
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Extend the datatype of formulae by the above until operator
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and prove the equivalence between semantics and model checking, i.e.\ that
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@{prop[display]"mc(EU f g) = {s. s \<Turnstile> EU f g}"}
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%For readability you may want to annotate {term EU} with its customary syntax
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%{text[display]"| EU formula formula    E[_ U _]"}
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%which enables you to read and write {text"E[f U g]"} instead of {term"EU f g"}.
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\end{exercise}
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For more CTL exercises see, for example, Huth and Ryan @{cite "Huth-Ryan-book"}.
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*}
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(*<*)
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definition eufix :: "state set \<Rightarrow> state set \<Rightarrow> state set \<Rightarrow> state set" where
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"eufix A B T \<equiv> B \<union> A \<inter> (M\<inverse> `` T)"
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lemma "lfp(eufix A B) \<subseteq> eusem A B"
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apply(rule lfp_lowerbound)
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apply(auto simp add: eusem_def eufix_def)
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 apply(rule_tac x = "[]" in exI)
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 apply simp
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apply(rule_tac x = "xa#xb" in exI)
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apply simp
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done
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lemma mono_eufix: "mono(eufix A B)"
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apply(simp add: mono_def eufix_def)
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apply blast
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done
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lemma "eusem A B \<subseteq> lfp(eufix A B)"
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apply(clarsimp simp add: eusem_def)
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apply(erule rev_mp)
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apply(rule_tac x = x in spec)
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apply(induct_tac p)
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 apply(subst lfp_unfold[OF mono_eufix])
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 apply(simp add: eufix_def)
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apply(clarsimp)
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apply(subst lfp_unfold[OF mono_eufix])
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apply(simp add: eufix_def)
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apply blast
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done
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(*
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definition eusem :: "state set \<Rightarrow> state set \<Rightarrow> state set" where
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"eusem A B \<equiv> {s. \<exists>p\<in>Paths s. \<exists>j. p j \<in> B \<and> (\<forall>i < j. p i \<in> A)}"
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axiomatization where
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M_total: "\<exists>t. (s,t) \<in> M"
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consts apath :: "state \<Rightarrow> (nat \<Rightarrow> state)"
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primrec
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"apath s 0 = s"
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"apath s (Suc i) = (SOME t. (apath s i,t) \<in> M)"
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lemma [iff]: "apath s \<in> Paths s";
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apply(simp add: Paths_def);
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apply(blast intro: M_total[THEN someI_ex])
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done
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definition pcons :: "state \<Rightarrow> (nat \<Rightarrow> state) \<Rightarrow> (nat \<Rightarrow> state)" where
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"pcons s p == \<lambda>i. case i of 0 \<Rightarrow> s | Suc j \<Rightarrow> p j"
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lemma pcons_PathI: "[| (s,t) : M; p \<in> Paths t |] ==> pcons s p \<in> Paths s";
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by(simp add: Paths_def pcons_def split: nat.split);
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lemma "lfp(eufix A B) \<subseteq> eusem A B"
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apply(rule lfp_lowerbound)
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apply(clarsimp simp add: eusem_def eufix_def);
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apply(erule disjE);
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 apply(rule_tac x = "apath x" in bexI);
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  apply(rule_tac x = 0 in exI);
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  apply simp;
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 apply simp;
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apply(clarify);
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apply(rule_tac x = "pcons xb p" in bexI);
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 apply(rule_tac x = "j+1" in exI);
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 apply (simp add: pcons_def split: nat.split);
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apply (simp add: pcons_PathI)
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done
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*)
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(*>*)
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text{* Let us close this section with a few words about the executability of
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our model checkers.  It is clear that if all sets are finite, they can be
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represented as lists and the usual set operations are easily
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implemented. Only @{const lfp} requires a little thought.  Fortunately, theory
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@{text While_Combinator} in the Library~@{cite "HOL-Library"} provides a
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theorem stating that in the case of finite sets and a monotone
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function~@{term F}, the value of \mbox{@{term"lfp F"}} can be computed by
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iterated application of @{term F} to~@{term"{}"} until a fixed point is
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reached. It is actually possible to generate executable functional programs
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from HOL definitions, but that is beyond the scope of the tutorial.%
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\index{CTL|)} *}
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(*<*)end(*>*)